Uy » Choraklik online testlar » Matematika choraklik » 11-sinf Matematika 2-chorak Matematika choraklik 11-sinf Matematika 2-chorak InfoMaster Aprel 20, 2021 379 Ko'rishlar 16 izohlar SaqlashSaqlanganOlib tashlandi 1 0 OMAD YOR BO'LSIN! Tomonidan yaratilgan InfoMaster 11-sinf Matematika 2-chorak Testni Mamadoliyev Diyorbek tayyorladi. 1 / 25 Funksiya hosilasini toping: f(x)=5 A) 5 B) 10 C) x D) 0 2 / 25 Funksiyaning kamayish oraliqlarini toping A) (-2;0) va (0;1) B) (-3;0) va (0;1) C) (-1;0) va (0;1) D) (-1;0) va (0;2) 3 / 25 funksiyaning [-4;1] kesmadagi eng kata qiymatini toping. A) 131 B) -13 C) 13 D) -4 4 / 25 Agar f(x)=x² va bo`lsa ,f(g(-4)) ni toping A) 0 B) -12 C) 12 D) 36 5 / 25 Agar A(1;2;3), B(3;7;6) bo’lsa, A̅B̅ vector koordinatalarini toping A) (2;5;3) B) (4;9;9) C) (4;9;9) D) (-2;-5;-3) 6 / 25 A(2;0;-3) va B(3;4;0) nuqtalar orasidagi masofani toping A) 25 B) 16 C) √26 D) √24 7 / 25 f(x)=3x2-5x+4 va g(x)=4x-5 funksiyalarining urinmalari parallel bo’ladigan nuqtalarini toping. A) 1.5 B) 0 C) 0.5 D) 2 8 / 25 Moddiy nuqta S(t)=5t3+3t2+2t+4 qonuniyat bilan harakatlanayotgan jismning t=2 sekunddagi tezligini toping. A) 74 B) 70 C) 60 D) 84 9 / 25 Moddiy nuqtaning berilgan t vaqtdagi tezligini hisoblang: , t=5 A) 75 B) 80 C) 90 D) 70 10 / 25 Koordinatalar boshidan y=x2-4x+3 parabolaning simmetriya o’qigacha bo’lgan masofani toping. A) 1 B) 4 C) 2 D) 3 11 / 25 Karim uyida 14 bet matn terib, 8ta imloviy xatoga yo’l qo’ydi. Agar 1 betda o’rtacha 380 ta so’z bo’lsa, Karim 100ta so’z terganda o’rtacha qancha xato qiladi? A) 0,5 B) 1,5 C) 0,15 D) 0,25 12 / 25 A(-4;3;6) nuqtaning Oxz tekisligiga nisbatan simmrtrik nuqtasini toping. A) (-4;-3;6) B) (-8;-3;6) C) (-4;-6;6) D) (-4;-3;9) 13 / 25 f(x)=2x+3 funksiyasi uchun A(1;5) nuqtadan o’tuvchi boshlang’ich funksiyasini toping. A) F(x)=x²+3x-1 B) F(x)=x²+3x+1 C) F(x)=x²-3x+1 D) F(x)=x²-3x-1 14 / 25 Limitni hisoblang: A) 4 B) 3 C) -4 D) -3 15 / 25 Nargiza 4minutda 260ta so`zni terib, 7ta imloviy xatoga yo`l qo`ydi. Nargizaning matn terish sifatini aniqlang A) 0,6 B) 0,01 C) 0,5 D) 0,0269 16 / 25 funksiyasining kamayish oralig’ini toping. A) (-∞;-1) B) [-1;-1/3] C) (-1;1/3) D) (-1/3;+∞) 17 / 25 funksiya grafigiga x=1 abssisssali nuqtadao`tkazilgan urinma tenglamasini yozing A) y=x B) y=1/2 C) y=-x D) y= 2x 18 / 25 Funksiya hosilasini toping f(x)=(2x+4)(3x+1) A) 16x+14 B) 12x+14 C) 3x+1 D) 12x 19 / 25 f(x)=sin2x funksiyasining barcha boshlang’ich funksiyalarini toping. A) F(x)=0,5cos2x+C B) F(x)=-0,5cos2x+C C) F(x)=-2cos2x+C D) F(x)=2sin4x+c 20 / 25 f(x)=excosx funksiyasi uchun f ’(π/2) ni aniqlang. A. e-0.5π B. e0,5π C. eπ D. e-π A) e^(-π) B) e^(-0.5π) C) e^(0.5π) D) e^(π) 21 / 25 To’g’riburchakli parallelepiped bir uchidan chiquvchi uchta qirralari uzunliklari 4,6 va 9 ga teng. Unga tengdosh kub qirrasining uzunligini toping. A) 7 B) 6 C) 8 D) 6 22 / 25 Kub to’la sirtining yuzi 105,84 sm2 bo’lsa, uning har bir yog’i yuzini va qirrasining uzunligini toping. A) 17,64 dm²; 4,9 dm B) 17,68 dm²; 4,2 dm C) 17,64 dm²; 4,2 dm D) 17,64 dm; 4,2 dm 23 / 25 Moddiy nuqta qonuniyat bilan harakatlanmoqda, eng katta tezlanishga erishiladigan vaqtni toping. A) 6 B) 5 C) 7 D) 4 24 / 25 Tandirdan olingan nonning temperaturasi 20 minut ichida 1000 dan 600 gacha pasayadi. Tashqi muhit temperaturasi 250. Nonning temperaturasi qancha vaqtda 300 gacha pasayadi? A) 61 B) 41 C) 71 D) 51 25 / 25 F(x)=0.2sin(5x+12) funksiyasi uchun f(x) ni toping A) f(x)=0.5cos(5x+12) B) f(x)=cos(5x+12) C) f(x)=-cos(5x+12) D) f(x)=-0,5sin(5x+12) 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz