Uy » Choraklik online testlar » Matematika choraklik » 11-sinf Matematika 2-chorak Matematika choraklik 11-sinf Matematika 2-chorak InfoMaster Aprel 20, 2021 34 Ko'rishlar 16 izohlar SaqlashSaqlanganOlib tashlandi 1 0 OMAD YOR BO'LSIN! 11-sinf Matematika 2-chorak Testni Mamadoliyev Diyorbek tayyorladi. 1 / 25 To’g’riburchakli parallelepiped asosining tomonlari 7:24 nisbatda, diagonal kesimining yuzi 50dm2 ga teng. Yon sirtining yuzini toping. A) 135 dm² B) 124 dm C) 224 dm² D) 124 dm² 2 / 25 To’g’ri to’rtburchak shaklidagi yer maydoninig atrofini o’rashmoqchi. 480 m panjara yordamida eng ko’pi bilan necha kvadrat metr yer maydonni o’rash mumkin? A) 8100 B) 19600 C) 25600 D) 14400 3 / 25 F(x)=0.2sin(5x+12) funksiyasi uchun f(x) ni toping A) f(x)=-0,5sin(5x+12) B) f(x)=cos(5x+12) C) f(x)=0.5cos(5x+12) D) f(x)=-cos(5x+12) 4 / 25 Qavariq ko’pburchakning har bir uchidan uchtadan qirra chiqadi. Agar bu ko’pyoqning qirralari soni 12 ta bo’lsa, uning nechta uchi va yog’i mavjud? A) 4;11 B) 4;18 C) 8;10 D) 4;10 5 / 25 Kub to’la sirtining yuzi 105,84 sm2 bo’lsa, uning har bir yog’i yuzini va qirrasining uzunligini toping. A) 17,64 dm²; 4,2 dm B) 17,64 dm; 4,2 dm C) 17,64 dm²; 4,9 dm D) 17,68 dm²; 4,2 dm 6 / 25 Moddiy nuqta qonuniyat bilan harakatlanmoqda, eng katta tezlanishga erishiladigan vaqtni toping. A) 6 B) 7 C) 4 D) 5 7 / 25 sonini taqriban hisoblang. A) 5,08 B) 5,01 C) 3,08 D) 4,08 8 / 25 f(x)=excosx funksiyasi uchun f ’(π/2) ni aniqlang. A. e-0.5π B. e0,5π C. eπ D. e-π A) e^(-π) B) e^(π) C) e^(-0.5π) D) e^(0.5π) 9 / 25 funksiyasining kamayish oralig’ini toping. A) (-1/3;+∞) B) (-∞;-1) C) [-1;-1/3] D) (-1;1/3) 10 / 25 Funksiya hosilasini toping: f(x)=5 A) 5 B) 10 C) 0 D) x 11 / 25 Agar A(1;2;3), B(3;7;6) bo’lsa, A̅B̅ vector koordinatalarini toping A) (-2;-5;-3) B) (2;5;3) C) (4;9;9) D) (4;9;9) 12 / 25 A(-4;3;6) nuqtaning Oxz tekisligiga nisbatan simmrtrik nuqtasini toping. A) (-4;-6;6) B) (-8;-3;6) C) (-4;-3;9) D) (-4;-3;6) 13 / 25 Agar f(x)=x² va bo`lsa ,f(g(2)) ni toping A) 36 B) 0 C) 12 D) 16 14 / 25 funksiya grafigiga x=1 abssisssali nuqtadao`tkazilgan urinma tenglamasini yozing A) y=1/2 B) y=-x C) y=x D) y= 2x 15 / 25 Uchlari A(2;-3;4) va B(-2;4;5) nuqtalarda bo’lgan AB kesmasining uzunligini toping A) √66 B) √19 C) √24 D) √55 16 / 25 Murakkab funksiyaning hosilasini toping. y=x2sinx A) y’=x²cosx-2xsinx B) y’=2xsinx-x² C) y’=2xsinx+x²cosx D) y’=-2xsinx+x² 17 / 25 Funksiyaning statsionar nuqtalarini toping A) x=-1, x=2 B) x=0, x=2 C) x=3, x=2 D) x=-1, x=3 18 / 25 Uchlari A(4;0;1), B(5;-2;1), C(4;8;5) nuqtalarda bo’lgan uchburchakning AL bissektrisasi uzunligini toping A) (4√2)3 B) (2√5)/3 C) 4 D) (4√2)/5 19 / 25 Agar f(x)=x² va bo`lsa ,f(g(-4)) ni toping A) 12 B) -12 C) 0 D) 36 20 / 25 A) 14 B) 13 C) 20 D) 18 21 / 25 Moddiy nuqta S(t)=5t3+3t2+2t+4 qonuniyat bilan harakatlanayotgan jismning t=2 sekunddagi tezligini toping. A) 70 B) 74 C) 84 D) 60 22 / 25 funksiya hosilasining x0=-2 nuqtadagi qiymatini hisoblang. A) -38/961 B) 38/961 C) -38/31 D) 38/31 23 / 25 Funksiya hosilasini toping f(x)=(2x+4)(3x+1) A) 16x+14 B) 12x C) 12x+14 D) 3x+1 24 / 25 Limitni hisoblang: A) -3 B) 4 C) 3 D) -4 25 / 25 tgx funksiya hosilasini toping A) cosx B) 1/cos²x C) 1/sinx D) sinx 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Tomonidan Wordpress Quiz plugin Author: InfoMaster Foydali bo'lsa mamnunmiz