11-sinf Matematika 4-chorak Aprel 17, 2021Aprel 20, 2021 da chop etilgan InfoMaster tomonidan 11-sinf Matematika 4-chorak ga fikr bildirilmagan. 73 OMAD YOR BO'LSIN! 11-sinf Matematika 4-chorak Testni Salomov Sardor tayyorladi. 1 / 25 Uchburchakli muntazam prizma asosining radiusi ga va balandligi 2 ga teng bo’lgan silindrga ichki chizilgan. Prizma yon sirtining yuzini toping A) 335 B) 3 C) 36 D) 4 2 / 25 Muntazam uchburchak tomoni 3 ga teng. Uchburchak tomonlari o’rtalari tutashtirilib, muntazam uchburchaklar hosil qilindi. Ichma-ich joylashgan uchburchaklar yuzlari yig’indisini toping A) 2√3 B) 3 C) 2 D) 3√3 3 / 25 (x2+23x+23)(x2+x+23)=23x2 tenglama haqiyqiy ildizlari yig’indisini toping A) 23 B) -24 C) 24 D) -23 4 / 25 Silindr shaklidagi idishga 6 sm3 suv solindi. Idishga detal to’liq cho’ktirilganda, suv sathi 1,5 marta ko’tarildi. Detal hajmini aniqlang A) 23 B) 3 C) 1 D) 14 5 / 25 2cosx+sinx=-2 tenglamaning [-π;π] kesmada nechta ildizi bor A) 1 B) 3 C) 2 D) Ø 6 / 25 B,C,D,E nuqtalar aylanadagi, A esa aylanadan tashqaridagi nuqtalar. D nuqta AE kesmada, B esa AC kesmada yotadi. Agar AE=12 va AC=16 bo’lsa, BE vatar uzunligining CD vatar uzunligiga nisbatini toping A) 1 B) 3/4 C) 3 D) 4 7 / 25 funksiyasining kamayish oralig’ini toping A) (0;+∞) B) ∅ C) (-∞;0] D) (-√5;√5) 8 / 25 Qavariq ko’pburchakning har bir uchidan uchtadan qirra chiqadi. Agar bu ko’pyoqning qirralari soni 12 ta bo’lsa, uning nechta uchi va yog’i mavjud? A) 4;18 B) 8;10 C) 4;11 D) 4;10 9 / 25 To’g’riburchakli parallelepiped asosining tomonlari 7:24 nisbatda, diagonal kesimining yuzi 50dm2 ga teng. Yon sirtining yuzini toping. A) 124 dm B) 224 dm² C) 135 dm² D) 124 dm² 10 / 25 f(x)=(3x+2)2 funksiyasining barcha boshlang’ich funksiyalarini toping. A) F(x)=6x³+3x²+4 B) F(x)=6x³+6x+4 C) F(x)=6x³+6x²+4 D) F(x)=6x³+3x²-4 11 / 25 A(2;0;-3) va B(3;4;0) nuqtalar orasidagi masofani toping A) √24 B) √26 C) 25 D) 16 12 / 25 Karim 3 minutda 213ta so`zni terib , 6ta imloviy xatoga yo`l qo`ydi. Karimning matn terish sifatini toping. A) 0,0321 B) 0,3265 C) 0,0282 D) 0,623 13 / 25 funksiya grafigiga x=1 abssisssali nuqtadao`tkazilgan urinma tenglamasini yozing A) y=x B) y=-x C) y=1/2 D) y= 2x 14 / 25 Funksiyaning statsionar nuqtalarini toping A) x=-1, x=2 B) x=0, x=2 C) x=-1, x=3 D) x=3, x=2 15 / 25 y=-3x3+2x2-4x+5 funksiyaga x0=-1 nuqtada o’tkazilgan urinma tenglamasining burchak koeffitsiyentini toping. A) 15 B) -17 C) 17 D) -13 16 / 25 funksiya uchun y=2x-1 to`g`ri chiziqqa parallel bo`lgan urinma tenglamasini yozing A) y=2x+3 B) y=2x-2,25 C) y=3x-2,2 D) y=2x 17 / 25 Funksiyaning kamayish oraliqlarini toping A) (-3;0) va (0;1) B) (-1;0) va (0;1) C) (-1;0) va (0;2) D) (-2;0) va (0;1) 18 / 25 funksiyasining kamayish oralig’ini toping. A) [-1;-1/3] B) (-1/3;+∞) C) (-1;1/3) D) (-∞;-1) 19 / 25 A) 20 B) 14 C) 13 D) 18 20 / 25 Moddiy nuqta S(t)=5t3+3t2+2t+4 qonuniyat bilan harakatlanayotgan jismning t=2 sekunddagi tezligini toping. A) 70 B) 60 C) 74 D) 84 21 / 25 tgx funksiya hosilasini toping A) 1/sinx B) sinx C) 1/cos²x D) cosx 22 / 25 A(-4;3;6) nuqtaning Oxz tekisligiga nisbatan simmrtrik nuqtasini toping. A) (-8;-3;6) B) (-4;-3;6) C) (-4;-3;9) D) (-4;-6;6) 23 / 25 A(1;-2;2), B(1;4;0), C(-4;1;1) va D(-5;-5;3) nuqtalar berilgan. AC va BD vektorlar orasidagi burchakni toping A) 80° B) 15° C) 52° D) 90° 24 / 25 Funksiya hosilasini toping: f(x)=5 A) x B) 0 C) 10 D) 5 25 / 25 funksiyaning [-4;1] kesmadagi eng kata qiymatini toping. A) 131 B) 13 C) -4 D) -13 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Author: InfoMaster Matematika choraklik Teglar:11-sinf, matematika