Uy » Choraklik online testlar » Matematika choraklik » 11-sinf Matematika 4-chorak Matematika choraklik 11-sinf Matematika 4-chorak InfoMaster Aprel 20, 2021 87 Ko'rishlar 83 izohlar SaqlashSaqlanganOlib tashlandi 1 2 OMAD YOR BO'LSIN! 11-sinf Matematika 4-chorak Testni Salomov Sardor tayyorladi. 1 / 25 Limitni hisoblang: A) -3 B) 3 C) 4 D) -4 2 / 25 Nargiza 4minutda 260ta so`zni terib, 7ta imloviy xatoga yo`l qo`ydi. Nargizaning matn terish sifatini aniqlang A) 0,0269 B) 0,6 C) 0,01 D) 0,5 3 / 25 Funksiya hosilasini toping: A) 14x+12 B) 12x²-12 C) 12x+12 D) 21x²-10x 4 / 25 limitni hisoblang A) 5 B) 0 C) 6 D) 7 5 / 25 Moddiy nuqtaning berilgan t vaqtdagi tezligini hisoblang: , t=5 A) 70 B) 80 C) 90 D) 75 6 / 25 f(x)=2x+3 funksiyasi uchun A(1;5) nuqtadan o’tuvchi boshlang’ich funksiyasini toping. A) F(x)=x²-3x-1 B) F(x)=x²+3x-1 C) F(x)=x²+3x+1 D) F(x)=x²-3x+1 7 / 25 Funksiyaning statsionar nuqtalarini toping A) x=-1, x=3 B) x=-1, x=2 C) x=3, x=2 D) x=0, x=2 8 / 25 A(2;0;-3) va B(3;4;0) nuqtalar orasidagi masofani toping A) √24 B) 25 C) 16 D) √26 9 / 25 Funksiyaning kamayish oraliqlarini toping A) (-1;0) va (0;1) B) (-1;0) va (0;2) C) (-3;0) va (0;1) D) (-2;0) va (0;1) 10 / 25 Moddiy nuqta S(t)=5t3+3t2+2t+4 qonuniyat bilan harakatlanayotgan jismning t=2 sekunddagi tezligini toping. A) 70 B) 84 C) 60 D) 74 11 / 25 tengsizlikning yechimi bo’lgan eng kichik natural sonni toping A) 1 B) 3 C) 5 D) 4 12 / 25 y>0 bo’lsin. To’g’riburchakning uchlari to’g’ri burchakli koordinatalar sistemasida qyuidagicha berilgan: A(0;0), B(0;y), C(-9;y) va D(-11;0). To’rtburchak diagonallarining o’tralari orasidagi masofani toping A) √22 B) √2 C) 1 D) 2 13 / 25 sin3x+cos3x≥0 tengsizligini yeching A) (-π/2+n π;- π/2+n π) B) [-π/9+2πn/3; 2π/9+2πn/3] C) [-π/9+n π/3;2 π/9+n π/3] D) ø 14 / 25 Uchlari soni 14 ta, qirralari soni esa 21 ta bo’lgan ko’pyoqning yoqlari sonini toping. A) 4 B) 16 C) 9 D) 8 15 / 25 sonini taqriban hisoblang. A) 5,01 B) 4,08 C) 5,08 D) 3,08 16 / 25 Qavariq ko’pburchakning har bir uchidan uchtadan qirra chiqadi. Agar bu ko’pyoqning qirralari soni 12 ta bo’lsa, uning nechta uchi va yog’i mavjud? A) 4;10 B) 4;11 C) 8;10 D) 4;18 17 / 25 f(x)=excosx funksiyasi uchun f ’(π/2) ni aniqlang. A. e-0.5π B. e0,5π C. eπ D. e-π A) e^(-π) B) e^(-0.5π) C) e^(π) D) e^(0.5π) 18 / 25 Moddiy nuqta qonuniyat bilan harakatlanmoqda, eng katta tezlanishga erishiladigan vaqtni toping. A) 7 B) 4 C) 5 D) 6 19 / 25 To’g’ri to’rtburchak shaklidagi yer maydoninig atrofini o’rashmoqchi. 480 m panjara yordamida eng ko’pi bilan necha kvadrat metr yer maydonni o’rash mumkin? A) 25600 B) 19600 C) 8100 D) 14400 20 / 25 F(x)=0.2sin(5x+12) funksiyasi uchun f(x) ni toping A) f(x)=-cos(5x+12) B) f(x)=-0,5sin(5x+12) C) f(x)=0.5cos(5x+12) D) f(x)=cos(5x+12) 21 / 25 f(x)=sin2x funksiyasining barcha boshlang’ich funksiyalarini toping. A) F(x)=0,5cos2x+C B) F(x)=-0,5cos2x+C C) F(x)=-2cos2x+C D) F(x)=2sin4x+c 22 / 25 Funksiyaning aniqlanish sohasini toping : y=logx-2(x2+7x-8) A) (8;+∞) B) (2;3)U(3;+∞) C) (-∞;-8)U(2;3)U(3;+∞) D) (-∞;-1)U(8;+∞) 23 / 25 2cosx+sinx=-2 tenglamaning [-π;π] kesmada nechta ildizi bor A) 3 B) Ø C) 2 D) 1 24 / 25 x=1, y=2x va y=2-x chiziqlari bilan chegaralangan sohaning yuzini toping A) log₃e B) ln4 C) ln3 D) log₄e 25 / 25 funksiyasining kamayish oralig’ini toping A) (0;+∞) B) ∅ C) (-∞;0] D) (-√5;√5) 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Tomonidan Wordpress Quiz plugin Author: InfoMaster Foydali bo'lsa mamnunmiz