Uy » Choraklik online testlar » Matematika choraklik » 11-sinf Matematika 4-chorak Matematika choraklik 11-sinf Matematika 4-chorak InfoMaster Aprel 20, 2021 697 Ko'rishlar 83 izohlar SaqlashSaqlanganOlib tashlandi 6 0 OMAD YOR BO'LSIN! Tomonidan yaratilgan InfoMaster 11-sinf Matematika 4-chorak Testni Salomov Sardor tayyorladi. 1 / 25 Tekislikdagi 1 m masofada yotgan nuqtadan ikkita teng og’ma o’tkazilgan. Agar og’malar perpendikulyar va tekislikka o’tkazilgan perpendikulyar bilan 600 ga teng burchaklar tashkil etsa, og’malarning asoslari orasidagi masofani toping A) 2√3 B) 4√2 C) 2√2 D) 1 2 / 25 Voleybol jamoasi 9 ta o’yinchidan iborat. Boshlang’ich tarkibga 6 ta o’yinchini nechta usul bilan tanlab olish mumkin A) 21 B) 42 C) 84 D) 168 3 / 25 2cosx+sinx=-2 tenglamaning [-π;π] kesmada nechta ildizi bor A) 3 B) 2 C) 1 D) Ø 4 / 25 Tomoni 4 ga teng bo’lgan teng tomonli uchburchak ichiga uchburchakning tomonlariga urinuvchi uchta teng doira joylashtirilgan. O’zaro urunuvchi doiralar yoylaridan hosil bo’lgan egri chiziqli uchburchakning yuzini toping A) 2√3-π B) (2-√3)(2-π) C) (2-√3)(2√3-π) D) (4-√3)(2√3-π) 5 / 25 Hisoblang: cos2330+cos2450-sin2600+cos2570 A) 0,75 B) 1,5 C) 0,5 D) 2,25 6 / 25 Havo shariga t[0;10] minut oralig’ida V(t)=t3+13t2+t+20 (m3) havo purkamoqda. t=10 minutdagi havo hajmini toping. A) 2025 B) 1023 C) 2330 D) 2300 7 / 25 f(x)=excosx funksiyasi uchun f ’(π/2) ni aniqlang. A. e-0.5π B. e0,5π C. eπ D. e-π A) e^(-0.5π) B) e^(π) C) e^(-π) D) e^(0.5π) 8 / 25 Moddiy nuqta qonuniyat bilan harakatlanmoqda, eng katta tezlanishga erishiladigan vaqtni toping. A) 7 B) 4 C) 5 D) 6 9 / 25 To’g’ri to’rtburchak shaklidagi yer maydoninig atrofini o’rashmoqchi. 480 m panjara yordamida eng ko’pi bilan necha kvadrat metr yer maydonni o’rash mumkin? A) 19600 B) 25600 C) 14400 D) 8100 10 / 25 sonini taqriban hisoblang. A) 5,08 B) 3,08 C) 4,08 D) 5,01 11 / 25 sin3x+cos3x≥0 tengsizligini yeching A) (-π/2+n π;- π/2+n π) B) ø C) [-π/9+2πn/3; 2π/9+2πn/3] D) [-π/9+n π/3;2 π/9+n π/3] 12 / 25 Ixtiyoriy kvadratga tashqi va ichki chizilgan aylanalar yuzlari nisbati a ga teng. Ixtiyoriy aylanaga ichki va tashqi chizilgan kvadratlar yuzlari nisbati b ga teng bolsa, a/b ni toping A) 1/2 B) 1 C) 4 D) 335 13 / 25 chiziqlar bilan chegaralangan shaklning yuzini toping A) 1 B) √2 C) 2 D) 0,5 14 / 25 Ushbu funksiyasining boshlang’ich funksiyasini toping A) (x+2)(x+1) B) lnIx-1I C) ln(|x+2|*|x+1|) D) lnI(x-2)(x-3)I 15 / 25 Uchlari soni 14 ta, qirralari soni esa 21 ta bo’lgan ko’pyoqning yoqlari sonini toping. A) 9 B) 4 C) 16 D) 8 16 / 25 Aylanaga o’tkazilgan vatar uni 5:7 nisbatda bo’ladi. Ushbu vatarga tiralgan, aylanaga ichki chizilgan katta burchakni toping A) 55° B) 125° C) 105° D) 75° 17 / 25 aniq integralni hisoblang A) 4 B) 6 C) 2,5 D) 2 18 / 25 Uchlari A(2;-3;4) va B(-2;4;5) nuqtalarda bo’lgan AB kesmasining uzunligini toping A) √24 B) √55 C) √19 D) √66 19 / 25 Murakkab funksiyaning hosilasini toping. y=x2sinx A) y’=2xsinx-x² B) y’=x²cosx-2xsinx C) y’=-2xsinx+x² D) y’=2xsinx+x²cosx 20 / 25 Limitni hisoblang: A) 3 B) -3 C) 4 D) -4 21 / 25 Funksiya hosilasini toping: f(x)=5 A) x B) 5 C) 10 D) 0 22 / 25 y=-3x3+2x2-4x+5 funksiyaga x0=-1 nuqtada o’tkazilgan urinma tenglamasining burchak koeffitsiyentini toping. A) 15 B) -17 C) 17 D) -13 23 / 25 Nargiza 4minutda 260ta so`zni terib, 7ta imloviy xatoga yo`l qo`ydi. Nargizaning matn terish sifatini aniqlang A) 0,6 B) 0,01 C) 0,5 D) 0,0269 24 / 25 A(1;-2;2), B(1;4;0), C(-4;1;1) va D(-5;-5;3) nuqtalar berilgan. AC va BD vektorlar orasidagi burchakni toping A) 52° B) 80° C) 15° D) 90° 25 / 25 f(x)=2x+3 funksiyasi uchun A(1;5) nuqtadan o’tuvchi boshlang’ich funksiyasini toping. A) F(x)=x²-3x-1 B) F(x)=x²+3x-1 C) F(x)=x²+3x+1 D) F(x)=x²-3x+1 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz