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11-sinf Matematika 4-chorak

InfoMaster

Aprel 20, 2021

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Tomonidan yaratilgan InfoMaster

11-sinf Matematika 4-chorak

Testni Salomov Sardor tayyorladi.

1 / 25

f(x)=sin2x funksiyasining barcha boshlang’ich funksiyalarini toping.

A) F(x)=-0,5cos2x+C

B) F(x)=0,5cos2x+C

C) F(x)=2sin4x+c

D) F(x)=-2cos2x+C

2 / 25

f(x)=(3x+2)² funksiyasining barcha boshlang’ich funksiyalarini toping.

A) F(x)=6x³+6x+4

B) F(x)=6x³+3x²-4

C) F(x)=6x³+3x²+4

D) F(x)=6x³+6x²+4

3 / 25

f(x)=e^xcosx funksiyasi uchun f ’(π/2) ni aniqlang.

A. e^-0.5π B. e^0,5π C. e^π D. e^-π

A) e^(-0.5π)

B) e^(-π)

C) e^(π)

D) e^(0.5π)

4 / 25

Havo shariga t $\in$ [0;10] minut oralig’ida V(t)=t³+13t²+t+20 (m³) havo purkamoqda. t=10 minutdagi havo hajmini toping.

A) 2300

B) 2025

C) 1023

D) 2330

5 / 25

A(-4;3;6) nuqtaning Oxz tekisligiga nisbatan simmrtrik nuqtasini toping.

A) (-4;-3;9)

B) (-8;-3;6)

C) (-4;-3;6)

D) (-4;-6;6)

6 / 25

Uchlari A(2;3;4) va B(-4;-5;-6) nuqtalarda bo’lgan AB kesmasining o’rtasining koordinatalarini toping.

A) (-1;-3;-1)

B) (-1;-1;-4)

C) (-1;-1;-1)

D) (-2;-4;-1)

7 / 25

Limitni hisoblang:

A) 4

B) -4

C) 3

D) -3

8 / 25

$f(x)=x^3+2x^2+x+3$ funksiyasining kamayish oralig’ini toping.

A) [-1;-1/3]

B) (-∞;-1)

C) (-1/3;+∞)

D) (-1;1/3)

9 / 25

Funksiyaning statsionar nuqtalarini toping $f(x)=2x^3-3x^2-12x+3$

A) x=-1, x=2

B) x=0, x=2

C) x=-1, x=3

D) x=3, x=2

10 / 25

$f(x)=x^3-2x^2+3x-2$ funksiya grafigiga x=4 abssissali nuqtada o`tkazilgan urinma tenglamasini tuzing

A) y=35x+30

B) y=35x

C) y=10x

D) y=20x+20

11 / 25

y=-3x³+2x²-4x+5 funksiyaga x₀=-1 nuqtada o’tkazilgan urinma tenglamasining burchak koeffitsiyentini toping.

A) -17

B) 17

C) -13

D) 15

12 / 25

$f(x)=x^4-8x^2+3$ funksiyaning [-4;1] kesmadagi eng kata qiymatini toping.

A) 131

B) -4

C) -13

D) 13

13 / 25

funksiyaning [-4;2] oraliqdagi eng katta qiymatini toping $f(x)=x^3+4.5x^2-9$

A) 17

B) 14

C) 18

D) 16

14 / 25

Murakkab funksiyaning hosilasini toping. y=x²sinx

A) y’=2xsinx+x²cosx

B) y’=2xsinx-x²

C) y’=-2xsinx+x²

D) y’=x²cosx-2xsinx

15 / 25

A(1;-2;2), B(1;4;0), C(-4;1;1) va D(-5;-5;3) nuqtalar berilgan. AC va BD vektorlar orasidagi burchakni toping

A) 15°

B) 52°

C) 90°

D) 80°

16 / 25

Agar f(x)=x² va bo`lsa ,f(g(2)) ni toping

A) 12

B) 0

C) 36

D) 16

17 / 25

Moddiy nuqta S(t)=5t³+3t²+2t+4 qonuniyat bilan harakatlanayotgan jismning t=2 sekunddagi tezligini toping.

A) 74

B) 60

C) 70

D) 84

18 / 25

chiziqlar bilan chegaralangan shaklning yuzini toping

A) 0,5

B) 1

C) 2

D) √2

19 / 25

Ixtiyoriy kvadratga tashqi va ichki chizilgan aylanalar yuzlari nisbati a ga teng. Ixtiyoriy aylanaga ichki va tashqi chizilgan kvadratlar yuzlari nisbati b ga teng bolsa, a/b ni toping

A) 1

B) 4

C) 1/2

D) 335

20 / 25

tengsizlikning yechimi bo’lgan eng kichik natural sonni toping

A) 3

B) 5

C) 4

D) 1

21 / 25

Bir burchagi 60⁰ bo’lgan to’g’ri burchakli uchburchakka tomoni 6 ga teng romb shunday ichki chizilganki, 60⁰ li burchak ular uchun umumiy, rombning barcha uchlari uchburchakning tomonlarida yotadi. Uchburchak yuzini toping

A) √3/2

B) (81√3)/2

C) (1√3)/2

D) (8√3)/2

22 / 25

Tomoni 4 ga teng bo’lgan teng tomonli uchburchak ichiga uchburchakning tomonlariga urinuvchi uchta teng doira joylashtirilgan. O’zaro urunuvchi doiralar yoylaridan hosil bo’lgan egri chiziqli uchburchakning yuzini toping

A) (2-√3)(2√3-π)

B) 2√3-π

C) (2-√3)(2-π)

D) (4-√3)(2√3-π)

23 / 25

x=1, y=2^x va y=2^-x chiziqlari bilan chegaralangan sohaning yuzini toping

A) log₃e

B) ln3

C) log₄e

D) ln4

24 / 25

Tekislikdagi 1 m masofada yotgan nuqtadan ikkita teng og’ma o’tkazilgan. Agar og’malar perpendikulyar va tekislikka o’tkazilgan perpendikulyar bilan 60⁰ ga teng burchaklar tashkil etsa, og’malarning asoslari orasidagi masofani toping

A) 4√2

B) 2√3

C) 1

D) 2√2

25 / 25

Hisoblang:

cos²33⁰+cos²45⁰-sin²60⁰+cos²57⁰