Uy » Choraklik online testlar » Matematika choraklik » 11-sinf Matematika 3-chorak Matematika choraklik 11-sinf Matematika 3-chorak InfoMaster Aprel 20, 2021 981 Ko'rishlar 8 izohlar SaqlashSaqlanganOlib tashlandi 3 1 OMAD YOR BO'LSIN! Tomonidan yaratilgan InfoMaster 11-sinf Matematika 3-chorak Testni Salomov Sardor tayyorladi. 1 / 25 To’g’riburchakli parallelepiped asosining tomonlari 7:24 nisbatda, diagonal kesimining yuzi 50dm2 ga teng. Yon sirtining yuzini toping. A) 135 dm² B) 124 dm C) 224 dm² D) 124 dm² 2 / 25 To’g’ri to’rtburchak shaklidagi yer maydoninig atrofini o’rashmoqchi. 480 m panjara yordamida eng ko’pi bilan necha kvadrat metr yer maydonni o’rash mumkin? A) 8100 B) 14400 C) 25600 D) 19600 3 / 25 Funksiyaning statsionar nuqtalarini toping A) x=0, x=2 B) x=-1, x=2 C) x=3, x=2 D) x=-1, x=3 4 / 25 f(x)=3x2-5x+4 va g(x)=4x-5 funksiyalarining urinmalari parallel bo’ladigan nuqtalarini toping. A) 0.5 B) 1.5 C) 0 D) 2 5 / 25 A(2;0;-3) va B(3;4;0) nuqtalar orasidagi masofani toping A) 16 B) 25 C) √26 D) √24 6 / 25 Funksiyaning kamayish oraliqlarini toping A) (-1;0) va (0;2) B) (-3;0) va (0;1) C) (-1;0) va (0;1) D) (-2;0) va (0;1) 7 / 25 funksiya grafigiga x=1 abssisssali nuqtadao`tkazilgan urinma tenglamasini yozing A) y=-x B) y=1/2 C) y=x D) y= 2x 8 / 25 Funksiya hosilasini toping f(x)=(2x+4)(3x+1) A) 12x B) 12x+14 C) 16x+14 D) 3x+1 9 / 25 Agar A(1;2;3), B(3;7;6) bo’lsa, A̅B̅ vector koordinatalarini toping A) (4;9;9) B) (2;5;3) C) (-2;-5;-3) D) (4;9;9) 10 / 25 Karim uyida 14 bet matn terib, 8ta imloviy xatoga yo’l qo’ydi. Agar 1 betda o’rtacha 380 ta so’z bo’lsa, Karim 100ta so’z terganda o’rtacha qancha xato qiladi? A) 0,15 B) 1,5 C) 0,25 D) 0,5 11 / 25 funksiyasining kamayish oralig’ini toping. A) (-1/3;+∞) B) (-∞;-1) C) [-1;-1/3] D) (-1;1/3) 12 / 25 funksiya grafigiga x=4 abssissali nuqtada o`tkazilgan urinma tenglamasini tuzing A) y=20x+20 B) y=35x C) y=35x+30 D) y=10x 13 / 25 Uchlari A(2;-3;4) va B(-2;4;5) nuqtalarda bo’lgan AB kesmasining uzunligini toping A) √24 B) √55 C) √66 D) √19 14 / 25 Uchlari A(4;0;1), B(5;-2;1), C(4;8;5) nuqtalarda bo’lgan uchburchakning AL bissektrisasi uzunligini toping A) 4 B) (4√2)/5 C) (2√5)/3 D) (4√2)3 15 / 25 Koordinatalar boshidan y=x2-4x+3 parabolaning simmetriya o’qigacha bo’lgan masofani toping. A) 4 B) 3 C) 1 D) 2 16 / 25 funksiyaning [-4;2] oraliqdagi eng katta qiymatini toping A) 17 B) 16 C) 14 D) 18 17 / 25 Nargiza 4minutda 260ta so`zni terib, 7ta imloviy xatoga yo`l qo`ydi. Nargizaning matn terish sifatini aniqlang A) 0,6 B) 0,01 C) 0,0269 D) 0,5 18 / 25 (x2+23x+23)(x2+x+23)=23x2 tenglama haqiyqiy ildizlari yig’indisini toping A) 23 B) -23 C) -24 D) 24 19 / 25 sin3x+cos3x≥0 tengsizligini yeching A) (-π/2+n π;- π/2+n π) B) ø C) [-π/9+2πn/3; 2π/9+2πn/3] D) [-π/9+n π/3;2 π/9+n π/3] 20 / 25 y>0 bo’lsin. To’g’riburchakning uchlari to’g’ri burchakli koordinatalar sistemasida qyuidagicha berilgan: A(0;0), B(0;y), C(-9;y) va D(-11;0). To’rtburchak diagonallarining o’tralari orasidagi masofani toping A) 1 B) 2 C) √22 D) √2 21 / 25 Trapetsiyaning kichik asosi 6 ga va yon tomoni 5 va 7 ga teng. Uning kata asosi ham butun son bo’lsa, perimetri eng ko’pi bilan nechaga teng bo’lishi mumkin A) 4 B) 1 C) 3 D) 3√2 22 / 25 Ushbu funksiyasining boshlang’ich funksiyasini toping A) ln(|x+2|*|x+1|) B) lnI(x-2)(x-3)I C) lnIx-1I D) (x+2)(x+1) 23 / 25 cos(2arctg(1/2)) ni hisoblang A) -37/35 B) 35/37 C) -35/37 D) 37/35 24 / 25 tengsizlikning yechimi bo’lgan eng kichik natural sonni toping A) 4 B) 5 C) 1 D) 3 25 / 25 Aylanaga o’tkazilgan vatar uni 5:7 nisbatda bo’ladi. Ushbu vatarga tiralgan, aylanaga ichki chizilgan katta burchakni toping A) 75° B) 125° C) 105° D) 55° 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz