Uy » Choraklik online testlar » Matematika choraklik » 11-sinf Matematika 3-chorak Matematika choraklik 11-sinf Matematika 3-chorak InfoMaster Aprel 20, 2021 1009 Ko'rishlar 8 izohlar SaqlashSaqlanganOlib tashlandi 3 0 OMAD YOR BO'LSIN! Tomonidan yaratilgan InfoMaster 11-sinf Matematika 3-chorak Testni Salomov Sardor tayyorladi. 1 / 25 To’g’riburchakli parallelepiped asosining tomonlari 7:24 nisbatda, diagonal kesimining yuzi 50dm2 ga teng. Yon sirtining yuzini toping. A) 135 dm² B) 124 dm C) 124 dm² D) 224 dm² 2 / 25 f(x)=excosx funksiyasi uchun f ’(π/2) ni aniqlang. A. e-0.5π B. e0,5π C. eπ D. e-π A) e^(-0.5π) B) e^(π) C) e^(0.5π) D) e^(-π) 3 / 25 Moddiy nuqta qonuniyat bilan harakatlanmoqda, eng katta tezlanishga erishiladigan vaqtni toping. A) 7 B) 5 C) 6 D) 4 4 / 25 f(x)=sin2x funksiyasining barcha boshlang’ich funksiyalarini toping. A) F(x)=-0,5cos2x+C B) F(x)=0,5cos2x+C C) F(x)=-2cos2x+C D) F(x)=2sin4x+c 5 / 25 Kub to’la sirtining yuzi 105,84 sm2 bo’lsa, uning har bir yog’i yuzini va qirrasining uzunligini toping. A) 17,68 dm²; 4,2 dm B) 17,64 dm; 4,2 dm C) 17,64 dm²; 4,9 dm D) 17,64 dm²; 4,2 dm 6 / 25 To’g’ri to’rtburchak shaklidagi yer maydoninig atrofini o’rashmoqchi. 480 m panjara yordamida eng ko’pi bilan necha kvadrat metr yer maydonni o’rash mumkin? A) 19600 B) 8100 C) 14400 D) 25600 7 / 25 funksiya uchun y=2x-1 to`g`ri chiziqqa parallel bo`lgan urinma tenglamasini yozing A) y=2x+3 B) y=2x-2,25 C) y=3x-2,2 D) y=2x 8 / 25 A(-4;3;6) nuqtaning Oxz tekisligiga nisbatan simmrtrik nuqtasini toping. A) (-8;-3;6) B) (-4;-6;6) C) (-4;-3;6) D) (-4;-3;9) 9 / 25 Agar A(1;2;3), B(3;7;6) bo’lsa, A̅B̅ vector koordinatalarini toping A) (2;5;3) B) (4;9;9) C) (4;9;9) D) (-2;-5;-3) 10 / 25 Funksiya hosilasini toping: A) 12x+12 B) 21x²-10x C) 14x+12 D) 12x²-12 11 / 25 Uchlari A(4;0;1), B(5;-2;1), C(4;8;5) nuqtalarda bo’lgan uchburchakning AL bissektrisasi uzunligini toping A) (4√2)/5 B) (2√5)/3 C) (4√2)3 D) 4 12 / 25 y=-3x3+2x2-4x+5 funksiyaga x0=-1 nuqtada o’tkazilgan urinma tenglamasining burchak koeffitsiyentini toping. A) 15 B) -13 C) -17 D) 17 13 / 25 limitni hisoblang A) 6 B) 5 C) 0 D) 7 14 / 25 funksiya hosilasining x0=-2 nuqtadagi qiymatini hisoblang. A) 38/961 B) -38/961 C) -38/31 D) 38/31 15 / 25 Uchlari A(2;-3;4) va B(-2;4;5) nuqtalarda bo’lgan AB kesmasining uzunligini toping A) √55 B) √66 C) √24 D) √19 16 / 25 Funksiyaning kamayish oraliqlarini toping A) (-1;0) va (0;1) B) (-1;0) va (0;2) C) (-2;0) va (0;1) D) (-3;0) va (0;1) 17 / 25 Karim 3 minutda 213ta so`zni terib , 6ta imloviy xatoga yo`l qo`ydi. Karimning matn terish sifatini toping. A) 0,0282 B) 0,0321 C) 0,3265 D) 0,623 18 / 25 Moddiy nuqtaning berilgan t vaqtdagi tezligini hisoblang: , t=5 A) 70 B) 90 C) 75 D) 80 19 / 25 funksiya grafigiga x=4 abssissali nuqtada o`tkazilgan urinma tenglamasini tuzing A) y=20x+20 B) y=35x+30 C) y=35x D) y=10x 20 / 25 Agar f(x)=x² va bo`lsa ,f(g(-4)) ni toping A) 36 B) 12 C) 0 D) -12 21 / 25 y>0 bo’lsin. To’g’riburchakning uchlari to’g’ri burchakli koordinatalar sistemasida qyuidagicha berilgan: A(0;0), B(0;y), C(-9;y) va D(-11;0). To’rtburchak diagonallarining o’tralari orasidagi masofani toping A) 2 B) 1 C) √2 D) √22 22 / 25 Silindr shaklidagi idishga 6 sm3 suv solindi. Idishga detal to’liq cho’ktirilganda, suv sathi 1,5 marta ko’tarildi. Detal hajmini aniqlang A) 1 B) 14 C) 3 D) 23 23 / 25 Ushbu funksiyasining boshlang’ich funksiyasini toping A) ln(|x+2|*|x+1|) B) (x+2)(x+1) C) lnI(x-2)(x-3)I D) lnIx-1I 24 / 25 Trapetsiyaning kichik asosi 6 ga va yon tomoni 5 va 7 ga teng. Uning kata asosi ham butun son bo’lsa, perimetri eng ko’pi bilan nechaga teng bo’lishi mumkin A) 3 B) 1 C) 3√2 D) 4 25 / 25 chiziqlar bilan chegaralangan shaklning yuzini toping A) 1 B) √2 C) 0,5 D) 2 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz