Uy » Choraklik online testlar » Matematika choraklik » 11-sinf Matematika 3-chorak Matematika choraklik 11-sinf Matematika 3-chorak InfoMaster Aprel 20, 2021 995 Ko'rishlar 8 izohlar SaqlashSaqlanganOlib tashlandi 3 1 OMAD YOR BO'LSIN! Tomonidan yaratilgan InfoMaster 11-sinf Matematika 3-chorak Testni Salomov Sardor tayyorladi. 1 / 25 Uchlari soni 14 ta, qirralari soni esa 21 ta bo’lgan ko’pyoqning yoqlari sonini toping. A) 4 B) 16 C) 9 D) 8 2 / 25 Muntazam uchburchak tomoni 3 ga teng. Uchburchak tomonlari o’rtalari tutashtirilib, muntazam uchburchaklar hosil qilindi. Ichma-ich joylashgan uchburchaklar yuzlari yig’indisini toping A) 2 B) 2√3 C) 3√3 D) 3 3 / 25 Ixtiyoriy kvadratga tashqi va ichki chizilgan aylanalar yuzlari nisbati a ga teng. Ixtiyoriy aylanaga ichki va tashqi chizilgan kvadratlar yuzlari nisbati b ga teng bolsa, a/b ni toping A) 4 B) 335 C) 1/2 D) 1 4 / 25 Aylanaga o’tkazilgan vatar uni 5:7 nisbatda bo’ladi. Ushbu vatarga tiralgan, aylanaga ichki chizilgan katta burchakni toping A) 55° B) 105° C) 125° D) 75° 5 / 25 chiziqlar bilan chegaralangan shaklning yuzini toping A) 1 B) 2 C) √2 D) 0,5 6 / 25 y>0 bo’lsin. To’g’riburchakning uchlari to’g’ri burchakli koordinatalar sistemasida qyuidagicha berilgan: A(0;0), B(0;y), C(-9;y) va D(-11;0). To’rtburchak diagonallarining o’tralari orasidagi masofani toping A) √22 B) 1 C) √2 D) 2 7 / 25 Trapetsiyaning kichik asosi 6 ga va yon tomoni 5 va 7 ga teng. Uning kata asosi ham butun son bo’lsa, perimetri eng ko’pi bilan nechaga teng bo’lishi mumkin A) 4 B) 3√2 C) 3 D) 1 8 / 25 (x2+23x+23)(x2+x+23)=23x2 tenglama haqiyqiy ildizlari yig’indisini toping A) 24 B) -23 C) 23 D) -24 9 / 25 f(x)=(3x+2)2 funksiyasining barcha boshlang’ich funksiyalarini toping. A) F(x)=6x³+3x²+4 B) F(x)=6x³+6x²+4 C) F(x)=6x³+3x²-4 D) F(x)=6x³+6x+4 10 / 25 F(x)=0.2sin(5x+12) funksiyasi uchun f(x) ni toping A) f(x)=-0,5sin(5x+12) B) f(x)=0.5cos(5x+12) C) f(x)=cos(5x+12) D) f(x)=-cos(5x+12) 11 / 25 funksiya grafigiga x=4 abssissali nuqtada o`tkazilgan urinma tenglamasini tuzing A) y=10x B) y=20x+20 C) y=35x D) y=35x+30 12 / 25 Karim uyida 14 bet matn terib, 8ta imloviy xatoga yo’l qo’ydi. Agar 1 betda o’rtacha 380 ta so’z bo’lsa, Karim 100ta so’z terganda o’rtacha qancha xato qiladi? A) 0,5 B) 0,15 C) 1,5 D) 0,25 13 / 25 funksiya hosilasining x0=-2 nuqtadagi qiymatini hisoblang. A) -38/961 B) 38/31 C) -38/31 D) 38/961 14 / 25 funksiyaning [-4;2] oraliqdagi eng katta qiymatini toping A) 17 B) 18 C) 16 D) 14 15 / 25 Limitni hisoblang: A) -4 B) 3 C) -3 D) 4 16 / 25 f(x)=2x+3 funksiyasi uchun A(1;5) nuqtadan o’tuvchi boshlang’ich funksiyasini toping. A) F(x)=x²-3x+1 B) F(x)=x²+3x-1 C) F(x)=x²+3x+1 D) F(x)=x²-3x-1 17 / 25 funksiya grafigiga x=1 abssisssali nuqtadao`tkazilgan urinma tenglamasini yozing A) y=x B) y=-x C) y= 2x D) y=1/2 18 / 25 y=-3x3+2x2-4x+5 funksiyaga x0=-1 nuqtada o’tkazilgan urinma tenglamasining burchak koeffitsiyentini toping. A) -13 B) -17 C) 15 D) 17 19 / 25 Uchlari A(4;0;1), B(5;-2;1), C(4;8;5) nuqtalarda bo’lgan uchburchakning AL bissektrisasi uzunligini toping A) (2√5)/3 B) (4√2)3 C) (4√2)/5 D) 4 20 / 25 Agar f(x)=x² va bo`lsa ,f(g(2)) ni toping A) 0 B) 12 C) 36 D) 16 21 / 25 Moddiy nuqta S(t)=5t3+3t2+2t+4 qonuniyat bilan harakatlanayotgan jismning t=2 sekunddagi tezligini toping. A) 60 B) 84 C) 70 D) 74 22 / 25 funksiyasining kamayish oralig’ini toping. A) [-1;-1/3] B) (-∞;-1) C) (-1;1/3) D) (-1/3;+∞) 23 / 25 Agar f(x)=x² va bo`lsa ,f(g(-4)) ni toping A) 12 B) 0 C) 36 D) -12 24 / 25 Murakkab funksiyaning hosilasini toping. y=x2sinx A) y’=-2xsinx+x² B) y’=2xsinx+x²cosx C) y’=x²cosx-2xsinx D) y’=2xsinx-x² 25 / 25 tgx funksiya hosilasini toping A) cosx B) sinx C) 1/sinx D) 1/cos²x 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz