Bo'lim: Matematika choraklik

6-sinf Matematika 1-chorak

Oktabr 26, 2021Oktabr 26, 2021 da chop etilgan InfoMaster tomonidan 6-sinf Matematika 1-chorak ga 2 fikr bildirilgan

OMAD YOR BO'LSIN!

Tomonidan yaratilgan InfoMaster

6-sinf Matematika 1-chorak

2-sinov

Ismi familiyangizni kriting!

1 / 25

Tub ko’paytuvchilarga ajrating.

A) 5175 = 5² * 3² *23

B) 5175 = 5 * 7 * 3

C) 5175 = 5 * 72 * 3

D) To'g'ri javob yo'q

2 / 25

To’g’ri to’rtburchakning bo’yi 25 sm, eni esa 20 sm. Ularning perimetrini toping?

A) 85

B) 90

C) 100

D) 95

3 / 25

Ekuk (28, 70, 140) topilsin.

A) 280

B) 130

C) 140

D) 70

4 / 25

Tengsizlik nechta tub yechimga ega: 54 < x ≤ 79

A) 24

B) 6

C) 5

D) 25

5 / 25

Kasrni airing:

A) 16/135

B) 18/60

C) 1/2

D) 8/90

6 / 25

Tenglamani yechimini toping:

A) 13

B) 15

C) 16

D) 14

7 / 25

Sonning bo’luvchilari nechta: 58

A) 5

B) 2

C) 3

D) 4

8 / 25

30 soni nechta bo`luvchiga ega ?

A) 5

B) 8

C) 6

D) 4

9 / 25

1; 2; 3; 15; 17; 21; 28; 47; 57; 89; 144; 300; 205 sonlari ichida nechta murakkab son bor ?

A) 5

B) 8

C) 6

D) 7

10 / 25

3 ta ketma-ket natural sonlarning ko`paytmasi quyidagi sonlarning qaysi biriga albatta bo`linadi ?

A) 6

B) 12

C) 24

D) 5

11 / 25

Ekub (215, 435, 600) topilsin

A) 3

B) 0

C) 2

D) 5

12 / 25

Poezdda 936 yo’lovchi bor edi. Erkaklar ayollardan 7 marta, ayollar esa 5 marta ko’p. Poezdda qancha ayol bo’lgan?

A) 240

B) 390

C) 360

D) 25

13 / 25

Hisoblang:

A) 4/20

B) 1/2

C) 1/5

D) 6/40

14 / 25

Ekub (21, 84) topilsin.

A) 3

B) 7

C) 21

D) 14

15 / 25

9 ga bo`linadigan sonni toping.

A) 2576

B) 1075

C) 6534

D) 2341

16 / 25

Gektarlarda ifodalang: 500 000 m²

A) 5000 g

B) 5 g

C) 500 g

D) 50 g

17 / 25

Qaysi juftlik o`zaro tub sonlardan iborat ?

A) (34; 45)

B) (12; 15)

C) (8; 10)

D) ( 28; 24)

18 / 25

kasrni qisqartiring.

A) 5/29

B) 1/25

C) 1/2

D) 2/5

19 / 25

Ikkinchi raqami 4 bo’lgan uch xonali son 9 ga va 2 ga bo’linadi, ammo 5 ga bo’linmaydi. Shu sonni toping?

A) 243

B) 944

C) 181

D) 144

20 / 25

Amallarni bajaring: 7758 : 18 + 720 : 8

A) 521

B) 510

C) 500

D) 511

21 / 25

Tenglamani yeching: x : 20 = 10

A) 2000

B) 20

C) 200

D) 2

22 / 25

Bir son ikkinchisidan 20 taga ko’p ularning yig’indisi 70 ga teng. Bu sonlarni toping?

A) 11 va 38

B) 25 va 45

C) 55 va 15

D) 30 va 40

23 / 25

Ayirmani toping:

A) 241/12

B) 243/12

C) 483/24

D) 121/12

24 / 25

Yulduzcha o`rniga qanday raqam qo`yish mumkin: 196 = 2 · 2 · * · 7

A) 7

B) 3

C) 11

D) 13

25 / 25

Ekuk (106, 159, 530) topilsin.

A) 3000

B) 3180

C) 150

D) 3280

Baholash mezoni

86%-100% 5 baho

71%-85% 4 baho

56%-70% 3 baho

55% va kamiga 2 baho

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Matematika choraklik

8-sinf Matematika 4-chorak №2

May 17, 2021May 18, 2021 da chop etilgan InfoMaster tomonidan 8-sinf Matematika 4-chorak №2 ga 1 fikr bildirilgan

Yaratilgan sanasi May 18, 2021 tomonidan InfoMaster

8-sinf Matematika 4-chorak

Ismi familiyangizni kriting!

Ism

1 / 25

Kvadrat tenglamani yeching $x^{2}+x-6$ =0

A) x₁=0, x₂=2

B) x₁=3, x₂=2

C) x₁=-3, x₂=-2

D) x₁=-3, x₂=2

2 / 25

$\vec{a}(m;4)$ vektorning uzunligi 5 ga teng. m ni toping.

A) 2

B) 3

C) 5

D) 4

3 / 25

Tenglamani yeching $x^{2}=64$

A) x₁,₂=-8

B) x₁,₂=±8

C) x₁,₂=√64

D) x₁,₂=8

4 / 25

Kvadrat tenglamani yeching $x^{2}-7x+10=0$

A) ø

B) x₁=-5, x₂=2

C) x₁=2, x₂=5

D) x₁=-2, x₂=5

5 / 25

Tenglamani yeching

A) x=-25

B) x=25

C) x=√25

D) x₁,₂=±25

6 / 25

$\vec{a}=5$ bo'lsa, $4\vec{a}-3$ vektorni hisoblang.

A) 10

B) 12

C) 15

D) 17

7 / 25

Ikki soning ayirmasi 3 ga, ularning ko`paytmasi 28 ga teng. Shu sonlarni toping

A) 5 va 2

B) 7 va 14

C) 7 va 4

D) 17 va 14

8 / 25

Rombning yuzi 80 $cm^{2}$ , diagonallaridan bin 20 cm ga teng. Shu rombning ikkinchi diagonalini toping.

A) 20

B) 4

C) 10

D) 8

9 / 25

Tenglmalar sistemasini yeching

A) x=1 , y=2

B) x=-2 , y=1

C) (1;4) va (4;1)

D) x=-4 , y=-1

10 / 25

5 : 13 sonini 0,001 gacha aniqlikdagi o’nli kasr ko’rinishida tasvirlang:

A) 0,835

B) 0,538

C) 0,853

D) 0,385

11 / 25

Parallelogrammning tomoni 16 cm ga, unga tushirilgan balandlik esa 9 cm ga teng. Shu parallelogrammga tengdosh kvadratning yuzini toping.

A) 12

B) 225

C) 15

D) 144

12 / 25

x ning qanday qiymatida funksiyaning qiymati 1 ga teng bo’ladi

A) 17/8

B) 12/13

C) 15/8

D) 16/10

13 / 25

Ta'rifni to'ldiring. Ikala tamoni parallel, qolgan tamonlari parallel bo'lmagan to'rtburchak .... deb ataladi.

A) parallelogramm

B) kvadrat

C) romb

D) trapetsiya

14 / 25

Kvadrat tenglamani yeching $x^{2}+7x+6$ =0

A) ø

B) x₁=0, x₂=-2

C) x₁=-6, x₂=-1

D) x₁=-1, x₂=1

15 / 25

Qanday vetorlar qarama-qarshi vektorlar deyiladi?

A) Yig'indisi nolga teng bo'lgan vektorlar

B) Bo'linmasi nolga teng bo'lgan vektorlar

C) Ko'paytmasi nolga teng bo'lgan vektorlar

D) Ayirmasi nolga teng bo'lgan vektorlar

16 / 25

Yuzi 400 $dm^{2}$ ga teng bo‘lgan kvadratning perimetrini toping.

A) 80

B) 120

C) 100

D) 160

17 / 25

106 ni kvadirati toping.

A) 1236

B) 11225

C) 1234

D) 11236

18 / 25

17 : 25 sonini 0,1 gacha aniqlikda o’nli kasr ko’rinishida tasvirlang:

A) 0,9

B) 0,8

C) 0,7

D) 0,5

19 / 25

Hisoblang: $\sqrt{28-12}$

A) 4

B) -4

C) 16

D) 3

20 / 25

A(-1;4) va B(3;9) nuqtalar berilgan bo'lsa $\vec{AB}$ ni toping.

A) (-1;5)

B) (10;-1)

C) (4;5)

D) (5;4)

21 / 25

7x+5 $\geq$ 3(x-1)-4x tengsizlikning yechimi bo`ladigan eng kichik butun sonni toping.

A) x=2

B) x=-1

C) x=1

D) x=-2

22 / 25

4 ga bo`lganda 3 qoldiq, 10 ga bo`lganda 1 qoldiq chiqadigan va ikkinchi bo`linma birinchi bo`linmadan 13 ta kam bo`ladigan natural sonni toping.

A) 91

B) 87

C) 81

D) 95

23 / 25

Tenglamani yeching $x^{4}-5x^{2}+4=0$

A) x₁,₂=±4 ,x₃,₄=1

B) x₁,₂=±1 ,x₃,₄=±2

C) x₁,₂=±4 ,x₃,₄=-1

D) x₁,₂=1 ,x₃,₄=±2

24 / 25

Kvadrat tenglamani yeching $x^{2}+x+1=0$

A) ø

B) x₁=2, x₂=0

C) x₁=-2, x₂=-2

D) x₁=-1, x₂=1

25 / 25

Teng yonli trapetsiyaning diagonallari o‘zaro perpendikular va balandligi 8 cm ga teng. Shu trapetsiyaning yuzini toping.

A) 64

B) 55

C) 36

D) 45

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Matematika choraklik

5-sinf Matematika 4-chorak

May 10, 2021May 12, 2021 da chop etilgan InfoMaster tomonidan 5-sinf Matematika 4-chorak ga 1 fikr bildirilgan

OMAD YOR BO'LSIN!

Tomonidan yaratilgan InfoMaster

5-sinf Matematika 4-chorak

Testni Shirinboyev Temurbek tayyorladi!

Ismi familiyangizni kriting!

Ism

1 / 25

Yig’indining oxirgi raqamini toping. $\large 7777^{222}+2222^{7777}$

A) 0

B) 3

C) 8

D) 1

2 / 25

1* 2* 3*......74* 75 ko’paytma nechta nol bilan tugaydi?

A) 16

B) 11

C) 17

D) 18

3 / 25

1041011021 sonining raqamlari yig’indisini kvadratni toping.

A) 124

B) 123

C) 121

D) 122

4 / 25

30 gacha bo’lgan tub sonlar ko’paytmasining oxirgi raqamini toping.

A) 7

B) 1

C) 0

D) 5

5 / 25

80 va 60 sonlarining EKUBidan 15 ning natural bo’luvchilari sonini ayiring.

A) 6

B) 26

C) 16

D) 14

6 / 25

≤textarea≥ elementining readonly atributi vazifasini toping.

A) element ichidagi yozuvni o‘zgartirib bo‘lmaydi, faqat o‘qish mumkin bo‘lgan holga keltiradi.

B) foydalanuvchi tomonidan kiritilishi mumkin bo‘lgan maksimal belgilar soni.

C) matn yozish uchun ajratilgan joy uzunligi belgilar soni bilan ifodalanadi

D) matn yozish uchun ajratilgan joy balandligi shu sondan so‘ng pastga tushish uchun aylantirgich hosil bo‘ladi

7 / 25

≤input type="checkbox" /≥ ushbu element qanday hollarda ishlatiladi.

A) 740374

B) bir necha tanlovni amalga oshiruvchi bayroqchani hosil qiladi;

C) 74347

D) bir necha tanlovdan faqat bittasini tanlash imkonini beradi;

E) 740347

F) 704347

G) bir qatorli matn kiritish uchun ishlatiladi

H) oddiy matnli element, asosan, parol yozish uchun ishlatiladi;

8 / 25

≤form≥ tegining method atributi qiymatining vazifasini toping.

A) forma ma’lumotlarini jo‘natish usuli.

B) a va b javoblar

C) formada har xil ko‘rinishdagi elementlarni hosil qiladi.

D) sonli ifoda

E) harfiy ifoda

F) qavsli misol

G) formaga nom berish (bu nom skriptlar yozishda ishlatiladi)

H) forma orqali jo‘natilayotgan ma’lumotlar qaysi sahifada qayta ishlanishi kerakligi beriladi.

9 / 25

Kasr sonni 0,01 ga bo’lish qanday songa ko`paytirish demakdir.

A) 100

B) 0,01

C) 1000

D) 10

10 / 25

Uchburchak burchaklari yig`indisi …….teng

A) 180

B) 270

C) 360

D) 250

11 / 25

Ko’paytirishni bajarish: 12.42 * 0,621;

A) 6,3428

B) 7,71282

C) 5,83549

D) 7,83597

12 / 25

90^o kichik bo`lgan burchakka……deyiladi

A) To’g’ri burchak

B) O’tkir burchak

C) Yoyiq burchak

D) O’tmas burchak

13 / 25

Sonni foiziga aylantirish uchun uni…….ko`paytirish.

A) 200 ga

B) 50 ga

C) 150 ga

D) 100 ga

14 / 25

Tenglamani yeching:3,08 : y = 4

A) 0,48

B) 12,32

C) 4,32

D) 0,77

15 / 25

4050:…=75tenglikda tushurib qoldirilgan son qaysi

A) 55

B) 75

C) 60

D) 54

16 / 25

Kasrni bo’linma ko’rinishida ifodalang va uning qiymatini toping:

A) 101 : 3131

B) 31 : 31 : 101

C) 3131 : 101

D) 101/3131

17 / 25

Tenglamani yeching: 21 * x = 903

A) 43

B) 54

C) 36

D) 28

18 / 25

Kubning hajmini 216 bo'lsa uning qirrasini toping.

A) 4

B) 8

C) 6

D) 5

19 / 25

Hisoblang: 15*(128:4)+12

A) 677

B) 492

C) 470

D) 577

20 / 25

Hisoblang: 2570 +7534

A) 52340

B) 56302

C) 50500

D) 50104

21 / 25

To’g’ri to’rtburchakning enini toping.

A) 2,11/13

B) 3,15/13

C) 2,14/13

D) 4,11/13

22 / 25

Massasi 4/15 kg bo’lgan pamidorga, 7/15 kg bodring va 2/15 kg piyoz qo’shilib salat tayyorlandi. Salatning massasini toping?

A) 13/45 kg

B) 11/15 kg

C) 11/45 kg

D) 13/15 kg

23 / 25

Millimetrda ifodalang:4 dm 6 sm 7 mm

A) 4670 mm

B) 4,67 mm

C) 467 mm

D) 46 mm

24 / 25

Yig’indini songa bo’lish qoidasiga ko’ra ifodaning qiymatini toping: (34 + 51) : 17;

A) 17

B) 5

C) 16

D) 12

25 / 25

Sonlarni yig’indisi toping. 112, 85, 2333;

A) 2530

B) 3446

C) 2624

D) 4940

Baholash mezoni

86%-100% 5 baho

71%-85% 4 baho

56%-70% 3 baho

55% va kamiga 2 baho

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Matematika choraklik

11-sinf Matematika 4-chorak

Aprel 17, 2021Aprel 20, 2021 da chop etilgan InfoMaster tomonidan 11-sinf Matematika 4-chorak ga 5 fikr bildirilgan

OMAD YOR BO'LSIN!

Tomonidan yaratilgan InfoMaster

11-sinf Matematika 4-chorak

Testni Salomov Sardor tayyorladi.

1 / 25

f(x)=sin2x funksiyasining barcha boshlang’ich funksiyalarini toping.

A) F(x)=-2cos2x+C

B) F(x)=2sin4x+c

C) F(x)=-0,5cos2x+C

D) F(x)=0,5cos2x+C

2 / 25

To’g’riburchakli parallelepiped asosining tomonlari 7:24 nisbatda, diagonal kesimining yuzi 50dm² ga teng. Yon sirtining yuzini toping.

A) 124 dm²

B) 224 dm²

C) 124 dm

D) 135 dm²

3 / 25

Voleybol jamoasi 9 ta o’yinchidan iborat. Boshlang’ich tarkibga 6 ta o’yinchini nechta usul bilan tanlab olish mumkin

A) 168

B) 84

C) 21

D) 42

4 / 25

x=1, y=2^x va y=2^-x chiziqlari bilan chegaralangan sohaning yuzini toping

A) ln4

B) log₄e

C) ln3

D) log₃e

5 / 25

Agar f(x)=6+5tg²2x bo’lsa, f^'(π) ni toping

A) 1

B) 5

C) 0

D) 3

6 / 25

B,C,D,E nuqtalar aylanadagi, A esa aylanadan tashqaridagi nuqtalar. D nuqta AE kesmada, B esa AC kesmada yotadi. Agar AE=12 va AC=16 bo’lsa, BE vatar uzunligining CD vatar uzunligiga nisbatini toping

A) 3/4

B) 3

C) 4

D) 1

7 / 25

chiziqlar bilan chegaralangan shaklning yuzini toping

A) 0,5

B) 2

C) √2

D) 1

8 / 25

aniq integralni hisoblang

A) 2,5

B) 6

C) 4

D) 2

9 / 25

cos(2arctg(1/2)) ni hisoblang

A) -35/37

B) 37/35

C) 35/37

D) -37/35

10 / 25

cos15⁰*cos45⁰ *cos75⁰ ni hisoblang

A) √8/2

B) √2

C) √2/2

D) 2√2

11 / 25

Aylanaga o’tkazilgan vatar uni 5:7 nisbatda bo’ladi. Ushbu vatarga tiralgan, aylanaga ichki chizilgan katta burchakni toping

A) 55°

B) 125°

C) 105°

D) 75°

12 / 25

Ixtiyoriy kvadratga tashqi va ichki chizilgan aylanalar yuzlari nisbati a ga teng. Ixtiyoriy aylanaga ichki va tashqi chizilgan kvadratlar yuzlari nisbati b ga teng bolsa, a/b ni toping

A) 4

B) 1

C) 1/2

D) 335

13 / 25

Moddiy nuqta S(t)=5t³+3t²+2t+4 qonuniyat bilan harakatlanayotgan jismning t=2 sekunddagi tezligini toping.

A) 60

B) 74

C) 70

D) 84

14 / 25

Agar f(x)=x² va bo`lsa ,f(g(-4)) ni toping

A) -12

B) 0

C) 12

D) 36

15 / 25

Murakkab funksiyaning hosilasini toping. y=x²sinx

A) y’=-2xsinx+x²

B) y’=2xsinx+x²cosx

C) y’=2xsinx-x²

D) y’=x²cosx-2xsinx

16 / 25

A(2;0;-3) va B(3;4;0) nuqtalar orasidagi masofani toping

A) 25

B) √24

C) √26

D) 16

17 / 25

Karim uyida 14 bet matn terib, 8ta imloviy xatoga yo’l qo’ydi. Agar 1 betda o’rtacha 380 ta so’z bo’lsa, Karim 100ta so’z terganda o’rtacha qancha xato qiladi?

A) 1,5

B) 0,5

C) 0,15

D) 0,25

18 / 25

$f(x)=x^3-2x^2$ funksiya grafigiga x=1 abssisssali nuqtadao`tkazilgan urinma tenglamasini yozing

A) y=-x

B) y=1/2

C) y= 2x

D) y=x

19 / 25

$\lim_{x\rightarrow -1}(5-2x)$ limitni hisoblang

A) 5

B) 7

C) 0

D) 6

20 / 25

Agar f(x)=x² va bo`lsa ,f(g(2)) ni toping

A) 36

B) 0

C) 12

D) 16

21 / 25

funksiya hosilasining x₀=-2 nuqtadagi qiymatini hisoblang.

A) -38/961

B) 38/31

C) -38/31

D) 38/961

22 / 25

Agar A(1;2;3), B(3;7;6) bo’lsa, A̅B̅ vector koordinatalarini toping

A) (4;9;9)

B) (2;5;3)

C) (-2;-5;-3)

D) (4;9;9)

23 / 25

Uchlari A(2;3;4) va B(-4;-5;-6) nuqtalarda bo’lgan AB kesmasining o’rtasining koordinatalarini toping.

A) (-2;-4;-1)

B) (-1;-1;-4)

C) (-1;-3;-1)

D) (-1;-1;-1)

24 / 25

$f(x)=x^2-3x+4$ funksiya uchun y=2x-1 to`g`ri chiziqqa parallel bo`lgan urinma tenglamasini yozing

A) y=2x-2,25

B) y=2x

C) y=2x+3

D) y=3x-2,2

25 / 25

Funksiya hosilasini toping

f(x)=(2x+4)(3x+1)

A) 3x+1

B) 16x+14

C) 12x+14

D) 12x

Baholash mezoni

86%-100% 5 baho

71%-85% 4 baho

56%-70% 3 baho

55% va kamiga 2 baho

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Matematika choraklik

11-sinf Matematika 3-chorak

Aprel 17, 2021Aprel 20, 2021 da chop etilgan InfoMaster tomonidan 11-sinf Matematika 3-chorak ga 1 fikr bildirilgan

OMAD YOR BO'LSIN!

Tomonidan yaratilgan InfoMaster

11-sinf Matematika 3-chorak

Testni Salomov Sardor tayyorladi.

1 / 25

Limitni hisoblang:

A) -4

B) 4

C) -3

D) 3

2 / 25

Uchlari A(2;3;4) va B(-4;-5;-6) nuqtalarda bo’lgan AB kesmasining o’rtasining koordinatalarini toping.

A) (-1;-3;-1)

B) (-1;-1;-1)

C) (-1;-1;-4)

D) (-2;-4;-1)

3 / 25

funksiya hosilasining x₀=-2 nuqtadagi qiymatini hisoblang.

A) 38/31

B) 38/961

C) -38/961

D) -38/31

4 / 25

Karim 3 minutda 213ta so`zni terib , 6ta imloviy xatoga yo`l qo`ydi. Karimning matn terish sifatini toping.

A) 0,3265

B) 0,623

C) 0,0321

D) 0,0282

5 / 25

tgx funksiya hosilasini toping

A) cosx

B) 1/sinx

C) 1/cos²x

D) sinx

6 / 25

$f(x)=x^2-3x+4$ funksiya uchun y=2x-1 to`g`ri chiziqqa parallel bo`lgan urinma tenglamasini yozing

A) y=2x+3

B) y=2x

C) y=2x-2,25

D) y=3x-2,2

7 / 25

Agar A(1;2;3), B(3;7;6) bo’lsa, A̅B̅ vector koordinatalarini toping

A) (4;9;9)

B) (2;5;3)

C) (4;9;9)

D) (-2;-5;-3)

8 / 25

$f(x)=x^3-2x^2$ funksiya grafigiga x=1 abssisssali nuqtadao`tkazilgan urinma tenglamasini yozing

A) y=x

B) y= 2x

C) y=1/2

D) y=-x

9 / 25

y=-3x³+2x²-4x+5 funksiyaga x₀=-1 nuqtada o’tkazilgan urinma tenglamasining burchak koeffitsiyentini toping.

A) 15

B) -13

C) -17

D) 17

10 / 25

Karim uyida 14 bet matn terib, 8ta imloviy xatoga yo’l qo’ydi. Agar 1 betda o’rtacha 380 ta so’z bo’lsa, Karim 100ta so’z terganda o’rtacha qancha xato qiladi?

A) 1,5

B) 0,15

C) 0,25

D) 0,5

11 / 25

$f(x)=x^4-8x^2+3$ funksiyaning [-4;1] kesmadagi eng kata qiymatini toping.

A) 13

B) 131

C) -4

D) -13

12 / 25

Koordinatalar boshidan y=x²-4x+3 parabolaning simmetriya o’qigacha bo’lgan masofani toping.

A) 3

B) 2

C) 4

D) 1

13 / 25

funksiyaning [-4;2] oraliqdagi eng katta qiymatini toping $f(x)=x^3+4.5x^2-9$

A) 16

B) 14

C) 17

D) 18

14 / 25

Agar f(x)=x² va bo`lsa ,f(g(2)) ni toping

A) 16

B) 12

C) 0

D) 36

15 / 25

A) 14

B) 13

C) 20

D) 18

16 / 25

f(x)=3x²-5x+4 va g(x)=4x-5 funksiyalarining urinmalari parallel bo’ladigan nuqtalarini toping.

A) 1.5

B) 0.5

C) 0

D) 2

17 / 25

(x²+23x+23)(x²+x+23)=23x² tenglama haqiyqiy ildizlari yig’indisini toping

A) -23

B) -24

C) 23

D) 24

18 / 25

Ixtiyoriy kvadratga tashqi va ichki chizilgan aylanalar yuzlari nisbati a ga teng. Ixtiyoriy aylanaga ichki va tashqi chizilgan kvadratlar yuzlari nisbati b ga teng bolsa, a/b ni toping

A) 1/2

B) 4

C) 1

D) 335

19 / 25

chiziqlar bilan chegaralangan shaklning yuzini toping

A) 1

B) √2

C) 2

D) 0,5

20 / 25

cos15⁰*cos45⁰ *cos75⁰ ni hisoblang

A) √8/2

B) √2/2

C) 2√2

D) √2

21 / 25

aniq integralni hisoblang

A) 4

B) 6

C) 2

D) 2,5

22 / 25

Muntazam uchburchak tomoni 3 ga teng. Uchburchak tomonlari o’rtalari tutashtirilib, muntazam uchburchaklar hosil qilindi. Ichma-ich joylashgan uchburchaklar yuzlari yig’indisini toping

A) 2

B) 3

C) 2√3

D) 3√3

23 / 25

sin3x+ $\sqrt{3}$ cos3x≥0 tengsizligini yeching

A) [-π/9+n π/3;2 π/9+n π/3]

B) [-π/9+2πn/3; 2π/9+2πn/3]

C) ø

D) (-π/2+n π;- π/2+n π)

24 / 25

Silindr shaklidagi idishga 6 sm³ suv solindi. Idishga detal to’liq cho’ktirilganda, suv sathi 1,5 marta ko’tarildi. Detal hajmini aniqlang

A) 14

B) 23

C) 1

D) 3

25 / 25

cos(2arctg(1/2)) ni hisoblang

A) -37/35

B) -35/37

C) 37/35

D) 35/37

Baholash mezoni

86%-100% 5 baho

71%-85% 4 baho

56%-70% 3 baho

55% va kamiga 2 baho

tomonidan Wordpress Quiz plugin

Matematika choraklik

11-sinf Matematika 2-chorak

Aprel 17, 2021Aprel 20, 2021 da chop etilgan InfoMaster tomonidan 11-sinf Matematika 2-chorak ga 1 fikr bildirilgan

OMAD YOR BO'LSIN!

Tomonidan yaratilgan InfoMaster

11-sinf Matematika 2-chorak

Testni Mamadoliyev Diyorbek tayyorladi.

1 / 25

To’g’riburchakli parallelepiped asosining tomonlari 7:24 nisbatda, diagonal kesimining yuzi 50dm² ga teng. Yon sirtining yuzini toping.

A) 135 dm²

B) 124 dm

C) 124 dm²

D) 224 dm²

2 / 25

Tandirdan olingan nonning temperaturasi 20 minut ichida 100⁰ dan 60⁰ gacha pasayadi. Tashqi muhit temperaturasi 25⁰. Nonning temperaturasi qancha vaqtda 30⁰ gacha pasayadi?

A) 51

B) 61

C) 41

D) 71

3 / 25

f(x)=e^xcosx funksiyasi uchun f ’(π/2) ni aniqlang.

A. e^-0.5π B. e^0,5π C. e^π D. e^-π

A) e^(-0.5π)

B) e^(-π)

C) e^(π)

D) e^(0.5π)

4 / 25

Havo shariga t $\in$ [0;10] minut oralig’ida V(t)=t³+13t²+t+20 (m³) havo purkamoqda. t=10 minutdagi havo hajmini toping.

A) 2330

B) 2300

C) 1023

D) 2025

5 / 25

Qavariq ko’pburchakning har bir uchidan uchtadan qirra chiqadi. Agar bu ko’pyoqning qirralari soni 12 ta bo’lsa, uning nechta uchi va yog’i mavjud?

A) 4;18

B) 4;10

C) 4;11

D) 8;10

6 / 25

To’g’ri to’rtburchak shaklidagi yer maydoninig atrofini o’rashmoqchi. 480 m panjara yordamida eng ko’pi bilan necha kvadrat metr yer maydonni o’rash mumkin?

A) 25600

B) 8100

C) 14400

D) 19600

7 / 25

f(x)=(3x+2)² funksiyasining barcha boshlang’ich funksiyalarini toping.

A) F(x)=6x³+3x²+4

B) F(x)=6x³+6x²+4

C) F(x)=6x³+3x²-4

D) F(x)=6x³+6x+4

8 / 25

Moddiy nuqta qonuniyat bilan harakatlanmoqda, eng katta tezlanishga erishiladigan vaqtni toping.

A) 7

B) 4

C) 5

D) 6

9 / 25

f(x)=2x+3 funksiyasi uchun A(1;5) nuqtadan o’tuvchi boshlang’ich funksiyasini toping.

A) F(x)=x²+3x+1

B) F(x)=x²-3x+1

C) F(x)=x²-3x-1

D) F(x)=x²+3x-1

10 / 25

Agar f(x)=x² va bo`lsa ,f(g(2)) ni toping

A) 16

B) 12

C) 0

D) 36

11 / 25

Moddiy nuqta S(t)=5t³+3t²+2t+4 qonuniyat bilan harakatlanayotgan jismning t=2 sekunddagi tezligini toping.

A) 60

B) 84

C) 70

D) 74

12 / 25

f(x)=3x²-5x+4 va g(x)=4x-5 funksiyalarining urinmalari parallel bo’ladigan nuqtalarini toping.

A) 0

B) 1.5

C) 0.5

D) 2

13 / 25

Agar A(1;2;3), B(3;7;6) bo’lsa, A̅B̅ vector koordinatalarini toping

A) (-2;-5;-3)

B) (4;9;9)

C) (2;5;3)

D) (4;9;9)

14 / 25

Funksiyaning statsionar nuqtalarini toping $f(x)=2x^3-3x^2-12x+3$

A) x=-1, x=3

B) x=0, x=2

C) x=-1, x=2

D) x=3, x=2

15 / 25

Nargiza 4minutda 260ta so`zni terib, 7ta imloviy xatoga yo`l qo`ydi. Nargizaning matn terish sifatini aniqlang

A) 0,01

B) 0,6

C) 0,0269

D) 0,5

16 / 25

y=-3x³+2x²-4x+5 funksiyaga x₀=-1 nuqtada o’tkazilgan urinma tenglamasining burchak koeffitsiyentini toping.

A) 15

B) -13

C) 17

D) -17

17 / 25

Moddiy nuqtaning berilgan t vaqtdagi tezligini hisoblang: $s(t)=t^3-2t^2+t$ , t=5

A) 90