Bo'lim: Matematika choraklik

6-sinf Matematika 1-chorak

Oktabr 26, 2021Oktabr 26, 2021 da chop etilgan InfoMaster tomonidan 6-sinf Matematika 1-chorak ga 1 fikr bildirilgan

OMAD YOR BO'LSIN!

Tomonidan yaratilgan InfoMaster

6-sinf Matematika 1-chorak

2-sinov

Ismi familiyangizni kriting!

1 / 25

1; 2; 3; 15; 17; 21; 28; 47; 57; 89; 144; 300; 205 sonlari ichida nechta murakkab son bor ?

A) 8

B) 5

C) 7

D) 6

2 / 25

Tenglamani yechimini toping:

A) 16

B) 15

C) 14

D) 13

3 / 25

Kasrni airing:

A) 1/2

B) 16/135

C) 18/60

D) 8/90

4 / 25

Poezdda 936 yo’lovchi bor edi. Erkaklar ayollardan 7 marta, ayollar esa 5 marta ko’p. Poezdda qancha ayol bo’lgan?

A) 240

B) 390

C) 360

D) 25

5 / 25

Ekub (215, 435, 600) topilsin

A) 3

B) 5

C) 2

D) 0

6 / 25

Ikkinchi raqami 4 bo’lgan uch xonali son 9 ga va 2 ga bo’linadi, ammo 5 ga bo’linmaydi. Shu sonni toping?

A) 243

B) 944

C) 181

D) 144

7 / 25

Tengsizlik nechta tub yechimga ega: 54 < x ≤ 79

A) 25

B) 6

C) 5

D) 24

8 / 25

Gektarlarda ifodalang: 500 000 m²

A) 50 g

B) 500 g

C) 5 g

D) 5000 g

9 / 25

Tub ko’paytuvchilarga ajrating.

A) 5175 = 5² * 3² *23

B) 5175 = 5 * 7 * 3

C) 5175 = 5 * 72 * 3

D) To'g'ri javob yo'q

10 / 25

9 ga bo`linadigan sonni toping.

A) 2576

B) 1075

C) 6534

D) 2341

11 / 25

To’g’ri to’rtburchakning bo’yi 25 sm, eni esa 20 sm. Ularning perimetrini toping?

A) 90

B) 95

C) 85

D) 100

12 / 25

Ekuk (28, 70, 140) topilsin.

A) 140

B) 280

C) 130

D) 70

13 / 25

3 ta ketma-ket natural sonlarning ko`paytmasi quyidagi sonlarning qaysi biriga albatta bo`linadi ?

A) 24

B) 5

C) 6

D) 12

14 / 25

30 soni nechta bo`luvchiga ega ?

A) 5

B) 8

C) 4

D) 6

15 / 25

Ekuk (106, 159, 530) topilsin.

A) 150

B) 3180

C) 3000

D) 3280

16 / 25

Ayirmani toping:

A) 121/12

B) 243/12

C) 483/24

D) 241/12

17 / 25

Qaysi juftlik o`zaro tub sonlardan iborat ?

A) (8; 10)

B) ( 28; 24)

C) (34; 45)

D) (12; 15)

18 / 25

Hisoblang:

A) 1/2

B) 4/20

C) 1/5

D) 6/40

19 / 25

Tenglamani yeching: x : 20 = 10

A) 2000

B) 2

C) 20

D) 200

20 / 25

Bir son ikkinchisidan 20 taga ko’p ularning yig’indisi 70 ga teng. Bu sonlarni toping?

A) 11 va 38

B) 30 va 40

C) 55 va 15

D) 25 va 45

21 / 25

Ekub (21, 84) topilsin.

A) 21

B) 7

C) 14

D) 3

22 / 25

Amallarni bajaring: 7758 : 18 + 720 : 8

A) 521

B) 511

C) 500

D) 510

23 / 25

Yulduzcha o`rniga qanday raqam qo`yish mumkin: 196 = 2 · 2 · * · 7

A) 7

B) 11

C) 13

D) 3

24 / 25

Sonning bo’luvchilari nechta: 58

A) 4

B) 2

C) 3

D) 5

25 / 25

kasrni qisqartiring.

A) 2/5

B) 1/2

C) 5/29

D) 1/25

Baholash mezoni

86%-100% 5 baho

71%-85% 4 baho

56%-70% 3 baho

55% va kamiga 2 baho

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Matematika choraklik

8-sinf Matematika 4-chorak №2

May 17, 2021May 18, 2021 da chop etilgan InfoMaster tomonidan 8-sinf Matematika 4-chorak №2 ga 1 fikr bildirilgan

Yaratilgan sanasi May 18, 2021 tomonidan InfoMaster

8-sinf Matematika 4-chorak

Ismi familiyangizni kriting!

Ism

1 / 25

$\vec{a}(2;4)$ va $\vec{b}(-1;4)$ berilgan bo'lsa $\vec{a}-\vec{b}$ vektorning kordinatalarini toping.

A) -3;0

B) 3;0

C) 1;8

D) -3;-8

2 / 25

Yuzi 400 $dm^{2}$ ga teng bo‘lgan kvadratning perimetrini toping.

A) 80

B) 100

C) 120

D) 160

3 / 25

Rombning yuzi 164 $cm^{2}$ , diagonallaridan bin 8 cm ga teng. Shu rombning ikkinchi diagonalini toping.

A) 50

B) 51

C) 41

D) 40

4 / 25

Teng yonli trapetsiyaning diagonallari o‘zaro perpendikular va balandligi 8 cm ga teng. Shu trapetsiyaning yuzini toping.

A) 64

B) 45

C) 55

D) 36

5 / 25

Tengsizlikni yeching: x + 4>3 – 2x

A) x>3

B) x<1/3

C) x>-1/3

D) x>1/3

6 / 25

Viktor deb nimaga qaytiladi?

A) Bunday tushuncha yo'q

B) Faqat yo'nalish qiymati bilan aniqlanadigan kattalikka

C) Son qiymati va yo'nalishi bilan aniqlanadigan kattalikka

D) Faqat son qiymati bilan aniqlanadigan kattalikka

7 / 25

Teng yonli trapetsiyaning diagonallari o‘zaro perpendikular va balandligi 8 cm ga teng. Shu trapetsiyaning yuzini toping.

A) 36

B) 45

C) 64

D) 55

8 / 25

Tengsizlikni yeching:

4(x-1)+5(x+1)<6(x+2)+7(x-1)

A) x<-1

B) x>-1

C) x<-6

D) x>1

9 / 25

Kvadrat tenglamani yeching $x^{2}+x-6$ =0

A) x₁=3, x₂=2

B) x₁=0, x₂=2

C) x₁=-3, x₂=2

D) x₁=-3, x₂=-2

10 / 25

Kvadratning tomoni 1.2 dm bo'lsauning yuzini toping $sm^{2}$ larda.

A) 144

B) 14,2

C) 1,44

D) 2,44

11 / 25

Trapetsiyaning asoslari 11 cm va 18 cm ga, balandligi esa 6 cm ga teng. Shu trapetsiyaning yuzini toping.

A) 96

B) 87

C) 78

D) 56

12 / 25

Tenglamani yeching $x^{4}-4x^{2}-5=0$

A) x₁,₂=±√5 , x₃,₄=1

B) x₁,₂=±5

C) x₁,₂=1 , x₃,₄=-1

D) x₁,₂=±√5

13 / 25

4 ga bo`lganda 3 qoldiq, 10 ga bo`lganda 1 qoldiq chiqadigan va ikkinchi bo`linma birinchi bo`linmadan 13 ta kam bo`ladigan natural sonni toping.

A) 91

B) 87

C) 81

D) 95

14 / 25

Tenglamani yeching $x^{2}=25$

A) x₁,₂=±5

B) x₁,₂=5

C) x=5

D) x₁,₂=-5

15 / 25

Ta'rifni to'ldiring. Ikala tamoni parallel, qolgan tamonlari parallel bo'lmagan to'rtburchak .... deb ataladi.

A) parallelogramm

B) trapetsiya

C) kvadrat

D) romb

16 / 25

Parallelogrammning yuzi 36 $cm^{2}$ , a tamoniga tushurilgan balandliklari 3 cm . Shu parallelogrammning a tamonini toping.

A) 6

B) 12

C) 3

D) 4

17 / 25

Kollinear vektorlar deb qanday vektorlarga aytiladi?

A) Faqat son qiymati bilan aniqlanadigan kattalikka

B) Parallel to'g'ri chiziqda yoki to'g'ri chiqiqda yotuvchi ikki vektorga

C) Yig'indisi nolga teng bo'lgan vektorlarga

D) Ko'paytmasi nolga teng bo'lgan vektorlarga

18 / 25

Tenglamani yeching $x^{2}=64$

A) x₁,₂=8

B) x₁,₂=-8

C) x₁,₂=±8

D) x₁,₂=√64

19 / 25

$\vec{a}(2;6)$ va $\vec{b}(-1;4)$ berilgan bo'lsa $\vec{a}+\vec{b}$ vektorning kordinatalarini toping.

A) 3;10

B) 3;2

C) -1;10

D) 1;10

20 / 25

To‘g‘ri burchakli uchburchakning katetlari 4 cm va 9 cm. Shu to‘g‘ri burchakli uchburchakning yuzini toping.

A) 20

B) 9

C) 18

D) 36

21 / 25

5 : 13 sonini 0,001 gacha aniqlikdagi o’nli kasr ko’rinishida tasvirlang:

A) 0,538

B) 0,385

C) 0,853

D) 0,835

22 / 25

Kvadrat tenglamani yeching $x^{2}-7x+10=0$

A) x₁=-5, x₂=2

B) ø

C) x₁=2, x₂=5

D) x₁=-2, x₂=5

23 / 25

Hisoblang: $\sqrt{28-12}$

A) 4

B) -4

C) 16

D) 3

24 / 25

Kvadrat tenglamani yeching $x^{2}+x+1=0$

A) x₁=2, x₂=0

B) x₁=-1, x₂=1

C) ø

D) x₁=-2, x₂=-2

25 / 25

tengsizliklar sistemasining yechimi bo‘la olmaydigan sonni toping

A) -1

B) 1

C) 10

D) -12

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Matematika choraklik

5-sinf Matematika 4-chorak

May 10, 2021May 12, 2021 da chop etilgan InfoMaster tomonidan 5-sinf Matematika 4-chorak ga 1 fikr bildirilgan

OMAD YOR BO'LSIN!

Tomonidan yaratilgan InfoMaster

5-sinf Matematika 4-chorak

Testni Shirinboyev Temurbek tayyorladi!

Ismi familiyangizni kriting!

Ism

1 / 25

Bo’linmani bajaring: 121,6 : 4

A) 45,2

B) 60,8

C) 72,8

D) 30,4

2 / 25

Agar x=100,bo`lsa 53,6x ifodaning qiymatini toping

A) 536

B) 53600

C) 563

D) 5360

3 / 25

Uchburchakning bitta burchagi 63^o ,ikkinchi burchagi esa 42^o ga teng. Uning uchinchi burchagini toping.

A) 60°

B) 75°

C) 69°

D) 180°

4 / 25

Uchburchak burchaklari yig`indisi …….teng

A) 180

B) 360

C) 270

D) 250

5 / 25

≤table≥ tegining align="left" atributi qiymatining vazifasini toping.

A) jadval foniga rang berish.

B) jadvalni markazga tekislash;

C) jadvalni o‘ng tomonga tekislash.

D) jadvalni chap tomonga tekislash;

6 / 25

≤table≥ tegining width atributi qiymatining vazifasini toping.

A) jadval balandligini o‘rnatish. Qiymat piksel yoki foizlarda berilishi mumkin.

B) jadvalning ramka qalinligi o‘rnatilgan bo‘lsa (border), jadval katagi bilan tashqi chegara ramkasi orasidagi masofani o‘rnatish.

7 / 25

≤table≥ tegining cellspacing atributi qiymatining vazifasini toping.

A) jadval kengligini o‘rnatish. Qiymat piksel yoki foizlarda berilishi mumkin.

B) jadval balandligini o‘rnatish. Qiymat piksel yoki foizlarda berilishi mumkin.

C) jadvalning ramka qalinligi o‘rnatilgan bo‘lsa (border), jadval katagi bilan tashqi chegara ramkasi orasidagi masofani o‘rnatish.

D) jadval chegarasidan yozuvgacha bo‘lgan masofani o‘rnatish (agar masofa o‘rnatilmasa, yozuv jadval chegarasiga yopishtirib yoziladi).

8 / 25

Massasi 4/15 kg bo’lgan pamidorga, 7/15 kg bodring va 2/15 kg piyoz qo’shilib salat tayyorlandi. Salatning massasini toping?

A) 13/15 kg

B) 13/45 kg

C) 11/45 kg

D) 11/15 kg

9 / 25

Kubning hajmini 125 bo'lsa uning qirralari uzunliklari yig'indisini toping.

A) 24

B) 50

C) 64

D) 60

10 / 25

Massasi 4/15 kg bo’lgan pamidorga, 7/15 kg bodring va 2/15 kg piyoz qo’shilib salat tayyorlandi. Salatning massasini toping?

A) 13/15 kg

B) 13/45 kg

C) 11/15 kg

D) 11/45 kg

11 / 25

Quyidagi oddiy kasni o'nli kasr ko'rinishda ifodalang.

A) 0,007

B) 0,0007

C) 0,7

D) 0,07

12 / 25

Yig’indini toping:

A) 8,20/14

B) 8,21/14

C) 8,19/14

D) 8,22/14

13 / 25

Amudaryoning uzunligi 2540 km . Sirdaryo unga qaraganda 479 km uzun. Sirdaryoning uzunligini toping.

A) 18128 km

B) 4765 km

C) 2061 km

D) 3019 km

14 / 25

Sonlarni yig’indisi toping. 112, 85, 2333;

A) 3446

B) 2624

C) 2530

D) 4940

15 / 25

Qo’sh tengsizlik ko’rinishida ifodalang. 44 soni 55 sonidan kichik, lekin 33 sonida katta;

A) 33<44<55

B) 44<55<33

C) 3344

D) 55<44<33

16 / 25

Kasrlar ustida amallar bajaring:

A) 12/125

B) 76/125

C) 80/250

D) 80/125

17 / 25

To'g'ri burchakli parallelepipedning a=3, b=4, c=5 tamonlari berilgan bo'lsa uning sirtini yuzini toping.

A) 56

B) 94

C) 92

D) 72

18 / 25

≤label≥…≤/label≥– juft teglarining vazifasi qanday?

A) veb-sahifaga forma joylashtirish uchun qo‘llaniladi

B) formadagi elementlarning nomlarini kiritish uchun foydalaniladi.

C) orqali forma elementlarini guruhlash mumkin.

D) bir necha variantlarga ega bo‘lgan ro‘yxat hosil qilish uchun ishlatiladi

19 / 25

≤form≥…≤/form≥– juft teglarining vazifasi qanday?

A) 29

B) tegi turli xil forma elementlarini yaratish uchun ishlatiladi, ya’ni formaning asosi hisoblanadi.

C) 27

D) 30

E) 33

F) veb-sahifaga forma joylashtirish uchun qo‘llaniladi

G) jadval qatoriga katakcha qo‘shish

H) jadvalga sarlavha qo‘shish

20 / 25

≤form≥ tegining name atributi qiymatining vazifasini toping.

A) Ikki tomoni cheksiz davom etadigan chiziq

B) Ikki to`g`ri chiziqning kesishishidan hosil bo`lgan shakl

C) Tog`ri chiziqning bir tomoni chegaralangan

D) forma orqali jo‘natilayotgan ma’lumotlar qaysi sahifada qayta ishlanishi kerakligi beriladi.

E) formaga nom berish (bu nom skriptlar yozishda ishlatiladi)

F) formada har xil ko‘rinishdagi elementlarni hosil qiladi.

G) forma ma’lumotlarini jo‘natish usuli.

H) Tog`ri chiziqning ikkala tomoni chegaralangan

21 / 25

Quyidagi mulohazalarning qaysilari to’g’ri?
1) tub sonlar faqat toq sonlardan iborat;
2) 72 sonining tub bo’lmagan natural bo’luvchilari soni 10 ta;
3) har qanday natural sonning butun bo’luvchilari soni 0 ga teng;
4) agar ko’paytuvchilardan biri m soniga bo’linsa, u holda ko’paytma ham m songa bo’linadi;
5) Bir – tub son ham, murakkab son ham emas.

A) 2; 4; 5

B) 1; 3; 4

C) 1; 2; 3

D) 3; 4; 5

22 / 25

1* 2* 3*......74* 75 ko’paytma nechta nol bilan tugaydi?

A) 16

B) 18

C) 17

D) 11

23 / 25

Yig’indining oxirgi raqamini toping
$116^{17}+116^{18}+116^{19}$

A) 8

B) 2

C) 4

D) 3

24 / 25

Raqamlari yig’indisi 28 ga teng bo’lgan eng katta to’rt xonali son(turli raqamli)ning birlar xonasidagi raqamni toping.

A) 6

B) 7

C) 4

D) 5

25 / 25

30 gacha bo’lgan tub sonlar ko’paytmasining oxirgi raqamini toping.

A) 0

B) 5

C) 1

D) 7

Baholash mezoni

86%-100% 5 baho

71%-85% 4 baho

56%-70% 3 baho

55% va kamiga 2 baho

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Matematika choraklik

11-sinf Matematika 4-chorak

Aprel 17, 2021Aprel 20, 2021 da chop etilgan InfoMaster tomonidan 11-sinf Matematika 4-chorak ga 83 fikr bildirilgan

OMAD YOR BO'LSIN!

Tomonidan yaratilgan InfoMaster

11-sinf Matematika 4-chorak

Testni Salomov Sardor tayyorladi.

1 / 25

To’g’ri to’rtburchak shaklidagi yer maydoninig atrofini o’rashmoqchi. 480 m panjara yordamida eng ko’pi bilan necha kvadrat metr yer maydonni o’rash mumkin?

A) 25600

B) 14400

C) 19600

D) 8100

2 / 25

f(x)=e^xcosx funksiyasi uchun f ’(π/2) ni aniqlang.

A. e^-0.5π B. e^0,5π C. e^π D. e^-π

A) e^(-π)

B) e^(-0.5π)

C) e^(0.5π)

D) e^(π)

3 / 25

To’g’riburchakli parallelepiped bir uchidan chiquvchi uchta qirralari uzunliklari 4,6 va 9 ga teng. Unga tengdosh kub qirrasining uzunligini toping.

A) 7

B) 6

C) 6

D) 8

4 / 25

F(x)=0.2sin(5x+12) funksiyasi uchun f(x) ni toping

A) f(x)=-0,5sin(5x+12)

B) f(x)=0.5cos(5x+12)

C) f(x)=-cos(5x+12)

D) f(x)=cos(5x+12)

5 / 25

f(x)=(3x+2)² funksiyasining barcha boshlang’ich funksiyalarini toping.

A) F(x)=6x³+6x+4

B) F(x)=6x³+3x²-4

C) F(x)=6x³+3x²+4

D) F(x)=6x³+6x²+4

6 / 25

Funksiyaning statsionar nuqtalarini toping $f(x)=2x^3-3x^2-12x+3$

A) x=-1, x=3

B) x=0, x=2

C) x=3, x=2

D) x=-1, x=2

7 / 25

Moddiy nuqtaning berilgan t vaqtdagi tezligini hisoblang: $s(t)=t^3-2t^2+t$ , t=5

A) 80

B) 75

C) 70

D) 90

8 / 25

Murakkab funksiyaning hosilasini toping. y=x²sinx

A) y’=x²cosx-2xsinx

B) y’=-2xsinx+x²

C) y’=2xsinx-x²

D) y’=2xsinx+x²cosx

9 / 25

Funksiya hosilasini toping: f(x)=5

A) 0

B) 10

C) x

D) 5

10 / 25

Funksiyaning kamayish oraliqlarini toping

A) (-1;0) va (0;2)

B) (-2;0) va (0;1)

C) (-1;0) va (0;1)

D) (-3;0) va (0;1)

11 / 25

A(2;0;-3) va B(3;4;0) nuqtalar orasidagi masofani toping

A) 16

B) √24

C) √26

D) 25

12 / 25

f(x)=3x²-5x+4 va g(x)=4x-5 funksiyalarining urinmalari parallel bo’ladigan nuqtalarini toping.

A) 2

B) 1.5

C) 0.5

D) 0

13 / 25

$f(x)=x^2-3x+4$ funksiya uchun y=2x-1 to`g`ri chiziqqa parallel bo`lgan urinma tenglamasini yozing

A) y=3x-2,2

B) y=2x-2,25

C) y=2x

D) y=2x+3

14 / 25

Agar A(1;2;3), B(3;7;6) bo’lsa, A̅B̅ vector koordinatalarini toping

A) (4;9;9)

B) (-2;-5;-3)

C) (4;9;9)

D) (2;5;3)

15 / 25

Funksiya hosilasini toping: $f(x)=7x^3-5x^2+4$

A) 14x+12

B) 12x²-12

C) 12x+12

D) 21x²-10x

16 / 25

Agar f(x)=x² va bo`lsa ,f(g(-4)) ni toping

A) 36

B) 12

C) 0

D) -12

17 / 25

chiziqlar bilan chegaralangan shaklning yuzini toping

A) √2

B) 0,5

C) 2

D) 1

18 / 25

Ixtiyoriy kvadratga tashqi va ichki chizilgan aylanalar yuzlari nisbati a ga teng. Ixtiyoriy aylanaga ichki va tashqi chizilgan kvadratlar yuzlari nisbati b ga teng bolsa, a/b ni toping

A) 1/2

B) 1

C) 335

D) 4

19 / 25

Ushbu funksiyasining boshlang’ich funksiyasini toping

A) (x+2)(x+1)

B) lnIx-1I

C) ln⁡(|x+2|*|x+1|)

D) lnI(x-2)(x-3)I

20 / 25

tengsizlikning yechimi bo’lgan eng kichik natural sonni toping

A) 1

B) 4

C) 3

D) 5

21 / 25

aniq integralni hisoblang

A) 2,5

B) 2

C) 6

D) 4

22 / 25

integralni hisoblang

A) 5ln3e³

B) 5ln2e

C) 5

D) 5ln4e

23 / 25

Tomoni 4 ga teng bo’lgan teng tomonli uchburchak ichiga uchburchakning tomonlariga urinuvchi uchta teng doira joylashtirilgan. O’zaro urunuvchi doiralar yoylaridan hosil bo’lgan egri chiziqli uchburchakning yuzini toping

A) 2√3-π

B) (2-√3)(2-π)

C) (2-√3)(2√3-π)

D) (4-√3)(2√3-π)

24 / 25

$y=6^{ln(x^{2}+5)}$ funksiyasining kamayish oralig’ini toping

A) ∅

B) (-√5;√5)

C) (-∞;0]

D) (0;+∞)

25 / 25

Tekislikdagi 1 m masofada yotgan nuqtadan ikkita teng og’ma o’tkazilgan. Agar og’malar perpendikulyar va tekislikka o’tkazilgan perpendikulyar bilan 60⁰ ga teng burchaklar tashkil etsa, og’malarning asoslari orasidagi masofani toping

A) 2√3

B) 2√2

C) 1

D) 4√2

Baholash mezoni

86%-100% 5 baho

71%-85% 4 baho

56%-70% 3 baho

55% va kamiga 2 baho

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Matematika choraklik

11-sinf Matematika 3-chorak

Aprel 17, 2021Aprel 20, 2021 da chop etilgan InfoMaster tomonidan 11-sinf Matematika 3-chorak ga 8 fikr bildirilgan

OMAD YOR BO'LSIN!

Tomonidan yaratilgan InfoMaster

11-sinf Matematika 3-chorak

Testni Salomov Sardor tayyorladi.

1 / 25

tengsizlikning yechimi bo’lgan eng kichik natural sonni toping

A) 4

B) 1

C) 3

D) 5

2 / 25

chiziqlar bilan chegaralangan shaklning yuzini toping

A) 2

B) 1

C) √2

D) 0,5

3 / 25

sin3x+ $\sqrt{3}$ cos3x≥0 tengsizligini yeching

A) [-π/9+2πn/3; 2π/9+2πn/3]

B) ø

C) (-π/2+n π;- π/2+n π)

D) [-π/9+n π/3;2 π/9+n π/3]

4 / 25

Aylanaga o’tkazilgan vatar uni 5:7 nisbatda bo’ladi. Ushbu vatarga tiralgan, aylanaga ichki chizilgan katta burchakni toping

A) 75°

B) 55°

C) 125°

D) 105°

5 / 25

Ixtiyoriy kvadratga tashqi va ichki chizilgan aylanalar yuzlari nisbati a ga teng. Ixtiyoriy aylanaga ichki va tashqi chizilgan kvadratlar yuzlari nisbati b ga teng bolsa, a/b ni toping

A) 335

B) 1/2

C) 1

D) 4

6 / 25

Silindr shaklidagi idishga 6 sm³ suv solindi. Idishga detal to’liq cho’ktirilganda, suv sathi 1,5 marta ko’tarildi. Detal hajmini aniqlang

A) 14

B) 1

C) 3

D) 23

7 / 25

Trapetsiyaning kichik asosi 6 ga va yon tomoni 5 va 7 ga teng. Uning kata asosi ham butun son bo’lsa, perimetri eng ko’pi bilan nechaga teng bo’lishi mumkin

A) 3

B) 1

C) 4

D) 3√2

8 / 25

$\sqrt[3]{131}$ sonini taqriban hisoblang.

A) 5,08

B) 5,01

C) 4,08

D) 3,08

9 / 25

To’g’riburchakli parallelepiped asosining tomonlari 7:24 nisbatda, diagonal kesimining yuzi 50dm² ga teng. Yon sirtining yuzini toping.

A) 124 dm²

B) 124 dm

C) 224 dm²

D) 135 dm²

10 / 25

F(x)=0.2sin(5x+12) funksiyasi uchun f(x) ni toping

A) f(x)=-0,5sin(5x+12)

B) f(x)=cos(5x+12)

C) f(x)=0.5cos(5x+12)

D) f(x)=-cos(5x+12)

11 / 25

To’g’ri to’rtburchak shaklidagi yer maydoninig atrofini o’rashmoqchi. 480 m panjara yordamida eng ko’pi bilan necha kvadrat metr yer maydonni o’rash mumkin?

A) 19600

B) 25600

C) 8100

D) 14400

12 / 25

Karim uyida 14 bet matn terib, 8ta imloviy xatoga yo’l qo’ydi. Agar 1 betda o’rtacha 380 ta so’z bo’lsa, Karim 100ta so’z terganda o’rtacha qancha xato qiladi?

A) 0,15

B) 1,5

C) 0,25

D) 0,5

13 / 25

$f(x)=x^3-2x^2$ funksiya grafigiga x=1 abssisssali nuqtadao`tkazilgan urinma tenglamasini yozing

A) y=x

B) y= 2x

C) y=1/2

D) y=-x

14 / 25

Funksiya hosilasini toping: $f(x)=7x^3-5x^2+4$

A) 12x²-12

B) 21x²-10x

C) 14x+12

D) 12x+12

15 / 25

$\lim_{x\rightarrow -1}(5-2x)$ limitni hisoblang

A) 7

B) 0

C) 5

D) 6

16 / 25

Agar A(1;2;3), B(3;7;6) bo’lsa, A̅B̅ vector koordinatalarini toping

A) (4;9;9)

B) (2;5;3)

C) (-2;-5;-3)

D) (4;9;9)

17 / 25

Funksiya hosilasini toping

f(x)=(2x+4)(3x+1)

A) 16x+14

B) 12x+14

C) 12x

D) 3x+1

18 / 25

Moddiy nuqta S(t)=5t³+3t²+2t+4 qonuniyat bilan harakatlanayotgan jismning t=2 sekunddagi tezligini toping.

A) 70

B) 60

C) 84

D) 74

19 / 25

Funksiyaning statsionar nuqtalarini toping $f(x)=2x^3-3x^2-12x+3$

A) x=3, x=2

B) x=-1, x=2

C) x=-1, x=3

D) x=0, x=2

20 / 25

Agar f(x)=x² va bo`lsa ,f(g(-4)) ni toping

A) 36

B) 0

C) 12

D) -12

21 / 25

A) 13

B) 14

C) 18

D) 20

22 / 25

Murakkab funksiyaning hosilasini toping. y=x²sinx

A) y’=x²cosx-2xsinx

B) y’=-2xsinx+x²

C) y’=2xsinx+x²cosx

D) y’=2xsinx-x²

23 / 25

A(1;-2;2), B(1;4;0), C(-4;1;1) va D(-5;-5;3) nuqtalar berilgan. AC va BD vektorlar orasidagi burchakni toping

A) 80°

B) 15°

C) 90°

D) 52°

24 / 25

$f(x)=x^3-2x^2+3x-2$ funksiya grafigiga x=4 abssissali nuqtada o`tkazilgan urinma tenglamasini tuzing

A) y=20x+20

B) y=10x

C) y=35x+30

D) y=35x

25 / 25

A(2;0;-3) va B(3;4;0) nuqtalar orasidagi masofani toping

A) √24

B) √26

C) 25

D) 16

Baholash mezoni

86%-100% 5 baho

71%-85% 4 baho

56%-70% 3 baho

55% va kamiga 2 baho

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Matematika choraklik

11-sinf Matematika 2-chorak

Aprel 17, 2021Aprel 20, 2021 da chop etilgan InfoMaster tomonidan 11-sinf Matematika 2-chorak ga 16 fikr bildirilgan

OMAD YOR BO'LSIN!

Tomonidan yaratilgan InfoMaster

11-sinf Matematika 2-chorak

Testni Mamadoliyev Diyorbek tayyorladi.

1 / 25

f(x)=e^xcosx funksiyasi uchun f ’(π/2) ni aniqlang.

A. e^-0.5π B. e^0,5π C. e^π D. e^-π

A) e^(-0.5π)

B) e^(π)

C) e^(0.5π)

D) e^(-π)

2 / 25

f(x)=sin2x funksiyasining barcha boshlang’ich funksiyalarini toping.

A) F(x)=-2cos2x+C

B) F(x)=2sin4x+c

C) F(x)=0,5cos2x+C

D) F(x)=-0,5cos2x+C

3 / 25

Moddiy nuqta qonuniyat bilan harakatlanmoqda, eng katta tezlanishga erishiladigan vaqtni toping.

A) 5

B) 6

C) 7

D) 4

4 / 25

Kub to’la sirtining yuzi 105,84 sm² bo’lsa, uning har bir yog’i yuzini va qirrasining uzunligini toping.

A) 17,64 dm²; 4,2 dm

B) 17,64 dm; 4,2 dm

C) 17,64 dm²; 4,9 dm

D) 17,68 dm²; 4,2 dm

5 / 25

To’g’riburchakli parallelepiped bir uchidan chiquvchi uchta qirralari uzunliklari 4,6 va 9 ga teng. Unga tengdosh kub qirrasining uzunligini toping.

A) 6

B) 8

C) 7

D) 6

6 / 25

F(x)=0.2sin(5x+12) funksiyasi uchun f(x) ni toping

A) f(x)=-cos(5x+12)

B) f(x)=-0,5sin(5x+12)

C) f(x)=cos(5x+12)

D) f(x)=0.5cos(5x+12)

7 / 25

A(1;-2;2), B(1;4;0), C(-4;1;1) va D(-5;-5;3) nuqtalar berilgan. AC va BD vektorlar orasidagi burchakni toping

A) 80°

B) 52°

C) 90°

D) 15°

8 / 25

Agar f(x)=x² va bo`lsa ,f(g(-4)) ni toping

A) 36

B) 12

C) 0

D) -12

9 / 25

f(x)=3x²-5x+4 va g(x)=4x-5 funksiyalarining urinmalari parallel bo’ladigan nuqtalarini toping.

A) 0.5

B) 2

C) 0

D) 1.5