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11-sinf Matematika 2-chorak

InfoMaster

Aprel 20, 2021

32 Ko'rishlar 16 izohlar

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OMAD YOR BO'LSIN!

11-sinf Matematika 2-chorak

Testni Mamadoliyev Diyorbek tayyorladi.

1 / 25

Kub to’la sirtining yuzi 105,84 sm² bo’lsa, uning har bir yog’i yuzini va qirrasining uzunligini toping.

A) 17,68 dm²; 4,2 dm

B) 17,64 dm; 4,2 dm

C) 17,64 dm²; 4,9 dm

D) 17,64 dm²; 4,2 dm

2 / 25

f(x)=(3x+2)² funksiyasining barcha boshlang’ich funksiyalarini toping.

A) F(x)=6x³+3x²+4

B) F(x)=6x³+6x²+4

C) F(x)=6x³+3x²-4

D) F(x)=6x³+6x+4

3 / 25

Moddiy nuqta qonuniyat bilan harakatlanmoqda, eng katta tezlanishga erishiladigan vaqtni toping.

A) 7

B) 6

C) 4

D) 5

4 / 25

Tandirdan olingan nonning temperaturasi 20 minut ichida 100⁰ dan 60⁰ gacha pasayadi. Tashqi muhit temperaturasi 25⁰. Nonning temperaturasi qancha vaqtda 30⁰ gacha pasayadi?

A) 51

B) 71

C) 41

D) 61

5 / 25

To’g’ri to’rtburchak shaklidagi yer maydoninig atrofini o’rashmoqchi. 480 m panjara yordamida eng ko’pi bilan necha kvadrat metr yer maydonni o’rash mumkin?

A) 8100

B) 19600

C) 25600

D) 14400

6 / 25

To’g’riburchakli parallelepiped bir uchidan chiquvchi uchta qirralari uzunliklari 4,6 va 9 ga teng. Unga tengdosh kub qirrasining uzunligini toping.

A) 8

B) 6

C) 7

D) 6

7 / 25

f(x)=sin2x funksiyasining barcha boshlang’ich funksiyalarini toping.

A) F(x)=-2cos2x+C

B) F(x)=0,5cos2x+C

C) F(x)=2sin4x+c

D) F(x)=-0,5cos2x+C

8 / 25

F(x)=0.2sin(5x+12) funksiyasi uchun f(x) ni toping

A) f(x)=cos(5x+12)

B) f(x)=-cos(5x+12)

C) f(x)=-0,5sin(5x+12)

D) f(x)=0.5cos(5x+12)

9 / 25

Funksiyaning statsionar nuqtalarini toping $f(x)=2x^3-3x^2-12x+3$

A) x=-1, x=2

B) x=3, x=2

C) x=-1, x=3

D) x=0, x=2

10 / 25

Funksiya hosilasini toping: $f(x)=7x^3-5x^2+4$

A) 21x²-10x

B) 12x²-12

C) 12x+12

D) 14x+12

11 / 25

Moddiy nuqtaning berilgan t vaqtdagi tezligini hisoblang: $s(t)=t^3-2t^2+t$ , t=5

A) 75

B) 90

C) 70

D) 80

12 / 25

$f(x)=x^3+2x^2+x+3$ funksiyasining kamayish oralig’ini toping.

A) [-1;-1/3]

B) (-1/3;+∞)

C) (-∞;-1)

D) (-1;1/3)

13 / 25

Koordinatalar boshidan y=x²-4x+3 parabolaning simmetriya o’qigacha bo’lgan masofani toping.

A) 1

B) 4

C) 3

D) 2

14 / 25

tgx funksiya hosilasini toping

A) 1/cos²x

B) cosx

C) 1/sinx

D) sinx

15 / 25

Murakkab funksiyaning hosilasini toping. y=x²sinx

A) y’=-2xsinx+x²

B) y’=2xsinx+x²cosx

C) y’=x²cosx-2xsinx

D) y’=2xsinx-x²

16 / 25

A(1;-2;2), B(1;4;0), C(-4;1;1) va D(-5;-5;3) nuqtalar berilgan. AC va BD vektorlar orasidagi burchakni toping

A) 80°

B) 15°

C) 90°

D) 52°

17 / 25

f(x)=2x+3 funksiyasi uchun A(1;5) nuqtadan o’tuvchi boshlang’ich funksiyasini toping.

A) F(x)=x²+3x+1

B) F(x)=x²-3x+1

C) F(x)=x²-3x-1

D) F(x)=x²+3x-1

18 / 25

Agar f(x)=x² va bo`lsa ,f(g(2)) ni toping

A) 0

B) 12

C) 16

D) 36

19 / 25

Karim uyida 14 bet matn terib, 8ta imloviy xatoga yo’l qo’ydi. Agar 1 betda o’rtacha 380 ta so’z bo’lsa, Karim 100ta so’z terganda o’rtacha qancha xato qiladi?

A) 0,25

B) 1,5

C) 0,15

D) 0,5

20 / 25

Funksiya hosilasini toping

f(x)=(2x+4)(3x+1)

A) 3x+1

B) 12x

C) 16x+14

D) 12x+14

21 / 25