Uy » Choraklik online testlar » Matematika choraklik » 11-sinf Matematika 2-chorak Matematika choraklik 11-sinf Matematika 2-chorak InfoMaster Aprel 20, 2021 32 Ko'rishlar 16 izohlar SaqlashSaqlanganOlib tashlandi 1 0 OMAD YOR BO'LSIN! 11-sinf Matematika 2-chorak Testni Mamadoliyev Diyorbek tayyorladi. 1 / 25 Qavariq ko’pburchakning har bir uchidan uchtadan qirra chiqadi. Agar bu ko’pyoqning qirralari soni 12 ta bo’lsa, uning nechta uchi va yog’i mavjud? A) 8;10 B) 4;11 C) 4;10 D) 4;18 2 / 25 Moddiy nuqta qonuniyat bilan harakatlanmoqda, eng katta tezlanishga erishiladigan vaqtni toping. A) 6 B) 5 C) 7 D) 4 3 / 25 To’g’ri to’rtburchak shaklidagi yer maydoninig atrofini o’rashmoqchi. 480 m panjara yordamida eng ko’pi bilan necha kvadrat metr yer maydonni o’rash mumkin? A) 25600 B) 8100 C) 19600 D) 14400 4 / 25 To’g’riburchakli parallelepiped bir uchidan chiquvchi uchta qirralari uzunliklari 4,6 va 9 ga teng. Unga tengdosh kub qirrasining uzunligini toping. A) 7 B) 8 C) 6 D) 6 5 / 25 sonini taqriban hisoblang. A) 3,08 B) 5,01 C) 4,08 D) 5,08 6 / 25 f(x)=sin2x funksiyasining barcha boshlang’ich funksiyalarini toping. A) F(x)=-2cos2x+C B) F(x)=-0,5cos2x+C C) F(x)=2sin4x+c D) F(x)=0,5cos2x+C 7 / 25 Havo shariga t[0;10] minut oralig’ida V(t)=t3+13t2+t+20 (m3) havo purkamoqda. t=10 minutdagi havo hajmini toping. A) 2300 B) 2025 C) 2330 D) 1023 8 / 25 Kub to’la sirtining yuzi 105,84 sm2 bo’lsa, uning har bir yog’i yuzini va qirrasining uzunligini toping. A) 17,68 dm²; 4,2 dm B) 17,64 dm²; 4,2 dm C) 17,64 dm; 4,2 dm D) 17,64 dm²; 4,9 dm 9 / 25 f(x)=excosx funksiyasi uchun f ’(π/2) ni aniqlang. A. e-0.5π B. e0,5π C. eπ D. e-π A) e^(π) B) e^(-0.5π) C) e^(0.5π) D) e^(-π) 10 / 25 Limitni hisoblang: A) -3 B) 4 C) -4 D) 3 11 / 25 Funksiyaning kamayish oraliqlarini toping A) (-2;0) va (0;1) B) (-1;0) va (0;2) C) (-3;0) va (0;1) D) (-1;0) va (0;1) 12 / 25 Moddiy nuqta S(t)=5t3+3t2+2t+4 qonuniyat bilan harakatlanayotgan jismning t=2 sekunddagi tezligini toping. A) 70 B) 84 C) 60 D) 74 13 / 25 Funksiya hosilasini toping f(x)=(2x+4)(3x+1) A) 12x B) 3x+1 C) 16x+14 D) 12x+14 14 / 25 f(x)=2x+3 funksiyasi uchun A(1;5) nuqtadan o’tuvchi boshlang’ich funksiyasini toping. A) F(x)=x²-3x+1 B) F(x)=x²+3x+1 C) F(x)=x²+3x-1 D) F(x)=x²-3x-1 15 / 25 Karim uyida 14 bet matn terib, 8ta imloviy xatoga yo’l qo’ydi. Agar 1 betda o’rtacha 380 ta so’z bo’lsa, Karim 100ta so’z terganda o’rtacha qancha xato qiladi? A) 0,15 B) 1,5 C) 0,5 D) 0,25 16 / 25 funksiya uchun y=2x-1 to`g`ri chiziqqa parallel bo`lgan urinma tenglamasini yozing A) y=2x-2,25 B) y=3x-2,2 C) y=2x+3 D) y=2x 17 / 25 Murakkab funksiyaning hosilasini toping. y=x2sinx A) y’=-2xsinx+x² B) y’=x²cosx-2xsinx C) y’=2xsinx+x²cosx D) y’=2xsinx-x² 18 / 25 funksiya grafigiga x=1 abssisssali nuqtadao`tkazilgan urinma tenglamasini yozing A) y=-x B) y= 2x C) y=1/2 D) y=x 19 / 25 Agar A(1;2;3), B(3;7;6) bo’lsa, A̅B̅ vector koordinatalarini toping A) (4;9;9) B) (-2;-5;-3) C) (4;9;9) D) (2;5;3) 20 / 25 funksiya grafigiga x=4 abssissali nuqtada o`tkazilgan urinma tenglamasini tuzing A) y=35x+30 B) y=10x C) y=20x+20 D) y=35x 21 / 25 Funksiya hosilasini toping: f(x)=5 A) 0 B) x C) 5 D) 10 22 / 25 Uchlari A(4;0;1), B(5;-2;1), C(4;8;5) nuqtalarda bo’lgan uchburchakning AL bissektrisasi uzunligini toping A) 4 B) (4√2)3 C) (4√2)/5 D) (2√5)/3 23 / 25 Funksiya hosilasini toping: A) 14x+12 B) 12x+12 C) 12x²-12 D) 21x²-10x 24 / 25 f(x)=3x2-5x+4 va g(x)=4x-5 funksiyalarining urinmalari parallel bo’ladigan nuqtalarini toping. A) 2 B) 0.5 C) 1.5 D) 0 25 / 25 tgx funksiya hosilasini toping A) sinx B) 1/sinx C) 1/cos²x D) cosx 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Tomonidan Wordpress Quiz plugin Author: InfoMaster Foydali bo'lsa mamnunmiz