Uy » Choraklik online testlar » Matematika choraklik » 11-sinf Matematika 2-chorak Matematika choraklik 11-sinf Matematika 2-chorak InfoMaster Aprel 20, 2021 361 Ko'rishlar 16 izohlar SaqlashSaqlanganOlib tashlandi 1 0 OMAD YOR BO'LSIN! Tomonidan yaratilgan InfoMaster 11-sinf Matematika 2-chorak Testni Mamadoliyev Diyorbek tayyorladi. 1 / 25 To’g’ri to’rtburchak shaklidagi yer maydoninig atrofini o’rashmoqchi. 480 m panjara yordamida eng ko’pi bilan necha kvadrat metr yer maydonni o’rash mumkin? A) 25600 B) 14400 C) 19600 D) 8100 2 / 25 sonini taqriban hisoblang. A) 5,01 B) 5,08 C) 3,08 D) 4,08 3 / 25 Havo shariga t[0;10] minut oralig’ida V(t)=t3+13t2+t+20 (m3) havo purkamoqda. t=10 minutdagi havo hajmini toping. A) 1023 B) 2330 C) 2025 D) 2300 4 / 25 Moddiy nuqta qonuniyat bilan harakatlanmoqda, eng katta tezlanishga erishiladigan vaqtni toping. A) 4 B) 6 C) 7 D) 5 5 / 25 f(x)=excosx funksiyasi uchun f ’(π/2) ni aniqlang. A. e-0.5π B. e0,5π C. eπ D. e-π A) e^(-π) B) e^(π) C) e^(0.5π) D) e^(-0.5π) 6 / 25 To’g’riburchakli parallelepiped asosining tomonlari 7:24 nisbatda, diagonal kesimining yuzi 50dm2 ga teng. Yon sirtining yuzini toping. A) 124 dm B) 224 dm² C) 124 dm² D) 135 dm² 7 / 25 Tandirdan olingan nonning temperaturasi 20 minut ichida 1000 dan 600 gacha pasayadi. Tashqi muhit temperaturasi 250. Nonning temperaturasi qancha vaqtda 300 gacha pasayadi? A) 41 B) 61 C) 51 D) 71 8 / 25 f(x)=sin2x funksiyasining barcha boshlang’ich funksiyalarini toping. A) F(x)=-0,5cos2x+C B) F(x)=0,5cos2x+C C) F(x)=-2cos2x+C D) F(x)=2sin4x+c 9 / 25 F(x)=0.2sin(5x+12) funksiyasi uchun f(x) ni toping A) f(x)=cos(5x+12) B) f(x)=0.5cos(5x+12) C) f(x)=-cos(5x+12) D) f(x)=-0,5sin(5x+12) 10 / 25 Qavariq ko’pburchakning har bir uchidan uchtadan qirra chiqadi. Agar bu ko’pyoqning qirralari soni 12 ta bo’lsa, uning nechta uchi va yog’i mavjud? A) 4;10 B) 8;10 C) 4;18 D) 4;11 11 / 25 A(-4;3;6) nuqtaning Oxz tekisligiga nisbatan simmrtrik nuqtasini toping. A) (-4;-3;6) B) (-4;-3;9) C) (-4;-6;6) D) (-8;-3;6) 12 / 25 limitni hisoblang A) 0 B) 5 C) 7 D) 6 13 / 25 y=-3x3+2x2-4x+5 funksiyaga x0=-1 nuqtada o’tkazilgan urinma tenglamasining burchak koeffitsiyentini toping. A) -13 B) 15 C) 17 D) -17 14 / 25 A) 20 B) 14 C) 13 D) 18 15 / 25 Agar A(1;2;3), B(3;7;6) bo’lsa, A̅B̅ vector koordinatalarini toping A) (-2;-5;-3) B) (4;9;9) C) (2;5;3) D) (4;9;9) 16 / 25 Agar f(x)=x² va bo`lsa ,f(g(-4)) ni toping A) 0 B) 12 C) 36 D) -12 17 / 25 Koordinatalar boshidan y=x2-4x+3 parabolaning simmetriya o’qigacha bo’lgan masofani toping. A) 4 B) 3 C) 2 D) 1 18 / 25 Moddiy nuqtaning berilgan t vaqtdagi tezligini hisoblang: , t=5 A) 75 B) 70 C) 90 D) 80 19 / 25 funksiya uchun y=2x-1 to`g`ri chiziqqa parallel bo`lgan urinma tenglamasini yozing A) y=2x B) y=2x+3 C) y=3x-2,2 D) y=2x-2,25 20 / 25 Agar f(x)=x² va bo`lsa ,f(g(2)) ni toping A) 12 B) 16 C) 0 D) 36 21 / 25 Uchlari A(2;3;4) va B(-4;-5;-6) nuqtalarda bo’lgan AB kesmasining o’rtasining koordinatalarini toping. A) (-1;-1;-1) B) (-1;-1;-4) C) (-2;-4;-1) D) (-1;-3;-1) 22 / 25 funksiya grafigiga x=1 abssisssali nuqtadao`tkazilgan urinma tenglamasini yozing A) y=1/2 B) y=x C) y= 2x D) y=-x 23 / 25 Nargiza 4minutda 260ta so`zni terib, 7ta imloviy xatoga yo`l qo`ydi. Nargizaning matn terish sifatini aniqlang A) 0,01 B) 0,0269 C) 0,5 D) 0,6 24 / 25 Funksiyaning statsionar nuqtalarini toping A) x=3, x=2 B) x=-1, x=3 C) x=0, x=2 D) x=-1, x=2 25 / 25 Funksiya hosilasini toping f(x)=(2x+4)(3x+1) A) 12x+14 B) 3x+1 C) 12x D) 16x+14 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz