Uy » Choraklik online testlar » Matematika choraklik » 11-sinf Matematika 2-chorak Matematika choraklik 11-sinf Matematika 2-chorak InfoMaster Aprel 20, 2021 378 Ko'rishlar 16 izohlar SaqlashSaqlanganOlib tashlandi 1 0 OMAD YOR BO'LSIN! Tomonidan yaratilgan InfoMaster 11-sinf Matematika 2-chorak Testni Mamadoliyev Diyorbek tayyorladi. 1 / 25 Tandirdan olingan nonning temperaturasi 20 minut ichida 1000 dan 600 gacha pasayadi. Tashqi muhit temperaturasi 250. Nonning temperaturasi qancha vaqtda 300 gacha pasayadi? A) 61 B) 41 C) 71 D) 51 2 / 25 Kub to’la sirtining yuzi 105,84 sm2 bo’lsa, uning har bir yog’i yuzini va qirrasining uzunligini toping. A) 17,64 dm; 4,2 dm B) 17,64 dm²; 4,9 dm C) 17,68 dm²; 4,2 dm D) 17,64 dm²; 4,2 dm 3 / 25 f(x)=(3x+2)2 funksiyasining barcha boshlang’ich funksiyalarini toping. A) F(x)=6x³+3x²-4 B) F(x)=6x³+6x²+4 C) F(x)=6x³+6x+4 D) F(x)=6x³+3x²+4 4 / 25 To’g’riburchakli parallelepiped bir uchidan chiquvchi uchta qirralari uzunliklari 4,6 va 9 ga teng. Unga tengdosh kub qirrasining uzunligini toping. A) 8 B) 6 C) 6 D) 7 5 / 25 f(x)=sin2x funksiyasining barcha boshlang’ich funksiyalarini toping. A) F(x)=-2cos2x+C B) F(x)=0,5cos2x+C C) F(x)=2sin4x+c D) F(x)=-0,5cos2x+C 6 / 25 Moddiy nuqta qonuniyat bilan harakatlanmoqda, eng katta tezlanishga erishiladigan vaqtni toping. A) 4 B) 5 C) 7 D) 6 7 / 25 Havo shariga t[0;10] minut oralig’ida V(t)=t3+13t2+t+20 (m3) havo purkamoqda. t=10 minutdagi havo hajmini toping. A) 2330 B) 2025 C) 1023 D) 2300 8 / 25 Funksiyaning kamayish oraliqlarini toping A) (-2;0) va (0;1) B) (-3;0) va (0;1) C) (-1;0) va (0;1) D) (-1;0) va (0;2) 9 / 25 Uchlari A(2;3;4) va B(-4;-5;-6) nuqtalarda bo’lgan AB kesmasining o’rtasining koordinatalarini toping. A) (-1;-1;-1) B) (-2;-4;-1) C) (-1;-1;-4) D) (-1;-3;-1) 10 / 25 Funksiya hosilasini toping: A) 12x+12 B) 12x²-12 C) 14x+12 D) 21x²-10x 11 / 25 funksiya uchun y=2x-1 to`g`ri chiziqqa parallel bo`lgan urinma tenglamasini yozing A) y=3x-2,2 B) y=2x C) y=2x-2,25 D) y=2x+3 12 / 25 f(x)=3x2-5x+4 va g(x)=4x-5 funksiyalarining urinmalari parallel bo’ladigan nuqtalarini toping. A) 2 B) 0 C) 1.5 D) 0.5 13 / 25 funksiya grafigiga x=4 abssissali nuqtada o`tkazilgan urinma tenglamasini tuzing A) y=10x B) y=20x+20 C) y=35x+30 D) y=35x 14 / 25 Karim 3 minutda 213ta so`zni terib , 6ta imloviy xatoga yo`l qo`ydi. Karimning matn terish sifatini toping. A) 0,0282 B) 0,0321 C) 0,623 D) 0,3265 15 / 25 A(-4;3;6) nuqtaning Oxz tekisligiga nisbatan simmrtrik nuqtasini toping. A) (-4;-6;6) B) (-4;-3;6) C) (-4;-3;9) D) (-8;-3;6) 16 / 25 Limitni hisoblang: A) 3 B) -3 C) 4 D) -4 17 / 25 Murakkab funksiyaning hosilasini toping. y=x2sinx A) y’=x²cosx-2xsinx B) y’=2xsinx+x²cosx C) y’=2xsinx-x² D) y’=-2xsinx+x² 18 / 25 Funksiyaning statsionar nuqtalarini toping A) x=0, x=2 B) x=-1, x=3 C) x=3, x=2 D) x=-1, x=2 19 / 25 Uchlari A(4;0;1), B(5;-2;1), C(4;8;5) nuqtalarda bo’lgan uchburchakning AL bissektrisasi uzunligini toping A) (4√2)/5 B) (2√5)/3 C) (4√2)3 D) 4 20 / 25 Agar f(x)=x² va bo`lsa ,f(g(-4)) ni toping A) 12 B) 36 C) 0 D) -12 21 / 25 Moddiy nuqta S(t)=5t3+3t2+2t+4 qonuniyat bilan harakatlanayotgan jismning t=2 sekunddagi tezligini toping. A) 70 B) 74 C) 84 D) 60 22 / 25 tgx funksiya hosilasini toping A) 1/cos²x B) sinx C) cosx D) 1/sinx 23 / 25 f(x)=2x+3 funksiyasi uchun A(1;5) nuqtadan o’tuvchi boshlang’ich funksiyasini toping. A) F(x)=x²-3x+1 B) F(x)=x²+3x-1 C) F(x)=x²+3x+1 D) F(x)=x²-3x-1 24 / 25 A(1;-2;2), B(1;4;0), C(-4;1;1) va D(-5;-5;3) nuqtalar berilgan. AC va BD vektorlar orasidagi burchakni toping A) 52° B) 90° C) 15° D) 80° 25 / 25 funksiya grafigiga x=1 abssisssali nuqtadao`tkazilgan urinma tenglamasini yozing A) y=1/2 B) y=-x C) y= 2x D) y=x 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz