Uy » Choraklik online testlar » Matematika choraklik » 11-sinf Matematika 2-chorak Matematika choraklik 11-sinf Matematika 2-chorak InfoMaster Aprel 20, 2021 39 Ko'rishlar 16 izohlar SaqlashSaqlanganOlib tashlandi 1 0 OMAD YOR BO'LSIN! 11-sinf Matematika 2-chorak Testni Mamadoliyev Diyorbek tayyorladi. 1 / 25 funksiyaning [-4;1] kesmadagi eng kata qiymatini toping. A) -4 B) 131 C) 13 D) -13 2 / 25 A(2;0;-3) va B(3;4;0) nuqtalar orasidagi masofani toping A) 16 B) √26 C) √24 D) 25 3 / 25 Funksiyaning kamayish oraliqlarini toping A) (-1;0) va (0;2) B) (-2;0) va (0;1) C) (-3;0) va (0;1) D) (-1;0) va (0;1) 4 / 25 Agar f(x)=x² va bo`lsa ,f(g(2)) ni toping A) 36 B) 12 C) 0 D) 16 5 / 25 Funksiya hosilasini toping f(x)=(2x+4)(3x+1) A) 16x+14 B) 12x C) 12x+14 D) 3x+1 6 / 25 Koordinatalar boshidan y=x2-4x+3 parabolaning simmetriya o’qigacha bo’lgan masofani toping. A) 3 B) 4 C) 1 D) 2 7 / 25 Limitni hisoblang: A) 4 B) 3 C) -4 D) -3 8 / 25 Funksiyaning statsionar nuqtalarini toping A) x=0, x=2 B) x=-1, x=3 C) x=-1, x=2 D) x=3, x=2 9 / 25 A(1;-2;2), B(1;4;0), C(-4;1;1) va D(-5;-5;3) nuqtalar berilgan. AC va BD vektorlar orasidagi burchakni toping A) 52° B) 80° C) 15° D) 90° 10 / 25 Funksiya hosilasini toping: A) 14x+12 B) 12x+12 C) 12x²-12 D) 21x²-10x 11 / 25 Moddiy nuqta S(t)=5t3+3t2+2t+4 qonuniyat bilan harakatlanayotgan jismning t=2 sekunddagi tezligini toping. A) 84 B) 70 C) 60 D) 74 12 / 25 Uchlari A(4;0;1), B(5;-2;1), C(4;8;5) nuqtalarda bo’lgan uchburchakning AL bissektrisasi uzunligini toping A) (4√2)/5 B) (2√5)/3 C) (4√2)3 D) 4 13 / 25 funksiyasining kamayish oralig’ini toping. A) [-1;-1/3] B) (-1/3;+∞) C) (-1;1/3) D) (-∞;-1) 14 / 25 Karim 3 minutda 213ta so`zni terib , 6ta imloviy xatoga yo`l qo`ydi. Karimning matn terish sifatini toping. A) 0,3265 B) 0,623 C) 0,0282 D) 0,0321 15 / 25 Murakkab funksiyaning hosilasini toping. y=x2sinx A) y’=2xsinx+x²cosx B) y’=x²cosx-2xsinx C) y’=-2xsinx+x² D) y’=2xsinx-x² 16 / 25 Uchlari A(2;-3;4) va B(-2;4;5) nuqtalarda bo’lgan AB kesmasining uzunligini toping A) √24 B) √55 C) √19 D) √66 17 / 25 funksiya hosilasining x0=-2 nuqtadagi qiymatini hisoblang. A) 38/961 B) 38/31 C) -38/961 D) -38/31 18 / 25 To’g’riburchakli parallelepiped asosining tomonlari 7:24 nisbatda, diagonal kesimining yuzi 50dm2 ga teng. Yon sirtining yuzini toping. A) 124 dm² B) 135 dm² C) 224 dm² D) 124 dm 19 / 25 To’g’riburchakli parallelepiped bir uchidan chiquvchi uchta qirralari uzunliklari 4,6 va 9 ga teng. Unga tengdosh kub qirrasining uzunligini toping. A) 7 B) 8 C) 6 D) 6 20 / 25 f(x)=(3x+2)2 funksiyasining barcha boshlang’ich funksiyalarini toping. A) F(x)=6x³+6x+4 B) F(x)=6x³+3x²-4 C) F(x)=6x³+6x²+4 D) F(x)=6x³+3x²+4 21 / 25 sonini taqriban hisoblang. A) 4,08 B) 5,08 C) 3,08 D) 5,01 22 / 25 Qavariq ko’pburchakning har bir uchidan uchtadan qirra chiqadi. Agar bu ko’pyoqning qirralari soni 12 ta bo’lsa, uning nechta uchi va yog’i mavjud? A) 4;10 B) 4;18 C) 8;10 D) 4;11 23 / 25 Moddiy nuqta qonuniyat bilan harakatlanmoqda, eng katta tezlanishga erishiladigan vaqtni toping. A) 6 B) 4 C) 5 D) 7 24 / 25 F(x)=0.2sin(5x+12) funksiyasi uchun f(x) ni toping A) f(x)=cos(5x+12) B) f(x)=-0,5sin(5x+12) C) f(x)=-cos(5x+12) D) f(x)=0.5cos(5x+12) 25 / 25 Havo shariga t[0;10] minut oralig’ida V(t)=t3+13t2+t+20 (m3) havo purkamoqda. t=10 minutdagi havo hajmini toping. A) 2025 B) 2300 C) 2330 D) 1023 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Tomonidan Wordpress Quiz plugin Author: InfoMaster Foydali bo'lsa mamnunmiz