Uy » Choraklik online testlar » Matematika choraklik » 11-sinf Matematika 2-chorak Matematika choraklik 11-sinf Matematika 2-chorak InfoMaster Aprel 20, 2021 354 Ko'rishlar 16 izohlar SaqlashSaqlanganOlib tashlandi 1 0 OMAD YOR BO'LSIN! Tomonidan yaratilgan InfoMaster 11-sinf Matematika 2-chorak Testni Mamadoliyev Diyorbek tayyorladi. 1 / 25 A(2;0;-3) va B(3;4;0) nuqtalar orasidagi masofani toping A) 16 B) √24 C) 25 D) √26 2 / 25 Funksiyaning kamayish oraliqlarini toping A) (-1;0) va (0;2) B) (-3;0) va (0;1) C) (-1;0) va (0;1) D) (-2;0) va (0;1) 3 / 25 y=-3x3+2x2-4x+5 funksiyaga x0=-1 nuqtada o’tkazilgan urinma tenglamasining burchak koeffitsiyentini toping. A) -17 B) 17 C) 15 D) -13 4 / 25 A(1;-2;2), B(1;4;0), C(-4;1;1) va D(-5;-5;3) nuqtalar berilgan. AC va BD vektorlar orasidagi burchakni toping A) 52° B) 15° C) 90° D) 80° 5 / 25 Koordinatalar boshidan y=x2-4x+3 parabolaning simmetriya o’qigacha bo’lgan masofani toping. A) 2 B) 1 C) 4 D) 3 6 / 25 Uchlari A(2;3;4) va B(-4;-5;-6) nuqtalarda bo’lgan AB kesmasining o’rtasining koordinatalarini toping. A) (-1;-1;-1) B) (-1;-3;-1) C) (-1;-1;-4) D) (-2;-4;-1) 7 / 25 funksiya uchun y=2x-1 to`g`ri chiziqqa parallel bo`lgan urinma tenglamasini yozing A) y=2x+3 B) y=2x C) y=3x-2,2 D) y=2x-2,25 8 / 25 Karim 3 minutda 213ta so`zni terib , 6ta imloviy xatoga yo`l qo`ydi. Karimning matn terish sifatini toping. A) 0,3265 B) 0,623 C) 0,0282 D) 0,0321 9 / 25 funksiya grafigiga x=4 abssissali nuqtada o`tkazilgan urinma tenglamasini tuzing A) y=35x B) y=10x C) y=20x+20 D) y=35x+30 10 / 25 Agar f(x)=x² va bo`lsa ,f(g(-4)) ni toping A) -12 B) 36 C) 0 D) 12 11 / 25 A(-4;3;6) nuqtaning Oxz tekisligiga nisbatan simmrtrik nuqtasini toping. A) (-4;-3;9) B) (-4;-6;6) C) (-4;-3;6) D) (-8;-3;6) 12 / 25 Limitni hisoblang: A) -4 B) 3 C) -3 D) 4 13 / 25 A) 13 B) 14 C) 20 D) 18 14 / 25 funksiyaning [-4;1] kesmadagi eng kata qiymatini toping. A) 131 B) -13 C) 13 D) -4 15 / 25 Agar A(1;2;3), B(3;7;6) bo’lsa, A̅B̅ vector koordinatalarini toping A) (2;5;3) B) (4;9;9) C) (4;9;9) D) (-2;-5;-3) 16 / 25 f(x)=3x2-5x+4 va g(x)=4x-5 funksiyalarining urinmalari parallel bo’ladigan nuqtalarini toping. A) 0 B) 1.5 C) 0.5 D) 2 17 / 25 Uchlari A(4;0;1), B(5;-2;1), C(4;8;5) nuqtalarda bo’lgan uchburchakning AL bissektrisasi uzunligini toping A) (4√2)3 B) 4 C) (2√5)/3 D) (4√2)/5 18 / 25 Funksiya hosilasini toping: f(x)=5 A) 5 B) 0 C) x D) 10 19 / 25 Nargiza 4minutda 260ta so`zni terib, 7ta imloviy xatoga yo`l qo`ydi. Nargizaning matn terish sifatini aniqlang A) 0,5 B) 0,0269 C) 0,6 D) 0,01 20 / 25 funksiya hosilasining x0=-2 nuqtadagi qiymatini hisoblang. A) 38/31 B) 38/961 C) -38/31 D) -38/961 21 / 25 Funksiyaning statsionar nuqtalarini toping A) x=-1, x=2 B) x=3, x=2 C) x=-1, x=3 D) x=0, x=2 22 / 25 Qavariq ko’pburchakning har bir uchidan uchtadan qirra chiqadi. Agar bu ko’pyoqning qirralari soni 12 ta bo’lsa, uning nechta uchi va yog’i mavjud? A) 4;18 B) 4;11 C) 8;10 D) 4;10 23 / 25 F(x)=0.2sin(5x+12) funksiyasi uchun f(x) ni toping A) f(x)=-cos(5x+12) B) f(x)=-0,5sin(5x+12) C) f(x)=cos(5x+12) D) f(x)=0.5cos(5x+12) 24 / 25 sonini taqriban hisoblang. A) 4,08 B) 3,08 C) 5,08 D) 5,01 25 / 25 To’g’riburchakli parallelepiped asosining tomonlari 7:24 nisbatda, diagonal kesimining yuzi 50dm2 ga teng. Yon sirtining yuzini toping. A) 135 dm² B) 224 dm² C) 124 dm D) 124 dm² 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz