Uy » Choraklik online testlar » Matematika choraklik » 11-sinf Matematika 2-chorak Matematika choraklik 11-sinf Matematika 2-chorak InfoMaster Aprel 20, 2021 373 Ko'rishlar 16 izohlar SaqlashSaqlanganOlib tashlandi 1 1 OMAD YOR BO'LSIN! Tomonidan yaratilgan InfoMaster 11-sinf Matematika 2-chorak Testni Mamadoliyev Diyorbek tayyorladi. 1 / 25 Uchlari A(2;-3;4) va B(-2;4;5) nuqtalarda bo’lgan AB kesmasining uzunligini toping A) √66 B) √19 C) √55 D) √24 2 / 25 Koordinatalar boshidan y=x2-4x+3 parabolaning simmetriya o’qigacha bo’lgan masofani toping. A) 2 B) 1 C) 4 D) 3 3 / 25 f(x)=3x2-5x+4 va g(x)=4x-5 funksiyalarining urinmalari parallel bo’ladigan nuqtalarini toping. A) 2 B) 1.5 C) 0 D) 0.5 4 / 25 f(x)=2x+3 funksiyasi uchun A(1;5) nuqtadan o’tuvchi boshlang’ich funksiyasini toping. A) F(x)=x²-3x-1 B) F(x)=x²+3x+1 C) F(x)=x²-3x+1 D) F(x)=x²+3x-1 5 / 25 A(2;0;-3) va B(3;4;0) nuqtalar orasidagi masofani toping A) 25 B) √26 C) √24 D) 16 6 / 25 Funksiya hosilasini toping: A) 12x²-12 B) 12x+12 C) 14x+12 D) 21x²-10x 7 / 25 Agar f(x)=x² va bo`lsa ,f(g(-4)) ni toping A) -12 B) 12 C) 36 D) 0 8 / 25 Moddiy nuqtaning berilgan t vaqtdagi tezligini hisoblang: , t=5 A) 75 B) 70 C) 80 D) 90 9 / 25 Uchlari A(4;0;1), B(5;-2;1), C(4;8;5) nuqtalarda bo’lgan uchburchakning AL bissektrisasi uzunligini toping A) 4 B) (4√2)/5 C) (2√5)/3 D) (4√2)3 10 / 25 funksiyaning [-4;2] oraliqdagi eng katta qiymatini toping A) 18 B) 17 C) 16 D) 14 11 / 25 funksiya hosilasining x0=-2 nuqtadagi qiymatini hisoblang. A) 38/31 B) -38/961 C) 38/961 D) -38/31 12 / 25 Funksiya hosilasini toping f(x)=(2x+4)(3x+1) A) 12x+14 B) 3x+1 C) 12x D) 16x+14 13 / 25 Uchlari A(2;3;4) va B(-4;-5;-6) nuqtalarda bo’lgan AB kesmasining o’rtasining koordinatalarini toping. A) (-1;-1;-4) B) (-2;-4;-1) C) (-1;-1;-1) D) (-1;-3;-1) 14 / 25 funksiyasining kamayish oralig’ini toping. A) (-1/3;+∞) B) (-∞;-1) C) (-1;1/3) D) [-1;-1/3] 15 / 25 Agar f(x)=x² va bo`lsa ,f(g(2)) ni toping A) 0 B) 36 C) 16 D) 12 16 / 25 A) 18 B) 13 C) 14 D) 20 17 / 25 Moddiy nuqta S(t)=5t3+3t2+2t+4 qonuniyat bilan harakatlanayotgan jismning t=2 sekunddagi tezligini toping. A) 70 B) 60 C) 74 D) 84 18 / 25 Havo shariga t[0;10] minut oralig’ida V(t)=t3+13t2+t+20 (m3) havo purkamoqda. t=10 minutdagi havo hajmini toping. A) 2330 B) 1023 C) 2300 D) 2025 19 / 25 Qavariq ko’pburchakning har bir uchidan uchtadan qirra chiqadi. Agar bu ko’pyoqning qirralari soni 12 ta bo’lsa, uning nechta uchi va yog’i mavjud? A) 4;18 B) 4;10 C) 8;10 D) 4;11 20 / 25 f(x)=sin2x funksiyasining barcha boshlang’ich funksiyalarini toping. A) F(x)=0,5cos2x+C B) F(x)=2sin4x+c C) F(x)=-0,5cos2x+C D) F(x)=-2cos2x+C 21 / 25 f(x)=excosx funksiyasi uchun f ’(π/2) ni aniqlang. A. e-0.5π B. e0,5π C. eπ D. e-π A) e^(-π) B) e^(π) C) e^(0.5π) D) e^(-0.5π) 22 / 25 sonini taqriban hisoblang. A) 3,08 B) 4,08 C) 5,01 D) 5,08 23 / 25 To’g’riburchakli parallelepiped bir uchidan chiquvchi uchta qirralari uzunliklari 4,6 va 9 ga teng. Unga tengdosh kub qirrasining uzunligini toping. A) 6 B) 7 C) 6 D) 8 24 / 25 f(x)=(3x+2)2 funksiyasining barcha boshlang’ich funksiyalarini toping. A) F(x)=6x³+3x²-4 B) F(x)=6x³+6x+4 C) F(x)=6x³+6x²+4 D) F(x)=6x³+3x²+4 25 / 25 F(x)=0.2sin(5x+12) funksiyasi uchun f(x) ni toping A) f(x)=cos(5x+12) B) f(x)=0.5cos(5x+12) C) f(x)=-cos(5x+12) D) f(x)=-0,5sin(5x+12) 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz