Uy » Choraklik online testlar » Matematika choraklik » 11-sinf Matematika 2-chorak Matematika choraklik 11-sinf Matematika 2-chorak InfoMaster Aprel 20, 2021 375 Ko'rishlar 16 izohlar SaqlashSaqlanganOlib tashlandi 1 0 OMAD YOR BO'LSIN! Tomonidan yaratilgan InfoMaster 11-sinf Matematika 2-chorak Testni Mamadoliyev Diyorbek tayyorladi. 1 / 25 funksiya grafigiga x=4 abssissali nuqtada o`tkazilgan urinma tenglamasini tuzing A) y=20x+20 B) y=35x+30 C) y=10x D) y=35x 2 / 25 A(1;-2;2), B(1;4;0), C(-4;1;1) va D(-5;-5;3) nuqtalar berilgan. AC va BD vektorlar orasidagi burchakni toping A) 15° B) 90° C) 52° D) 80° 3 / 25 A) 18 B) 13 C) 20 D) 14 4 / 25 Funksiya hosilasini toping: A) 14x+12 B) 12x²-12 C) 12x+12 D) 21x²-10x 5 / 25 Koordinatalar boshidan y=x2-4x+3 parabolaning simmetriya o’qigacha bo’lgan masofani toping. A) 1 B) 4 C) 3 D) 2 6 / 25 Agar f(x)=x² va bo`lsa ,f(g(-4)) ni toping A) 0 B) 36 C) 12 D) -12 7 / 25 Agar f(x)=x² va bo`lsa ,f(g(2)) ni toping A) 36 B) 12 C) 0 D) 16 8 / 25 funksiyaning [-4;1] kesmadagi eng kata qiymatini toping. A) -13 B) -4 C) 131 D) 13 9 / 25 A(-4;3;6) nuqtaning Oxz tekisligiga nisbatan simmrtrik nuqtasini toping. A) (-4;-3;6) B) (-8;-3;6) C) (-4;-3;9) D) (-4;-6;6) 10 / 25 Limitni hisoblang: A) 3 B) 4 C) -4 D) -3 11 / 25 Uchlari A(2;3;4) va B(-4;-5;-6) nuqtalarda bo’lgan AB kesmasining o’rtasining koordinatalarini toping. A) (-2;-4;-1) B) (-1;-1;-1) C) (-1;-1;-4) D) (-1;-3;-1) 12 / 25 Uchlari A(2;-3;4) va B(-2;4;5) nuqtalarda bo’lgan AB kesmasining uzunligini toping A) √19 B) √55 C) √66 D) √24 13 / 25 f(x)=3x2-5x+4 va g(x)=4x-5 funksiyalarining urinmalari parallel bo’ladigan nuqtalarini toping. A) 2 B) 0.5 C) 1.5 D) 0 14 / 25 Karim uyida 14 bet matn terib, 8ta imloviy xatoga yo’l qo’ydi. Agar 1 betda o’rtacha 380 ta so’z bo’lsa, Karim 100ta so’z terganda o’rtacha qancha xato qiladi? A) 1,5 B) 0,5 C) 0,25 D) 0,15 15 / 25 Karim 3 minutda 213ta so`zni terib , 6ta imloviy xatoga yo`l qo`ydi. Karimning matn terish sifatini toping. A) 0,3265 B) 0,0321 C) 0,623 D) 0,0282 16 / 25 Funksiya hosilasini toping: f(x)=5 A) 5 B) x C) 0 D) 10 17 / 25 funksiyasining kamayish oralig’ini toping. A) [-1;-1/3] B) (-1/3;+∞) C) (-1;1/3) D) (-∞;-1) 18 / 25 limitni hisoblang A) 0 B) 6 C) 5 D) 7 19 / 25 funksiyaning [-4;2] oraliqdagi eng katta qiymatini toping A) 14 B) 17 C) 18 D) 16 20 / 25 Funksiyaning statsionar nuqtalarini toping A) x=-1, x=2 B) x=-1, x=3 C) x=3, x=2 D) x=0, x=2 21 / 25 A(2;0;-3) va B(3;4;0) nuqtalar orasidagi masofani toping A) 16 B) √26 C) 25 D) √24 22 / 25 Qavariq ko’pburchakning har bir uchidan uchtadan qirra chiqadi. Agar bu ko’pyoqning qirralari soni 12 ta bo’lsa, uning nechta uchi va yog’i mavjud? A) 4;11 B) 4;18 C) 4;10 D) 8;10 23 / 25 Moddiy nuqta qonuniyat bilan harakatlanmoqda, eng katta tezlanishga erishiladigan vaqtni toping. A) 6 B) 7 C) 5 D) 4 24 / 25 Havo shariga t[0;10] minut oralig’ida V(t)=t3+13t2+t+20 (m3) havo purkamoqda. t=10 minutdagi havo hajmini toping. A) 2025 B) 2300 C) 1023 D) 2330 25 / 25 To’g’riburchakli parallelepiped bir uchidan chiquvchi uchta qirralari uzunliklari 4,6 va 9 ga teng. Unga tengdosh kub qirrasining uzunligini toping. A) 7 B) 8 C) 6 D) 6 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz