Uy » Choraklik online testlar » Matematika choraklik » 11-sinf Matematika 2-chorak Matematika choraklik 11-sinf Matematika 2-chorak InfoMaster Aprel 20, 2021 39 Ko'rishlar 16 izohlar SaqlashSaqlanganOlib tashlandi 1 0 OMAD YOR BO'LSIN! 11-sinf Matematika 2-chorak Testni Mamadoliyev Diyorbek tayyorladi. 1 / 25 Havo shariga t[0;10] minut oralig’ida V(t)=t3+13t2+t+20 (m3) havo purkamoqda. t=10 minutdagi havo hajmini toping. A) 2330 B) 2025 C) 1023 D) 2300 2 / 25 Kub to’la sirtining yuzi 105,84 sm2 bo’lsa, uning har bir yog’i yuzini va qirrasining uzunligini toping. A) 17,64 dm²; 4,2 dm B) 17,64 dm; 4,2 dm C) 17,64 dm²; 4,9 dm D) 17,68 dm²; 4,2 dm 3 / 25 F(x)=0.2sin(5x+12) funksiyasi uchun f(x) ni toping A) f(x)=cos(5x+12) B) f(x)=-cos(5x+12) C) f(x)=-0,5sin(5x+12) D) f(x)=0.5cos(5x+12) 4 / 25 f(x)=sin2x funksiyasining barcha boshlang’ich funksiyalarini toping. A) F(x)=-2cos2x+C B) F(x)=0,5cos2x+C C) F(x)=-0,5cos2x+C D) F(x)=2sin4x+c 5 / 25 Moddiy nuqta qonuniyat bilan harakatlanmoqda, eng katta tezlanishga erishiladigan vaqtni toping. A) 4 B) 7 C) 6 D) 5 6 / 25 f(x)=(3x+2)2 funksiyasining barcha boshlang’ich funksiyalarini toping. A) F(x)=6x³+3x²+4 B) F(x)=6x³+3x²-4 C) F(x)=6x³+6x²+4 D) F(x)=6x³+6x+4 7 / 25 f(x)=excosx funksiyasi uchun f ’(π/2) ni aniqlang. A. e-0.5π B. e0,5π C. eπ D. e-π A) e^(-0.5π) B) e^(0.5π) C) e^(π) D) e^(-π) 8 / 25 f(x)=3x2-5x+4 va g(x)=4x-5 funksiyalarining urinmalari parallel bo’ladigan nuqtalarini toping. A) 0.5 B) 2 C) 0 D) 1.5 9 / 25 Uchlari A(2;-3;4) va B(-2;4;5) nuqtalarda bo’lgan AB kesmasining uzunligini toping A) √55 B) √24 C) √19 D) √66 10 / 25 Limitni hisoblang: A) 4 B) 3 C) -3 D) -4 11 / 25 Agar f(x)=x² va bo`lsa ,f(g(-4)) ni toping A) 12 B) 36 C) -12 D) 0 12 / 25 Koordinatalar boshidan y=x2-4x+3 parabolaning simmetriya o’qigacha bo’lgan masofani toping. A) 1 B) 3 C) 2 D) 4 13 / 25 funksiya uchun y=2x-1 to`g`ri chiziqqa parallel bo`lgan urinma tenglamasini yozing A) y=2x B) y=2x-2,25 C) y=3x-2,2 D) y=2x+3 14 / 25 tgx funksiya hosilasini toping A) 1/cos²x B) sinx C) cosx D) 1/sinx 15 / 25 y=-3x3+2x2-4x+5 funksiyaga x0=-1 nuqtada o’tkazilgan urinma tenglamasining burchak koeffitsiyentini toping. A) 15 B) -17 C) 17 D) -13 16 / 25 Nargiza 4minutda 260ta so`zni terib, 7ta imloviy xatoga yo`l qo`ydi. Nargizaning matn terish sifatini aniqlang A) 0,6 B) 0,0269 C) 0,5 D) 0,01 17 / 25 limitni hisoblang A) 0 B) 5 C) 6 D) 7 18 / 25 funksiyasining kamayish oralig’ini toping. A) (-1;1/3) B) (-∞;-1) C) [-1;-1/3] D) (-1/3;+∞) 19 / 25 Uchlari A(4;0;1), B(5;-2;1), C(4;8;5) nuqtalarda bo’lgan uchburchakning AL bissektrisasi uzunligini toping A) 4 B) (4√2)3 C) (4√2)/5 D) (2√5)/3 20 / 25 A(1;-2;2), B(1;4;0), C(-4;1;1) va D(-5;-5;3) nuqtalar berilgan. AC va BD vektorlar orasidagi burchakni toping A) 90° B) 15° C) 52° D) 80° 21 / 25 Funksiyaning statsionar nuqtalarini toping A) x=0, x=2 B) x=-1, x=2 C) x=-1, x=3 D) x=3, x=2 22 / 25 funksiya grafigiga x=4 abssissali nuqtada o`tkazilgan urinma tenglamasini tuzing A) y=35x+30 B) y=20x+20 C) y=10x D) y=35x 23 / 25 Karim uyida 14 bet matn terib, 8ta imloviy xatoga yo’l qo’ydi. Agar 1 betda o’rtacha 380 ta so’z bo’lsa, Karim 100ta so’z terganda o’rtacha qancha xato qiladi? A) 1,5 B) 0,15 C) 0,25 D) 0,5 24 / 25 funksiyaning [-4;1] kesmadagi eng kata qiymatini toping. A) 131 B) 13 C) -13 D) -4 25 / 25 Funksiya hosilasini toping: f(x)=5 A) 5 B) x C) 0 D) 10 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Tomonidan Wordpress Quiz plugin Author: InfoMaster Foydali bo'lsa mamnunmiz