Uy » Choraklik online testlar » Matematika choraklik » 11-sinf Matematika 2-chorak Matematika choraklik 11-sinf Matematika 2-chorak InfoMaster Aprel 20, 2021 349 Ko'rishlar 16 izohlar SaqlashSaqlanganOlib tashlandi 1 0 OMAD YOR BO'LSIN! Tomonidan yaratilgan InfoMaster 11-sinf Matematika 2-chorak Testni Mamadoliyev Diyorbek tayyorladi. 1 / 25 A) 18 B) 14 C) 13 D) 20 2 / 25 funksiya uchun y=2x-1 to`g`ri chiziqqa parallel bo`lgan urinma tenglamasini yozing A) y=3x-2,2 B) y=2x-2,25 C) y=2x D) y=2x+3 3 / 25 Funksiyaning statsionar nuqtalarini toping A) x=0, x=2 B) x=-1, x=2 C) x=3, x=2 D) x=-1, x=3 4 / 25 A(2;0;-3) va B(3;4;0) nuqtalar orasidagi masofani toping A) √26 B) 16 C) √24 D) 25 5 / 25 Agar A(1;2;3), B(3;7;6) bo’lsa, A̅B̅ vector koordinatalarini toping A) (4;9;9) B) (-2;-5;-3) C) (2;5;3) D) (4;9;9) 6 / 25 funksiyaning [-4;2] oraliqdagi eng katta qiymatini toping A) 14 B) 18 C) 16 D) 17 7 / 25 f(x)=2x+3 funksiyasi uchun A(1;5) nuqtadan o’tuvchi boshlang’ich funksiyasini toping. A) F(x)=x²+3x-1 B) F(x)=x²-3x+1 C) F(x)=x²-3x-1 D) F(x)=x²+3x+1 8 / 25 Uchlari A(2;-3;4) va B(-2;4;5) nuqtalarda bo’lgan AB kesmasining uzunligini toping A) √19 B) √66 C) √24 D) √55 9 / 25 Limitni hisoblang: A) -4 B) 4 C) 3 D) -3 10 / 25 funksiya grafigiga x=1 abssisssali nuqtadao`tkazilgan urinma tenglamasini yozing A) y=-x B) y=x C) y= 2x D) y=1/2 11 / 25 Agar f(x)=x² va bo`lsa ,f(g(2)) ni toping A) 12 B) 36 C) 0 D) 16 12 / 25 Uchlari A(4;0;1), B(5;-2;1), C(4;8;5) nuqtalarda bo’lgan uchburchakning AL bissektrisasi uzunligini toping A) 4 B) (2√5)/3 C) (4√2)/5 D) (4√2)3 13 / 25 funksiyasining kamayish oralig’ini toping. A) [-1;-1/3] B) (-1;1/3) C) (-1/3;+∞) D) (-∞;-1) 14 / 25 Karim 3 minutda 213ta so`zni terib , 6ta imloviy xatoga yo`l qo`ydi. Karimning matn terish sifatini toping. A) 0,3265 B) 0,623 C) 0,0282 D) 0,0321 15 / 25 Uchlari A(2;3;4) va B(-4;-5;-6) nuqtalarda bo’lgan AB kesmasining o’rtasining koordinatalarini toping. A) (-2;-4;-1) B) (-1;-1;-4) C) (-1;-1;-1) D) (-1;-3;-1) 16 / 25 A(1;-2;2), B(1;4;0), C(-4;1;1) va D(-5;-5;3) nuqtalar berilgan. AC va BD vektorlar orasidagi burchakni toping A) 52° B) 90° C) 80° D) 15° 17 / 25 funksiya hosilasining x0=-2 nuqtadagi qiymatini hisoblang. A) -38/31 B) -38/961 C) 38/31 D) 38/961 18 / 25 Moddiy nuqta S(t)=5t3+3t2+2t+4 qonuniyat bilan harakatlanayotgan jismning t=2 sekunddagi tezligini toping. A) 84 B) 60 C) 70 D) 74 19 / 25 Moddiy nuqtaning berilgan t vaqtdagi tezligini hisoblang: , t=5 A) 75 B) 80 C) 70 D) 90 20 / 25 limitni hisoblang A) 0 B) 6 C) 5 D) 7 21 / 25 To’g’riburchakli parallelepiped asosining tomonlari 7:24 nisbatda, diagonal kesimining yuzi 50dm2 ga teng. Yon sirtining yuzini toping. A) 124 dm² B) 224 dm² C) 135 dm² D) 124 dm 22 / 25 To’g’ri to’rtburchak shaklidagi yer maydoninig atrofini o’rashmoqchi. 480 m panjara yordamida eng ko’pi bilan necha kvadrat metr yer maydonni o’rash mumkin? A) 25600 B) 14400 C) 19600 D) 8100 23 / 25 sonini taqriban hisoblang. A) 5,08 B) 5,01 C) 3,08 D) 4,08 24 / 25 f(x)=(3x+2)2 funksiyasining barcha boshlang’ich funksiyalarini toping. A) F(x)=6x³+6x²+4 B) F(x)=6x³+3x²-4 C) F(x)=6x³+3x²+4 D) F(x)=6x³+6x+4 25 / 25 Qavariq ko’pburchakning har bir uchidan uchtadan qirra chiqadi. Agar bu ko’pyoqning qirralari soni 12 ta bo’lsa, uning nechta uchi va yog’i mavjud? A) 8;10 B) 4;10 C) 4;18 D) 4;11 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz