Uy » Choraklik online testlar » Matematika choraklik » 11-sinf Matematika 2-chorak Matematika choraklik 11-sinf Matematika 2-chorak InfoMaster Aprel 20, 2021 378 Ko'rishlar 16 izohlar SaqlashSaqlanganOlib tashlandi 1 0 OMAD YOR BO'LSIN! Tomonidan yaratilgan InfoMaster 11-sinf Matematika 2-chorak Testni Mamadoliyev Diyorbek tayyorladi. 1 / 25 funksiyasining kamayish oralig’ini toping. A) (-1;1/3) B) [-1;-1/3] C) (-1/3;+∞) D) (-∞;-1) 2 / 25 f(x)=2x+3 funksiyasi uchun A(1;5) nuqtadan o’tuvchi boshlang’ich funksiyasini toping. A) F(x)=x²-3x-1 B) F(x)=x²-3x+1 C) F(x)=x²+3x-1 D) F(x)=x²+3x+1 3 / 25 Funksiyaning kamayish oraliqlarini toping A) (-2;0) va (0;1) B) (-3;0) va (0;1) C) (-1;0) va (0;1) D) (-1;0) va (0;2) 4 / 25 Funksiya hosilasini toping: f(x)=5 A) x B) 0 C) 5 D) 10 5 / 25 y=-3x3+2x2-4x+5 funksiyaga x0=-1 nuqtada o’tkazilgan urinma tenglamasining burchak koeffitsiyentini toping. A) -13 B) -17 C) 17 D) 15 6 / 25 funksiya grafigiga x=4 abssissali nuqtada o`tkazilgan urinma tenglamasini tuzing A) y=35x B) y=10x C) y=35x+30 D) y=20x+20 7 / 25 Uchlari A(2;-3;4) va B(-2;4;5) nuqtalarda bo’lgan AB kesmasining uzunligini toping A) √24 B) √66 C) √55 D) √19 8 / 25 funksiyaning [-4;2] oraliqdagi eng katta qiymatini toping A) 17 B) 14 C) 16 D) 18 9 / 25 Agar A(1;2;3), B(3;7;6) bo’lsa, A̅B̅ vector koordinatalarini toping A) (2;5;3) B) (4;9;9) C) (-2;-5;-3) D) (4;9;9) 10 / 25 Murakkab funksiyaning hosilasini toping. y=x2sinx A) y’=x²cosx-2xsinx B) y’=2xsinx+x²cosx C) y’=-2xsinx+x² D) y’=2xsinx-x² 11 / 25 Uchlari A(4;0;1), B(5;-2;1), C(4;8;5) nuqtalarda bo’lgan uchburchakning AL bissektrisasi uzunligini toping A) (4√2)/5 B) (4√2)3 C) (2√5)/3 D) 4 12 / 25 A(1;-2;2), B(1;4;0), C(-4;1;1) va D(-5;-5;3) nuqtalar berilgan. AC va BD vektorlar orasidagi burchakni toping A) 90° B) 80° C) 52° D) 15° 13 / 25 Moddiy nuqtaning berilgan t vaqtdagi tezligini hisoblang: , t=5 A) 80 B) 75 C) 90 D) 70 14 / 25 A) 13 B) 18 C) 20 D) 14 15 / 25 Funksiya hosilasini toping: A) 12x+12 B) 12x²-12 C) 21x²-10x D) 14x+12 16 / 25 limitni hisoblang A) 7 B) 5 C) 0 D) 6 17 / 25 Agar f(x)=x² va bo`lsa ,f(g(2)) ni toping A) 36 B) 0 C) 16 D) 12 18 / 25 To’g’riburchakli parallelepiped asosining tomonlari 7:24 nisbatda, diagonal kesimining yuzi 50dm2 ga teng. Yon sirtining yuzini toping. A) 224 dm² B) 124 dm² C) 135 dm² D) 124 dm 19 / 25 Qavariq ko’pburchakning har bir uchidan uchtadan qirra chiqadi. Agar bu ko’pyoqning qirralari soni 12 ta bo’lsa, uning nechta uchi va yog’i mavjud? A) 4;11 B) 8;10 C) 4;18 D) 4;10 20 / 25 f(x)=excosx funksiyasi uchun f ’(π/2) ni aniqlang. A. e-0.5π B. e0,5π C. eπ D. e-π A) e^(π) B) e^(-π) C) e^(-0.5π) D) e^(0.5π) 21 / 25 Kub to’la sirtining yuzi 105,84 sm2 bo’lsa, uning har bir yog’i yuzini va qirrasining uzunligini toping. A) 17,64 dm²; 4,9 dm B) 17,64 dm; 4,2 dm C) 17,68 dm²; 4,2 dm D) 17,64 dm²; 4,2 dm 22 / 25 sonini taqriban hisoblang. A) 5,08 B) 3,08 C) 5,01 D) 4,08 23 / 25 Havo shariga t[0;10] minut oralig’ida V(t)=t3+13t2+t+20 (m3) havo purkamoqda. t=10 minutdagi havo hajmini toping. A) 2330 B) 2025 C) 2300 D) 1023 24 / 25 Tandirdan olingan nonning temperaturasi 20 minut ichida 1000 dan 600 gacha pasayadi. Tashqi muhit temperaturasi 250. Nonning temperaturasi qancha vaqtda 300 gacha pasayadi? A) 61 B) 41 C) 71 D) 51 25 / 25 To’g’riburchakli parallelepiped bir uchidan chiquvchi uchta qirralari uzunliklari 4,6 va 9 ga teng. Unga tengdosh kub qirrasining uzunligini toping. A) 6 B) 8 C) 6 D) 7 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz