Uy » Choraklik online testlar » Matematika choraklik » 11-sinf Matematika 2-chorak Matematika choraklik 11-sinf Matematika 2-chorak InfoMaster Aprel 20, 2021 366 Ko'rishlar 16 izohlar SaqlashSaqlanganOlib tashlandi 1 0 OMAD YOR BO'LSIN! Tomonidan yaratilgan InfoMaster 11-sinf Matematika 2-chorak Testni Mamadoliyev Diyorbek tayyorladi. 1 / 25 Qavariq ko’pburchakning har bir uchidan uchtadan qirra chiqadi. Agar bu ko’pyoqning qirralari soni 12 ta bo’lsa, uning nechta uchi va yog’i mavjud? A) 4;10 B) 4;18 C) 8;10 D) 4;11 2 / 25 F(x)=0.2sin(5x+12) funksiyasi uchun f(x) ni toping A) f(x)=0.5cos(5x+12) B) f(x)=-cos(5x+12) C) f(x)=cos(5x+12) D) f(x)=-0,5sin(5x+12) 3 / 25 f(x)=(3x+2)2 funksiyasining barcha boshlang’ich funksiyalarini toping. A) F(x)=6x³+6x+4 B) F(x)=6x³+6x²+4 C) F(x)=6x³+3x²+4 D) F(x)=6x³+3x²-4 4 / 25 f(x)=excosx funksiyasi uchun f ’(π/2) ni aniqlang. A. e-0.5π B. e0,5π C. eπ D. e-π A) e^(-π) B) e^(-0.5π) C) e^(0.5π) D) e^(π) 5 / 25 Kub to’la sirtining yuzi 105,84 sm2 bo’lsa, uning har bir yog’i yuzini va qirrasining uzunligini toping. A) 17,68 dm²; 4,2 dm B) 17,64 dm²; 4,2 dm C) 17,64 dm; 4,2 dm D) 17,64 dm²; 4,9 dm 6 / 25 Moddiy nuqta S(t)=5t3+3t2+2t+4 qonuniyat bilan harakatlanayotgan jismning t=2 sekunddagi tezligini toping. A) 84 B) 70 C) 74 D) 60 7 / 25 Funksiyaning statsionar nuqtalarini toping A) x=0, x=2 B) x=-1, x=2 C) x=3, x=2 D) x=-1, x=3 8 / 25 Funksiya hosilasini toping: A) 12x+12 B) 21x²-10x C) 12x²-12 D) 14x+12 9 / 25 funksiya grafigiga x=1 abssisssali nuqtadao`tkazilgan urinma tenglamasini yozing A) y=1/2 B) y= 2x C) y=-x D) y=x 10 / 25 Uchlari A(2;3;4) va B(-4;-5;-6) nuqtalarda bo’lgan AB kesmasining o’rtasining koordinatalarini toping. A) (-1;-1;-1) B) (-1;-1;-4) C) (-1;-3;-1) D) (-2;-4;-1) 11 / 25 Funksiya hosilasini toping f(x)=(2x+4)(3x+1) A) 12x+14 B) 12x C) 16x+14 D) 3x+1 12 / 25 Funksiya hosilasini toping: f(x)=5 A) 10 B) x C) 5 D) 0 13 / 25 Agar A(1;2;3), B(3;7;6) bo’lsa, A̅B̅ vector koordinatalarini toping A) (2;5;3) B) (4;9;9) C) (4;9;9) D) (-2;-5;-3) 14 / 25 funksiyaning [-4;2] oraliqdagi eng katta qiymatini toping A) 14 B) 17 C) 16 D) 18 15 / 25 funksiyaning [-4;1] kesmadagi eng kata qiymatini toping. A) -13 B) 13 C) -4 D) 131 16 / 25 funksiya uchun y=2x-1 to`g`ri chiziqqa parallel bo`lgan urinma tenglamasini yozing A) y=2x+3 B) y=2x C) y=2x-2,25 D) y=3x-2,2 17 / 25 Murakkab funksiyaning hosilasini toping. y=x2sinx A) y’=x²cosx-2xsinx B) y’=-2xsinx+x² C) y’=2xsinx+x²cosx D) y’=2xsinx-x² 18 / 25 funksiya grafigiga x=4 abssissali nuqtada o`tkazilgan urinma tenglamasini tuzing A) y=35x+30 B) y=10x C) y=35x D) y=20x+20 19 / 25 Uchlari A(4;0;1), B(5;-2;1), C(4;8;5) nuqtalarda bo’lgan uchburchakning AL bissektrisasi uzunligini toping A) 4 B) (4√2)/5 C) (4√2)3 D) (2√5)/3 20 / 25 y=-3x3+2x2-4x+5 funksiyaga x0=-1 nuqtada o’tkazilgan urinma tenglamasining burchak koeffitsiyentini toping. A) -13 B) -17 C) 17 D) 15 21 / 25 Karim 3 minutda 213ta so`zni terib , 6ta imloviy xatoga yo`l qo`ydi. Karimning matn terish sifatini toping. A) 0,0321 B) 0,0282 C) 0,623 D) 0,3265 22 / 25 funksiyasining kamayish oralig’ini toping. A) (-1;1/3) B) [-1;-1/3] C) (-1/3;+∞) D) (-∞;-1) 23 / 25 limitni hisoblang A) 7 B) 0 C) 5 D) 6 24 / 25 Karim uyida 14 bet matn terib, 8ta imloviy xatoga yo’l qo’ydi. Agar 1 betda o’rtacha 380 ta so’z bo’lsa, Karim 100ta so’z terganda o’rtacha qancha xato qiladi? A) 1,5 B) 0,15 C) 0,25 D) 0,5 25 / 25 f(x)=3x2-5x+4 va g(x)=4x-5 funksiyalarining urinmalari parallel bo’ladigan nuqtalarini toping. A) 0.5 B) 0 C) 1.5 D) 2 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz