Uy » Choraklik online testlar » Matematika choraklik » 11-sinf Matematika 2-chorak Matematika choraklik 11-sinf Matematika 2-chorak InfoMaster Aprel 20, 2021 21 Ko'rishlar 16 izohlar SaqlashSaqlanganOlib tashlandi 0 1 OMAD YOR BO'LSIN! 11-sinf Matematika 2-chorak Testni Mamadoliyev Diyorbek tayyorladi. 1 / 25 Moddiy nuqta qonuniyat bilan harakatlanmoqda, eng katta tezlanishga erishiladigan vaqtni toping. A) 6 B) 5 C) 7 D) 4 2 / 25 Tandirdan olingan nonning temperaturasi 20 minut ichida 1000 dan 600 gacha pasayadi. Tashqi muhit temperaturasi 250. Nonning temperaturasi qancha vaqtda 300 gacha pasayadi? A) 41 B) 71 C) 61 D) 51 3 / 25 Kub to’la sirtining yuzi 105,84 sm2 bo’lsa, uning har bir yog’i yuzini va qirrasining uzunligini toping. A) 17,64 dm²; 4,9 dm B) 17,64 dm; 4,2 dm C) 17,68 dm²; 4,2 dm D) 17,64 dm²; 4,2 dm 4 / 25 Havo shariga t[0;10] minut oralig’ida V(t)=t3+13t2+t+20 (m3) havo purkamoqda. t=10 minutdagi havo hajmini toping. A) 2330 B) 2025 C) 2300 D) 1023 5 / 25 Limitni hisoblang: A) 3 B) -3 C) -4 D) 4 6 / 25 Funksiya hosilasini toping: A) 12x+12 B) 21x²-10x C) 12x²-12 D) 14x+12 7 / 25 y=-3x3+2x2-4x+5 funksiyaga x0=-1 nuqtada o’tkazilgan urinma tenglamasining burchak koeffitsiyentini toping. A) -17 B) -13 C) 15 D) 17 8 / 25 Moddiy nuqta S(t)=5t3+3t2+2t+4 qonuniyat bilan harakatlanayotgan jismning t=2 sekunddagi tezligini toping. A) 70 B) 84 C) 74 D) 60 9 / 25 tgx funksiya hosilasini toping A) sinx B) cosx C) 1/sinx D) 1/cos²x 10 / 25 Funksiyaning kamayish oraliqlarini toping A) (-2;0) va (0;1) B) (-3;0) va (0;1) C) (-1;0) va (0;2) D) (-1;0) va (0;1) 11 / 25 Uchlari A(4;0;1), B(5;-2;1), C(4;8;5) nuqtalarda bo’lgan uchburchakning AL bissektrisasi uzunligini toping A) 4 B) (2√5)/3 C) (4√2)/5 D) (4√2)3 12 / 25 Murakkab funksiyaning hosilasini toping. y=x2sinx A) y’=2xsinx+x²cosx B) y’=x²cosx-2xsinx C) y’=2xsinx-x² D) y’=-2xsinx+x² 13 / 25 Koordinatalar boshidan y=x2-4x+3 parabolaning simmetriya o’qigacha bo’lgan masofani toping. A) 1 B) 2 C) 4 D) 3 14 / 25 A(1;-2;2), B(1;4;0), C(-4;1;1) va D(-5;-5;3) nuqtalar berilgan. AC va BD vektorlar orasidagi burchakni toping A) 80° B) 15° C) 52° D) 90° 15 / 25 Funksiyaning statsionar nuqtalarini toping A) x=-1, x=2 B) x=-1, x=3 C) x=0, x=2 D) x=3, x=2 16 / 25 Nargiza 4minutda 260ta so`zni terib, 7ta imloviy xatoga yo`l qo`ydi. Nargizaning matn terish sifatini aniqlang A) 0,5 B) 0,6 C) 0,01 D) 0,0269 17 / 25 funksiyaning [-4;2] oraliqdagi eng katta qiymatini toping A) 17 B) 14 C) 16 D) 18 18 / 25 Uchlari A(2;3;4) va B(-4;-5;-6) nuqtalarda bo’lgan AB kesmasining o’rtasining koordinatalarini toping. A) (-1;-1;-1) B) (-2;-4;-1) C) (-1;-1;-4) D) (-1;-3;-1) 19 / 25 funksiya grafigiga x=1 abssisssali nuqtadao`tkazilgan urinma tenglamasini yozing A) y= 2x B) y=x C) y=-x D) y=1/2 20 / 25 A(2;0;-3) va B(3;4;0) nuqtalar orasidagi masofani toping A) √26 B) 16 C) √24 D) 25 21 / 25 funksiya uchun y=2x-1 to`g`ri chiziqqa parallel bo`lgan urinma tenglamasini yozing A) y=2x-2,25 B) y=2x+3 C) y=3x-2,2 D) y=2x 22 / 25 Uchlari A(2;-3;4) va B(-2;4;5) nuqtalarda bo’lgan AB kesmasining uzunligini toping A) √19 B) √66 C) √55 D) √24 23 / 25 funksiya grafigiga x=4 abssissali nuqtada o`tkazilgan urinma tenglamasini tuzing A) y=35x+30 B) y=35x C) y=20x+20 D) y=10x 24 / 25 A) 18 B) 14 C) 13 D) 20 25 / 25 funksiyasining kamayish oralig’ini toping. A) (-∞;-1) B) (-1;1/3) C) (-1/3;+∞) D) [-1;-1/3] 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Tomonidan Wordpress Quiz plugin Author: InfoMaster Foydali bo'lsa mamnunmiz