Uy » Choraklik online testlar » Matematika choraklik » 11-sinf Matematika 2-chorak Matematika choraklik 11-sinf Matematika 2-chorak InfoMaster Aprel 20, 2021 356 Ko'rishlar 16 izohlar SaqlashSaqlanganOlib tashlandi 1 0 OMAD YOR BO'LSIN! Tomonidan yaratilgan InfoMaster 11-sinf Matematika 2-chorak Testni Mamadoliyev Diyorbek tayyorladi. 1 / 25 Agar f(x)=x² va bo`lsa ,f(g(2)) ni toping A) 36 B) 12 C) 16 D) 0 2 / 25 f(x)=3x2-5x+4 va g(x)=4x-5 funksiyalarining urinmalari parallel bo’ladigan nuqtalarini toping. A) 0.5 B) 2 C) 0 D) 1.5 3 / 25 Agar A(1;2;3), B(3;7;6) bo’lsa, A̅B̅ vector koordinatalarini toping A) (4;9;9) B) (2;5;3) C) (4;9;9) D) (-2;-5;-3) 4 / 25 funksiyaning [-4;2] oraliqdagi eng katta qiymatini toping A) 14 B) 18 C) 17 D) 16 5 / 25 funksiya uchun y=2x-1 to`g`ri chiziqqa parallel bo`lgan urinma tenglamasini yozing A) y=2x+3 B) y=2x C) y=3x-2,2 D) y=2x-2,25 6 / 25 Funksiya hosilasini toping: f(x)=5 A) x B) 0 C) 10 D) 5 7 / 25 f(x)=2x+3 funksiyasi uchun A(1;5) nuqtadan o’tuvchi boshlang’ich funksiyasini toping. A) F(x)=x²-3x+1 B) F(x)=x²+3x+1 C) F(x)=x²+3x-1 D) F(x)=x²-3x-1 8 / 25 funksiyaning [-4;1] kesmadagi eng kata qiymatini toping. A) -4 B) 131 C) 13 D) -13 9 / 25 Funksiya hosilasini toping: A) 12x+12 B) 14x+12 C) 21x²-10x D) 12x²-12 10 / 25 Nargiza 4minutda 260ta so`zni terib, 7ta imloviy xatoga yo`l qo`ydi. Nargizaning matn terish sifatini aniqlang A) 0,5 B) 0,0269 C) 0,01 D) 0,6 11 / 25 Uchlari A(2;-3;4) va B(-2;4;5) nuqtalarda bo’lgan AB kesmasining uzunligini toping A) √19 B) √66 C) √24 D) √55 12 / 25 A(1;-2;2), B(1;4;0), C(-4;1;1) va D(-5;-5;3) nuqtalar berilgan. AC va BD vektorlar orasidagi burchakni toping A) 80° B) 15° C) 52° D) 90° 13 / 25 Agar f(x)=x² va bo`lsa ,f(g(-4)) ni toping A) 12 B) 36 C) 0 D) -12 14 / 25 Uchlari A(2;3;4) va B(-4;-5;-6) nuqtalarda bo’lgan AB kesmasining o’rtasining koordinatalarini toping. A) (-1;-1;-4) B) (-1;-1;-1) C) (-1;-3;-1) D) (-2;-4;-1) 15 / 25 A(-4;3;6) nuqtaning Oxz tekisligiga nisbatan simmrtrik nuqtasini toping. A) (-4;-3;6) B) (-8;-3;6) C) (-4;-6;6) D) (-4;-3;9) 16 / 25 funksiyasining kamayish oralig’ini toping. A) [-1;-1/3] B) (-∞;-1) C) (-1/3;+∞) D) (-1;1/3) 17 / 25 funksiya hosilasining x0=-2 nuqtadagi qiymatini hisoblang. A) 38/31 B) -38/961 C) -38/31 D) 38/961 18 / 25 Funksiyaning kamayish oraliqlarini toping A) (-1;0) va (0;1) B) (-3;0) va (0;1) C) (-1;0) va (0;2) D) (-2;0) va (0;1) 19 / 25 To’g’riburchakli parallelepiped asosining tomonlari 7:24 nisbatda, diagonal kesimining yuzi 50dm2 ga teng. Yon sirtining yuzini toping. A) 124 dm B) 124 dm² C) 135 dm² D) 224 dm² 20 / 25 To’g’riburchakli parallelepiped bir uchidan chiquvchi uchta qirralari uzunliklari 4,6 va 9 ga teng. Unga tengdosh kub qirrasining uzunligini toping. A) 8 B) 6 C) 7 D) 6 21 / 25 Moddiy nuqta qonuniyat bilan harakatlanmoqda, eng katta tezlanishga erishiladigan vaqtni toping. A) 6 B) 5 C) 4 D) 7 22 / 25 F(x)=0.2sin(5x+12) funksiyasi uchun f(x) ni toping A) f(x)=-cos(5x+12) B) f(x)=0.5cos(5x+12) C) f(x)=-0,5sin(5x+12) D) f(x)=cos(5x+12) 23 / 25 To’g’ri to’rtburchak shaklidagi yer maydoninig atrofini o’rashmoqchi. 480 m panjara yordamida eng ko’pi bilan necha kvadrat metr yer maydonni o’rash mumkin? A) 8100 B) 19600 C) 14400 D) 25600 24 / 25 Kub to’la sirtining yuzi 105,84 sm2 bo’lsa, uning har bir yog’i yuzini va qirrasining uzunligini toping. A) 17,64 dm; 4,2 dm B) 17,64 dm²; 4,2 dm C) 17,64 dm²; 4,9 dm D) 17,68 dm²; 4,2 dm 25 / 25 f(x)=excosx funksiyasi uchun f ’(π/2) ni aniqlang. A. e-0.5π B. e0,5π C. eπ D. e-π A) e^(0.5π) B) e^(-0.5π) C) e^(π) D) e^(-π) 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz