Uy » Choraklik online testlar » Matematika choraklik » 11-sinf Matematika 2-chorak Matematika choraklik 11-sinf Matematika 2-chorak InfoMaster Aprel 20, 2021 360 Ko'rishlar 16 izohlar SaqlashSaqlanganOlib tashlandi 1 0 OMAD YOR BO'LSIN! Tomonidan yaratilgan InfoMaster 11-sinf Matematika 2-chorak Testni Mamadoliyev Diyorbek tayyorladi. 1 / 25 Qavariq ko’pburchakning har bir uchidan uchtadan qirra chiqadi. Agar bu ko’pyoqning qirralari soni 12 ta bo’lsa, uning nechta uchi va yog’i mavjud? A) 4;11 B) 4;10 C) 4;18 D) 8;10 2 / 25 Kub to’la sirtining yuzi 105,84 sm2 bo’lsa, uning har bir yog’i yuzini va qirrasining uzunligini toping. A) 17,64 dm; 4,2 dm B) 17,68 dm²; 4,2 dm C) 17,64 dm²; 4,9 dm D) 17,64 dm²; 4,2 dm 3 / 25 To’g’riburchakli parallelepiped bir uchidan chiquvchi uchta qirralari uzunliklari 4,6 va 9 ga teng. Unga tengdosh kub qirrasining uzunligini toping. A) 6 B) 8 C) 6 D) 7 4 / 25 Moddiy nuqta qonuniyat bilan harakatlanmoqda, eng katta tezlanishga erishiladigan vaqtni toping. A) 4 B) 7 C) 5 D) 6 5 / 25 Tandirdan olingan nonning temperaturasi 20 minut ichida 1000 dan 600 gacha pasayadi. Tashqi muhit temperaturasi 250. Nonning temperaturasi qancha vaqtda 300 gacha pasayadi? A) 61 B) 51 C) 71 D) 41 6 / 25 To’g’ri to’rtburchak shaklidagi yer maydoninig atrofini o’rashmoqchi. 480 m panjara yordamida eng ko’pi bilan necha kvadrat metr yer maydonni o’rash mumkin? A) 14400 B) 19600 C) 25600 D) 8100 7 / 25 funksiyaning [-4;1] kesmadagi eng kata qiymatini toping. A) 131 B) -4 C) 13 D) -13 8 / 25 A(-4;3;6) nuqtaning Oxz tekisligiga nisbatan simmrtrik nuqtasini toping. A) (-4;-3;6) B) (-8;-3;6) C) (-4;-6;6) D) (-4;-3;9) 9 / 25 Funksiya hosilasini toping: f(x)=5 A) 0 B) x C) 5 D) 10 10 / 25 Nargiza 4minutda 260ta so`zni terib, 7ta imloviy xatoga yo`l qo`ydi. Nargizaning matn terish sifatini aniqlang A) 0,0269 B) 0,6 C) 0,01 D) 0,5 11 / 25 funksiya uchun y=2x-1 to`g`ri chiziqqa parallel bo`lgan urinma tenglamasini yozing A) y=2x+3 B) y=2x C) y=3x-2,2 D) y=2x-2,25 12 / 25 A(1;-2;2), B(1;4;0), C(-4;1;1) va D(-5;-5;3) nuqtalar berilgan. AC va BD vektorlar orasidagi burchakni toping A) 90° B) 52° C) 80° D) 15° 13 / 25 Funksiya hosilasini toping f(x)=(2x+4)(3x+1) A) 12x B) 12x+14 C) 3x+1 D) 16x+14 14 / 25 f(x)=3x2-5x+4 va g(x)=4x-5 funksiyalarining urinmalari parallel bo’ladigan nuqtalarini toping. A) 2 B) 0.5 C) 0 D) 1.5 15 / 25 funksiyasining kamayish oralig’ini toping. A) [-1;-1/3] B) (-1/3;+∞) C) (-∞;-1) D) (-1;1/3) 16 / 25 Moddiy nuqta S(t)=5t3+3t2+2t+4 qonuniyat bilan harakatlanayotgan jismning t=2 sekunddagi tezligini toping. A) 70 B) 84 C) 74 D) 60 17 / 25 A(2;0;-3) va B(3;4;0) nuqtalar orasidagi masofani toping A) 25 B) √24 C) 16 D) √26 18 / 25 Karim 3 minutda 213ta so`zni terib , 6ta imloviy xatoga yo`l qo`ydi. Karimning matn terish sifatini toping. A) 0,0321 B) 0,623 C) 0,0282 D) 0,3265 19 / 25 A) 14 B) 20 C) 13 D) 18 20 / 25 Koordinatalar boshidan y=x2-4x+3 parabolaning simmetriya o’qigacha bo’lgan masofani toping. A) 1 B) 2 C) 4 D) 3 21 / 25 y=-3x3+2x2-4x+5 funksiyaga x0=-1 nuqtada o’tkazilgan urinma tenglamasining burchak koeffitsiyentini toping. A) 17 B) -17 C) 15 D) -13 22 / 25 Agar A(1;2;3), B(3;7;6) bo’lsa, A̅B̅ vector koordinatalarini toping A) (4;9;9) B) (-2;-5;-3) C) (2;5;3) D) (4;9;9) 23 / 25 Funksiyaning kamayish oraliqlarini toping A) (-2;0) va (0;1) B) (-1;0) va (0;2) C) (-3;0) va (0;1) D) (-1;0) va (0;1) 24 / 25 Limitni hisoblang: A) -4 B) 4 C) 3 D) -3 25 / 25 tgx funksiya hosilasini toping A) sinx B) 1/sinx C) 1/cos²x D) cosx 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz