11-sinf Matematika 2-chorak Aprel 17, 2021Aprel 20, 2021 da chop etilgan InfoMaster tomonidan 11-sinf Matematika 2-chorak ga 16 fikr bildirilgan 0 OMAD YOR BO'LSIN! Tomonidan yaratilgan InfoMaster 11-sinf Matematika 2-chorak Testni Mamadoliyev Diyorbek tayyorladi. 1 / 25 Funksiyaning statsionar nuqtalarini toping A) x=-1, x=3 B) x=-1, x=2 C) x=0, x=2 D) x=3, x=2 2 / 25 Moddiy nuqtaning berilgan t vaqtdagi tezligini hisoblang: , t=5 A) 70 B) 90 C) 75 D) 80 3 / 25 Nargiza 4minutda 260ta so`zni terib, 7ta imloviy xatoga yo`l qo`ydi. Nargizaning matn terish sifatini aniqlang A) 0,5 B) 0,6 C) 0,01 D) 0,0269 4 / 25 funksiyaning [-4;2] oraliqdagi eng katta qiymatini toping A) 16 B) 18 C) 17 D) 14 5 / 25 f(x)=3x2-5x+4 va g(x)=4x-5 funksiyalarining urinmalari parallel bo’ladigan nuqtalarini toping. A) 0.5 B) 1.5 C) 2 D) 0 6 / 25 funksiya hosilasining x0=-2 nuqtadagi qiymatini hisoblang. A) -38/31 B) 38/961 C) 38/31 D) -38/961 7 / 25 Karim 3 minutda 213ta so`zni terib , 6ta imloviy xatoga yo`l qo`ydi. Karimning matn terish sifatini toping. A) 0,0282 B) 0,0321 C) 0,623 D) 0,3265 8 / 25 Funksiyaning kamayish oraliqlarini toping A) (-3;0) va (0;1) B) (-2;0) va (0;1) C) (-1;0) va (0;1) D) (-1;0) va (0;2) 9 / 25 Murakkab funksiyaning hosilasini toping. y=x2sinx A) y’=-2xsinx+x² B) y’=x²cosx-2xsinx C) y’=2xsinx+x²cosx D) y’=2xsinx-x² 10 / 25 A(-4;3;6) nuqtaning Oxz tekisligiga nisbatan simmrtrik nuqtasini toping. A) (-8;-3;6) B) (-4;-3;6) C) (-4;-6;6) D) (-4;-3;9) 11 / 25 Funksiya hosilasini toping f(x)=(2x+4)(3x+1) A) 12x B) 12x+14 C) 16x+14 D) 3x+1 12 / 25 Karim uyida 14 bet matn terib, 8ta imloviy xatoga yo’l qo’ydi. Agar 1 betda o’rtacha 380 ta so’z bo’lsa, Karim 100ta so’z terganda o’rtacha qancha xato qiladi? A) 0,5 B) 0,15 C) 1,5 D) 0,25 13 / 25 A(2;0;-3) va B(3;4;0) nuqtalar orasidagi masofani toping A) 25 B) √26 C) √24 D) 16 14 / 25 Funksiya hosilasini toping: A) 21x²-10x B) 12x²-12 C) 14x+12 D) 12x+12 15 / 25 funksiyasining kamayish oralig’ini toping. A) (-1;1/3) B) (-1/3;+∞) C) [-1;-1/3] D) (-∞;-1) 16 / 25 y=-3x3+2x2-4x+5 funksiyaga x0=-1 nuqtada o’tkazilgan urinma tenglamasining burchak koeffitsiyentini toping. A) 17 B) 15 C) -13 D) -17 17 / 25 f(x)=sin2x funksiyasining barcha boshlang’ich funksiyalarini toping. A) F(x)=2sin4x+c B) F(x)=-0,5cos2x+C C) F(x)=0,5cos2x+C D) F(x)=-2cos2x+C 18 / 25 Qavariq ko’pburchakning har bir uchidan uchtadan qirra chiqadi. Agar bu ko’pyoqning qirralari soni 12 ta bo’lsa, uning nechta uchi va yog’i mavjud? A) 4;18 B) 4;11 C) 8;10 D) 4;10 19 / 25 To’g’ri to’rtburchak shaklidagi yer maydoninig atrofini o’rashmoqchi. 480 m panjara yordamida eng ko’pi bilan necha kvadrat metr yer maydonni o’rash mumkin? A) 8100 B) 19600 C) 14400 D) 25600 20 / 25 Kub to’la sirtining yuzi 105,84 sm2 bo’lsa, uning har bir yog’i yuzini va qirrasining uzunligini toping. A) 17,64 dm²; 4,9 dm B) 17,64 dm²; 4,2 dm C) 17,68 dm²; 4,2 dm D) 17,64 dm; 4,2 dm 21 / 25 F(x)=0.2sin(5x+12) funksiyasi uchun f(x) ni toping A) f(x)=0.5cos(5x+12) B) f(x)=cos(5x+12) C) f(x)=-0,5sin(5x+12) D) f(x)=-cos(5x+12) 22 / 25 To’g’riburchakli parallelepiped asosining tomonlari 7:24 nisbatda, diagonal kesimining yuzi 50dm2 ga teng. Yon sirtining yuzini toping. A) 135 dm² B) 124 dm C) 124 dm² D) 224 dm² 23 / 25 Havo shariga t[0;10] minut oralig’ida V(t)=t3+13t2+t+20 (m3) havo purkamoqda. t=10 minutdagi havo hajmini toping. A) 2300 B) 1023 C) 2025 D) 2330 24 / 25 Tandirdan olingan nonning temperaturasi 20 minut ichida 1000 dan 600 gacha pasayadi. Tashqi muhit temperaturasi 250. Nonning temperaturasi qancha vaqtda 300 gacha pasayadi? A) 71 B) 51 C) 61 D) 41 25 / 25 Moddiy nuqta qonuniyat bilan harakatlanmoqda, eng katta tezlanishga erishiladigan vaqtni toping. A) 7 B) 4 C) 6 D) 5 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring tomonidan Wordpress Quiz plugin Matematika choraklik Teglar:11-sinf, matematika
