Uy » Choraklik online testlar » Matematika choraklik » 11-sinf Matematika 2-chorak Matematika choraklik 11-sinf Matematika 2-chorak InfoMaster Aprel 20, 2021 349 Ko'rishlar 16 izohlar SaqlashSaqlanganOlib tashlandi 1 0 OMAD YOR BO'LSIN! Tomonidan yaratilgan InfoMaster 11-sinf Matematika 2-chorak Testni Mamadoliyev Diyorbek tayyorladi. 1 / 25 Uchlari A(2;-3;4) va B(-2;4;5) nuqtalarda bo’lgan AB kesmasining uzunligini toping A) √24 B) √66 C) √19 D) √55 2 / 25 f(x)=2x+3 funksiyasi uchun A(1;5) nuqtadan o’tuvchi boshlang’ich funksiyasini toping. A) F(x)=x²-3x-1 B) F(x)=x²+3x+1 C) F(x)=x²+3x-1 D) F(x)=x²-3x+1 3 / 25 funksiya grafigiga x=4 abssissali nuqtada o`tkazilgan urinma tenglamasini tuzing A) y=35x B) y=20x+20 C) y=35x+30 D) y=10x 4 / 25 limitni hisoblang A) 5 B) 0 C) 6 D) 7 5 / 25 Agar f(x)=x² va bo`lsa ,f(g(2)) ni toping A) 12 B) 0 C) 16 D) 36 6 / 25 Koordinatalar boshidan y=x2-4x+3 parabolaning simmetriya o’qigacha bo’lgan masofani toping. A) 2 B) 4 C) 3 D) 1 7 / 25 tgx funksiya hosilasini toping A) cosx B) sinx C) 1/sinx D) 1/cos²x 8 / 25 Moddiy nuqtaning berilgan t vaqtdagi tezligini hisoblang: , t=5 A) 70 B) 75 C) 90 D) 80 9 / 25 A(1;-2;2), B(1;4;0), C(-4;1;1) va D(-5;-5;3) nuqtalar berilgan. AC va BD vektorlar orasidagi burchakni toping A) 90° B) 52° C) 15° D) 80° 10 / 25 funksiyasining kamayish oralig’ini toping. A) (-1/3;+∞) B) (-∞;-1) C) [-1;-1/3] D) (-1;1/3) 11 / 25 funksiyaning [-4;2] oraliqdagi eng katta qiymatini toping A) 17 B) 16 C) 14 D) 18 12 / 25 Funksiyaning statsionar nuqtalarini toping A) x=-1, x=3 B) x=0, x=2 C) x=3, x=2 D) x=-1, x=2 13 / 25 funksiyaning [-4;1] kesmadagi eng kata qiymatini toping. A) 131 B) -13 C) -4 D) 13 14 / 25 Agar A(1;2;3), B(3;7;6) bo’lsa, A̅B̅ vector koordinatalarini toping A) (-2;-5;-3) B) (2;5;3) C) (4;9;9) D) (4;9;9) 15 / 25 Uchlari A(4;0;1), B(5;-2;1), C(4;8;5) nuqtalarda bo’lgan uchburchakning AL bissektrisasi uzunligini toping A) 4 B) (4√2)/5 C) (4√2)3 D) (2√5)/3 16 / 25 Karim 3 minutda 213ta so`zni terib , 6ta imloviy xatoga yo`l qo`ydi. Karimning matn terish sifatini toping. A) 0,0321 B) 0,3265 C) 0,623 D) 0,0282 17 / 25 F(x)=0.2sin(5x+12) funksiyasi uchun f(x) ni toping A) f(x)=-cos(5x+12) B) f(x)=-0,5sin(5x+12) C) f(x)=cos(5x+12) D) f(x)=0.5cos(5x+12) 18 / 25 Tandirdan olingan nonning temperaturasi 20 minut ichida 1000 dan 600 gacha pasayadi. Tashqi muhit temperaturasi 250. Nonning temperaturasi qancha vaqtda 300 gacha pasayadi? A) 71 B) 51 C) 61 D) 41 19 / 25 Moddiy nuqta qonuniyat bilan harakatlanmoqda, eng katta tezlanishga erishiladigan vaqtni toping. A) 4 B) 6 C) 5 D) 7 20 / 25 Havo shariga t[0;10] minut oralig’ida V(t)=t3+13t2+t+20 (m3) havo purkamoqda. t=10 minutdagi havo hajmini toping. A) 2330 B) 2025 C) 1023 D) 2300 21 / 25 sonini taqriban hisoblang. A) 4,08 B) 5,08 C) 3,08 D) 5,01 22 / 25 To’g’riburchakli parallelepiped bir uchidan chiquvchi uchta qirralari uzunliklari 4,6 va 9 ga teng. Unga tengdosh kub qirrasining uzunligini toping. A) 6 B) 8 C) 7 D) 6 23 / 25 To’g’ri to’rtburchak shaklidagi yer maydoninig atrofini o’rashmoqchi. 480 m panjara yordamida eng ko’pi bilan necha kvadrat metr yer maydonni o’rash mumkin? A) 14400 B) 8100 C) 25600 D) 19600 24 / 25 To’g’riburchakli parallelepiped asosining tomonlari 7:24 nisbatda, diagonal kesimining yuzi 50dm2 ga teng. Yon sirtining yuzini toping. A) 224 dm² B) 124 dm² C) 135 dm² D) 124 dm 25 / 25 f(x)=sin2x funksiyasining barcha boshlang’ich funksiyalarini toping. A) F(x)=-2cos2x+C B) F(x)=0,5cos2x+C C) F(x)=2sin4x+c D) F(x)=-0,5cos2x+C 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz