Uy » Choraklik online testlar » Matematika choraklik » 11-sinf Matematika 2-chorak Matematika choraklik 11-sinf Matematika 2-chorak InfoMaster Aprel 20, 2021 373 Ko'rishlar 16 izohlar SaqlashSaqlanganOlib tashlandi 1 1 OMAD YOR BO'LSIN! Tomonidan yaratilgan InfoMaster 11-sinf Matematika 2-chorak Testni Mamadoliyev Diyorbek tayyorladi. 1 / 25 f(x)=3x2-5x+4 va g(x)=4x-5 funksiyalarining urinmalari parallel bo’ladigan nuqtalarini toping. A) 2 B) 1.5 C) 0.5 D) 0 2 / 25 A(2;0;-3) va B(3;4;0) nuqtalar orasidagi masofani toping A) √26 B) 16 C) 25 D) √24 3 / 25 Moddiy nuqtaning berilgan t vaqtdagi tezligini hisoblang: , t=5 A) 70 B) 90 C) 80 D) 75 4 / 25 Uchlari A(2;-3;4) va B(-2;4;5) nuqtalarda bo’lgan AB kesmasining uzunligini toping A) √66 B) √55 C) √24 D) √19 5 / 25 Karim 3 minutda 213ta so`zni terib , 6ta imloviy xatoga yo`l qo`ydi. Karimning matn terish sifatini toping. A) 0,0282 B) 0,0321 C) 0,3265 D) 0,623 6 / 25 Agar f(x)=x² va bo`lsa ,f(g(-4)) ni toping A) 12 B) 36 C) 0 D) -12 7 / 25 Uchlari A(4;0;1), B(5;-2;1), C(4;8;5) nuqtalarda bo’lgan uchburchakning AL bissektrisasi uzunligini toping A) (4√2)3 B) (2√5)/3 C) (4√2)/5 D) 4 8 / 25 Nargiza 4minutda 260ta so`zni terib, 7ta imloviy xatoga yo`l qo`ydi. Nargizaning matn terish sifatini aniqlang A) 0,6 B) 0,5 C) 0,0269 D) 0,01 9 / 25 funksiya grafigiga x=1 abssisssali nuqtadao`tkazilgan urinma tenglamasini yozing A) y= 2x B) y=1/2 C) y=x D) y=-x 10 / 25 funksiya hosilasining x0=-2 nuqtadagi qiymatini hisoblang. A) -38/31 B) 38/961 C) -38/961 D) 38/31 11 / 25 Funksiya hosilasini toping f(x)=(2x+4)(3x+1) A) 3x+1 B) 12x C) 16x+14 D) 12x+14 12 / 25 A(-4;3;6) nuqtaning Oxz tekisligiga nisbatan simmrtrik nuqtasini toping. A) (-4;-3;6) B) (-4;-6;6) C) (-4;-3;9) D) (-8;-3;6) 13 / 25 Agar A(1;2;3), B(3;7;6) bo’lsa, A̅B̅ vector koordinatalarini toping A) (-2;-5;-3) B) (2;5;3) C) (4;9;9) D) (4;9;9) 14 / 25 Limitni hisoblang: A) 3 B) -4 C) 4 D) -3 15 / 25 Murakkab funksiyaning hosilasini toping. y=x2sinx A) y’=-2xsinx+x² B) y’=2xsinx+x²cosx C) y’=2xsinx-x² D) y’=x²cosx-2xsinx 16 / 25 funksiya grafigiga x=4 abssissali nuqtada o`tkazilgan urinma tenglamasini tuzing A) y=35x+30 B) y=20x+20 C) y=10x D) y=35x 17 / 25 funksiya uchun y=2x-1 to`g`ri chiziqqa parallel bo`lgan urinma tenglamasini yozing A) y=2x B) y=2x-2,25 C) y=3x-2,2 D) y=2x+3 18 / 25 f(x)=2x+3 funksiyasi uchun A(1;5) nuqtadan o’tuvchi boshlang’ich funksiyasini toping. A) F(x)=x²+3x-1 B) F(x)=x²-3x-1 C) F(x)=x²+3x+1 D) F(x)=x²-3x+1 19 / 25 Qavariq ko’pburchakning har bir uchidan uchtadan qirra chiqadi. Agar bu ko’pyoqning qirralari soni 12 ta bo’lsa, uning nechta uchi va yog’i mavjud? A) 8;10 B) 4;18 C) 4;10 D) 4;11 20 / 25 f(x)=excosx funksiyasi uchun f ’(π/2) ni aniqlang. A. e-0.5π B. e0,5π C. eπ D. e-π A) e^(-0.5π) B) e^(0.5π) C) e^(π) D) e^(-π) 21 / 25 f(x)=(3x+2)2 funksiyasining barcha boshlang’ich funksiyalarini toping. A) F(x)=6x³+6x²+4 B) F(x)=6x³+6x+4 C) F(x)=6x³+3x²-4 D) F(x)=6x³+3x²+4 22 / 25 To’g’riburchakli parallelepiped asosining tomonlari 7:24 nisbatda, diagonal kesimining yuzi 50dm2 ga teng. Yon sirtining yuzini toping. A) 124 dm B) 124 dm² C) 224 dm² D) 135 dm² 23 / 25 Tandirdan olingan nonning temperaturasi 20 minut ichida 1000 dan 600 gacha pasayadi. Tashqi muhit temperaturasi 250. Nonning temperaturasi qancha vaqtda 300 gacha pasayadi? A) 41 B) 61 C) 71 D) 51 24 / 25 Moddiy nuqta qonuniyat bilan harakatlanmoqda, eng katta tezlanishga erishiladigan vaqtni toping. A) 6 B) 5 C) 7 D) 4 25 / 25 To’g’riburchakli parallelepiped bir uchidan chiquvchi uchta qirralari uzunliklari 4,6 va 9 ga teng. Unga tengdosh kub qirrasining uzunligini toping. A) 6 B) 6 C) 8 D) 7 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz