Uy » Online olimpiada » Matematika olimpiada » 11-sinf Matematika olimpiada №4 Matematika olimpiadaTuman 2022-2023 o'quv yili 11-sinf Matematika olimpiada №4 InfoMaster Avgust 19, 2024 29 Ko'rishlar 2 izohlar SaqlashSaqlanganOlib tashlandi 0 0 123456789101112131415161718192021222324252627282930 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster 11-sinf Matematika olimpiada №4 2022-yil 12-oktyabr: 2022-2023 o'quv yilida tuman bosqichida tushgan savollar! 1 / 30 1. ko‘phadning barcha koeffitsientlari va ozod hadining yig‘indisini toping. A) -238 B) 245 C) -247 D) 125 2 / 30 2. funksiyaning aniqlanish sohasini toping. A) (-∞;4/3)∪(4/3;∞) B) (-∞;2/3)∪(2/3;∞) C) (2/3;∞) D) (-∞;4/3) 3 / 30 3. f(x)=x³/3-x²-35x+2 funksiya uchun f `(x)=0 bo`lsa x ni toping. A) −5 va 7 B) −7 va −5 C) 5 va 7 D) −7 va 5 4 / 30 4. Tenglama nechta yechimga ega? Bunda, x ∈ (1; 47) A) 15 B) 14 C) 12 D) 16 5 / 30 5. Soddalashtiring: A) 3cos2x B) 3sin2x C) cosx D) 3cosx 6 / 30 6. Agar ifodaning qiymatini toping. A) 4 B) 20 C) 0.8 D) 0.05 7 / 30 7. un ketma-ketlik quyidagicha berilgan: u1 = 1, un+1 = un + 8n. U holda, u50 −u30 ni toping. A) 6320 B) 6230 C) 5320 D) 6320 8 / 30 8. ? soniga teskari bo‘lgan son ? ning 9% ini tashkil qiladi. ? ni toping. (?u yerda, ? > 0) A) 13/3 B) 8/3 C) 10/3 D) 16/3 9 / 30 9. (3 − cos²x− 2sinx)(lg²y+ 2lgy+ 4) ≤ 3 bo‘lsa, sin²x+ 20y+ 1 ni toping. A) 3 B) 2 C) 4 D) 5 10 / 30 10. To‘g‘ri burchakli uchburchakning bir burchagi 60° ga teng. Bu burchakdan chiqarilgan bissektrisaning uzunligi 2 m. Uchburchakning gipotenuzasi uzunligini toping. A) 2√3 B) √5 C) √5 +1 D) √3 11 / 30 11. Arifmetik progressiyada ?2 = 12, ?7 − ?4 = 9 bo‘lsa, ?19 ni toping. A) 54 B) 56 C) 63 D) 61 12 / 30 12. ∠CAD = 2∠ACD, AC =13a, BD = 5a va AB = CD bo’lsa, 20⋅cos ∠ACD ni toping.(chizmaga qarang!) A) 15 B) 16 C) 19 D) 17 13 / 30 13. Natural son roppa-rosa 2 ta tub bo‘luvchiga, bu sonning kvadrati esa 45 ta turli natural bo‘luvchiga ega. Berilgan sonning kubi eng ko‘pi bilan nechta natural bo‘luvchiga ega bo‘lishi mumkin? A) 41 B) 40 C) 81 D) 91 14 / 30 14. O‘tkir burchakli uchburchakning ikki tomon uzunliklari ayirmasi 8, bu tomonlarning uchinchi tomondagi proyeksiyalari mos ravishda 8 va 20 ga teng. Berilgan uchburchakka tashqi chizilgan aylana radiusini toping. A) 37/3 B) 35/3 C) 85/6 D) 83/6 15 / 30 15. y = x² − 2x + 3 parabolaga y = 3 to‘g‘ri chiziqqa nisbatan simmetrik bo‘lgan parabola tenglamasini tuzing. A) y =-x² + 2x + 3 B) y = x² − 2x - 3 C) y =-x² + 2x - 3 D) y = -x² − 2x + 3 16 / 30 16. Raqamlari yig‘indisi 10 dan kam bo‘lmagan, raqamlari ko‘paytmasi esa 10 dan katta bo‘lmagan uch xonali sonlar nechta? A) 89 B) 100 C) 106 D) 96 17 / 30 17. Nargizada 2 ta olma va 3 ta nok bor. U 5 kun ketma-ket har kuni singliga bittadan meva beradi. Bu ishni necha usul bilan amalga oshirish mumkin? A) 6 B) 10 C) 8 D) 12 18 / 30 18. Soatning minut mili 144° ga burilganda, soatning soat mili qanday burchakka burilada? A) 9° B) 6° C) 12° D) 18° 19 / 30 19. Soddalashtiring: A) -1 B) −сtg1° C) −сtg13° D) −сtg²1° 20 / 30 20. ABCD - kvadrat, AC-diagonal. Agar AE=BE+CE ( a + b = c ) bo‘lsa, ∠AEB burchakni toping(chizmaga qarang!). A) 45 B) 55 C) 60 D) 50 21 / 30 21. ABC uchburchakda ctgA+ctgB= 3 va AB= 12 bo‘lsa, ABC uchburchak yuzini toping. A) 216 B) 265 C) 521 D) 123 22 / 30 22. Soddalashtiring: bunda, |?| < 1. A) 2-2a B) -2 C) 4-2a D) 2a+4 23 / 30 23. Hisoblang: A) D B) A C) C D) B 24 / 30 24. bo’lsa, P(−1) ni toping. A) 115 B) 120 C) 105 D) 100 25 / 30 25. Tenglamani yeching: A) 10/21 B) 29/462 C) 0 D) ∅ 26 / 30 26. BC = BE = CD ,∠DAE = 20°, ∠BCD = 60° ,∠ADE = ? (chizmaga qarang) A) 50° B) 40° C) 30° D) 20° 27 / 30 27. Soddalashtiring: A) D B) B C) A D) C 28 / 30 28. formula bilan berilgan sonli ketma-ketlikning dastlabki 20 ta hadining o‘rta arifmetigini toping. A) 25/6 B) 20/3 C) 23/6 D) 22/3 29 / 30 29. ?(3) ∙ (? − 2) + ?(? − 1) = 3? bo‘lsa, ?(1) ni toping. A) 2 B) 4 C) 3 D) 6 30 / 30 30. Uchlari A(2; −3), B(6; −1), C(6; 4) va D(2; 2) nuqtalarda bo‘lgan ABCD to‘rtburchak yuzini toping. A) 16 B) 20 C) 18 D) 15 0% Tomonidan Wordpress Quiz plugin Author: InfoMaster Foydali bo'lsa mamnunmiz