Uy » Online olimpiada » Matematika olimpiada » 11-sinf Matematika olimpiada №4 Matematika olimpiadaTuman 2022-2023 o'quv yili 11-sinf Matematika olimpiada №4 InfoMaster Avgust 19, 2024 49 Ko'rishlar 2 izohlar SaqlashSaqlanganOlib tashlandi 0 0 123456789101112131415161718192021222324252627282930 Vaqtingiz tugadi! 11-sinf Matematika olimpiada №4 2022-yil 12-oktyabr: 2022-2023 o'quv yilida tuman bosqichida tushgan savollar! 1 / 30 1. tengsizlik yechimlari joylashgan interval uzunligini toping. A) 0,25 B) 0,5 C) 0,125 D) 0,75 2 / 30 2. y=6sin2x+sin12x funksiyaning hosilasini toping. A) 24sin7xsin5x B) 24sin5xcos7x C) −24sin7xcos5x D) 24cos7xcos5x 3 / 30 3. ni hisoblang. A) -12 B) 13 C) 12 D) -13 4 / 30 4. Hisoblang: 1 + 2 ∙ 2 + 3 ∙ 22 + 4 ∙ 23+. … + 100 ∙ 299 A) D B) C C) B D) A 5 / 30 5. АВCDE beshburchak berilgan, М, N, Р va Q nuqtalar —АВ, ВС, CD va DE tomonlarning o‘rtalari. Agar U va V — МP? va NQ ning o‘rtasi bo‘lsa, АЕ: UV nisbatni toping. A) 6 B) 5 C) 4 D) 3 6 / 30 6. Tenglamani yeching: A) ∅ B) 10/21 C) 0 D) 29/462 7 / 30 7. a2b5 = 620 tenglikni qanoatlantiruvchi nechta (?; ?) butun sonlar juftligi mavjud? A) 14 B) 12 C) 8 D) 10 8 / 30 8. (3 − cos²x− 2sinx)(lg²y+ 2lgy+ 4) ≤ 3 bo‘lsa, sin²x+ 20y+ 1 ni toping. A) 3 B) 5 C) 2 D) 4 9 / 30 9. To‘g‘ri burchakli uchburchakning bir burchagi 60° ga teng. Bu burchakdan chiqarilgan bissektrisaning uzunligi 2 m. Uchburchakning gipotenuzasi uzunligini toping. A) 2√3 B) √5 +1 C) √5 D) √3 10 / 30 10. Uchlari A(2; −3), B(6; −1), C(6; 4) va D(2; 2) nuqtalarda bo‘lgan ABCD to‘rtburchak yuzini toping. A) 20 B) 16 C) 18 D) 15 11 / 30 11. ABC uchburchakda ctgA+ctgB= 3 va AB= 12 bo‘lsa, ABC uchburchak yuzini toping. A) 123 B) 216 C) 265 D) 521 12 / 30 12. Agar ifodaning qiymatini toping. A) 0.05 B) 20 C) 0.8 D) 4 13 / 30 13. Hisoblang: A) D B) C C) B D) A 14 / 30 14. ? soniga teskari bo‘lgan son ? ning 9% ini tashkil qiladi. ? ni toping. (?u yerda, ? > 0) A) 10/3 B) 16/3 C) 8/3 D) 13/3 15 / 30 15. Soddalashtiring: bunda, |?| < 1. A) 2a+4 B) -2 C) 2-2a D) 4-2a 16 / 30 16. Agar bo‘lsa sin²α ni toping. A) C B) B C) D D) A 17 / 30 17. Soddalashtiring: A) A B) C C) B D) D 18 / 30 18. Soatning minut mili 144° ga burilganda, soatning soat mili qanday burchakka burilada? A) 18° B) 6° C) 12° D) 9° 19 / 30 19. Soddalashtiring: A) -1 B) −сtg1° C) −сtg²1° D) −сtg13° 20 / 30 20. ?(3) ∙ (? − 2) + ?(? − 1) = 3? bo‘lsa, ?(1) ni toping. A) 4 B) 3 C) 2 D) 6 21 / 30 21. Muntazam uchburchak 36 ta yuzi 1 ga teng bo‘lgan kichkina muntazam uchburchaklardan iborat (chizmaga qarang!). ABC uchburchak yuzini toping. A) 12 B) 13 C) 11 D) 10 22 / 30 22. ABCD - kvadrat, AC-diagonal. Agar AE=BE+CE ( a + b = c ) bo‘lsa, ∠AEB burchakni toping(chizmaga qarang!). A) 50 B) 60 C) 55 D) 45 23 / 30 23. ∠CAD = 2∠ACD, AC =13a, BD = 5a va AB = CD bo’lsa, 20⋅cos ∠ACD ni toping.(chizmaga qarang!) A) 15 B) 17 C) 16 D) 19 24 / 30 24. formula bilan berilgan sonli ketma-ketlikning dastlabki 20 ta hadining o‘rta arifmetigini toping. A) 23/6 B) 25/6 C) 22/3 D) 20/3 25 / 30 25. y = x² − 2x + 3 parabolaga y = 3 to‘g‘ri chiziqqa nisbatan simmetrik bo‘lgan parabola tenglamasini tuzing. A) y =-x² + 2x - 3 B) y = x² − 2x - 3 C) y =-x² + 2x + 3 D) y = -x² − 2x + 3 26 / 30 26. Tengsizliklar sistemasinining butun yechimlari sonini toping. A) 6 B) 5 C) 7 D) 4 27 / 30 27. bo’lsa, P(−1) ni toping. A) 120 B) 100 C) 105 D) 115 28 / 30 28. Arifmetik progressiyada ?2 = 12, ?7 − ?4 = 9 bo‘lsa, ?19 ni toping. A) 54 B) 56 C) 61 D) 63 29 / 30 29. Raqamlari yig‘indisi 10 dan kam bo‘lmagan, raqamlari ko‘paytmasi esa 10 dan katta bo‘lmagan uch xonali sonlar nechta? A) 106 B) 96 C) 100 D) 89 30 / 30 30. BC = BE = CD ,∠DAE = 20°, ∠BCD = 60° ,∠ADE = ? (chizmaga qarang) A) 20° B) 50° C) 40° D) 30° 0% Tomonidan Wordpress Quiz plugin Author: InfoMaster Foydali bo'lsa mamnunmiz