Uy » Online olimpiada » Matematika olimpiada » 11-sinf Matematika olimpiada №4 Matematika olimpiadaTuman 2022-2023 o'quv yili 11-sinf Matematika olimpiada №4 InfoMaster Avgust 19, 2024 71 Ko'rishlar 2 izohlar SaqlashSaqlanganOlib tashlandi 0 4 123456789101112131415161718192021222324252627282930 Vaqtingiz tugadi! 11-sinf Matematika olimpiada №4 2022-yil 12-oktyabr: 2022-2023 o'quv yilida tuman bosqichida tushgan savollar! 1 / 30 1. 1!+2!+3!+.....+10! sonining oxirgi raqamini toping. A) 6 B) 0 C) 7 D) 3 2 / 30 2. ni hisoblang. A) -12 B) -13 C) 13 D) 12 3 / 30 3. ifodani soddalshtiring A) 2cosα B) cosα C) 2sinα D) 1 4 / 30 4. Funksiyaning eng kichik qiymatini toping. ?(?) = (2? + 6)5 − 4(2? + 6)4, bunda |? + 3| ≤ 2. A) -2¹¹ B) -4⁵ C) -4⁴ D) -2⁹ 5 / 30 5. Agar a = √5 + 1 va b = √5 − 1 bo‘lsa, 2a² − ab − a² ifodaning qiymatini toping. A) 6√5 + 1 B) 3√5 + 6 C) √5 + 6 D) 6√5 + 2 6 / 30 6. y = x² − 2x + 3 parabolaga y = 3 to‘g‘ri chiziqqa nisbatan simmetrik bo‘lgan parabola tenglamasini tuzing. A) y =-x² + 2x - 3 B) y =-x² + 2x + 3 C) y = x² − 2x - 3 D) y = -x² − 2x + 3 7 / 30 7. Soddalashtiring: A) D B) C C) A D) B 8 / 30 8. ABCD - kvadrat, AC-diagonal. Agar AE=BE+CE ( a + b = c ) bo‘lsa, ∠AEB burchakni toping(chizmaga qarang!). A) 60 B) 50 C) 55 D) 45 9 / 30 9. Raqamlari yig‘indisi 10 dan kam bo‘lmagan, raqamlari ko‘paytmasi esa 10 dan katta bo‘lmagan uch xonali sonlar nechta? A) 89 B) 106 C) 100 D) 96 10 / 30 10. Doskaga ?1, ?2, ?3, . . . , ?200 sonlari yozilgan. Ma’lumki, ?1 = 3, ?2 = 9. Agar ixtiyoriy n natural son uchun ?n+2 = ?n+1 − ?n tenglik o‘rinli bo‘lsa, ?200 ni toping. A) 3 B) 9 C) 6 D) 8 11 / 30 11. BC = BE = CD ,∠DAE = 20°, ∠BCD = 60° ,∠ADE = ? (chizmaga qarang) A) 40° B) 50° C) 20° D) 30° 12 / 30 12. Tenglamani yeching: A) 29/462 B) ∅ C) 0 D) 10/21 13 / 30 13. bo’lsa, P(−1) ni toping. A) 100 B) 115 C) 120 D) 105 14 / 30 14. Soddalashtiring: A) -1 B) −сtg1° C) −сtg²1° D) −сtg13° 15 / 30 15. (3 − cos²x− 2sinx)(lg²y+ 2lgy+ 4) ≤ 3 bo‘lsa, sin²x+ 20y+ 1 ni toping. A) 4 B) 3 C) 5 D) 2 16 / 30 16. Nargizada 2 ta olma va 3 ta nok bor. U 5 kun ketma-ket har kuni singliga bittadan meva beradi. Bu ishni necha usul bilan amalga oshirish mumkin? A) 12 B) 6 C) 8 D) 10 17 / 30 17. ABC uchburchakda ctgA+ctgB= 3 va AB= 12 bo‘lsa, ABC uchburchak yuzini toping. A) 521 B) 216 C) 265 D) 123 18 / 30 18. un ketma-ketlik quyidagicha berilgan: u1 = 1, un+1 = un + 8n. U holda, u50 −u30 ni toping. A) 6320 B) 6230 C) 5320 D) 6320 19 / 30 19. Uchlari A(2; −3), B(6; −1), C(6; 4) va D(2; 2) nuqtalarda bo‘lgan ABCD to‘rtburchak yuzini toping. A) 20 B) 18 C) 15 D) 16 20 / 30 20. Natural son roppa-rosa 2 ta tub bo‘luvchiga, bu sonning kvadrati esa 45 ta turli natural bo‘luvchiga ega. Berilgan sonning kubi eng ko‘pi bilan nechta natural bo‘luvchiga ega bo‘lishi mumkin? A) 81 B) 41 C) 91 D) 40 21 / 30 21. Soddalashtiring: bunda, |?| < 1. A) 2a+4 B) 4-2a C) -2 D) 2-2a 22 / 30 22. Agar bo‘lsa sin²α ni toping. A) A B) B C) D D) C 23 / 30 23. a2b5 = 620 tenglikni qanoatlantiruvchi nechta (?; ?) butun sonlar juftligi mavjud? A) 10 B) 8 C) 14 D) 12 24 / 30 24. Muntazam uchburchak 36 ta yuzi 1 ga teng bo‘lgan kichkina muntazam uchburchaklardan iborat (chizmaga qarang!). ABC uchburchak yuzini toping. A) 12 B) 11 C) 13 D) 10 25 / 30 25. Soatning minut mili 144° ga burilganda, soatning soat mili qanday burchakka burilada? A) 6° B) 18° C) 9° D) 12° 26 / 30 26. ?(3) ∙ (? − 2) + ?(? − 1) = 3? bo‘lsa, ?(1) ni toping. A) 4 B) 3 C) 6 D) 2 27 / 30 27. Tengsizliklar sistemasinining butun yechimlari sonini toping. A) 5 B) 4 C) 7 D) 6 28 / 30 28. ∠CAD = 2∠ACD, AC =13a, BD = 5a va AB = CD bo’lsa, 20⋅cos ∠ACD ni toping.(chizmaga qarang!) A) 19 B) 15 C) 16 D) 17 29 / 30 29. Agar ifodaning qiymatini toping. A) 0.05 B) 0.8 C) 4 D) 20 30 / 30 30. Arifmetik progressiyada ?2 = 12, ?7 − ?4 = 9 bo‘lsa, ?19 ni toping. A) 56 B) 63 C) 54 D) 61 0% Tomonidan Wordpress Quiz plugin Author: InfoMaster Foydali bo'lsa mamnunmiz