Uy » Choraklik online testlar » Matematika choraklik » 11-sinf Matematika 3-chorak Matematika choraklik 11-sinf Matematika 3-chorak InfoMaster Aprel 20, 2021 455 Ko'rishlar 8 izohlar SaqlashSaqlanganOlib tashlandi 1 7 OMAD YOR BO'LSIN! 11-sinf Matematika 3-chorak Testni Salomov Sardor tayyorladi. 1 / 25 Silindr shaklidagi idishga 6 sm3 suv solindi. Idishga detal to’liq cho’ktirilganda, suv sathi 1,5 marta ko’tarildi. Detal hajmini aniqlang A) 14 B) 1 C) 3 D) 23 2 / 25 Uchlari soni 14 ta, qirralari soni esa 21 ta bo’lgan ko’pyoqning yoqlari sonini toping. A) 16 B) 8 C) 9 D) 4 3 / 25 tengsizlikning yechimi bo’lgan eng kichik natural sonni toping A) 5 B) 3 C) 1 D) 4 4 / 25 cos150*cos450 *cos750 ni hisoblang A) √8/2 B) √2 C) √2/2 D) 2√2 5 / 25 Aylanaga o’tkazilgan vatar uni 5:7 nisbatda bo’ladi. Ushbu vatarga tiralgan, aylanaga ichki chizilgan katta burchakni toping A) 105° B) 75° C) 55° D) 125° 6 / 25 cos(2arctg(1/2)) ni hisoblang A) -37/35 B) 37/35 C) -35/37 D) 35/37 7 / 25 A(2;0;-3) va B(3;4;0) nuqtalar orasidagi masofani toping A) 16 B) √26 C) √24 D) 25 8 / 25 Agar f(x)=x² va bo`lsa ,f(g(-4)) ni toping A) 0 B) 12 C) 36 D) -12 9 / 25 funksiya grafigiga x=1 abssisssali nuqtadao`tkazilgan urinma tenglamasini yozing A) y=1/2 B) y= 2x C) y=-x D) y=x 10 / 25 limitni hisoblang A) 7 B) 5 C) 0 D) 6 11 / 25 Funksiyaning statsionar nuqtalarini toping A) x=0, x=2 B) x=3, x=2 C) x=-1, x=3 D) x=-1, x=2 12 / 25 Murakkab funksiyaning hosilasini toping. y=x2sinx A) y’=x²cosx-2xsinx B) y’=2xsinx+x²cosx C) y’=2xsinx-x² D) y’=-2xsinx+x² 13 / 25 Agar A(1;2;3), B(3;7;6) bo’lsa, A̅B̅ vector koordinatalarini toping A) (4;9;9) B) (2;5;3) C) (4;9;9) D) (-2;-5;-3) 14 / 25 Agar f(x)=x² va bo`lsa ,f(g(2)) ni toping A) 12 B) 36 C) 16 D) 0 15 / 25 Moddiy nuqta S(t)=5t3+3t2+2t+4 qonuniyat bilan harakatlanayotgan jismning t=2 sekunddagi tezligini toping. A) 74 B) 70 C) 84 D) 60 16 / 25 Karim uyida 14 bet matn terib, 8ta imloviy xatoga yo’l qo’ydi. Agar 1 betda o’rtacha 380 ta so’z bo’lsa, Karim 100ta so’z terganda o’rtacha qancha xato qiladi? A) 0,15 B) 0,5 C) 0,25 D) 1,5 17 / 25 y=-3x3+2x2-4x+5 funksiyaga x0=-1 nuqtada o’tkazilgan urinma tenglamasining burchak koeffitsiyentini toping. A) -17 B) 15 C) 17 D) -13 18 / 25 funksiyasining kamayish oralig’ini toping. A) [-1;-1/3] B) (-∞;-1) C) (-1/3;+∞) D) (-1;1/3) 19 / 25 Limitni hisoblang: A) -4 B) 3 C) -3 D) 4 20 / 25 F(x)=0.2sin(5x+12) funksiyasi uchun f(x) ni toping A) f(x)=cos(5x+12) B) f(x)=-cos(5x+12) C) f(x)=0.5cos(5x+12) D) f(x)=-0,5sin(5x+12) 21 / 25 f(x)=excosx funksiyasi uchun f ’(π/2) ni aniqlang. A. e-0.5π B. e0,5π C. eπ D. e-π A) e^(π) B) e^(0.5π) C) e^(-0.5π) D) e^(-π) 22 / 25 To’g’riburchakli parallelepiped asosining tomonlari 7:24 nisbatda, diagonal kesimining yuzi 50dm2 ga teng. Yon sirtining yuzini toping. A) 124 dm B) 224 dm² C) 135 dm² D) 124 dm² 23 / 25 Havo shariga t[0;10] minut oralig’ida V(t)=t3+13t2+t+20 (m3) havo purkamoqda. t=10 minutdagi havo hajmini toping. A) 1023 B) 2300 C) 2330 D) 2025 24 / 25 To’g’ri to’rtburchak shaklidagi yer maydoninig atrofini o’rashmoqchi. 480 m panjara yordamida eng ko’pi bilan necha kvadrat metr yer maydonni o’rash mumkin? A) 8100 B) 14400 C) 25600 D) 19600 25 / 25 f(x)=(3x+2)2 funksiyasining barcha boshlang’ich funksiyalarini toping. A) F(x)=6x³+6x²+4 B) F(x)=6x³+3x²-4 C) F(x)=6x³+3x²+4 D) F(x)=6x³+6x+4 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Tomonidan Wordpress Quiz plugin Author: InfoMaster Foydali bo'lsa mamnunmiz