Uy » Choraklik online testlar » Matematika choraklik » 11-sinf Matematika 3-chorak Matematika choraklik 11-sinf Matematika 3-chorak InfoMaster Aprel 20, 2021 477 Ko'rishlar 8 izohlar SaqlashSaqlanganOlib tashlandi 2 0 OMAD YOR BO'LSIN! 11-sinf Matematika 3-chorak Testni Salomov Sardor tayyorladi. 1 / 25 Moddiy nuqta qonuniyat bilan harakatlanmoqda, eng katta tezlanishga erishiladigan vaqtni toping. A) 5 B) 7 C) 6 D) 4 2 / 25 Tandirdan olingan nonning temperaturasi 20 minut ichida 1000 dan 600 gacha pasayadi. Tashqi muhit temperaturasi 250. Nonning temperaturasi qancha vaqtda 300 gacha pasayadi? A) 71 B) 51 C) 61 D) 41 3 / 25 f(x)=(3x+2)2 funksiyasining barcha boshlang’ich funksiyalarini toping. A) F(x)=6x³+6x²+4 B) F(x)=6x³+3x²+4 C) F(x)=6x³+6x+4 D) F(x)=6x³+3x²-4 4 / 25 To’g’ri to’rtburchak shaklidagi yer maydoninig atrofini o’rashmoqchi. 480 m panjara yordamida eng ko’pi bilan necha kvadrat metr yer maydonni o’rash mumkin? A) 8100 B) 19600 C) 14400 D) 25600 5 / 25 F(x)=0.2sin(5x+12) funksiyasi uchun f(x) ni toping A) f(x)=-0,5sin(5x+12) B) f(x)=0.5cos(5x+12) C) f(x)=-cos(5x+12) D) f(x)=cos(5x+12) 6 / 25 Qavariq ko’pburchakning har bir uchidan uchtadan qirra chiqadi. Agar bu ko’pyoqning qirralari soni 12 ta bo’lsa, uning nechta uchi va yog’i mavjud? A) 8;10 B) 4;11 C) 4;18 D) 4;10 7 / 25 To’g’riburchakli parallelepiped asosining tomonlari 7:24 nisbatda, diagonal kesimining yuzi 50dm2 ga teng. Yon sirtining yuzini toping. A) 135 dm² B) 124 dm² C) 224 dm² D) 124 dm 8 / 25 Trapetsiyaning kichik asosi 6 ga va yon tomoni 5 va 7 ga teng. Uning kata asosi ham butun son bo’lsa, perimetri eng ko’pi bilan nechaga teng bo’lishi mumkin A) 3 B) 1 C) 3√2 D) 4 9 / 25 cos150*cos450 *cos750 ni hisoblang A) √8/2 B) 2√2 C) √2/2 D) √2 10 / 25 Uchlari soni 14 ta, qirralari soni esa 21 ta bo’lgan ko’pyoqning yoqlari sonini toping. A) 8 B) 4 C) 9 D) 16 11 / 25 Aylanaga o’tkazilgan vatar uni 5:7 nisbatda bo’ladi. Ushbu vatarga tiralgan, aylanaga ichki chizilgan katta burchakni toping A) 55° B) 125° C) 105° D) 75° 12 / 25 cos(2arctg(1/2)) ni hisoblang A) -37/35 B) 35/37 C) 37/35 D) -35/37 13 / 25 y>0 bo’lsin. To’g’riburchakning uchlari to’g’ri burchakli koordinatalar sistemasida qyuidagicha berilgan: A(0;0), B(0;y), C(-9;y) va D(-11;0). To’rtburchak diagonallarining o’tralari orasidagi masofani toping A) 2 B) √22 C) 1 D) √2 14 / 25 funksiyaning [-4;2] oraliqdagi eng katta qiymatini toping A) 14 B) 16 C) 18 D) 17 15 / 25 funksiya grafigiga x=1 abssisssali nuqtadao`tkazilgan urinma tenglamasini yozing A) y= 2x B) y=x C) y=-x D) y=1/2 16 / 25 A(2;0;-3) va B(3;4;0) nuqtalar orasidagi masofani toping A) √24 B) √26 C) 16 D) 25 17 / 25 A(-4;3;6) nuqtaning Oxz tekisligiga nisbatan simmrtrik nuqtasini toping. A) (-8;-3;6) B) (-4;-3;9) C) (-4;-3;6) D) (-4;-6;6) 18 / 25 Moddiy nuqtaning berilgan t vaqtdagi tezligini hisoblang: , t=5 A) 90 B) 70 C) 75 D) 80 19 / 25 Funksiya hosilasini toping f(x)=(2x+4)(3x+1) A) 16x+14 B) 3x+1 C) 12x+14 D) 12x 20 / 25 limitni hisoblang A) 0 B) 6 C) 7 D) 5 21 / 25 Koordinatalar boshidan y=x2-4x+3 parabolaning simmetriya o’qigacha bo’lgan masofani toping. A) 4 B) 1 C) 3 D) 2 22 / 25 Funksiya hosilasini toping: A) 12x+12 B) 21x²-10x C) 14x+12 D) 12x²-12 23 / 25 Agar f(x)=x² va bo`lsa ,f(g(-4)) ni toping A) -12 B) 0 C) 36 D) 12 24 / 25 Funksiyaning kamayish oraliqlarini toping A) (-3;0) va (0;1) B) (-2;0) va (0;1) C) (-1;0) va (0;1) D) (-1;0) va (0;2) 25 / 25 funksiya uchun y=2x-1 to`g`ri chiziqqa parallel bo`lgan urinma tenglamasini yozing A) y=2x B) y=3x-2,2 C) y=2x+3 D) y=2x-2,25 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Tomonidan Wordpress Quiz plugin Author: InfoMaster Foydali bo'lsa mamnunmiz