Uy » Choraklik online testlar » Matematika choraklik » 11-sinf Matematika 3-chorak Matematika choraklik 11-sinf Matematika 3-chorak InfoMaster Aprel 20, 2021 463 Ko'rishlar 8 izohlar SaqlashSaqlanganOlib tashlandi 1 0 OMAD YOR BO'LSIN! 11-sinf Matematika 3-chorak Testni Salomov Sardor tayyorladi. 1 / 25 To’g’riburchakli parallelepiped bir uchidan chiquvchi uchta qirralari uzunliklari 4,6 va 9 ga teng. Unga tengdosh kub qirrasining uzunligini toping. A) 6 B) 6 C) 7 D) 8 2 / 25 Havo shariga t[0;10] minut oralig’ida V(t)=t3+13t2+t+20 (m3) havo purkamoqda. t=10 minutdagi havo hajmini toping. A) 2300 B) 2025 C) 2330 D) 1023 3 / 25 f(x)=excosx funksiyasi uchun f ’(π/2) ni aniqlang. A. e-0.5π B. e0,5π C. eπ D. e-π A) e^(-π) B) e^(0.5π) C) e^(π) D) e^(-0.5π) 4 / 25 To’g’ri to’rtburchak shaklidagi yer maydoninig atrofini o’rashmoqchi. 480 m panjara yordamida eng ko’pi bilan necha kvadrat metr yer maydonni o’rash mumkin? A) 14400 B) 19600 C) 8100 D) 25600 5 / 25 Kub to’la sirtining yuzi 105,84 sm2 bo’lsa, uning har bir yog’i yuzini va qirrasining uzunligini toping. A) 17,64 dm²; 4,2 dm B) 17,64 dm; 4,2 dm C) 17,68 dm²; 4,2 dm D) 17,64 dm²; 4,9 dm 6 / 25 f(x)=3x2-5x+4 va g(x)=4x-5 funksiyalarining urinmalari parallel bo’ladigan nuqtalarini toping. A) 1.5 B) 0 C) 0.5 D) 2 7 / 25 funksiyaning [-4;1] kesmadagi eng kata qiymatini toping. A) -13 B) 13 C) 131 D) -4 8 / 25 f(x)=2x+3 funksiyasi uchun A(1;5) nuqtadan o’tuvchi boshlang’ich funksiyasini toping. A) F(x)=x²+3x-1 B) F(x)=x²-3x-1 C) F(x)=x²+3x+1 D) F(x)=x²-3x+1 9 / 25 Funksiya hosilasini toping: f(x)=5 A) 5 B) x C) 10 D) 0 10 / 25 funksiya grafigiga x=4 abssissali nuqtada o`tkazilgan urinma tenglamasini tuzing A) y=10x B) y=20x+20 C) y=35x D) y=35x+30 11 / 25 Uchlari A(2;3;4) va B(-4;-5;-6) nuqtalarda bo’lgan AB kesmasining o’rtasining koordinatalarini toping. A) (-1;-3;-1) B) (-1;-1;-4) C) (-2;-4;-1) D) (-1;-1;-1) 12 / 25 y=-3x3+2x2-4x+5 funksiyaga x0=-1 nuqtada o’tkazilgan urinma tenglamasining burchak koeffitsiyentini toping. A) -17 B) -13 C) 15 D) 17 13 / 25 Murakkab funksiyaning hosilasini toping. y=x2sinx A) y’=2xsinx-x² B) y’=2xsinx+x²cosx C) y’=x²cosx-2xsinx D) y’=-2xsinx+x² 14 / 25 Moddiy nuqta S(t)=5t3+3t2+2t+4 qonuniyat bilan harakatlanayotgan jismning t=2 sekunddagi tezligini toping. A) 74 B) 60 C) 70 D) 84 15 / 25 Agar A(1;2;3), B(3;7;6) bo’lsa, A̅B̅ vector koordinatalarini toping A) (-2;-5;-3) B) (2;5;3) C) (4;9;9) D) (4;9;9) 16 / 25 Agar f(x)=x² va bo`lsa ,f(g(2)) ni toping A) 16 B) 36 C) 0 D) 12 17 / 25 Funksiya hosilasini toping f(x)=(2x+4)(3x+1) A) 16x+14 B) 12x+14 C) 3x+1 D) 12x 18 / 25 Nargiza 4minutda 260ta so`zni terib, 7ta imloviy xatoga yo`l qo`ydi. Nargizaning matn terish sifatini aniqlang A) 0,0269 B) 0,5 C) 0,6 D) 0,01 19 / 25 funksiyaning [-4;2] oraliqdagi eng katta qiymatini toping A) 18 B) 16 C) 17 D) 14 20 / 25 A(1;-2;2), B(1;4;0), C(-4;1;1) va D(-5;-5;3) nuqtalar berilgan. AC va BD vektorlar orasidagi burchakni toping A) 90° B) 15° C) 52° D) 80° 21 / 25 Ixtiyoriy kvadratga tashqi va ichki chizilgan aylanalar yuzlari nisbati a ga teng. Ixtiyoriy aylanaga ichki va tashqi chizilgan kvadratlar yuzlari nisbati b ga teng bolsa, a/b ni toping A) 335 B) 1/2 C) 4 D) 1 22 / 25 Uchlari soni 14 ta, qirralari soni esa 21 ta bo’lgan ko’pyoqning yoqlari sonini toping. A) 4 B) 16 C) 8 D) 9 23 / 25 (x2+23x+23)(x2+x+23)=23x2 tenglama haqiyqiy ildizlari yig’indisini toping A) -23 B) 23 C) 24 D) -24 24 / 25 cos(2arctg(1/2)) ni hisoblang A) 35/37 B) 37/35 C) -37/35 D) -35/37 25 / 25 Uchburchakli muntazam prizma asosining radiusi ga va balandligi 2 ga teng bo’lgan silindrga ichki chizilgan. Prizma yon sirtining yuzini toping A) 3 B) 36 C) 4 D) 335 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Tomonidan Wordpress Quiz plugin Author: InfoMaster Foydali bo'lsa mamnunmiz