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11-sinf Matematika 1-chorak

InfoMaster

Aprel 20, 2021

57 Ko'rishlar 8 izohlar

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OMAD YOR BO'LSIN!

11-sinf Matematika 1-chorak

Testni Mamadoliyev Diyorbek tayyorladi.

1 / 25

Uchlari A(2;3;4) va B(-4;-5;-6) nuqtalarda bo’lgan AB kesmasining o’rtasining koordinatalarini toping.

A) (-1;-1;-1)

B) (-2;-4;-1)

C) (-1;-3;-1)

D) (-1;-1;-4)

2 / 25

Funksiya hosilasini toping: $f(x)=7x^3-5x^2+4$

A) 14x+12

B) 21x²-10x

C) 12x²-12

D) 12x+12

3 / 25

$f(x)=x^2-3x+4$ funksiya uchun y=2x-1 to`g`ri chiziqqa parallel bo`lgan urinma tenglamasini yozing

A) y=2x

B) y=2x-2,25

C) y=3x-2,2

D) y=2x+3

4 / 25

f(x)=3x²-5x+4 va g(x)=4x-5 funksiyalarining urinmalari parallel bo’ladigan nuqtalarini toping.

A) 2

B) 0.5

C) 1.5

D) 0

5 / 25

Funksiyaning statsionar nuqtalarini toping $f(x)=2x^3-3x^2-12x+3$

A) x=3, x=2

B) x=-1, x=3

C) x=-1, x=2

D) x=0, x=2

6 / 25

funksiyaning [-4;2] oraliqdagi eng katta qiymatini toping $f(x)=x^3+4.5x^2-9$

A) 18

B) 16

C) 14

D) 17

7 / 25

Funksiyaning kamayish oraliqlarini toping

A) (-1;0) va (0;1)

B) (-3;0) va (0;1)

C) (-2;0) va (0;1)

D) (-1;0) va (0;2)

8 / 25

Limitni hisoblang:

A) 3

B) -3

C) -4

D) 4

9 / 25

Nargiza 4minutda 260ta so`zni terib, 7ta imloviy xatoga yo`l qo`ydi. Nargizaning matn terish sifatini aniqlang

A) 0,01

B) 0,5

C) 0,0269

D) 0,6

10 / 25

$f(x)=x^3-2x^2$ funksiya grafigiga x=1 abssisssali nuqtadao`tkazilgan urinma tenglamasini yozing

A) y=x

B) y= 2x

C) y=1/2

D) y=-x

11 / 25

$f(x)=x^3+2x^2+x+3$ funksiyasining kamayish oralig’ini toping.

A) (-∞;-1)

B) (-1/3;+∞)

C) [-1;-1/3]

D) (-1;1/3)

12 / 25

A) 13

B) 20

C) 18

D) 14

13 / 25

funksiya hosilasining x₀=-2 nuqtadagi qiymatini hisoblang.

A) -38/961

B) 38/961

C) -38/31

D) 38/31

14 / 25

Agar A(1;2;3), B(3;7;6) bo’lsa, A̅B̅ vector koordinatalarini toping

A) (-2;-5;-3)

B) (4;9;9)

C) (4;9;9)

D) (2;5;3)

15 / 25

Uchlari A(2;-3;4) va B(-2;4;5) nuqtalarda bo’lgan AB kesmasining uzunligini toping

A) √24

B) √19

C) √66

D) √55

16 / 25

A(2;0;-3) va B(3;4;0) nuqtalar orasidagi masofani toping

A) √26

B) √24

C) 25

D) 16

17 / 25

Murakkab funksiyaning hosilasini toping. y=x²sinx

A) y’=x²cosx-2xsinx

B) y’=2xsinx+x²cosx

C) y’=2xsinx-x²

D) y’=-2xsinx+x²

18 / 25

Funksiya hosilasini toping: f(x)=5

A) 10

B) 5

C) x

D) 0

19 / 25

Koordinatalar boshidan y=x²-4x+3 parabolaning simmetriya o’qigacha bo’lgan masofani toping.

A) 2

B) 3

C) 4

D) 1

20 / 25

Agar f(x)=x² va bo`lsa ,f(g(2)) ni toping

A) 0

B) 36

C) 16

D) 12

21 / 25

Moddiy nuqta S(t)=5t³+3t²+2t+4 qonuniyat bilan harakatlanayotgan jismning t=2 sekunddagi tezligini toping.

A) 60

B) 84

C) 70

D) 74

22 / 25

Moddiy nuqtaning berilgan t vaqtdagi tezligini hisoblang: $s(t)=t^3-2t^2+t$ , t=5

A) 70

B) 90

C) 80

D) 75

23 / 25

A(-4;3;6) nuqtaning Oxz tekisligiga nisbatan simmrtrik nuqtasini toping.

A) (-4;-3;9)

B) (-4;-3;6)

C) (-8;-3;6)

D) (-4;-6;6)

24 / 25

Agar f(x)=x² va bo`lsa ,f(g(-4)) ni toping

A) 0

B) 36

C) 12

D) -12

25 / 25

f(x)=2x+3 funksiyasi uchun A(1;5) nuqtadan o’tuvchi boshlang’ich funksiyasini toping.

A) F(x)=x²-3x-1

B) F(x)=x²+3x-1

C) F(x)=x²-3x+1

D) F(x)=x²+3x+1

Baholash mezoni

86%-100% 5 baho

71%-85% 4 baho

56%-70% 3 baho

55% va kamiga 2 baho

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