Uy » Choraklik online testlar » Matematika choraklik » 11-sinf Matematika 1-chorak Matematika choraklik 11-sinf Matematika 1-chorak InfoMaster Aprel 20, 2021 63 Ko'rishlar 8 izohlar SaqlashSaqlanganOlib tashlandi 0 1 OMAD YOR BO'LSIN! 11-sinf Matematika 1-chorak Testni Mamadoliyev Diyorbek tayyorladi. 1 / 25 Funksiya hosilasini toping f(x)=(2x+4)(3x+1) A) 3x+1 B) 12x+14 C) 16x+14 D) 12x 2 / 25 Funksiyaning statsionar nuqtalarini toping A) x=-1, x=2 B) x=3, x=2 C) x=-1, x=3 D) x=0, x=2 3 / 25 funksiya grafigiga x=1 abssisssali nuqtadao`tkazilgan urinma tenglamasini yozing A) y=x B) y=1/2 C) y= 2x D) y=-x 4 / 25 tgx funksiya hosilasini toping A) sinx B) 1/cos²x C) 1/sinx D) cosx 5 / 25 funksiyaning [-4;2] oraliqdagi eng katta qiymatini toping A) 14 B) 17 C) 18 D) 16 6 / 25 Agar f(x)=x² va bo`lsa ,f(g(-4)) ni toping A) 36 B) 0 C) 12 D) -12 7 / 25 f(x)=2x+3 funksiyasi uchun A(1;5) nuqtadan o’tuvchi boshlang’ich funksiyasini toping. A) F(x)=x²+3x+1 B) F(x)=x²-3x-1 C) F(x)=x²-3x+1 D) F(x)=x²+3x-1 8 / 25 funksiyasining kamayish oralig’ini toping. A) (-∞;-1) B) (-1;1/3) C) (-1/3;+∞) D) [-1;-1/3] 9 / 25 Limitni hisoblang: A) -3 B) -4 C) 4 D) 3 10 / 25 Funksiya hosilasini toping: f(x)=5 A) 5 B) 10 C) 0 D) x 11 / 25 y=-3x3+2x2-4x+5 funksiyaga x0=-1 nuqtada o’tkazilgan urinma tenglamasining burchak koeffitsiyentini toping. A) 17 B) -13 C) -17 D) 15 12 / 25 A(1;-2;2), B(1;4;0), C(-4;1;1) va D(-5;-5;3) nuqtalar berilgan. AC va BD vektorlar orasidagi burchakni toping A) 90° B) 80° C) 15° D) 52° 13 / 25 Moddiy nuqtaning berilgan t vaqtdagi tezligini hisoblang: , t=5 A) 80 B) 70 C) 90 D) 75 14 / 25 Karim uyida 14 bet matn terib, 8ta imloviy xatoga yo’l qo’ydi. Agar 1 betda o’rtacha 380 ta so’z bo’lsa, Karim 100ta so’z terganda o’rtacha qancha xato qiladi? A) 0,15 B) 1,5 C) 0,5 D) 0,25 15 / 25 Agar f(x)=x² va bo`lsa ,f(g(2)) ni toping A) 16 B) 0 C) 36 D) 12 16 / 25 funksiyaning [-4;1] kesmadagi eng kata qiymatini toping. A) 13 B) 131 C) -13 D) -4 17 / 25 Uchlari A(4;0;1), B(5;-2;1), C(4;8;5) nuqtalarda bo’lgan uchburchakning AL bissektrisasi uzunligini toping A) (2√5)/3 B) (4√2)/5 C) (4√2)3 D) 4 18 / 25 Moddiy nuqta S(t)=5t3+3t2+2t+4 qonuniyat bilan harakatlanayotgan jismning t=2 sekunddagi tezligini toping. A) 74 B) 84 C) 70 D) 60 19 / 25 Agar A(1;2;3), B(3;7;6) bo’lsa, A̅B̅ vector koordinatalarini toping A) (-2;-5;-3) B) (4;9;9) C) (2;5;3) D) (4;9;9) 20 / 25 funksiya uchun y=2x-1 to`g`ri chiziqqa parallel bo`lgan urinma tenglamasini yozing A) y=2x B) y=2x+3 C) y=2x-2,25 D) y=3x-2,2 21 / 25 limitni hisoblang A) 0 B) 7 C) 5 D) 6 22 / 25 A(2;0;-3) va B(3;4;0) nuqtalar orasidagi masofani toping A) 25 B) √24 C) √26 D) 16 23 / 25 Uchlari A(2;-3;4) va B(-2;4;5) nuqtalarda bo’lgan AB kesmasining uzunligini toping A) √24 B) √66 C) √19 D) √55 24 / 25 Funksiya hosilasini toping: A) 12x+12 B) 21x²-10x C) 14x+12 D) 12x²-12 25 / 25 f(x)=3x2-5x+4 va g(x)=4x-5 funksiyalarining urinmalari parallel bo’ladigan nuqtalarini toping. A) 2 B) 1.5 C) 0 D) 0.5 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Tomonidan Wordpress Quiz plugin Author: InfoMaster Foydali bo'lsa mamnunmiz