Uy » Choraklik online testlar » Matematika choraklik » 11-sinf Matematika 1-chorak Matematika choraklik 11-sinf Matematika 1-chorak InfoMaster Aprel 20, 2021 73 Ko'rishlar 8 izohlar SaqlashSaqlanganOlib tashlandi 0 1 OMAD YOR BO'LSIN! 11-sinf Matematika 1-chorak Testni Mamadoliyev Diyorbek tayyorladi. 1 / 25 Karim 3 minutda 213ta so`zni terib , 6ta imloviy xatoga yo`l qo`ydi. Karimning matn terish sifatini toping. A) 0,623 B) 0,0282 C) 0,0321 D) 0,3265 2 / 25 funksiya grafigiga x=4 abssissali nuqtada o`tkazilgan urinma tenglamasini tuzing A) y=35x B) y=10x C) y=35x+30 D) y=20x+20 3 / 25 Karim uyida 14 bet matn terib, 8ta imloviy xatoga yo’l qo’ydi. Agar 1 betda o’rtacha 380 ta so’z bo’lsa, Karim 100ta so’z terganda o’rtacha qancha xato qiladi? A) 0,15 B) 0,5 C) 1,5 D) 0,25 4 / 25 Nargiza 4minutda 260ta so`zni terib, 7ta imloviy xatoga yo`l qo`ydi. Nargizaning matn terish sifatini aniqlang A) 0,6 B) 0,01 C) 0,0269 D) 0,5 5 / 25 Moddiy nuqtaning berilgan t vaqtdagi tezligini hisoblang: , t=5 A) 70 B) 80 C) 75 D) 90 6 / 25 Koordinatalar boshidan y=x2-4x+3 parabolaning simmetriya o’qigacha bo’lgan masofani toping. A) 4 B) 2 C) 1 D) 3 7 / 25 Agar f(x)=x² va bo`lsa ,f(g(-4)) ni toping A) -12 B) 36 C) 12 D) 0 8 / 25 Funksiyaning kamayish oraliqlarini toping A) (-1;0) va (0;1) B) (-3;0) va (0;1) C) (-1;0) va (0;2) D) (-2;0) va (0;1) 9 / 25 funksiya grafigiga x=1 abssisssali nuqtadao`tkazilgan urinma tenglamasini yozing A) y=x B) y= 2x C) y=1/2 D) y=-x 10 / 25 funksiyaning [-4;1] kesmadagi eng kata qiymatini toping. A) -4 B) 13 C) -13 D) 131 11 / 25 Funksiya hosilasini toping: A) 14x+12 B) 21x²-10x C) 12x+12 D) 12x²-12 12 / 25 Funksiyaning statsionar nuqtalarini toping A) x=-1, x=2 B) x=0, x=2 C) x=3, x=2 D) x=-1, x=3 13 / 25 Uchlari A(2;-3;4) va B(-2;4;5) nuqtalarda bo’lgan AB kesmasining uzunligini toping A) √19 B) √55 C) √66 D) √24 14 / 25 Uchlari A(4;0;1), B(5;-2;1), C(4;8;5) nuqtalarda bo’lgan uchburchakning AL bissektrisasi uzunligini toping A) (2√5)/3 B) 4 C) (4√2)/5 D) (4√2)3 15 / 25 A(-4;3;6) nuqtaning Oxz tekisligiga nisbatan simmrtrik nuqtasini toping. A) (-4;-6;6) B) (-4;-3;9) C) (-8;-3;6) D) (-4;-3;6) 16 / 25 f(x)=2x+3 funksiyasi uchun A(1;5) nuqtadan o’tuvchi boshlang’ich funksiyasini toping. A) F(x)=x²+3x-1 B) F(x)=x²-3x-1 C) F(x)=x²-3x+1 D) F(x)=x²+3x+1 17 / 25 Limitni hisoblang: A) 3 B) 4 C) -3 D) -4 18 / 25 limitni hisoblang A) 6 B) 7 C) 0 D) 5 19 / 25 A) 14 B) 20 C) 18 D) 13 20 / 25 Agar A(1;2;3), B(3;7;6) bo’lsa, A̅B̅ vector koordinatalarini toping A) (-2;-5;-3) B) (4;9;9) C) (2;5;3) D) (4;9;9) 21 / 25 A(2;0;-3) va B(3;4;0) nuqtalar orasidagi masofani toping A) √26 B) 25 C) √24 D) 16 22 / 25 f(x)=3x2-5x+4 va g(x)=4x-5 funksiyalarining urinmalari parallel bo’ladigan nuqtalarini toping. A) 0 B) 2 C) 1.5 D) 0.5 23 / 25 Agar f(x)=x² va bo`lsa ,f(g(2)) ni toping A) 36 B) 0 C) 16 D) 12 24 / 25 Funksiya hosilasini toping f(x)=(2x+4)(3x+1) A) 3x+1 B) 12x+14 C) 16x+14 D) 12x 25 / 25 funksiyasining kamayish oralig’ini toping. A) (-1;1/3) B) [-1;-1/3] C) (-1/3;+∞) D) (-∞;-1) 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Tomonidan Wordpress Quiz plugin Author: InfoMaster Foydali bo'lsa mamnunmiz