Uy » Choraklik online testlar » Matematika choraklik » 11-sinf Matematika 3-chorak Matematika choraklik 11-sinf Matematika 3-chorak InfoMaster Aprel 20, 2021 480 Ko'rishlar 8 izohlar SaqlashSaqlanganOlib tashlandi 2 0 OMAD YOR BO'LSIN! 11-sinf Matematika 3-chorak Testni Salomov Sardor tayyorladi. 1 / 25 To’g’riburchakli parallelepiped bir uchidan chiquvchi uchta qirralari uzunliklari 4,6 va 9 ga teng. Unga tengdosh kub qirrasining uzunligini toping. A) 7 B) 8 C) 6 D) 6 2 / 25 Kub to’la sirtining yuzi 105,84 sm2 bo’lsa, uning har bir yog’i yuzini va qirrasining uzunligini toping. A) 17,64 dm²; 4,2 dm B) 17,68 dm²; 4,2 dm C) 17,64 dm²; 4,9 dm D) 17,64 dm; 4,2 dm 3 / 25 A(2;0;-3) va B(3;4;0) nuqtalar orasidagi masofani toping A) 25 B) 16 C) √26 D) √24 4 / 25 funksiya uchun y=2x-1 to`g`ri chiziqqa parallel bo`lgan urinma tenglamasini yozing A) y=2x B) y=3x-2,2 C) y=2x+3 D) y=2x-2,25 5 / 25 Karim 3 minutda 213ta so`zni terib , 6ta imloviy xatoga yo`l qo`ydi. Karimning matn terish sifatini toping. A) 0,623 B) 0,0282 C) 0,3265 D) 0,0321 6 / 25 Agar A(1;2;3), B(3;7;6) bo’lsa, A̅B̅ vector koordinatalarini toping A) (-2;-5;-3) B) (2;5;3) C) (4;9;9) D) (4;9;9) 7 / 25 Funksiya hosilasini toping: A) 14x+12 B) 12x+12 C) 21x²-10x D) 12x²-12 8 / 25 Agar f(x)=x² va bo`lsa ,f(g(2)) ni toping A) 36 B) 16 C) 0 D) 12 9 / 25 Moddiy nuqta S(t)=5t3+3t2+2t+4 qonuniyat bilan harakatlanayotgan jismning t=2 sekunddagi tezligini toping. A) 74 B) 84 C) 70 D) 60 10 / 25 funksiyasining kamayish oralig’ini toping. A) [-1;-1/3] B) (-1;1/3) C) (-∞;-1) D) (-1/3;+∞) 11 / 25 Uchlari A(2;3;4) va B(-4;-5;-6) nuqtalarda bo’lgan AB kesmasining o’rtasining koordinatalarini toping. A) (-1;-1;-4) B) (-1;-3;-1) C) (-1;-1;-1) D) (-2;-4;-1) 12 / 25 funksiya grafigiga x=1 abssisssali nuqtadao`tkazilgan urinma tenglamasini yozing A) y=1/2 B) y=-x C) y= 2x D) y=x 13 / 25 Uchlari A(4;0;1), B(5;-2;1), C(4;8;5) nuqtalarda bo’lgan uchburchakning AL bissektrisasi uzunligini toping A) (2√5)/3 B) (4√2)3 C) (4√2)/5 D) 4 14 / 25 A(1;-2;2), B(1;4;0), C(-4;1;1) va D(-5;-5;3) nuqtalar berilgan. AC va BD vektorlar orasidagi burchakni toping A) 80° B) 15° C) 90° D) 52° 15 / 25 Funksiya hosilasini toping: f(x)=5 A) 0 B) 10 C) x D) 5 16 / 25 Murakkab funksiyaning hosilasini toping. y=x2sinx A) y’=-2xsinx+x² B) y’=2xsinx+x²cosx C) y’=2xsinx-x² D) y’=x²cosx-2xsinx 17 / 25 Ushbu funksiyasining boshlang’ich funksiyasini toping A) lnIx-1I B) ln(|x+2|*|x+1|) C) (x+2)(x+1) D) lnI(x-2)(x-3)I 18 / 25 tengsizlikning yechimi bo’lgan eng kichik natural sonni toping A) 5 B) 4 C) 1 D) 3 19 / 25 Uchlari soni 14 ta, qirralari soni esa 21 ta bo’lgan ko’pyoqning yoqlari sonini toping. A) 4 B) 8 C) 16 D) 9 20 / 25 Ixtiyoriy kvadratga tashqi va ichki chizilgan aylanalar yuzlari nisbati a ga teng. Ixtiyoriy aylanaga ichki va tashqi chizilgan kvadratlar yuzlari nisbati b ga teng bolsa, a/b ni toping A) 335 B) 1/2 C) 4 D) 1 21 / 25 sin3x+cos3x≥0 tengsizligini yeching A) ø B) (-π/2+n π;- π/2+n π) C) [-π/9+n π/3;2 π/9+n π/3] D) [-π/9+2πn/3; 2π/9+2πn/3] 22 / 25 y>0 bo’lsin. To’g’riburchakning uchlari to’g’ri burchakli koordinatalar sistemasida qyuidagicha berilgan: A(0;0), B(0;y), C(-9;y) va D(-11;0). To’rtburchak diagonallarining o’tralari orasidagi masofani toping A) 1 B) 2 C) √2 D) √22 23 / 25 Trapetsiyaning kichik asosi 6 ga va yon tomoni 5 va 7 ga teng. Uning kata asosi ham butun son bo’lsa, perimetri eng ko’pi bilan nechaga teng bo’lishi mumkin A) 3√2 B) 4 C) 3 D) 1 24 / 25 Muntazam uchburchak tomoni 3 ga teng. Uchburchak tomonlari o’rtalari tutashtirilib, muntazam uchburchaklar hosil qilindi. Ichma-ich joylashgan uchburchaklar yuzlari yig’indisini toping A) 2 B) 3 C) 3√3 D) 2√3 25 / 25 chiziqlar bilan chegaralangan shaklning yuzini toping A) 1 B) √2 C) 0,5 D) 2 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Tomonidan Wordpress Quiz plugin Author: InfoMaster Foydali bo'lsa mamnunmiz