Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №14 Matematika attestatsiya Matematika attestatsiya №14 InfoMaster Oktabr 30, 2022 257 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 1 0% 3 12345678910111213141516171819202122232425262728293031323334353637383940 OMAD YOR BO'LSIN! Matematika fanidan attestatsiya savollari №14 17.10.2022 Toshkent savollari! 1 / 40 1. Kamayish tartibida joylashtiring. a)5√6 b)12 c)4√10 A) a>b>c B) a>c>b C) c>a>b D) b>a>c 2 / 40 2. Muntazam uchburchak ichidan olingan nuqtadan uchburchak tomonlarigacha bo'lgan masofalar mos holda c(2;3;1), b(1;2;1) va a(1;2;3) vektorlarning absolut qiymatlariga teng bo'lsa, uchburchakning balandligini toping. A) 16 B) √6+√14 C) 18 D) 2√14+√6 3 / 40 3. Hisoblang: -121+(-135)-(-1)28 A) -2 B) -3 C) -1 D) 0 4 / 40 4. Agar tenglamaning ildizi m/n bo‘lsa, m+ n ni toping. Bunda EKUB(m; n)=1. A) 50 B) 32 C) 25 D) 41 5 / 40 5. sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 23 B) 35 C) 24 D) 14 6 / 40 6. ABCD trapetsiyaning AD kichik asosi 6 ga teng. C burchagining CF bissektrisasi AB tomonga perpendikulyar bo‘lib, bunda BF = 3AF = 6 bo‘lsa, katta asos uzunligini toping. A) 18 B) 15 C) 9 D) 12 7 / 40 7. bo‘lsa, f ''(1) ning qiymatini toping. A) 0 B) 12 C) -12 D) -24 8 / 40 8. ∇ABC da ∠BAC = 30° , AC = f ′(3) va AB = f (3) bo‘lsa, ∇ABC ning yuzini toping. Bunda f(x) = x³ - 5x -4 A) 44 B) 60 C) 42 D) 22 9 / 40 9. A(1; 3) nuqtadan 12x+5y+a–4=0 to’g’ri chiziqqacha bo’lgan masofa 2 bo’lsa, a ni toping. A) 2 B) 3 C) 1 D) 4 10 / 40 10. 2 ta bola 64 m masofaga yugurish bo’yicha noodatiy ravishda bellashishmoqda. Bellashuv shartiga ko’ra boshlang’ich chiziqdan 3 qadam oldinga yurgandan so’ng, 2 qadam orqaga yurish kerak. 1-bolaning qadami uzunligi 50 sm, 2-bolani qadami uzunligi esa 40 sm, lekin har 3 sekundda: 1-bola 3 marta qadam tashlaydi, 2-si 4 qadam tashlagan bo’lsa, qaysi bola g’alaba qozongan? A) 1-bola B) Aniqlab bo’lmaydi C) Ikkalasi teng keladi D) 2-bola 11 / 40 11. a ning qanday qiymatida 3a + ax + (-x² )= 0 tenglama o‘zaro teng ildizlarga ega bo‘ladi? A) a=0 B) a=0; a=12 C) a=0; a=-12 D) a=12 12 / 40 12. Tenglamani yeching. A) 2 B) 3 C) 4 D) 1 13 / 40 13. To’g’ri burchakli uchburchakning katetlari 5 sm va 12 sm. Uchburchakka ichki chizilgan aylananing radiusini toping. A) 4 sm; B) 2 m; C) 2 sm; D) 3 sm; 14 / 40 14. Integralni hisoblang: A) 3π/4 B) 3π/16 C) 3π/8 D) 3π/26 15 / 40 15. Hisoblang: cos² 10°+ cos² 30°+ cos² 80° A) 2.25 B) 1.75 C) 1 D) 1,5 16 / 40 16. Chizmada nechta parallelogramm bor? A) 12 B) 18 C) 16 D) 24 17 / 40 17. bo‘lsa, ni toping. A) 1.5 B) 0 C) 2 D) 1 18 / 40 18. Tengsizlikni yeching: 3·9x -10·21x + 7 ·49x ≤0 A) [0;1] B) [1;2] C) [-1;0] D) [-1;1] 19 / 40 19. bo‘lsa, x· y ni toping. A) 4 B) 3 C) 2 D) 1 20 / 40 20. Agar cos4x = acos4 x + bcos² x +1 bo‘lsa, a+b = ? A) 1 B) 0 C) -2 D) -1 21 / 40 21. tenglamani yeching. A) 3 B) 0 C) 2 D) 1 22 / 40 22. englamaning [0;π ] kesmadagi ildizlari soni 3 tadan ko‘pmi? A) ha B) yo'q 23 / 40 23. tenglama ildizlari yig‘indisini toping. A) 0 B) -2 C) 1 D) -1 24 / 40 24. tengsizlik nechta butun yechimga ega? A) 1 B) cheksiz ko‘p C) Ø D) 2 25 / 40 25. ABCD parallelogramm va SKBCE =18 bo‘lsa, SABCD = ? A) 54 B) 72 C) 36 D) 48 26 / 40 26. Tenglamani yeching: A) 5 B) 4 C) 2 D) 1 27 / 40 27. va bo‘lsa, a ni b orqali ifodalang. A) a=24-3b B) a=18-3b C) a=18+2b D) a=24-5b 28 / 40 28. Agar x= y + 4 bo‘lsa, A) 1 B) 3 C) 0 D) 2 29 / 40 29. Agar tgx α =4 bo‘lsa, A) -47/25 B) -2 C) 4 D) 1 30 / 40 30. Agar va ular orasidagi burchak 120o bo‘lsa, ni toping. A) 2√7 B) 5 C) 2√5 D) 7 31 / 40 31. Hisoblang: A) 6 B) 2 C) 11 D) 9 32 / 40 32. Hisoblang: A) 2019 B) 2021 C) 2022 D) 2020 33 / 40 33. |x²-2x|≤xtengsizlikning butun yechimlari yig‘indisini toping. A) 10 B) 3 C) 15 D) 6 34 / 40 34. bo‘lsa, f -1(x) ni toping. Bunda f -1(x)-f(x) ga teskari funksiya. A) 1 B) 3 C) 2 D) 4 35 / 40 35. Agar f (x)-3x-2 bo‘lsa, f(a+b+c)-f(abc)=? Bunda a, b, c – kvadrat funksiya koeffitsiyentlari. A) 9 B) 8 C) 7 D) 10 36 / 40 36. y = xln x funksiya hosilasini toping. A) lnx(x+1) B) lnx+1 C) xx(lnx+1)ln x 1 D) lnx+x 37 / 40 37. Ayirmasi d ga teng bo‘lgan arifmetik progressiya uchun ni toping. A) 1/2 B) 1/4 C) 2/3 D) 1/3 38 / 40 38. y=x²+1-|sinx| funksiya grafigi Ox o‘qidan pastda yotadimi? A) yo'q B) ha 39 / 40 39. Agar bo‘lsa, f(1)+f(-1) ni toping. A) 0 B) -1 C) 2 D) 1 40 / 40 40. tengsizlikni yeching. A) (1;1000) B) (0;1)∪(1;1000) C) Ø D) (0;1000) 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 14 Matematika fanidan attestatsiya savollari №16
