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Matematika attestatsiya №12

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Aprel 8, 2022

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OMAD YOR BO'LSIN!

Matematika fanidan attestatsiya savollari №12

28.03.2022 da Toshkentda tushgan savollar

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Testda 76% va undan yuqori natija oling va sertifikatni yuklab oling.

1 / 40

f (x) = (x² )^1−log_xa funksiya uchun, f (3^x+1) = a^x−1 bo`lsa, a parametr quyidagilardan qaysi biriga teng?

A) 27

B) 1

C) 9

D) 3

2 / 40

x⁶ -10x⁵ + ax⁴ + bx³ + cx² + dx +16 ko‘phadning barcha ildizlari natural sonlardan iborat (ba’zi ildizlar takrorlanuvchi ham bo‘lishi mumkin). U holda b ning qiymati nechaga teng?

A) -80

B) -88

C) -64

D) -41

3 / 40

Rasmda tasvirlangan favvora ko‘rinishi y=-x(x+6) ko'rinishda bo'lsa, favvora eng ko’pi bilan qaysi balandlikga ko’tarila oladi. (Koordinata Oy o’qi , suv yuzasida joylashgan)

A) 9

B) 8

C) Hisoblab bo'lmaydi

D) 6

4 / 40

Agar tgα = 7 bo‘lsa, ifodaning qiymatini toping.

A) 0,45

B) 0,5

C) 0,49

D) 0,47

5 / 40

a=1^0,(6), b=8^0,(3) , c=2^0,(9) bo'lsa, (a+b)^c=?

A) 25

B) 0

C) 9

D) 16

6 / 40

Hisoblang.

A) 9/11

B) 9/13

C) 7/11

D) 0

7 / 40

ABCD parallelogramm va S_KBCE= 18 bo'lsa, S_ABCD=?

A) 62

B) 48

C) 56

D) 54

8 / 40

Hisoblang.

A) 4

B) 1

C) 0

D) 2

9 / 40

Tenglama ildizlari yig'indisini toping.

A) 4

B) -1

C) 0

D) 2

10 / 40

Tengsizlikni yeching.

A) [-7;-5) u [-1;∞)

B) [-7;-3) u [-1;∞)

C) [-7;3 u [-1;∞)

D) [-7;-3] u [-1;∞)

11 / 40

y=xlnx funksiyani hosilasini toping.

A) 1

B) 2lnx-1

C) lnx+1

D) lnx/2+1

12 / 40

Tenglamani yeching.

A) 3

B) 1

C) 2

D) 4

13 / 40

Noaniq integralni toping. ∫(sin²x+cos²x)dx

A) x+c

B) 4x+c

C) 2x+c

D) x/2+c

14 / 40

Tengsizlikni yeching.

A) x∈(0;1000)

B) x∈(10;1000)

C) x∈(1;1000]

D) x∈[0;1000]

15 / 40

Tangga besh martta tashlanganda 2 martta gerb chiqishi ehtimolini toping.

A) 5/13

B) 5/16

C) 7/16

D) 9/16

16 / 40

y = x²+1-|sinx| funksiya grafigi OX o'qidan pastda yotadimi?

A) Yotmaydi

B) Yotadi

17 / 40

Hisoblang.

A) 32

B) 98

C) 94

D) 96

18 / 40

Hisoblang.

A) 3/2

B) 3/5

C) 2/3

D) 5/3

19 / 40

Hisoblang.

A) 14-2b

B) 24+3b

C) 24-3b

D) 26-3b

20 / 40

Ayirmasi d ga teng bo'lgan arifmetik progrssiya uchun ni toping.

A) 2

B) 2/3

C) 1/2

D) 1

21 / 40

Hisoblang.

A) 2021

B) 1

C) 2019

D) 2020

22 / 40

Tenglamani yeching.

A) 2

B) 1

C) 0

D) 5

23 / 40

Noaniq integralni toping. ∫(sin²x+cos²x)dx

A) x+c

B) 2x+c

C) 4x+c

D) c

24 / 40

Hisoblang.

A) 5

B) 4

C) 6

D) 3

25 / 40

|x²-2x|≤x yengsizlikni yeching.

A) (-2;0)∪[1;3]

B) {0}∪(1;3]

C) {0}∪[1;3]

D) {0}∪[1;3)

26 / 40

Chizmada nechta uchburchak tasvirlangan?

A) 52

B) 54

C) 48

D) 50

27 / 40

To'g'ri burchakli uchburchakning yuzi 96 ga, perimetri esa 48 ga teng bo'lsa, gipatenuza uzunligini toping.

A) 18

B) 23

C) 20

D) 21

28 / 40

Hisoblang.

A) -47/24

B) -47/25

C) 51/29

D) 49/25

29 / 40

Hisoblang.

A) 0

B) 2

C) 1

D) -1

30 / 40

To'g'ri burchakli uchburchakka ichki va tashqi chizilgan aylanalar raduslari 6 va 15 ga teng bo'lsa, katetlar yig'indini toping.

A) 42

B) 48

C) 28

D) 35

31 / 40

Tamonlarini ayirmasi 14 bo'lgan parallelogramning o'rmas burchagidan katta diagonaliga tushgan balandlik uni 12 va 30 ga teng kesmalarga ajratadi. Tamonlar uzunligini toping.

A) 30 va 24

B) 36 va 18

C) 32 va 22

D) 34 va 20

32 / 40

Hisoblang. cos²10° + cos²30° + cos²80°

A) 0

B) 7/3

C) 7/4

D) 3/7

33 / 40

Hisoblang.

A) 0

B) 1

C) -1

D) 2

34 / 40

Arimetik progerssiyada s₁₂=354, P=a₁+a₂+...+a₁₁, Q=a₂+a₄+...+a₁₂ va P/Q=32/27 ga teng bo'lsa, d ni toping.

A) -5

B) -4

C) -3

D) -6

35 / 40

Tengsizlikni yeching: 3 · 9^x–10 · 21^x+ 7 · 49 ^x ≤ 0

A) [-1;1]

B) [-1;0)

C) [-1;0]

D) (-1;3]

36 / 40

f(x)+(x-2)·g(x)=x²+5, f(3)=10 bo'lsa, g^-1=(4) ni toping. Bunda g^-1(x) g(x) ga teskari funksiya.

A) 6

B) 3

C) 4

D) 5

37 / 40

Tenglamani yeching:

A) 5,5

B) 2,5

C) 2

D) 6

38 / 40

To'g'ri burchakli uchburchakning gipotenuzasiga o'tkazilgan bissiktriksasi uni 20 va 30 ga teng kesmalarga ajratadi. To'g'ri burchakli uchburchak yuzini toping.

A) 7551/15

B) 15

C) 7500/13

D) 6700/13

39 / 40

Agar va ular orasidagi burchak 120° bo'lsa, ni toping.

A) √7

B) 3√7

C) 4√5

D) 2√7

40 / 40

Hisoblang.

A) 0

B) -2 yoki -1

C) -2 yoki 2

D) -2 yoki 0

Baholash mezoni

- 75 foiz va undan yuqori ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, oliy malaka toifasi (bosh o’qituvchi lavozimi) saqlansin”;

- 75 foizdan past ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, birinchi malaka toifasi (yetakchi o’qituvchi lavozimi)ga tushirilsin”;

- 75 foiz va undan yuqori ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, oliy malaka toifasi (bosh o’qituvchi lavozimi) berilsin”;

- 74 foizdan 65 foizgacha ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, birinchi malaka toifasi (yetakchi o’qituvchi lavozimi) saqlansin”;

- 65 foizdan kam ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, ikkinchi malaka toifasi (katta o’qituvchi lavozimi)ga tushirilsin”

- 64 foizdan 60 foizgacha ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, ikkinchi malaka toifasi (katta o’qituvchi lavozimi) saqlansin”;

- 60 foizdan kam ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, mutaxassis (oliy yoki o’rta maxsus, kasb-hunar ma'lumotli o’qituvchi) lavozimiga tushirilsin”