Uy » Online olimpiada » Matematika olimpiada » 11-sinf Matematika olimpiada №6 Matematika olimpiadaTuman 2023-2024 o'quv yili 11-sinf Matematika olimpiada №6 InfoMaster Avgust 19, 2024 14 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0 123456789101112131415161718192021222324252627282930 Vaqtingiz tugadi! Yaratilgan Avgust 19, 2024 Tomonidan InfoMaster 11-sinf Matematika olimpiada №6 2023-yil 21-oktyabr: 2023-2024 o'quv yili tuman bosqichida tushgan savollar! 1 / 30 Juft funksiyani ko‘rsating. A) B B) D C) A D) C 2 / 30 ko‘paytmani 1000 ga bo‘lgandagi qoldiqni toping. Tekshirish 3 / 30 Soddalashtiring: A) 1 B) 2 C) √10 D) √5 − 2 4 / 30 𝐴𝐵𝐶 uchburchakda ∠𝐴 = 90°, ∠𝐵 = 30°. Agar 𝐴𝐷, 𝐵𝐹 − uchburchakning ichki bissektrisalari bo‘lsa, 𝐵𝐹: 𝐴𝐷 ni toping. Tekshirish 5 / 30 tenglama nechta haqiqiy ildizga ega? (bunda [𝑥] − 𝑥 sonining butun qismi) Tekshirish 6 / 30 Soddalashtiring: A) B B) D C) A D) C 7 / 30 bo‘lsa, N ni toping. (n! = 1 ∙ 2 ∙ 3 ∙ … ∙ n) A) 1 B) 1.5 C) 0.5 D) 2 8 / 30 𝐴𝐵𝐶 −to‘g‘riburchakli uchburchak. Agar 𝐴𝐸 = 𝐸𝐹 = 𝐹𝐷 = 𝐷𝐵 = 2 bo‘lsa, 𝐶𝐸² + 𝐶𝐹² + 𝐶𝐷² yig‘indini toping. A) 56 B) 32 C) 42 D) 36 9 / 30 to‘g‘ri chiziqqa perpendikulyar va 𝐴(−5; 3) nuqta orqali o‘tuvchi to‘g‘ri chiziq tenglamasini ko‘rsating. A) 𝑦 = (− 1/5) 𝑥 + 2 B) 𝑦 = 5𝑥 + 28 C) 𝑦 = ( 1/5) 𝑥 + 4 D) 𝑦 = −5𝑥 − 22 10 / 30 f(x) = x2 − x − 1 bo‘lsa, f(0, (1)) − f(0, (2)) + f(0, (3)) − f(0, (4)) + f(0, (5)) − f(0, (6)) + f(0, (7)) − f(0, (8)) ni hisoblang. Tekshirish 11 / 30 funksiyalar grafiklari bilan chegaralangan shakl yuzini toping. (Necha π ekanligini yozing. Masalan: 8 yoki 9) Tekshirish 12 / 30 AB-aylana diametri. bo‘lsa, AB ni toping. Tekshirish 13 / 30 Ifodani soddalashtiring: A) sin(𝛽 − 𝛼) B) cos(𝛽 − 𝛼) C) sin(𝛼 − 𝛽) D) −cos(𝛼 − 𝛽) 14 / 30 Tomonlari 8, 15, 17 bo‘lgan uchburchakka ichki chizilgan aylana radiusini toping. A) 1 B) 4 C) 2 D) 3 15 / 30 AB/BC ni toping. A) C B) B C) D D) A 16 / 30 funksiyaning eng katta qiymatini toping. Tekshirish 17 / 30 𝑎, 𝑏 < 0 bo‘lsa, ni soddalashtiring. A) A B) C C) B D) D 18 / 30 𝐴𝐵 = 𝐵𝐶 = 𝐶𝐷, ∠𝐴𝐵𝐶 = 90°, ∠𝐵𝐶𝐷 = 150° bo‘lsa, ∠𝐴𝐷𝐶 ni toping. (Javobni gradusda kriting) Tekshirish 19 / 30 Hisoblang: cos²21° + cos²69° ∙ ctg²25° A) 0 B) 1 C) 2 D) -1 20 / 30 Tenglamaning eng katta va eng kichik ildizlari ayirmasini toping ||𝑥² − 𝑥| − 𝑥²| = 4 Tekshirish 21 / 30 bo‘lsa, |𝑥 + 𝑦| ni hisoblang. A) √40 B) 2 C) √20 D) 4 22 / 30 𝐴𝐶 = 𝐵𝐷, ∠𝐴 = 80° , ∠𝐵 = 20°, ∠𝐴𝐷𝐶 burchakni toping. (Javobni gradusda kiriting.) Tekshirish 23 / 30 Agar 𝑎 + 2/b=26 va 𝑎𝑏 = 11 bo‘lsa, 𝑎 ni toping. A) 22 B) 0.5 C) 11 D) 2 24 / 30 Taqqoslang: A) 𝑏 > 𝑐 > 𝑎 B) 𝑎 > 𝑐 > 𝑏 C) 𝑎 > 𝑏 > 𝑐 D) 𝑏 > 𝑎 > 𝑐 25 / 30 Hisoblang: A) 4.8 B) 3.4 C) 3.8 D) 2.4 26 / 30 𝑚 = 𝑐𝑡𝑔 175º; 𝑛 = sin 105º; 𝑝 = 𝑡𝑔 175º va 𝑞 = cos 75º sonlarini taqqoslang. A) 𝑞 > 𝑝 > 𝑛 > 𝑚 B) 𝑛 > 𝑞 > 𝑝 > 𝑚 C) 𝑞 > 𝑛 > 𝑝 > 𝑚 D) 𝑛 > 𝑞 > 𝑚 > 𝑝 27 / 30 𝐴𝐵𝐶 uchburchakda, ∠A=2·∠B=2·x, AC=3, BC=4 boʻlsa, u holda cosx ni toping. A) 3/4 B) 3/8 C) 1/3 D) 2/3 28 / 30 𝑥² − 2𝑥 + 𝑎 = −1 tenglama [-4;3] oraliqda ildizga ega bo‘ladigan 𝑎 parametrning barcha qiymatlarini toping? A) [-9;0] B) [-9;25] C) [-25;0] D) [-25;-4] 29 / 30 qavsni ochganda 𝑥 ishtirok etmagan hadni toping. A) 495/16 B) 165/16 C) 495/8 D) 165/8 30 / 30 Arifmetik progressiyada 𝑎1 + 𝑎3 + 𝑎5 = 36 va 𝑎²3 − 𝑎1 = 128 bo‘lsa, 𝑎1 ni toping. A) 15 B) 14 C) 13 D) 16 0% Testni qayta ishga tushiring Tomonidan Wordpress Quiz plugin Author: InfoMaster Foydali bo'lsa mamnunmiz
