Matematika attestatsiya №14 Oktabr 30, 2022Oktabr 30, 2022 da chop etilgan InfoMaster tomonidan Matematika attestatsiya №14 ga fikr bildirilmagan. 0% 30 12345678910111213141516171819202122232425262728293031323334353637383940 OMAD YOR BO'LSIN! Matematika fanidan attestatsiya savollari №14 17.10.2022 Toshkent savollari! 1 / 40 1. y=kx+n funksiyaning grafigi I va III chorakdan o‘tishi uchun k va n qanday bo‘lishi kerak? A) n > 0, k = 0 B) n = 0, k > 0 C) n < 0, k = 0 D) n = 0, k < 0 2 / 40 2. y=f(x) funksiya uchun tenglik o'rinli bo'lsa, f(π/4)=? A) 1/5 B) 1/4 C) 4 D) 1/3 3 / 40 3. Hisoblang: -121+(-135)-(-1)28 A) -2 B) -1 C) 0 D) -3 4 / 40 4. 275+330 sonini 41 ga bo‘lganda qoladigan qoldiqni aniqlang. A) 0 B) 1 C) 5 D) 9 5 / 40 5. sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 35 B) 24 C) 23 D) 14 6 / 40 6. ABCD trapetsiyaning AD kichik asosi 6 ga teng. C burchagining CF bissektrisasi AB tomonga perpendikulyar bo‘lib, bunda BF = 3AF = 6 bo‘lsa, katta asos uzunligini toping. A) 15 B) 12 C) 9 D) 18 7 / 40 7. sonining oxirgi raqamini toping. A) 3 B) 9 C) 0 D) 1 8 / 40 8. f (x) = (x² )1−logxa funksiya uchun, f (3x+1) = ax−1 bo`lsa, a parametr quyidagilardan qaysi biriga teng? A) 9 B) 27 C) 1 D) 3 9 / 40 9. Agar x² -1 = 0 tenglamaning ildizi r-1/r bo‘lsa, u holda r4+1/r4 ni toping. A) 1 B) 5 C) 4 D) 7 10 / 40 10. f(x) va g(x) funksiyalar f(x)+(x-2)·g(x)=x²+5 bog’lanishda va f(3)=10 bo’lsa, g-1 (4) ning qiymatini toping.(g-1 (x)-g(x) ga teskari funksiya) A) 2 B) 3 C) 6 D) 4 11 / 40 11. Tenglama ildizining natural bo‘luvchilari sonini toping. A) 2 B) 5 C) 6 D) 4 12 / 40 12. To'g'ri burchakli uchburchakning gipotenuzasiga o'tkazilgan bissiktriksasi uni 20 va 30 ga teng kesmalarga ajratadi. To'g'ri burchakli uchburchak yuzini toping. A) 7500/13 B) 7551/15 C) 6700/13 D) 15 13 / 40 13. sin²α+ sin²β= 1 tenglamada 0<α<π/2 va 0<β<π/2 bo’lsa, α²+π²/2+β²+2αβ ni hisoblang. A) 2π² B) 3π²/4 C) α² D) π²/4 14 / 40 14. bo‘lsa, f -1(x) ni toping. Bunda f -1(x)-f(x) ga teskari funksiya. A) 1 B) 2 C) 3 D) 4 15 / 40 15. englamaning [0;π ] kesmadagi ildizlari soni 3 tadan ko‘pmi? A) ha B) yo'q 16 / 40 16. y = xln x funksiya hosilasini toping. A) lnx+x B) lnx+1 C) xx(lnx+1)ln x 1 D) lnx(x+1) 17 / 40 17. Hisoblang: A) 131 B) 132 C) 129 D) 133 18 / 40 18. Hisoblang: A) 2019 B) 2020 C) 2021 D) 2022 19 / 40 19. Agar va ular orasidagi burchak 120o bo‘lsa, ni toping. A) 5 B) 2√7 C) 2√5 D) 7 20 / 40 20. Tenglamani yeching: A) 2 B) 4 C) 1 D) 5 21 / 40 21. Agar bo‘lsa, f(1)+f(-1) ni toping. A) -1 B) 1 C) 2 D) 0 22 / 40 22. Chizmada nechta parallelogramm bor? A) 24 B) 12 C) 16 D) 18 23 / 40 23. tenglama ildizlari yig‘indisini toping. A) -1 B) 1 C) 0 D) -2 24 / 40 24. tengsizlikni yeching. A) Ø B) (0;1000) C) (0;1)∪(1;1000) D) (1;1000) 25 / 40 25. bo‘lsa, ni toping. A) 0 B) 2 C) 1.5 D) 1 26 / 40 26. ABCD parallelogramm va SKBCE =18 bo‘lsa, SABCD = ? A) 72 B) 36 C) 48 D) 54 27 / 40 27. tengsizlik nechta butun yechimga ega? A) 1 B) cheksiz ko‘p C) Ø D) 2 28 / 40 28. tenglamani yeching. A) 0 B) 3 C) 2 D) 1 29 / 40 29. Agar tgx α =4 bo‘lsa, A) 1 B) -47/25 C) 4 D) -2 30 / 40 30. Ayirmasi d ga teng bo‘lgan arifmetik progressiya uchun ni toping. A) 2/3 B) 1/4 C) 1/3 D) 1/2 31 / 40 31. Hisoblang: cos² 10°+ cos² 30°+ cos² 80° A) 1.75 B) 1,5 C) 2.25 D) 1 32 / 40 32. Agar x= y + 4 bo‘lsa, A) 0 B) 1 C) 2 D) 3 33 / 40 33. Integralni hisoblang: A) 3π/26 B) 3π/8 C) 3π/4 D) 3π/16 34 / 40 34. Agar cos4x = acos4 x + bcos² x +1 bo‘lsa, a+b = ? A) -1 B) -2 C) 1 D) 0 35 / 40 35. |x²-2x|≤xtengsizlikning butun yechimlari yig‘indisini toping. A) 6 B) 15 C) 10 D) 3 36 / 40 36. va bo‘lsa, a ni b orqali ifodalang. A) a=24-3b B) a=18-3b C) a=18+2b D) a=24-3b 37 / 40 37. va f(x)=y(x) bo‘lsa, f(5) ni toping. A) -5 B) -1 C) 1 D) 5 38 / 40 38. Hisoblang: A) 6 B) 2 C) 9 D) 11 39 / 40 39. bo‘lsa, x· y ni toping. A) 4 B) 1 C) 3 D) 2 40 / 40 40. Agar f (x)-3x-2 bo‘lsa, f(a+b+c)-f(abc)=? Bunda a, b, c – kvadrat funksiya koeffitsiyentlari. A) 7 B) 10 C) 9 D) 8 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Matematika attestatsiya