9-sinf Matematika olimpiada №3.1 Oktabr 2, 2022Avgust 19, 2024 da chop etilgan InfoMaster tomonidan 9-sinf Matematika olimpiada №3.1 ga 2 fikr bildirilgan 0 12345678910111213141516171819202122232425 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster 9-sinf Matematika olimpiada №3.1 2021-2022 o'quv yil viloyat bosqichida tushgan savollar. 1 / 25 1. Hovuzga uchta quvur o‘tkazilgan. Birinchisi hovuzni 12 soatda, ikkinchisi 8 soatda to‘ldiradi. Uchinchisi hovuzni 1 sutkada bo‘shatadi. Agar uchala quvur birgalikda ochib qo‘yilsa, bo‘sh hovuzning yarmi qancha vaqt(soat)da to‘ladi? A) 3 B) 1,5 C) 2,5 D) 2 2 / 25 2. ax²+bc+c=0 kvadrat tenglama bitta manfiy, bitta musbat ildizga ega bo`lsa, quyidagilardan qaysibiri to`g`ri?(D=b2−4ac) A) 2 B) 3 C) 1 D) 4 3 / 25 3. Agar ning qiymatini toping. A) -3 B) 3 C) -1 D) 2 4 / 25 4. Raqamlari joylashuvi kamayish tartibida bo‘ladigan nechta uch xonali natural son mavjud? (masalan, 983, 751,210) A) 115 B) 120 C) 125 D) 130 5 / 25 5. Agar ? + ? + ? = 0 bo‘lsa, ni soddalashtiring. A) 0 B) 1.2 C) 1.8 D) 1 6 / 25 6. tengsizlikning butun yechimlari yig‘indisini toping. A) 18 B) 12 C) 21 D) 20 7 / 25 7. Aylanaga tashqi chizilgan ABCD teng yonli trapetsiyaning yuzi √3 ga teng. Agar ВС : AD = 1 : 3 bo‘lsa, trapetsiyaning АВ yon tomonini toping. A) √3 B) 2 C) √6 D) √2 8 / 25 8. f(x) kvadrat funksiyaga nisbatan ma’lumki, f(0) + f(1) = 0, f(2) + f(3) = 0. f(x) = 2022 tenglamaning ildizlari yig‘indisi nimaga teng? (bunda, f(x) = 2022 tenglama 2 ta turli yechimga ega). A) 4 B) 6 C) 3 D) 5 9 / 25 9. 1 dan 100 gacha bo‘lgan natural sonlar orasidagi ? sonlar shundayki, ? ning natural bo‘luvchilari ko‘paytmasi(1 va ? ham inobatga olinganda) ?³ ga teng. Shunday ? natural sonlar nechta? A) 10 B) 12 C) 16 D) 18 10 / 25 10. Yig‘indini toping: A) 2022 B) 2020 C) 2021 D) 2023 11 / 25 11. Kenguru oldinga 1 metrga yoki 3 metrga sakraydi. U 10 metr masofani bosib o‘tishni xohlaydi. U bu ishni necha usulda amalga oshira oladi? A) 30 B) 36 C) 28 D) 55 12 / 25 12. Soddalashtiring: A) I B) IV C) II D) III 13 / 25 13. 4 ga bo‘lganda 3, 3 ga bo‘lganda esa 2 qoldiq hosil bo‘ladigan barcha ikki xonali sonlar yig‘indisini toping. A) 420 B) 376 C) 384 D) 424 14 / 25 14. Chizmadagi 14 ta kvadratning perimetrlar yig‘indisi 400 sm ga teng. Ushbu kvadratlarning yuzlari yig‘indisi necha kv.sm ni tashkil qiladi? A) 900 B) 800 C) 850 D) 950 15 / 25 15. to‘g‘ri chiziqlar orasidagi burchakni toping. A) 45° B) 15° C) 5° D) 30° 16 / 25 16. Tenglama butun sonlarda nechta yechimga ega? (? − 2021)² − ?² + 2? = 14 A) 4 B) 5 C) 6 D) 3 17 / 25 17. ABC uchburchak berilgan ∠B = 90°. AC va BC tomonlarida mos ravishda E va D nuqtalar shunday olinganki, bunda AE = EC, ∠ADB = ∠EDC. U holda CD: BD ni toping. A) 2 B) 5 C) 3 D) 4 18 / 25 18. A) -6 B) -36 C) -1 D) -216 19 / 25 19. Tenglama ildizlari yig‘indisini toping. (? − |?|)² + ? + |?| = 100 . A) 45 B) 50 C) 55 D) 40 20 / 25 20. Hisoblang: bunda, A) -64 B) -144 C) -100 D) -49 21 / 25 21. ?1 va ?2 sonlari 2?² − 3? − 2 = 0 tenglamaning ildizlari, |?1 − ?2| ni toping. A) 3 B) 3.5 C) 2.5 D) 2 22 / 25 22. ?(?) = 6/(?−1) va ?(?) = 2? − 1. ?(?(2)) + ?(?(3)) + ?(?(2)) + ?(?(3)) ni toping. A) 11.4 B) 12.6 C) 9.8 D) 18.2 23 / 25 23. Tenglamani yeching: (71² + 81²)(7² + 8²) = 1135² + ?² A) 159 B) 169 C) 161 D) 151 24 / 25 24. Beshta musbat son berilgan. Birinchi va beshinchi sonlar yig‘indisi 13 ga teng. Berilgan barcha sonlar yig‘indisidan ikkinchi son 3 marta, uchinchi son 4 marta, to‘rtinchi son esa 5 marta kichik. Berilgan sonlardan eng kattasini toping. A) 15 B) 20 C) 22 D) 12 25 / 25 25. Dastlab tarvuzning 99% i suv edi, quritilgandan so‘ng esa 98% suv bo‘ldi. Tarvuzning massasi necha marta kamaydi? A) 4 B) 1.5 C) 2 D) 2.5 0% Testni qayta ishga tushiring tomonidan Wordpress Quiz plugin Matematika olimpiada, Viloyat 2021-2022 o'quv yili
