Uy » Online olimpiada » Matematika olimpiada » 9-sinf Matematika olimpiada №3.1 Matematika olimpiadaViloyat 2021-2022 o'quv yili 9-sinf Matematika olimpiada №3.1 InfoMaster Avgust 19, 2024 20 Ko'rishlar 2 izohlar SaqlashSaqlanganOlib tashlandi 0 0 12345678910111213141516171819202122232425 Vaqtingiz tugadi! 9-sinf Matematika olimpiada №3.1 2021-2022 o'quv yil viloyat bosqichida tushgan savollar. 1 / 25 1. bo‘lsa, ifodaning qiymatini toping A) 2/3 B) 13/16 C) 15/16 D) 3/16 2 / 25 2. Birinchi quvurdan ikkinchi quvurga qaraganda ikki barobar ko’p suv oqadi.Ikkalasi birgalikda bo’sh hovuzni 12 soatda to’ldiradi.Birinchi quvur hovuzning uchdan bir qismini necha soatda to’ldiradi? A) 12 B) 4 C) 9 D) 6 3 / 25 3. bo‘lsa, 3? + ? ni toping. A) 10 B) 5 C) 7,5 D) 2,5 4 / 25 4. Kenguru oldinga 1 metrga yoki 3 metrga sakraydi. U 10 metr masofani bosib o‘tishni xohlaydi. U bu ishni necha usulda amalga oshira oladi? A) 55 B) 36 C) 28 D) 30 5 / 25 5. Tenglama butun sonlarda nechta yechimga ega? (? − 2021)² − ?² + 2? = 14 A) 6 B) 3 C) 4 D) 5 6 / 25 6. ?(?) = 6/(?−1) va ?(?) = 2? − 1. ?(?(2)) + ?(?(3)) + ?(?(2)) + ?(?(3)) ni toping. A) 11.4 B) 9.8 C) 12.6 D) 18.2 7 / 25 7. to‘g‘ri chiziqlar orasidagi burchakni toping. A) 30° B) 45° C) 15° D) 5° 8 / 25 8. Raqamlari yig‘indisidan 12 marta katta bo‘lgan uch xonali sonlarni toping. A) 150 B) 109 C) 108 D) 111 9 / 25 9. ABC uchburchak berilgan ∠B = 90°. AC va BC tomonlarida mos ravishda E va D nuqtalar shunday olinganki, bunda AE = EC, ∠ADB = ∠EDC. U holda CD: BD ni toping. A) 3 B) 4 C) 5 D) 2 10 / 25 10. bo‘lsa, ? + ? ni toping. A) 11 B) 12 C) 13 D) 16 11 / 25 11. Tenglama ildizlari yig‘indisini toping. (? − |?|)² + ? + |?| = 100 . A) 50 B) 40 C) 45 D) 55 12 / 25 12. Uchburchakning to‘g‘ri burchagidan chiquvchi bissektrisa gipotenizani 15 va 20 ga teng qismlarga ajratadi. Uchburchak yuzini toping. A) 294 B) 288 C) 264 D) 268 13 / 25 13. ?1 va ?2 sonlari 2?² − 3? − 2 = 0 tenglamaning ildizlari, |?1 − ?2| ni toping. A) 3.5 B) 3 C) 2.5 D) 2 14 / 25 14. A) -6 B) -216 C) -1 D) -36 15 / 25 15. Aylanaga tashqi chizilgan ABCD teng yonli trapetsiyaning yuzi √3 ga teng. Agar ВС : AD = 1 : 3 bo‘lsa, trapetsiyaning АВ yon tomonini toping. A) √6 B) √2 C) √3 D) 2 16 / 25 16. Soddalashtiring: A) III B) IV C) II D) I 17 / 25 17. Tenglamalar sistemasi nechta yechimga ega? A) 12 B) 8 C) 6 D) 10 18 / 25 18. Tenglamani yeching: (71² + 81²)(7² + 8²) = 1135² + ?² A) 151 B) 161 C) 159 D) 169 19 / 25 19. Raqamlari joylashuvi kamayish tartibida bo‘ladigan nechta uch xonali natural son mavjud? (masalan, 983, 751,210) A) 130 B) 120 C) 115 D) 125 20 / 25 20. Beshta musbat son berilgan. Birinchi va beshinchi sonlar yig‘indisi 13 ga teng. Berilgan barcha sonlar yig‘indisidan ikkinchi son 3 marta, uchinchi son 4 marta, to‘rtinchi son esa 5 marta kichik. Berilgan sonlardan eng kattasini toping. A) 12 B) 20 C) 15 D) 22 21 / 25 21. Ucburchakning tomonlari 13; 14; 15 ga teng. Ichki chizilgan aylana radiusini toping. A) 4 B) 4.5 C) 3.5 D) 4.8 22 / 25 22. Aylanaga ichki chizilgan trapetsiyaning diagonallari o‘zaro perpendikulyar. Trapetsiya asoslari 1:7 nisbatda va perimetri 18 ga teng bo‘lsa, trapetsiya yuzini toping. A) 18 B) 16 C) 22 D) 13 23 / 25 23. Tenglamaning ildizlari yig‘indisini toping: [?] + {2?} = 2,5 (bu yerda, [?]⎯ ? sonining butun qismi, {?}⎯ ? sonining kasr qismi, ya’ni {?} = ? − [?]) A) 6 B) 3 C) 9 D) 5 24 / 25 24. 1 dan 100 gacha bo‘lgan natural sonlar orasidagi ? sonlar shundayki, ? ning natural bo‘luvchilari ko‘paytmasi(1 va ? ham inobatga olinganda) ?³ ga teng. Shunday ? natural sonlar nechta? A) 10 B) 18 C) 16 D) 12 25 / 25 25. tengsizlikning butun yechimlari yig‘indisini toping. A) 18 B) 21 C) 12 D) 20 0% Testni qayta ishga tushiring Tomonidan Wordpress Quiz plugin Author: InfoMaster Foydali bo'lsa mamnunmiz