Uy » Online olimpiada » Matematika olimpiada » 10-sinf Matematika olimpiada №3 Matematika olimpiadaViloyat 2021-2022 o'quv yili 10-sinf Matematika olimpiada №3 InfoMaster Avgust 19, 2024 91 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0 12345678910111213141516171819202122232425 Vaqtingiz tugadi! 10-sinf Matematika olimpiada №3 2021-2022 o'quv yili viloyat bosqichida tushgan savollar. 1 / 25 1. tengsizlik qiymatlarida o‘rinli bo‘ladigan ning barcha qiymatlarini toping. A) (2;8) B) [2;8] C) (8;19) D) (-2;8) 2 / 25 2. 7(kx−2)=7k+2(x−8) tenglama k ning qanday qiymatlarida ildizga ega bo`lmaydi? A) (2/7; ∞) B) ∅ C) k=2/7 D) (−∞; 2/7) 3 / 25 3. Agar ni toping. A) 0.9 B) 0.96 C) 0.81 D) 0.8 4 / 25 4. ?/? kasr (?, ? −natural sonlar)— qisqarmas kasr va (7?+6?)/(3?+2?) kasr esa qisqaradi. Ushbu kasr qanday songa qisqaradi? A) 8 B) 2 C) 5 D) 3 5 / 25 5. Uchburchak tomonlarining uzunliklari berilgan tenglamaning ildizlariga mos keladi. ?³ − 24?² + 183? − 440 = 0. Uchburchakning yuzini hisoblang. A) 35 B) √21 C) 4√21 D) 2√21 6 / 25 6. Soddalashtiring: (4cos² 9° −3)(4cos² 27° −3)·ctg9° A) 1 B) 2cos² 9° C) sin18° D) tg9° 7 / 25 7. 102022 − 22021 ayirmani 24 ga bo‘lgandagi qoldiqni toping. A) 16 B) 8 C) 12 D) 0 8 / 25 8. Ayirmasi noldan farqli bo‘lgan arifmetik progressiyaning 4-hadidan boshlab 14- hadigacha bo‘lgan hadlar yig‘indisi 77 ga teng. Progressiyaning 7 ga teng bo‘lgan had nomerini toping. A) 10 B) 8 C) 9 D) 11 9 / 25 9. ABCD to‘rtburchakda А va В burchaklar- to‘g‘ri, tg∠D = 3/4 va ВС = AD/2 = АВ + 2 bo‘lsa, АС ni toping. A) 15 B) 8 C) 9 D) 10 10 / 25 10. ABCD to‘rtburchakda АВ = CD = 9 va bu to‘rtburchakka radiusi 4 ga teng aylana ichki chizilgan. ABCD to‘rtburchak yuzini toping. A) 144 B) 72 C) 36 D) 81 11 / 25 11. bo‘lsa ? ning qiymatini toping. A) 25 B) 40 C) 37 D) 12 12 / 25 12. Agar cos ∠A = 1/5 va sin∠B = 1/2 bo‘lsa, АВС uchburchakning mos ravishda А va В uchlaridan tushirilgan balandliklar nisbatini toping. A) 5√3/12 B) 5√2/5 C) 5√6/24 D) 2/5 13 / 25 13. Tenglamalar sistemasi nechta yechimga ega? A) 8 B) 6 C) 12 D) 10 14 / 25 14. (?² − 2? + 3)(?² + 6? + 12) = 6 bo‘lsa, ? + ? ni toping. A) -3 B) 2 C) 3 D) -2 15 / 25 15. Tenglama nechta yechimga ega? A) 5 B) 3 C) 4 D) 2 16 / 25 16. Agar ?1 = 6? − 6 va у2//?1 hamda у2 to‘g‘ri chiziq ?(6; 6) nuqtadan o‘tsa, ?2 ni toping. A) 6? − 24 B) 6? − 30 C) −6? + 6 D) −6? + 42 17 / 25 17. Tenglamani yeching: 3x+3 + 8·3x+2 = 33 A) 0 B) -1 C) -2 D) 1 18 / 25 18. ?(?) = ?5 − 7?4 + 3?3 − ? + 2 ko‘phadni ?2 + ? ga bo‘lgandagi qoldiqni aniqlang. A) 4? + 2 B) 8? + 2 C) 10? + 2 D) 6? + 2 19 / 25 19. englikni qanoatlantiradigan ? ning eng kichik qiymatini toping. A) 1 B) 3 C) -1 D) 0 20 / 25 20. x, y sonlari (x² + 1)(y² + 1) + 2(x − y)(1 − xy) = 4(1 + xy) tenglikni qanoatlantiradi |1 + x| ∙ |1 − y| ni toping. A) 9 B) 3 C) 2 D) 1 21 / 25 21. ABC uchburchakning AC tomonida D nuqta olingan, bunda ∠ABC = ∠BDC. Agar AD = 10, CD = 8 bo‘lsa, BC ni toping. A) 9 B) 12 C) 15 D) 10 22 / 25 22. Qavariq to‘rtburchakning diagonallari 3 va 4 ga teng. Agar qarama qarshi tomonlarining o‘rtalarini tutashtirishdan hosil bo‘lgan kesmalar uzunliklari o‘zaro teng bo‘lsa, qavariq to‘rtburchakning yuzini toping. A) 6 B) 8 C) 7 D) 5 23 / 25 23. ?(? − 1) = 2?(5? + 4) va ?(2? − 1) = 4? + 4 bo‘lsa, ?(?) ni toping A) 0 B) 20x+50 C) 20x+48 D) x+25 24 / 25 24. Agar bo‘lsa, |xyz| ni toping. A) 100 B) 1000 C) 800 D) 500 25 / 25 25. tenglama nechta yechimga ega, agar x ∈ (0; 50)? A) 15 B) 16 C) 17 D) 14 0% Testni qayta ishga tushiring Author: InfoMaster Foydali bo'lsa mamnunmiz
