9-sinf Matematika olimpiada №3.1 Oktabr 2, 2022Oktabr 2, 2022 da chop etilgan InfoMaster tomonidan 9-sinf Matematika olimpiada №3.1 ga fikr bildirilmagan. 0 12345678910111213141516171819202122232425 Vaqtingiz tugadi! 9-sinf Matematika olimpiada №3.1 2021-2022 o'quv yil viloyat bosqichida tushgan savollar. 1 / 25 1. P(x) ko‘phadni x-a ga bo‘lgandagi qoldiqni toping. A) P(a) B) P(x-a) C) 0 D) P(x) 2 / 25 2. Agar x2−8x+20z+4z2+41=0 tenglik o`rinli bo`lsa, xz ni toping. A) -20 B) -40 C) -5 D) -10 3 / 25 3. To’rt xonali son “yoqimli” deyiladi, agar sonning o‘zi 25 ga bo‘linsa, uning raqamlari yig‘indisi 25 ga bo‘linsa va uning raqamlari ko‘paytmasi 25 ga bo‘linsa. Barcha “yoqimli” sonlarning yig‘indisini toping. A) 14450 B) 14455 C) 450 D) 13450 4 / 25 4. Beshta musbat son berilgan. Birinchi va beshinchi sonlar yig‘indisi 13 ga teng. Berilgan barcha sonlar yig‘indisidan ikkinchi son 3 marta, uchinchi son 4 marta, to‘rtinchi son esa 5 marta kichik. Berilgan sonlardan eng kattasini toping. A) 12 B) 15 C) 20 D) 22 5 / 25 5. A) -6 B) -216 C) -36 D) -1 6 / 25 6. Aylanaga ichki chizilgan trapetsiyaning diagonallari o‘zaro perpendikulyar. Trapetsiya asoslari 1:7 nisbatda va perimetri 18 ga teng bo‘lsa, trapetsiya yuzini toping. A) 13 B) 16 C) 22 D) 18 7 / 25 7. Teng yonli trapetsiyaning asoslari 6 va 10 ga, diagonali 10 ga teng. Trapetsiya yuzini toping. A) 56 B) 64 C) 36 D) 48 8 / 25 8. bo‘lsa, ? + ? ni toping. A) 11 B) 16 C) 12 D) 13 9 / 25 9. Tenglama butun sonlarda nechta yechimga ega? (? − 2021)² − ?² + 2? = 14 A) 5 B) 3 C) 6 D) 4 10 / 25 10. 4 ga bo‘lganda 3, 3 ga bo‘lganda esa 2 qoldiq hosil bo‘ladigan barcha ikki xonali sonlar yig‘indisini toping. A) 384 B) 424 C) 420 D) 376 11 / 25 11. 1 dan 100 gacha bo‘lgan natural sonlar orasidagi ? sonlar shundayki, ? ning natural bo‘luvchilari ko‘paytmasi(1 va ? ham inobatga olinganda) ?³ ga teng. Shunday ? natural sonlar nechta? A) 10 B) 18 C) 12 D) 16 12 / 25 12. Agar ? + ? + ? = 0 bo‘lsa, ni soddalashtiring. A) 1.8 B) 1 C) 1.2 D) 0 13 / 25 13. tengsizlikning butun yechimlari yig‘indisini toping. A) 18 B) 21 C) 12 D) 20 14 / 25 14. Yig‘indini toping: A) 2020 B) 2023 C) 2022 D) 2021 15 / 25 15. Soddalashtiring: A) IV B) I C) III D) II 16 / 25 16. Uchburchakning to‘g‘ri burchagidan chiquvchi bissektrisa gipotenizani 15 va 20 ga teng qismlarga ajratadi. Uchburchak yuzini toping. A) 264 B) 268 C) 288 D) 294 17 / 25 17. Raqamlari yig‘indisidan 12 marta katta bo‘lgan uch xonali sonlarni toping. A) 111 B) 109 C) 150 D) 108 18 / 25 18. ?1 va ?2 sonlari 2?² − 3? − 2 = 0 tenglamaning ildizlari, |?1 − ?2| ni toping. A) 3 B) 2 C) 3.5 D) 2.5 19 / 25 19. ABC uchburchak berilgan ∠B = 90°. AC va BC tomonlarida mos ravishda E va D nuqtalar shunday olinganki, bunda AE = EC, ∠ADB = ∠EDC. U holda CD: BD ni toping. A) 5 B) 2 C) 4 D) 3 20 / 25 20. f(x) kvadrat funksiyaga nisbatan ma’lumki, f(0) + f(1) = 0, f(2) + f(3) = 0. f(x) = 2022 tenglamaning ildizlari yig‘indisi nimaga teng? (bunda, f(x) = 2022 tenglama 2 ta turli yechimga ega). A) 5 B) 6 C) 4 D) 3 21 / 25 21. Ucburchakning tomonlari 13; 14; 15 ga teng. Ichki chizilgan aylana radiusini toping. A) 3.5 B) 4.8 C) 4 D) 4.5 22 / 25 22. Tenglamalar sistemasi nechta yechimga ega? A) 10 B) 6 C) 12 D) 8 23 / 25 23. Tenglamani yeching: (71² + 81²)(7² + 8²) = 1135² + ?² A) 161 B) 151 C) 169 D) 159 24 / 25 24. Raqamlari joylashuvi kamayish tartibida bo‘ladigan nechta uch xonali natural son mavjud? (masalan, 983, 751,210) A) 130 B) 125 C) 115 D) 120 25 / 25 25. ?(?) = 6/(?−1) va ?(?) = 2? − 1. ?(?(2)) + ?(?(3)) + ?(?(2)) + ?(?(3)) ni toping. A) 9.8 B) 18.2 C) 11.4 D) 12.6 0% Testni qayta ishga tushiring Author: InfoMaster Matematika olimpiada