Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №14 Matematika attestatsiya Matematika attestatsiya №14 InfoMaster Oktabr 30, 2022 197 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 1 0% 0 12345678910111213141516171819202122232425262728293031323334353637383940 OMAD YOR BO'LSIN! Matematika fanidan attestatsiya savollari №14 17.10.2022 Toshkent savollari! 1 / 40 1. Agar ni hisoblang. A) 8 B) 9 C) 0 D) Cheksiz 2 / 40 2. P(-2;2) nuqtadan o'tuvchi va a(6;4)a vektorga perpendikulyar bo'lgan to'g'ri chiziq tenglamasini toping. A) 3x-2y+2=0 B) 3x-2y-2=0 C) 3x+2y+2=0 D) 3x+2y-2=0 3 / 40 3. Hisoblang: A) 2 B) 3 C) 1 D) 4 4 / 40 4. 275+330 sonini 41 ga bo‘lganda qoladigan qoldiqni aniqlang. A) 5 B) 1 C) 9 D) 0 5 / 40 5. Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 10 B) 8 C) 6√7 D) 4√7 6 / 40 6. Tenglamalar sistemasidan foydalanib x + 3y ni toping. A) 8 B) 6 C) 5 D) 4 7 / 40 7. sonining oxirgi raqamini toping. A) 0 B) 3 C) 1 D) 9 8 / 40 8. Hisoblang. A) 0 B) 2019/2018 C) 1 D) 2019/4036 9 / 40 9. f(f(2)) ni toping. A) 0 B) -1 C) 3 D) 2 10 / 40 10. ABCD parallelogramm va ABED toʻrtburchakka aylana ichki chizilgan. Agar DE=8, AB=12 boʻlsa, BEC uchburchakning perimetrini toping. A) 24 B) 22 C) 25 D) 27 11 / 40 11. x²-20, x+1 va -x-6 manfiy sonlar arifmetik progressiyaning ketma-ket hadlari bo‘lsa, x ni toping. A) -7 B) 7 C) 6 D) -4 12 / 40 12. Hisoblang. A) 5 B) 6 C) 3 D) 4 13 / 40 13. Teng yonli uchburchakning asosi yon tomonidan 15 ga ortiq uchburchakning asosiga tushirilgan balandligi 15 ga teng bo’lsa , uning asosini toping. A) 36 B) 42 C) 20 D) 40 14 / 40 14. bo‘lsa, x· y ni toping. A) 4 B) 1 C) 2 D) 3 15 / 40 15. Agar cos4x = acos4 x + bcos² x +1 bo‘lsa, a+b = ? A) -2 B) 1 C) 0 D) -1 16 / 40 16. Integralni hisoblang: A) 3π/26 B) 3π/16 C) 3π/4 D) 3π/8 17 / 40 17. Agar x= y + 4 bo‘lsa, A) 1 B) 3 C) 2 D) 0 18 / 40 18. Ayirmasi d ga teng bo‘lgan arifmetik progressiya uchun ni toping. A) 1/3 B) 2/3 C) 1/2 D) 1/4 19 / 40 19. Hisoblang: A) 2 B) 11 C) 6 D) 9 20 / 40 20. Agar bo‘lsa, f(1)+f(-1) ni toping. A) 0 B) 2 C) -1 D) 1 21 / 40 21. tenglama ildizlari yig‘indisini toping. A) 1 B) -1 C) 0 D) -2 22 / 40 22. englamaning [0;π ] kesmadagi ildizlari soni 3 tadan ko‘pmi? A) yo'q B) ha 23 / 40 23. tengsizlik nechta butun yechimga ega? A) cheksiz ko‘p B) 2 C) Ø D) 1 24 / 40 24. Hisoblang: A) 129 B) 133 C) 131 D) 132 25 / 40 25. Chizmada nechta parallelogramm bor? A) 16 B) 12 C) 18 D) 24 26 / 40 26. Hisoblang: A) 2019 B) 2022 C) 2021 D) 2020 27 / 40 27. tenglamani yeching. A) 0 B) 1 C) 2 D) 3 28 / 40 28. va bo‘lsa, a ni b orqali ifodalang. A) a=24-5b B) a=18+2b C) a=18-3b D) a=24-3b 29 / 40 29. Chizmada nechta uchburchak tasvirlangan? A) 52 B) 48 C) 64 D) 36 30 / 40 30. tengsizlikni yeching. A) Ø B) (1;1000) C) (0;1)∪(1;1000) D) (0;1000) 31 / 40 31. Agar f (x)-3x-2 bo‘lsa, f(a+b+c)-f(abc)=? Bunda a, b, c – kvadrat funksiya koeffitsiyentlari. A) 10 B) 7 C) 8 D) 9 32 / 40 32. Hisoblang: cos² 10°+ cos² 30°+ cos² 80° A) 2.25 B) 1 C) 1.75 D) 1,5 33 / 40 33. Tenglamani yeching: A) 1 B) 2 C) 4 D) 5 34 / 40 34. bo‘lsa, ni toping. A) 0 B) 1 C) 1.5 D) 2 35 / 40 35. Agar tgx α =4 bo‘lsa, A) 1 B) -47/25 C) 4 D) -2 36 / 40 36. va f(x)=y(x) bo‘lsa, f(5) ni toping. A) 1 B) -5 C) 5 D) -1 37 / 40 37. Agar va ular orasidagi burchak 120o bo‘lsa, ni toping. A) 5 B) 2√7 C) 2√5 D) 7 38 / 40 38. y = xln x funksiya hosilasini toping. A) lnx+1 B) lnx+x C) xx(lnx+1)ln x 1 D) lnx(x+1) 39 / 40 39. |x²-2x|≤xtengsizlikning butun yechimlari yig‘indisini toping. A) 10 B) 15 C) 3 D) 6 40 / 40 40. bo‘lsa, f -1(x) ni toping. Bunda f -1(x)-f(x) ga teskari funksiya. A) 4 B) 3 C) 2 D) 1 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
