Uy » Online olimpiada » Matematika olimpiada » 11-sinf Matematika olimpiada №4 Matematika olimpiadaTuman 2022-2023 o'quv yili 11-sinf Matematika olimpiada №4 InfoMaster Avgust 19, 2024 1086 Ko'rishlar 2 izohlar SaqlashSaqlanganOlib tashlandi 1 0 Savollar 123456789101112131415161718192021222324252627282930 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster 11-sinf Matematika olimpiada №4 2022-yil 12-oktyabr: 2022-2023 o'quv yilida tuman bosqichida tushgan savollar! 1 / 30 1. 2, 3, 4, 5, 6, 7, 8, 9, 10 sonlariga bo‘lganda mos ravishda 1, 2, 3, 4, 5, 6, 7, 8, 9 qoldiqlar hosil bo‘ladigan eng kichik natural sonni toping A) 5039 B) 2519 C) 1519 D) 1019 2 / 30 2. Tenglamani yeching: |x²-3x-2|=x²+3|x+2|+4 A) [2;∞) B) (−∞;−2] C) [−2;0] D) [−2;∞) 3 / 30 3. y=6sin2x+sin12x funksiyaning hosilasini toping. A) 24sin5xcos7x B) 24sin7xsin5x C) −24sin7xcos5x D) 24cos7xcos5x 4 / 30 4. Quyidagi sonlar orasidan musbat sonni aniqlang. A) B B) C C) D D) A 5 / 30 5. Aylananing ОА, ОВ, ОС radiuslari o‘tkazilgan. Agar bo‘lsa, АОВ burchakni toping. A) 90° B) 120° C) 30° D) 60° 6 / 30 6. a2b5 = 620 tenglikni qanoatlantiruvchi nechta (?; ?) butun sonlar juftligi mavjud? A) 14 B) 12 C) 8 D) 10 7 / 30 7. ?(3) ∙ (? − 2) + ?(? − 1) = 3? bo‘lsa, ?(1) ni toping. A) 3 B) 4 C) 2 D) 6 8 / 30 8. ∠CAD = 2∠ACD, AC =13a, BD = 5a va AB = CD bo’lsa, 20⋅cos ∠ACD ni toping.(chizmaga qarang!) A) 16 B) 17 C) 19 D) 15 9 / 30 9. y = x² − 2x + 3 parabolaga y = 3 to‘g‘ri chiziqqa nisbatan simmetrik bo‘lgan parabola tenglamasini tuzing. A) y =-x² + 2x - 3 B) y = x² − 2x - 3 C) y = -x² − 2x + 3 D) y =-x² + 2x + 3 10 / 30 10. Raqamlari yig‘indisi 10 dan kam bo‘lmagan, raqamlari ko‘paytmasi esa 10 dan katta bo‘lmagan uch xonali sonlar nechta? A) 96 B) 106 C) 89 D) 100 11 / 30 11. ? soniga teskari bo‘lgan son ? ning 9% ini tashkil qiladi. ? ni toping. (?u yerda, ? > 0) A) 10/3 B) 13/3 C) 16/3 D) 8/3 12 / 30 12. bo’lsa, P(−1) ni toping. A) 120 B) 100 C) 105 D) 115 13 / 30 13. un ketma-ketlik quyidagicha berilgan: u1 = 1, un+1 = un + 8n. U holda, u50 −u30 ni toping. A) 6320 B) 5320 C) 6320 D) 6230 14 / 30 14. To‘g‘ri burchakli uchburchakning bir burchagi 60° ga teng. Bu burchakdan chiqarilgan bissektrisaning uzunligi 2 m. Uchburchakning gipotenuzasi uzunligini toping. A) √5 B) √5 +1 C) √3 D) 2√3 15 / 30 15. Doskaga ?1, ?2, ?3, . . . , ?200 sonlari yozilgan. Ma’lumki, ?1 = 3, ?2 = 9. Agar ixtiyoriy n natural son uchun ?n+2 = ?n+1 − ?n tenglik o‘rinli bo‘lsa, ?200 ni toping. A) 6 B) 8 C) 9 D) 3 16 / 30 16. Hisoblang: A) B B) A C) C D) D 17 / 30 17. Soatning minut mili 144° ga burilganda, soatning soat mili qanday burchakka burilada? A) 9° B) 18° C) 6° D) 12° 18 / 30 18. BC = BE = CD ,∠DAE = 20°, ∠BCD = 60° ,∠ADE = ? (chizmaga qarang) A) 50° B) 30° C) 20° D) 40° 19 / 30 19. Muntazam uchburchak 36 ta yuzi 1 ga teng bo‘lgan kichkina muntazam uchburchaklardan iborat (chizmaga qarang!). ABC uchburchak yuzini toping. A) 12 B) 11 C) 13 D) 10 20 / 30 20. Tenglamani yeching: A) 10/21 B) 29/462 C) 0 D) ∅ 21 / 30 21. Agar bo‘lsa sin²α ni toping. A) A B) B C) D D) C 22 / 30 22. Uchlari A(2; −3), B(6; −1), C(6; 4) va D(2; 2) nuqtalarda bo‘lgan ABCD to‘rtburchak yuzini toping. A) 16 B) 18 C) 15 D) 20 23 / 30 23. Soddalashtiring: A) D B) B C) A D) C 24 / 30 24. Arifmetik progressiyada ?2 = 12, ?7 − ?4 = 9 bo‘lsa, ?19 ni toping. A) 56 B) 61 C) 54 D) 63 25 / 30 25. Soddalashtiring: bunda, |?| < 1. A) 2-2a B) 2a+4 C) -2 D) 4-2a 26 / 30 26. O‘tkir burchakli uchburchakning ikki tomon uzunliklari ayirmasi 8, bu tomonlarning uchinchi tomondagi proyeksiyalari mos ravishda 8 va 20 ga teng. Berilgan uchburchakka tashqi chizilgan aylana radiusini toping. A) 37/3 B) 85/6 C) 35/3 D) 83/6 27 / 30 27. ABC uchburchakda ctgA+ctgB= 3 va AB= 12 bo‘lsa, ABC uchburchak yuzini toping. A) 216 B) 265 C) 521 D) 123 28 / 30 28. Nargizada 2 ta olma va 3 ta nok bor. U 5 kun ketma-ket har kuni singliga bittadan meva beradi. Bu ishni necha usul bilan amalga oshirish mumkin? A) 12 B) 8 C) 6 D) 10 29 / 30 29. Tengsizliklar sistemasinining butun yechimlari sonini toping. A) 5 B) 6 C) 4 D) 7 30 / 30 30. Natural son roppa-rosa 2 ta tub bo‘luvchiga, bu sonning kvadrati esa 45 ta turli natural bo‘luvchiga ega. Berilgan sonning kubi eng ko‘pi bilan nechta natural bo‘luvchiga ega bo‘lishi mumkin? A) 81 B) 41 C) 91 D) 40 0% Author: InfoMaster Foydali bo'lsa mamnunmiz