Uy » Online olimpiada » Matematika olimpiada » 10-sinf Matematika olimpiada №3 Matematika olimpiadaViloyat 2021-2022 o'quv yili 10-sinf Matematika olimpiada №3 InfoMaster Avgust 19, 2024 13 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0 12345678910111213141516171819202122232425 Vaqtingiz tugadi! 10-sinf Matematika olimpiada №3 2021-2022 o'quv yili viloyat bosqichida tushgan savollar. 1 / 25 1. Hisoblang: A) 1 B) -1 C) 2 D) -0,5 2 / 25 2. Ko`paytmani hisoblang. cos12°cos24°cos36°cos48°cos60°cos72°cos84° A) 1/128 B) 1/64 C) 1/16 D) 1/32 3 / 25 3. ?² + |? − 3| ≤ |?2 + ?| − 3 tengsizlikni yeching. A) x<0 B) 3 ≤ x C) x ≤ 3 D) x>3 4 / 25 4. Uchburchak tomonlarining uzunliklari berilgan tenglamaning ildizlariga mos keladi. ?³ − 24?² + 183? − 440 = 0. Uchburchakning yuzini hisoblang. A) 4√21 B) 2√21 C) √21 D) 35 5 / 25 5. ?(?) = ?5 − 7?4 + 3?3 − ? + 2 ko‘phadni ?2 + ? ga bo‘lgandagi qoldiqni aniqlang. A) 4? + 2 B) 10? + 2 C) 6? + 2 D) 8? + 2 6 / 25 6. 102022 − 22021 ayirmani 24 ga bo‘lgandagi qoldiqni toping. A) 8 B) 0 C) 16 D) 12 7 / 25 7. Agar ni toping. A) 0.96 B) 0.81 C) 0.8 D) 0.9 8 / 25 8. ?/? kasr (?, ? −natural sonlar)— qisqarmas kasr va (7?+6?)/(3?+2?) kasr esa qisqaradi. Ushbu kasr qanday songa qisqaradi? A) 2 B) 3 C) 5 D) 8 9 / 25 9. Tenglamalar sistemasi nechta yechimga ega? A) 12 B) 10 C) 6 D) 8 10 / 25 10. Tenglama nechta yechimga ega? A) 4 B) 2 C) 5 D) 3 11 / 25 11. ABCD to‘rtburchakda АВ = CD = 9 va bu to‘rtburchakka radiusi 4 ga teng aylana ichki chizilgan. ABCD to‘rtburchak yuzini toping. A) 72 B) 36 C) 81 D) 144 12 / 25 12. Agar cos ∠A = 1/5 va sin∠B = 1/2 bo‘lsa, АВС uchburchakning mos ravishda А va В uchlaridan tushirilgan balandliklar nisbatini toping. A) 5√3/12 B) 2/5 C) 5√6/24 D) 5√2/5 13 / 25 13. ABC uchburchakning AC tomonida D nuqta olingan, bunda ∠ABC = ∠BDC. Agar AD = 10, CD = 8 bo‘lsa, BC ni toping. A) 9 B) 12 C) 10 D) 15 14 / 25 14. Agar A) 0 B) 3π/2 C) π D) π/2 15 / 25 15. ?(? − 1) = 2?(5? + 4) va ?(2? − 1) = 4? + 4 bo‘lsa, ?(?) ni toping A) 0 B) 20x+48 C) x+25 D) 20x+50 16 / 25 16. ABCD to‘rtburchakda А va В burchaklar- to‘g‘ri, tg∠D = 3/4 va ВС = AD/2 = АВ + 2 bo‘lsa, АС ni toping. A) 10 B) 15 C) 9 D) 8 17 / 25 17. Ayirmasi noldan farqli bo‘lgan arifmetik progressiyaning 4-hadidan boshlab 14- hadigacha bo‘lgan hadlar yig‘indisi 77 ga teng. Progressiyaning 7 ga teng bo‘lgan had nomerini toping. A) 8 B) 11 C) 9 D) 10 18 / 25 18. ABC – gipotenuzasi AB bo‘lgan to‘g‘ri burchakli uchburchak. Gipotenuzaning ikki tomon davomida AB to‘g‘ri chiziqda AK = AC va BM = BC shartlar bilan kesmalar ajratilgan. KCM burchakni toping. A) 135° B) 150° C) 120° D) 90° 19 / 25 19. Qavariq to‘rtburchakning diagonallari 3 va 4 ga teng. Agar qarama qarshi tomonlarining o‘rtalarini tutashtirishdan hosil bo‘lgan kesmalar uzunliklari o‘zaro teng bo‘lsa, qavariq to‘rtburchakning yuzini toping. A) 7 B) 8 C) 6 D) 5 20 / 25 20. a,b,c−ABC uchburchakning tomonlari. Agar a4 + b4 + c4 + 32 = 2(a²b² + b²c² + a²c²) bo‘lsa, ABC uchburchak yuzini toping. A) 2√2 B) √2 C) √3 D) 1 21 / 25 21. bo‘lsa ? ning qiymatini toping. A) 37 B) 12 C) 25 D) 40 22 / 25 22. englikni qanoatlantiradigan ? ning eng kichik qiymatini toping. A) -1 B) 0 C) 1 D) 3 23 / 25 23. tenglama nechta yechimga ega, agar x ∈ (0; 50)? A) 14 B) 17 C) 15 D) 16 24 / 25 24. Agar bo‘lsa, |xyz| ni toping. A) 100 B) 500 C) 1000 D) 800 25 / 25 25. (?² − 2? + 3)(?² + 6? + 12) = 6 bo‘lsa, ? + ? ni toping. A) 3 B) -2 C) 2 D) -3 0% Testni qayta ishga tushiring Tomonidan Wordpress Quiz plugin Author: InfoMaster Foydali bo'lsa mamnunmiz
