Uy » Online olimpiada » Matematika olimpiada » 10-sinf Matematika olimpiada №3 Matematika olimpiadaViloyat 2021-2022 o'quv yili 10-sinf Matematika olimpiada №3 InfoMaster Avgust 19, 2024 38 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0 12345678910111213141516171819202122232425 Vaqtingiz tugadi! 10-sinf Matematika olimpiada №3 2021-2022 o'quv yili viloyat bosqichida tushgan savollar. 1 / 25 1. Hisoblang: A) 2 B) -0,5 C) 1 D) -1 2 / 25 2. Tenglamaning ildizini nimchoragi nechaga teng ? A) 0,5 B) 0,125 C) 20/69 D) 0,25 3 / 25 3. a,b,c−ABC uchburchakning tomonlari. Agar a4 + b4 + c4 + 32 = 2(a²b² + b²c² + a²c²) bo‘lsa, ABC uchburchak yuzini toping. A) 2√2 B) √3 C) 1 D) √2 4 / 25 4. ABCD to‘rtburchakda АВ = CD = 9 va bu to‘rtburchakka radiusi 4 ga teng aylana ichki chizilgan. ABCD to‘rtburchak yuzini toping. A) 144 B) 81 C) 72 D) 36 5 / 25 5. bo‘lsa ? ning qiymatini toping. A) 37 B) 40 C) 12 D) 25 6 / 25 6. Tenglamani yeching: 3x+3 + 8·3x+2 = 33 A) 0 B) 1 C) -1 D) -2 7 / 25 7. Agar bo‘lsa, ?(0) − ?(5) ayirmani toping. A) -26 B) -27 C) -25 D) -24 8 / 25 8. ?² + |? − 3| ≤ |?2 + ?| − 3 tengsizlikni yeching. A) x>3 B) x ≤ 3 C) x<0 D) 3 ≤ x 9 / 25 9. tenglama nechta yechimga ega, agar x ∈ (0; 50)? A) 17 B) 15 C) 16 D) 14 10 / 25 10. Uchburchak tomonlarining uzunliklari berilgan tenglamaning ildizlariga mos keladi. ?³ − 24?² + 183? − 440 = 0. Uchburchakning yuzini hisoblang. A) 4√21 B) 2√21 C) √21 D) 35 11 / 25 11. ABC – gipotenuzasi AB bo‘lgan to‘g‘ri burchakli uchburchak. Gipotenuzaning ikki tomon davomida AB to‘g‘ri chiziqda AK = AC va BM = BC shartlar bilan kesmalar ajratilgan. KCM burchakni toping. A) 90° B) 150° C) 135° D) 120° 12 / 25 12. ABC uchburchakning AC tomonida D nuqta olingan, bunda ∠ABC = ∠BDC. Agar AD = 10, CD = 8 bo‘lsa, BC ni toping. A) 15 B) 10 C) 9 D) 12 13 / 25 13. Agar A) 0 B) π/2 C) 3π/2 D) π 14 / 25 14. englikni qanoatlantiradigan ? ning eng kichik qiymatini toping. A) -1 B) 3 C) 0 D) 1 15 / 25 15. Agar ? > 0, ? + ?² = 7,25; ?² − ? = 2 va ?² = √(? − 1) ∙ √(2 − ?) bo‘lsa, ?(√(? − 1) + √(2 − ?)) ning qiymatini toping. A) 6 B) 5 C) 7 D) 4 16 / 25 16. Agar bo‘lsa, |xyz| ni toping. A) 100 B) 500 C) 800 D) 1000 17 / 25 17. ?(?) = ?5 − 7?4 + 3?3 − ? + 2 ko‘phadni ?2 + ? ga bo‘lgandagi qoldiqni aniqlang. A) 10? + 2 B) 8? + 2 C) 4? + 2 D) 6? + 2 18 / 25 18. Soddalashtiring: (4cos² 9° −3)(4cos² 27° −3)·ctg9° A) sin18° B) tg9° C) 1 D) 2cos² 9° 19 / 25 19. Tenglama nechta yechimga ega? A) 5 B) 4 C) 3 D) 2 20 / 25 20. Qavariq to‘rtburchakning diagonallari 3 va 4 ga teng. Agar qarama qarshi tomonlarining o‘rtalarini tutashtirishdan hosil bo‘lgan kesmalar uzunliklari o‘zaro teng bo‘lsa, qavariq to‘rtburchakning yuzini toping. A) 8 B) 6 C) 7 D) 5 21 / 25 21. Ayirmasi noldan farqli bo‘lgan arifmetik progressiyaning 4-hadidan boshlab 14- hadigacha bo‘lgan hadlar yig‘indisi 77 ga teng. Progressiyaning 7 ga teng bo‘lgan had nomerini toping. A) 11 B) 9 C) 10 D) 8 22 / 25 22. (?² − 2? + 3)(?² + 6? + 12) = 6 bo‘lsa, ? + ? ni toping. A) -3 B) 3 C) 2 D) -2 23 / 25 23. ?(? − 1) = 2?(5? + 4) va ?(2? − 1) = 4? + 4 bo‘lsa, ?(?) ni toping A) 20x+50 B) x+25 C) 20x+48 D) 0 24 / 25 24. ABCD to‘rtburchakda А va В burchaklar- to‘g‘ri, tg∠D = 3/4 va ВС = AD/2 = АВ + 2 bo‘lsa, АС ni toping. A) 8 B) 10 C) 15 D) 9 25 / 25 25. Agar ?1 = 6? − 6 va у2//?1 hamda у2 to‘g‘ri chiziq ?(6; 6) nuqtadan o‘tsa, ?2 ni toping. A) −6? + 6 B) 6? − 24 C) 6? − 30 D) −6? + 42 0% Testni qayta ishga tushiring Author: InfoMaster Foydali bo'lsa mamnunmiz
