Uy » Online olimpiada » Matematika olimpiada » 10-sinf Matematika olimpiada №3 Matematika olimpiadaViloyat 2021-2022 o'quv yili 10-sinf Matematika olimpiada №3 InfoMaster Avgust 19, 2024 2 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0 12345678910111213141516171819202122232425 Vaqtingiz tugadi! 10-sinf Matematika olimpiada №3 2021-2022 o'quv yili viloyat bosqichida tushgan savollar. 1 / 25 1. tenglamaning ildizi qaysi oraliqda joylashgan? A) [2;4] B) [0;2] C) [4;9] D) [-2;0] 2 / 25 2. Uchburchakning ikkita burchagi mos ravishda 38o va 52oga teng. Uchinchi burchagi uchidan tushirilgan bissektrisa va mediana orasidagi burchakni toping. A) 17° B) 10° C) 7° D) 14° 3 / 25 3. Soddalashtiring: (4cos² 9° −3)(4cos² 27° −3)·ctg9° A) 2cos² 9° B) 1 C) sin18° D) tg9° 4 / 25 4. Tenglamani yeching: 3x+3 + 8·3x+2 = 33 A) -1 B) -2 C) 1 D) 0 5 / 25 5. x, y sonlari (x² + 1)(y² + 1) + 2(x − y)(1 − xy) = 4(1 + xy) tenglikni qanoatlantiradi |1 + x| ∙ |1 − y| ni toping. A) 3 B) 9 C) 2 D) 1 6 / 25 6. Agar ? > 0, ? + ?² = 7,25; ?² − ? = 2 va ?² = √(? − 1) ∙ √(2 − ?) bo‘lsa, ?(√(? − 1) + √(2 − ?)) ning qiymatini toping. A) 5 B) 6 C) 7 D) 4 7 / 25 7. ?² + |? − 3| ≤ |?2 + ?| − 3 tengsizlikni yeching. A) x<0 B) x ≤ 3 C) x>3 D) 3 ≤ x 8 / 25 8. Agar bo‘lsa, |xyz| ni toping. A) 800 B) 1000 C) 500 D) 100 9 / 25 9. ABCD to‘rtburchakda АВ = CD = 9 va bu to‘rtburchakka radiusi 4 ga teng aylana ichki chizilgan. ABCD to‘rtburchak yuzini toping. A) 36 B) 72 C) 81 D) 144 10 / 25 10. ABCD to‘rtburchakda А va В burchaklar- to‘g‘ri, tg∠D = 3/4 va ВС = AD/2 = АВ + 2 bo‘lsa, АС ni toping. A) 15 B) 10 C) 8 D) 9 11 / 25 11. Tenglama nechta yechimga ega? A) 5 B) 3 C) 2 D) 4 12 / 25 12. Agar cos ∠A = 1/5 va sin∠B = 1/2 bo‘lsa, АВС uchburchakning mos ravishda А va В uchlaridan tushirilgan balandliklar nisbatini toping. A) 5√3/12 B) 5√2/5 C) 2/5 D) 5√6/24 13 / 25 13. (?² − 2? + 3)(?² + 6? + 12) = 6 bo‘lsa, ? + ? ni toping. A) 2 B) -2 C) 3 D) -3 14 / 25 14. ABC uchburchakning AC tomonida D nuqta olingan, bunda ∠ABC = ∠BDC. Agar AD = 10, CD = 8 bo‘lsa, BC ni toping. A) 9 B) 10 C) 12 D) 15 15 / 25 15. 102022 − 22021 ayirmani 24 ga bo‘lgandagi qoldiqni toping. A) 8 B) 16 C) 12 D) 0 16 / 25 16. ABC – gipotenuzasi AB bo‘lgan to‘g‘ri burchakli uchburchak. Gipotenuzaning ikki tomon davomida AB to‘g‘ri chiziqda AK = AC va BM = BC shartlar bilan kesmalar ajratilgan. KCM burchakni toping. A) 135° B) 90° C) 120° D) 150° 17 / 25 17. bo‘lsa ? ning qiymatini toping. A) 12 B) 37 C) 25 D) 40 18 / 25 18. Uchburchak tomonlarining uzunliklari berilgan tenglamaning ildizlariga mos keladi. ?³ − 24?² + 183? − 440 = 0. Uchburchakning yuzini hisoblang. A) 4√21 B) 2√21 C) √21 D) 35 19 / 25 19. ?(? − 1) = 2?(5? + 4) va ?(2? − 1) = 4? + 4 bo‘lsa, ?(?) ni toping A) 0 B) 20x+50 C) 20x+48 D) x+25 20 / 25 20. Agar A) 0 B) 3π/2 C) π/2 D) π 21 / 25 21. Qavariq to‘rtburchakning diagonallari 3 va 4 ga teng. Agar qarama qarshi tomonlarining o‘rtalarini tutashtirishdan hosil bo‘lgan kesmalar uzunliklari o‘zaro teng bo‘lsa, qavariq to‘rtburchakning yuzini toping. A) 6 B) 7 C) 8 D) 5 22 / 25 22. Agar ni toping. A) 0.81 B) 0.9 C) 0.96 D) 0.8 23 / 25 23. englikni qanoatlantiradigan ? ning eng kichik qiymatini toping. A) 3 B) 1 C) -1 D) 0 24 / 25 24. Agar ?1 = 6? − 6 va у2//?1 hamda у2 to‘g‘ri chiziq ?(6; 6) nuqtadan o‘tsa, ?2 ni toping. A) −6? + 42 B) −6? + 6 C) 6? − 24 D) 6? − 30 25 / 25 25. Agar bo‘lsa, ?(0) − ?(5) ayirmani toping. A) -26 B) -24 C) -25 D) -27 0% Testni qayta ishga tushiring Tomonidan Wordpress Quiz plugin Author: InfoMaster Foydali bo'lsa mamnunmiz
