Uy » Online olimpiada » Matematika olimpiada » 10-sinf Matematika olimpiada №3 Matematika olimpiadaViloyat 2021-2022 o'quv yili 10-sinf Matematika olimpiada №3 InfoMaster Avgust 19, 2024 26 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0 12345678910111213141516171819202122232425 Vaqtingiz tugadi! 10-sinf Matematika olimpiada №3 2021-2022 o'quv yili viloyat bosqichida tushgan savollar. 1 / 25 1. Agar ikki xonali sonning o‘ng tomoniga 6 raqami yozib qo‘yilsa, berilgan sonning yarmi bilan 500 ning yig‘indisiga teng son hosil bo‘ladi. Bu qanday ikki xonali son? A) 30 B) 60 C) 43 D) 52 2 / 25 2. Ta`lim muassasida barcha o`quvchilar kamida bitta ingliz yoki nemis tilida so`zlashа oladilar. Ayrimlari ikkala tilni ham biladilar. O`quvchilarning 85%i ingliz tilini, 75%i nemis tilini biladilar. Ikkala tilni ham biladigan o`quvchilar barcha o`quvchilarning necha % ini tashkil etadi. A) 50% B) 70% C) 60% D) 65% 3 / 25 3. Agar ?1 = 6? − 6 va у2//?1 hamda у2 to‘g‘ri chiziq ?(6; 6) nuqtadan o‘tsa, ?2 ni toping. A) 6? − 30 B) −6? + 6 C) 6? − 24 D) −6? + 42 4 / 25 4. Agar bo‘lsa, |xyz| ni toping. A) 100 B) 500 C) 800 D) 1000 5 / 25 5. Agar bo‘lsa, ?(0) − ?(5) ayirmani toping. A) -27 B) -24 C) -25 D) -26 6 / 25 6. ABC – gipotenuzasi AB bo‘lgan to‘g‘ri burchakli uchburchak. Gipotenuzaning ikki tomon davomida AB to‘g‘ri chiziqda AK = AC va BM = BC shartlar bilan kesmalar ajratilgan. KCM burchakni toping. A) 135° B) 120° C) 150° D) 90° 7 / 25 7. ?/? kasr (?, ? −natural sonlar)— qisqarmas kasr va (7?+6?)/(3?+2?) kasr esa qisqaradi. Ushbu kasr qanday songa qisqaradi? A) 3 B) 8 C) 2 D) 5 8 / 25 8. Agar ni toping. A) 0.8 B) 0.96 C) 0.9 D) 0.81 9 / 25 9. Agar cos ∠A = 1/5 va sin∠B = 1/2 bo‘lsa, АВС uchburchakning mos ravishda А va В uchlaridan tushirilgan balandliklar nisbatini toping. A) 5√3/12 B) 5√6/24 C) 2/5 D) 5√2/5 10 / 25 10. 102022 − 22021 ayirmani 24 ga bo‘lgandagi qoldiqni toping. A) 8 B) 12 C) 0 D) 16 11 / 25 11. Qavariq to‘rtburchakning diagonallari 3 va 4 ga teng. Agar qarama qarshi tomonlarining o‘rtalarini tutashtirishdan hosil bo‘lgan kesmalar uzunliklari o‘zaro teng bo‘lsa, qavariq to‘rtburchakning yuzini toping. A) 6 B) 8 C) 5 D) 7 12 / 25 12. englikni qanoatlantiradigan ? ning eng kichik qiymatini toping. A) 0 B) -1 C) 1 D) 3 13 / 25 13. Tenglama nechta yechimga ega? A) 5 B) 4 C) 2 D) 3 14 / 25 14. Agar A) 0 B) 3π/2 C) π/2 D) π 15 / 25 15. Agar ? > 0, ? + ?² = 7,25; ?² − ? = 2 va ?² = √(? − 1) ∙ √(2 − ?) bo‘lsa, ?(√(? − 1) + √(2 − ?)) ning qiymatini toping. A) 4 B) 6 C) 5 D) 7 16 / 25 16. (?² − 2? + 3)(?² + 6? + 12) = 6 bo‘lsa, ? + ? ni toping. A) 3 B) -2 C) 2 D) -3 17 / 25 17. ABCD to‘rtburchakda АВ = CD = 9 va bu to‘rtburchakka radiusi 4 ga teng aylana ichki chizilgan. ABCD to‘rtburchak yuzini toping. A) 144 B) 72 C) 36 D) 81 18 / 25 18. Uchburchak tomonlarining uzunliklari berilgan tenglamaning ildizlariga mos keladi. ?³ − 24?² + 183? − 440 = 0. Uchburchakning yuzini hisoblang. A) 2√21 B) 35 C) 4√21 D) √21 19 / 25 19. Ayirmasi noldan farqli bo‘lgan arifmetik progressiyaning 4-hadidan boshlab 14- hadigacha bo‘lgan hadlar yig‘indisi 77 ga teng. Progressiyaning 7 ga teng bo‘lgan had nomerini toping. A) 11 B) 9 C) 8 D) 10 20 / 25 20. ABC uchburchakning AC tomonida D nuqta olingan, bunda ∠ABC = ∠BDC. Agar AD = 10, CD = 8 bo‘lsa, BC ni toping. A) 12 B) 9 C) 10 D) 15 21 / 25 21. a,b,c−ABC uchburchakning tomonlari. Agar a4 + b4 + c4 + 32 = 2(a²b² + b²c² + a²c²) bo‘lsa, ABC uchburchak yuzini toping. A) 1 B) √3 C) 2√2 D) √2 22 / 25 22. Soddalashtiring: (4cos² 9° −3)(4cos² 27° −3)·ctg9° A) 2cos² 9° B) 1 C) tg9° D) sin18° 23 / 25 23. ABCD to‘rtburchakda А va В burchaklar- to‘g‘ri, tg∠D = 3/4 va ВС = AD/2 = АВ + 2 bo‘lsa, АС ni toping. A) 9 B) 10 C) 8 D) 15 24 / 25 24. bo‘lsa ? ning qiymatini toping. A) 40 B) 37 C) 12 D) 25 25 / 25 25. Tenglamalar sistemasi nechta yechimga ega? A) 8 B) 6 C) 10 D) 12 0% Testni qayta ishga tushiring Tomonidan Wordpress Quiz plugin Author: InfoMaster Foydali bo'lsa mamnunmiz
