10-sinf Matematika olimpiada №3 Oktabr 3, 2022Avgust 19, 2024 da chop etilgan InfoMaster tomonidan 10-sinf Matematika olimpiada №3 ga 1 fikr bildirilgan 0 12345678910111213141516171819202122232425 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster 10-sinf Matematika olimpiada №3 2021-2022 o'quv yili viloyat bosqichida tushgan savollar. 1 / 25 1. Hisoblang: A) 1 B) 4 C) 3 D) 2 2 / 25 2. Korxona xom−ashyuo qimmatlashgani sababli maxsulot narxi 20% ga oshirildi, biroq mijojlar soni 20 % ga kamayib ketdi. Shunda korxona narxni qanchadir foizga kamaytirib mijozlari sonini 25% ga oshirishga erishdi. Shundan keyin korxona tushumi narx o`zgarmasdan oldingi tushumga qaraganda 8% ga oshgan bo`lsa, yangi narx necha foizga kamaytirilgan? A) 10 B) 4 C) 20 D) 12 3 / 25 3. Agar ?1 = 6? − 6 va у2//?1 hamda у2 to‘g‘ri chiziq ?(6; 6) nuqtadan o‘tsa, ?2 ni toping. A) −6? + 6 B) 6? − 24 C) −6? + 42 D) 6? − 30 4 / 25 4. Uchburchak tomonlarining uzunliklari berilgan tenglamaning ildizlariga mos keladi. ?³ − 24?² + 183? − 440 = 0. Uchburchakning yuzini hisoblang. A) √21 B) 35 C) 4√21 D) 2√21 5 / 25 5. ABCD to‘rtburchakda АВ = CD = 9 va bu to‘rtburchakka radiusi 4 ga teng aylana ichki chizilgan. ABCD to‘rtburchak yuzini toping. A) 72 B) 36 C) 144 D) 81 6 / 25 6. bo‘lsa ? ning qiymatini toping. A) 37 B) 40 C) 25 D) 12 7 / 25 7. Agar A) 3π/2 B) π/2 C) 0 D) π 8 / 25 8. tenglama nechta yechimga ega, agar x ∈ (0; 50)? A) 15 B) 17 C) 14 D) 16 9 / 25 9. Agar ni toping. A) 0.9 B) 0.96 C) 0.8 D) 0.81 10 / 25 10. englikni qanoatlantiradigan ? ning eng kichik qiymatini toping. A) 1 B) 3 C) 0 D) -1 11 / 25 11. Ayirmasi noldan farqli bo‘lgan arifmetik progressiyaning 4-hadidan boshlab 14- hadigacha bo‘lgan hadlar yig‘indisi 77 ga teng. Progressiyaning 7 ga teng bo‘lgan had nomerini toping. A) 8 B) 9 C) 10 D) 11 12 / 25 12. ?(?) = ?5 − 7?4 + 3?3 − ? + 2 ko‘phadni ?2 + ? ga bo‘lgandagi qoldiqni aniqlang. A) 4? + 2 B) 8? + 2 C) 10? + 2 D) 6? + 2 13 / 25 13. ABCD to‘rtburchakda А va В burchaklar- to‘g‘ri, tg∠D = 3/4 va ВС = AD/2 = АВ + 2 bo‘lsa, АС ni toping. A) 15 B) 8 C) 9 D) 10 14 / 25 14. Agar bo‘lsa, ?(0) − ?(5) ayirmani toping. A) -26 B) -27 C) -24 D) -25 15 / 25 15. ?² + |? − 3| ≤ |?2 + ?| − 3 tengsizlikni yeching. A) x>3 B) 3 ≤ x C) x<0 D) x ≤ 3 16 / 25 16. (?² − 2? + 3)(?² + 6? + 12) = 6 bo‘lsa, ? + ? ni toping. A) 2 B) 3 C) -2 D) -3 17 / 25 17. Tenglama nechta yechimga ega? A) 2 B) 3 C) 5 D) 4 18 / 25 18. Qavariq to‘rtburchakning diagonallari 3 va 4 ga teng. Agar qarama qarshi tomonlarining o‘rtalarini tutashtirishdan hosil bo‘lgan kesmalar uzunliklari o‘zaro teng bo‘lsa, qavariq to‘rtburchakning yuzini toping. A) 8 B) 6 C) 5 D) 7 19 / 25 19. ?/? kasr (?, ? −natural sonlar)— qisqarmas kasr va (7?+6?)/(3?+2?) kasr esa qisqaradi. Ushbu kasr qanday songa qisqaradi? A) 5 B) 2 C) 8 D) 3 20 / 25 20. 102022 − 22021 ayirmani 24 ga bo‘lgandagi qoldiqni toping. A) 16 B) 8 C) 0 D) 12 21 / 25 21. ?(? − 1) = 2?(5? + 4) va ?(2? − 1) = 4? + 4 bo‘lsa, ?(?) ni toping A) 20x+50 B) 20x+48 C) 0 D) x+25 22 / 25 22. Agar cos ∠A = 1/5 va sin∠B = 1/2 bo‘lsa, АВС uchburchakning mos ravishda А va В uchlaridan tushirilgan balandliklar nisbatini toping. A) 5√6/24 B) 5√3/12 C) 5√2/5 D) 2/5 23 / 25 23. Agar bo‘lsa, |xyz| ni toping. A) 500 B) 800 C) 1000 D) 100 24 / 25 24. x, y sonlari (x² + 1)(y² + 1) + 2(x − y)(1 − xy) = 4(1 + xy) tenglikni qanoatlantiradi |1 + x| ∙ |1 − y| ni toping. A) 3 B) 9 C) 1 D) 2 25 / 25 25. Soddalashtiring: (4cos² 9° −3)(4cos² 27° −3)·ctg9° A) sin18° B) 2cos² 9° C) tg9° D) 1 0% Testni qayta ishga tushiring tomonidan Wordpress Quiz plugin Matematika olimpiada, Viloyat 2021-2022 o'quv yili
