Uy » Online olimpiada » Matematika olimpiada » 10-sinf Matematika olimpiada №3 Matematika olimpiadaViloyat 2021-2022 o'quv yili 10-sinf Matematika olimpiada №3 InfoMaster Avgust 19, 2024 49 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0 12345678910111213141516171819202122232425 Vaqtingiz tugadi! 10-sinf Matematika olimpiada №3 2021-2022 o'quv yili viloyat bosqichida tushgan savollar. 1 / 25 1. a ning qanday qiymatlarida kvadrat tenglamaning ildizlari yig‘indisi manfiy bo‘ladi? A) a<1 B) 0<a<1 C) 0<a<2 D) a<0 2 / 25 2. Agar f(x+1) =7+3x funksiya uchun f (a)=2 tenglik o`rinli bo`lsa, a ning qiymatini toping. A) 10 B) 8 C) -2/3 D) 12 3 / 25 3. ?(? − 1) = 2?(5? + 4) va ?(2? − 1) = 4? + 4 bo‘lsa, ?(?) ni toping A) 20x+50 B) x+25 C) 20x+48 D) 0 4 / 25 4. ABCD to‘rtburchakda А va В burchaklar- to‘g‘ri, tg∠D = 3/4 va ВС = AD/2 = АВ + 2 bo‘lsa, АС ni toping. A) 8 B) 10 C) 9 D) 15 5 / 25 5. Agar ni toping. A) 0.81 B) 0.9 C) 0.96 D) 0.8 6 / 25 6. ABCD to‘rtburchakda АВ = CD = 9 va bu to‘rtburchakka radiusi 4 ga teng aylana ichki chizilgan. ABCD to‘rtburchak yuzini toping. A) 81 B) 36 C) 72 D) 144 7 / 25 7. Agar bo‘lsa, |xyz| ni toping. A) 500 B) 100 C) 1000 D) 800 8 / 25 8. Tenglamani yeching: 3x+3 + 8·3x+2 = 33 A) -1 B) 0 C) 1 D) -2 9 / 25 9. (?² − 2? + 3)(?² + 6? + 12) = 6 bo‘lsa, ? + ? ni toping. A) 2 B) -2 C) -3 D) 3 10 / 25 10. ?² + |? − 3| ≤ |?2 + ?| − 3 tengsizlikni yeching. A) x<0 B) 3 ≤ x C) x ≤ 3 D) x>3 11 / 25 11. tenglama nechta yechimga ega, agar x ∈ (0; 50)? A) 15 B) 17 C) 14 D) 16 12 / 25 12. Soddalashtiring: (4cos² 9° −3)(4cos² 27° −3)·ctg9° A) tg9° B) 1 C) sin18° D) 2cos² 9° 13 / 25 13. Agar A) 3π/2 B) 0 C) π/2 D) π 14 / 25 14. Qavariq to‘rtburchakning diagonallari 3 va 4 ga teng. Agar qarama qarshi tomonlarining o‘rtalarini tutashtirishdan hosil bo‘lgan kesmalar uzunliklari o‘zaro teng bo‘lsa, qavariq to‘rtburchakning yuzini toping. A) 7 B) 5 C) 6 D) 8 15 / 25 15. bo‘lsa ? ning qiymatini toping. A) 37 B) 40 C) 25 D) 12 16 / 25 16. a,b,c−ABC uchburchakning tomonlari. Agar a4 + b4 + c4 + 32 = 2(a²b² + b²c² + a²c²) bo‘lsa, ABC uchburchak yuzini toping. A) √2 B) √3 C) 2√2 D) 1 17 / 25 17. englikni qanoatlantiradigan ? ning eng kichik qiymatini toping. A) 1 B) 3 C) -1 D) 0 18 / 25 18. ABC uchburchakning AC tomonida D nuqta olingan, bunda ∠ABC = ∠BDC. Agar AD = 10, CD = 8 bo‘lsa, BC ni toping. A) 12 B) 10 C) 9 D) 15 19 / 25 19. Uchburchak tomonlarining uzunliklari berilgan tenglamaning ildizlariga mos keladi. ?³ − 24?² + 183? − 440 = 0. Uchburchakning yuzini hisoblang. A) 2√21 B) 4√21 C) √21 D) 35 20 / 25 20. ABC – gipotenuzasi AB bo‘lgan to‘g‘ri burchakli uchburchak. Gipotenuzaning ikki tomon davomida AB to‘g‘ri chiziqda AK = AC va BM = BC shartlar bilan kesmalar ajratilgan. KCM burchakni toping. A) 135° B) 120° C) 150° D) 90° 21 / 25 21. Tenglamalar sistemasi nechta yechimga ega? A) 12 B) 10 C) 6 D) 8 22 / 25 22. Tenglama nechta yechimga ega? A) 4 B) 2 C) 3 D) 5 23 / 25 23. ?/? kasr (?, ? −natural sonlar)— qisqarmas kasr va (7?+6?)/(3?+2?) kasr esa qisqaradi. Ushbu kasr qanday songa qisqaradi? A) 3 B) 8 C) 2 D) 5 24 / 25 24. Agar ? > 0, ? + ?² = 7,25; ?² − ? = 2 va ?² = √(? − 1) ∙ √(2 − ?) bo‘lsa, ?(√(? − 1) + √(2 − ?)) ning qiymatini toping. A) 7 B) 4 C) 6 D) 5 25 / 25 25. Agar ?1 = 6? − 6 va у2//?1 hamda у2 to‘g‘ri chiziq ?(6; 6) nuqtadan o‘tsa, ?2 ni toping. A) 6? − 24 B) −6? + 42 C) 6? − 30 D) −6? + 6 0% Testni qayta ishga tushiring Author: InfoMaster Foydali bo'lsa mamnunmiz
