Uy » Online olimpiada » Matematika olimpiada » 10-sinf Matematika olimpiada №3 Matematika olimpiadaViloyat 2021-2022 o'quv yili 10-sinf Matematika olimpiada №3 InfoMaster Avgust 19, 2024 1 Ko'rish 1 izoh SaqlashSaqlanganOlib tashlandi 0 0 12345678910111213141516171819202122232425 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster 10-sinf Matematika olimpiada №3 2021-2022 o'quv yili viloyat bosqichida tushgan savollar. 1 / 25 1. Tenglama ildizlarining o‘rta arifmetik qiymatini toping: A) 1 B) 3 C) 5 D) 2 2 / 25 2. trigonometrik tenglamani yeching. A) π/6+πk; k∈Z B) π/12+2πk; k∈Z C) π/12+πk; k∈Z D) π/12+πk/2; k∈Z 3 / 25 3. a,b,c−ABC uchburchakning tomonlari. Agar a4 + b4 + c4 + 32 = 2(a²b² + b²c² + a²c²) bo‘lsa, ABC uchburchak yuzini toping. A) 1 B) √2 C) 2√2 D) √3 4 / 25 4. englikni qanoatlantiradigan ? ning eng kichik qiymatini toping. A) 3 B) 0 C) -1 D) 1 5 / 25 5. bo‘lsa ? ning qiymatini toping. A) 12 B) 37 C) 40 D) 25 6 / 25 6. tenglama nechta yechimga ega, agar x ∈ (0; 50)? A) 16 B) 14 C) 17 D) 15 7 / 25 7. ABCD to‘rtburchakda АВ = CD = 9 va bu to‘rtburchakka radiusi 4 ga teng aylana ichki chizilgan. ABCD to‘rtburchak yuzini toping. A) 144 B) 36 C) 72 D) 81 8 / 25 8. Agar ni toping. A) 0.9 B) 0.96 C) 0.8 D) 0.81 9 / 25 9. Agar cos ∠A = 1/5 va sin∠B = 1/2 bo‘lsa, АВС uchburchakning mos ravishda А va В uchlaridan tushirilgan balandliklar nisbatini toping. A) 5√6/24 B) 5√3/12 C) 2/5 D) 5√2/5 10 / 25 10. ?² + |? − 3| ≤ |?2 + ?| − 3 tengsizlikni yeching. A) x>3 B) x<0 C) 3 ≤ x D) x ≤ 3 11 / 25 11. Tenglamani yeching: 3x+3 + 8·3x+2 = 33 A) 1 B) -2 C) 0 D) -1 12 / 25 12. Uchburchak tomonlarining uzunliklari berilgan tenglamaning ildizlariga mos keladi. ?³ − 24?² + 183? − 440 = 0. Uchburchakning yuzini hisoblang. A) √21 B) 35 C) 4√21 D) 2√21 13 / 25 13. Tenglamalar sistemasi nechta yechimga ega? A) 12 B) 6 C) 10 D) 8 14 / 25 14. Tenglama nechta yechimga ega? A) 3 B) 4 C) 2 D) 5 15 / 25 15. Agar bo‘lsa, ?(0) − ?(5) ayirmani toping. A) -26 B) -27 C) -25 D) -24 16 / 25 16. ?/? kasr (?, ? −natural sonlar)— qisqarmas kasr va (7?+6?)/(3?+2?) kasr esa qisqaradi. Ushbu kasr qanday songa qisqaradi? A) 2 B) 5 C) 3 D) 8 17 / 25 17. (?² − 2? + 3)(?² + 6? + 12) = 6 bo‘lsa, ? + ? ni toping. A) 3 B) 2 C) -2 D) -3 18 / 25 18. ?(?) = ?5 − 7?4 + 3?3 − ? + 2 ko‘phadni ?2 + ? ga bo‘lgandagi qoldiqni aniqlang. A) 6? + 2 B) 4? + 2 C) 8? + 2 D) 10? + 2 19 / 25 19. 102022 − 22021 ayirmani 24 ga bo‘lgandagi qoldiqni toping. A) 12 B) 16 C) 8 D) 0 20 / 25 20. Soddalashtiring: (4cos² 9° −3)(4cos² 27° −3)·ctg9° A) 1 B) tg9° C) sin18° D) 2cos² 9° 21 / 25 21. x, y sonlari (x² + 1)(y² + 1) + 2(x − y)(1 − xy) = 4(1 + xy) tenglikni qanoatlantiradi |1 + x| ∙ |1 − y| ni toping. A) 2 B) 1 C) 3 D) 9 22 / 25 22. Agar ? > 0, ? + ?² = 7,25; ?² − ? = 2 va ?² = √(? − 1) ∙ √(2 − ?) bo‘lsa, ?(√(? − 1) + √(2 − ?)) ning qiymatini toping. A) 5 B) 6 C) 7 D) 4 23 / 25 23. Agar A) π B) π/2 C) 0 D) 3π/2 24 / 25 24. ?(? − 1) = 2?(5? + 4) va ?(2? − 1) = 4? + 4 bo‘lsa, ?(?) ni toping A) 0 B) x+25 C) 20x+50 D) 20x+48 25 / 25 25. Qavariq to‘rtburchakning diagonallari 3 va 4 ga teng. Agar qarama qarshi tomonlarining o‘rtalarini tutashtirishdan hosil bo‘lgan kesmalar uzunliklari o‘zaro teng bo‘lsa, qavariq to‘rtburchakning yuzini toping. A) 7 B) 6 C) 5 D) 8 0% Testni qayta ishga tushiring Tomonidan Wordpress Quiz plugin Author: InfoMaster Foydali bo'lsa mamnunmiz
