Uy » Online olimpiada » Matematika olimpiada » 10-sinf Matematika olimpiada №3 Matematika olimpiadaViloyat 2021-2022 o'quv yili 10-sinf Matematika olimpiada №3 InfoMaster Avgust 19, 2024 89 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0 12345678910111213141516171819202122232425 Vaqtingiz tugadi! 10-sinf Matematika olimpiada №3 2021-2022 o'quv yili viloyat bosqichida tushgan savollar. 1 / 25 1. tengsizlik qiymatlarida o‘rinli bo‘ladigan ning barcha qiymatlarini toping. A) (-2;8) B) (2;8) C) (8;19) D) [2;8] 2 / 25 2. bo'lsa kasrning qiymatini hisoblang. A) √11+1 B) √11-1 C) √11-2 D) 2-√11 3 / 25 3. ?/? kasr (?, ? −natural sonlar)— qisqarmas kasr va (7?+6?)/(3?+2?) kasr esa qisqaradi. Ushbu kasr qanday songa qisqaradi? A) 8 B) 5 C) 3 D) 2 4 / 25 4. ABCD to‘rtburchakda АВ = CD = 9 va bu to‘rtburchakka radiusi 4 ga teng aylana ichki chizilgan. ABCD to‘rtburchak yuzini toping. A) 72 B) 81 C) 36 D) 144 5 / 25 5. Ayirmasi noldan farqli bo‘lgan arifmetik progressiyaning 4-hadidan boshlab 14- hadigacha bo‘lgan hadlar yig‘indisi 77 ga teng. Progressiyaning 7 ga teng bo‘lgan had nomerini toping. A) 11 B) 8 C) 9 D) 10 6 / 25 6. englikni qanoatlantiradigan ? ning eng kichik qiymatini toping. A) 3 B) -1 C) 1 D) 0 7 / 25 7. Agar A) π B) 0 C) π/2 D) 3π/2 8 / 25 8. Tenglama nechta yechimga ega? A) 3 B) 2 C) 4 D) 5 9 / 25 9. ABC – gipotenuzasi AB bo‘lgan to‘g‘ri burchakli uchburchak. Gipotenuzaning ikki tomon davomida AB to‘g‘ri chiziqda AK = AC va BM = BC shartlar bilan kesmalar ajratilgan. KCM burchakni toping. A) 150° B) 135° C) 90° D) 120° 10 / 25 10. Agar ?1 = 6? − 6 va у2//?1 hamda у2 to‘g‘ri chiziq ?(6; 6) nuqtadan o‘tsa, ?2 ni toping. A) −6? + 6 B) 6? − 30 C) 6? − 24 D) −6? + 42 11 / 25 11. Tenglamalar sistemasi nechta yechimga ega? A) 8 B) 6 C) 12 D) 10 12 / 25 12. Agar bo‘lsa, |xyz| ni toping. A) 500 B) 1000 C) 800 D) 100 13 / 25 13. Uchburchak tomonlarining uzunliklari berilgan tenglamaning ildizlariga mos keladi. ?³ − 24?² + 183? − 440 = 0. Uchburchakning yuzini hisoblang. A) 4√21 B) √21 C) 35 D) 2√21 14 / 25 14. ABCD to‘rtburchakda А va В burchaklar- to‘g‘ri, tg∠D = 3/4 va ВС = AD/2 = АВ + 2 bo‘lsa, АС ni toping. A) 10 B) 8 C) 15 D) 9 15 / 25 15. ?(? − 1) = 2?(5? + 4) va ?(2? − 1) = 4? + 4 bo‘lsa, ?(?) ni toping A) 20x+50 B) 20x+48 C) 0 D) x+25 16 / 25 16. 102022 − 22021 ayirmani 24 ga bo‘lgandagi qoldiqni toping. A) 8 B) 12 C) 0 D) 16 17 / 25 17. x, y sonlari (x² + 1)(y² + 1) + 2(x − y)(1 − xy) = 4(1 + xy) tenglikni qanoatlantiradi |1 + x| ∙ |1 − y| ni toping. A) 9 B) 1 C) 2 D) 3 18 / 25 18. (?² − 2? + 3)(?² + 6? + 12) = 6 bo‘lsa, ? + ? ni toping. A) 2 B) -2 C) 3 D) -3 19 / 25 19. Tenglamani yeching: 3x+3 + 8·3x+2 = 33 A) 0 B) 1 C) -1 D) -2 20 / 25 20. Agar ? > 0, ? + ?² = 7,25; ?² − ? = 2 va ?² = √(? − 1) ∙ √(2 − ?) bo‘lsa, ?(√(? − 1) + √(2 − ?)) ning qiymatini toping. A) 5 B) 4 C) 6 D) 7 21 / 25 21. tenglama nechta yechimga ega, agar x ∈ (0; 50)? A) 16 B) 17 C) 14 D) 15 22 / 25 22. a,b,c−ABC uchburchakning tomonlari. Agar a4 + b4 + c4 + 32 = 2(a²b² + b²c² + a²c²) bo‘lsa, ABC uchburchak yuzini toping. A) 1 B) √2 C) 2√2 D) √3 23 / 25 23. ?² + |? − 3| ≤ |?2 + ?| − 3 tengsizlikni yeching. A) x<0 B) 3 ≤ x C) x>3 D) x ≤ 3 24 / 25 24. Agar ni toping. A) 0.8 B) 0.96 C) 0.81 D) 0.9 25 / 25 25. bo‘lsa ? ning qiymatini toping. A) 25 B) 37 C) 12 D) 40 0% Testni qayta ishga tushiring Author: InfoMaster Foydali bo'lsa mamnunmiz
