Uy » Choraklik online testlar » Matematika choraklik » 5-sinf Matematika 4-chorak Matematika choraklik 5-sinf Matematika 4-chorak InfoMaster May 12, 2021 2923 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 10 0 OMAD YOR BO'LSIN! Tomonidan yaratilgan InfoMaster 5-sinf Matematika 4-chorak Testni Shirinboyev Temurbek tayyorladi! Ismi familiyangizni kriting! Ism 1 / 25 ≤table≥ tegining cellspacing atributi qiymatining vazifasini toping. A) jadval chegarasidan yozuvgacha bo‘lgan masofani o‘rnatish (agar masofa o‘rnatilmasa, yozuv jadval chegarasiga yopishtirib yoziladi). B) jadvalning ramka qalinligi o‘rnatilgan bo‘lsa (border), jadval katagi bilan tashqi chegara ramkasi orasidagi masofani o‘rnatish. C) jadval kengligini o‘rnatish. Qiymat piksel yoki foizlarda berilishi mumkin. D) jadval balandligini o‘rnatish. Qiymat piksel yoki foizlarda berilishi mumkin. 2 / 25 input elementining type atributi vazifasini toping. A) A=B B) matnli elementlarda yozuv yozish mumkin bo‘lgan joy uzunligini o‘rnatadi. C) A katta B dan D) B katta A dan E) To'g'ri javob yo'q F) forma elementiga takrorlanmas nom beradi. G) forma elementi turi H) foydalanuvchi tomonidan kiritilishi mumkin bo‘lgan axborotning maksimal o‘lchami. 3 / 25 Ko’paytmaning natural bo’luvchilari soni 75 ga teng bo’lsa, n ni toping. A) 11 B) 5 C) 1 D) 6 4 / 25 5xy soni 4 ga qoldiqsiz bo’linsa, x va y barcha qiymatlari yig’indisini toping. A) 50 B) 70 C) 95 D) 90 5 / 25 Tub sonlar ichida 3 ga bo`linadiganlari nechta? A) 2 ta B) 1 ta C) yo'q D) cheksiz ko`p 6 / 25 EKUB(140;150;160)+EKUK(21;42;84)=? A) 94 B) 116 C) 224 D) 52 7 / 25 Raqamlari yig’indisi 28 ga teng bo’lgan eng katta to’rt xonali son(turli raqamli)ning birlar xonasidagi raqamni toping. A) 5 B) 6 C) 7 D) 4 8 / 25 2;0;1;4 raqamlardan foydalanib, eng kichik to’rt xonali son hosil qilindi. Hosil bo’lgan sonni 32 ga bo’lgandagi bo’linmani toping. A) 32 B) 0 C) 4 D) 28 9 / 25 Berilgan juftliklardan o'zaro tub sonlarni toping. A) (1167;2001) B) (8001;2001) C) (80001;80002) D) (1001;469) 10 / 25 To'g'ri burchakli parallelepipedning asoning yuzi 15 dm^2, hadmi 60 dm^3 bo'lsa uning balandligini toping. A) 4 B) 8 C) 2 D) 45 11 / 25 To'g'ri burchakli parallelepipedning hajmini topish formulasini ko'rsating. A) V=a^2 B) V=abc C) V=a^3 D) S=6a^2 12 / 25 Kasrni bo’linma ko’rinishida ifodalang va uning qiymatini toping: A) 3131 : 101 B) 101 : 3131 C) 101/3131 D) 31 : 31 : 101 13 / 25 To'g'ri burchakli parallelepipedning a=5, b=3, c=7 tamonlari berilgan bo'lsa uning hajmini toping. A) 30 B) 105 C) 70 D) 60 14 / 25 Kubning qirrasi 8 dm bo'lsa uning hajmini toping. A) 256 B) 512 C) 64 D) 128 15 / 25 To’g’ri to’rtburchakning enini toping. A) 2,11/13 B) 2,14/13 C) 4,11/13 D) 3,15/13 16 / 25 AB kesmani C nuqta AC va CB qismlarga ajratadi. Agar AC kesma uzunligi 56 sm bo’lib, u BC kesmadan 23 sm qisqa bo’lsa, AB kesma uzunligini toping. A) 129 sm B) 125 sm C) 135 sm D) 233 sm 17 / 25 Kasr sonni 0,01 ga bo’lish qanday songa ko`paytirish demakdir. A) 10 B) 100 C) 0,01 D) 1000 18 / 25 Sonning o’rta arifmetigini toping: 2,11; 2,12; 2,19; 2,48 A) 4,248 B) 2,482 C) 3,182 D) 2,225 19 / 25 Bo’linmani bajaring: 121,6 : 4 A) 72,8 B) 45,2 C) 30,4 D) 60,8 20 / 25 Hisoblang. (53+142):13 A) 25 B) 19 C) 20 D) 15 21 / 25 Hisoblang: 0,872*6,3 A) 8,4262 B) 5,4936 C) 6,4592 D) 7,846 22 / 25 To’g’ri to’rtburchak tomonlari: 8 m va 2,66 m bo’lsa, uning yuzini toping? A) 35,42 B) 23,12 C) 29,72 D) 21,28 23 / 25 4050:…=75tenglikda tushurib qoldirilgan son qaysi A) 54 B) 60 C) 55 D) 75 24 / 25 Ifodaning qiymatini toping. b+d bunda b=40,d=50 A) 90 B) 10 C) 75 D) 80 25 / 25 Hisoblang:4,387 : 100; A) 438700 B) 0,4387 C) 0,04387 D) 4387 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz