Uy » Choraklik online testlar » Matematika choraklik » 5-sinf Matematika 4-chorak Matematika choraklik 5-sinf Matematika 4-chorak InfoMaster May 12, 2021 1412 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 7 0 OMAD YOR BO'LSIN! Tomonidan yaratilgan InfoMaster 5-sinf Matematika 4-chorak Testni Shirinboyev Temurbek tayyorladi! Ismi familiyangizni kriting! Ism 1 / 25 Kubning qirrasi 6 dm bo'lsa uning qirralari uzunliklari yig'indisini toping. A) 24 B) 72 C) 36 D) 12 2 / 25 Kasrni bo’linma ko’rinishida ifodalang va uning qiymatini toping: A) 101 : 3131 B) 101/3131 C) 31 : 31 : 101 D) 3131 : 101 3 / 25 Qoldiqli bo’lishni bajaring ; 54 102 : 44; A) 136(2q) B) 1229 (26q) C) 123 (5q) D) 1631 (8q) 4 / 25 To'g'ri burchakli parallelepipedning a=3, b=4, c=5 tamonlari berilgan bo'lsa uning sirtini yuzini toping. A) 56 B) 92 C) 94 D) 72 5 / 25 AB kesmani C nuqta AC va CB qismlarga ajratadi. Agar AC kesma uzunligi 56 sm bo’lib, u BC kesmadan 23 sm qisqa bo’lsa, AB kesma uzunligini toping. A) 135 sm B) 129 sm C) 233 sm D) 125 sm 6 / 25 Sonni noto’g’ri kasr ko’rinishi ifodalang: A) 2221/316 B) 79/316 C) 2568/316 D) 2021/316 7 / 25 Qo’sh tengsizlik ko’rinishida ifodalang. 44 soni 55 sonidan kichik, lekin 33 sonida katta; A) 44<55<33 B) 3344 C) 33<44<55 D) 55<44<33 8 / 25 2;0;1;4 raqamlardan foydalanib, eng kichik to’rt xonali son hosil qilindi. Hosil bo’lgan sonni 32 ga bo’lgandagi bo’linmani toping. A) 0 B) 4 C) 32 D) 28 9 / 25 Yig’indining oxirgi raqamini toping A) 3 B) 4 C) 2 D) 8 10 / 25 Yig’indining oxirgi raqamini toping. A) 1 B) 8 C) 3 D) 0 11 / 25 28900 sonining tub bo’luvchilari yig’indisini toping. A) 22 B) 14 C) 19 D) 24 12 / 25 Quyidagi sonni 5 ga bo’lganda qanday qoldiq qoladi? A) 2 B) 1 C) 4 D) 3 13 / 25 Berilgan juftliklardan o'zaro tub sonlarni toping. A) (80001;80002) B) (8001;2001) C) (1167;2001) D) (1001;469) 14 / 25 30 gacha bo’lgan tub sonlar ko’paytmasining oxirgi raqamini toping. A) 0 B) 5 C) 1 D) 7 15 / 25 a=6,38, b=63, bo`lsa a*100+b ifodaning qiymatini toping. A) 614,2 B) 701 C) 248,3 D) 712 16 / 25 4050:…=75tenglikda tushurib qoldirilgan son qaysi A) 54 B) 60 C) 55 D) 75 17 / 25 Sonni foiziga aylantirish uchun uni…….ko`paytirish. A) 200 ga B) 50 ga C) 150 ga D) 100 ga 18 / 25 O’nli kasr ko’rinishida yozing: 825/100 A) 83,25 B) 8,25 C) 3,32 D) 4,8 19 / 25 Tenglamani yeching x*17=119 A) x=13 B) x=10 C) x=12 D) x=7 20 / 25 Miqdor (sonning)yuzdan bir ulushi uning…….deb ataladi A) Yig’indisi B) Ko’paytmasi C) Foizi D) Bo’linmasi 21 / 25 Bo’linmani bajaring: 121,6 : 4 A) 45,2 B) 60,8 C) 72,8 D) 30,4 22 / 25 Sonning o’rta arifmetigini toping: 2,11; 2,12; 2,19; 2,48 A) 3,182 B) 2,482 C) 2,225 D) 4,248 23 / 25 ≤form≥ tegining method atributi qiymatining vazifasini toping. A) harfiy ifoda B) forma orqali jo‘natilayotgan ma’lumotlar qaysi sahifada qayta ishlanishi kerakligi beriladi. C) sonli ifoda D) a va b javoblar E) qavsli misol F) formada har xil ko‘rinishdagi elementlarni hosil qiladi. G) forma ma’lumotlarini jo‘natish usuli. H) formaga nom berish (bu nom skriptlar yozishda ishlatiladi) 24 / 25 form elementida har doim qaysi atributi ishtirok etishi lozim? A) action B) valign C) 1 m2=1000dm2 D) height E) 1 m2=100 dm2 F) aling G) 1 m2=100000 dm2 H) 1 m2=10 dm2 25 / 25 input elementining type atributi vazifasini toping. A) B katta A dan B) To'g'ri javob yo'q C) foydalanuvchi tomonidan kiritilishi mumkin bo‘lgan axborotning maksimal o‘lchami. D) forma elementiga takrorlanmas nom beradi. E) matnli elementlarda yozuv yozish mumkin bo‘lgan joy uzunligini o‘rnatadi. F) A=B G) A katta B dan H) forma elementi turi 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
