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11-sinf Matematika 4-chorak

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Aprel 20, 2021

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11-sinf Matematika 4-chorak

Testni Salomov Sardor tayyorladi.

1 / 25

(x²+23x+23)(x²+x+23)=23x² tenglama haqiyqiy ildizlari yig’indisini toping

A) -24

B) 24

C) 23

D) -23

2 / 25

aniq integralni hisoblang

A) 6

B) 2,5

C) 4

D) 2

3 / 25

Ushbu funksiyasining boshlang’ich funksiyasini toping

A) lnIx-1I

B) ln⁡(|x+2|*|x+1|)

C) (x+2)(x+1)

D) lnI(x-2)(x-3)I

4 / 25

Ixtiyoriy kvadratga tashqi va ichki chizilgan aylanalar yuzlari nisbati a ga teng. Ixtiyoriy aylanaga ichki va tashqi chizilgan kvadratlar yuzlari nisbati b ga teng bolsa, a/b ni toping

A) 1/2

B) 1

C) 335

D) 4

5 / 25

cos(2arctg(1/2)) ni hisoblang

A) 37/35

B) -37/35

C) -35/37

D) 35/37

6 / 25

Silindr shaklidagi idishga 6 sm³ suv solindi. Idishga detal to’liq cho’ktirilganda, suv sathi 1,5 marta ko’tarildi. Detal hajmini aniqlang

A) 23

B) 3

C) 1

D) 14

7 / 25

integralni hisoblang

A) 5ln2e

B) 5ln3e³

C) 5

D) 5ln4e

8 / 25

Bir burchagi 60⁰ bo’lgan to’g’ri burchakli uchburchakka tomoni 6 ga teng romb shunday ichki chizilganki, 60⁰ li burchak ular uchun umumiy, rombning barcha uchlari uchburchakning tomonlarida yotadi. Uchburchak yuzini toping

A) (8√3)/2

B) (81√3)/2

C) (1√3)/2

D) √3/2

9 / 25

Tomoni 4 ga teng bo’lgan teng tomonli uchburchak ichiga uchburchakning tomonlariga urinuvchi uchta teng doira joylashtirilgan. O’zaro urunuvchi doiralar yoylaridan hosil bo’lgan egri chiziqli uchburchakning yuzini toping

A) (2-√3)(2√3-π)

B) (2-√3)(2-π)

C) (4-√3)(2√3-π)

D) 2√3-π

10 / 25

Hisoblang:

cos²33⁰+cos²45⁰-sin²60⁰+cos²57⁰

A) 0,75

B) 2,25

C) 0,5

D) 1,5

11 / 25

Voleybol jamoasi 9 ta o’yinchidan iborat. Boshlang’ich tarkibga 6 ta o’yinchini nechta usul bilan tanlab olish mumkin

A) 21

B) 168

C) 42

D) 84

12 / 25

Funksiyaning aniqlanish sohasini toping : y=log_x-2(x²+7x-8)

A) (2;3)U(3;+∞)

B) (8;+∞)

C) (-∞;-8)U(2;3)U(3;+∞)

D) (-∞;-1)U(8;+∞)

13 / 25

2cosx+sinx=-2 tenglamaning [-π;π] kesmada nechta ildizi bor

A) Ø

B) 1

C) 2

D) 3

14 / 25

y=x²-│2x-4│ funksiya grafigiga x=3 va

x= -3 nuqtalarda o’tkazilgan urinmalar kesishish nuqtasi ordinatasini toping

A) -12

B) -9

C) -6

D) -5

15 / 25

Agar A(1;2;3), B(3;7;6) bo’lsa, A̅B̅ vector koordinatalarini toping

A) (2;5;3)

B) (4;9;9)

C) (4;9;9)

D) (-2;-5;-3)

16 / 25

Moddiy nuqta S(t)=5t³+3t²+2t+4 qonuniyat bilan harakatlanayotgan jismning t=2 sekunddagi tezligini toping.

A) 84

B) 74

C) 70

D) 60

17 / 25

Murakkab funksiyaning hosilasini toping. y=x²sinx

A) y’=x²cosx-2xsinx

B) y’=2xsinx-x²

C) y’=2xsinx+x²cosx

D) y’=-2xsinx+x²

18 / 25

A(1;-2;2), B(1;4;0), C(-4;1;1) va D(-5;-5;3) nuqtalar berilgan. AC va BD vektorlar orasidagi burchakni toping

A) 80°

B) 90°

C) 15°

D) 52°

19 / 25

Funksiyaning statsionar nuqtalarini toping $f(x)=2x^3-3x^2-12x+3$

A) x=-1, x=3

B) x=0, x=2

C) x=3, x=2

D) x=-1, x=2

20 / 25

$f(x)=x^3+2x^2+x+3$ funksiyasining kamayish oralig’ini toping.

A) (-∞;-1)

B) [-1;-1/3]

C) (-1/3;+∞)

D) (-1;1/3)

21 / 25

Karim 3 minutda 213ta so`zni terib , 6ta imloviy xatoga yo`l qo`ydi. Karimning matn terish sifatini toping.

A) 0,3265

B) 0,623

C) 0,0321

D) 0,0282

22 / 25

funksiya hosilasining x₀=-2 nuqtadagi qiymatini hisoblang.

A) -38/961

B) 38/961

C) 38/31

D) -38/31

23 / 25

f(x)=(3x+2)² funksiyasining barcha boshlang’ich funksiyalarini toping.

A) F(x)=6x³+3x²+4

B) F(x)=6x³+6x²+4

C) F(x)=6x³+3x²-4

D) F(x)=6x³+6x+4

24 / 25

To’g’ri to’rtburchak shaklidagi yer maydoninig atrofini o’rashmoqchi. 480 m panjara yordamida eng ko’pi bilan necha kvadrat metr yer maydonni o’rash mumkin?

A) 19600

B) 14400

C) 8100

D) 25600

25 / 25

f(x)=sin2x funksiyasining barcha boshlang’ich funksiyalarini toping.

A) F(x)=-0,5cos2x+C

B) F(x)=2sin4x+c

C) F(x)=0,5cos2x+C

D) F(x)=-2cos2x+C