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11-sinf Matematika 4-chorak

InfoMaster

Aprel 20, 2021

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11-sinf Matematika 4-chorak

Testni Salomov Sardor tayyorladi.

1 / 25

Ushbu funksiyasining boshlang’ich funksiyasini toping

A) lnI(x-2)(x-3)I

B) lnIx-1I

C) ln⁡(|x+2|*|x+1|)

D) (x+2)(x+1)

2 / 25

chiziqlar bilan chegaralangan shaklning yuzini toping

A) 0,5

B) 1

C) √2

D) 2

3 / 25

Silindr shaklidagi idishga 6 sm³ suv solindi. Idishga detal to’liq cho’ktirilganda, suv sathi 1,5 marta ko’tarildi. Detal hajmini aniqlang

A) 1

B) 3

C) 14

D) 23

4 / 25

Uchburchakli muntazam prizma asosining radiusi $\sqrt{3}$ ga va balandligi 2 ga teng bo’lgan silindrga ichki chizilgan. Prizma yon sirtining yuzini toping

A) 335

B) 36

C) 4

D) 3

5 / 25

cos15⁰*cos45⁰ *cos75⁰ ni hisoblang

A) 2√2

B) √2

C) √8/2

D) √2/2

6 / 25

cos(2arctg(1/2)) ni hisoblang

A) 37/35

B) -37/35

C) -35/37

D) 35/37

7 / 25

f(x)=3x²-5x+4 va g(x)=4x-5 funksiyalarining urinmalari parallel bo’ladigan nuqtalarini toping.

A) 2

B) 1.5

C) 0.5

D) 0

8 / 25

Funksiya hosilasini toping: f(x)=5

A) 5

B) x

C) 0

D) 10

9 / 25

$f(x)=x^3+2x^2+x+3$ funksiyasining kamayish oralig’ini toping.

A) [-1;-1/3]

B) (-∞;-1)

C) (-1/3;+∞)

D) (-1;1/3)

10 / 25

Funksiya hosilasini toping: $f(x)=7x^3-5x^2+4$

A) 12x²-12

B) 14x+12

C) 21x²-10x

D) 12x+12

11 / 25

A(-4;3;6) nuqtaning Oxz tekisligiga nisbatan simmrtrik nuqtasini toping.

A) (-4;-6;6)

B) (-4;-3;6)

C) (-4;-3;9)

D) (-8;-3;6)

12 / 25

Murakkab funksiyaning hosilasini toping. y=x²sinx

A) y’=x²cosx-2xsinx

B) y’=-2xsinx+x²

C) y’=2xsinx-x²

D) y’=2xsinx+x²cosx

13 / 25

Hisoblang:

cos²33⁰+cos²45⁰-sin²60⁰+cos²57⁰

A) 0,75

B) 0,5

C) 1,5

D) 2,25

14 / 25

Agar f(x)=6+5tg²2x bo’lsa, f^'(π) ni toping

A) 3

B) 0

C) 5

D) 1

15 / 25

integralni hisoblang

A) 5

B) 5ln2e

C) 5ln3e³

D) 5ln4e

16 / 25

Tekislikdagi 1 m masofada yotgan nuqtadan ikkita teng og’ma o’tkazilgan. Agar og’malar perpendikulyar va tekislikka o’tkazilgan perpendikulyar bilan 60⁰ ga teng burchaklar tashkil etsa, og’malarning asoslari orasidagi masofani toping

A) 2√3

B) 4√2

C) 1

D) 2√2

17 / 25

2cosx+sinx=-2 tenglamaning [-π;π] kesmada nechta ildizi bor

A) Ø

B) 2

C) 3

D) 1

18 / 25

Bir burchagi 60⁰ bo’lgan to’g’ri burchakli uchburchakka tomoni 6 ga teng romb shunday ichki chizilganki, 60⁰ li burchak ular uchun umumiy, rombning barcha uchlari uchburchakning tomonlarida yotadi. Uchburchak yuzini toping

A) (81√3)/2

B) √3/2

C) (8√3)/2

D) (1√3)/2

19 / 25

B,C,D,E nuqtalar aylanadagi, A esa aylanadan tashqaridagi nuqtalar. D nuqta AE kesmada, B esa AC kesmada yotadi. Agar AE=12 va AC=16 bo’lsa, BE vatar uzunligining CD vatar uzunligiga nisbatini toping

A) 4

B) 3

C) 1

D) 3/4

20 / 25

Massasi 735 gr va konsentratsiyasi 16% bo’lgan yodning spirtdagi eritmasiga qancha toza spirt qo’shilsa, uning konsentratsiyasi 10% bo’ladi

A) 252

B) 420

C) 256

D) 441

21 / 25

$\sqrt[3]{131}$ sonini taqriban hisoblang.

A) 4,08

B) 5,01

C) 5,08

D) 3,08

22 / 25

f(x)=(3x+2)² funksiyasining barcha boshlang’ich funksiyalarini toping.

A) F(x)=6x³+3x²-4

B) F(x)=6x³+3x²+4

C) F(x)=6x³+6x+4

D) F(x)=6x³+6x²+4

23 / 25

Kub to’la sirtining yuzi 105,84 sm² bo’lsa, uning har bir yog’i yuzini va qirrasining uzunligini toping.

A) 17,64 dm²; 4,2 dm

B) 17,64 dm; 4,2 dm

C) 17,68 dm²; 4,2 dm

D) 17,64 dm²; 4,9 dm

24 / 25

To’g’riburchakli parallelepiped asosining tomonlari 7:24 nisbatda, diagonal kesimining yuzi 50dm² ga teng. Yon sirtining yuzini toping.

A) 124 dm

B) 135 dm²

C) 224 dm²

D) 124 dm²

25 / 25

F(x)=0.2sin(5x+12) funksiyasi uchun f(x) ni toping

A) f(x)=0.5cos(5x+12)

B) f(x)=cos(5x+12)

C) f(x)=-cos(5x+12)

D) f(x)=-0,5sin(5x+12)

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11-sinf Matematika 4-chorak

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55% va kamiga 2 baho

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