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11-sinf Matematika 4-chorak

InfoMaster

Aprel 20, 2021

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11-sinf Matematika 4-chorak

Testni Salomov Sardor tayyorladi.

1 / 25

Moddiy nuqta S(t)=5t³+3t²+2t+4 qonuniyat bilan harakatlanayotgan jismning t=2 sekunddagi tezligini toping.

A) 84

B) 74

C) 60

D) 70

2 / 25

A(-4;3;6) nuqtaning Oxz tekisligiga nisbatan simmrtrik nuqtasini toping.

A) (-4;-3;6)

B) (-8;-3;6)

C) (-4;-3;9)

D) (-4;-6;6)

3 / 25

Agar f(x)=x² va bo`lsa ,f(g(2)) ni toping

A) 16

B) 36

C) 12

D) 0

4 / 25

Funksiya hosilasini toping

f(x)=(2x+4)(3x+1)

A) 3x+1

B) 12x

C) 12x+14

D) 16x+14

5 / 25

$f(x)=x^3-2x^2+3x-2$ funksiya grafigiga x=4 abssissali nuqtada o`tkazilgan urinma tenglamasini tuzing

A) y=20x+20

B) y=10x

C) y=35x+30

D) y=35x

6 / 25

Funksiya hosilasini toping: f(x)=5

A) 0

B) x

C) 10

D) 5

7 / 25

f(x)=2x+3 funksiyasi uchun A(1;5) nuqtadan o’tuvchi boshlang’ich funksiyasini toping.

A) F(x)=x²-3x-1

B) F(x)=x²+3x+1

C) F(x)=x²-3x+1

D) F(x)=x²+3x-1

8 / 25

A(2;0;-3) va B(3;4;0) nuqtalar orasidagi masofani toping

A) 25

B) 16

C) √26

D) √24

9 / 25

Funksiyaning kamayish oraliqlarini toping

A) (-1;0) va (0;1)

B) (-3;0) va (0;1)

C) (-2;0) va (0;1)

D) (-1;0) va (0;2)

10 / 25

$f(x)=x^3-2x^2$ funksiya grafigiga x=1 abssisssali nuqtadao`tkazilgan urinma tenglamasini yozing

A) y= 2x

B) y=1/2

C) y=-x

D) y=x

11 / 25

$f(x)=x^2-3x+4$ funksiya uchun y=2x-1 to`g`ri chiziqqa parallel bo`lgan urinma tenglamasini yozing

A) y=2x+3

B) y=3x-2,2

C) y=2x

D) y=2x-2,25

12 / 25

funksiya hosilasining x₀=-2 nuqtadagi qiymatini hisoblang.

A) -38/31

B) -38/961

C) 38/31

D) 38/961

13 / 25

Funksiya hosilasini toping: $f(x)=7x^3-5x^2+4$

A) 14x+12

B) 12x+12

C) 21x²-10x

D) 12x²-12

14 / 25

sin3x+ $\sqrt{3}$ cos3x≥0 tengsizligini yeching

A) ø

B) [-π/9+n π/3;2 π/9+n π/3]

C) [-π/9+2πn/3; 2π/9+2πn/3]

D) (-π/2+n π;- π/2+n π)

15 / 25

tengsizlikning yechimi bo’lgan eng kichik natural sonni toping

A) 1

B) 4

C) 3

D) 5

16 / 25

Ixtiyoriy kvadratga tashqi va ichki chizilgan aylanalar yuzlari nisbati a ga teng. Ixtiyoriy aylanaga ichki va tashqi chizilgan kvadratlar yuzlari nisbati b ga teng bolsa, a/b ni toping

A) 4

B) 335

C) 1

D) 1/2

17 / 25

Uchburchakli muntazam prizma asosining radiusi $\sqrt{3}$ ga va balandligi 2 ga teng bo’lgan silindrga ichki chizilgan. Prizma yon sirtining yuzini toping

A) 36

B) 4

C) 335

D) 3

18 / 25

y>0 bo’lsin. To’g’riburchakning uchlari to’g’ri burchakli koordinatalar sistemasida qyuidagicha berilgan:
A(0;0), B(0;y), C(-9;y) va D(-11;0). To’rtburchak diagonallarining o’tralari orasidagi masofani toping

A) 2

B) 1

C) √2

D) √22

19 / 25

Silindr shaklidagi idishga 6 sm³ suv solindi. Idishga detal to’liq cho’ktirilganda, suv sathi 1,5 marta ko’tarildi. Detal hajmini aniqlang

A) 1

B) 14

C) 3

D) 23

20 / 25

cos(2arctg(1/2)) ni hisoblang

A) 37/35

B) -35/37

C) -37/35

D) 35/37

21 / 25

F(x)=0.2sin(5x+12) funksiyasi uchun f(x) ni toping

A) f(x)=-0,5sin(5x+12)

B) f(x)=0.5cos(5x+12)

C) f(x)=cos(5x+12)

D) f(x)=-cos(5x+12)

22 / 25

Moddiy nuqta qonuniyat bilan harakatlanmoqda, eng katta tezlanishga erishiladigan vaqtni toping.

A) 4

B) 6

C) 7

D) 5

23 / 25

Funksiyaning aniqlanish sohasini toping : y=log_x-2(x²+7x-8)

A) (2;3)U(3;+∞)

B) (8;+∞)

C) (-∞;-8)U(2;3)U(3;+∞)

D) (-∞;-1)U(8;+∞)

24 / 25

Tekislikdagi 1 m masofada yotgan nuqtadan ikkita teng og’ma o’tkazilgan. Agar og’malar perpendikulyar va tekislikka o’tkazilgan perpendikulyar bilan 60⁰ ga teng burchaklar tashkil etsa, og’malarning asoslari orasidagi masofani toping

A) 2√2

B) 1

C) 2√3

D) 4√2

25 / 25

f(x)=(sinx)^cosx bo’lsa, f '(5π/6) ni toping

A) (ln2+3)/2)*(√3^√3)

B) (ln2+3)/2)*(√2^√3)

C) (ln2-3)/2)*(√2^√3)

D) (ln2+3)/2)*(√2^√2)