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11-sinf Matematika 4-chorak

InfoMaster

Aprel 20, 2021

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11-sinf Matematika 4-chorak

Testni Salomov Sardor tayyorladi.

1 / 25

F(x)=0.2sin(5x+12) funksiyasi uchun f(x) ni toping

A) f(x)=-0,5sin(5x+12)

B) f(x)=-cos(5x+12)

C) f(x)=0.5cos(5x+12)

D) f(x)=cos(5x+12)

2 / 25

Havo shariga t $\in$ [0;10] minut oralig’ida V(t)=t³+13t²+t+20 (m³) havo purkamoqda. t=10 minutdagi havo hajmini toping.

A) 1023

B) 2025

C) 2300

D) 2330

3 / 25

Moddiy nuqta qonuniyat bilan harakatlanmoqda, eng katta tezlanishga erishiladigan vaqtni toping.

A) 5

B) 6

C) 4

D) 7

4 / 25

To’g’riburchakli parallelepiped asosining tomonlari 7:24 nisbatda, diagonal kesimining yuzi 50dm² ga teng. Yon sirtining yuzini toping.

A) 124 dm²

B) 124 dm

C) 135 dm²

D) 224 dm²

5 / 25

A) 20

B) 18

C) 14

D) 13

6 / 25

f(x)=3x²-5x+4 va g(x)=4x-5 funksiyalarining urinmalari parallel bo’ladigan nuqtalarini toping.

A) 2

B) 0.5

C) 0

D) 1.5

7 / 25

y=-3x³+2x²-4x+5 funksiyaga x₀=-1 nuqtada o’tkazilgan urinma tenglamasining burchak koeffitsiyentini toping.

A) 15

B) 17

C) -17

D) -13

8 / 25

Moddiy nuqta S(t)=5t³+3t²+2t+4 qonuniyat bilan harakatlanayotgan jismning t=2 sekunddagi tezligini toping.

A) 70

B) 74

C) 84

D) 60

9 / 25

A(2;0;-3) va B(3;4;0) nuqtalar orasidagi masofani toping

A) √24

B) 16

C) √26

D) 25

10 / 25

$f(x)=x^3-2x^2$ funksiya grafigiga x=1 abssisssali nuqtadao`tkazilgan urinma tenglamasini yozing

A) y=x

B) y=1/2

C) y= 2x

D) y=-x

11 / 25

$f(x)=x^3-2x^2+3x-2$ funksiya grafigiga x=4 abssissali nuqtada o`tkazilgan urinma tenglamasini tuzing

A) y=20x+20

B) y=35x+30

C) y=10x

D) y=35x

12 / 25

Uchlari A(4;0;1), B(5;-2;1), C(4;8;5) nuqtalarda bo’lgan uchburchakning AL bissektrisasi uzunligini toping

A) 4

B) (4√2)/5

C) (2√5)/3

D) (4√2)3

13 / 25

funksiya hosilasining x₀=-2 nuqtadagi qiymatini hisoblang.

A) -38/31

B) -38/961

C) 38/31

D) 38/961

14 / 25

Funksiya hosilasini toping: $f(x)=7x^3-5x^2+4$

A) 12x+12

B) 14x+12

C) 21x²-10x

D) 12x²-12

15 / 25

A(1;-2;2), B(1;4;0), C(-4;1;1) va D(-5;-5;3) nuqtalar berilgan. AC va BD vektorlar orasidagi burchakni toping

A) 80°

B) 52°

C) 90°

D) 15°

16 / 25

chiziqlar bilan chegaralangan shaklning yuzini toping

A) 2

B) √2

C) 0,5

D) 1

17 / 25

y>0 bo’lsin. To’g’riburchakning uchlari to’g’ri burchakli koordinatalar sistemasida qyuidagicha berilgan:
A(0;0), B(0;y), C(-9;y) va D(-11;0). To’rtburchak diagonallarining o’tralari orasidagi masofani toping

A) √2

B) 2

C) √22

D) 1

18 / 25

Trapetsiyaning kichik asosi 6 ga va yon tomoni 5 va 7 ga teng. Uning kata asosi ham butun son bo’lsa, perimetri eng ko’pi bilan nechaga teng bo’lishi mumkin

A) 4

B) 3

C) 1

D) 3√2

19 / 25

Hisoblang:

cos²33⁰+cos²45⁰-sin²60⁰+cos²57⁰

A) 0,5

B) 0,75

C) 2,25

D) 1,5

20 / 25

$y=6^{ln(x^{2}+5)}$ funksiyasining kamayish oralig’ini toping

A) (0;+∞)

B) ∅

C) (-∞;0]

D) (-√5;√5)

21 / 25

Funksiyaning aniqlanish sohasini toping : y=log_x-2(x²+7x-8)

A) (8;+∞)

B) (-∞;-1)U(8;+∞)

C) (2;3)U(3;+∞)

D) (-∞;-8)U(2;3)U(3;+∞)

22 / 25

Voleybol jamoasi 9 ta o’yinchidan iborat. Boshlang’ich tarkibga 6 ta o’yinchini nechta usul bilan tanlab olish mumkin

A) 168

B) 21

C) 84

D) 42

23 / 25

Tekislikdagi 1 m masofada yotgan nuqtadan ikkita teng og’ma o’tkazilgan. Agar og’malar perpendikulyar va tekislikka o’tkazilgan perpendikulyar bilan 60⁰ ga teng burchaklar tashkil etsa, og’malarning asoslari orasidagi masofani toping

A) 2√3

B) 1

C) 4√2

D) 2√2

24 / 25

integralni hisoblang