Uy » Choraklik online testlar » Matematika choraklik » 11-sinf Matematika 4-chorak Matematika choraklik 11-sinf Matematika 4-chorak InfoMaster Aprel 20, 2021 85 Ko'rishlar 83 izohlar SaqlashSaqlanganOlib tashlandi 1 2 OMAD YOR BO'LSIN! 11-sinf Matematika 4-chorak Testni Salomov Sardor tayyorladi. 1 / 25 Bir burchagi 600 bo’lgan to’g’ri burchakli uchburchakka tomoni 6 ga teng romb shunday ichki chizilganki, 600 li burchak ular uchun umumiy, rombning barcha uchlari uchburchakning tomonlarida yotadi. Uchburchak yuzini toping A) √3/2 B) (1√3)/2 C) (81√3)/2 D) (8√3)/2 2 / 25 integralni hisoblang A) 5ln2e B) 5 C) 5ln3e³ D) 5ln4e 3 / 25 f(x)=(sinx)cosx bo’lsa, f '(5π/6) ni toping A) (ln2+3)/2)*(√3^√3) B) (ln2+3)/2)*(√2^√2) C) (ln2-3)/2)*(√2^√3) D) (ln2+3)/2)*(√2^√3) 4 / 25 Voleybol jamoasi 9 ta o’yinchidan iborat. Boshlang’ich tarkibga 6 ta o’yinchini nechta usul bilan tanlab olish mumkin A) 21 B) 84 C) 42 D) 168 5 / 25 funksiyasining kamayish oralig’ini toping A) (0;+∞) B) ∅ C) (-√5;√5) D) (-∞;0] 6 / 25 Muntazam uchburchak tomoni 3 ga teng. Uchburchak tomonlari o’rtalari tutashtirilib, muntazam uchburchaklar hosil qilindi. Ichma-ich joylashgan uchburchaklar yuzlari yig’indisini toping A) 3√3 B) 2 C) 3 D) 2√3 7 / 25 (x2+23x+23)(x2+x+23)=23x2 tenglama haqiyqiy ildizlari yig’indisini toping A) -23 B) -24 C) 23 D) 24 8 / 25 Ushbu funksiyasining boshlang’ich funksiyasini toping A) lnIx-1I B) lnI(x-2)(x-3)I C) ln(|x+2|*|x+1|) D) (x+2)(x+1) 9 / 25 chiziqlar bilan chegaralangan shaklning yuzini toping A) √2 B) 2 C) 1 D) 0,5 10 / 25 cos(2arctg(1/2)) ni hisoblang A) -35/37 B) 37/35 C) 35/37 D) -37/35 11 / 25 Uchlari A(2;3;4) va B(-4;-5;-6) nuqtalarda bo’lgan AB kesmasining o’rtasining koordinatalarini toping. A) (-1;-3;-1) B) (-1;-1;-4) C) (-2;-4;-1) D) (-1;-1;-1) 12 / 25 Uchlari A(4;0;1), B(5;-2;1), C(4;8;5) nuqtalarda bo’lgan uchburchakning AL bissektrisasi uzunligini toping A) (4√2)/5 B) 4 C) (2√5)/3 D) (4√2)3 13 / 25 Funksiya hosilasini toping: A) 14x+12 B) 21x²-10x C) 12x+12 D) 12x²-12 14 / 25 f(x)=2x+3 funksiyasi uchun A(1;5) nuqtadan o’tuvchi boshlang’ich funksiyasini toping. A) F(x)=x²-3x-1 B) F(x)=x²+3x+1 C) F(x)=x²+3x-1 D) F(x)=x²-3x+1 15 / 25 f(x)=3x2-5x+4 va g(x)=4x-5 funksiyalarining urinmalari parallel bo’ladigan nuqtalarini toping. A) 1.5 B) 0 C) 2 D) 0.5 16 / 25 A(-4;3;6) nuqtaning Oxz tekisligiga nisbatan simmrtrik nuqtasini toping. A) (-8;-3;6) B) (-4;-3;6) C) (-4;-3;9) D) (-4;-6;6) 17 / 25 A(2;0;-3) va B(3;4;0) nuqtalar orasidagi masofani toping A) 16 B) √26 C) 25 D) √24 18 / 25 funksiya uchun y=2x-1 to`g`ri chiziqqa parallel bo`lgan urinma tenglamasini yozing A) y=2x-2,25 B) y=3x-2,2 C) y=2x D) y=2x+3 19 / 25 funksiya grafigiga x=1 abssisssali nuqtadao`tkazilgan urinma tenglamasini yozing A) y=x B) y=-x C) y=1/2 D) y= 2x 20 / 25 Funksiya hosilasini toping f(x)=(2x+4)(3x+1) A) 12x+14 B) 12x C) 3x+1 D) 16x+14 21 / 25 sonini taqriban hisoblang. A) 5,08 B) 4,08 C) 5,01 D) 3,08 22 / 25 f(x)=excosx funksiyasi uchun f ’(π/2) ni aniqlang. A. e-0.5π B. e0,5π C. eπ D. e-π A) e^(-0.5π) B) e^(-π) C) e^(0.5π) D) e^(π) 23 / 25 Moddiy nuqta qonuniyat bilan harakatlanmoqda, eng katta tezlanishga erishiladigan vaqtni toping. A) 4 B) 6 C) 5 D) 7 24 / 25 To’g’riburchakli parallelepiped bir uchidan chiquvchi uchta qirralari uzunliklari 4,6 va 9 ga teng. Unga tengdosh kub qirrasining uzunligini toping. A) 7 B) 6 C) 8 D) 6 25 / 25 To’g’riburchakli parallelepiped asosining tomonlari 7:24 nisbatda, diagonal kesimining yuzi 50dm2 ga teng. Yon sirtining yuzini toping. A) 224 dm² B) 135 dm² C) 124 dm² D) 124 dm 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Tomonidan Wordpress Quiz plugin Author: InfoMaster Foydali bo'lsa mamnunmiz