Uy » Choraklik online testlar » Matematika choraklik » 11-sinf Matematika 4-chorak Matematika choraklik 11-sinf Matematika 4-chorak InfoMaster Aprel 20, 2021 297 Ko'rishlar 83 izohlar SaqlashSaqlanganOlib tashlandi 4 5 OMAD YOR BO'LSIN! 11-sinf Matematika 4-chorak Testni Salomov Sardor tayyorladi. 1 / 25 sonini taqriban hisoblang. A) 5,08 B) 3,08 C) 4,08 D) 5,01 2 / 25 Havo shariga t[0;10] minut oralig’ida V(t)=t3+13t2+t+20 (m3) havo purkamoqda. t=10 minutdagi havo hajmini toping. A) 2300 B) 1023 C) 2330 D) 2025 3 / 25 f(x)=sin2x funksiyasining barcha boshlang’ich funksiyalarini toping. A) F(x)=2sin4x+c B) F(x)=-0,5cos2x+C C) F(x)=0,5cos2x+C D) F(x)=-2cos2x+C 4 / 25 f(x)=(3x+2)2 funksiyasining barcha boshlang’ich funksiyalarini toping. A) F(x)=6x³+6x+4 B) F(x)=6x³+3x²+4 C) F(x)=6x³+3x²-4 D) F(x)=6x³+6x²+4 5 / 25 Uchlari soni 14 ta, qirralari soni esa 21 ta bo’lgan ko’pyoqning yoqlari sonini toping. A) 8 B) 9 C) 16 D) 4 6 / 25 (x2+23x+23)(x2+x+23)=23x2 tenglama haqiyqiy ildizlari yig’indisini toping A) 24 B) 23 C) -23 D) -24 7 / 25 Aylanaga o’tkazilgan vatar uni 5:7 nisbatda bo’ladi. Ushbu vatarga tiralgan, aylanaga ichki chizilgan katta burchakni toping A) 125° B) 105° C) 55° D) 75° 8 / 25 Trapetsiyaning kichik asosi 6 ga va yon tomoni 5 va 7 ga teng. Uning kata asosi ham butun son bo’lsa, perimetri eng ko’pi bilan nechaga teng bo’lishi mumkin A) 3√2 B) 1 C) 3 D) 4 9 / 25 cos(2arctg(1/2)) ni hisoblang A) -37/35 B) 35/37 C) -35/37 D) 37/35 10 / 25 cos150*cos450 *cos750 ni hisoblang A) √8/2 B) √2/2 C) 2√2 D) √2 11 / 25 Agar A(1;2;3), B(3;7;6) bo’lsa, A̅B̅ vector koordinatalarini toping A) (2;5;3) B) (4;9;9) C) (-2;-5;-3) D) (4;9;9) 12 / 25 Agar f(x)=x² va bo`lsa ,f(g(-4)) ni toping A) -12 B) 12 C) 36 D) 0 13 / 25 Funksiyaning statsionar nuqtalarini toping A) x=3, x=2 B) x=-1, x=3 C) x=-1, x=2 D) x=0, x=2 14 / 25 Nargiza 4minutda 260ta so`zni terib, 7ta imloviy xatoga yo`l qo`ydi. Nargizaning matn terish sifatini aniqlang A) 0,01 B) 0,5 C) 0,0269 D) 0,6 15 / 25 funksiya uchun y=2x-1 to`g`ri chiziqqa parallel bo`lgan urinma tenglamasini yozing A) y=2x+3 B) y=2x C) y=2x-2,25 D) y=3x-2,2 16 / 25 tgx funksiya hosilasini toping A) cosx B) sinx C) 1/cos²x D) 1/sinx 17 / 25 A(1;-2;2), B(1;4;0), C(-4;1;1) va D(-5;-5;3) nuqtalar berilgan. AC va BD vektorlar orasidagi burchakni toping A) 15° B) 52° C) 90° D) 80° 18 / 25 A(-4;3;6) nuqtaning Oxz tekisligiga nisbatan simmrtrik nuqtasini toping. A) (-4;-3;9) B) (-4;-6;6) C) (-8;-3;6) D) (-4;-3;6) 19 / 25 Hisoblang: cos2330+cos2450-sin2600+cos2570 A) 0,5 B) 1,5 C) 0,75 D) 2,25 20 / 25 Bir burchagi 600 bo’lgan to’g’ri burchakli uchburchakka tomoni 6 ga teng romb shunday ichki chizilganki, 600 li burchak ular uchun umumiy, rombning barcha uchlari uchburchakning tomonlarida yotadi. Uchburchak yuzini toping A) √3/2 B) (8√3)/2 C) (1√3)/2 D) (81√3)/2 21 / 25 Tekislikdagi 1 m masofada yotgan nuqtadan ikkita teng og’ma o’tkazilgan. Agar og’malar perpendikulyar va tekislikka o’tkazilgan perpendikulyar bilan 600 ga teng burchaklar tashkil etsa, og’malarning asoslari orasidagi masofani toping A) 4√2 B) 2√2 C) 2√3 D) 1 22 / 25 Funksiyaning aniqlanish sohasini toping : y=logx-2(x2+7x-8) A) (-∞;-8)U(2;3)U(3;+∞) B) (-∞;-1)U(8;+∞) C) (2;3)U(3;+∞) D) (8;+∞) 23 / 25 B,C,D,E nuqtalar aylanadagi, A esa aylanadan tashqaridagi nuqtalar. D nuqta AE kesmada, B esa AC kesmada yotadi. Agar AE=12 va AC=16 bo’lsa, BE vatar uzunligining CD vatar uzunligiga nisbatini toping A) 3 B) 1 C) 3/4 D) 4 24 / 25 funksiyasining kamayish oralig’ini toping A) (-∞;0] B) (-√5;√5) C) (0;+∞) D) ∅ 25 / 25 x=1, y=2x va y=2-x chiziqlari bilan chegaralangan sohaning yuzini toping A) ln3 B) ln4 C) log₄e D) log₃e 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Tomonidan Wordpress Quiz plugin Author: InfoMaster Foydali bo'lsa mamnunmiz