Uy » Choraklik online testlar » Matematika choraklik » 11-sinf Matematika 4-chorak Matematika choraklik 11-sinf Matematika 4-chorak InfoMaster Aprel 20, 2021 705 Ko'rishlar 83 izohlar SaqlashSaqlanganOlib tashlandi 6 1 OMAD YOR BO'LSIN! Tomonidan yaratilgan InfoMaster 11-sinf Matematika 4-chorak Testni Salomov Sardor tayyorladi. 1 / 25 Kub to’la sirtining yuzi 105,84 sm2 bo’lsa, uning har bir yog’i yuzini va qirrasining uzunligini toping. A) 17,68 dm²; 4,2 dm B) 17,64 dm²; 4,9 dm C) 17,64 dm²; 4,2 dm D) 17,64 dm; 4,2 dm 2 / 25 f(x)=(3x+2)2 funksiyasining barcha boshlang’ich funksiyalarini toping. A) F(x)=6x³+6x+4 B) F(x)=6x³+3x²+4 C) F(x)=6x³+3x²-4 D) F(x)=6x³+6x²+4 3 / 25 Moddiy nuqta qonuniyat bilan harakatlanmoqda, eng katta tezlanishga erishiladigan vaqtni toping. A) 6 B) 4 C) 5 D) 7 4 / 25 f(x)=sin2x funksiyasining barcha boshlang’ich funksiyalarini toping. A) F(x)=0,5cos2x+C B) F(x)=-0,5cos2x+C C) F(x)=2sin4x+c D) F(x)=-2cos2x+C 5 / 25 y>0 bo’lsin. To’g’riburchakning uchlari to’g’ri burchakli koordinatalar sistemasida qyuidagicha berilgan: A(0;0), B(0;y), C(-9;y) va D(-11;0). To’rtburchak diagonallarining o’tralari orasidagi masofani toping A) √22 B) 1 C) √2 D) 2 6 / 25 Trapetsiyaning kichik asosi 6 ga va yon tomoni 5 va 7 ga teng. Uning kata asosi ham butun son bo’lsa, perimetri eng ko’pi bilan nechaga teng bo’lishi mumkin A) 3√2 B) 3 C) 4 D) 1 7 / 25 cos150*cos450 *cos750 ni hisoblang A) √2/2 B) √8/2 C) 2√2 D) √2 8 / 25 cos(2arctg(1/2)) ni hisoblang A) -35/37 B) -37/35 C) 35/37 D) 37/35 9 / 25 aniq integralni hisoblang A) 6 B) 2,5 C) 2 D) 4 10 / 25 Uchlari A(2;-3;4) va B(-2;4;5) nuqtalarda bo’lgan AB kesmasining uzunligini toping A) √55 B) √19 C) √24 D) √66 11 / 25 Funksiya hosilasini toping: A) 14x+12 B) 21x²-10x C) 12x²-12 D) 12x+12 12 / 25 funksiya uchun y=2x-1 to`g`ri chiziqqa parallel bo`lgan urinma tenglamasini yozing A) y=2x+3 B) y=3x-2,2 C) y=2x D) y=2x-2,25 13 / 25 Agar f(x)=x² va bo`lsa ,f(g(2)) ni toping A) 16 B) 36 C) 0 D) 12 14 / 25 funksiyaning [-4;2] oraliqdagi eng katta qiymatini toping A) 17 B) 14 C) 16 D) 18 15 / 25 A(1;-2;2), B(1;4;0), C(-4;1;1) va D(-5;-5;3) nuqtalar berilgan. AC va BD vektorlar orasidagi burchakni toping A) 15° B) 90° C) 80° D) 52° 16 / 25 funksiya hosilasining x0=-2 nuqtadagi qiymatini hisoblang. A) 38/31 B) -38/31 C) -38/961 D) 38/961 17 / 25 Uchlari A(4;0;1), B(5;-2;1), C(4;8;5) nuqtalarda bo’lgan uchburchakning AL bissektrisasi uzunligini toping A) (4√2)3 B) 4 C) (2√5)/3 D) (4√2)/5 18 / 25 funksiyasining kamayish oralig’ini toping. A) (-1/3;+∞) B) (-1;1/3) C) [-1;-1/3] D) (-∞;-1) 19 / 25 Agar f(x)=x² va bo`lsa ,f(g(-4)) ni toping A) -12 B) 12 C) 0 D) 36 20 / 25 f(x)=2x+3 funksiyasi uchun A(1;5) nuqtadan o’tuvchi boshlang’ich funksiyasini toping. A) F(x)=x²-3x+1 B) F(x)=x²-3x-1 C) F(x)=x²+3x-1 D) F(x)=x²+3x+1 21 / 25 Nargiza 4minutda 260ta so`zni terib, 7ta imloviy xatoga yo`l qo`ydi. Nargizaning matn terish sifatini aniqlang A) 0,5 B) 0,6 C) 0,0269 D) 0,01 22 / 25 A(2;0;-3) va B(3;4;0) nuqtalar orasidagi masofani toping A) √24 B) 25 C) √26 D) 16 23 / 25 integralni hisoblang A) 5ln4e B) 5ln2e C) 5 D) 5ln3e³ 24 / 25 y=x2-│2x-4│ funksiya grafigiga x=3 va x= -3 nuqtalarda o’tkazilgan urinmalar kesishish nuqtasi ordinatasini toping A) -6 B) -12 C) -5 D) -9 25 / 25 funksiyasining kamayish oralig’ini toping A) (0;+∞) B) (-∞;0] C) ∅ D) (-√5;√5) 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz