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11-sinf Matematika 4-chorak

InfoMaster

Aprel 20, 2021

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SaqlashSaqlanganOlib tashlandi 5

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Tomonidan yaratilgan InfoMaster

11-sinf Matematika 4-chorak

Testni Salomov Sardor tayyorladi.

1 / 25

Massasi 735 gr va konsentratsiyasi 16% bo’lgan yodning spirtdagi eritmasiga qancha toza spirt qo’shilsa, uning konsentratsiyasi 10% bo’ladi

A) 252

B) 441

C) 420

D) 256

2 / 25

$y=6^{ln(x^{2}+5)}$ funksiyasining kamayish oralig’ini toping

A) (-√5;√5)

B) ∅

C) (-∞;0]

D) (0;+∞)

3 / 25

f(x)=(sinx)^cosx bo’lsa, f '(5π/6) ni toping

A) (ln2+3)/2)*(√3^√3)

B) (ln2+3)/2)*(√2^√2)

C) (ln2+3)/2)*(√2^√3)

D) (ln2-3)/2)*(√2^√3)

4 / 25

Hisoblang:

cos²33⁰+cos²45⁰-sin²60⁰+cos²57⁰

A) 0,5

B) 2,25

C) 1,5

D) 0,75

5 / 25

Tomoni 4 ga teng bo’lgan teng tomonli uchburchak ichiga uchburchakning tomonlariga urinuvchi uchta teng doira joylashtirilgan. O’zaro urunuvchi doiralar yoylaridan hosil bo’lgan egri chiziqli uchburchakning yuzini toping

A) (2-√3)(2-π)

B) (2-√3)(2√3-π)

C) 2√3-π

D) (4-√3)(2√3-π)

6 / 25

To’g’ri to’rtburchak shaklidagi yer maydoninig atrofini o’rashmoqchi. 480 m panjara yordamida eng ko’pi bilan necha kvadrat metr yer maydonni o’rash mumkin?

A) 25600

B) 14400

C) 19600

D) 8100

7 / 25

f(x)=e^xcosx funksiyasi uchun f ’(π/2) ni aniqlang.

A. e^-0.5π B. e^0,5π C. e^π D. e^-π

A) e^(-π)

B) e^(0.5π)

C) e^(π)

D) e^(-0.5π)

8 / 25

Aylanaga o’tkazilgan vatar uni 5:7 nisbatda bo’ladi. Ushbu vatarga tiralgan, aylanaga ichki chizilgan katta burchakni toping

A) 75°

B) 105°

C) 125°

D) 55°

9 / 25

cos15⁰*cos45⁰ *cos75⁰ ni hisoblang

A) 2√2

B) √2/2

C) √8/2

D) √2

10 / 25

Ixtiyoriy kvadratga tashqi va ichki chizilgan aylanalar yuzlari nisbati a ga teng. Ixtiyoriy aylanaga ichki va tashqi chizilgan kvadratlar yuzlari nisbati b ga teng bolsa, a/b ni toping

A) 1/2

B) 1

C) 335

D) 4

11 / 25

cos(2arctg(1/2)) ni hisoblang

A) 37/35

B) -37/35

C) 35/37

D) -35/37

12 / 25

Muntazam uchburchak tomoni 3 ga teng. Uchburchak tomonlari o’rtalari tutashtirilib, muntazam uchburchaklar hosil qilindi. Ichma-ich joylashgan uchburchaklar yuzlari yig’indisini toping

A) 2

B) 2√3

C) 3√3

D) 3

13 / 25

$f(x)=x^3+2x^2+x+3$ funksiyasining kamayish oralig’ini toping.

A) (-1;1/3)

B) (-1/3;+∞)

C) [-1;-1/3]

D) (-∞;-1)

14 / 25

tgx funksiya hosilasini toping

A) 1/cos²x

B) cosx

C) 1/sinx

D) sinx

15 / 25

Uchlari A(2;-3;4) va B(-2;4;5) nuqtalarda bo’lgan AB kesmasining uzunligini toping

A) √24

B) √66

C) √55

D) √19

16 / 25

funksiyaning [-4;2] oraliqdagi eng katta qiymatini toping $f(x)=x^3+4.5x^2-9$

A) 14

B) 17

C) 18

D) 16

17 / 25

$f(x)=x^3-2x^2+3x-2$ funksiya grafigiga x=4 abssissali nuqtada o`tkazilgan urinma tenglamasini tuzing

A) y=35x+30

B) y=20x+20

C) y=35x

D) y=10x

18 / 25

Moddiy nuqtaning berilgan t vaqtdagi tezligini hisoblang: $s(t)=t^3-2t^2+t$ , t=5

A) 75

B) 90

C) 80

D) 70

19 / 25

A(-4;3;6) nuqtaning Oxz tekisligiga nisbatan simmrtrik nuqtasini toping.

A) (-4;-3;9)

B) (-8;-3;6)

C) (-4;-3;6)

D) (-4;-6;6)

20 / 25

Karim 3 minutda 213ta so`zni terib , 6ta imloviy xatoga yo`l qo`ydi. Karimning matn terish sifatini toping.

A) 0,3265

B) 0,0321

C) 0,623

D) 0,0282

21 / 25

Moddiy nuqta S(t)=5t³+3t²+2t+4 qonuniyat bilan harakatlanayotgan jismning t=2 sekunddagi tezligini toping.

A) 74

B) 70

C) 84

D) 60

22 / 25

Funksiyaning kamayish oraliqlarini toping

A) (-1;0) va (0;2)

B) (-3;0) va (0;1)

C) (-2;0) va (0;1)

D) (-1;0) va (0;1)

23 / 25

Koordinatalar boshidan y=x²-4x+3 parabolaning simmetriya o’qigacha bo’lgan masofani toping.

A) 1

B) 2

C) 4

D) 3

24 / 25

$f(x)=x^3-2x^2$ funksiya grafigiga x=1 abssisssali nuqtadao`tkazilgan urinma tenglamasini yozing

A) y=-x

B) y=x

C) y=1/2

D) y= 2x

25 / 25

A(1;-2;2), B(1;4;0), C(-4;1;1) va D(-5;-5;3) nuqtalar berilgan. AC va BD vektorlar orasidagi burchakni toping

A) 90°

B) 52°

C) 80°

D) 15°

Baholash mezoni

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71%-85% 4 baho

56%-70% 3 baho

55% va kamiga 2 baho

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11-sinf Matematika 4-chorak

Baholash mezoni

86%-100% 5 baho

71%-85% 4 baho

56%-70% 3 baho

55% va kamiga 2 baho

Author: InfoMaster

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Boshlang'ich sinf ATTESTATSIYA №1

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