Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 198 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 Ushbu (y6+y3+1)(y3+1)(y3-1)-y6+y3+1 ifodani soddalashtish natijasida ko’phad hosil qilindi. Uning nechta hadi bor? A) 3 B) 2 C) 4 D) 1 2 / 30 tenglamalar sistemasini yeching A) (4;–4) B) (-4;4) C) (-4;-4) D) (4;4) 3 / 30 x2-5|x|-6=0 tenglama ildizini toping A) ±6 B) ±;±6 C) -1;-6 D) -1;6 4 / 30 tenglamalar sistemasini yeching A) (4;3) B) (–4;3) C) (3;–4) D) (4;–3) 5 / 30 a=sin 1; b=sin 2; c=sin 3; d=sin 4 va e=sin 5 sonlarni kamayish tartibida joylashtiring. A) a>b>c>d>e B) b>c>a>d>e C) e>b>a>d>c D) b>a>c>d>e 6 / 30 Hisoblang. 11+192+1993+19994+199995+1999996+19999997+199999998+1999999999 A) 222222222222 B) 22222222220 C) 2222222175 D) 222220175 7 / 30 Hisoblang A) 0 B) 1 C) 2 D) -1 8 / 30 sonning oxirgi raqamini toping. A) 4 B) 6 C) 8 D) 2 9 / 30 Agar f(x)=ax3-5x2+b va bo’lsa, a ni toping. A) 1 B) 3 C) 0 D) 2 10 / 30 sistema a ning qanday qiymatida cheksiz ko’p yechimga ega? A) (-∞;6) B) (-∞;6])v[6;∞) C) 6 D) (2;∞) 11 / 30 Teng yonli uchburchakning tomonlari 5, 5 va 6 ga teng. Bu uchburchakning bissektiritsalari va medianalari kesishgan nuqtalar A) 1/6 B) 1/2 C) 1,2 D) 1 12 / 30 Hisoblang A) √3 B) 2 C) 1/2 D) √3/2 13 / 30 Agar x,y sonlar (x+5)2+(y-12)2=142 tenglikni qanoatlantirsa, x2+y2 ifodaning eng kichik qiymatini toping. A) 2 B) 1 C) √3 D) √2 14 / 30 AA1A2A3A4A5A6 muntazam oltiburchakli piramidaning hajmi ga va balandligi 2 ga teng bo‘lsa, u holda AA2A6 kesim yuzini toping. A) √15 B) 2 C) √5 D) 3 15 / 30 Arifmetik progressiyada a17=33 va a45=89. Progressiyaning birinchi hadi hamda ayirmasining o’rta geometrigini toping. A) √2 B) 2√2 C) 4 D) 2 16 / 30 To’g’ri burchakli uchburchakning yuzi 24 ga, katetlaridan biri 6 ga teng bo’lsa, gipotenuzasini toping A) 11 B) 12 C) √46 D) 10 17 / 30 Fazoda (1;2;3) nuqtalardan o’tuvchi to’g’ri chiziq tenglamasini tuzing. A) -x-y+z=0 B) x-1/2=y-2/3=z-3/4 C) x=y/3=z/2 D) 2x+3y+z=0 18 / 30 sistemada xy ning qiymatini toping. A) 60 B) 75 C) 80 D) 64 19 / 30 Ushbu funksiyaning boshlang’ich funksiyasini toping. A) ln|x+4/x-1|+c B) ln|x-1/x+4|+c C) ln(|x+4+|x-1|)+c D) ln(|x+4*|x-1|)+c 20 / 30 Qaysi javobda faqat juft funksiyalar ko’rsatilgan? A) 3, 4 B) 1, 3 C) 2, 3 D) 1,4 21 / 30 y=cos(2sinx) funksiyaning qiymatlar sohasini toping. A) [-1;1] B) [cos2;1] C) [0;1] D) [0;cos2] 22 / 30 7 sonini uchta natural sonlar yig’indisi ko’rinishida necha xil usulda yozish mumkin? A) 6 B) 3 C) 5 D) 4 23 / 30 To’rtburchakli muntazam piramidaning yon qirrasidagi ikki yoqli burchak 120 ga teng. Diagonal kesimining yuzasi S ga teng bo’lsa, uning yon sirtini toping. A) 0,5S B) 4S C) 2S D) 3S 24 / 30 Bir vaqtning o’zida 9,13, . . . ,405 va 15,21, . . . ,255 ketma–ketliklarning hadlari bo’lgan sonlarning eng kattasi va eng kichigining ayirmasini toping A) 150 B) 147 C) 231 D) 228 25 / 30 Tengsizlik nechta butun yechimga ega? A) 4 B) 1 C) 3 D) cheksiz ko’p 26 / 30 sistemadan x+y+z ning qiymatini toping. A) 150/41 B) 139/41 C) -139/41 D) 140/41 27 / 30 Hisoblang. A) 2/17 B) 15/34 C) 2/34 D) 17/34 28 / 30 Muntazam uchburchakli piramidaning yon qirrasi asos tekisligi bilan 45o li burchak tashkil etgan bo‘lsa, u holda piramidaning yon sirti yuzining uning asosi yuziga nisbatini toping. A) 2√5 B) 4 C) 2√3 D) 3√3 29 / 30 Agar arctga+ arctgb + arctgc= bo’lsa, a+b+c ni toping. A) abc B) ab C) ab/c D) 1 30 / 30 Soddalashtiring. (0<m<7) A) 7-2m B) m C) 7 D) 2m-7 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz