Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 168 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 a=sin 1; b=sin 2; c=sin 3; d=sin 4 va e=sin 5 sonlarni kamayish tartibida joylashtiring. A) b>c>a>d>e B) e>b>a>d>c C) a>b>c>d>e D) b>a>c>d>e 2 / 30 Agar x,y sonlar (x+5)2+(y-12)2=142 tenglikni qanoatlantirsa, x2+y2 ifodaning eng kichik qiymatini toping. A) 2 B) 1 C) √3 D) √2 3 / 30 Parallelogrammning tomonlari nisbati 3:5 kabi. Agar parallelogrmmning perimetri 48 ga burchaklaridan biri 1200 ga teng bo’lsa, uning yuzini toping. A) 135√3/4 B) 67,5 C) 67,5√3 D) 48√3 4 / 30 Hisoblang. A) 2/34 B) 17/34 C) 15/34 D) 2/17 5 / 30 m ning qanday eng katta butun qiymatida y=2x-mx-5+m funksiyaning grafigi 1,3,4 –choraklarda yotadi? A) 1 B) 5 C) 3 D) 2 6 / 30 funksiya uchun quyidagi mulohazalardan qaysi biri o’rinli? A) toq funksiya B) bunday funksiya mavjud emas C) juft ham emas, toq ham emas funksiya D) juft funksiya 7 / 30 Tenglamaning ildizlari yig`indisini toping. A) 3 B) 5 C) 4 D) 6 8 / 30 a(x+2)=2x+1 tenglama a ning qanday qiymatida yechimga ega emas? A) (-∞;2) B) (2;∞) C) (-∞;2)v(2;∞) D) (∞;∞) 9 / 30 Soat 3:37 bo’lganda minut va soat millari orasidagi burchakni toping. A) 113° B) 113,5° C) 100° D) 112,5° 10 / 30 Agar arctga+ arctgb + arctgc= bo’lsa, a+b+c ni toping. A) abc B) ab/c C) ab D) 1 11 / 30 Parallelogrammning yuzi 213 ga, tomonlaridan biri 7 ga va o’tkir burchagi 600 ga teng bo’lsa, ikkinchi tomonini toping A) 5 B) 4 C) 6 D) 8 12 / 30 sistema a ning qanday qiymatida cheksiz ko’p yechimga ega? A) (-∞;6) B) 6 C) (-∞;6])v[6;∞) D) (2;∞) 13 / 30 Rombning yuzi 96 ga, dioganallaridan biri 16 ga teng. Romb tomonini toping. A) 11 B) 9 C) 12 D) 10 14 / 30 Tomoni 2 ga teng kvadratga tashqi chizilgan aylana uzunligini toping. A) 4π B) 2π/3 C) 2π D) 3π 15 / 30 x2-5|x|-6=0 tenglama ildizini toping A) ±;±6 B) -1;-6 C) ±6 D) -1;6 16 / 30 Agar f(x)=ax3-5x2+b va bo’lsa, a ni toping. A) 0 B) 2 C) 1 D) 3 17 / 30 Yuzasi 10 ga teng bo’lgan kvadratning ketma-ket ikki uchidan o’tuvchi aylana chizilgan. Uchinchi uchidan aylanaga urunma o’tkazilgan. Urunma tomondan ikki marta katta bo’lsa, aylana radiusini toping. A) 10 B) 4 C) 6 D) 5 18 / 30 bo’lsa ni toping. Bunda funksiya f(x) ga teskari funksiya. A) -4 B) -10 C) -12 D) -14 19 / 30 Agar sinx+cosx=a bo’lsa, ning qiymatini toping. A) -1/2 B) 2/5 C) 1/3 D) 1/2 20 / 30 Sin9x =4sin3x tenglamani yeching A) π/2+πn, n€Ζ B) πn/3, n€Ζ C) π/3+πn, n€Ζ D) πn, n€Ζ 21 / 30 “Tutgan balig‘ining og‘irligi qancha?” degan savolga baliqchi: “Baliqning dumi 3 kg, boshi uning dumi hamda tanasi yarmining og‘irligiga teng, tanasi esa boshi va dumining og‘irligiga teng”, deb javob berdi. Baliqning og‘irligini (kg) toping. A) 3 B) 18 C) 12 D) 6 22 / 30 A) 2 B) 3 C) 1 D) 5 23 / 30 sonning oxirgi raqamini toping. A) 4 B) 6 C) 2 D) 8 24 / 30 Quyidagi 2x-y+3z=2018 va x+5y+z=2019 tekisliklarning holatini aniqlang. A) aniqlab bo’lmaydi B) o’zaro parallel C) o’zaro perpendikulyar D) ayqash 25 / 30 To’rtburchakli muntazam piramidaning yon qirrasidagi ikki yoqli burchak 120 ga teng. Diagonal kesimining yuzasi S ga teng bo’lsa, uning yon sirtini toping. A) 3S B) 4S C) 0,5S D) 2S 26 / 30 integralning qiymatini toping. A) 0 B) -π/2 C) π/4 D) π/2 27 / 30 To‘g‘ri to‘rtburchakning eni 25% ga orttirildi, bo‘yi esa 25% ga kamaytirildi. Natijada uning yuzi qanday o‘zgardi? A) o‘zgarmaydi B) 6,25% ga ortadi C) 2,5% ga ortadi D) 6,25% ga kamayadi 28 / 30 sistema yagona yechimga ega bo’ladigan a ning barcha qiymatlari to’plamini toping. A) {-1;3} B) {-1;2} C) {1;2} D) {2;4} 29 / 30 Hisoblang A) √3 B) √3/2 C) 2 D) 1/2 30 / 30 y= funktsiyaning aniqlanish sohasini toping. A) (2;∞) B) [2;∞) C) (-∞;2)v(2;∞) D) (-∞;2) 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
