Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 227 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 Markazi nuqtada bo‘lgan aylanaga va urinmalar o‘tkazilgan bo’lib, va nuqtalar urinish nuqtalari bo’lsin. Aylanadagi Q nuqtadan o‘tkazilgan uchinchi urinma va kesmalarni X va Y nuqtalarda kesib o‘tadi. Agar uchburchakka ichki chizilgan aylana markazi bo‘lsa, u holda burchakni toping. A) 90° B) 72° C) 60° D) 30° 2 / 30 Arifmetik progressiyada a17=33 va a45=89. Progressiyaning birinchi hadi hamda ayirmasining o’rta geometrigini toping. A) √2 B) 4 C) 2 D) 2√2 3 / 30 Bir vaqtning o’zida 9,13, . . . ,405 va 15,21, . . . ,255 ketma–ketliklarning hadlari bo’lgan sonlarning eng kattasi va eng kichigining ayirmasini toping A) 150 B) 231 C) 147 D) 228 4 / 30 sin2x-cos2x=1 tenglama [-π; 2π] oraliqda nechta ildizga ega? A) 7 B) 9 C) 6 D) 10 5 / 30 a ning 7x-a-13=(a-5)(x+7) tenglama yechimga ega bo’lmaydigan qiymatining natural bo’luvchilar sonini toping. A) 12 B) 8 C) 6 D) 4 6 / 30 ABC muntazam uchburchak ichidan ixtiyoriy P nuqta olinib, undan BC, CA va AB tomonlarga mos ravishda PD, PE va PF perpendikulyarlar tushirilgan bo’lsa,ni toping. A) 0,5 B) 1/√2 C) 1/√3 D) 1 7 / 30 Konsert zalining birinchi qatorida 40 ta o’rindiq bor. Har bir keyingi qatordagi o’rindiqlar soni oldingi qatordan 4 ga ko’p. Agar konsert zalida jami 40 ta qator bo’lsa, u holda shu zaldagi barcha o’rindiqlar sonini toping. A) 4720 B) 4680 C) 4760 D) 4716 8 / 30 Perimetri 60 ga teng bo’lgan parallelogrammning tomonlari nisbati 2:3 ga, o’tkir burchagi esa 300 ga teng. Parallelogrammning yuzini toping. A) 48√3 B) 54 C) 52√3 D) 108 9 / 30 Hisoblang A) √3 B) 3√3 C) 1 D) 2√3 10 / 30 funktsiyaning aniqlanish sohasini toping. A) (1;2) B) [1;2] C) (-∞;1)v(2;∞) D) (-∞;1]v[2;∞) 11 / 30 Parallelogrammning tomonlari nisbati 3:5 kabi. Agar parallelogrmmning perimetri 48 ga burchaklaridan biri 1200 ga teng bo’lsa, uning yuzini toping. A) 67,5 B) 135√3/4 C) 48√3 D) 67,5√3 12 / 30 Tomoni 12 ga teng bo`lgan teng tomonli uchburchakga ichki chizilgan aylana uzunligini toping. A) 4√3π B) 2√3π C) 3π D) 12π 13 / 30 Tenglamaning ildizlari yig`indisini toping. A) 3 B) 4 C) 5 D) 6 14 / 30 Hisoblang A) -1 B) 2 C) 0 D) 1 15 / 30 A) √6 B) 2 C) 1 D) 0 16 / 30 sistemadan x+y+z ning qiymatini toping. A) -139/41 B) 150/41 C) 139/41 D) 140/41 17 / 30 Agar bank qo’yilgan pulga 40% yillik bersa, qo’yilgan 4500 so’m pul bir yildan so’ng qancha bo’ladi? A) 6100 B) 6000 C) 6300 D) 6200 18 / 30 Agar funksiya berilgan bo’lsa, u holda M=ning qiymatini toping. A) e⁻⁵⁰⁵⁰ B) e⁴⁹⁵⁰ C) e⁵⁰⁵⁰ D) e⁻⁴⁹⁵⁰ 19 / 30 Tenglamani yeching. |x2-11x+10|=x2-11x+10 A) (-∞;1]v[10;∞) B) [10;∞) C) 1; 10 D) (-∞;1] 20 / 30 Radiusi 25 bo’lgan doirada 48 ga teng vatar o’tkazilgan. Doira markazidan shu vatargacha masofani toping. A) 9 B) 8 C) 7 D) 10 21 / 30 Tenglamaning nechta ildizi bor? |x+1|=|2x-1| A) 4 B) 3 C) 1 D) 2 22 / 30 Quyidagi 2x-y+3z=2018 va x+5y+z=2019 tekisliklarning holatini aniqlang. A) aniqlab bo’lmaydi B) o’zaro parallel C) o’zaro perpendikulyar D) ayqash 23 / 30 ifodaning qiymatini toping. A) -0,5 B) 0,5 C) 0 D) -2 24 / 30 Teng yonli trpetsiyaning asoslari 15 va 25 ga balandligi esa 15 ga teng trapetsiyaning dioganalini toping A) 25 B) 30 C) 28 D) 20 25 / 30 AA1A2A3A4A5A6 muntazam oltiburchakli piramidaning hajmi ga va balandligi 2 ga teng bo‘lsa, u holda AA2A6 kesim yuzini toping. A) 2 B) √5 C) √15 D) 3 26 / 30 ABCD to’gri to’rtburchak ichidan olingan O nuqtadan A, B, C, D uchlarigacha bo’lgan masofalar mos ravishda 3, 4, 5, 6 ga teng bo’lsa, u holda AB tomon uzunligini toping. A) √7 B) bunday to’gri to’rtburchak mavjud emas C) √37 D) 2 27 / 30 Ifodani soddalashtiring. [ln(ln x)-ln(loge10)].log10e A) lg(lg x) B) ln(ln x) C) ln(lg x) D) lg(ln x) 28 / 30 ABCD kvadrat ichidan olingan O nuqtadan A, B, C uchlarigacha bo’lgan masofalar mos ravishda 3, 4, 5 ga teng bo’lsa, u holda OD kesma uzunligini toping. A) 6 B) √37 C) √32 D) 3 29 / 30 Soddalashtiring. (0<m<7) A) 7 B) 2m-7 C) m D) 7-2m 30 / 30 Ikki burchagi graduslari yig’indisi uchinchi burchagi gradusidan katta bo’lgan uchburchaklar sonini toping. A) 1 B) 2019 C) cheksiz ko’p D) 0 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
