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Matematika abituriyent testi №1

InfoMaster

Aprel 5, 2022

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Matematika abituriyentlar uchun №1

1 / 30

O’q kesimining diagonallari o’zaro perpendikulyar bo’lgan kesik konus yasovchisi va asos tekisligi orasidagi burchak ga teng. Agar o’q kesimining diagonali ga teng bo’lsa, kesik konus asosining yuzini toping.

A) πa²(1+2cosα/4sin²)

B) πa²(1-2sinα/4sin²)

C) πa²/4sin²α

D) πa²/4cos²α

2 / 30

Agar x,y sonlar (x+5)²+(y-12)²=14² tenglikni qanoatlantirsa, x²+y² ifodaning eng kichik qiymatini toping.

A) 2

B) 1

C) √2

D) √3

3 / 30

Soddalashtiring.

A) 2019

B) 2018

C) 2018a/a+1

D) a+1

4 / 30

sistemada xy ning qiymatini toping.

A) 80

B) 64

C) 75

D) 60

5 / 30

Tenglamani yeching.

|x²-11x+10|=x²-11x+10

A) (-∞;1]v[10;∞)

B) 1; 10

C) [10;∞)

D) (-∞;1]

6 / 30

Anvar tub son o’yladi va o’ylagan sonini 5 ga ko’paytirib, 8 ni ayirgan edi, yana tub son hosil bo’ldi. Anvar qanday son o’ylagan?

A) 374389

B) 412967

C) aniqlab bo’lmaydi

D) 2

7 / 30

To‘g‘ri to‘rtburchakning eni 25% ga orttirildi, bo‘yi esa 25% ga kamaytirildi. Natijada uning yuzi qanday o‘zgardi?

A) 6,25% ga kamayadi

B) 2,5% ga ortadi

C) o‘zgarmaydi

D) 6,25% ga ortadi

8 / 30

Agar f(x)=ax³-5x²+b va bo’lsa, a ni toping.

A) 3

B) 1

C) 0

D) 2

9 / 30

x(t)=t²+6t+5 qonuniyat bo’yicha harakatlanayotgan moddiy nuqta harakat boshlangandan necha sekund o’tgach boshlang’ich nuqtaga nisbatan 77 metr masofaga siljiydi?

A) 8

B) 6

C) 7

D) 10

10 / 30

integralning qiymatini toping.

A) 0

B) π/4

C) -π/2

D) π/2

11 / 30

Fazoda (1;2;3) nuqtalardan o’tuvchi to’g’ri chiziq tenglamasini tuzing.

A) -x-y+z=0

B) 2x+3y+z=0

C) x-1/2=y-2/3=z-3/4

D) x=y/3=z/2

12 / 30

Konsert zalining birinchi qatorida 40 ta o’rindiq bor. Har bir keyingi qatordagi o’rindiqlar soni oldingi qatordan 4 ga ko’p. Agar konsert zalida jami 40 ta qator bo’lsa, u holda shu zaldagi barcha o’rindiqlar sonini toping.

A) 4680

B) 4720

C) 4760

D) 4716

13 / 30

To’g’ri burchakli uchburchakning yuzi 24 ga, katetlaridan biri 6 ga teng bo’lsa, gipotenuzasini toping

A) 12

B) √46

C) 10

D) 11

14 / 30

Tomoni 6 ga teng bo`lgan teng tomonli uchburchakga tashqi chizilgan doiraning yuzini toping.

A) 10 π

B) 7 π

C) 12π

D) 6 π

15 / 30

Agar arctga+ arctgb + arctgc= bo’lsa, a+b+c ni toping.

A) ab/c

B) 1

C) ab

D) abc

16 / 30

y= $\sqrt{2x^{2}-4x}$ funksiyaning aniqlanish sohasini toping

A) (2;∞)

B) (0,2)

C) (-∞;0)v(2;∞)

D) (-∞;0])v[2;∞)

17 / 30

Hisoblang:

A) 1

B) -1

C) 3

D) 2

18 / 30

Teng yonli trpetsiyaning asoslari 15 va 25 ga balandligi esa 15 ga teng trapetsiyaning dioganalini toping

A) 28

B) 30

C) 20

D) 25

19 / 30

y= funktsiyaning aniqlanish sohasini toping.

A) (-∞;2)

B) (-∞;2)v(2;∞)

C) [2;∞)

D) (2;∞)

20 / 30

Bog’bon uch kun davomida o’nta daraxt ko’chati o’tqazishi lozim. Agar bog’bon bir kunda eng kamida bitta ko’chat o’tqazadigan bo’lsa, u shu ishni kunlar bo’yicha necha xil usul bilan taqsimlashi mumkin?

A) 30

B) 32

C) 36

D) 25

21 / 30

Uchburchakning balandligi 12 ga teng bo’lib, u asosni 5:16 nidbatda bo’ladi. Agar asosning uzunligi 21 ga teng bo’lsa, uchburchakning perimetrini toping

A) 108

B) 48

C) 52

D) 54

22 / 30

Yuzasi 10 ga teng bo’lgan kvadratning ketma-ket ikki uchidan o’tuvchi aylana chizilgan. Uchinchi uchidan aylanaga urunma o’tkazilgan. Urunma tomondan ikki marta katta bo’lsa, aylana radiusini toping.

A) 6

B) 5

C) 4

D) 10

23 / 30

Sin9x =4sin3x tenglamani yeching

A) π/3+πn, n€Ζ

B) π/2+πn, n€Ζ

C) πn/3, n€Ζ

D) πn, n€Ζ

24 / 30

Hisoblang

A) 1/2

B) √3

C) √3/2

D) 2

25 / 30

sistemadan x+y ning qiymatini toping.

A) 35/4

B) 12

C) 6

D) -12

26 / 30

To’g’ri burchakli uchburchakning gipotenuzasi 13 ga, katetlaridan biri 52 ga teng. Gipotenuzaga tushirilgan balandlik uzunligini toping

A) 6

B) 5

C) 4

D) 7

27 / 30

Soddalashtiring. (0<m<7)

A) 7

B) 7-2m

C) m

D) 2m-7

28 / 30

Agar f(x)=sin2x va g(x)=cos2x bo’lsa, u holda f(g(x)) funksiyaning hosilasini toping.

A) 4sin2x*cos(cos2x)

B) -4sin2x*cos(cos2x)

C) -4sin2x*cos(2cos2x)

D) 4sin2x*cos(2cos2x)

29 / 30

a ning qanday qiymatlarida ushbu 7x-a-13=(a-5)(x+7) tenglama yagona yechimga ega

A) a≠5

B) a ning bunday qiymati yo’q

C) a=12

D) a≠12

30 / 30

Agar geometrik progressiyaning ketma–ket dastlabki uchta hadining yig’indisi 62 ga, ularning o’nli logarifmlari yig’indisi 3 ga teng bo’lsa, shu geometrik progressiyaning birinchi hadini toping.

A) 50

B) 10 yoki 50

C) 2 yoki 50

D) 10