Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 137 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 4 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 y=cos(2sinx) funksiyaning qiymatlar sohasini toping. A) [cos2;1] B) [-1;1] C) [0;1] D) [0;cos2] 2 / 30 Agar x,y sonlar (x+5)2+(y-12)2=142 tenglikni qanoatlantirsa, x2+y2 ifodaning eng kichik qiymatini toping. A) √3 B) 2 C) √2 D) 1 3 / 30 Rombning yuzi 96 ga, dioganallaridan biri 16 ga teng. Romb tomonini toping. A) 12 B) 9 C) 11 D) 10 4 / 30 Bir vaqtning o’zida 9,13, . . . ,405 va 15,21, . . . ,255 ketma–ketliklarning hadlari bo’lgan sonlarning eng kattasi va eng kichigining ayirmasini toping A) 147 B) 231 C) 150 D) 228 5 / 30 Konsert zalining birinchi qatorida 40 ta o’rindiq bor. Har bir keyingi qatordagi o’rindiqlar soni oldingi qatordan 4 ga ko’p. Agar konsert zalida jami 40 ta qator bo’lsa, u holda shu zaldagi barcha o’rindiqlar sonini toping. A) 4760 B) 4716 C) 4680 D) 4720 6 / 30 Uchburchakning balandligi 12 ga teng bo’lib, u asosni 5:16 nidbatda bo’ladi. Agar asosning uzunligi 21 ga teng bo’lsa, uchburchakning perimetrini toping A) 48 B) 52 C) 108 D) 54 7 / 30 Soddalashtiring. (0<m<7) A) 2m-7 B) 7 C) 7-2m D) m 8 / 30 Soddalashtiring. A) 2018a/a+1 B) 2019 C) a+1 D) 2018 9 / 30 Parallelogrammning tomonlari nisbati 3:5 kabi. Agar parallelogrmmning perimetri 48 ga burchaklaridan biri 1200 ga teng bo’lsa, uning yuzini toping. A) 48√3 B) 67,5 C) 135√3/4 D) 67,5√3 10 / 30 Teng yonli trpetsiyaning asoslari 15 va 25 ga balandligi esa 15 ga teng trapetsiyaning dioganalini toping A) 25 B) 30 C) 28 D) 20 11 / 30 Muntazam uchburchakli piramidaning yon qirrasi asos tekisligi bilan 45o li burchak tashkil etgan bo‘lsa, u holda piramidaning yon sirti yuzining uning asosi yuziga nisbatini toping. A) 2√5 B) 4 C) 2√3 D) 3√3 12 / 30 Ostki asosining yuzi 16π ga va ustki asosining yuzi 4π ga teng bo‘lgan kesik konus berilgan. Agar kesik konusga shar ichki chizilgan bo‘lsa, u holda sharning hajmini toping. A) 64√2π/3 B) (5√3+3)π/3 C) 8√2π/5 D) 3√2π/4 13 / 30 sin2x-cos2x=1 tenglama [-π; 2π] oraliqda nechta ildizga ega? A) 7 B) 6 C) 10 D) 9 14 / 30 tenglamalar sistemasini yeching A) (4;–4) B) (-4;-4) C) (4;4) D) (-4;4) 15 / 30 Bekzodda 50 so’m va Sobirda 70 so’m pul bor edi. Anvar Bekzodga o’z pulining 10 foizini bergandan so’ng, Bekzod Sobirga pulining yarmini berdi. So’ng Sobir Anvarga pulining 10 foizini berdi. Anvar o’zidagi pullarini hisoblab, pullari dastlabki holdagi puli bilan teng ekanligini bildi. Anvarda qancha pul bo’lgan? A) 127 B) 100 C) 375 D) 400 16 / 30 Quyidagilardan qaysi biri barcha lar uchun ma’noga ega (aniqlangan)? A) (512-1/2⁻⁹)° B) 4k+1/1/8:7-1/56 C) ⁴ᴷ⁺³√-√2k+1 D) ²ᴷ⁺⁴v2k+1/k²+1 17 / 30 Agar sinx+cosx=a bo’lsa, ning qiymatini toping. A) 2/5 B) 1/2 C) 1/3 D) -1/2 18 / 30 Musobaqada 5 ta ishtirokchidan 3 tasiga 1, 2, 3-o’rinlarni necha xil usulda berish mumkin? A) 47 B) 120 C) 60 D) 18 19 / 30 Ifodani soddalashtiring. [ln(ln x)-ln(loge10)].log10e A) ln(lg x) B) ln(ln x) C) lg(ln x) D) lg(lg x) 20 / 30 A) 5 B) 1 C) 2 D) 3 21 / 30 x(t)=t2+6t+5 qonuniyat bo’yicha harakatlanayotgan moddiy nuqta harakat boshlangandan necha sekund o’tgach boshlang’ich nuqtaga nisbatan 77 metr masofaga siljiydi? A) 7 B) 8 C) 10 D) 6 22 / 30 Tomoni 12 ga teng bo`lgan teng tomonli uchburchakga ichki chizilgan aylana uzunligini toping. A) 2√3π B) 3π C) 4√3π D) 12π 23 / 30 To’rtburchakning uchi M (0, 4) ; N(-4,0) ; P(-3;2) uchlari berilgan. Agar bo’lsa, Q uchining koordinatalarini toping. A) (-7; 1) B) (7; 1) C) (-7;-1) D) (4; -3) 24 / 30 O’q kesimining diagonallari o’zaro perpendikulyar bo’lgan kesik konus yasovchisi va asos tekisligi orasidagi burchak ga teng. Agar o’q kesimining diagonali ga teng bo’lsa, kesik konus asosining yuzini toping. A) πa²(1+2cosα/4sin²) B) πa²/4sin²α C) πa²(1-2sinα/4sin²) D) πa²/4cos²α 25 / 30 |x2-5x-14|+20≥5|x+2|+4|x-7| tengsizlikni yeching. A) [1;6] B) (-∞;-6]v{2}v[12;∞) C) [-2;4]v{6} D) [2;4]v{2}v[3;∞) 26 / 30 Hisoblang: A) -1 B) 1 C) 2 D) 3 27 / 30 Agar geometrik progressiyaning ketma–ket dastlabki uchta hadining yig’indisi 62 ga, ularning o’nli logarifmlari yig’indisi 3 ga teng bo’lsa, shu geometrik progressiyaning birinchi hadini toping. A) 10 B) 50 C) 2 yoki 50 D) 10 yoki 50 28 / 30 a ning qanday qiymatlarida ushbu 7x-a-13=(a-5)(x+7) tenglama yagona yechimga ega A) a≠12 B) a ning bunday qiymati yo’q C) a≠5 D) a=12 29 / 30 ABCD to’gri to’rtburchak ichidan olingan O nuqtadan A, B, C, D uchlarigacha bo’lgan masofalar mos ravishda 1; 2; 1,5; 1,2 ga teng bo’ladigan barcha to’g’ri to’rtburchaklar sonini toping A) 0 B) cheksiz ko’p C) 1 D) 2 30 / 30 Ifodani soddalashtiring. 2 cos55o.cos40o.sin55o+cos110o.sin40o A) 0 B) 1 C) 0,5 D) 2 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
