Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 129 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 4 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 Quyidagi va to’g’ri chiziqlarning o’zaro holatini aniqlang. A) o’zaro kesishadi B) o’zaro parallel C) ayqash to’gri chiziqlar D) o’zaro perpendikulyar 2 / 30 Tenglamaning ildizlari yig’indisi va ko’paytmasining yig’indisini toping. |x+1|.|x-4|=5 A) 9 B) -6 C) 6 D) -3 3 / 30 Hisoblang A) 1 B) 2 C) -1 D) 0 4 / 30 integralning qiymatini toping. A) -π/2 B) π/4 C) 0 D) π/2 5 / 30 Agar sinx+cosx=a bo’lsa, ning qiymatini toping. A) 2/5 B) 1/2 C) 1/3 D) -1/2 6 / 30 A(2;-2,5) nuqtadan y= - 4x parabolagacha bo’lgan eng qisqa masofani toping. A) 1,5 B) √3/2 C) 1 D) √5/2 7 / 30 O’q kesimining diagonallari o’zaro perpendikulyar bo’lgan kesik konus yasovchisi va asos tekisligi orasidagi burchak ga teng. Agar o’q kesimining diagonali ga teng bo’lsa, kesik konus asosining yuzini toping. A) πa²(1-2sinα/4sin²) B) πa²/4sin²α C) πa²(1+2cosα/4sin²) D) πa²/4cos²α 8 / 30 Tomoni 2 ga teng kvadratga tashqi chizilgan aylana uzunligini toping. A) 2π/3 B) 4π C) 2π D) 3π 9 / 30 Agar va b-a=4 bo’lsa, a+b ni toping. A) 3 B) 3,5 C) 4 D) 2 10 / 30 y= funksiyaning aniqlanish sohasini toping A) (2;∞) B) (-∞;0)v(2;∞) C) (-∞;0])v[2;∞) D) (0,2) 11 / 30 Parallelogrammning tomonlari nisbati 3:5 kabi. Agar parallelogrmmning perimetri 48 ga burchaklaridan biri 1200 ga teng bo’lsa, uning yuzini toping. A) 67,5√3 B) 48√3 C) 135√3/4 D) 67,5 12 / 30 Ag ar tgα=2 bo’lsa, u holda ni hisoblang A) -10/27 B) 10/3 C) 10/27 D) -10/3 13 / 30 tenglamani yeching. A) 0 B) 2019 C) 2018 D) 2017 14 / 30 Teng yonli uchburchakning tomonlari 5, 5 va 6 ga teng. Bu uchburchakning bissektiritsalari va medianalari kesishgan nuqtalar A) 1,2 B) 1 C) 1/2 D) 1/6 15 / 30 Soddalashtiring. (0<m<7) A) 7-2m B) 7 C) m D) 2m-7 16 / 30 Ushbu arifmetik progressiyaning manfiy hadlari yig’indisini toping. A) -0,25 B) -0,75 C) -1 D) -0,5 17 / 30 Fazoda (1;2;3) nuqtalardan o’tuvchi to’g’ri chiziq tenglamasini tuzing. A) 2x+3y+z=0 B) x-1/2=y-2/3=z-3/4 C) -x-y+z=0 D) x=y/3=z/2 18 / 30 Agar f(x)=ax3-5x2+b va bo’lsa, a ni toping. A) 3 B) 1 C) 0 D) 2 19 / 30 Tenglamani yeching. |x2-11x+10|=x2-11x+10 A) (-∞;1]v[10;∞) B) [10;∞) C) (-∞;1] D) 1; 10 20 / 30 a=sin 1; b=sin 2; c=sin 3; d=sin 4 va e=sin 5 sonlarni kamayish tartibida joylashtiring. A) e>b>a>d>c B) a>b>c>d>e C) b>c>a>d>e D) b>a>c>d>e 21 / 30 Ushbu (y6+y3+1)(y3+1)(y3-1)-y6+y3+1 ifodani soddalashtish natijasida ko’phad hosil qilindi. Uning nechta hadi bor? A) 4 B) 2 C) 3 D) 1 22 / 30 Radiusi 25 bo’lgan doirada 48 ga teng vatar o’tkazilgan. Doira markazidan shu vatargacha masofani toping. A) 7 B) 8 C) 10 D) 9 23 / 30 Musobaqada 5 ta ishtirokchidan 3 tasiga 1, 2, 3-o’rinlarni necha xil usulda berish mumkin? A) 120 B) 18 C) 47 D) 60 24 / 30 AA1A2A3A4A5A6 muntazam oltiburchakli piramidaning hajmi ga va balandligi 2 ga teng bo‘lsa, u holda AA2A6 kesim yuzini toping. A) 3 B) √5 C) 2 D) √15 25 / 30 Radiusi 1 ga teng aylana uchta yoyga bo`lingan. Ularga mos markaziy burchaklar 1, 2 va 6 sonlariga proporsional. Yoylardan eng kattasining uzunligini toping. A) 2π/3 B) 3π/4 C) 4π/3 D) 3π/2 26 / 30 tenglamalar sistemasini yeching A) (–4;3) B) (4;3) C) (3;–4) D) (4;–3) 27 / 30 Tengsizlikni yeching. A) 0 B) (-1/³ √2 ;0) C) (0;+∞) D) to'g'ri javob yo'q 28 / 30 Teng yonli trpetsiyaning asoslari 15 va 25 ga balandligi esa 15 ga teng trapetsiyaning dioganalini toping A) 20 B) 28 C) 25 D) 30 29 / 30 Ifodani soddalashtiring. [ln(ln x)-ln(loge10)].log10e A) ln(lg x) B) ln(ln x) C) lg(ln x) D) lg(lg x) 30 / 30 bo’lsa, ni x orqali ifodalang. A) 25/x B) 2-x C) 2/x D) x/25 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
