Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 141 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 7 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 Agar geometrik progressiyaning ketma–ket dastlabki uchta hadining yig’indisi 62 ga, ularning o’nli logarifmlari yig’indisi 3 ga teng bo’lsa, shu geometrik progressiyaning birinchi hadini toping. A) 10 B) 2 yoki 50 C) 10 yoki 50 D) 50 2 / 30 Teng yonli uchburchakning tomonlari 5, 5 va 6 ga teng. Bu uchburchakning bissektiritsalari va medianalari kesishgan nuqtalar A) 1/2 B) 1/6 C) 1,2 D) 1 3 / 30 y=cos(2sinx) funksiyaning qiymatlar sohasini toping. A) [0;cos2] B) [0;1] C) [cos2;1] D) [-1;1] 4 / 30 AA1A2A3A4A5A6 muntazam oltiburchakli piramidaning hajmi ga va balandligi 2 ga teng bo‘lsa, u holda AA2A6 kesim yuzini toping. A) 2 B) √15 C) 3 D) √5 5 / 30 Tomoni 2 ga teng kvadratga tashqi chizilgan aylana uzunligini toping. A) 4π B) 3π C) 2π D) 2π/3 6 / 30 Ushbu (y6+y3+1)(y3+1)(y3-1)-y6+y3+1 ifodani soddalashtish natijasida ko’phad hosil qilindi. Uning nechta hadi bor? A) 1 B) 3 C) 2 D) 4 7 / 30 x(t)=t2+7t-6 qonuniyat bo’yicha harakatlanayotgan moddiy nuqtaning tezligi harakat boshlangandan necha sekund o’tgach 87 m/s ga teng bo’ladi? A) 54 B) 40 C) 50 D) 36 8 / 30 Tenglamaning nechta ildizi bor? |x+1|=|2x-1| A) 4 B) 2 C) 3 D) 1 9 / 30 To‘g‘ri to‘rtburchakning eni 25% ga orttirildi, bo‘yi esa 25% ga kamaytirildi. Natijada uning yuzi qanday o‘zgardi? A) 6,25% ga ortadi B) o‘zgarmaydi C) 2,5% ga ortadi D) 6,25% ga kamayadi 10 / 30 Rasmda ko‘rsatilgan ko‘pyoqlardan qaysi birida 4 ta yoq, 6 ta qirra bor? A) 1, 3 B) 1, 2 C) 3 D) 2 11 / 30 Tengsizlik nechta butun yechimga ega? A) 3 B) 4 C) cheksiz ko’p D) 1 12 / 30 Ikki burchagi graduslari yig’indisi uchinchi burchagi gradusidan katta bo’lgan uchburchaklar sonini toping. A) 2019 B) 0 C) cheksiz ko’p D) 1 13 / 30 Quyidagi 2x-y+3z=2018 va x+5y+z=2019 tekisliklarning holatini aniqlang. A) aniqlab bo’lmaydi B) ayqash C) o’zaro perpendikulyar D) o’zaro parallel 14 / 30 Musobaqada 5 ta ishtirokchidan 3 tasiga 1, 2, 3-o’rinlarni necha xil usulda berish mumkin? A) 120 B) 47 C) 18 D) 60 15 / 30 Markazi nuqtada bo‘lgan aylanaga va urinmalar o‘tkazilgan bo’lib, va nuqtalar urinish nuqtalari bo’lsin. Aylanadagi Q nuqtadan o‘tkazilgan uchinchi urinma va kesmalarni X va Y nuqtalarda kesib o‘tadi. Agar uchburchakka ichki chizilgan aylana markazi bo‘lsa, u holda burchakni toping. A) 30° B) 90° C) 72° D) 60° 16 / 30 x(t)=t2+6t+5 qonuniyat bo’yicha harakatlanayotgan moddiy nuqta harakat boshlangandan necha sekund o’tgach boshlang’ich nuqtaga nisbatan 77 metr masofaga siljiydi? A) 7 B) 8 C) 10 D) 6 17 / 30 ABC muntazam uchburchak ichidan ixtiyoriy P nuqta olinib, undan BC, CA va AB tomonlarga mos ravishda PD, PE va PF perpendikulyarlar tushirilgan bo’lsa,ni toping. A) 1 B) 1/√2 C) 0,5 D) 1/√3 18 / 30 a ning 7x-a-13=(a-5)(x+7) tenglama yechimga ega bo’lmaydigan qiymatining natural bo’luvchilar sonini toping. A) 4 B) 8 C) 6 D) 12 19 / 30 ABCD kvadrat ichidan olingan O nuqtadan A, B, C uchlarigacha bo’lgan masofalar mos ravishda 3, 4, 5 ga teng bo’lsa, u holda OD kesma uzunligini toping. A) √37 B) 6 C) √32 D) 3 20 / 30 tenglamalar sistemasini yeching A) (-4;4) B) (4;4) C) (4;–4) D) (-4;-4) 21 / 30 To’rtburchakli muntazam piramidaning yon qirrasidagi ikki yoqli burchak 120 ga teng. Diagonal kesimining yuzasi S ga teng bo’lsa, uning yon sirtini toping. A) 2S B) 4S C) 3S D) 0,5S 22 / 30 Agar f(x)=4x3-6x2-2x+3x .log3e bo’lsa, u holda ni toping. A) √2e B) e C) 3e D) 1 23 / 30 Ostki asosining yuzi 20π va ustki asosining yuzi 10π ga teng bo‘lgan kesik konus berilgan. Agar kesik konusga shar ichki chizilgan bo‘lsa, u holda kesik konus hajmining shar hajmiga nisbatini toping. A) 3√2+2/4 B) 3√3+1/5 C) 2√2/3 D) 5√3+3/3 24 / 30 Sin9x =4sin3x tenglamani yeching A) πn, n€Ζ B) π/3+πn, n€Ζ C) π/2+πn, n€Ζ D) πn/3, n€Ζ 25 / 30 Tengsizlikni yeching. A) (-4;2)v(2;3) B) (2;4) C) (-3;2) D) (-3;2)v(2;4) 26 / 30 O’qishni bilmaydigan bola alifbening A,A,A, N,N, S- 6 ta harflarini ixtiyoriy ravishda terib chiqadi. Bunda ANANAS so’zining hosil bo’lish ehtimolini toping. A) 5/720 B) 1/60 C) 5/24 D) 6/720 27 / 30 Soat 3:37 bo’lganda minut va soat millari orasidagi burchakni toping. A) 113° B) 112,5° C) 100° D) 113,5° 28 / 30 Tengsizlikni yeching. A) to'g'ri javob yo'q B) (0;+∞) C) (-1/³ √2 ;0) D) 0 29 / 30 Ifodani soddalashtiring. 2 cos55o.cos40o.sin55o+cos110o.sin40o A) 0 B) 2 C) 0,5 D) 1 30 / 30 O’q kesimining diagonallari o’zaro perpendikulyar bo’lgan kesik konus yasovchisi va asos tekisligi orasidagi burchak ga teng. Agar o’q kesimining diagonali ga teng bo’lsa, kesik konus asosining yuzini toping. A) πa²(1-2sinα/4sin²) B) πa²/4sin²α C) πa²/4cos²α D) πa²(1+2cosα/4sin²) 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
