Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 150 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 tenglamani yeching. A) 2019 B) 0 C) 2018 D) 2017 2 / 30 n ning qanday qiymatida ushbu 81 .82 .83 .….8n=51222 tenglik o’rinli bo’ladi? A) 12 B) 11 C) 14 D) 10 3 / 30 Arifmetik progressiyada a17=33 va a45=89. Progressiyaning birinchi hadi hamda ayirmasining o’rta geometrigini toping. A) √2 B) 4 C) 2 D) 2√2 4 / 30 Tomoni 25 ga diagonallaridan biri 4 ga teng bo’lgan rombning yuzini toping. A) 24√5 B) 16 C) 32 D) 8√5 5 / 30 Hisoblang. A) 17/34 B) 15/34 C) 2/34 D) 2/17 6 / 30 O’qishni bilmaydigan bola alifbening A,A,A, N,N, S- 6 ta harflarini ixtiyoriy ravishda terib chiqadi. Bunda ANANAS so’zining hosil bo’lish ehtimolini toping. A) 5/720 B) 6/720 C) 5/24 D) 1/60 7 / 30 sonning oxirgi raqamini toping. A) 8 B) 2 C) 4 D) 6 8 / 30 Markazi nuqtada bo‘lgan aylanaga va urinmalar o‘tkazilgan bo’lib, va nuqtalar urinish nuqtalari bo’lsin. Aylanadagi Q nuqtadan o‘tkazilgan uchinchi urinma va kesmalarni X va Y nuqtalarda kesib o‘tadi. Agar uchburchakning perimetri 48 va aylana radiusi 7 ga teng bo‘lsa, u holda kesma uzunligini toping A) 15 B) 30 C) 12 D) 25 9 / 30 Sin9x =4sin3x tenglamani yeching A) π/2+πn, n€Ζ B) πn, n€Ζ C) πn/3, n€Ζ D) π/3+πn, n€Ζ 10 / 30 a(x+2)=2x+1 tenglama a ning qanday qiymatida yechimga ega emas? A) (-∞;2) B) (∞;∞) C) (2;∞) D) (-∞;2)v(2;∞) 11 / 30 Uchburchakning balandligi 12 ga teng bo’lib, u asosni 5:16 nidbatda bo’ladi. Agar asosning uzunligi 21 ga teng bo’lsa, uchburchakning perimetrini toping A) 54 B) 48 C) 108 D) 52 12 / 30 Tengsizlik nechta butun yechimga ega? A) cheksiz ko’p B) 3 C) 4 D) 1 13 / 30 Ostki asosining yuzi 32π va ustki asosining yuzi 18π ga teng bo‘lgan kesik konus berilgan. Agar kesik konusga shar ichki chizilgan bo‘lsa, u holda sharning sirtini toping. A) 72π B) 96π C) 100π D) 56π 14 / 30 To’rtburchakning uchi M (0, 4) ; N(-4,0) ; P(-3;2) uchlari berilgan. Agar bo’lsa, Q uchining koordinatalarini toping. A) (-7;-1) B) (7; 1) C) (4; -3) D) (-7; 1) 15 / 30 Hisoblang: A) -1 B) 2 C) 1 D) 3 16 / 30 x(t)=t2+6t+5 qonuniyat bo’yicha harakatlanayotgan moddiy nuqta harakat boshlangandan necha sekund o’tgach boshlang’ich nuqtaga nisbatan 77 metr masofaga siljiydi? A) 10 B) 8 C) 6 D) 7 17 / 30 sistema yagona yechimga ega bo’ladigan a ning barcha qiymatlari to’plamini toping. A) {1;2} B) {2;4} C) {-1;3} D) {-1;2} 18 / 30 Bekzodda 50 so’m va Sobirda 70 so’m pul bor edi. Anvar Bekzodga o’z pulining 10 foizini bergandan so’ng, Bekzod Sobirga pulining yarmini berdi. So’ng Sobir Anvarga pulining 10 foizini berdi. Anvar o’zidagi pullarini hisoblab, pullari dastlabki holdagi puli bilan teng ekanligini bildi. Anvarda qancha pul bo’lgan? A) 127 B) 400 C) 375 D) 100 19 / 30 Ushbu (y6+y3+1)(y3+1)(y3-1)-y6+y3+1 ifodani soddalashtish natijasida ko’phad hosil qilindi. Uning nechta hadi bor? A) 3 B) 1 C) 4 D) 2 20 / 30 Parallelogrammning tomonlari nisbati 3:5 kabi. Agar parallelogrmmning perimetri 48 ga burchaklaridan biri 1200 ga teng bo’lsa, uning yuzini toping. A) 48√3 B) 67,5 C) 135√3/4 D) 67,5√3 21 / 30 Tomoni 6 ga teng bo`lgan teng tomonli uchburchakga tashqi chizilgan doiraning yuzini toping. A) 6 π B) 10 π C) 12π D) 7 π 22 / 30 Radiusi 25 bo’lgan doirada 48 ga teng vatar o’tkazilgan. Doira markazidan shu vatargacha masofani toping. A) 8 B) 7 C) 10 D) 9 23 / 30 Soddalashtiring. (0<m<7) A) 2m-7 B) 7-2m C) m D) 7 24 / 30 Ikki burchagi graduslari yig’indisi uchinchi burchagi gradusidan katta bo’lgan uchburchaklar sonini toping. A) 0 B) cheksiz ko’p C) 2019 D) 1 25 / 30 Ikki burchagi graduslari yig’indisi uchinchi burchagi gradusiga teng bo’lgan uchburchak qanday uchburchak deyiladi? A) o’tkir burchakli uchburchak B) to’gri burchakli uchburchak C) o’tmas burchakli uchburchak D) teng tomonli uchburchak 26 / 30 Ifodani soddalashtiring. [ln(ln x)-ln(loge10)].log10e A) lg(lg x) B) lg(ln x) C) ln(lg x) D) ln(ln x) 27 / 30 Quyidagilardan qaysi biri barcha lar uchun ma’noga ega (aniqlangan)? A) (512-1/2⁻⁹)° B) 4k+1/1/8:7-1/56 C) ⁴ᴷ⁺³√-√2k+1 D) ²ᴷ⁺⁴v2k+1/k²+1 28 / 30 Hisoblang. 11+192+1993+19994+199995+1999996+19999997+199999998+1999999999 A) 222220175 B) 2222222175 C) 22222222220 D) 222222222222 29 / 30 a ning 7x-a-13=(a-5)(x+7) tenglama yechimga ega bo’lmaydigan qiymatining natural bo’luvchilar sonini toping. A) 12 B) 6 C) 8 D) 4 30 / 30 integralning qiymatini toping. A) -π/2 B) 0 C) π/4 D) π/2 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
