Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 221 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 8 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 Bankda qo`yilgan pul bir yildan kegin foydasi bilan 2600 so`m bo`ldi; Agar bank yillik 30% foyda to`lasa, boshida qancha pul qo`yilgan bo`ladi ? A) 1900 B) 2100 C) 2200 D) 2000 2 / 30 Tengsizlikni yeching. A) to'g'ri javob yo'q B) 0 C) (0;+∞) D) (-1/³ √2 ;0) 3 / 30 A) 2 B) 3 C) 1 D) 5 4 / 30 Ushbu (y6+y3+1)(y3+1)(y3-1)-y6+y3+1 ifodani soddalashtish natijasida ko’phad hosil qilindi. Uning nechta hadi bor? A) 1 B) 3 C) 4 D) 2 5 / 30 Agar f(x)=4x3-6x2-2x+3x .log3e bo’lsa, u holda ni toping. A) 1 B) e C) √2e D) 3e 6 / 30 integralning qiymatini toping. A) -π/2 B) 0 C) π/2 D) π/4 7 / 30 m ning qanday eng katta butun qiymatida y=2x-mx-5+m funksiyaning grafigi 1,3,4 –choraklarda yotadi? A) 2 B) 3 C) 5 D) 1 8 / 30 bo’lsa ni toping. Bunda funksiya f(x) ga teskari funksiya. A) -4 B) -12 C) -14 D) -10 9 / 30 Tenglamaning ildizlari yig`indisini toping. A) 5 B) 4 C) 6 D) 3 10 / 30 Tomoni 12 ga teng bo`lgan teng tomonli uchburchakga ichki chizilgan aylana uzunligini toping. A) 2√3π B) 4√3π C) 3π D) 12π 11 / 30 ifodaning qiymatini toping. A) 0,5 B) -2 C) -0,5 D) 0 12 / 30 Soddalashtiring. A) 2018a/a+1 B) a+1 C) 2018 D) 2019 13 / 30 Fazoda (1;2;3) nuqtalardan o’tuvchi to’g’ri chiziq tenglamasini tuzing. A) x=y/3=z/2 B) 2x+3y+z=0 C) -x-y+z=0 D) x-1/2=y-2/3=z-3/4 14 / 30 Radiusi 1 ga teng aylana uchta yoyga bo`lingan. Ularga mos markaziy burchaklar 1, 2 va 6 sonlariga proporsional. Yoylardan eng kattasining uzunligini toping. A) 4π/3 B) 2π/3 C) 3π/4 D) 3π/2 15 / 30 n ning qanday qiymatida ushbu 81 .82 .83 .….8n=51222 tenglik o’rinli bo’ladi? A) 11 B) 10 C) 14 D) 12 16 / 30 Tenglamaning ildizlari yig’indisi va ko’paytmasining yig’indisini toping. |x+1|.|x-4|=5 A) -6 B) 9 C) -3 D) 6 17 / 30 a=sin 1; b=sin 2; c=sin 3; d=sin 4 va e=sin 5 sonlarni kamayish tartibida joylashtiring. A) b>c>a>d>e B) b>a>c>d>e C) a>b>c>d>e D) e>b>a>d>c 18 / 30 Qaysi javobda faqat juft funksiyalar ko’rsatilgan? A) 3, 4 B) 1,4 C) 1, 3 D) 2, 3 19 / 30 Ushbu funksiyaning boshlang’ich funksiyasini toping. A) ln|x-1/x+4|+c B) ln|x+4/x-1|+c C) ln(|x+4*|x-1|)+c D) ln(|x+4+|x-1|)+c 20 / 30 To’g’ri to’rtburchakning perimetri 50 ga teng. Bir tomoni boshqa tomonidan 5 ga ko’p. To’g’ri to’rtburchakning yuzini toping. A) 50 B) 60 C) 150 D) 225 21 / 30 ABCD to’gri to’rtburchak ichidan olingan O nuqtadan A, B, C, D uchlarigacha bo’lgan masofalar mos ravishda 1; 2; 1,5; 1,2 ga teng bo’ladigan barcha to’g’ri to’rtburchaklar sonini toping A) cheksiz ko’p B) 2 C) 0 D) 1 22 / 30 Hisoblang A) 1/2 B) √3/2 C) √3 D) 2 23 / 30 Tomoni 25 ga diagonallaridan biri 4 ga teng bo’lgan rombning yuzini toping. A) 24√5 B) 16 C) 8√5 D) 32 24 / 30 Tenglamani yeching. (x+2)+(x+4)+(x+6)+…+(x+100)=2800 A) 7 B) 5 C) 3 D) 4 25 / 30 Uchburchakning balandligi 12 ga teng bo’lib, u asosni 5:16 nidbatda bo’ladi. Agar asosning uzunligi 21 ga teng bo’lsa, uchburchakning perimetrini toping A) 48 B) 54 C) 108 D) 52 26 / 30 Hisoblang A) 2 B) 1 C) -1 D) 0 27 / 30 x(t)=t2+7t-6 qonuniyat bo’yicha harakatlanayotgan moddiy nuqtaning tezligi harakat boshlangandan necha sekund o’tgach 87 m/s ga teng bo’ladi? A) 54 B) 40 C) 50 D) 36 28 / 30 sin2x-cos2x=1 tenglama [-π; 2π] oraliqda nechta ildizga ega? A) 7 B) 6 C) 10 D) 9 29 / 30 Soddalashtiring. (0<m<7) A) 2m-7 B) 7-2m C) m D) 7 30 / 30 Bog’bon uch kun davomida o’nta daraxt ko’chati o’tqazishi lozim. Agar bog’bon bir kunda eng kamida bitta ko’chat o’tqazadigan bo’lsa, u shu ishni kunlar bo’yicha necha xil usul bilan taqsimlashi mumkin? A) 36 B) 32 C) 25 D) 30 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz