Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 131 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 4 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 Markazi nuqtada bo‘lgan aylanaga va urinmalar o‘tkazilgan bo’lib, va nuqtalar urinish nuqtalari bo’lsin. Aylanadagi Q nuqtadan o‘tkazilgan uchinchi urinma va kesmalarni X va Y nuqtalarda kesib o‘tadi. Agar uchburchakka ichki chizilgan aylana markazi bo‘lsa, u holda burchakni toping. A) 30° B) 90° C) 60° D) 72° 2 / 30 Markazi nuqtada bo‘lgan aylanaga va urinmalar o‘tkazilgan bo’lib, va nuqtalar urinish nuqtalari bo’lsin. Aylanadagi Q nuqtadan o‘tkazilgan uchinchi urinma va kesmalarni X va Y nuqtalarda kesib o‘tadi. Agar uchburchakning perimetri 48 va aylana radiusi 7 ga teng bo‘lsa, u holda kesma uzunligini toping A) 30 B) 25 C) 12 D) 15 3 / 30 ABCD to’gri to’rtburchak ichidan olingan O nuqtadan A, B, C, D uchlarigacha bo’lgan masofalar mos ravishda 1; 2; 1,5; 1,2 ga teng bo’ladigan barcha to’g’ri to’rtburchaklar sonini toping A) cheksiz ko’p B) 0 C) 2 D) 1 4 / 30 Tengsizlikni yeching. A) (2;4) B) (-4;2)v(2;3) C) (-3;2)v(2;4) D) (-3;2) 5 / 30 ABCD kvadrat ichidan olingan O nuqtadan A, B, C uchlarigacha bo’lgan masofalar mos ravishda 3, 4, 5 ga teng bo’lsa, u holda OD kesma uzunligini toping. A) 6 B) √37 C) 3 D) √32 6 / 30 Quyidagilardan qaysi biri barcha lar uchun ma’noga ega (aniqlangan)? A) ²ᴷ⁺⁴v2k+1/k²+1 B) (512-1/2⁻⁹)° C) ⁴ᴷ⁺³√-√2k+1 D) 4k+1/1/8:7-1/56 7 / 30 Muntazam uchburchakli piramidaning yon qirrasi asos tekisligi bilan 45o li burchak tashkil etgan bo‘lsa, u holda piramidaning yon sirti yuzining uning asosi yuziga nisbatini toping. A) 2√5 B) 2√3 C) 4 D) 3√3 8 / 30 Agar f(x)=4x3-6x2-2x+3x .log3e bo’lsa, u holda ni toping. A) 1 B) 3e C) √2e D) e 9 / 30 ABC muntazam uchburchak ichidan ixtiyoriy P nuqta olinib, undan BC, CA va AB tomonlarga mos ravishda PD, PE va PF perpendikulyarlar tushirilgan bo’lsa,ni toping. A) 1/√2 B) 0,5 C) 1 D) 1/√3 10 / 30 Bekzodda 50 so’m va Sobirda 70 so’m pul bor edi. Anvar Bekzodga o’z pulining 10 foizini bergandan so’ng, Bekzod Sobirga pulining yarmini berdi. So’ng Sobir Anvarga pulining 10 foizini berdi. Anvar o’zidagi pullarini hisoblab, pullari dastlabki holdagi puli bilan teng ekanligini bildi. Anvarda qancha pul bo’lgan? A) 127 B) 400 C) 375 D) 100 11 / 30 Hisoblang. 11+192+1993+19994+199995+1999996+19999997+199999998+1999999999 A) 22222222220 B) 222222222222 C) 2222222175 D) 222220175 12 / 30 Tenglamaning ildizlari yig`indisini toping. A) 3 B) 5 C) 6 D) 4 13 / 30 tenglamalar sistemasini yeching A) (4;–3) B) (–4;3) C) (3;–4) D) (4;3) 14 / 30 integralning qiymatini toping. A) -π/2 B) 0 C) π/2 D) π/4 15 / 30 Ifodani soddalashtiring. 2 cos55o.cos40o.sin55o+cos110o.sin40o A) 1 B) 2 C) 0,5 D) 0 16 / 30 sistema a ning qanday qiymatida cheksiz ko’p yechimga ega? A) (-∞;6])v[6;∞) B) (2;∞) C) 6 D) (-∞;6) 17 / 30 qonuniyat bo’yicha harakatlanayotgan moddiy nuqta harakatning 200- metrida qanday tezlikka (m/s) erishadi? A) 42 B) 32 C) 36 D) 38 18 / 30 Ostki asosining yuzi 16π ga va ustki asosining yuzi 4π ga teng bo‘lgan kesik konus berilgan. Agar kesik konusga shar ichki chizilgan bo‘lsa, u holda sharning hajmini toping. A) 8√2π/5 B) 3√2π/4 C) 64√2π/3 D) (5√3+3)π/3 19 / 30 A) 0 B) 1 C) √6 D) 2 20 / 30 y= funksiyaning aniqlanish sohasini toping A) (-∞;0])v[2;∞) B) (-∞;0)v(2;∞) C) (2;∞) D) (0,2) 21 / 30 Teng yonli trpetsiyaning asoslari 15 va 25 ga balandligi esa 15 ga teng trapetsiyaning dioganalini toping A) 30 B) 28 C) 20 D) 25 22 / 30 Agar funksiya berilgan bo’lsa, u holda M=ning qiymatini toping. A) e⁴⁹⁵⁰ B) e⁻⁵⁰⁵⁰ C) e⁵⁰⁵⁰ D) e⁻⁴⁹⁵⁰ 23 / 30 Anvar tub son o’yladi va o’ylagan sonini 5 ga ko’paytirib, 8 ni ayirgan edi, yana tub son hosil bo’ldi. Anvar qanday son o’ylagan? A) 2 B) 374389 C) 412967 D) aniqlab bo’lmaydi 24 / 30 Soddalashtiring. A) 2018a/a+1 B) 2018 C) 2019 D) a+1 25 / 30 Hisoblang A) √3/2 B) 2 C) √3 D) 1/2 26 / 30 Tenglamani yeching. |x2-11x+10|=x2-11x+10 A) [10;∞) B) 1; 10 C) (-∞;1] D) (-∞;1]v[10;∞) 27 / 30 Hisoblang A) -1 B) 2 C) 0 D) 1 28 / 30 a ning 7x-a-13=(a-5)(x+7) tenglama yechimga ega bo’lmaydigan qiymatining natural bo’luvchilar sonini toping. A) 4 B) 6 C) 8 D) 12 29 / 30 a ning qanday qiymatlarida ushbu 7x-a-13=(a-5)(x+7) tenglama yagona yechimga ega A) a ning bunday qiymati yo’q B) a=12 C) a≠12 D) a≠5 30 / 30 To’g’ri to’rtburchakning perimetri 50 ga teng. Bir tomoni boshqa tomonidan 5 ga ko’p. To’g’ri to’rtburchakning yuzini toping. A) 60 B) 225 C) 150 D) 50 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
