Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 129 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 4 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 Tomoni 12 ga teng bo`lgan teng tomonli uchburchakga ichki chizilgan aylana uzunligini toping. A) 2√3π B) 4√3π C) 3π D) 12π 2 / 30 To’g’ri to’rtburchakning perimetri 50 ga teng. Bir tomoni boshqa tomonidan 5 ga ko’p. To’g’ri to’rtburchakning yuzini toping. A) 225 B) 60 C) 150 D) 50 3 / 30 Agar f(x)=sin2x va g(x)=cos2x bo’lsa, u holda f(g(x)) funksiyaning hosilasini toping. A) -4sin2x*cos(2cos2x) B) 4sin2x*cos(2cos2x) C) -4sin2x*cos(cos2x) D) 4sin2x*cos(cos2x) 4 / 30 y= funksiyaning aniqlanish sohasini toping A) (2;∞) B) (-∞;0])v[2;∞) C) (-∞;0)v(2;∞) D) (0,2) 5 / 30 Bankda qo`yilgan pul bir yildan kegin foydasi bilan 2600 so`m bo`ldi; Agar bank yillik 30% foyda to`lasa, boshida qancha pul qo`yilgan bo`ladi ? A) 2000 B) 2100 C) 1900 D) 2200 6 / 30 ABC muntazam uchburchak ichidan ixtiyoriy P nuqta olinib, undan BC, CA va AB tomonlarga mos ravishda PD, PE va PF perpendikulyarlar tushirilgan bo’lsa,ni toping. A) 1 B) 1/√3 C) 0,5 D) 1/√2 7 / 30 Tenglamaning ildizlari yig’indisi va ko’paytmasining yig’indisini toping. |x+1|.|x-4|=5 A) -3 B) 6 C) -6 D) 9 8 / 30 funksiya uchun quyidagi mulohazalardan qaysi biri o’rinli? A) juft ham emas, toq ham emas funksiya B) bunday funksiya mavjud emas C) juft funksiya D) toq funksiya 9 / 30 sonning oxirgi raqamini toping. A) 2 B) 4 C) 6 D) 8 10 / 30 sistemadan x+y ning qiymatini toping. A) 6 B) -12 C) 12 D) 35/4 11 / 30 A) 0 B) 2 C) 1 D) √6 12 / 30 Konsert zalining birinchi qatorida 40 ta o’rindiq bor. Har bir keyingi qatordagi o’rindiqlar soni oldingi qatordan 4 ga ko’p. Agar konsert zalida jami 40 ta qator bo’lsa, u holda shu zaldagi barcha o’rindiqlar sonini toping. A) 4680 B) 4716 C) 4760 D) 4720 13 / 30 a ning 7x-a-13=(a-5)(x+7) tenglama yechimga ega bo’lmaydigan qiymatining natural bo’luvchilar sonini toping. A) 4 B) 6 C) 12 D) 8 14 / 30 Tenglamaning nechta ildizi bor? |x+1|=|2x-1| A) 2 B) 4 C) 1 D) 3 15 / 30 Soddalashtiring. A) a+1 B) 2018 C) 2019 D) 2018a/a+1 16 / 30 Agar va b-a=4 bo’lsa, a+b ni toping. A) 3,5 B) 3 C) 2 D) 4 17 / 30 x(t)=t2+7t-6 qonuniyat bo’yicha harakatlanayotgan moddiy nuqtaning tezligi harakat boshlangandan necha sekund o’tgach 87 m/s ga teng bo’ladi? A) 54 B) 36 C) 40 D) 50 18 / 30 Musobaqada 5 ta ishtirokchidan 3 tasiga 1, 2, 3-o’rinlarni necha xil usulda berish mumkin? A) 60 B) 18 C) 47 D) 120 19 / 30 Agar f(x)=ax3-5x2+b va bo’lsa, a ni toping. A) 1 B) 3 C) 0 D) 2 20 / 30 Ostki asosining yuzi 32π va ustki asosining yuzi 18π ga teng bo‘lgan kesik konus berilgan. Agar kesik konusga shar ichki chizilgan bo‘lsa, u holda sharning sirtini toping. A) 100π B) 56π C) 96π D) 72π 21 / 30 Muntazam uchburchakli piramidaning yon qirrasi asos tekisligi bilan 45o li burchak tashkil etgan bo‘lsa, u holda piramidaning yon sirti yuzining uning asosi yuziga nisbatini toping. A) 3√3 B) 2√5 C) 4 D) 2√3 22 / 30 Rasmda ko‘rsatilgan ko‘pyoqlardan qaysi birida 4 ta yoq, 6 ta qirra bor? A) 1, 2 B) 3 C) 1, 3 D) 2 23 / 30 Perimetri 60 ga teng bo’lgan parallelogrammning tomonlari nisbati 2:3 ga, o’tkir burchagi esa 300 ga teng. Parallelogrammning yuzini toping. A) 52√3 B) 48√3 C) 108 D) 54 24 / 30 tenglamalar sistemasini yeching A) (–4;3) B) (4;–3) C) (3;–4) D) (4;3) 25 / 30 y= funktsiyaning aniqlanish sohasini toping. A) (2;∞) B) (-∞;2) C) [2;∞) D) (-∞;2)v(2;∞) 26 / 30 Teng yonli trpetsiyaning asoslari 15 va 25 ga balandligi esa 15 ga teng trapetsiyaning dioganalini toping A) 28 B) 30 C) 20 D) 25 27 / 30 a(x+2)=2x+1 tenglama a ning qanday qiymatida yechimga ega emas? A) (-∞;2)v(2;∞) B) (-∞;2) C) (∞;∞) D) (2;∞) 28 / 30 Ushbu (y6+y3+1)(y3+1)(y3-1)-y6+y3+1 ifodani soddalashtish natijasida ko’phad hosil qilindi. Uning nechta hadi bor? A) 4 B) 2 C) 1 D) 3 29 / 30 O’q kesimining diagonallari o’zaro perpendikulyar bo’lgan kesik konus yasovchisi va asos tekisligi orasidagi burchak ga teng. Agar o’q kesimining diagonali ga teng bo’lsa, kesik konus asosining yuzini toping. A) πa²/4sin²α B) πa²/4cos²α C) πa²(1+2cosα/4sin²) D) πa²(1-2sinα/4sin²) 30 / 30 Quyidagilardan qaysi biri barcha lar uchun ma’noga ega (aniqlangan)? A) ²ᴷ⁺⁴v2k+1/k²+1 B) 4k+1/1/8:7-1/56 C) ⁴ᴷ⁺³√-√2k+1 D) (512-1/2⁻⁹)° 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
