Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 156 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 1 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 Hisoblang A) √3/2 B) 2 C) 1/2 D) √3 2 / 30 Rasmda ko‘rsatilgan ko‘pyoqlardan qaysi birida 4 ta yoq, 6 ta qirra bor? A) 1, 3 B) 1, 2 C) 3 D) 2 3 / 30 Quyidagi 2x-y+3z=2018 va x+5y+z=2019 tekisliklarning holatini aniqlang. A) o’zaro parallel B) ayqash C) aniqlab bo’lmaydi D) o’zaro perpendikulyar 4 / 30 Agar va b-a=4 bo’lsa, a+b ni toping. A) 4 B) 2 C) 3,5 D) 3 5 / 30 To‘g‘ri to‘rtburchakning eni 25% ga orttirildi, bo‘yi esa 25% ga kamaytirildi. Natijada uning yuzi qanday o‘zgardi? A) 6,25% ga kamayadi B) o‘zgarmaydi C) 2,5% ga ortadi D) 6,25% ga ortadi 6 / 30 ifodaning qiymatini toping. A) -0,5 B) -2 C) 0 D) 0,5 7 / 30 Ushbu arifmetik progressiyaning manfiy hadlari yig’indisini toping. A) -0,5 B) -0,75 C) -0,25 D) -1 8 / 30 Tomoni 25 ga diagonallaridan biri 4 ga teng bo’lgan rombning yuzini toping. A) 32 B) 16 C) 24√5 D) 8√5 9 / 30 Tenglamani yeching. (x+2)+(x+4)+(x+6)+…+(x+100)=2800 A) 3 B) 5 C) 7 D) 4 10 / 30 Ushbu (y6+y3+1)(y3+1)(y3-1)-y6+y3+1 ifodani soddalashtish natijasida ko’phad hosil qilindi. Uning nechta hadi bor? A) 1 B) 4 C) 2 D) 3 11 / 30 sin2x-cos2x=1 tenglama [-π; 2π] oraliqda nechta ildizga ega? A) 9 B) 6 C) 7 D) 10 12 / 30 Agar x,y sonlar (x+5)2+(y-12)2=142 tenglikni qanoatlantirsa, x2+y2 ifodaning eng kichik qiymatini toping. A) √2 B) √3 C) 1 D) 2 13 / 30 Tengsizlikni yeching. A) (-1/³ √2 ;0) B) 0 C) to'g'ri javob yo'q D) (0;+∞) 14 / 30 Parallelogrammning yuzi 213 ga, tomonlaridan biri 7 ga va o’tkir burchagi 600 ga teng bo’lsa, ikkinchi tomonini toping A) 6 B) 8 C) 5 D) 4 15 / 30 x(t)=t2+7t-6 qonuniyat bo’yicha harakatlanayotgan moddiy nuqtaning tezligi harakat boshlangandan necha sekund o’tgach 87 m/s ga teng bo’ladi? A) 50 B) 40 C) 36 D) 54 16 / 30 Ostki asosining yuzi 16π ga va ustki asosining yuzi 4π ga teng bo‘lgan kesik konus berilgan. Agar kesik konusga shar ichki chizilgan bo‘lsa, u holda sharning hajmini toping. A) 64√2π/3 B) (5√3+3)π/3 C) 8√2π/5 D) 3√2π/4 17 / 30 O’qishni bilmaydigan bola alifbening A,A,A, N,N, S- 6 ta harflarini ixtiyoriy ravishda terib chiqadi. Bunda ANANAS so’zining hosil bo’lish ehtimolini toping. A) 5/24 B) 1/60 C) 5/720 D) 6/720 18 / 30 Ifodani soddalashtiring. [ln(ln x)-ln(loge10)].log10e A) ln(lg x) B) lg(ln x) C) lg(lg x) D) ln(ln x) 19 / 30 Uchburchakning balandligi 12 ga teng bo’lib, u asosni 5:16 nidbatda bo’ladi. Agar asosning uzunligi 21 ga teng bo’lsa, uchburchakning perimetrini toping A) 54 B) 108 C) 48 D) 52 20 / 30 tenglamani yeching. A) 0 B) 2018 C) 2019 D) 2017 21 / 30 Agar f(x)=4x3-6x2-2x+3x .log3e bo’lsa, u holda ni toping. A) e B) 1 C) √2e D) 3e 22 / 30 Tomoni 12 ga teng bo`lgan teng tomonli uchburchakga ichki chizilgan aylana uzunligini toping. A) 2√3π B) 12π C) 3π D) 4√3π 23 / 30 funksiya uchun quyidagi mulohazalardan qaysi biri o’rinli? A) bunday funksiya mavjud emas B) toq funksiya C) juft funksiya D) juft ham emas, toq ham emas funksiya 24 / 30 Hisoblang: A) 3 B) 2 C) -1 D) 1 25 / 30 A) 1 B) 2 C) 5 D) 3 26 / 30 Quyidagilardan qaysi biri barcha lar uchun ma’noga ega (aniqlangan)? A) 4k+1/1/8:7-1/56 B) ²ᴷ⁺⁴v2k+1/k²+1 C) (512-1/2⁻⁹)° D) ⁴ᴷ⁺³√-√2k+1 27 / 30 ABCD to’gri to’rtburchak ichidan olingan O nuqtadan A, B, C, D uchlarigacha bo’lgan masofalar mos ravishda 3, 4, 5, 6 ga teng bo’lsa, u holda AB tomon uzunligini toping. A) 2 B) √7 C) bunday to’gri to’rtburchak mavjud emas D) √37 28 / 30 A) 2 B) 1 C) √6 D) 0 29 / 30 Qaysi javobda faqat juft funksiyalar ko’rsatilgan? A) 1, 3 B) 1,4 C) 3, 4 D) 2, 3 30 / 30 Tenglamaning ildizlari yig`indisini toping. A) 4 B) 3 C) 5 D) 6 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
