Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 141 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 7 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 Bir vaqtning o’zida 9,13, . . . ,405 va 15,21, . . . ,255 ketma–ketliklarning hadlari bo’lgan sonlarning eng kattasi va eng kichigining ayirmasini toping A) 231 B) 150 C) 228 D) 147 2 / 30 Quyidagi 2x-y+3z=2018 va x+5y+z=2019 tekisliklarning holatini aniqlang. A) o’zaro perpendikulyar B) o’zaro parallel C) aniqlab bo’lmaydi D) ayqash 3 / 30 Ushbu arifmetik progressiyaning manfiy hadlari yig’indisini toping. A) -0,25 B) -1 C) -0,5 D) -0,75 4 / 30 ABC muntazam uchburchak ichidan ixtiyoriy P nuqta olinib, undan BC, CA va AB tomonlarga mos ravishda PD, PE va PF perpendikulyarlar tushirilgan bo’lsa,ni toping. A) 0,5 B) 1/√3 C) 1 D) 1/√2 5 / 30 Uchburchakning balandligi 12 ga teng bo’lib, u asosni 5:16 nidbatda bo’ladi. Agar asosning uzunligi 21 ga teng bo’lsa, uchburchakning perimetrini toping A) 48 B) 54 C) 52 D) 108 6 / 30 A) 0 B) 2 C) √6 D) 1 7 / 30 Agar funksiya berilgan bo’lsa, u holda M=ning qiymatini toping. A) e⁻⁴⁹⁵⁰ B) e⁵⁰⁵⁰ C) e⁻⁵⁰⁵⁰ D) e⁴⁹⁵⁰ 8 / 30 Tenglamaning nechta ildizi bor? |x+1|=|2x-1| A) 4 B) 2 C) 1 D) 3 9 / 30 y= funksiyaning aniqlanish sohasini toping A) (0,2) B) (-∞;0)v(2;∞) C) (-∞;0])v[2;∞) D) (2;∞) 10 / 30 x2-5|x|-6=0 tenglama ildizini toping A) -1;-6 B) -1;6 C) ±6 D) ±;±6 11 / 30 Soddalashtiring. A) 2018 B) a+1 C) 2018a/a+1 D) 2019 12 / 30 Arifmetik progressiyada a17=33 va a45=89. Progressiyaning birinchi hadi hamda ayirmasining o’rta geometrigini toping. A) √2 B) 2√2 C) 4 D) 2 13 / 30 Tomoni 25 ga diagonallaridan biri 4 ga teng bo’lgan rombning yuzini toping. A) 8√5 B) 24√5 C) 16 D) 32 14 / 30 Teng yonli uchburchakning tomonlari 5, 5 va 6 ga teng. Bu uchburchakning bissektiritsalari va medianalari kesishgan nuqtalar A) 1 B) 1/2 C) 1/6 D) 1,2 15 / 30 x(t)=t2+7t-6 qonuniyat bo’yicha harakatlanayotgan moddiy nuqtaning tezligi harakat boshlangandan necha sekund o’tgach 87 m/s ga teng bo’ladi? A) 54 B) 50 C) 40 D) 36 16 / 30 To’rtburchakli muntazam piramidaning yon qirrasidagi ikki yoqli burchak 120 ga teng. Diagonal kesimining yuzasi S ga teng bo’lsa, uning yon sirtini toping. A) 2S B) 4S C) 3S D) 0,5S 17 / 30 integralning qiymatini toping. A) π/2 B) π/4 C) -π/2 D) 0 18 / 30 Agar f(x)=4x3-6x2-2x+3x .log3e bo’lsa, u holda ni toping. A) 3e B) 1 C) √2e D) e 19 / 30 sistemadan x+y+z ning qiymatini toping. A) 150/41 B) 140/41 C) 139/41 D) -139/41 20 / 30 Sin9x =4sin3x tenglamani yeching A) πn, n€Ζ B) π/2+πn, n€Ζ C) πn/3, n€Ζ D) π/3+πn, n€Ζ 21 / 30 sistemada xy ning qiymatini toping. A) 80 B) 64 C) 60 D) 75 22 / 30 a(x+2)=2x+1 tenglama a ning qanday qiymatida yechimga ega emas? A) (2;∞) B) (-∞;2) C) (-∞;2)v(2;∞) D) (∞;∞) 23 / 30 Soddalashtiring. (0<m<7) A) m B) 7 C) 7-2m D) 2m-7 24 / 30 Yuzasi 10 ga teng bo’lgan kvadratning ketma-ket ikki uchidan o’tuvchi aylana chizilgan. Uchinchi uchidan aylanaga urunma o’tkazilgan. Urunma tomondan ikki marta katta bo’lsa, aylana radiusini toping. A) 6 B) 10 C) 5 D) 4 25 / 30 Konsert zalining birinchi qatorida 40 ta o’rindiq bor. Har bir keyingi qatordagi o’rindiqlar soni oldingi qatordan 4 ga ko’p. Agar konsert zalida jami 40 ta qator bo’lsa, u holda shu zaldagi barcha o’rindiqlar sonini toping. A) 4716 B) 4720 C) 4760 D) 4680 26 / 30 Parallelogrammning tomonlari nisbati 3:5 kabi. Agar parallelogrmmning perimetri 48 ga burchaklaridan biri 1200 ga teng bo’lsa, uning yuzini toping. A) 67,5√3 B) 67,5 C) 135√3/4 D) 48√3 27 / 30 bo’lsa ni toping. Bunda funksiya f(x) ga teskari funksiya. A) -10 B) -4 C) -14 D) -12 28 / 30 x(t)=t2+6t+5 qonuniyat bo’yicha harakatlanayotgan moddiy nuqta harakat boshlangandan necha sekund o’tgach boshlang’ich nuqtaga nisbatan 77 metr masofaga siljiydi? A) 8 B) 7 C) 10 D) 6 29 / 30 ABCD to’gri to’rtburchak ichidan olingan O nuqtadan A, B, C, D uchlarigacha bo’lgan masofalar mos ravishda 3, 4, 5, 6 ga teng bo’lsa, u holda AB tomon uzunligini toping. A) √7 B) √37 C) 2 D) bunday to’gri to’rtburchak mavjud emas 30 / 30 Anvar tub son o’yladi va o’ylagan sonini 5 ga ko’paytirib, 8 ni ayirgan edi, yana tub son hosil bo’ldi. Anvar qanday son o’ylagan? A) 2 B) 412967 C) aniqlab bo’lmaydi D) 374389 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz