Barcha fanlardan online testlar

Matematika abituriyent testi №1

InfoMaster

Aprel 5, 2022

188 Ko'rishlar 1 izoh

SaqlashSaqlanganOlib tashlandi 0

Tomonidan yaratilgan InfoMaster

Matematika abituriyentlar uchun №1

1 / 30

Tomoni 2 ga teng kvadratga tashqi chizilgan aylana uzunligini toping.

A) 2π

B) 3π

C) 4π

D) 2π/3

2 / 30

To’g’ri burchakli uchburchakning gipotenuzasi 13 ga, katetlaridan biri 52 ga teng. Gipotenuzaga tushirilgan balandlik uzunligini toping

A) 6

B) 7

C) 4

D) 5

3 / 30

Hisoblang.

A) 15/34

B) 2/17

C) 17/34

D) 2/34

4 / 30

Ushbu arifmetik progressiyaning manfiy hadlari yig’indisini toping.

A) -0,75

B) -0,5

C) -1

D) -0,25

5 / 30

A(2;-2,5) nuqtadan y= - 4x parabolagacha bo’lgan eng qisqa masofani toping.

A) √3/2

B) 1,5

C) 1

D) √5/2

6 / 30

Arifmetik progressiyada a₁₇=33 va a₄₅=89. Progressiyaning birinchi hadi hamda ayirmasining o’rta geometrigini toping.

A) 4

B) 2

C) 2√2

D) √2

7 / 30

Radiusi 1 ga teng aylana uchta yoyga bo`lingan. Ularga mos markaziy burchaklar 1, 2 va 6 sonlariga proporsional. Yoylardan eng kattasining uzunligini toping.

A) 4π/3

B) 3π/4

C) 2π/3

D) 3π/2

8 / 30

Teng yonli trpetsiyaning asoslari 15 va 25 ga balandligi esa 15 ga teng trapetsiyaning dioganalini toping

A) 30

B) 28

C) 20

D) 25

9 / 30

Agar va b-a=4 bo’lsa, a+b ni toping.

A) 4

B) 3

C) 2

D) 3,5

10 / 30

bo’lsa ni toping. Bunda funksiya f(x) ga teskari funksiya.

A) -4

B) -10

C) -12

D) -14

11 / 30

tenglamalar sistemasini yeching

A) (-4;-4)

B) (4;4)

C) (-4;4)

D) (4;–4)

12 / 30

Agar arctga+ arctgb + arctgc= bo’lsa, a+b+c ni toping.

A) 1

B) abc

C) ab

D) ab/c

13 / 30

A) 3

B) 1

C) 2

D) 5

14 / 30

Hisoblang:

A) 1

B) -1

C) 2

D) 3

15 / 30

Qaysi javobda faqat juft funksiyalar ko’rsatilgan?

A) 2, 3

B) 1,4

C) 3, 4

D) 1, 3

16 / 30

Tomoni 12 ga teng bo`lgan teng tomonli uchburchakga ichki chizilgan aylana uzunligini toping.

A) 2√3π

B) 4√3π

C) 3π

D) 12π

17 / 30

Yuzasi 10 ga teng bo’lgan kvadratning ketma-ket ikki uchidan o’tuvchi aylana chizilgan. Uchinchi uchidan aylanaga urunma o’tkazilgan. Urunma tomondan ikki marta katta bo’lsa, aylana radiusini toping.

A) 6

B) 4

C) 10

D) 5

18 / 30

Agar f(x)=sin2x va g(x)=cos2x bo’lsa, u holda f(g(x)) funksiyaning hosilasini toping.

A) -4sin2x*cos(cos2x)

B) 4sin2x*cos(2cos2x)

C) 4sin2x*cos(cos2x)

D) -4sin2x*cos(2cos2x)

19 / 30

a(x+2)=2x+1 tenglama a ning qanday qiymatida yechimga ega emas?

A) (-∞;2)v(2;∞)

B) (∞;∞)

C) (-∞;2)

D) (2;∞)

20 / 30

Quyidagilardan qaysi biri barcha lar uchun ma’noga ega (aniqlangan)?

A) (512-1/2⁻⁹)°

B) ²ᴷ⁺⁴v2k+1/k²+1

C) ⁴ᴷ⁺³√-√2k+1

D) 4k+1/1/8:7-1/56

21 / 30

Parallelogrammning yuzi 213 ga, tomonlaridan biri 7 ga va o’tkir burchagi 60⁰ ga teng bo’lsa, ikkinchi tomonini toping

A) 8

B) 6

C) 4

D) 5

22 / 30

ABCD kvadrat ichidan olingan O nuqtadan A, B, C uchlarigacha bo’lgan masofalar mos ravishda 3, 4, 5 ga teng bo’lsa, u holda OD kesma uzunligini toping.

A) √37

B) 6

C) 3

D) √32

23 / 30

tenglamani yeching.

A) 2019

B) 2018

C) 2017

D) 0

24 / 30

Markazi nuqtada bo‘lgan aylanaga va urinmalar o‘tkazilgan bo’lib, va nuqtalar urinish nuqtalari bo’lsin. Aylanadagi Q nuqtadan o‘tkazilgan uchinchi urinma va kesmalarni X va Y nuqtalarda kesib o‘tadi. Agar uchburchakka ichki chizilgan aylana markazi bo‘lsa, u holda burchakni toping.

A) 90°

B) 60°

C) 72°

D) 30°

25 / 30

|x²-5x-14|+20≥5|x+2|+4|x-7| tengsizlikni yeching.

A) [1;6]

B) [-2;4]v{6}

C) [2;4]v{2}v[3;∞)

D) (-∞;-6]v{2}v[12;∞)

26 / 30

sistema yagona yechimga ega bo’ladigan a ning barcha qiymatlari to’plamini toping.

A) {-1;3}

B) {1;2}

C) {2;4}

D) {-1;2}

27 / 30

ifodaning qiymatini toping.

A) -2

B) -0,5

C) 0

D) 0,5

28 / 30

Agar geometrik progressiyaning ketma–ket dastlabki uchta hadining yig’indisi 62 ga, ularning o’nli logarifmlari yig’indisi 3 ga teng bo’lsa, shu geometrik progressiyaning birinchi hadini toping.

A) 2 yoki 50

B) 10

C) 10 yoki 50

D) 50

29 / 30

Tenglamani yeching.

|x²-11x+10|=x²-11x+10

A) (-∞;1]v[10;∞)

B) [10;∞)

C) (-∞;1]

D) 1; 10

30 / 30