Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 194 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 Soddalashtiring. (0<m<7) A) 7-2m B) 2m-7 C) m D) 7 2 / 30 ABCD to’gri to’rtburchak ichidan olingan O nuqtadan A, B, C, D uchlarigacha bo’lgan masofalar mos ravishda 1; 2; 1,5; 1,2 ga teng bo’ladigan barcha to’g’ri to’rtburchaklar sonini toping A) 1 B) cheksiz ko’p C) 2 D) 0 3 / 30 Ostki asosining yuzi 20π va ustki asosining yuzi 10π ga teng bo‘lgan kesik konus berilgan. Agar kesik konusga shar ichki chizilgan bo‘lsa, u holda kesik konus hajmining shar hajmiga nisbatini toping. A) 3√3+1/5 B) 3√2+2/4 C) 2√2/3 D) 5√3+3/3 4 / 30 y=cos(2sinx) funksiyaning qiymatlar sohasini toping. A) [0;cos2] B) [cos2;1] C) [0;1] D) [-1;1] 5 / 30 Soat 3:37 bo’lganda minut va soat millari orasidagi burchakni toping. A) 112,5° B) 113,5° C) 113° D) 100° 6 / 30 Tengsizlikni yeching. A) (2;4) B) (-3;2)v(2;4) C) (-4;2)v(2;3) D) (-3;2) 7 / 30 tenglamani yeching. A) 0 B) 2017 C) 2019 D) 2018 8 / 30 Agar bank qo`yilgan pulga 40% yillik foyda bersa, qo`yilgan 5000 so`m pul bir yildan keyin qancha bo`ladi ? A) 7000 B) 6900 C) 7200 D) 6200 9 / 30 tenglamalar sistemasini yeching A) (4;–3) B) (4;3) C) (3;–4) D) (–4;3) 10 / 30 a=sin 1; b=sin 2; c=sin 3; d=sin 4 va e=sin 5 sonlarni kamayish tartibida joylashtiring. A) e>b>a>d>c B) b>c>a>d>e C) b>a>c>d>e D) a>b>c>d>e 11 / 30 tenglamalar sistemasini yeching A) (4;–4) B) (-4;4) C) (-4;-4) D) (4;4) 12 / 30 Quyidagilardan qaysi biri barcha lar uchun ma’noga ega (aniqlangan)? A) 4k+1/1/8:7-1/56 B) (512-1/2⁻⁹)° C) ⁴ᴷ⁺³√-√2k+1 D) ²ᴷ⁺⁴v2k+1/k²+1 13 / 30 sin2x-cos2x=1 tenglama [-π; 2π] oraliqda nechta ildizga ega? A) 10 B) 7 C) 6 D) 9 14 / 30 a(x+2)=2x+1 tenglama a ning qanday qiymatida yechimga ega emas? A) (-∞;2) B) (∞;∞) C) (-∞;2)v(2;∞) D) (2;∞) 15 / 30 Quyidagi 2x-y+3z=2018 va x+5y+z=2019 tekisliklarning holatini aniqlang. A) aniqlab bo’lmaydi B) o’zaro perpendikulyar C) o’zaro parallel D) ayqash 16 / 30 Ostki asosining yuzi 16π ga va ustki asosining yuzi 4π ga teng bo‘lgan kesik konus berilgan. Agar kesik konusga shar ichki chizilgan bo‘lsa, u holda sharning hajmini toping. A) 64√2π/3 B) 3√2π/4 C) (5√3+3)π/3 D) 8√2π/5 17 / 30 Agar f(x)=4x3-6x2-2x+3x .log3e bo’lsa, u holda ni toping. A) √2e B) 3e C) e D) 1 18 / 30 x2-5|x|-6=0 tenglama ildizini toping A) -1;-6 B) ±6 C) ±;±6 D) -1;6 19 / 30 Hisoblang A) √3 B) √3/2 C) 1/2 D) 2 20 / 30 Hisoblang: A) 1 B) -1 C) 3 D) 2 21 / 30 sistema a ning qanday qiymatida cheksiz ko’p yechimga ega? A) (2;∞) B) (-∞;6) C) (-∞;6])v[6;∞) D) 6 22 / 30 Ushbu (y6+y3+1)(y3+1)(y3-1)-y6+y3+1 ifodani soddalashtish natijasida ko’phad hosil qilindi. Uning nechta hadi bor? A) 1 B) 3 C) 4 D) 2 23 / 30 To’rtburchakli muntazam piramidaning yon qirrasidagi ikki yoqli burchak 120 ga teng. Diagonal kesimining yuzasi S ga teng bo’lsa, uning yon sirtini toping. A) 4S B) 3S C) 0,5S D) 2S 24 / 30 Perimetri 60 ga teng bo’lgan parallelogrammning tomonlari nisbati 2:3 ga, o’tkir burchagi esa 300 ga teng. Parallelogrammning yuzini toping. A) 108 B) 52√3 C) 48√3 D) 54 25 / 30 sistema yagona yechimga ega bo’ladigan a ning barcha qiymatlari to’plamini toping. A) {2;4} B) {-1;3} C) {1;2} D) {-1;2} 26 / 30 Uchburchakning balandligi 12 ga teng bo’lib, u asosni 5:16 nidbatda bo’ladi. Agar asosning uzunligi 21 ga teng bo’lsa, uchburchakning perimetrini toping A) 48 B) 54 C) 52 D) 108 27 / 30 A) 0 B) 2 C) 1 D) √6 28 / 30 Ag ar tgα=2 bo’lsa, u holda ni hisoblang A) -10/3 B) -10/27 C) 10/27 D) 10/3 29 / 30 x(t)=t2+7t-6 qonuniyat bo’yicha harakatlanayotgan moddiy nuqtaning tezligi harakat boshlangandan necha sekund o’tgach 87 m/s ga teng bo’ladi? A) 40 B) 50 C) 36 D) 54 30 / 30 Agar funksiya berilgan bo’lsa, u holda M=ning qiymatini toping. A) e⁴⁹⁵⁰ B) e⁻⁵⁰⁵⁰ C) e⁵⁰⁵⁰ D) e⁻⁴⁹⁵⁰ 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
