Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 206 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 5 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 AA1A2A3A4A5A6 muntazam oltiburchakli piramidaning hajmi ga va balandligi 2 ga teng bo‘lsa, u holda AA2A6 kesim yuzini toping. A) √15 B) 2 C) 3 D) √5 2 / 30 Uchburchakning balandligi 12 ga teng bo’lib, u asosni 5:16 nidbatda bo’ladi. Agar asosning uzunligi 21 ga teng bo’lsa, uchburchakning perimetrini toping A) 48 B) 52 C) 108 D) 54 3 / 30 Bir vaqtning o’zida 9,13, . . . ,405 va 15,21, . . . ,255 ketma–ketliklarning hadlari bo’lgan sonlarning eng kattasi va eng kichigining ayirmasini toping A) 228 B) 231 C) 150 D) 147 4 / 30 (-3;4) nuqtaga absissa, ordinata o’qlariga va koordinata boshiga nisbatan simmetrik bo’lgan nuqtalarni tutashtirishdan hosil bo’lgan uchburchakning eng kata tomonini toping. A) 10 B) 12 C) 24 D) 14 5 / 30 funktsiyaning aniqlanish sohasini toping. A) (1;2) B) [1;2] C) (-∞;1)v(2;∞) D) (-∞;1]v[2;∞) 6 / 30 sistema yagona yechimga ega bo’ladigan a ning barcha qiymatlari to’plamini toping. A) {-1;2} B) {1;2} C) {2;4} D) {-1;3} 7 / 30 Ag ar tgα=2 bo’lsa, u holda ni hisoblang A) -10/3 B) -10/27 C) 10/3 D) 10/27 8 / 30 To‘g‘ri to‘rtburchakning eni 25% ga orttirildi, bo‘yi esa 25% ga kamaytirildi. Natijada uning yuzi qanday o‘zgardi? A) 2,5% ga ortadi B) 6,25% ga ortadi C) 6,25% ga kamayadi D) o‘zgarmaydi 9 / 30 Agar geometrik progressiyaning ketma–ket dastlabki uchta hadining yig’indisi 62 ga, ularning o’nli logarifmlari yig’indisi 3 ga teng bo’lsa, shu geometrik progressiyaning birinchi hadini toping. A) 2 yoki 50 B) 10 yoki 50 C) 10 D) 50 10 / 30 Muntazam uchburchakli piramidaning yon qirrasi asos tekisligi bilan 45o li burchak tashkil etgan bo‘lsa, u holda piramidaning yon sirti yuzining uning asosi yuziga nisbatini toping. A) 2√5 B) 4 C) 2√3 D) 3√3 11 / 30 Radiuslari orasidagi burchagi 36o va radiusi 5 ga teng bo`lgan sektor yoyining uzunligini toping. A) 2π B) π C) 2π/3 D) π/2 12 / 30 funksiya uchun quyidagi mulohazalardan qaysi biri o’rinli? A) toq funksiya B) juft ham emas, toq ham emas funksiya C) juft funksiya D) bunday funksiya mavjud emas 13 / 30 tenglamalar sistemasini yeching A) (4;–4) B) (-4;4) C) (4;4) D) (-4;-4) 14 / 30 Ifodani soddalashtiring. 2 cos55o.cos40o.sin55o+cos110o.sin40o A) 2 B) 0,5 C) 0 D) 1 15 / 30 Agar va b-a=4 bo’lsa, a+b ni toping. A) 2 B) 3,5 C) 4 D) 3 16 / 30 Konsert zalining birinchi qatorida 40 ta o’rindiq bor. Har bir keyingi qatordagi o’rindiqlar soni oldingi qatordan 4 ga ko’p. Agar konsert zalida jami 40 ta qator bo’lsa, u holda shu zaldagi barcha o’rindiqlar sonini toping. A) 4760 B) 4716 C) 4680 D) 4720 17 / 30 Ostki asosining yuzi 20π va ustki asosining yuzi 10π ga teng bo‘lgan kesik konus berilgan. Agar kesik konusga shar ichki chizilgan bo‘lsa, u holda kesik konus hajmining shar hajmiga nisbatini toping. A) 5√3+3/3 B) 2√2/3 C) 3√2+2/4 D) 3√3+1/5 18 / 30 x2-5|x|-6=0 tenglama ildizini toping A) -1;-6 B) ±6 C) -1;6 D) ±;±6 19 / 30 Agar f(x)=4x3-6x2-2x+3x .log3e bo’lsa, u holda ni toping. A) 3e B) √2e C) 1 D) e 20 / 30 Radiusi 1 ga teng aylana uchta yoyga bo`lingan. Ularga mos markaziy burchaklar 1, 2 va 6 sonlariga proporsional. Yoylardan eng kattasining uzunligini toping. A) 4π/3 B) 3π/2 C) 2π/3 D) 3π/4 21 / 30 Perimetri 60 ga teng bo’lgan parallelogrammning tomonlari nisbati 2:3 ga, o’tkir burchagi esa 300 ga teng. Parallelogrammning yuzini toping. A) 54 B) 52√3 C) 108 D) 48√3 22 / 30 x(t)=t2+6t+5 qonuniyat bo’yicha harakatlanayotgan moddiy nuqta harakat boshlangandan necha sekund o’tgach boshlang’ich nuqtaga nisbatan 77 metr masofaga siljiydi? A) 7 B) 8 C) 10 D) 6 23 / 30 Tomoni 12 ga teng bo`lgan teng tomonli uchburchakga ichki chizilgan aylana uzunligini toping. A) 2√3π B) 3π C) 4√3π D) 12π 24 / 30 To’rtburchakli muntazam piramidaning yon qirrasidagi ikki yoqli burchak 120 ga teng. Diagonal kesimining yuzasi S ga teng bo’lsa, uning yon sirtini toping. A) 0,5S B) 4S C) 3S D) 2S 25 / 30 Hisoblang. A) 15/34 B) 17/34 C) 2/17 D) 2/34 26 / 30 Sin9x =4sin3x tenglamani yeching A) πn, n€Ζ B) π/3+πn, n€Ζ C) π/2+πn, n€Ζ D) πn/3, n€Ζ 27 / 30 sonning oxirgi raqamini toping. A) 4 B) 6 C) 2 D) 8 28 / 30 Tenglamani yeching. (x+2)+(x+4)+(x+6)+…+(x+100)=2800 A) 4 B) 7 C) 5 D) 3 29 / 30 Quyidagi va to’g’ri chiziqlarning o’zaro holatini aniqlang. A) o’zaro parallel B) o’zaro perpendikulyar C) ayqash to’gri chiziqlar D) o’zaro kesishadi 30 / 30 Agar f(x)=sin2x va g(x)=cos2x bo’lsa, u holda f(g(x)) funksiyaning hosilasini toping. A) -4sin2x*cos(2cos2x) B) 4sin2x*cos(cos2x) C) -4sin2x*cos(cos2x) D) 4sin2x*cos(2cos2x) 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
