Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 154 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 sistema yagona yechimga ega bo’ladigan a ning barcha qiymatlari to’plamini toping. A) {-1;3} B) {1;2} C) {-1;2} D) {2;4} 2 / 30 Ushbu funksiyaning boshlang’ich funksiyasini toping. A) ln|x+4/x-1|+c B) ln|x-1/x+4|+c C) ln(|x+4*|x-1|)+c D) ln(|x+4+|x-1|)+c 3 / 30 Quyidagi 2x-y+3z=2018 va x+5y+z=2019 tekisliklarning holatini aniqlang. A) o’zaro perpendikulyar B) o’zaro parallel C) ayqash D) aniqlab bo’lmaydi 4 / 30 Anvar tub son o’yladi va o’ylagan sonini 5 ga ko’paytirib, 8 ni ayirgan edi, yana tub son hosil bo’ldi. Anvar qanday son o’ylagan? A) 412967 B) 374389 C) aniqlab bo’lmaydi D) 2 5 / 30 To‘g‘ri to‘rtburchakning eni 25% ga orttirildi, bo‘yi esa 25% ga kamaytirildi. Natijada uning yuzi qanday o‘zgardi? A) o‘zgarmaydi B) 6,25% ga kamayadi C) 2,5% ga ortadi D) 6,25% ga ortadi 6 / 30 To’g’ri to’rtburchakning perimetri 50 ga teng. Bir tomoni boshqa tomonidan 5 ga ko’p. To’g’ri to’rtburchakning yuzini toping. A) 60 B) 225 C) 150 D) 50 7 / 30 Hisoblang A) 1/2 B) √3 C) √3/2 D) 2 8 / 30 tenglamalar sistemasini yeching A) (-4;-4) B) (4;4) C) (4;–4) D) (-4;4) 9 / 30 A(2;-2,5) nuqtadan y= - 4x parabolagacha bo’lgan eng qisqa masofani toping. A) 1 B) √3/2 C) 1,5 D) √5/2 10 / 30 funktsiyaning aniqlanish sohasini toping. A) (-∞;1]v[2;∞) B) [1;2] C) (1;2) D) (-∞;1)v(2;∞) 11 / 30 Tomoni 12 ga teng bo`lgan teng tomonli uchburchakga ichki chizilgan aylana uzunligini toping. A) 12π B) 2√3π C) 4√3π D) 3π 12 / 30 Tengsizlik nechta butun yechimga ega? A) 3 B) 1 C) 4 D) cheksiz ko’p 13 / 30 Arifmetik progressiyada a17=33 va a45=89. Progressiyaning birinchi hadi hamda ayirmasining o’rta geometrigini toping. A) √2 B) 2√2 C) 2 D) 4 14 / 30 200 kishidan iborat turistlar guruxida 140 kishi ingliz tilini, 90 kishi nemis tilini va 46 kishi ikkala tilni biladi. Ikkala tilni xam bilmaydigan turistlar necha foizni tashkil qiladi. A) 4 B) 16 C) 12 D) 8 15 / 30 Agar geometrik progressiyaning ketma–ket dastlabki uchta hadining yig’indisi 62 ga, ularning o’nli logarifmlari yig’indisi 3 ga teng bo’lsa, shu geometrik progressiyaning birinchi hadini toping. A) 10 yoki 50 B) 50 C) 10 D) 2 yoki 50 16 / 30 Qaysi javobda faqat juft funksiyalar ko’rsatilgan? A) 1,4 B) 1, 3 C) 3, 4 D) 2, 3 17 / 30 Hisoblang: A) 3 B) -1 C) 1 D) 2 18 / 30 Bekzodda 50 so’m va Sobirda 70 so’m pul bor edi. Anvar Bekzodga o’z pulining 10 foizini bergandan so’ng, Bekzod Sobirga pulining yarmini berdi. So’ng Sobir Anvarga pulining 10 foizini berdi. Anvar o’zidagi pullarini hisoblab, pullari dastlabki holdagi puli bilan teng ekanligini bildi. Anvarda qancha pul bo’lgan? A) 375 B) 100 C) 127 D) 400 19 / 30 |x2-5x-14|+20≥5|x+2|+4|x-7| tengsizlikni yeching. A) [2;4]v{2}v[3;∞) B) [1;6] C) (-∞;-6]v{2}v[12;∞) D) [-2;4]v{6} 20 / 30 Ifodani soddalashtiring. [ln(ln x)-ln(loge10)].log10e A) lg(lg x) B) ln(ln x) C) lg(ln x) D) ln(lg x) 21 / 30 a ning qanday qiymatlarida ushbu 7x-a-13=(a-5)(x+7) tenglama yagona yechimga ega A) a≠12 B) a ning bunday qiymati yo’q C) a=12 D) a≠5 22 / 30 Hisoblang A) 1 B) -1 C) 2 D) 0 23 / 30 Rombning yuzi 96 ga, dioganallaridan biri 16 ga teng. Romb tomonini toping. A) 9 B) 12 C) 10 D) 11 24 / 30 Sin9x =4sin3x tenglamani yeching A) πn, n€Ζ B) πn/3, n€Ζ C) π/3+πn, n€Ζ D) π/2+πn, n€Ζ 25 / 30 tenglamani yeching. A) 2017 B) 0 C) 2019 D) 2018 26 / 30 7 sonini uchta natural sonlar yig’indisi ko’rinishida necha xil usulda yozish mumkin? A) 3 B) 6 C) 5 D) 4 27 / 30 Soddalashtiring. (0<m<7) A) 2m-7 B) 7-2m C) m D) 7 28 / 30 Ag ar tgα=2 bo’lsa, u holda ni hisoblang A) 10/27 B) -10/27 C) -10/3 D) 10/3 29 / 30 Agar f(x)=ax3-5x2+b va bo’lsa, a ni toping. A) 2 B) 0 C) 3 D) 1 30 / 30 n ning qanday qiymatida ushbu 81 .82 .83 .….8n=51222 tenglik o’rinli bo’ladi? A) 10 B) 11 C) 12 D) 14 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
