Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 153 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 ABCD to’gri to’rtburchak ichidan olingan O nuqtadan A, B, C, D uchlarigacha bo’lgan masofalar mos ravishda 3, 4, 5, 6 ga teng bo’lsa, u holda AB tomon uzunligini toping. A) √7 B) 2 C) bunday to’gri to’rtburchak mavjud emas D) √37 2 / 30 Ostki asosining yuzi 16π ga va ustki asosining yuzi 4π ga teng bo‘lgan kesik konus berilgan. Agar kesik konusga shar ichki chizilgan bo‘lsa, u holda sharning hajmini toping. A) 3√2π/4 B) (5√3+3)π/3 C) 64√2π/3 D) 8√2π/5 3 / 30 Anvar tub son o’yladi va o’ylagan sonini 5 ga ko’paytirib, 8 ni ayirgan edi, yana tub son hosil bo’ldi. Anvar qanday son o’ylagan? A) 2 B) aniqlab bo’lmaydi C) 374389 D) 412967 4 / 30 Agar bank qo`yilgan pulga 40% yillik foyda bersa, qo`yilgan 5000 so`m pul bir yildan keyin qancha bo`ladi ? A) 6200 B) 7200 C) 7000 D) 6900 5 / 30 To’rtburchakning uchi M (0, 4) ; N(-4,0) ; P(-3;2) uchlari berilgan. Agar bo’lsa, Q uchining koordinatalarini toping. A) (7; 1) B) (4; -3) C) (-7; 1) D) (-7;-1) 6 / 30 Rombning yuzi 96 ga, dioganallaridan biri 16 ga teng. Romb tomonini toping. A) 9 B) 10 C) 12 D) 11 7 / 30 To‘g‘ri to‘rtburchakning eni 25% ga orttirildi, bo‘yi esa 25% ga kamaytirildi. Natijada uning yuzi qanday o‘zgardi? A) 2,5% ga ortadi B) 6,25% ga kamayadi C) 6,25% ga ortadi D) o‘zgarmaydi 8 / 30 Tenglamaning ildizlari yig`indisini toping. A) 4 B) 5 C) 3 D) 6 9 / 30 Agar sinx+cosx=a bo’lsa, ning qiymatini toping. A) 2/5 B) -1/2 C) 1/3 D) 1/2 10 / 30 Tenglamani yeching. (x+2)+(x+4)+(x+6)+…+(x+100)=2800 A) 3 B) 7 C) 5 D) 4 11 / 30 Radiusi 25 bo’lgan doirada 48 ga teng vatar o’tkazilgan. Doira markazidan shu vatargacha masofani toping. A) 7 B) 8 C) 9 D) 10 12 / 30 Ifodani soddalashtiring. [ln(ln x)-ln(loge10)].log10e A) ln(ln x) B) ln(lg x) C) lg(ln x) D) lg(lg x) 13 / 30 x(t)=t2+6t+5 qonuniyat bo’yicha harakatlanayotgan moddiy nuqta harakat boshlangandan necha sekund o’tgach boshlang’ich nuqtaga nisbatan 77 metr masofaga siljiydi? A) 7 B) 6 C) 10 D) 8 14 / 30 bo’lsa, ni x orqali ifodalang. A) 2/x B) x/25 C) 2-x D) 25/x 15 / 30 ABCD to’gri to’rtburchak ichidan olingan O nuqtadan A, B, C, D uchlarigacha bo’lgan masofalar mos ravishda 1; 2; 1,5; 1,2 ga teng bo’ladigan barcha to’g’ri to’rtburchaklar sonini toping A) cheksiz ko’p B) 2 C) 1 D) 0 16 / 30 Ushbu (y6+y3+1)(y3+1)(y3-1)-y6+y3+1 ifodani soddalashtish natijasida ko’phad hosil qilindi. Uning nechta hadi bor? A) 2 B) 1 C) 3 D) 4 17 / 30 Bog’bon uch kun davomida o’nta daraxt ko’chati o’tqazishi lozim. Agar bog’bon bir kunda eng kamida bitta ko’chat o’tqazadigan bo’lsa, u shu ishni kunlar bo’yicha necha xil usul bilan taqsimlashi mumkin? A) 30 B) 32 C) 25 D) 36 18 / 30 Markazi nuqtada bo‘lgan aylanaga va urinmalar o‘tkazilgan bo’lib, va nuqtalar urinish nuqtalari bo’lsin. Aylanadagi Q nuqtadan o‘tkazilgan uchinchi urinma va kesmalarni X va Y nuqtalarda kesib o‘tadi. Agar uchburchakning perimetri 48 va aylana radiusi 7 ga teng bo‘lsa, u holda kesma uzunligini toping A) 12 B) 25 C) 15 D) 30 19 / 30 |x2-5x-14|+20≥5|x+2|+4|x-7| tengsizlikni yeching. A) (-∞;-6]v{2}v[12;∞) B) [-2;4]v{6} C) [2;4]v{2}v[3;∞) D) [1;6] 20 / 30 Parallelogrammning tomonlari nisbati 3:5 kabi. Agar parallelogrmmning perimetri 48 ga burchaklaridan biri 1200 ga teng bo’lsa, uning yuzini toping. A) 48√3 B) 67,5 C) 67,5√3 D) 135√3/4 21 / 30 Agar f(x)=sin2x va g(x)=cos2x bo’lsa, u holda f(g(x)) funksiyaning hosilasini toping. A) -4sin2x*cos(cos2x) B) 4sin2x*cos(2cos2x) C) -4sin2x*cos(2cos2x) D) 4sin2x*cos(cos2x) 22 / 30 Qaysi javobda faqat juft funksiyalar ko’rsatilgan? A) 3, 4 B) 1,4 C) 1, 3 D) 2, 3 23 / 30 Ifodani soddalashtiring. 2 cos55o.cos40o.sin55o+cos110o.sin40o A) 2 B) 0,5 C) 1 D) 0 24 / 30 funksiya uchun quyidagi mulohazalardan qaysi biri o’rinli? A) juft ham emas, toq ham emas funksiya B) juft funksiya C) toq funksiya D) bunday funksiya mavjud emas 25 / 30 Teng yonli uchburchakning tomonlari 5, 5 va 6 ga teng. Bu uchburchakning bissektiritsalari va medianalari kesishgan nuqtalar A) 1/2 B) 1,2 C) 1/6 D) 1 26 / 30 Hisoblang A) 3√3 B) √3 C) 2√3 D) 1 27 / 30 To’g’ri burchakli uchburchakning yuzi 24 ga, katetlaridan biri 6 ga teng bo’lsa, gipotenuzasini toping A) 10 B) 12 C) √46 D) 11 28 / 30 Tomoni 2 ga teng kvadratga tashqi chizilgan aylana uzunligini toping. A) 2π/3 B) 4π C) 3π D) 2π 29 / 30 Tengsizlikni yeching. A) (-1/³ √2 ;0) B) 0 C) to'g'ri javob yo'q D) (0;+∞) 30 / 30 Yuzasi 10 ga teng bo’lgan kvadratning ketma-ket ikki uchidan o’tuvchi aylana chizilgan. Uchinchi uchidan aylanaga urunma o’tkazilgan. Urunma tomondan ikki marta katta bo’lsa, aylana radiusini toping. A) 4 B) 5 C) 10 D) 6 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
