Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 194 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 a ning 7x-a-13=(a-5)(x+7) tenglama yechimga ega bo’lmaydigan qiymatining natural bo’luvchilar sonini toping. A) 8 B) 4 C) 6 D) 12 2 / 30 Bekzodda 50 so’m va Sobirda 70 so’m pul bor edi. Anvar Bekzodga o’z pulining 10 foizini bergandan so’ng, Bekzod Sobirga pulining yarmini berdi. So’ng Sobir Anvarga pulining 10 foizini berdi. Anvar o’zidagi pullarini hisoblab, pullari dastlabki holdagi puli bilan teng ekanligini bildi. Anvarda qancha pul bo’lgan? A) 375 B) 100 C) 127 D) 400 3 / 30 Tengsizlikni yeching. A) (-3;2)v(2;4) B) (-3;2) C) (-4;2)v(2;3) D) (2;4) 4 / 30 Tenglamaning ildizlari yig`indisini toping. A) 3 B) 4 C) 6 D) 5 5 / 30 Muntazam uchburchakli piramidaning yon qirrasi asos tekisligi bilan 45o li burchak tashkil etgan bo‘lsa, u holda piramidaning yon sirti yuzining uning asosi yuziga nisbatini toping. A) 2√3 B) 2√5 C) 4 D) 3√3 6 / 30 Tomoni 12 ga teng bo`lgan teng tomonli uchburchakga ichki chizilgan aylana uzunligini toping. A) 2√3π B) 4√3π C) 3π D) 12π 7 / 30 Ostki asosining yuzi 16π ga va ustki asosining yuzi 4π ga teng bo‘lgan kesik konus berilgan. Agar kesik konusga shar ichki chizilgan bo‘lsa, u holda sharning hajmini toping. A) 64√2π/3 B) (5√3+3)π/3 C) 8√2π/5 D) 3√2π/4 8 / 30 y=cos(2sinx) funksiyaning qiymatlar sohasini toping. A) [cos2;1] B) [0;cos2] C) [0;1] D) [-1;1] 9 / 30 Soat 3:37 bo’lganda minut va soat millari orasidagi burchakni toping. A) 112,5° B) 113° C) 113,5° D) 100° 10 / 30 qonuniyat bo’yicha harakatlanayotgan moddiy nuqta harakatning 200- metrida qanday tezlikka (m/s) erishadi? A) 42 B) 32 C) 38 D) 36 11 / 30 Agar f(x)=4x3-6x2-2x+3x .log3e bo’lsa, u holda ni toping. A) 3e B) e C) √2e D) 1 12 / 30 Parallelogrammning tomonlari nisbati 3:5 kabi. Agar parallelogrmmning perimetri 48 ga burchaklaridan biri 1200 ga teng bo’lsa, uning yuzini toping. A) 135√3/4 B) 67,5 C) 67,5√3 D) 48√3 13 / 30 To‘g‘ri to‘rtburchakning eni 25% ga orttirildi, bo‘yi esa 25% ga kamaytirildi. Natijada uning yuzi qanday o‘zgardi? A) o‘zgarmaydi B) 2,5% ga ortadi C) 6,25% ga ortadi D) 6,25% ga kamayadi 14 / 30 |x2-5x-14|+20≥5|x+2|+4|x-7| tengsizlikni yeching. A) [2;4]v{2}v[3;∞) B) (-∞;-6]v{2}v[12;∞) C) [-2;4]v{6} D) [1;6] 15 / 30 tenglamani yeching. A) 2019 B) 2018 C) 0 D) 2017 16 / 30 7 sonini uchta natural sonlar yig’indisi ko’rinishida necha xil usulda yozish mumkin? A) 6 B) 3 C) 4 D) 5 17 / 30 Markazi O nuqtada bo‘lgan aylanaga PA va PB urinmalar o‘tkazilgan bo’lib, A va B nuqtalar urinish nuqtalari bo’lsin. Aylanadagi Q nuqtadan o‘tkazilgan uchinchi urinma PA va PB kesmalarni X va Y nuqtalarda kesib o‘tadi. Agar XQ=YQ bo‘lsa, u holda PXY uchburchak qanday uchburchak bo‘ladi? A) teng yonli uchburchak B) to`g`ri burchakli uchburchak C) muntazam uchburchak D) ixtiyoriy uchburchak 18 / 30 Rombning balandligi 8 ga dioganallarining ko’paytmasi 80 ga teng. Rombning perimetrini toping A) 24 B) 20 C) 32 D) 16 19 / 30 Musobaqada 5 ta ishtirokchidan 3 tasiga 1, 2, 3-o’rinlarni necha xil usulda berish mumkin? A) 120 B) 18 C) 47 D) 60 20 / 30 a ning qanday qiymatlarida ushbu 7x-a-13=(a-5)(x+7) tenglama yagona yechimga ega A) a≠12 B) a=12 C) a ning bunday qiymati yo’q D) a≠5 21 / 30 Teng yonli uchburchakning tomonlari 5, 5 va 6 ga teng. Bu uchburchakning bissektiritsalari va medianalari kesishgan nuqtalar A) 1/2 B) 1,2 C) 1 D) 1/6 22 / 30 To’g’ri burchakli uchburchakning yuzi 24 ga, katetlaridan biri 6 ga teng bo’lsa, gipotenuzasini toping A) 12 B) √46 C) 11 D) 10 23 / 30 integralning qiymatini toping. A) -π/2 B) π/2 C) 0 D) π/4 24 / 30 Agar va b-a=4 bo’lsa, a+b ni toping. A) 4 B) 3,5 C) 3 D) 2 25 / 30 Fazoda (1;2;3) nuqtalardan o’tuvchi to’g’ri chiziq tenglamasini tuzing. A) -x-y+z=0 B) 2x+3y+z=0 C) x=y/3=z/2 D) x-1/2=y-2/3=z-3/4 26 / 30 y= funksiyaning aniqlanish sohasini toping A) (-∞;0)v(2;∞) B) (2;∞) C) (0,2) D) (-∞;0])v[2;∞) 27 / 30 Ifodani soddalashtiring. 2 cos55o.cos40o.sin55o+cos110o.sin40o A) 2 B) 0,5 C) 0 D) 1 28 / 30 bo’lsa ni toping. Bunda funksiya f(x) ga teskari funksiya. A) -12 B) -10 C) -4 D) -14 29 / 30 Bir vaqtning o’zida 9,13, . . . ,405 va 15,21, . . . ,255 ketma–ketliklarning hadlari bo’lgan sonlarning eng kattasi va eng kichigining ayirmasini toping A) 150 B) 231 C) 228 D) 147 30 / 30 Ikki burchagi graduslari yig’indisi uchinchi burchagi gradusidan katta bo’lgan uchburchaklar sonini toping. A) 1 B) 2019 C) 0 D) cheksiz ko’p 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz