Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 160 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 2 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 Ag ar tgα=2 bo’lsa, u holda ni hisoblang A) -10/27 B) 10/3 C) 10/27 D) -10/3 2 / 30 Radiuslari orasidagi burchagi 36o va radiusi 5 ga teng bo`lgan sektor yoyining uzunligini toping. A) 2π B) π/2 C) 2π/3 D) π 3 / 30 Bir vaqtning o’zida 9,13, . . . ,405 va 15,21, . . . ,255 ketma–ketliklarning hadlari bo’lgan sonlarning eng kattasi va eng kichigining ayirmasini toping A) 150 B) 228 C) 147 D) 231 4 / 30 Qaysi javobda faqat juft funksiyalar ko’rsatilgan? A) 1, 3 B) 2, 3 C) 1,4 D) 3, 4 5 / 30 tenglamalar sistemasini yeching A) (4;3) B) (–4;3) C) (3;–4) D) (4;–3) 6 / 30 Muntazam uchburchakli piramidaning yon qirrasi asos tekisligi bilan 45o li burchak tashkil etgan bo‘lsa, u holda piramidaning yon sirti yuzining uning asosi yuziga nisbatini toping. A) 2√3 B) 2√5 C) 4 D) 3√3 7 / 30 Soddalashtiring. (0<m<7) A) 7 B) 7-2m C) 2m-7 D) m 8 / 30 Rombning yuzi 96 ga, dioganallaridan biri 16 ga teng. Romb tomonini toping. A) 12 B) 11 C) 9 D) 10 9 / 30 AA1A2A3A4A5A6 muntazam oltiburchakli piramidaning hajmi ga va balandligi 2 ga teng bo‘lsa, u holda AA2A6 kesim yuzini toping. A) √5 B) √15 C) 3 D) 2 10 / 30 Ostki asosining yuzi 20π va ustki asosining yuzi 10π ga teng bo‘lgan kesik konus berilgan. Agar kesik konusga shar ichki chizilgan bo‘lsa, u holda kesik konus hajmining shar hajmiga nisbatini toping. A) 5√3+3/3 B) 3√3+1/5 C) 2√2/3 D) 3√2+2/4 11 / 30 Fazoda (1;2;3) nuqtalardan o’tuvchi to’g’ri chiziq tenglamasini tuzing. A) -x-y+z=0 B) 2x+3y+z=0 C) x=y/3=z/2 D) x-1/2=y-2/3=z-3/4 12 / 30 To’rtburchakning uchi M (0, 4) ; N(-4,0) ; P(-3;2) uchlari berilgan. Agar bo’lsa, Q uchining koordinatalarini toping. A) (4; -3) B) (7; 1) C) (-7;-1) D) (-7; 1) 13 / 30 Bekzodda 50 so’m va Sobirda 70 so’m pul bor edi. Anvar Bekzodga o’z pulining 10 foizini bergandan so’ng, Bekzod Sobirga pulining yarmini berdi. So’ng Sobir Anvarga pulining 10 foizini berdi. Anvar o’zidagi pullarini hisoblab, pullari dastlabki holdagi puli bilan teng ekanligini bildi. Anvarda qancha pul bo’lgan? A) 400 B) 100 C) 375 D) 127 14 / 30 sin2x-cos2x=1 tenglama [-π; 2π] oraliqda nechta ildizga ega? A) 6 B) 7 C) 10 D) 9 15 / 30 Parallelogrammning tomonlari nisbati 3:5 kabi. Agar parallelogrmmning perimetri 48 ga burchaklaridan biri 1200 ga teng bo’lsa, uning yuzini toping. A) 67,5 B) 48√3 C) 67,5√3 D) 135√3/4 16 / 30 Ostki asosining yuzi 32π va ustki asosining yuzi 18π ga teng bo‘lgan kesik konus berilgan. Agar kesik konusga shar ichki chizilgan bo‘lsa, u holda sharning sirtini toping. A) 96π B) 100π C) 56π D) 72π 17 / 30 O’q kesimining diagonallari o’zaro perpendikulyar bo’lgan kesik konus yasovchisi va asos tekisligi orasidagi burchak ga teng. Agar o’q kesimining diagonali ga teng bo’lsa, kesik konus asosining yuzini toping. A) πa²(1+2cosα/4sin²) B) πa²/4sin²α C) πa²/4cos²α D) πa²(1-2sinα/4sin²) 18 / 30 (-3;4) nuqtaga absissa, ordinata o’qlariga va koordinata boshiga nisbatan simmetrik bo’lgan nuqtalarni tutashtirishdan hosil bo’lgan uchburchakning eng kata tomonini toping. A) 10 B) 24 C) 14 D) 12 19 / 30 sistemadan x+y ning qiymatini toping. A) 35/4 B) 12 C) 6 D) -12 20 / 30 Agar f(x)=ax3-5x2+b va bo’lsa, a ni toping. A) 0 B) 1 C) 2 D) 3 21 / 30 integralning qiymatini toping. A) π/4 B) 0 C) π/2 D) -π/2 22 / 30 O’qishni bilmaydigan bola alifbening A,A,A, N,N, S- 6 ta harflarini ixtiyoriy ravishda terib chiqadi. Bunda ANANAS so’zining hosil bo’lish ehtimolini toping. A) 6/720 B) 1/60 C) 5/24 D) 5/720 23 / 30 To‘g‘ri to‘rtburchakning eni 25% ga orttirildi, bo‘yi esa 25% ga kamaytirildi. Natijada uning yuzi qanday o‘zgardi? A) o‘zgarmaydi B) 6,25% ga ortadi C) 6,25% ga kamayadi D) 2,5% ga ortadi 24 / 30 Ikki burchagi graduslari yig’indisi uchinchi burchagi gradusiga teng bo’lgan uchburchak qanday uchburchak deyiladi? A) teng tomonli uchburchak B) to’gri burchakli uchburchak C) o’tkir burchakli uchburchak D) o’tmas burchakli uchburchak 25 / 30 Hisoblang A) √3 B) 3√3 C) 2√3 D) 1 26 / 30 Tomoni 25 ga diagonallaridan biri 4 ga teng bo’lgan rombning yuzini toping. A) 32 B) 16 C) 24√5 D) 8√5 27 / 30 funksiya uchun quyidagi mulohazalardan qaysi biri o’rinli? A) bunday funksiya mavjud emas B) juft funksiya C) juft ham emas, toq ham emas funksiya D) toq funksiya 28 / 30 Agar arctga+ arctgb + arctgc= bo’lsa, a+b+c ni toping. A) abc B) 1 C) ab/c D) ab 29 / 30 Tenglamani yeching. |x2-11x+10|=x2-11x+10 A) (-∞;1] B) [10;∞) C) 1; 10 D) (-∞;1]v[10;∞) 30 / 30 tenglamani yeching. A) 2017 B) 0 C) 2018 D) 2019 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
