Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 164 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 2 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 Rombning yuzi 96 ga, dioganallaridan biri 16 ga teng. Romb tomonini toping. A) 12 B) 10 C) 9 D) 11 2 / 30 Markazi O nuqtada bo‘lgan aylanaga PA va PB urinmalar o‘tkazilgan bo’lib, A va B nuqtalar urinish nuqtalari bo’lsin. Aylanadagi Q nuqtadan o‘tkazilgan uchinchi urinma PA va PB kesmalarni X va Y nuqtalarda kesib o‘tadi. Agar XQ=YQ bo‘lsa, u holda PXY uchburchak qanday uchburchak bo‘ladi? A) muntazam uchburchak B) ixtiyoriy uchburchak C) teng yonli uchburchak D) to`g`ri burchakli uchburchak 3 / 30 sonning oxirgi raqamini toping. A) 2 B) 8 C) 4 D) 6 4 / 30 sistema a ning qanday qiymatida cheksiz ko’p yechimga ega? A) (-∞;6])v[6;∞) B) (2;∞) C) (-∞;6) D) 6 5 / 30 Agar x,y sonlar (x+5)2+(y-12)2=142 tenglikni qanoatlantirsa, x2+y2 ifodaning eng kichik qiymatini toping. A) √3 B) 2 C) √2 D) 1 6 / 30 a ning 7x-a-13=(a-5)(x+7) tenglama yechimga ega bo’lmaydigan qiymatining natural bo’luvchilar sonini toping. A) 4 B) 12 C) 8 D) 6 7 / 30 Tengsizlikni yeching. A) to'g'ri javob yo'q B) (0;+∞) C) (-1/³ √2 ;0) D) 0 8 / 30 Fazoda (1;2;3) nuqtalardan o’tuvchi to’g’ri chiziq tenglamasini tuzing. A) x=y/3=z/2 B) 2x+3y+z=0 C) -x-y+z=0 D) x-1/2=y-2/3=z-3/4 9 / 30 Hisoblang. A) 17/34 B) 2/17 C) 2/34 D) 15/34 10 / 30 Tomoni 25 ga diagonallaridan biri 4 ga teng bo’lgan rombning yuzini toping. A) 8√5 B) 16 C) 32 D) 24√5 11 / 30 ABCD to’gri to’rtburchak ichidan olingan O nuqtadan A, B, C, D uchlarigacha bo’lgan masofalar mos ravishda 3, 4, 5, 6 ga teng bo’lsa, u holda AB tomon uzunligini toping. A) bunday to’gri to’rtburchak mavjud emas B) √7 C) √37 D) 2 12 / 30 Hisoblang A) 1 B) √3 C) 3√3 D) 2√3 13 / 30 Sin9x =4sin3x tenglamani yeching A) πn, n€Ζ B) π/2+πn, n€Ζ C) π/3+πn, n€Ζ D) πn/3, n€Ζ 14 / 30 Bog’bon uch kun davomida o’nta daraxt ko’chati o’tqazishi lozim. Agar bog’bon bir kunda eng kamida bitta ko’chat o’tqazadigan bo’lsa, u shu ishni kunlar bo’yicha necha xil usul bilan taqsimlashi mumkin? A) 25 B) 30 C) 36 D) 32 15 / 30 To’g’ri burchakli uchburchakning gipotenuzasi 13 ga, katetlaridan biri 52 ga teng. Gipotenuzaga tushirilgan balandlik uzunligini toping A) 7 B) 5 C) 4 D) 6 16 / 30 Parallelogrammning yuzi 213 ga, tomonlaridan biri 7 ga va o’tkir burchagi 600 ga teng bo’lsa, ikkinchi tomonini toping A) 5 B) 8 C) 4 D) 6 17 / 30 Tenglamani yeching. |x2-11x+10|=x2-11x+10 A) 1; 10 B) [10;∞) C) (-∞;1] D) (-∞;1]v[10;∞) 18 / 30 m ning qanday eng katta butun qiymatida y=2x-mx-5+m funksiyaning grafigi 1,3,4 –choraklarda yotadi? A) 2 B) 3 C) 5 D) 1 19 / 30 Parallelogrammning tomonlari nisbati 3:5 kabi. Agar parallelogrmmning perimetri 48 ga burchaklaridan biri 1200 ga teng bo’lsa, uning yuzini toping. A) 67,5√3 B) 48√3 C) 67,5 D) 135√3/4 20 / 30 x2-5|x|-6=0 tenglama ildizini toping A) ±6 B) -1;-6 C) -1;6 D) ±;±6 21 / 30 Yuzasi 10 ga teng bo’lgan kvadratning ketma-ket ikki uchidan o’tuvchi aylana chizilgan. Uchinchi uchidan aylanaga urunma o’tkazilgan. Urunma tomondan ikki marta katta bo’lsa, aylana radiusini toping. A) 5 B) 10 C) 6 D) 4 22 / 30 sistemada xy ning qiymatini toping. A) 80 B) 64 C) 60 D) 75 23 / 30 Agar funksiya berilgan bo’lsa, u holda M=ning qiymatini toping. A) e⁻⁵⁰⁵⁰ B) e⁵⁰⁵⁰ C) e⁴⁹⁵⁰ D) e⁻⁴⁹⁵⁰ 24 / 30 “Tutgan balig‘ining og‘irligi qancha?” degan savolga baliqchi: “Baliqning dumi 3 kg, boshi uning dumi hamda tanasi yarmining og‘irligiga teng, tanasi esa boshi va dumining og‘irligiga teng”, deb javob berdi. Baliqning og‘irligini (kg) toping. A) 12 B) 6 C) 18 D) 3 25 / 30 Markazi nuqtada bo‘lgan aylanaga va urinmalar o‘tkazilgan bo’lib, va nuqtalar urinish nuqtalari bo’lsin. Aylanadagi Q nuqtadan o‘tkazilgan uchinchi urinma va kesmalarni X va Y nuqtalarda kesib o‘tadi. Agar uchburchakka ichki chizilgan aylana markazi bo‘lsa, u holda burchakni toping. A) 30° B) 60° C) 90° D) 72° 26 / 30 y=cos(2sinx) funksiyaning qiymatlar sohasini toping. A) [0;1] B) [0;cos2] C) [-1;1] D) [cos2;1] 27 / 30 Rasmda ko‘rsatilgan ko‘pyoqlardan qaysi birida 4 ta yoq, 6 ta qirra bor? A) 3 B) 1, 2 C) 2 D) 1, 3 28 / 30 A) 0 B) 1 C) 2 D) √6 29 / 30 Ushbu (y6+y3+1)(y3+1)(y3-1)-y6+y3+1 ifodani soddalashtish natijasida ko’phad hosil qilindi. Uning nechta hadi bor? A) 4 B) 2 C) 3 D) 1 30 / 30 Ag ar tgα=2 bo’lsa, u holda ni hisoblang A) -10/3 B) -10/27 C) 10/27 D) 10/3 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
