Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 141 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 7 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 Rombning yuzi 96 ga, dioganallaridan biri 16 ga teng. Romb tomonini toping. A) 10 B) 9 C) 12 D) 11 2 / 30 Ostki asosining yuzi 32π va ustki asosining yuzi 18π ga teng bo‘lgan kesik konus berilgan. Agar kesik konusga shar ichki chizilgan bo‘lsa, u holda sharning sirtini toping. A) 56π B) 100π C) 96π D) 72π 3 / 30 Ikki burchagi graduslari yig’indisi uchinchi burchagi gradusiga teng bo’lgan uchburchak qanday uchburchak deyiladi? A) o’tkir burchakli uchburchak B) o’tmas burchakli uchburchak C) teng tomonli uchburchak D) to’gri burchakli uchburchak 4 / 30 sistema yagona yechimga ega bo’ladigan a ning barcha qiymatlari to’plamini toping. A) {1;2} B) {2;4} C) {-1;2} D) {-1;3} 5 / 30 Tenglamaning nechta ildizi bor? |x+1|=|2x-1| A) 2 B) 1 C) 4 D) 3 6 / 30 O’q kesimining diagonallari o’zaro perpendikulyar bo’lgan kesik konus yasovchisi va asos tekisligi orasidagi burchak ga teng. Agar o’q kesimining diagonali ga teng bo’lsa, kesik konus asosining yuzini toping. A) πa²(1-2sinα/4sin²) B) πa²/4cos²α C) πa²(1+2cosα/4sin²) D) πa²/4sin²α 7 / 30 a ning 7x-a-13=(a-5)(x+7) tenglama yechimga ega bo’lmaydigan qiymatining natural bo’luvchilar sonini toping. A) 6 B) 12 C) 8 D) 4 8 / 30 Konsert zalining birinchi qatorida 40 ta o’rindiq bor. Har bir keyingi qatordagi o’rindiqlar soni oldingi qatordan 4 ga ko’p. Agar konsert zalida jami 40 ta qator bo’lsa, u holda shu zaldagi barcha o’rindiqlar sonini toping. A) 4716 B) 4680 C) 4720 D) 4760 9 / 30 ABC muntazam uchburchak ichidan ixtiyoriy P nuqta olinib, undan BC, CA va AB tomonlarga mos ravishda PD, PE va PF perpendikulyarlar tushirilgan bo’lsa,ni toping. A) 0,5 B) 1 C) 1/√3 D) 1/√2 10 / 30 Radiusi 25 bo’lgan doirada 48 ga teng vatar o’tkazilgan. Doira markazidan shu vatargacha masofani toping. A) 10 B) 9 C) 8 D) 7 11 / 30 n ning qanday qiymatida ushbu 81 .82 .83 .….8n=51222 tenglik o’rinli bo’ladi? A) 14 B) 12 C) 10 D) 11 12 / 30 y=cos(2sinx) funksiyaning qiymatlar sohasini toping. A) [cos2;1] B) [0;cos2] C) [-1;1] D) [0;1] 13 / 30 Agar f(x)=ax3-5x2+b va bo’lsa, a ni toping. A) 2 B) 0 C) 3 D) 1 14 / 30 bo’lsa, ni x orqali ifodalang. A) x/25 B) 2/x C) 2-x D) 25/x 15 / 30 Ostki asosining yuzi 16π ga va ustki asosining yuzi 4π ga teng bo‘lgan kesik konus berilgan. Agar kesik konusga shar ichki chizilgan bo‘lsa, u holda sharning hajmini toping. A) 3√2π/4 B) 8√2π/5 C) (5√3+3)π/3 D) 64√2π/3 16 / 30 Soddalashtiring. (0<m<7) A) 7-2m B) 2m-7 C) m D) 7 17 / 30 Parallelogrammning tomonlari nisbati 3:5 kabi. Agar parallelogrmmning perimetri 48 ga burchaklaridan biri 1200 ga teng bo’lsa, uning yuzini toping. A) 67,5√3 B) 135√3/4 C) 67,5 D) 48√3 18 / 30 Agar f(x)=4x3-6x2-2x+3x .log3e bo’lsa, u holda ni toping. A) 3e B) √2e C) e D) 1 19 / 30 Hisoblang A) -1 B) 2 C) 1 D) 0 20 / 30 Tenglamani yeching. |x2-11x+10|=x2-11x+10 A) (-∞;1] B) (-∞;1]v[10;∞) C) [10;∞) D) 1; 10 21 / 30 7 sonini uchta natural sonlar yig’indisi ko’rinishida necha xil usulda yozish mumkin? A) 6 B) 3 C) 4 D) 5 22 / 30 Ifodani soddalashtiring. [ln(ln x)-ln(loge10)].log10e A) ln(lg x) B) ln(ln x) C) lg(ln x) D) lg(lg x) 23 / 30 Bekzodda 50 so’m va Sobirda 70 so’m pul bor edi. Anvar Bekzodga o’z pulining 10 foizini bergandan so’ng, Bekzod Sobirga pulining yarmini berdi. So’ng Sobir Anvarga pulining 10 foizini berdi. Anvar o’zidagi pullarini hisoblab, pullari dastlabki holdagi puli bilan teng ekanligini bildi. Anvarda qancha pul bo’lgan? A) 400 B) 375 C) 127 D) 100 24 / 30 To’rtburchakning uchi M (0, 4) ; N(-4,0) ; P(-3;2) uchlari berilgan. Agar bo’lsa, Q uchining koordinatalarini toping. A) (7; 1) B) (4; -3) C) (-7; 1) D) (-7;-1) 25 / 30 m ning qanday eng katta butun qiymatida y=2x-mx-5+m funksiyaning grafigi 1,3,4 –choraklarda yotadi? A) 1 B) 3 C) 2 D) 5 26 / 30 Quyidagi 2x-y+3z=2018 va x+5y+z=2019 tekisliklarning holatini aniqlang. A) ayqash B) o’zaro perpendikulyar C) aniqlab bo’lmaydi D) o’zaro parallel 27 / 30 To’g’ri to’rtburchakning perimetri 50 ga teng. Bir tomoni boshqa tomonidan 5 ga ko’p. To’g’ri to’rtburchakning yuzini toping. A) 225 B) 60 C) 50 D) 150 28 / 30 Ifodani soddalashtiring. 2 cos55o.cos40o.sin55o+cos110o.sin40o A) 2 B) 1 C) 0,5 D) 0 29 / 30 funktsiyaning aniqlanish sohasini toping. A) (-∞;1)v(2;∞) B) (1;2) C) (-∞;1]v[2;∞) D) [1;2] 30 / 30 Ushbu funksiyaning boshlang’ich funksiyasini toping. A) ln|x+4/x-1|+c B) ln|x-1/x+4|+c C) ln(|x+4+|x-1|)+c D) ln(|x+4*|x-1|)+c 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
