Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 188 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 3 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 Tomoni 6 ga teng bo`lgan teng tomonli uchburchakga tashqi chizilgan doiraning yuzini toping. A) 6 π B) 7 π C) 10 π D) 12π 2 / 30 x(t)=t2+7t-6 qonuniyat bo’yicha harakatlanayotgan moddiy nuqtaning tezligi harakat boshlangandan necha sekund o’tgach 87 m/s ga teng bo’ladi? A) 54 B) 40 C) 50 D) 36 3 / 30 Arifmetik progressiyada a17=33 va a45=89. Progressiyaning birinchi hadi hamda ayirmasining o’rta geometrigini toping. A) 4 B) √2 C) 2 D) 2√2 4 / 30 Radiuslari orasidagi burchagi 36o va radiusi 5 ga teng bo`lgan sektor yoyining uzunligini toping. A) 2π/3 B) 2π C) π D) π/2 5 / 30 y= funktsiyaning aniqlanish sohasini toping. A) (-∞;2) B) (2;∞) C) (-∞;2)v(2;∞) D) [2;∞) 6 / 30 Teng yonli trpetsiyaning asoslari 15 va 25 ga balandligi esa 15 ga teng trapetsiyaning dioganalini toping A) 25 B) 28 C) 30 D) 20 7 / 30 Quyidagi va to’g’ri chiziqlarning o’zaro holatini aniqlang. A) o’zaro perpendikulyar B) ayqash to’gri chiziqlar C) o’zaro parallel D) o’zaro kesishadi 8 / 30 Agar f(x)=ax3-5x2+b va bo’lsa, a ni toping. A) 0 B) 1 C) 3 D) 2 9 / 30 Ostki asosining yuzi 20π va ustki asosining yuzi 10π ga teng bo‘lgan kesik konus berilgan. Agar kesik konusga shar ichki chizilgan bo‘lsa, u holda kesik konus hajmining shar hajmiga nisbatini toping. A) 2√2/3 B) 5√3+3/3 C) 3√3+1/5 D) 3√2+2/4 10 / 30 Tengsizlikni yeching. A) (-4;2)v(2;3) B) (-3;2)v(2;4) C) (-3;2) D) (2;4) 11 / 30 Ikki burchagi graduslari yig’indisi uchinchi burchagi gradusiga teng bo’lgan uchburchak qanday uchburchak deyiladi? A) o’tmas burchakli uchburchak B) teng tomonli uchburchak C) o’tkir burchakli uchburchak D) to’gri burchakli uchburchak 12 / 30 ABCD kvadrat ichidan olingan O nuqtadan A, B, C uchlarigacha bo’lgan masofalar mos ravishda 3, 4, 5 ga teng bo’lsa, u holda OD kesma uzunligini toping. A) √37 B) 3 C) √32 D) 6 13 / 30 A) 0 B) √6 C) 2 D) 1 14 / 30 tenglamalar sistemasini yeching A) (3;–4) B) (–4;3) C) (4;–3) D) (4;3) 15 / 30 y=cos(2sinx) funksiyaning qiymatlar sohasini toping. A) [0;1] B) [-1;1] C) [cos2;1] D) [0;cos2] 16 / 30 Agar sinx+cosx=a bo’lsa, ning qiymatini toping. A) 1/2 B) 2/5 C) 1/3 D) -1/2 17 / 30 Yuzasi 10 ga teng bo’lgan kvadratning ketma-ket ikki uchidan o’tuvchi aylana chizilgan. Uchinchi uchidan aylanaga urunma o’tkazilgan. Urunma tomondan ikki marta katta bo’lsa, aylana radiusini toping. A) 4 B) 6 C) 10 D) 5 18 / 30 Radiusi 1 ga teng aylana uchta yoyga bo`lingan. Ularga mos markaziy burchaklar 1, 2 va 6 sonlariga proporsional. Yoylardan eng kattasining uzunligini toping. A) 2π/3 B) 3π/2 C) 3π/4 D) 4π/3 19 / 30 Ushbu funksiyaning boshlang’ich funksiyasini toping. A) ln(|x+4*|x-1|)+c B) ln|x-1/x+4|+c C) ln(|x+4+|x-1|)+c D) ln|x+4/x-1|+c 20 / 30 (-3;4) nuqtaga absissa, ordinata o’qlariga va koordinata boshiga nisbatan simmetrik bo’lgan nuqtalarni tutashtirishdan hosil bo’lgan uchburchakning eng kata tomonini toping. A) 10 B) 14 C) 12 D) 24 21 / 30 m ning qanday eng katta butun qiymatida y=2x-mx-5+m funksiyaning grafigi 1,3,4 –choraklarda yotadi? A) 2 B) 3 C) 1 D) 5 22 / 30 Tenglamani yeching. |x2-11x+10|=x2-11x+10 A) [10;∞) B) 1; 10 C) (-∞;1] D) (-∞;1]v[10;∞) 23 / 30 Markazi O nuqtada bo‘lgan aylanaga PA va PB urinmalar o‘tkazilgan bo’lib, A va B nuqtalar urinish nuqtalari bo’lsin. Aylanadagi Q nuqtadan o‘tkazilgan uchinchi urinma PA va PB kesmalarni X va Y nuqtalarda kesib o‘tadi. Agar XQ=YQ bo‘lsa, u holda PXY uchburchak qanday uchburchak bo‘ladi? A) muntazam uchburchak B) teng yonli uchburchak C) to`g`ri burchakli uchburchak D) ixtiyoriy uchburchak 24 / 30 O’qishni bilmaydigan bola alifbening A,A,A, N,N, S- 6 ta harflarini ixtiyoriy ravishda terib chiqadi. Bunda ANANAS so’zining hosil bo’lish ehtimolini toping. A) 6/720 B) 5/720 C) 5/24 D) 1/60 25 / 30 Qaysi javobda faqat juft funksiyalar ko’rsatilgan? A) 2, 3 B) 3, 4 C) 1,4 D) 1, 3 26 / 30 Fazoda (1;2;3) nuqtalardan o’tuvchi to’g’ri chiziq tenglamasini tuzing. A) -x-y+z=0 B) x-1/2=y-2/3=z-3/4 C) x=y/3=z/2 D) 2x+3y+z=0 27 / 30 Ushbu arifmetik progressiyaning manfiy hadlari yig’indisini toping. A) -0,5 B) -0,75 C) -1 D) -0,25 28 / 30 Hisoblang: A) 3 B) -1 C) 2 D) 1 29 / 30 To‘g‘ri to‘rtburchakning eni 25% ga orttirildi, bo‘yi esa 25% ga kamaytirildi. Natijada uning yuzi qanday o‘zgardi? A) 6,25% ga kamayadi B) 2,5% ga ortadi C) o‘zgarmaydi D) 6,25% ga ortadi 30 / 30 x2-5|x|-6=0 tenglama ildizini toping A) ±6 B) -1;-6 C) ±;±6 D) -1;6 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
