Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 284 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 4 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 a=sin 1; b=sin 2; c=sin 3; d=sin 4 va e=sin 5 sonlarni kamayish tartibida joylashtiring. A) b>a>c>d>e B) a>b>c>d>e C) b>c>a>d>e D) e>b>a>d>c 2 / 30 sistemadan x+y+z ning qiymatini toping. A) 139/41 B) 150/41 C) 140/41 D) -139/41 3 / 30 Radiusi 1 ga teng aylana uchta yoyga bo`lingan. Ularga mos markaziy burchaklar 1, 2 va 6 sonlariga proporsional. Yoylardan eng kattasining uzunligini toping. A) 3π/2 B) 3π/4 C) 2π/3 D) 4π/3 4 / 30 Ushbu arifmetik progressiyaning manfiy hadlari yig’indisini toping. A) -0,25 B) -1 C) -0,75 D) -0,5 5 / 30 Soddalashtiring. A) 2019 B) 2018a/a+1 C) a+1 D) 2018 6 / 30 bo’lsa ni toping. Bunda funksiya f(x) ga teskari funksiya. A) -4 B) -14 C) -10 D) -12 7 / 30 Radiuslari orasidagi burchagi 36o va radiusi 5 ga teng bo`lgan sektor yoyining uzunligini toping. A) 2π/3 B) 2π C) π/2 D) π 8 / 30 Agar x,y sonlar (x+5)2+(y-12)2=142 tenglikni qanoatlantirsa, x2+y2 ifodaning eng kichik qiymatini toping. A) 1 B) 2 C) √2 D) √3 9 / 30 ABCD to’gri to’rtburchak ichidan olingan O nuqtadan A, B, C, D uchlarigacha bo’lgan masofalar mos ravishda 3, 4, 5, 6 ga teng bo’lsa, u holda AB tomon uzunligini toping. A) √7 B) bunday to’gri to’rtburchak mavjud emas C) 2 D) √37 10 / 30 a ning qanday qiymatlarida ushbu 7x-a-13=(a-5)(x+7) tenglama yagona yechimga ega A) a≠5 B) a ning bunday qiymati yo’q C) a=12 D) a≠12 11 / 30 Konsert zalining birinchi qatorida 40 ta o’rindiq bor. Har bir keyingi qatordagi o’rindiqlar soni oldingi qatordan 4 ga ko’p. Agar konsert zalida jami 40 ta qator bo’lsa, u holda shu zaldagi barcha o’rindiqlar sonini toping. A) 4720 B) 4716 C) 4680 D) 4760 12 / 30 Qaysi javobda faqat juft funksiyalar ko’rsatilgan? A) 1, 3 B) 1,4 C) 3, 4 D) 2, 3 13 / 30 Tengsizlikni yeching. A) to'g'ri javob yo'q B) (-1/³ √2 ;0) C) (0;+∞) D) 0 14 / 30 Teng yonli trpetsiyaning asoslari 15 va 25 ga balandligi esa 15 ga teng trapetsiyaning dioganalini toping A) 30 B) 25 C) 20 D) 28 15 / 30 tenglamani yeching. A) 2018 B) 2019 C) 0 D) 2017 16 / 30 Quyidagi va to’g’ri chiziqlarning o’zaro holatini aniqlang. A) o’zaro kesishadi B) ayqash to’gri chiziqlar C) o’zaro parallel D) o’zaro perpendikulyar 17 / 30 Ifodani soddalashtiring. [ln(ln x)-ln(loge10)].log10e A) ln(lg x) B) lg(ln x) C) lg(lg x) D) ln(ln x) 18 / 30 Hisoblang A) 2 B) 1/2 C) √3/2 D) √3 19 / 30 Ifodani soddalashtiring. 2 cos55o.cos40o.sin55o+cos110o.sin40o A) 0 B) 1 C) 0,5 D) 2 20 / 30 Agar arctga+ arctgb + arctgc= bo’lsa, a+b+c ni toping. A) ab B) abc C) 1 D) ab/c 21 / 30 ABC muntazam uchburchak ichidan ixtiyoriy P nuqta olinib, undan BC, CA va AB tomonlarga mos ravishda PD, PE va PF perpendikulyarlar tushirilgan bo’lsa,ni toping. A) 1 B) 1/√2 C) 1/√3 D) 0,5 22 / 30 A) √6 B) 0 C) 1 D) 2 23 / 30 (-3;4) nuqtaga absissa, ordinata o’qlariga va koordinata boshiga nisbatan simmetrik bo’lgan nuqtalarni tutashtirishdan hosil bo’lgan uchburchakning eng kata tomonini toping. A) 14 B) 12 C) 10 D) 24 24 / 30 sin2x-cos2x=1 tenglama [-π; 2π] oraliqda nechta ildizga ega? A) 10 B) 7 C) 6 D) 9 25 / 30 Tengsizlik nechta butun yechimga ega? A) 1 B) 4 C) 3 D) cheksiz ko’p 26 / 30 a(x+2)=2x+1 tenglama a ning qanday qiymatida yechimga ega emas? A) (2;∞) B) (-∞;2)v(2;∞) C) (∞;∞) D) (-∞;2) 27 / 30 Teng yonli uchburchakning tomonlari 5, 5 va 6 ga teng. Bu uchburchakning bissektiritsalari va medianalari kesishgan nuqtalar A) 1 B) 1,2 C) 1/6 D) 1/2 28 / 30 Ikki burchagi graduslari yig’indisi uchinchi burchagi gradusidan katta bo’lgan uchburchaklar sonini toping. A) cheksiz ko’p B) 1 C) 0 D) 2019 29 / 30 A) 5 B) 1 C) 3 D) 2 30 / 30 Perimetri 60 ga teng bo’lgan parallelogrammning tomonlari nisbati 2:3 ga, o’tkir burchagi esa 300 ga teng. Parallelogrammning yuzini toping. A) 52√3 B) 108 C) 48√3 D) 54 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz