Barcha fanlardan online testlar

Matematika attestatsiya №12

InfoMaster

Aprel 8, 2022

60 Ko'rishlar 1 izoh

SaqlashSaqlanganOlib tashlandi 2

OMAD YOR BO'LSIN!

Matematika fanidan attestatsiya savollari №12

28.03.2022 da Toshkentda tushgan savollar

DIQQAT! Endi siz o'z bilmingizni sinab ko'rish bilan birga sertifikatga ham ega bo'lishingiz mumkin.

Sertifikat olish uchun barcha ma'lumotlarni to'g'ri kiriting!

e-mail manzilini to'g'ri kriting, barcha ma'lumotlar sizga yuboriladi.
Testda 76% va undan yuqori natija oling va sertifikatni yuklab oling.

1 / 40

f(x) = log_₃(x+3) bo'lsa, f^-1(3) ni toping.

A) 24

B) 6

C) 1

D) 30

2 / 40

A(1; 3) nuqtadan 12x+5y+a–4=0 to’g’ri chiziqqacha bo’lgan masofa 2 bo’lsa, a ni toping.

A) 2

B) 3

C) 1

D) 4

3 / 40

Rasmda tasvirlangan favvora ko‘rinishi y=-x(x+6) ko'rinishda bo'lsa, favvora eng ko’pi bilan qaysi balandlikga ko’tarila oladi. (Koordinata Oy o’qi , suv yuzasida joylashgan)

A) 6

B) 8

C) Hisoblab bo'lmaydi

D) 9

4 / 40

a ning qanday qiymatida 3a + ax + (-x² )= 0 tenglama o‘zaro teng ildizlarga ega bo‘ladi?

A) a=12

B) a=0; a=-12

C) a=0; a=12

D) a=0

5 / 40

Hisoblang.

A) -1

B) 2

C) 1

D) 0

6 / 40

Hisoblang. cos²10° + cos²30° + cos²80°

A) 3/7

B) 0

C) 7/3

D) 7/4

7 / 40

Agar bo'lsa, ni toping.

A) 5,2

B) 0

C) 3

D) 2,5

8 / 40

Tangga besh martta tashlanganda 2 martta gerb chiqishi ehtimolini toping.

A) 5/16

B) 5/13

C) 9/16

D) 7/16

9 / 40

Tenglamani yeching:

A) 2,5

B) 6

C) 5,5

D) 2

10 / 40

Noaniq integralni toping. ∫(sin²x+cos²x)dx

A) 4x+c

B) x/2+c

C) 2x+c

D) x+c

11 / 40

Hisoblang.

A) 0

B) -2 yoki -1

C) -2 yoki 2

D) -2 yoki 0

12 / 40

Noaniq integralni toping. ∫(sin²x+cos²x)dx

A) 2x+c

B) x+c

C) c

D) 4x+c

13 / 40

ABCD parallelogramm va S_KBCE= 18 bo'lsa, S_ABCD=?

A) 62

B) 48

C) 54

D) 56

14 / 40

(tgx+ctgx)⁴ yoyilmaning ozod hadini toping.

A) 6

B) 5

C) 4

D) 3

15 / 40

Hisoblang.

A) 1

B) 0

C) 2

D) 4

16 / 40

y = x²+1-|sinx| funksiya grafigi OX o'qidan pastda yotadimi?

A) Yotadi

B) Yotmaydi

17 / 40

Hisoblang.

A) 2020

B) 2021

C) 2019

D) 1

18 / 40

To'g'ri burchakli uchburchakning yuzi 96 ga, perimetri esa 48 ga teng bo'lsa, gipatenuza uzunligini toping.

A) 21

B) 20

C) 23

D) 18

19 / 40

Ayirmasi d ga teng bo'lgan arifmetik progrssiya uchun ni toping.

A) 1

B) 2/3

C) 1/2

D) 2

20 / 40

Tengsizlikni yeching: 3 · 9^x–10 · 21^x+ 7 · 49 ^x ≤ 0

A) [-1;1]

B) (-1;3]

C) [-1;0)

D) [-1;0]

21 / 40

Hisoblang.

A) 1

B) -1

C) 0

D) 2

22 / 40

Uchburchak tamonlari 10, 24 va 26 ga teng bo'lsa, katta burchagi necha gradus?

A) 80°

B) 75°

C) 60°

D) 90°

23 / 40

To'g'ri burchakli uchburchakning gipotenuzasiga o'tkazilgan bissiktriksasi uni 20 va 30 ga teng kesmalarga ajratadi. To'g'ri burchakli uchburchak yuzini toping.

A) 15

B) 6700/13

C) 7551/15

D) 7500/13

24 / 40

To'g'ri burchakli uchburchakka ichki va tashqi chizilgan aylanalar raduslari 6 va 15 ga teng bo'lsa, katetlar yig'indini toping.

A) 35

B) 42

C) 28

D) 48

25 / 40

y=xlnx funksiyani hosilasini toping.

A) lnx+1

B) 2lnx-1

C) 1

D) lnx/2+1

26 / 40

Hisoblang.

A) 4

B) 2

C) 1

D) 3

27 / 40

Tenglamani yeching.

A) 2

B) 3

C) 1

D) 4

28 / 40

Agar cos4x = acos⁴x+bcos2²x+1 bo'lsa, a+b=?

A) 1

B) 0

C) -1

D) 2

29 / 40

Hisoblang

A) 6

B) 9

C) 36

D) 12

30 / 40

(2; 3; -5) nuqtaning OX o'qiga nisbatan simmetrik nuqtasini toping.

A) (2; 3; -5)

B) (2; -3; 5)

C) (2; -3; -5)

D) (-2; 3; 5)

31 / 40

Hisoblang.

A) 26-3b

B) 24-3b

C) 14-2b

D) 24+3b

32 / 40

Hisoblang.

A) 9/11

B) 0

C) 7/11

D) 9/13

33 / 40

f(x) = x²-3x-2 bo'lsa. f(a+b+c)-f(abc)=? Bunda a, b, c - kvadrat funksiya koeffitsiyentlari.

A) 42

B) 36

C) 38

D) 40

34 / 40

Hisoblang.

A) 6

B) 4

C) 3

D) 5

35 / 40

|x²-2x|≤x yengsizlikni yeching.

A) (-2;0)∪[1;3]

B) {0}∪[1;3]

C) {0}∪[1;3)

D) {0}∪(1;3]

36 / 40

(tgx-2ctgx)⁴ yoyilmaning ozod hadini toping.

A) 58

B) 24

C) 6

D) 25

37 / 40

Hisoblang.

A) 1

B) 0

C) 2

D) -1

38 / 40

Hisoblang.

A) 32

B) 98

C) 94

D) 96

39 / 40

Agar va ular orasidagi burchak 120° bo'lsa, ni toping.

A) 4√5

B) √7

C) 3√7

D) 2√7

40 / 40

Hisoblang.

A) 51/29

B) 49/25

C) -47/25

D) -47/24

Baholash mezoni

- 75 foiz va undan yuqori ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, oliy malaka toifasi (bosh o’qituvchi lavozimi) saqlansin”;

- 75 foizdan past ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, birinchi malaka toifasi (yetakchi o’qituvchi lavozimi)ga tushirilsin”;

- 75 foiz va undan yuqori ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, oliy malaka toifasi (bosh o’qituvchi lavozimi) berilsin”;

- 74 foizdan 65 foizgacha ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, birinchi malaka toifasi (yetakchi o’qituvchi lavozimi) saqlansin”;

- 65 foizdan kam ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, ikkinchi malaka toifasi (katta o’qituvchi lavozimi)ga tushirilsin”

- 64 foizdan 60 foizgacha ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, ikkinchi malaka toifasi (katta o’qituvchi lavozimi) saqlansin”;

- 60 foizdan kam ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, mutaxassis (oliy yoki o’rta maxsus, kasb-hunar ma'lumotli o’qituvchi) lavozimiga tushirilsin”