Uy » Choraklik online testlar » Matematika choraklik » 5-sinf Matematika 4-chorak Matematika choraklik 5-sinf Matematika 4-chorak InfoMaster May 12, 2021 3033 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 10 2 OMAD YOR BO'LSIN! Tomonidan yaratilgan InfoMaster 5-sinf Matematika 4-chorak Testni Shirinboyev Temurbek tayyorladi! Ismi familiyangizni kriting! Ism 1 / 25 O’nli kasr ko’rinishida yozing: 825/100 A) 83,25 B) 4,8 C) 3,32 D) 8,25 2 / 25 Hisoblang. (53+142):13 A) 19 B) 25 C) 20 D) 15 3 / 25 90 o kichik bo`lgan burchakka……deyiladi A) To’g’ri burchak B) O’tkir burchak C) O’tmas burchak D) Yoyiq burchak 4 / 25 Tenglamani yeching:3,08 : y = 4 A) 4,32 B) 0,48 C) 12,32 D) 0,77 5 / 25 Hisoblang: 0,872*6,3 A) 5,4936 B) 7,846 C) 8,4262 D) 6,4592 6 / 25 1* 2* 3*......74* 75 ko’paytma nechta nol bilan tugaydi? A) 17 B) 18 C) 11 D) 16 7 / 25 1591 va 1207 sonlarining EKUB va EKUK larini ko’paytmasini toping. A) 191913 B) 1920337 C) 2798 D) 202057 8 / 25 28900 sonining tub bo’luvchilari yig’indisini toping. A) 24 B) 22 C) 14 D) 19 9 / 25 Ko’paytmaning natural bo’luvchilari soni 75 ga teng bo’lsa, n ni toping. A) 5 B) 11 C) 1 D) 6 10 / 25 32 ni bo’lganda qoldiq 4 chiqadigan barcha natural sonlar yig’indisini toping? A) 53 B) 52 C) 49 D) 55 11 / 25 202122232425…119120 ushbu son necha xonali son? A) 20 B) 100 C) 18 D) 223 12 / 25 Quyidagi sonni 38 ga bo’lgandagi qoldiqni toping. A) 1 B) 16 C) 32 D) 7 13 / 25 Uchta natural bo’luvchiga ega dastlabki ikkita murakkab sonning yig’indisini toping. A) 16 B) 15 C) 11 D) 13 14 / 25 2;0;1;4 raqamlardan foydalanib, eng kichik to’rt xonali son hosil qilindi. Hosil bo’lgan sonni 32 ga bo’lgandagi bo’linmani toping. A) 32 B) 28 C) 4 D) 0 15 / 25 28900 sonining tub bo’luvchilari yig’indisini toping. A) 24 B) 14 C) 22 D) 19 16 / 25 Quyidagi mulohazalarning qaysilari to’g’ri? 1) tub sonlar faqat toq sonlardan iborat; 2) 72 sonining tub bo’lmagan natural bo’luvchilari soni 10 ta; 3) har qanday natural sonning butun bo’luvchilari soni 0 ga teng; 4) agar ko’paytuvchilardan biri m soniga bo’linsa, u holda ko’paytma ham m songa bo’linadi; 5) Bir – tub son ham, murakkab son ham emas. A) 1; 2; 3 B) 2; 4; 5 C) 3; 4; 5 D) 1; 3; 4 17 / 25 ≤form≥ tegining action atributi qiymatining vazifasini toping. A) hamma qirralari teng bo`lgan to`g`ri burchakli parallelepipedga aytiladi B) forma ma’lumotlarini jo‘natish usuli. C) formaga nom berish (bu nom skriptlar yozishda ishlatiladi) D) formada har xil ko‘rinishdagi elementlarni hosil qiladi. E) hamma tomonlari teng bo`lgan to`g`ri to`rtburchak F) qarama qarshi tomonlari teng bo`lgan figura G) Tomonlarining har biri 10 sm bo`lgan to`rtburchk H) forma orqali jo‘natilayotgan ma’lumotlar qaysi sahifada qayta ishlanishi kerakligi beriladi. 18 / 25 form elementida har doim qaysi atributi ishtirok etishi lozim? A) 1 m2=100 dm2 B) aling C) height D) 1 m2=100000 dm2 E) 1 m2=10 dm2 F) valign G) 1 m2=1000dm2 H) action 19 / 25 ≤label≥…≤/label≥– juft teglarining vazifasi qanday? A) bir necha variantlarga ega bo‘lgan ro‘yxat hosil qilish uchun ishlatiladi B) orqali forma elementlarini guruhlash mumkin. C) veb-sahifaga forma joylashtirish uchun qo‘llaniladi D) formadagi elementlarning nomlarini kiritish uchun foydalaniladi. 20 / 25 ≤input type="password" /≥ ushbu element qanday hollarda ishlatiladi. A) bir necha tanlovni amalga oshiruvchi bayroqchani hosil qiladi; B) 63,64 , 66,67 C) 65,6676,78 D) 62,61, 67,66 E) bir qatorli matn kiritish uchun ishlatiladi F) bir necha tanlovdan faqat bittasini tanlash imkonini beradi; G) 64,65, 66,68 H) oddiy matnli element, asosan, parol yozish uchun ishlatiladi; 21 / 25 Tenglamani yeching: A) 8/14 B) 8/28 C) 14/28 D) 11/14 22 / 25 To’g’ri to’rtburchakning enini toping. A) 3,15/13 B) 2,11/13 C) 4,11/13 D) 2,14/13 23 / 25 Yig’indini toping: A) 8,21/14 B) 8,20/14 C) 8,22/14 D) 8,19/14 24 / 25 Tenglamani yeching: 21 * x = 903 A) 28 B) 43 C) 36 D) 54 25 / 25 Sonni noto’g’ri kasr ko’rinishi ifodalang: A) 2221/316 B) 2021/316 C) 2568/316 D) 79/316 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
