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Matematika attestatsiya №12

InfoMaster

Aprel 8, 2022

119 Ko'rishlar 1 izoh

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OMAD YOR BO'LSIN!

Matematika fanidan attestatsiya savollari №12

28.03.2022 da Toshkentda tushgan savollar

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Testda 76% va undan yuqori natija oling va sertifikatni yuklab oling.

1 / 40

ABCD to‘g‘ri to‘rtburchakda CD tomonining o‘rtasi E nuqta, EA kesmaning o‘rtasi esa F nuqta. AB=4 va bu to‘g‘ri to‘rtburchakning yuzi 8 ga teng bo‘lsa, BF/FA nisbat nechiga teng bo‘ladi?

A) √3

B) √2

C) √5

D) 1

2 / 40

Agar g ( x) - uchinchi darajali keltirilgan f(x)=x³+ax²+bx+c ko‘phadning ildizlari, ko‘phad ildizlarining teskarisiga teng bo‘lsa, u holda g (1) ning qiymatini a, b, c lar
orqali ifodalang.

A) 1

B) 3

C) 4

D) 2

3 / 40

Quyida y=f(x+2) funksiya grafigi tasvirlangan. Barilgan malumotlardan foydalanib ning qiymatini toping

A) 3

B) 1

C) 2

D) -3

4 / 40

Tengsizlikni yeching:

A) x∈[0;4), x∈R

B) x∈ [4;∞), x∈N

C) x∈(-∞;0) ∪[4;∞), x∈R

D) x∈ [4;∞), x∈R

5 / 40

Hisoblang.

A) 2

B) 1

C) 4

D) 0

6 / 40

ABCD parallelogramm va S_KBCE= 18 bo'lsa, S_ABCD=?

A) 62

B) 56

C) 48

D) 54

7 / 40

Tengsizlikni yeching.

A) [-7;3 u [-1;∞)

B) [-7;-3] u [-1;∞)

C) [-7;-5) u [-1;∞)

D) [-7;-3) u [-1;∞)

8 / 40

Noaniq integralni toping. ∫(sin²x+cos²x)dx

A) x+c

B) x/2+c

C) 2x+c

D) 4x+c

9 / 40

Hisoblang.

A) 2020

B) 2019

C) 2021

D) 1

10 / 40

|x²-2x|≤x yengsizlikni yeching.

A) {0}∪[1;3]

B) (-2;0)∪[1;3]

C) {0}∪(1;3]

D) {0}∪[1;3)

11 / 40

y = x²+1-|sinx| funksiya grafigi OX o'qidan pastda yotadimi?

A) Yotadi

B) Yotmaydi

12 / 40

Hisoblang.

A) 26-3b

B) 14-2b

C) 24-3b

D) 24+3b

13 / 40

Tenglamani yeching.

A) 5

B) 1

C) 0

D) 2

14 / 40

Chizmada nechta uchburchak tasvirlangan?

A) 52

B) 48

C) 54

D) 50

15 / 40

Agar va ular orasidagi burchak 120° bo'lsa, ni toping.

A) √7

B) 2√7

C) 3√7

D) 4√5

16 / 40

To'g'ri burchakli uchburchakning gipotenuzasiga o'tkazilgan bissiktriksasi uni 20 va 30 ga teng kesmalarga ajratadi. To'g'ri burchakli uchburchak yuzini toping.

A) 7551/15

B) 6700/13

C) 7500/13

D) 15

17 / 40

Hisoblang.

A) 2

B) -1

C) 0

D) 1

18 / 40

f(x) = x²-3x-2 bo'lsa. f(a+b+c)-f(abc)=? Bunda a, b, c - kvadrat funksiya koeffitsiyentlari.

A) 38

B) 42

C) 36

D) 40

19 / 40

Hisoblang.

A) 94

B) 96

C) 98

D) 32

20 / 40

5^-x≤ 0,04 x ning eng kichik butun qiymatini toping.

A) -1

B) 3

C) 2

D) 0

21 / 40

Tengsizlikni yeching: 3 · 9^x–10 · 21^x+ 7 · 49 ^x ≤ 0

A) (-1;3]

B) [-1;0]

C) [-1;0)

D) [-1;1]

22 / 40

(2; 3; -5) nuqtaning OX o'qiga nisbatan simmetrik nuqtasini toping.

A) (2; -3; -5)

B) (-2; 3; 5)

C) (2; -3; 5)

D) (2; 3; -5)

23 / 40

Hisoblang

A) 12

B) 9

C) 6

D) 36

24 / 40

Hisoblang.

A) 5/3

B) 3/5

C) 3/2

D) 2/3

25 / 40

Tenglama ildizlari yig'indisini toping.

A) 0

B) 4

C) -1

D) 2

26 / 40

Noaniq integralni toping. ∫(sin²x+cos²x)dx

A) x+c

B) c

C) 4x+c

D) 2x+c

27 / 40

Hisoblang.

A) 1

B) 3

C) 4

D) 2

28 / 40

Tenglamani yeching.

A) 3

B) 1

C) 2

D) 4

29 / 40

Tangga besh martta tashlanganda 2 martta gerb chiqishi ehtimolini toping.

A) 5/16

B) 7/16

C) 9/16

D) 5/13

30 / 40

Hisoblang.

A) 9/13

B) 0

C) 9/11

D) 7/11

31 / 40

Hisoblang.

A) 51/29

B) -47/24

C) 49/25

D) -47/25

32 / 40

Hisoblang.

A) 3

B) 5

C) 4

D) 6

33 / 40

(tgx-2ctgx)⁴ yoyilmaning ozod hadini toping.

A) 25

B) 24

C) 6

D) 58

34 / 40

Tenglamaning [0;π] kesmadagi ildizlari soni 3 tadan ko'pmi?

A) Yo'q

B) Ha

35 / 40

Hisoblang. cos²10° + cos²30° + cos²80°

A) 7/4

B) 0

C) 7/3

D) 3/7

36 / 40

Agar bo'lsa, ni toping.

A) 0

B) 5,2

C) 2,5

D) 3

37 / 40

Hisoblang.

A) 131

B) 133

C) 135

D) 121

38 / 40

To'g'ri burchakli uchburchakning yuzi 96 ga, perimetri esa 48 ga teng bo'lsa, gipatenuza uzunligini toping.

A) 18

B) 21

C) 23

D) 20

39 / 40

y=xlnx funksiyani hosilasini toping.

A) lnx/2+1

B) 2lnx-1

C) lnx+1

D) 1

40 / 40

Tengsizlikni yeching.

A) x∈(0;1000)

B) x∈[0;1000]

C) x∈(10;1000)

D) x∈(1;1000]

Baholash mezoni

- 75 foiz va undan yuqori ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, oliy malaka toifasi (bosh o’qituvchi lavozimi) saqlansin”;

- 75 foizdan past ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, birinchi malaka toifasi (yetakchi o’qituvchi lavozimi)ga tushirilsin”;

- 75 foiz va undan yuqori ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, oliy malaka toifasi (bosh o’qituvchi lavozimi) berilsin”;

- 74 foizdan 65 foizgacha ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, birinchi malaka toifasi (yetakchi o’qituvchi lavozimi) saqlansin”;

- 65 foizdan kam ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, ikkinchi malaka toifasi (katta o’qituvchi lavozimi)ga tushirilsin”

- 64 foizdan 60 foizgacha ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, ikkinchi malaka toifasi (katta o’qituvchi lavozimi) saqlansin”;

- 60 foizdan kam ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, mutaxassis (oliy yoki o’rta maxsus, kasb-hunar ma'lumotli o’qituvchi) lavozimiga tushirilsin”