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Matematika attestatsiya №12

InfoMaster

Aprel 8, 2022

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OMAD YOR BO'LSIN!

Matematika fanidan attestatsiya savollari №12

28.03.2022 da Toshkentda tushgan savollar

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Testda 76% va undan yuqori natija oling va sertifikatni yuklab oling.

1 / 40

Arifmetik progressiyada a₃+a₆+a₉+....+a_3n=80 bo‘lsa, a_2n-3+a_n+6=16 bo‘lsa, n ning qiymatini toping.

A) 10

B) 8

C) 11

D) 5

2 / 40

Tenglama katta ildizining kichik idiziga nisbatini toping.

A) -2,5

B) -0,4

C) -0,2

D) 0,4

3 / 40

f(x) va g(x) funksiyalar f(x)+(x-2)·g(x)=x²+5 bog’lanishda va f(3)=10 bo’lsa, g^-1 (4) ning qiymatini toping.(g^-1 (x)-g(x) ga teskari funksiya)

A) 6

B) 3

C) 4

D) 2

4 / 40

Piramidaning asosi tomoni 4√3 va o‘tkir burchagi 45° ga teng bo’lgan rombdan iborat. Ushbu piramidaga ichki chizilgan konusning yasovchisi asos tekisligi bilan 60° li burchak tashkil etadi. Konusning hajmini toping.

A) 3π

B) 6π

C) 6√2π

D) 6√3π

5 / 40

(tgx+ctgx)⁴ yoyilmaning ozod hadini toping.

A) 6

B) 5

C) 4

D) 3

6 / 40

Tengsizlikni yeching.

A) [-7;3 u [-1;∞)

B) [-7;-3] u [-1;∞)

C) [-7;-3) u [-1;∞)

D) [-7;-5) u [-1;∞)

7 / 40

Hisoblang.

A) 49/25

B) -47/25

C) -47/24

D) 51/29

8 / 40

1, 2, 3, 4 raqamlaridan foydalanib 400 dan kichik kechta uc xonali son yasash mumkin?

A) 47

B) 48

C) 49

D) 51

9 / 40

|x²-2x|≤x yengsizlikni yeching.

A) {0}∪[1;3]

B) (-2;0)∪[1;3]

C) {0}∪(1;3]

D) {0}∪[1;3)

10 / 40

a=1^0,(6), b=8^0,(3) , c=2^0,(9) bo'lsa, (a+b)^c=?

A) 9

B) 0

C) 25

D) 16

11 / 40

Hisoblang. cos²10° + cos²30° + cos²80°

A) 7/3

B) 7/4

C) 3/7

D) 0

12 / 40

To'g'ri burchakli uchburchakka ichki va tashqi chizilgan aylanalar raduslari 6 va 15 ga teng bo'lsa, katetlar yig'indini toping.

A) 42

B) 28

C) 35

D) 48

13 / 40

(tgx-2ctgx)⁴ yoyilmaning ozod hadini toping.

A) 25

B) 24

C) 58

D) 6

14 / 40

Hisoblang.

A) 5/3

B) 2/3

C) 3/5

D) 3/2

15 / 40

Noaniq integralni toping. ∫(sin²x+cos²x)dx

A) x+c

B) 2x+c

C) c

D) 4x+c

16 / 40

(2; 3; -5) nuqtaning OX o'qiga nisbatan simmetrik nuqtasini toping.

A) (2; -3; -5)

B) (-2; 3; 5)

C) (2; 3; -5)

D) (2; -3; 5)

17 / 40

Hisoblang.

A) 4

B) 5

C) 6

D) 3

18 / 40

Tenglamani yeching:

A) 5,5

B) 6

C) 2,5

D) 2

19 / 40

Hisoblang.

A) 1

B) -1

C) 0

D) 2

20 / 40

Tangga besh martta tashlanganda 2 martta gerb chiqishi ehtimolini toping.

A) 5/13

B) 5/16

C) 9/16

D) 7/16

21 / 40

Agar bo'lsa, ni toping.

A) 2,5

B) 3

C) 5,2

D) 0

22 / 40

Hisoblang.

A) 32

B) 98

C) 96

D) 94

23 / 40

Agar bo'lsa f(x)=?

A) 2x²-1

B) x²+2

C) x²-2

D) x²-1

24 / 40

Hisoblang.

A) 9/11

B) 0

C) 7/11

D) 9/13

25 / 40

Hisoblang.

A) 1

B) 0

C) -1

D) 2

26 / 40

5^-x≤ 0,04 x ning eng kichik butun qiymatini toping.

A) -1

B) 3

C) 0

D) 2

27 / 40

Arimetik progerssiyada s₁₂=354, P=a₁+a₂+...+a₁₁, Q=a₂+a₄+...+a₁₂ va P/Q=32/27 ga teng bo'lsa, d ni toping.

A) -5

B) -3

C) -4

D) -6

28 / 40

Chizmada nechta uchburchak tasvirlangan?

A) 54

B) 48

C) 50

D) 52

29 / 40

Hisoblang

A) 36

B) 9

C) 12

D) 6

30 / 40

Hisoblang.

A) 121

B) 133

C) 135

D) 131

31 / 40

To'g'ri burchakli uchburchakning yuzi 96 ga, perimetri esa 48 ga teng bo'lsa, gipatenuza uzunligini toping.

A) 23

B) 21

C) 20

D) 18

32 / 40

Tengsizlikni yeching: 3 · 9^x–10 · 21^x+ 7 · 49 ^x ≤ 0

A) [-1;0]

B) [-1;1]

C) [-1;0)

D) (-1;3]

33 / 40

ABCD parallelogramm va S_KBCE= 18 bo'lsa, S_ABCD=?

A) 56

B) 54

C) 48

D) 62

34 / 40

y=xlnx funksiyani hosilasini toping.

A) lnx/2+1

B) 2lnx-1

C) 1

D) lnx+1

35 / 40

f(x)+(x-2)·g(x)=x²+5, f(3)=10 bo'lsa, g^-1=(4) ni toping. Bunda g^-1(x) g(x) ga teskari funksiya.

A) 6

B) 3

C) 4

D) 5

36 / 40

Hisoblang.

A) 26-3b

B) 24+3b

C) 24-3b

D) 14-2b

37 / 40

Hisoblang.

A) -2 yoki 0

B) -2 yoki -1

C) -2 yoki 2

D) 0

38 / 40

Tenglamani yeching.

A) 2

B) 1

C) 4

D) 3

39 / 40

Tenglama ildizlari yig'indisini toping.

A) -1

B) 4

C) 0

D) 2

40 / 40

Tenglamani yeching.

A) 1

B) 0

C) 2

D) 5

Baholash mezoni

- 75 foiz va undan yuqori ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, oliy malaka toifasi (bosh o’qituvchi lavozimi) saqlansin”;

- 75 foizdan past ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, birinchi malaka toifasi (yetakchi o’qituvchi lavozimi)ga tushirilsin”;

- 75 foiz va undan yuqori ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, oliy malaka toifasi (bosh o’qituvchi lavozimi) berilsin”;

- 74 foizdan 65 foizgacha ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, birinchi malaka toifasi (yetakchi o’qituvchi lavozimi) saqlansin”;

- 65 foizdan kam ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, ikkinchi malaka toifasi (katta o’qituvchi lavozimi)ga tushirilsin”

- 64 foizdan 60 foizgacha ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, ikkinchi malaka toifasi (katta o’qituvchi lavozimi) saqlansin”;

- 60 foizdan kam ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, mutaxassis (oliy yoki o’rta maxsus, kasb-hunar ma'lumotli o’qituvchi) lavozimiga tushirilsin”