Barcha fanlardan online testlar

Matematika attestatsiya №12

InfoMaster

Aprel 8, 2022

59 Ko'rishlar 1 izoh

SaqlashSaqlanganOlib tashlandi 2

OMAD YOR BO'LSIN!

Matematika fanidan attestatsiya savollari №12

28.03.2022 da Toshkentda tushgan savollar

DIQQAT! Endi siz o'z bilmingizni sinab ko'rish bilan birga sertifikatga ham ega bo'lishingiz mumkin.

Sertifikat olish uchun barcha ma'lumotlarni to'g'ri kiriting!

e-mail manzilini to'g'ri kriting, barcha ma'lumotlar sizga yuboriladi.
Testda 76% va undan yuqori natija oling va sertifikatni yuklab oling.

1 / 40

(a²+b²+9)x²+2(a+b+3)x+3 = 0 tenglama haqiqiy yechimlarga ega bo‘lsa, 3a – b ni toping.

A) 6

B) -4

C) 3

D) -3

2 / 40

f(f(2)) ni toping.

A) 0

B) 2

C) 3

D) -1

3 / 40

Quyida y=f(x+2) funksiya grafigi tasvirlangan. Barilgan malumotlardan foydalanib ning qiymatini toping

A) -3

B) 1

C) 3

D) 2

4 / 40

(0!+1!+ 2022!)¹²⁵ sonning birlar xonasida qaysi raqam turadi?

A) 4

B) 3

C) 6

D) 2

5 / 40

Hisoblang. cos²10° + cos²30° + cos²80°

A) 7/4

B) 3/7

C) 7/3

D) 0

6 / 40

y=xlnx funksiyani hosilasini toping.

A) 1

B) lnx/2+1

C) 2lnx-1

D) lnx+1

7 / 40

5^-x≤ 0,04 x ning eng kichik butun qiymatini toping.

A) 3

B) 2

C) 0

D) -1

8 / 40

Tenglamaning [0;π] kesmadagi ildizlari soni 3 tadan ko'pmi?

A) Yo'q

B) Ha

9 / 40

To'g'ri burchakli uchburchakning gipotenuzasiga o'tkazilgan bissiktriksasi uni 20 va 30 ga teng kesmalarga ajratadi. To'g'ri burchakli uchburchak yuzini toping.

A) 15

B) 7500/13

C) 7551/15

D) 6700/13

10 / 40

Tenglamani yeching.

A) 1

B) 5

C) 2

D) 0

11 / 40

Hisoblang.

A) 0

B) -1

C) 1

D) 2

12 / 40

Hisoblang.

A) 4

B) 2

C) 0

D) 1

13 / 40

Tengsizlikni yeching.

A) x∈(1;1000]

B) x∈[0;1000]

C) x∈(0;1000)

D) x∈(10;1000)

14 / 40

Tenglamani yeching:

A) 2,5

B) 5,5

C) 2

D) 6

15 / 40

Agar va ular orasidagi burchak 120° bo'lsa, ni toping.

A) 4√5

B) √7

C) 3√7

D) 2√7

16 / 40

Tengsizlikni yeching: 3 · 9^x–10 · 21^x+ 7 · 49 ^x ≤ 0

A) [-1;1]

B) [-1;0]

C) (-1;3]

D) [-1;0)

17 / 40

Hisoblang.

A) 14-2b

B) 24+3b

C) 26-3b

D) 24-3b

18 / 40

Chizmada nechta uchburchak tasvirlangan?

A) 54

B) 50

C) 48

D) 52

19 / 40

Hisoblang.

A) 96

B) 94

C) 32

D) 98

20 / 40

Tenglamani yeching.

A) 3

B) 4

C) 2

D) 1

21 / 40

Hisoblang.

A) 51/29

B) -47/25

C) -47/24

D) 49/25

22 / 40

Ayirmasi d ga teng bo'lgan arifmetik progrssiya uchun ni toping.

A) 2

B) 1/2

C) 1

D) 2/3

23 / 40

f(x)+(x-2)·g(x)=x²+5, f(3)=10 bo'lsa, g^-1=(4) ni toping. Bunda g^-1(x) g(x) ga teskari funksiya.

A) 4

B) 5

C) 6

D) 3

24 / 40

Uchburchak tamonlari 10, 24 va 26 ga teng bo'lsa, katta burchagi necha gradus?

A) 60°

B) 75°

C) 90°

D) 80°

25 / 40

|x²-2x|≤x yengsizlikni yeching.

A) {0}∪[1;3]

B) (-2;0)∪[1;3]

C) {0}∪(1;3]

D) {0}∪[1;3)

26 / 40

Tengsizlikni yeching.

A) [-7;-3] u [-1;∞)

B) [-7;-3) u [-1;∞)

C) [-7;-5) u [-1;∞)

D) [-7;3 u [-1;∞)

27 / 40

y = x²+1-|sinx| funksiya grafigi OX o'qidan pastda yotadimi?

A) Yotadi

B) Yotmaydi

28 / 40

Noaniq integralni toping. ∫(sin²x+cos²x)dx

A) c

B) 4x+c

C) 2x+c

D) x+c

29 / 40

a=1^0,(6), b=8^0,(3) , c=2^0,(9) bo'lsa, (a+b)^c=?

A) 16

B) 9

C) 0

D) 25

30 / 40

Noaniq integralni toping. ∫(sin²x+cos²x)dx

A) 4x+c

B) x/2+c

C) 2x+c

D) x+c

31 / 40

Tenglama ildizlari yig'indisini toping.

A) 2

B) -1

C) 4

D) 0

32 / 40

1, 2, 3, 4 raqamlaridan foydalanib 400 dan kichik kechta uc xonali son yasash mumkin?

A) 49

B) 51

C) 47

D) 48

33 / 40

Agar bo'lsa f(x)=?

A) x²-2

B) 2x²-1

C) x²-1

D) x²+2

34 / 40

(2; 3; -5) nuqtaning OX o'qiga nisbatan simmetrik nuqtasini toping.

A) (2; -3; 5)

B) (2; 3; -5)

C) (2; -3; -5)

D) (-2; 3; 5)

35 / 40

Hisoblang.

A) 1

B) 3

C) 6

D) 2

36 / 40

Hisoblang.

A) 2019

B) 1

C) 2020

D) 2021

37 / 40

Agar cos4x = acos⁴x+bcos2²x+1 bo'lsa, a+b=?

A) 0

B) 2

C) 1

D) -1

38 / 40

Hisoblang.

A) 1

B) 2

C) 0

D) -1

39 / 40

Hisoblang.

A) 3

B) 4

C) 6

D) 5

40 / 40

ABCD parallelogramm va S_KBCE= 18 bo'lsa, S_ABCD=?

A) 54

B) 48

C) 62

D) 56

Baholash mezoni

- 75 foiz va undan yuqori ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, oliy malaka toifasi (bosh o’qituvchi lavozimi) saqlansin”;

- 75 foizdan past ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, birinchi malaka toifasi (yetakchi o’qituvchi lavozimi)ga tushirilsin”;

- 75 foiz va undan yuqori ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, oliy malaka toifasi (bosh o’qituvchi lavozimi) berilsin”;

- 74 foizdan 65 foizgacha ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, birinchi malaka toifasi (yetakchi o’qituvchi lavozimi) saqlansin”;

- 65 foizdan kam ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, ikkinchi malaka toifasi (katta o’qituvchi lavozimi)ga tushirilsin”

- 64 foizdan 60 foizgacha ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, ikkinchi malaka toifasi (katta o’qituvchi lavozimi) saqlansin”;

- 60 foizdan kam ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, mutaxassis (oliy yoki o’rta maxsus, kasb-hunar ma'lumotli o’qituvchi) lavozimiga tushirilsin”