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Matematika attestatsiya №12

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Aprel 8, 2022

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OMAD YOR BO'LSIN!

Matematika fanidan attestatsiya savollari №12

28.03.2022 da Toshkentda tushgan savollar

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Testda 76% va undan yuqori natija oling va sertifikatni yuklab oling.

1 / 40

I, M , O - turli natural sonlar uchun I·M·O = 2022 bo‘lsa, I + M+O yig‘indining mumkin bo‘lgan eng katta va eng kichik qiymatlari yig‘indisini toping.

A) 1014

B) 1011

C) 1356

D) 1250

2 / 40

Bir nechta natural sonlardan tuzilgan S to‘plam berilgan. Bu sonlarning o‘rta
arifmetigi eng kattasini hisobga olmaganda 32 ga, eng kichigini hisobga olmaganda 40 ga, eng kattasini ham eng kichigini ham hisobga olmaganda esa 35 ga teng. Agar eng katta son eng kichigidan 72 ga ortiq bo‘lsa, u holda S to‘plamdagi barcha sonlarning o‘rta arifmetigini toping.

A) 36,4

B) 36,8

C) 36,6

D) 36,2

3 / 40

f(x) va g(x) funksiyalar f(x)+(x-2)·g(x)=x²+5 bog’lanishda va f(3)=10 bo’lsa, g^-1 (4) ning qiymatini toping.(g^-1 (x)-g(x) ga teskari funksiya)

A) 4

B) 3

C) 6

D) 2

4 / 40

to‘plamning nechta xos qism-to‘plamlari mavjud?

A) 16

B) 30

C) 5

D) 32

5 / 40

|x²-2x|≤x yengsizlikni yeching.

A) {0}∪[1;3)

B) {0}∪(1;3]

C) (-2;0)∪[1;3]

D) {0}∪[1;3]

6 / 40

To'g'ri burchakli uchburchakning gipotenuzasiga o'tkazilgan bissiktriksasi uni 20 va 30 ga teng kesmalarga ajratadi. To'g'ri burchakli uchburchak yuzini toping.

A) 7551/15

B) 6700/13

C) 7500/13

D) 15

7 / 40

Noaniq integralni toping. ∫(sin²x+cos²x)dx

A) 2x+c

B) 4x+c

C) x+c

D) c

8 / 40

5^-x≤ 0,04 x ning eng kichik butun qiymatini toping.

A) -1

B) 2

C) 3

D) 0

9 / 40

Hisoblang.

A) 2

B) 3

C) 1

D) 6

10 / 40

Uchburchak tamonlari 10, 24 va 26 ga teng bo'lsa, katta burchagi necha gradus?

A) 90°

B) 80°

C) 60°

D) 75°

11 / 40

Arimetik progerssiyada s₁₂=354, P=a₁+a₂+...+a₁₁, Q=a₂+a₄+...+a₁₂ va P/Q=32/27 ga teng bo'lsa, d ni toping.

A) -5

B) -4

C) -6

D) -3

12 / 40

Hisoblang.

A) -1

B) 1

C) 0

D) 2

13 / 40

a=1^0,(6), b=8^0,(3) , c=2^0,(9) bo'lsa, (a+b)^c=?

A) 0

B) 16

C) 9

D) 25

14 / 40

Hisoblang.

A) 24-3b

B) 24+3b

C) 14-2b

D) 26-3b

15 / 40

Tamonlarini ayirmasi 14 bo'lgan parallelogramning o'rmas burchagidan katta diagonaliga tushgan balandlik uni 12 va 30 ga teng kesmalarga ajratadi. Tamonlar uzunligini toping.

A) 30 va 24

B) 36 va 18

C) 32 va 22

D) 34 va 20

16 / 40

Ayirmasi d ga teng bo'lgan arifmetik progrssiya uchun ni toping.

A) 2

B) 1/2

C) 1

D) 2/3

17 / 40

Noaniq integralni toping. ∫(sin²x+cos²x)dx

A) 2x+c

B) x/2+c

C) x+c

D) 4x+c

18 / 40

Hisoblang. cos²10° + cos²30° + cos²80°

A) 7/4

B) 7/3

C) 0

D) 3/7

19 / 40

Agar bo'lsa f(x)=?

A) x²-2

B) x²+2

C) 2x²-1

D) x²-1

20 / 40

(2; 3; -5) nuqtaning OX o'qiga nisbatan simmetrik nuqtasini toping.

A) (-2; 3; 5)

B) (2; -3; -5)

C) (2; -3; 5)

D) (2; 3; -5)

21 / 40

Tengsizlikni yeching.

A) x∈(10;1000)

B) x∈(0;1000)

C) x∈(1;1000]

D) x∈[0;1000]

22 / 40

To'g'ri burchakli uchburchakning yuzi 96 ga, perimetri esa 48 ga teng bo'lsa, gipatenuza uzunligini toping.

A) 21

B) 18

C) 20

D) 23

23 / 40

Hisoblang.

A) 9/11

B) 0

C) 7/11

D) 9/13

24 / 40

Hisoblang.

A) -47/25

B) 51/29

C) 49/25

D) -47/24

25 / 40

Tenglamani yeching:

A) 6

B) 2,5

C) 2

D) 5,5

26 / 40

Agar cos4x = acos⁴x+bcos2²x+1 bo'lsa, a+b=?

A) 1

B) -1

C) 0

D) 2

27 / 40

Tenglamaning [0;π] kesmadagi ildizlari soni 3 tadan ko'pmi?

A) Ha

B) Yo'q

28 / 40

Hisoblang.

A) 2

B) 4

C) 0

D) 1

29 / 40

Hisoblang.

A) 4

B) 5

C) 6

D) 3

30 / 40

y = x²+1-|sinx| funksiya grafigi OX o'qidan pastda yotadimi?

A) Yotadi

B) Yotmaydi

31 / 40

To'g'ri burchakli uchburchakka ichki va tashqi chizilgan aylanalar raduslari 6 va 15 ga teng bo'lsa, katetlar yig'indini toping.

A) 48

B) 35

C) 28

D) 42

32 / 40

Hisoblang.

A) -2 yoki -1

B) 0

C) -2 yoki 2

D) -2 yoki 0

33 / 40

(tgx-2ctgx)⁴ yoyilmaning ozod hadini toping.

A) 6

B) 24

C) 25

D) 58

34 / 40

1, 2, 3, 4 raqamlaridan foydalanib 400 dan kichik kechta uc xonali son yasash mumkin?

A) 48

B) 51

C) 47

D) 49

35 / 40

ABCD parallelogramm va S_KBCE= 18 bo'lsa, S_ABCD=?

A) 48

B) 56

C) 54

D) 62

36 / 40

Agar va ular orasidagi burchak 120° bo'lsa, ni toping.

A) √7

B) 3√7

C) 4√5

D) 2√7

37 / 40

Tenglamani yeching.

A) 4

B) 3

C) 2

D) 1

38 / 40

f(x) = x²-3x-2 bo'lsa. f(a+b+c)-f(abc)=? Bunda a, b, c - kvadrat funksiya koeffitsiyentlari.

A) 40

B) 42

C) 38

D) 36

39 / 40

Hisoblang.

A) 135

B) 133

C) 131

D) 121

40 / 40

Tenglamani yeching.

A) 0

B) 5

C) 1

D) 2

Baholash mezoni

- 75 foiz va undan yuqori ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, oliy malaka toifasi (bosh o’qituvchi lavozimi) saqlansin”;

- 75 foizdan past ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, birinchi malaka toifasi (yetakchi o’qituvchi lavozimi)ga tushirilsin”;

- 75 foiz va undan yuqori ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, oliy malaka toifasi (bosh o’qituvchi lavozimi) berilsin”;

- 74 foizdan 65 foizgacha ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, birinchi malaka toifasi (yetakchi o’qituvchi lavozimi) saqlansin”;

- 65 foizdan kam ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, ikkinchi malaka toifasi (katta o’qituvchi lavozimi)ga tushirilsin”

- 64 foizdan 60 foizgacha ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, ikkinchi malaka toifasi (katta o’qituvchi lavozimi) saqlansin”;

- 60 foizdan kam ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, mutaxassis (oliy yoki o’rta maxsus, kasb-hunar ma'lumotli o’qituvchi) lavozimiga tushirilsin”