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Matematika attestatsiya №12

InfoMaster

Aprel 8, 2022

132 Ko'rishlar 1 izoh

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OMAD YOR BO'LSIN!

Matematika fanidan attestatsiya savollari №12

28.03.2022 da Toshkentda tushgan savollar

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Testda 76% va undan yuqori natija oling va sertifikatni yuklab oling.

1 / 40

Agar a∈[-3;1] va b∈[-2;2]bo‘lsa, a² + b³ qanday oraliqda bo‘ladi?

A) [0;17]

B) [-8;17]

C) [-8;0]

D) [-17;8]

2 / 40

Bir nechta natural sonlardan tuzilgan S to‘plam berilgan. Bu sonlarning o‘rta
arifmetigi eng kattasini hisobga olmaganda 32 ga, eng kichigini hisobga olmaganda 40 ga, eng kattasini ham eng kichigini ham hisobga olmaganda esa 35 ga teng. Agar eng katta son eng kichigidan 72 ga ortiq bo‘lsa, u holda S to‘plamdagi barcha sonlarning o‘rta arifmetigini toping.

A) 36,8

B) 36,2

C) 36,4

D) 36,6

3 / 40

ABCD parallelogramm va ABED toʻrtburchakka aylana ichki chizilgan. Agar DE=8, AB=12 boʻlsa, BEC uchburchakning perimetrini toping.

A) 22

B) 25

C) 27

D) 24

4 / 40

360 ning juft va tub bo‘luvchilarining yig‘indisini toping.

A) 1112

B) 1092

C) 1102

D) 960

5 / 40

Tenglama ildizlari yig'indisini toping.

A) -1

B) 2

C) 4

D) 0

6 / 40

Tenglamani yeching:

A) 2

B) 6

C) 2,5

D) 5,5

7 / 40

Hisoblang.

A) 1

B) 6

C) 3

D) 2

8 / 40

Noaniq integralni toping. ∫(sin²x+cos²x)dx

A) c

B) x+c

C) 2x+c

D) 4x+c

9 / 40

ABCD parallelogramm va S_KBCE= 18 bo'lsa, S_ABCD=?

A) 56

B) 54

C) 62

D) 48

10 / 40

|x²-2x|≤x yengsizlikni yeching.

A) {0}∪[1;3)

B) (-2;0)∪[1;3]

C) {0}∪(1;3]

D) {0}∪[1;3]

11 / 40

Hisoblang.

A) 121

B) 135

C) 133

D) 131

12 / 40

Hisoblang.

A) 94

B) 96

C) 32

D) 98

13 / 40

Hisoblang.

A) 0

B) -2 yoki 0

C) -2 yoki -1

D) -2 yoki 2

14 / 40

To'g'ri burchakli uchburchakning yuzi 96 ga, perimetri esa 48 ga teng bo'lsa, gipatenuza uzunligini toping.

A) 20

B) 23

C) 18

D) 21

15 / 40

Agar bo'lsa, ni toping.

A) 5,2

B) 2,5

C) 3

D) 0

16 / 40

Hisoblang.

A) 2

B) 1

C) -1

D) 0

17 / 40

f(x) = x²-3x-2 bo'lsa. f(a+b+c)-f(abc)=? Bunda a, b, c - kvadrat funksiya koeffitsiyentlari.

A) 38

B) 40

C) 42

D) 36

18 / 40

Agar cos4x = acos⁴x+bcos2²x+1 bo'lsa, a+b=?

A) 0

B) 2

C) -1

D) 1

19 / 40

Hisoblang.

A) 4

B) 1

C) 2

D) 0

20 / 40

Hisoblang.

A) 7/11

B) 9/11

C) 0

D) 9/13

21 / 40

Tengsizlikni yeching.

A) x∈[0;1000]

B) x∈(0;1000)

C) x∈(10;1000)

D) x∈(1;1000]

22 / 40

Uchburchak tamonlari 10, 24 va 26 ga teng bo'lsa, katta burchagi necha gradus?

A) 90°

B) 80°

C) 75°

D) 60°

23 / 40

Hisoblang.

A) 2019

B) 2021

C) 1

D) 2020

24 / 40

a=1^0,(6), b=8^0,(3) , c=2^0,(9) bo'lsa, (a+b)^c=?

A) 9

B) 0

C) 25

D) 16

25 / 40

Hisoblang.

A) 2

B) 1

C) -1

D) 0

26 / 40

Hisoblang.

A) 0

B) 2

C) -1

D) 1

27 / 40

Hisoblang

A) 9

B) 12

C) 6

D) 36

28 / 40

(2; 3; -5) nuqtaning OX o'qiga nisbatan simmetrik nuqtasini toping.

A) (2; -3; -5)

B) (2; -3; 5)

C) (-2; 3; 5)

D) (2; 3; -5)

29 / 40

To'g'ri burchakli uchburchakning gipotenuzasiga o'tkazilgan bissiktriksasi uni 20 va 30 ga teng kesmalarga ajratadi. To'g'ri burchakli uchburchak yuzini toping.

A) 15

B) 6700/13

C) 7551/15

D) 7500/13

30 / 40

1, 2, 3, 4 raqamlaridan foydalanib 400 dan kichik kechta uc xonali son yasash mumkin?

A) 49

B) 48

C) 51

D) 47

31 / 40

Tenglamaning [0;π] kesmadagi ildizlari soni 3 tadan ko'pmi?

A) Ha

B) Yo'q

32 / 40

y = x²+1-|sinx| funksiya grafigi OX o'qidan pastda yotadimi?

A) Yotadi

B) Yotmaydi

33 / 40

5^-x≤ 0,04 x ning eng kichik butun qiymatini toping.

A) 0

B) -1

C) 3

D) 2

34 / 40

Agar va ular orasidagi burchak 120° bo'lsa, ni toping.

A) 4√5

B) 3√7

C) 2√7

D) √7

35 / 40

Noaniq integralni toping. ∫(sin²x+cos²x)dx

A) 4x+c

B) x/2+c

C) 2x+c

D) x+c

36 / 40

Hisoblang.

A) -47/24

B) -47/25

C) 51/29

D) 49/25

37 / 40

Hisoblang.

A) 4

B) 5

C) 6

D) 3

38 / 40

Tengsizlikni yeching: 3 · 9^x–10 · 21^x+ 7 · 49 ^x ≤ 0

A) [-1;0]

B) [-1;0)

C) (-1;3]

D) [-1;1]

39 / 40

Agar bo'lsa f(x)=?

A) x²-1

B) 2x²-1

C) x²+2

D) x²-2

40 / 40

Tenglamani yeching.

A) 5

B) 1

C) 2

D) 0

Baholash mezoni

- 75 foiz va undan yuqori ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, oliy malaka toifasi (bosh o’qituvchi lavozimi) saqlansin”;

- 75 foizdan past ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, birinchi malaka toifasi (yetakchi o’qituvchi lavozimi)ga tushirilsin”;

- 75 foiz va undan yuqori ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, oliy malaka toifasi (bosh o’qituvchi lavozimi) berilsin”;

- 74 foizdan 65 foizgacha ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, birinchi malaka toifasi (yetakchi o’qituvchi lavozimi) saqlansin”;

- 65 foizdan kam ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, ikkinchi malaka toifasi (katta o’qituvchi lavozimi)ga tushirilsin”

- 64 foizdan 60 foizgacha ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, ikkinchi malaka toifasi (katta o’qituvchi lavozimi) saqlansin”;

- 60 foizdan kam ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, mutaxassis (oliy yoki o’rta maxsus, kasb-hunar ma'lumotli o’qituvchi) lavozimiga tushirilsin”