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Matematika attestatsiya №12

InfoMaster

Aprel 8, 2022

114 Ko'rishlar 1 izoh

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OMAD YOR BO'LSIN!

Matematika fanidan attestatsiya savollari №12

28.03.2022 da Toshkentda tushgan savollar

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Testda 76% va undan yuqori natija oling va sertifikatni yuklab oling.

1 / 40

ni hisoblang.

A) 4

B) 2

C) 3

D) 1

2 / 40

Bir nechta natural sonlardan tuzilgan S to‘plam berilgan. Bu sonlarning o‘rta
arifmetigi eng kattasini hisobga olmaganda 32 ga, eng kichigini hisobga olmaganda 40 ga, eng kattasini ham eng kichigini ham hisobga olmaganda esa 35 ga teng. Agar eng katta son eng kichigidan 72 ga ortiq bo‘lsa, u holda S to‘plamdagi barcha sonlarning o‘rta arifmetigini toping.

A) 36,6

B) 36,8

C) 36,4

D) 36,2

3 / 40

Hisoblang:

A) 77/810

B) 7/18

C) 70/80

D) 71/91

4 / 40

0, 1, 2, 3, 4, 5 raqamlaridan nechta 3 xonali tuzish mumkin?

A) 100

B) 125

C) 180

D) 200

5 / 40

Noaniq integralni toping. ∫(sin²x+cos²x)dx

A) x+c

B) 4x+c

C) x/2+c

D) 2x+c

6 / 40

Tengsizlikni yeching: 3 · 9^x–10 · 21^x+ 7 · 49 ^x ≤ 0

A) [-1;1]

B) [-1;0)

C) [-1;0]

D) (-1;3]

7 / 40

Tengsizlikni yeching.

A) [-7;-3] u [-1;∞)

B) [-7;-3) u [-1;∞)

C) [-7;3 u [-1;∞)

D) [-7;-5) u [-1;∞)

8 / 40

Agar cos4x = acos⁴x+bcos2²x+1 bo'lsa, a+b=?

A) 0

B) 2

C) 1

D) -1

9 / 40

To'g'ri burchakli uchburchakning yuzi 96 ga, perimetri esa 48 ga teng bo'lsa, gipatenuza uzunligini toping.

A) 23

B) 18

C) 20

D) 21

10 / 40

|x²-2x|≤x yengsizlikni yeching.

A) {0}∪[1;3]

B) (-2;0)∪[1;3]

C) {0}∪(1;3]

D) {0}∪[1;3)

11 / 40

ABCD parallelogramm va S_KBCE= 18 bo'lsa, S_ABCD=?

A) 54

B) 56

C) 62

D) 48

12 / 40

(tgx-2ctgx)⁴ yoyilmaning ozod hadini toping.

A) 58

B) 25

C) 24

D) 6

13 / 40

Tenglama ildizlari yig'indisini toping.

A) 0

B) 4

C) 2

D) -1

14 / 40

Tamonlarini ayirmasi 14 bo'lgan parallelogramning o'rmas burchagidan katta diagonaliga tushgan balandlik uni 12 va 30 ga teng kesmalarga ajratadi. Tamonlar uzunligini toping.

A) 32 va 22

B) 36 va 18

C) 34 va 20

D) 30 va 24

15 / 40

Hisoblang.

A) -2 yoki 2

B) -2 yoki -1

C) 0

D) -2 yoki 0

16 / 40

Tengsizlikni yeching.

A) x∈(0;1000)

B) x∈(10;1000)

C) x∈[0;1000]

D) x∈(1;1000]

17 / 40

Hisoblang.

A) 24+3b

B) 26-3b

C) 24-3b

D) 14-2b

18 / 40

Arimetik progerssiyada s₁₂=354, P=a₁+a₂+...+a₁₁, Q=a₂+a₄+...+a₁₂ va P/Q=32/27 ga teng bo'lsa, d ni toping.

A) -5

B) -6

C) -4

D) -3

19 / 40

y = x²+1-|sinx| funksiya grafigi OX o'qidan pastda yotadimi?

A) Yotadi

B) Yotmaydi

20 / 40

Noaniq integralni toping. ∫(sin²x+cos²x)dx

A) x+c

B) 2x+c

C) 4x+c

D) c

21 / 40

(tgx+ctgx)⁴ yoyilmaning ozod hadini toping.

A) 6

B) 3

C) 4

D) 5

22 / 40

Tenglamani yeching.

A) 2

B) 0

C) 1

D) 5

23 / 40

Hisoblang.

A) 2021

B) 1

C) 2020

D) 2019

24 / 40

Hisoblang. cos²10° + cos²30° + cos²80°

A) 3/7

B) 0

C) 7/4

D) 7/3

25 / 40

Hisoblang

A) 6

B) 36

C) 12

D) 9

26 / 40

a=1^0,(6), b=8^0,(3) , c=2^0,(9) bo'lsa, (a+b)^c=?

A) 0

B) 9

C) 25

D) 16

27 / 40

(2; 3; -5) nuqtaning OX o'qiga nisbatan simmetrik nuqtasini toping.

A) (-2; 3; 5)

B) (2; 3; -5)

C) (2; -3; -5)

D) (2; -3; 5)

28 / 40

Hisoblang.

A) 5

B) 6

C) 4

D) 3

29 / 40

Hisoblang.

A) 1

B) 0

C) 2

D) 4

30 / 40

Hisoblang.

A) 9/11

B) 0

C) 9/13

D) 7/11

31 / 40

Agar va ular orasidagi burchak 120° bo'lsa, ni toping.

A) 3√7

B) 2√7

C) √7

D) 4√5

32 / 40

Hisoblang.

A) 3

B) 1

C) 4

D) 2

33 / 40

Tenglamani yeching.

A) 4

B) 1

C) 2

D) 3

34 / 40

To'g'ri burchakli uchburchakning gipotenuzasiga o'tkazilgan bissiktriksasi uni 20 va 30 ga teng kesmalarga ajratadi. To'g'ri burchakli uchburchak yuzini toping.

A) 7551/15

B) 15

C) 7500/13

D) 6700/13

35 / 40

Tangga besh martta tashlanganda 2 martta gerb chiqishi ehtimolini toping.

A) 7/16

B) 9/16

C) 5/13

D) 5/16

36 / 40

Hisoblang.

A) -47/24

B) -47/25

C) 49/25

D) 51/29

37 / 40

y=xlnx funksiyani hosilasini toping.

A) lnx+1

B) 2lnx-1

C) lnx/2+1

D) 1

38 / 40

Uchburchak tamonlari 10, 24 va 26 ga teng bo'lsa, katta burchagi necha gradus?

A) 60°

B) 90°

C) 80°

D) 75°

39 / 40

Hisoblang.

A) 5/3

B) 3/2

C) 2/3

D) 3/5

40 / 40

Agar bo'lsa f(x)=?

A) x²+2

B) 2x²-1

C) x²-2

D) x²-1

Baholash mezoni

- 75 foiz va undan yuqori ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, oliy malaka toifasi (bosh o’qituvchi lavozimi) saqlansin”;

- 75 foizdan past ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, birinchi malaka toifasi (yetakchi o’qituvchi lavozimi)ga tushirilsin”;

- 75 foiz va undan yuqori ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, oliy malaka toifasi (bosh o’qituvchi lavozimi) berilsin”;

- 74 foizdan 65 foizgacha ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, birinchi malaka toifasi (yetakchi o’qituvchi lavozimi) saqlansin”;

- 65 foizdan kam ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, ikkinchi malaka toifasi (katta o’qituvchi lavozimi)ga tushirilsin”

- 64 foizdan 60 foizgacha ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, ikkinchi malaka toifasi (katta o’qituvchi lavozimi) saqlansin”;

- 60 foizdan kam ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, mutaxassis (oliy yoki o’rta maxsus, kasb-hunar ma'lumotli o’qituvchi) lavozimiga tushirilsin”