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Matematika attestatsiya №12

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Aprel 8, 2022

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OMAD YOR BO'LSIN!

Matematika fanidan attestatsiya savollari №12

28.03.2022 da Toshkentda tushgan savollar

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1 / 40

Quyidagilardan qaysi biri to‘g‘ri?

A) To‘g‘ri kasrning surat va maxrajiga bir xil son qo‘shib borilsa, kasr kichiklashib boradi.

B) Barchasi

C) 5²⁰²²+6²⁰²²<7²⁰²²

D) Parallelogrammning diagonallari o‘zaro perpendikulyar bo‘lsa, u kvadrat bo‘ladi.

2 / 40

a, b, c - haqiqiy sonlari uchun a ·b² < 0 < c - b va a·c > 0 bo‘lsa, a, b va c larning ishoralarini aniqlang.

A) -,+,+

B) -,-,-

C) -,+,-

D) -,-,+

3 / 40

ABCD parallelogramm va ABED toʻrtburchakka aylana ichki chizilgan. Agar DE=8, AB=12 boʻlsa, BEC uchburchakning perimetrini toping.

A) 24

B) 25

C) 22

D) 27

4 / 40

Quyidagi tenglikdan a ni toping.

A) 1/16

B) 1/64

C) 1/48

D) 1/4

5 / 40

Noaniq integralni toping. ∫(sin²x+cos²x)dx

A) 4x+c

B) 2x+c

C) x+c

D) c

6 / 40

Tamonlarini ayirmasi 14 bo'lgan parallelogramning o'rmas burchagidan katta diagonaliga tushgan balandlik uni 12 va 30 ga teng kesmalarga ajratadi. Tamonlar uzunligini toping.

A) 32 va 22

B) 36 va 18

C) 34 va 20

D) 30 va 24

7 / 40

Hisoblang.

A) 3/2

B) 3/5

C) 2/3

D) 5/3

8 / 40

(tgx-2ctgx)⁴ yoyilmaning ozod hadini toping.

A) 24

B) 25

C) 58

D) 6

9 / 40

1, 2, 3, 4 raqamlaridan foydalanib 400 dan kichik kechta uc xonali son yasash mumkin?

A) 49

B) 47

C) 48

D) 51

10 / 40

Tenglama ildizlari yig'indisini toping.

A) 4

B) -1

C) 0

D) 2

11 / 40

Hisoblang.

A) 4

B) 2

C) 1

D) 3

12 / 40

Hisoblang.

A) 2

B) -1

C) 1

D) 0

13 / 40

Hisoblang.

A) 96

B) 94

C) 98

D) 32

14 / 40

Noaniq integralni toping. ∫(sin²x+cos²x)dx

A) 4x+c

B) x+c

C) 2x+c

D) x/2+c

15 / 40

To'g'ri burchakli uchburchakning gipotenuzasiga o'tkazilgan bissiktriksasi uni 20 va 30 ga teng kesmalarga ajratadi. To'g'ri burchakli uchburchak yuzini toping.

A) 7500/13

B) 15

C) 6700/13

D) 7551/15

16 / 40

Agar bo'lsa f(x)=?

A) x²-2

B) x²-1

C) x²+2

D) 2x²-1

17 / 40

y=xlnx funksiyani hosilasini toping.

A) lnx+1

B) lnx/2+1

C) 2lnx-1

D) 1

18 / 40

Tengsizlikni yeching.

A) x∈(1;1000]

B) x∈(10;1000)

C) x∈[0;1000]

D) x∈(0;1000)

19 / 40

Hisoblang.

A) 2

B) 0

C) 4

D) 1

20 / 40

ABCD parallelogramm va S_KBCE= 18 bo'lsa, S_ABCD=?

A) 48

B) 54

C) 56

D) 62

21 / 40

Hisoblang.

A) -47/25

B) 51/29

C) 49/25

D) -47/24

22 / 40

Tengsizlikni yeching: 3 · 9^x–10 · 21^x+ 7 · 49 ^x ≤ 0

A) [-1;1]

B) [-1;0]

C) [-1;0)

D) (-1;3]

23 / 40

Hisoblang.

A) 6

B) 2

C) 3

D) 1

24 / 40

(tgx+ctgx)⁴ yoyilmaning ozod hadini toping.

A) 4

B) 6

C) 3

D) 5

25 / 40

Hisoblang.

A) -2 yoki 0

B) -2 yoki 2

C) 0

D) -2 yoki -1

26 / 40

f(x) = x²-3x-2 bo'lsa. f(a+b+c)-f(abc)=? Bunda a, b, c - kvadrat funksiya koeffitsiyentlari.

A) 42

B) 36

C) 38

D) 40

27 / 40

Agar va ular orasidagi burchak 120° bo'lsa, ni toping.

A) √7

B) 3√7

C) 4√5

D) 2√7

28 / 40

a=1^0,(6), b=8^0,(3) , c=2^0,(9) bo'lsa, (a+b)^c=?

A) 16

B) 9

C) 0

D) 25

29 / 40

To'g'ri burchakli uchburchakning yuzi 96 ga, perimetri esa 48 ga teng bo'lsa, gipatenuza uzunligini toping.

A) 20

B) 21

C) 23

D) 18

30 / 40

Tenglamani yeching.

A) 4

B) 3

C) 2

D) 1

31 / 40

Tenglamaning [0;π] kesmadagi ildizlari soni 3 tadan ko'pmi?

A) Yo'q

B) Ha

32 / 40

Hisoblang

A) 36

B) 6

C) 9

D) 12

33 / 40

Tengsizlikni yeching.

A) [-7;-3] u [-1;∞)

B) [-7;-5) u [-1;∞)

C) [-7;3 u [-1;∞)

D) [-7;-3) u [-1;∞)

34 / 40

|x²-2x|≤x yengsizlikni yeching.

A) (-2;0)∪[1;3]

B) {0}∪(1;3]

C) {0}∪[1;3]

D) {0}∪[1;3)

35 / 40

Hisoblang.

A) 121

B) 133

C) 135

D) 131

36 / 40

Arimetik progerssiyada s₁₂=354, P=a₁+a₂+...+a₁₁, Q=a₂+a₄+...+a₁₂ va P/Q=32/27 ga teng bo'lsa, d ni toping.

A) -6

B) -3

C) -4

D) -5

37 / 40

Chizmada nechta uchburchak tasvirlangan?

A) 52

B) 48

C) 50

D) 54

38 / 40

Tenglamani yeching.

A) 2

B) 5

C) 1

D) 0

39 / 40

Uchburchak tamonlari 10, 24 va 26 ga teng bo'lsa, katta burchagi necha gradus?

A) 60°

B) 75°

C) 90°

D) 80°

40 / 40

Hisoblang.

A) 1

B) 2019

C) 2020

D) 2021

Baholash mezoni

- 75 foiz va undan yuqori ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, oliy malaka toifasi (bosh o’qituvchi lavozimi) saqlansin”;

- 75 foizdan past ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, birinchi malaka toifasi (yetakchi o’qituvchi lavozimi)ga tushirilsin”;

- 75 foiz va undan yuqori ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, oliy malaka toifasi (bosh o’qituvchi lavozimi) berilsin”;

- 74 foizdan 65 foizgacha ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, birinchi malaka toifasi (yetakchi o’qituvchi lavozimi) saqlansin”;

- 65 foizdan kam ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, ikkinchi malaka toifasi (katta o’qituvchi lavozimi)ga tushirilsin”

- 64 foizdan 60 foizgacha ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, ikkinchi malaka toifasi (katta o’qituvchi lavozimi) saqlansin”;

- 60 foizdan kam ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, mutaxassis (oliy yoki o’rta maxsus, kasb-hunar ma'lumotli o’qituvchi) lavozimiga tushirilsin”