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Matematika attestatsiya №12

InfoMaster

Aprel 8, 2022

120 Ko'rishlar 1 izoh

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OMAD YOR BO'LSIN!

Matematika fanidan attestatsiya savollari №12

28.03.2022 da Toshkentda tushgan savollar

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Testda 76% va undan yuqori natija oling va sertifikatni yuklab oling.

1 / 40

Agar x+1/x=1 bo'lsa, ning qiymatini toping.

A) 3

B) 1/3

C) 2

D) -1/2

2 / 40

A(1; 3) nuqtadan 12x+5y+a–4=0 to’g’ri chiziqqacha bo’lgan masofa 2 bo’lsa, a ni toping.

A) 4

B) 3

C) 1

D) 2

3 / 40

Rostgo’ylar va yolg’onchilar orolida gulxan atrofida o’tirgan 7 ta kishi har biri “Men ikki yolg’onchining orasida o’tiribman” deydi. Orolda nechta yolg’onchi bor?

A) 5 ta

B) 7 ta

C) 3 ta

D) 4 ta

4 / 40

Agar A=x³+x²-2x, B=x⁴-x va C=x⁴+2x³-3x² bo'lsa, EKUB( A; B;C) ni toping.

A) x+3

B) x-2

C) x

D) x(x-1)

5 / 40

Hisoblang.

A) 0

B) -2 yoki -1

C) -2 yoki 2

D) -2 yoki 0

6 / 40

To'g'ri burchakli uchburchakning gipotenuzasiga o'tkazilgan bissiktriksasi uni 20 va 30 ga teng kesmalarga ajratadi. To'g'ri burchakli uchburchak yuzini toping.

A) 7551/15

B) 7500/13

C) 15

D) 6700/13

7 / 40

Agar bo'lsa f(x)=?

A) x²+2

B) x²-2

C) 2x²-1

D) x²-1

8 / 40

Hisoblang.

A) 24-3b

B) 24+3b

C) 26-3b

D) 14-2b

9 / 40

Hisoblang.

A) 1

B) 2

C) -1

D) 0

10 / 40

Hisoblang.

A) -47/24

B) 51/29

C) 49/25

D) -47/25

11 / 40

To'g'ri burchakli uchburchakka ichki va tashqi chizilgan aylanalar raduslari 6 va 15 ga teng bo'lsa, katetlar yig'indini toping.

A) 35

B) 48

C) 42

D) 28

12 / 40

y=xlnx funksiyani hosilasini toping.

A) lnx+1

B) lnx/2+1

C) 2lnx-1

D) 1

13 / 40

Hisoblang.

A) 121

B) 131

C) 135

D) 133

14 / 40

Agar va ular orasidagi burchak 120° bo'lsa, ni toping.

A) 4√5

B) 2√7

C) √7

D) 3√7

15 / 40

(2; 3; -5) nuqtaning OX o'qiga nisbatan simmetrik nuqtasini toping.

A) (2; -3; 5)

B) (2; 3; -5)

C) (-2; 3; 5)

D) (2; -3; -5)

16 / 40

a=1^0,(6), b=8^0,(3) , c=2^0,(9) bo'lsa, (a+b)^c=?

A) 16

B) 9

C) 0

D) 25

17 / 40

y = x²+1-|sinx| funksiya grafigi OX o'qidan pastda yotadimi?

A) Yotadi

B) Yotmaydi

18 / 40

Hisoblang. cos²10° + cos²30° + cos²80°

A) 3/7

B) 7/3

C) 0

D) 7/4

19 / 40

Tengsizlikni yeching.

A) [-7;3 u [-1;∞)

B) [-7;-3) u [-1;∞)

C) [-7;-3] u [-1;∞)

D) [-7;-5) u [-1;∞)

20 / 40

Hisoblang.

A) 1

B) 4

C) 2

D) 0

21 / 40

Noaniq integralni toping. ∫(sin²x+cos²x)dx

A) x+c

B) c

C) 4x+c

D) 2x+c

22 / 40

Hisoblang.

A) -1

B) 1

C) 2

D) 0

23 / 40

Tengsizlikni yeching.

A) x∈[0;1000]

B) x∈(10;1000)

C) x∈(1;1000]

D) x∈(0;1000)

24 / 40

Tenglama ildizlari yig'indisini toping.

A) 4

B) 0

C) 2

D) -1

25 / 40

5^-x≤ 0,04 x ning eng kichik butun qiymatini toping.

A) 0

B) 3

C) -1

D) 2

26 / 40

Tenglamani yeching:

A) 2,5

B) 2

C) 6

D) 5,5

27 / 40

1, 2, 3, 4 raqamlaridan foydalanib 400 dan kichik kechta uc xonali son yasash mumkin?

A) 51

B) 48

C) 49

D) 47

28 / 40

(tgx+ctgx)⁴ yoyilmaning ozod hadini toping.

A) 5

B) 4

C) 3

D) 6

29 / 40

Uchburchak tamonlari 10, 24 va 26 ga teng bo'lsa, katta burchagi necha gradus?

A) 90°

B) 80°

C) 60°

D) 75°

30 / 40

To'g'ri burchakli uchburchakning yuzi 96 ga, perimetri esa 48 ga teng bo'lsa, gipatenuza uzunligini toping.

A) 23

B) 20

C) 18

D) 21

31 / 40

|x²-2x|≤x yengsizlikni yeching.

A) {0}∪(1;3]

B) (-2;0)∪[1;3]

C) {0}∪[1;3)

D) {0}∪[1;3]

32 / 40

f(x)+(x-2)·g(x)=x²+5, f(3)=10 bo'lsa, g^-1=(4) ni toping. Bunda g^-1(x) g(x) ga teskari funksiya.

A) 4

B) 5

C) 6

D) 3

33 / 40

Hisoblang.

A) -1

B) 0

C) 2

D) 1

34 / 40

Ayirmasi d ga teng bo'lgan arifmetik progrssiya uchun ni toping.

A) 2

B) 1/2

C) 1

D) 2/3

35 / 40

Hisoblang.

A) 4

B) 6

C) 5

D) 3

36 / 40

f(x) = x²-3x-2 bo'lsa. f(a+b+c)-f(abc)=? Bunda a, b, c - kvadrat funksiya koeffitsiyentlari.

A) 42

B) 36

C) 38

D) 40

37 / 40

Hisoblang.

A) 3/2

B) 3/5

C) 5/3

D) 2/3

38 / 40

Chizmada nechta uchburchak tasvirlangan?

A) 52

B) 50

C) 54

D) 48

39 / 40

Hisoblang.

A) 2

B) 3

C) 1

D) 6

40 / 40

Tamonlarini ayirmasi 14 bo'lgan parallelogramning o'rmas burchagidan katta diagonaliga tushgan balandlik uni 12 va 30 ga teng kesmalarga ajratadi. Tamonlar uzunligini toping.

A) 30 va 24

B) 32 va 22

C) 34 va 20

D) 36 va 18

Baholash mezoni

- 75 foiz va undan yuqori ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, oliy malaka toifasi (bosh o’qituvchi lavozimi) saqlansin”;

- 75 foizdan past ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, birinchi malaka toifasi (yetakchi o’qituvchi lavozimi)ga tushirilsin”;

- 75 foiz va undan yuqori ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, oliy malaka toifasi (bosh o’qituvchi lavozimi) berilsin”;

- 74 foizdan 65 foizgacha ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, birinchi malaka toifasi (yetakchi o’qituvchi lavozimi) saqlansin”;

- 65 foizdan kam ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, ikkinchi malaka toifasi (katta o’qituvchi lavozimi)ga tushirilsin”

- 64 foizdan 60 foizgacha ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, ikkinchi malaka toifasi (katta o’qituvchi lavozimi) saqlansin”;

- 60 foizdan kam ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, mutaxassis (oliy yoki o’rta maxsus, kasb-hunar ma'lumotli o’qituvchi) lavozimiga tushirilsin”