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Matematika attestatsiya №12

InfoMaster

Aprel 8, 2022

115 Ko'rishlar 1 izoh

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OMAD YOR BO'LSIN!

Matematika fanidan attestatsiya savollari №12

28.03.2022 da Toshkentda tushgan savollar

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Testda 76% va undan yuqori natija oling va sertifikatni yuklab oling.

1 / 40

Agar aylananing o‘zaro parallel bo‘lgan uzunliklari 38, 38 va 34 ga teng vatarlari orasidagi masofalar bir xil bo‘lsa, shu masofani toping.

A) 5,5

B) 6,5

C) 7

D) 6

2 / 40

Agar g ( x) - uchinchi darajali keltirilgan f(x)=x³+ax²+bx+c ko‘phadning ildizlari, ko‘phad ildizlarining teskarisiga teng bo‘lsa, u holda g (1) ning qiymatini a, b, c lar
orqali ifodalang.

A) 1

B) 2

C) 4

D) 3

3 / 40

f(x) va g(x) funksiyalar f(x)+(x-2)·g(x)=x²+5 bog’lanishda va f(3)=10 bo’lsa, g^-1 (4) ning qiymatini toping.(g^-1 (x)-g(x) ga teskari funksiya)

A) 3

B) 4

C) 6

D) 2

4 / 40

Piramidaning asosi tomoni 4√3 va o‘tkir burchagi 45° ga teng bo’lgan rombdan iborat. Ushbu piramidaga ichki chizilgan konusning yasovchisi asos tekisligi bilan 60° li burchak tashkil etadi. Konusning hajmini toping.

A) 6√2π

B) 6√3π

C) 3π

D) 6π

5 / 40

Hisoblang.

A) 24+3b

B) 26-3b

C) 14-2b

D) 24-3b

6 / 40

Tenglamaning [0;π] kesmadagi ildizlari soni 3 tadan ko'pmi?

A) Ha

B) Yo'q

7 / 40

Hisoblang.

A) 1

B) 2

C) 0

D) -1

8 / 40

Hisoblang

A) 12

B) 6

C) 9

D) 36

9 / 40

Agar va ular orasidagi burchak 120° bo'lsa, ni toping.

A) 3√7

B) 4√5

C) √7

D) 2√7

10 / 40

Tenglama ildizlari yig'indisini toping.

A) 0

B) -1

C) 4

D) 2

11 / 40

Hisoblang.

A) -1

B) 0

C) 1

D) 2

12 / 40

y = x²+1-|sinx| funksiya grafigi OX o'qidan pastda yotadimi?

A) Yotmaydi

B) Yotadi

13 / 40

5^-x≤ 0,04 x ning eng kichik butun qiymatini toping.

A) 2

B) -1

C) 3

D) 0

14 / 40

Hisoblang.

A) 2/3

B) 5/3

C) 3/5

D) 3/2

15 / 40

Hisoblang.

A) 7/11

B) 9/13

C) 0

D) 9/11

16 / 40

Arimetik progerssiyada s₁₂=354, P=a₁+a₂+...+a₁₁, Q=a₂+a₄+...+a₁₂ va P/Q=32/27 ga teng bo'lsa, d ni toping.

A) -3

B) -4

C) -6

D) -5

17 / 40

Agar bo'lsa, ni toping.

A) 5,2

B) 3

C) 2,5

D) 0

18 / 40

f(x) = x²-3x-2 bo'lsa. f(a+b+c)-f(abc)=? Bunda a, b, c - kvadrat funksiya koeffitsiyentlari.

A) 38

B) 36

C) 42

D) 40

19 / 40

Chizmada nechta uchburchak tasvirlangan?

A) 48

B) 52

C) 50

D) 54

20 / 40

Hisoblang.

A) -47/24

B) 49/25

C) 51/29

D) -47/25

21 / 40

ABCD parallelogramm va S_KBCE= 18 bo'lsa, S_ABCD=?

A) 62

B) 48

C) 54

D) 56

22 / 40

Hisoblang.

A) 3

B) 1

C) 4

D) 2

23 / 40

Tengsizlikni yeching: 3 · 9^x–10 · 21^x+ 7 · 49 ^x ≤ 0

A) [-1;0]

B) [-1;0)

C) [-1;1]

D) (-1;3]

24 / 40

Tenglamani yeching.

A) 5

B) 0

C) 1

D) 2

25 / 40

Hisoblang. cos²10° + cos²30° + cos²80°

A) 0

B) 7/3

C) 3/7

D) 7/4

26 / 40

Ayirmasi d ga teng bo'lgan arifmetik progrssiya uchun ni toping.

A) 2/3

B) 1

C) 1/2

D) 2

27 / 40

a=1^0,(6), b=8^0,(3) , c=2^0,(9) bo'lsa, (a+b)^c=?

A) 0

B) 9

C) 16

D) 25

28 / 40

Tenglamani yeching:

A) 2

B) 5,5

C) 2,5

D) 6

29 / 40

|x²-2x|≤x yengsizlikni yeching.

A) {0}∪(1;3]

B) {0}∪[1;3)

C) {0}∪[1;3]

D) (-2;0)∪[1;3]

30 / 40

Hisoblang.

A) 6

B) 5

C) 3

D) 4

31 / 40

Hisoblang.

A) 2

B) 3

C) 6

D) 1

32 / 40

To'g'ri burchakli uchburchakning yuzi 96 ga, perimetri esa 48 ga teng bo'lsa, gipatenuza uzunligini toping.

A) 20

B) 18

C) 21

D) 23

33 / 40

(tgx+ctgx)⁴ yoyilmaning ozod hadini toping.

A) 3

B) 6

C) 5

D) 4

34 / 40

To'g'ri burchakli uchburchakka ichki va tashqi chizilgan aylanalar raduslari 6 va 15 ga teng bo'lsa, katetlar yig'indini toping.

A) 35

B) 48

C) 28

D) 42

35 / 40

Hisoblang.

A) -2 yoki -1

B) -2 yoki 0

C) -2 yoki 2

D) 0

36 / 40

To'g'ri burchakli uchburchakning gipotenuzasiga o'tkazilgan bissiktriksasi uni 20 va 30 ga teng kesmalarga ajratadi. To'g'ri burchakli uchburchak yuzini toping.

A) 7500/13

B) 7551/15

C) 15

D) 6700/13

37 / 40

y=xlnx funksiyani hosilasini toping.

A) 2lnx-1

B) lnx+1

C) lnx/2+1

D) 1

38 / 40

Noaniq integralni toping. ∫(sin²x+cos²x)dx

A) x+c

B) x/2+c

C) 2x+c

D) 4x+c

39 / 40

Hisoblang.

A) 94

B) 96

C) 98

D) 32

40 / 40

Agar bo'lsa f(x)=?

A) x²-2

B) x²-1

C) 2x²-1

D) x²+2

Baholash mezoni

- 75 foiz va undan yuqori ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, oliy malaka toifasi (bosh o’qituvchi lavozimi) saqlansin”;

- 75 foizdan past ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, birinchi malaka toifasi (yetakchi o’qituvchi lavozimi)ga tushirilsin”;

- 75 foiz va undan yuqori ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, oliy malaka toifasi (bosh o’qituvchi lavozimi) berilsin”;

- 74 foizdan 65 foizgacha ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, birinchi malaka toifasi (yetakchi o’qituvchi lavozimi) saqlansin”;

- 65 foizdan kam ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, ikkinchi malaka toifasi (katta o’qituvchi lavozimi)ga tushirilsin”

- 64 foizdan 60 foizgacha ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, ikkinchi malaka toifasi (katta o’qituvchi lavozimi) saqlansin”;

- 60 foizdan kam ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, mutaxassis (oliy yoki o’rta maxsus, kasb-hunar ma'lumotli o’qituvchi) lavozimiga tushirilsin”