Uy » Choraklik online testlar » Matematika choraklik » 7-sinf Matematika 2-chorak Matematika choraklik 7-sinf Matematika 2-chorak InfoMaster Aprel 7, 2021 180 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0 OMAD YOR BO'LSIN! Tomonidan yaratilgan InfoMaster 7-sinf Matematika 2-chorak Testni Mamadoliyev Diyorbek tayyorladi. 1 / 25 Ifodani soddalashtiring: A) 10a + 6b B) 2a C) 10a D) 6b 2 / 25 Birhadning son qiymatini toping:, bunda y = -15, x = 6. A) 18 B) 3 C) 1 D) 12 3 / 25 Hisoblang: A) a²b² B) a² C) a/b D) b² 4 / 25 Hisoblang: A) 625 B) 25 C) 5 D) 1 5 / 25 Algebraik ifodaning qiymatini toping: bunda a= 2 b=5 A) 0 B) 250 C) 1250 D) 50 6 / 25 Uchburchakning bir uchi va shu uchining qarshisidagi tomon o`rtasini tutashtiruvchi kesma nima deb ataladi A) mediana B) bissektrisa C) to`g`ri javob yo`q D) balandlik 7 / 25 Teng yonli uchburchakning asosi yon tomonidan 3 birlikka kam, perimetri 36 ga teng bo`lsa uchburchakning yon tomonini toping. A) 12 B) 10 C) 8 D) 13 8 / 25 To`g`ri chiziqning ixtiyoriy nuqtasidan unga nechta perpendikulyar to`g`ri chiziq o`tkazish mumkin ? A) istalgancha B) 1 C) 2 D) 3 9 / 25 Birhadning son qiymatini toping: bunda y=-15, x=6 A) 18 B) 12 C) -1 D) 3 10 / 25 n ning qanday qiymatida tenglik to`g`ri bo`ladi: A) 8 B) 1 C) 3 D) 2 11 / 25 Uchburchakning bir uchidan shu uchining qarshisidagi tomonga tushirilgan perpendikulyar nima deb ataladi A) to`g`ri javob yo`q B) bissektrisa C) mediana D) balandlik 12 / 25 Teng yonli uchburchakning perimetri 48 ga teng. Uning tomonlaridan biri 12 ga teng bo`lsa, qolgan tomonlarini toping A) 18; 24 B) 18; 18 C) 16; 16 D) 12; 12 13 / 25 Ikki to`g`ri chiziqning kesishishidan hosil bo`lgan burchaklardan ikkitasining yig`indisi 1200. Bu burchaklarni toping A) 60gradus , 60gradus B) 30gradus , 90gradus C) 15gradus , 105gradus D) 45gradus, 75gradus 14 / 25 a sonni shunday tanlangki, 3x - 4 = a - 2x tenglama x = 1 ildizga ega bo`lsin A) 0 B) 1 C) 5 D) -9 15 / 25 Tenglik shaklida yozing: a va b sonlari yig`indisining ikkilangani ularning ko`paytmasiga teng. A) 2∙(a+b) = 2a • b B) a + b • 2 = a • b C) a + b = 2 • a • b D) 2∙(a+b) = a • b 16 / 25 (x -1) : (x+1) = 3 : 5 tenglamaning ildizi bo`lsa, 41 - ifodaning son qiymatini toping. A) 26 B) 23 C) 4 D) 37 17 / 25 O`xshash hadlarni ixchamlang: 3,4 a - b - 1- 1,4a + 3b. A) 2a -4b -1 B) 4,8a + 2b - 1 C) 2a +2b -1 D) 4,8 a +4b -1 18 / 25 Tenglamani yeching: (3x - 4) - (6 - 2x) = 3. A) 13 B) 1,2 C) 2,6 D) 3,8 19 / 25 Tenglamani yeching: A) -3/5 B) 21 C) 3/5 D) -4,2 20 / 25 75 gradusli burchakka qo`shni burchakni toping. A) 105 gradus B) 15 gradus C) 115 gradus D) 45 gradus 21 / 25 Algebraik ifodaning qiymatini toping: 3a + 2b, bunda a = 3, b = -5. A) 19 B) -1 C) 0 D) 4 22 / 25 Futbol musobaqasida har biri 1500 so`mdan 6000 ta chipta va har biri 2000 so`mdan 4000 ta chipta sotildi. Hamma chiptalar uchun qancha pul olingan ? A) 17000000 so`m B) 8900000 so`m C) 14560000 D) 9800000 23 / 25 Teng yonli uchburchakning asosining uzunligi a ga teng bo`lib, u yon tomonlaridan 5 ga ortiq. Shu uchburchakning perimetrini hisoblash uchun ifoda tuzing. A) 3a +5 B) 3a C) 3a + 10 D) 3a -10 24 / 25 Ikki to`g`ri chiziqning kesishishidan hosil bo`lgan burchaklardan uchtasining yig`indisi 250 gradus ga teng. Burchaklardan kichigini toping. A) 70° B) 35° C) 50° D) 40° 25 / 25 Bo`yi enidan 3 marta katta bo`lgan to`g`ri to`rtburchakning perimetri 120 sm ga teng. Shu to`g`ri to`rtburchakning bo`yini toping. A) 90 sm B) 45 sm C) 15 sm D) 60 sm 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
