Uy » Choraklik online testlar » Fizika choraklik » 7-sinf Fizika 4-chorak Fizika choraklik 7-sinf Fizika 4-chorak InfoMaster Aprel 26, 2021 1018 Ko'rishlar 0 SaqlashSaqlanganOlib tashlandi 1 0 Tomonidan yaratilgan InfoMaster 7-sinf Fizika 4-chorak Testni Vafaqulov Alisher tayyorladi. 1 / 25 Jismning vaqt birligi ichida to’liq aylanishlari soni aylanishi ….. deb ataladi A) tezligi B) chastotasi C) tezlanishi D) davri 2 / 25 Aylanma tekis harakatda chiziqli tezlik bilan burchak tezlik orasidagi munosabat formulasini ko’rsating A) V=wR B) w=2¶V C) w=2¶/T D) w=4/t 3 / 25 Soatning minut mili burchakli tezligini toping A) π/30 B) π/10 C) π/1800 D) π/2600 4 / 25 Velosiped raridusi 25 m bo’lgan aylanma yo’lda 10 m/s tezlik bilan tekis harakatlanmoqda. Uning markazga intilma tezlanishini toping. (m/s²) A) 2 B) 3 C) 5 D) 4 5 / 25 Velosiped g’ildiragining o’qidan eng uzoq nuqtasi 0,02 s davomida 20 km yo’lni bosib o’tdi. Velosipedning tezligini toping A) 4 km/soat B) 0,36 km/soat C) 3,6 km/soat D) 36 km/soat 6 / 25 Soatning minut mili aylanishining chastotasini toping.(Hz) A) 100 B) 1/100 C) 1/7200 D) 1/3600 7 / 25 Aylanma tekis harakatda aylanish davri va chastotasi bog’lanishi formulasini ko’rsating A) t=T*N B) T=1/v C) T=t/N D) T=2¶R/V 8 / 25 0,1 s davomida g’ildirak 1 chapga buriladi. Uning o’qidan 5sm uzoqlikdagi nuqtasining chiziqli tezligini toping A) 10m/s B) 5 m/s C) 50m/s D) 0,5 m/s 9 / 25 Raketa quyosh sistemasini tark etishi uchun u yerdan 16,7 km/s tezlik bilan uchirilishi kerak. Bu tezlikni nomi A) 3-kosmik tezlik B) 2-kosmik tezlik C) 1-kosmik tezlik D) notekis tezlik 10 / 25 Oyning yer atrofida harakatlanish tezligini toping. Yer massasi 6*10 24 kg, yer bilan oy orasidagi masofa 400 000 km gravitatsion doimiylik Nm2/kg2 A) 1 km/s B) 9,8 km/s C) 11,2 km/s D) 7,9 km/s 11 / 25 Yer uchun ikkinchi kosmik tezlik qiymatini ko’rsating A) 7,9 m/s B) 11,2 km/s C) 16,7 km/s D) 7,9 km/s 12 / 25 Odam liftda turibdi. Odamga ta’sir qiluvchi kuchlar: mg – og’irlik kuchi, N – tayanch reaksiya kuchi, Lift pastda to’xtashdan oldin sekinlashganda kuchlar orasidagi munosabatni ko’rsating. Lift pastda to’xtashdan oldin sekinlashyapti 1) mg > N 2) mg < N 3) mg = N 4) mg = 0; N = 0 A) 2 B) 3 C) 1 D) 4 13 / 25 1000 mN necha N? A) 400 B) 10 C) 1 D) 70 14 / 25 O’zaro ta’sirlashuvchi jismlarning bir-biriga ta’sir kuchlari bir to’g’ri chiziq bo’yicha yo’nalgan, moduli bo’yicha teng va yo’nalish bo’yicha qarama-qarshidir. Bu ....... A) Nyutonning 3 qonuni B) Nyutonning 2 qonuni C) Nyutonning 1 qonuni D) Nyutonning butun olam tortishish kuchi qonuni 15 / 25 Odam liftda turibdi. Odamga ta’sir qiluvchi kuchlar: mg – og’irlik kuchi, N – tayanch reaksiya kuchi, Lift tinch turganda kuchlar orasidagi munosabatni ko’rsating 1) mg > N 2) mg < N 3) mg = N 4) mg = 0; N = 0 A) 1 B) 3 C) 4 D) 2 16 / 25 Nyutonning 3 qonuni formulasi qaysi ifodada to’g’ri ko’rsatilgan? A) F1 =- F2 B) F = - k x C) F = mv²/ R D) F = mg 17 / 25 Gorizontal tekislikda yotgan 6 kg massali jism qanday kuch ta’sirida 1s da 2 m/s tezlikka erishadi? Jismga ta’sir etayotgan ishqalanish kuchi 4 N ga teng deb xisoblang A) 8 B) 4 C) 16 D) 12 18 / 25 Samolyot qo’nish paytida g’ildiraklari yerga tekkandagi tezligi 360 km/soat. Agar uning tezlanishi 2m/s2 bo’lsa, u qancha vaqtdan keyin to’xtaydi A) 50 s B) 5 s C) 100 s D) 25 s 19 / 25 Erkin tushayotgan jism ikkinchi sekundda qanday masofani (m) o’tadi? A) 15 B) 5 C) 25 D) 35 20 / 25 Jism yerdan 35 m/s tezlik bilan tik yuqoriga otildi. U yerga necha sekunddan so’ng tushadi? A) 5 B) 7 C) 9 D) 3 21 / 25 25 m/s tezlik bilan yuqoriga tik otilgan jismning 2 s dan keyingi tezligi qancha bo’ladi? A) 15 m/s B) 20 m/s C) 10 m/s D) 5 m/s 22 / 25 Tekis sekinlanuvchan harakatda tezlik va tezlanish ishoralarining munosabatini ko’rsating. 1) υ0 > 0, a<0 2) υ0 = 0, a<0 3) υ0 < 0, a>0 4) υ >0, a>0 A) 3,4 B) 4 C) 2,3 D) 1,3 23 / 25 Joyidan qo’zg’algan jism 0,3 m/s2 tezlanish bilan harakat qilib, qancha vaqtda 9 m/s tezlikka erishadi? A) 30 s B) 25 s C) 20 s D) 15 s 24 / 25 Jism tezlik proporsiyasining vaqtga bog’lanish v = 3+2t (m/s) ko’rinishga ega. Ko’chish proyeksiyasining vaqtga bog’lanishi qanday? A) S = 2t + 3 ² B) S = 3t + 1 t² C) S = 3t + 2 t² D) S = 2t² 25 / 25 Jism harakat tenglamasi x=5+3t–t2 formula bilan berilgan. Jismning boshlang’ich koordinatasi nimaga teng? A) 9 m B) 1 m C) 5 m D) 3 m 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz