Uy » Choraklik online testlar » Fizika choraklik » 7-sinf Fizika 4-chorak Fizika choraklik 7-sinf Fizika 4-chorak InfoMaster Aprel 26, 2021 1009 Ko'rishlar 0 SaqlashSaqlanganOlib tashlandi 1 0 Tomonidan yaratilgan InfoMaster 7-sinf Fizika 4-chorak Testni Vafaqulov Alisher tayyorladi. 1 / 25 Nyutonning 3 qonuni formulasi qaysi ifodada to’g’ri ko’rsatilgan? A) F = mv²/ R B) F = mg C) F1 =- F2 D) F = - k x 2 / 25 Avtomobil 5 m/s2 tezlanish bilan tinch holatdan harakat boshladi. U 4s da necha metr yo’l o’tadi? A) 40 B) 20 C) 30 D) 10 3 / 25 Jismning harakat tenglamasi x = 2 – 3 t + 2 t2 formula bilan berilgan. Bu harakat uchun tezlik tenglamasini yozing A) υ= - 3 + 4 t B) υ = 4 t C) υ= 4 + 3 t D) υ= 4 - 3 t 4 / 25 Balkondan boshlang’ich tezliksiz tushib ketgan jism 1 s da yerga etib kelgan bo’lsa, u qanday balandlikdan (m) tushgan? A) 5 B) 20 C) 10 D) 15 5 / 25 Tezlanish formulasi qanday ifodalanadi A) p = F / S B) S = at² / 2 C) a = (v - v˳)/t D) p = m / v 6 / 25 Jism tekis tezlanuvchan harakat boshlab, 3-sekundda 5 m yo’l o’tdi. U harakatning boshlang’ich 3 sekundida qanday yo’l o’tadi (m) ? A) 7 B) 9 C) 13 D) 11 7 / 25 25 m/s tezlik bilan yuqoriga tik otilgan jismning 2 s dan keyingi tezligi qancha bo’ladi? A) 5 m/s B) 10 m/s C) 20 m/s D) 15 m/s 8 / 25 Erkin tushish deb qaysi harakatga aytiladi A) jismning havosiz joyda faqat yerning tortish ta’sridagi harakatiga B) qo’ldan qo’yib yuborgan jism harakatiga C) xar qanday harakatga D) jismga hech qanday kuch ta’sir qilmagandagi harakatiga 9 / 25 Erkin tushib harakat qilayotgan jismning tezligi har sekundda qanchaga o’zgaradi A) o’zgarmaydi B) 10 m/s C) 15 m/s D) 5 m/s 10 / 25 Joyidan qo’zg’algan jism 0,2 m/s2 tezlanish bilan harakatlanganda 1 minutda u qanday tezlikka erishadi A) 12 m/s B) 1,2 m/s C) 120 m/s D) 0,12 m/s 11 / 25 Erkin tushish tezlanishi jismning yer sirtidan balandligiga bog’likligi qaysi formulada ko’rsatilgan A) g/m² B) m/s² C) g=GM/(R+h)² D) f/m 12 / 25 Ikki jism bir biriga F kuchi bilan tortilmoqda. Agar birining massasi n marta kamaytirilsa ular qanday kuch bilan tortiladi A) F/n B) F(n+1) C) F*n D) F(n-1) 13 / 25 Oyning yer atrofida aylanish tezligi nimaga teng A) 1 km/s B) 40 km/s C) 10 km/s D) 30 km/s 14 / 25 Lift a A) P=m(a-g) B) (P=mg) C) P=m(g-a) D) P=m(g+a) 15 / 25 Zambarakdan gorizantga burchak ostida uchib chiqqan snaryad 12 sekund uchgan. Snaryad ko’tarilgan eng yuqori balandlik qancha A) 20m B) 10m C) 360m D) 180m 16 / 25 Oyda erkin tushish tezlanishi nimaga teng? (m/s2) A) 9,8 B) 1,6 C) 7,9 D) 1 17 / 25 Yerga tortilishi tufayli jismning tayanchga yoki osmaga tasr etadigan kuchi .......... deb ataladi A) bosim kuchi B) jism og’irligi C) og’irlik kuchi D) reaksiya kuchi 18 / 25 Yerning quyosh atrofida aylanish tezligi nimaga teng A) 1 km/s B) 30 km/s C) 40 km/s D) 10 km/s 19 / 25 Burchakli ko’chishning vaqtga nisbati qanday fizik kattalik? A) tezlanish B) burchakli tezlik C) davr D) chastota 20 / 25 Soatning vaqt mili burchakli tezligini toping. (rad/s) A) π/2600 B) π/10 C) π/30 D) π/1800 21 / 25 Agar moddiy nuqta aylana bo’ylab teng vaqtlar orasida teng yollarni bosib o’tsa, bunday harakat ....... harakat deyiladi A) aylanma o’zgaruvchan B) tekis C) notekis D) tekis aylanma tezlik 22 / 25 Aylanma tekis harakatda aylanish davri va chastotasi bog’lanishi formulasini ko’rsating A) T=1/v B) t=T*N C) T=2¶R/V D) T=t/N 23 / 25 Aylanma tekis harakatga chiziqli tezlik va burchakli tezlik bog’lanish formulasini ko’rsating A) υ=2pR/T B) υ=ωR C) ω=2p υ D) ω=2p/T 24 / 25 Aylanish davri bilan chiziqli tezligi orasidagi munosabat formulasini toping. A) V=wR B) V=S/t C) V=2¶R/T D) V=at 25 / 25 Velosiped g’ildiragining o’qidan eng uzoq nuqtasi 0,02 s davomida 20 km yo’lni bosib o’tdi. Velosipedning tezligini toping A) 36 km/soat B) 3,6 km/soat C) 0,36 km/soat D) 4 km/soat 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz