Uy » Choraklik online testlar » Fizika choraklik » 7-sinf Fizika 4-chorak Fizika choraklik 7-sinf Fizika 4-chorak InfoMaster Aprel 26, 2021 1046 Ko'rishlar 0 SaqlashSaqlanganOlib tashlandi 1 0 Tomonidan yaratilgan InfoMaster 7-sinf Fizika 4-chorak Testni Vafaqulov Alisher tayyorladi. 1 / 25 Massasi 60 kg bo’lgan jism tik yuqoriga 1 m /s2 tezlanish bilan ko’tarilayotgan bo’lsa, uning og’irligi qanday bo’ladi? A) 600 N B) 540 N C) 660 N D) 480 N 2 / 25 Odam liftda turibdi. Odamga ta’sir qiluvchi kuchlar: mg – og’irlik kuchi, N – tayanch reaksiya kuchi, Lift yuqoriga xarakatlana boshlaganda kuchlar orasidagi munosabatni ko’rsating. 1) mg > N 2) mg < N 3) mg = N 4) mg = 0; N = 0 A) 1 B) 3 C) 4 D) 2 3 / 25 60 N kuch jismga 0,8 m/s2 tezlanish beradi. Qanday kuch bu jismga 2 m/s2 tezlanish beradi? A) 24 N B) 240 N C) 15 N D) 150 N 4 / 25 Odam liftda turibdi. Odamga ta’sir qiluvchi kuchlar: mg – og’irlik kuchi, N – tayanch reaksiya kuchi, Lift tinch turganda kuchlar orasidagi munosabatni ko’rsating 1) mg > N 2) mg < N 3) mg = N 4) mg = 0; N = 0 A) 1 B) 3 C) 2 D) 4 5 / 25 Qaysi shart bajarilganda, jism suyuqlikda tekis cho’ka boshlaydi? (mg-og’irlik kuchi, Fa- Arximed kuchi, F-qarshilik kuchi) 1) m g > F = F a 2) m g = F 3) m g = F = F a 4) mg < F = F a A) 4 B) 2 C) 1 D) 3 6 / 25 Xalqaro birliklar sistemasida kuch birligi A) kg*m²/s² B) kg / s² C) kg*m / s² D) m / s² 7 / 25 Odam liftda turibdi. Odamga ta’sir qiluvchi kuchlar: mg – og’irlik kuchi, N – tayanch reaksiya kuchi, Lift pastda to’xtashdan oldin sekinlashganda kuchlar orasidagi munosabatni ko’rsating. Lift pastda to’xtashdan oldin sekinlashyapti 1) mg > N 2) mg < N 3) mg = N 4) mg = 0; N = 0 A) 4 B) 1 C) 2 D) 3 8 / 25 Motosikl botiq ko’prik ustida tekis harakatlanmoqda. Ko’prikning eng quyi nuqtasiga yetganida unga qo’yilgan kuchlarning teng ta’sir etuvchisi qanday yo’nalgan bo’ladi? A) Pastga B) Yuqoriga C) Orqaga D) Oldinga 9 / 25 Zambarakdan gorizantga burchak ostida uchib chiqqan snaryad 12 sekund uchgan. Snaryad ko’tarilgan eng yuqori balandlik qancha A) 10m B) 20m C) 180m D) 360m 10 / 25 Yer uchun ikkinchi kosmik tezlik qiymatini ko’rsating A) 7,9 km/s B) 16,7 km/s C) 11,2 km/s D) 7,9 m/s 11 / 25 Yer uchun uchunchi kosmik tezlik qiymatini ko’rsating A) 11,2 km/s B) 7,9 km/s C) 7,9 m/s D) 16,7 km/s 12 / 25 Oyning yer atrofida aylanish tezligi nimaga teng A) 40 km/s B) 30 km/s C) 10 km/s D) 1 km/s 13 / 25 Aylanma tekis harakatda tezlanish qanday yo’nalgan? A) urinma bo’ylab B) radius bo’ylab markazga C) radius bo’ylab markazdan D) xar xil yo’nalgan bo’lishi mumkin 14 / 25 Soatning vaqt mili burchakli tezligini toping. (rad/s) A) π/10 B) π/30 C) π/2600 D) π/1800 15 / 25 Soatning sekund mili burchakli tezligini toping. (rad/s) A) π/1800 B) π/10 C) π/30 D) π/2600 16 / 25 Soatning 30 mm uzunlikdagi minut uchi 10 minutda 31,4 mm uzunlikdagi yo’lni bosib o’tdi. Minut mili uchining burilish burchagini toping. (rad) A) 5 rad B) 3 rad C) 1,05 rad D) 4 rad 17 / 25 Avtomabil 200 m radiusli aylana yo’lda 72 km/soat tezlik bilan harakatlanadi. Uning markaziga intilma tezlanishi qancha m/s2 ga teng? A) 4 B) 2 C) 5 D) 3 18 / 25 Aylanma tekis harakatda aylanish davri va chastotasi bog’lanishi formulasini ko’rsating A) T=1/v B) T=t/N C) t=T*N D) T=2¶R/V 19 / 25 Soatning 30 mm uzunlikdagi minut mili uchi 10 minutda 31,4 mm uzunlikdagi yo’lni bosib o’tdi. Minut mili uchining chiziqli tezligini toping A) 0,00005 m/s B) 0,5 m/s C) 0,0005 m/s D) 0,005 m/s 20 / 25 Tekis sekinlanuvchan harakatda tezlik va tezlanish ishoralarining munosabatini ko’rsating. 1) υ0 > 0, a<0 2) υ0 = 0, a<0 3) υ0 < 0, a>0 4) υ >0, a>0 A) 1,3 B) 3,4 C) 4 D) 2,3 21 / 25 m/s2 tezlanish bilan to’g’ri chiziq bo’ylab harakatlanayotgan jismning holatidan boshlab birinchi sekunda qanday masofani (m) o’tadi? A) 8 B) 6 C) 4 D) 7 22 / 25 Yuqoriga tik otilgan jism H balandlikkacha ko’tarildi. U 4H balandlikkacha ko’tarilishi uchun otish tezligini qanday o’zgartirishi kerak? A) 2marta orttirish B) 1marta orttirish C) 5marta kamaytirish D) 4marta orttirish 23 / 25 Tezlanishning o’lchov birligini ko’rsating A) m²/s B) m/s² C) m/s D) s/ m² 24 / 25 Balkondan boshlang’ich tezliksiz tushib ketgan jism 1 s da yerga etib kelgan bo’lsa, u qanday balandlikdan (m) tushgan? A) 10 B) 5 C) 20 D) 15 25 / 25 Jism tezlik proporsiyasining vaqtga bog’lanish v = 3+2t (m/s) ko’rinishga ega. Ko’chish proyeksiyasining vaqtga bog’lanishi qanday? A) S = 3t + 1 t² B) S = 2t + 3 ² C) S = 2t² D) S = 3t + 2 t² 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz