Uy » Choraklik online testlar » Fizika choraklik » 7-sinf Fizika 4-chorak Fizika choraklik 7-sinf Fizika 4-chorak InfoMaster Aprel 26, 2021 1114 Ko'rishlar 0 SaqlashSaqlanganOlib tashlandi 1 2 Tomonidan yaratilgan InfoMaster 7-sinf Fizika 4-chorak Testni Vafaqulov Alisher tayyorladi. 1 / 25 Agar jism biror balandlikdan ikki baravar katta tezlik bilan gorizantal otilsa, uning uchish vaqti qanday o’zgaradi A) 4 martta ortadi B) o’zgarmaydi C) 2 marta kamayadi D) 2 marta ortadi 2 / 25 Ikki jism bir biriga F kuchi bilan tortilmoqda. Agar birining massasi n marta kamaytirilsa ular qanday kuch bilan tortiladi A) F(n-1) B) F/n C) F(n+1) D) F*n 3 / 25 Jismning yerga tortilish kuchi …… deb ataladi A) og’irlik kuchi B) reaksiya kuchi C) bosim kuchi D) jism og’irligi 4 / 25 Raketa quyosh sistemasini tark etishi uchun u yerdan 16,7 km/s tezlik bilan uchirilishi kerak. Bu tezlikni nomi A) 3-kosmik tezlik B) notekis tezlik C) 1-kosmik tezlik D) 2-kosmik tezlik 5 / 25 Oyning yer atrofida aylanish tezligi nimaga teng A) 1 km/s B) 10 km/s C) 30 km/s D) 40 km/s 6 / 25 Faqat butun olam tortishish kuchlari ta’sirida erkin harakat qilayotgan xar qanday jism ......... xolatida bo’ladi A) turg’unmas muvozanat B) vaznsizlik C) o’ta yuklanish D) turg’un muvozanat 7 / 25 Aylanma tekis harakatdagi chiziqli tezlik formulasini ko’rsating. 1) V=2¶R/T, 2) V=wR, 3)V=2¶RV A) 2 B) 1 C) 3 D) 1,2,3 8 / 25 Avtomabil 200 m radiusli aylana yo’lda 72 km/soat tezlik bilan harakatlanadi. Uning markaziga intilma tezlanishi qancha m/s2 ga teng? A) 4 B) 3 C) 2 D) 5 9 / 25 Jismning vaqt birligi ichida to’liq aylanishlari soni aylanishi ….. deb ataladi A) chastotasi B) tezlanishi C) tezligi D) davri 10 / 25 Aylanma tekis harakatda aylanish davri va chastotasi bog’lanishi formulasini ko’rsating A) T=1/v B) t=T*N C) T=2¶R/V D) T=t/N 11 / 25 Soatning sekund mili burchakli tezligini toping. (rad/s) A) π/2600 B) π/1800 C) π/10 D) π/30 12 / 25 60 N kuch jismga 0,8 m/s2 tezlanish beradi. Qanday kuch bu jismga 2 m/s2 tezlanish beradi? A) 240 N B) 24 N C) 150 N D) 15 N 13 / 25 O’zaro ta’sirlashuvchi jismlarning bir-biriga ta’sir kuchlari bir to’g’ri chiziq bo’yicha yo’nalgan, moduli bo’yicha teng va yo’nalish bo’yicha qarama-qarshidir. Bu ....... A) Nyutonning 2 qonuni B) Nyutonning 3 qonuni C) Nyutonning 1 qonuni D) Nyutonning butun olam tortishish kuchi qonuni 14 / 25 Odam liftda turibdi. Odamga ta’sir qiluvchi kuchlar: mg – og’irlik kuchi, N – tayanch reaksiya kuchi, Lift yuqorida to’xtashdan oldin sekinlashganda kuchlar orasidagi munosabatni ko’rsating. Lift yuqorida to’xtashdan oldin sekinlashyapti 1) mg > N 2) mg < N 3) mg = N 4) mg = 0; N = 0 A) 1 B) 4 C) 2 D) 3 15 / 25 Nyutonning 2-qonuni formulasini ko’rsating A) a = v/t B) a = v² /R C) a = 2s/ t² D) a = F / m 16 / 25 Odam liftda turibdi. Odamga ta’sir qiluvchi kuchlar: mg – og’irlik kuchi, N – tayanch reaksiya kuchi, Lift tinch turganda kuchlar orasidagi munosabatni ko’rsating 1) mg > N 2) mg < N 3) mg = N 4) mg = 0; N = 0 A) 1 B) 2 C) 3 D) 4 17 / 25 Tennischi 100 kg massali koptokni 250 N kuch bilan urganda koptok 50 m/s tezlik oldi. Zarb necha sekund davom etgan? A) 100 B) 50 C) 10 D) 20 18 / 25 Massasi 4 kg bo’lgan jism biror kuch ta’siri ostida 2 m/s2 tezlanish oldi. Shunday kuch ta’siri ostida massasi 10 kg bo’lgan jism qanday tezlanish oladi? A) 0,8 m/s² B) 2 m/s² C) 0 D) 1 m/s² 19 / 25 Massasi 0,5 kg bo’lgan koptokka 0,02 s davomida zarb berilgandan keyin u 10 m / s tezlik oladi. Zarbning o’rtacha kuchini toping A) 1000 N B) 500 N C) 200 N D) 250 N 20 / 25 Tekis tezlanuvchan harakatda tezlik va tezlanish ishoralarning munosabatini ko’rsating. 1) υ0 > 0, a>0 2) υ0 > 0, a<0 3) υ0 < 0, a<0 4) υ0<0, a>0 A) 2,4 B) 1,3 C) 3,4 D) 1,2 21 / 25 Jismning harakat tenglamasi x = 2 – 3 t + 2 t2 formula bilan berilgan. Bu harakat uchun tezlik tenglamasini yozing A) υ = 4 t B) υ= 4 + 3 t C) υ= - 3 + 4 t D) υ= 4 - 3 t 22 / 25 Erkin tushayotgan jism ikkinchi sekundda qanday masofani (m) o’tadi? A) 25 B) 5 C) 35 D) 15 23 / 25 Jism 20 m/s tezlik bilan tik yuqoriga otildi. Jism necha sekund eng baland nuqtasigacha ko’tariladi? g = 10 m/s2 A) 4 c B) 3 c C) 2 c D) 1 c 24 / 25 Tezlanish formulasi qanday ifodalanadi A) p = m / v B) a = (v - v˳)/t C) S = at² / 2 D) p = F / S 25 / 25 Boshlang’ich tezliksiz erkin tushayotgan jism 3-sekund ichida qanday masofani o’tadi? g = 10 m/s2 A) 5 m/s B) 25 m/s C) 15 m/s D) 10 m/s 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz