Uy » Choraklik online testlar » Fizika choraklik » 7-sinf Fizika 4-chorak Fizika choraklik 7-sinf Fizika 4-chorak InfoMaster Aprel 26, 2021 1018 Ko'rishlar 0 SaqlashSaqlanganOlib tashlandi 1 0 Tomonidan yaratilgan InfoMaster 7-sinf Fizika 4-chorak Testni Vafaqulov Alisher tayyorladi. 1 / 25 1000 mN necha N? A) 10 B) 1 C) 70 D) 400 2 / 25 Agar reaktiv samolyot dvigatelining tortish kuchi 90 k N bo’lsa, massasi 60 t bo’lgan samolyot tezlik olish vaqtida qanday tezlanish bilan harakatlanadi? A) 1 m/s² B) 2 m/s² C) 0,5 m/s² D) 0 3 / 25 Odam liftda turibdi. Odamga ta’sir qiluvchi kuchlar: mg – og’irlik kuchi, N – tayanch reaksiya kuchi, Lift yuqorida to’xtashdan oldin sekinlashganda kuchlar orasidagi munosabatni ko’rsating. Lift yuqorida to’xtashdan oldin sekinlashyapti 1) mg > N 2) mg < N 3) mg = N 4) mg = 0; N = 0 A) 1 B) 4 C) 3 D) 2 4 / 25 Gorizontal tekislikda yotgan 6 kg massali jism qanday kuch ta’sirida 1s da 2 m/s tezlikka erishadi? Jismga ta’sir etayotgan ishqalanish kuchi 4 N ga teng deb xisoblang A) 4 B) 12 C) 8 D) 16 5 / 25 Raketa quyosh sistemasini tark etishi uchun u yerdan 16,7 km/s tezlik bilan uchirilishi kerak. Bu tezlikni nomi A) 2-kosmik tezlik B) 3-kosmik tezlik C) 1-kosmik tezlik D) notekis tezlik 6 / 25 Jismning yerga tortilish kuchi …… deb ataladi A) jism og’irligi B) og’irlik kuchi C) reaksiya kuchi D) bosim kuchi 7 / 25 Oyda erkin tushish tezlanishi nimaga teng? (m/s2) A) 9,8 B) 7,9 C) 1 D) 1,6 8 / 25 Yerga tortilishi tufayli jismning tayanchga yoki osmaga tasr etadigan kuchi .......... deb ataladi A) jism og’irligi B) og’irlik kuchi C) reaksiya kuchi D) bosim kuchi 9 / 25 Liftdagi odam o’ta yuklanishga duch kelishi mumkinmi? A) Xa lift tezlanish bilan pastga tushganda B) Xa lift yuqoriga ko’tarilganda C) Yo’q D) Xa agar lift tezlanish bilan yuqoriga ko’tarilsa 10 / 25 Oyning yer atrofida harakatlanish tezligini toping. Yer massasi 6*10 24 kg, yer bilan oy orasidagi masofa 400 000 km gravitatsion doimiylik Nm2/kg2 A) 9,8 km/s B) 7,9 km/s C) 11,2 km/s D) 1 km/s 11 / 25 Boshlang’ich tezliksiz erkin tushayotgan jism birinchi sekunda qanday masofani o’tadi?g = 10 m/s2 A) 5 m B) 5,5 m C) 0,5 m D) 50 m 12 / 25 Jism yerdan 35 m/s tezlik bilan tik yuqoriga otildi. U yerga necha sekunddan so’ng tushadi? A) 7 B) 3 C) 9 D) 5 13 / 25 Jism tekis tezlanuvchan harakat boshlab, 3-sekundda 5 m yo’l o’tdi. U harakatning boshlang’ich 3 sekundida qanday yo’l o’tadi (m) ? A) 7 B) 9 C) 11 D) 13 14 / 25 Tekis tezlanuvchan harakatda tezlik va tezlanish ishoralarning munosabatini ko’rsating. 1) υ0 > 0, a>0 2) υ0 > 0, a<0 3) υ0 < 0, a<0 4) υ0<0, a>0 A) 2,4 B) 1,2 C) 3,4 D) 1,3 15 / 25 Joyidan qo’zg’algan jism 0,2 m/s2 tezlanish bilan harakatlanganda 1 minutda u qanday tezlikka erishadi A) 0,12 m/s B) 120 m/s C) 12 m/s D) 1,2 m/s 16 / 25 Soatning minut mili aylanishining chastotasini toping.(Hz) A) 1/7200 B) 1/3600 C) 100 D) 1/100 17 / 25 Velosiped raridusi 25 m bo’lgan aylanma yo’lda 10 m/s tezlik bilan tekis harakatlanmoqda. Uning markazga intilma tezlanishini toping. (m/s²) A) 3 B) 5 C) 4 D) 2 18 / 25 Soatning vaqt mili burchakli tezligini toping. (rad/s) A) π/2600 B) π/1800 C) π/10 D) π/30 19 / 25 Soatning 30 mm uzunlikdagi minut mili uchi 10 minutda 31,4 mm uzunlikdagi yo’lni bosib o’tdi. Minut mili uchining chiziqli tezligini toping A) 0,5 m/s B) 0,00005 m/s C) 0,0005 m/s D) 0,005 m/s 20 / 25 Uzunligi 25 sm bo’lgan ipga bog’langan sharcha 5 m/s chiziqli tezlik bilan aylanmoqda. Sharning markaziga intilma tezlanishini toping. (m/s2) A) 2 B) 1 C) 10 D) 100 21 / 25 Aylanma tekis harakatdagi chiziqli tezlik formulasini ko’rsating. 1) V=2¶R/T, 2) V=wR, 3)V=2¶RV A) 1,2,3 B) 3 C) 2 D) 1 22 / 25 Jismning vaqt birligi ichida to’liq aylanishlari soni aylanishi ….. deb ataladi A) tezlanishi B) chastotasi C) tezligi D) davri 23 / 25 Avtomabil 200 m radiusli aylana yo’lda 72 km/soat tezlik bilan harakatlanadi. Uning markaziga intilma tezlanishi qancha m/s2 ga teng? A) 5 B) 2 C) 4 D) 3 24 / 25 Aylanma tekis harakatda chiziqli tezlik bilan burchak tezlik orasidagi munosabat formulasini ko’rsating A) w=2¶/T B) V=wR C) w=4/t D) w=2¶V 25 / 25 Markazga intilma tezlanish formulasi qaysi ifodada to'g'ri ko’rsatilgan? A) a=v²/R B) a=(v-v˳)/t C) a=v/t D) a=F/m 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz