Uy » Choraklik online testlar » Fizika choraklik » 7-sinf Fizika 4-chorak Fizika choraklik 7-sinf Fizika 4-chorak InfoMaster Aprel 26, 2021 1011 Ko'rishlar 0 SaqlashSaqlanganOlib tashlandi 1 1 Tomonidan yaratilgan InfoMaster 7-sinf Fizika 4-chorak Testni Vafaqulov Alisher tayyorladi. 1 / 25 Yerga tortilishi tufayli jismning tayanchga yoki osmaga tasr etadigan kuchi .......... deb ataladi A) jism og’irligi B) reaksiya kuchi C) og’irlik kuchi D) bosim kuchi 2 / 25 Agar jism biror balandlikdan ikki baravar katta tezlik bilan gorizantal otilsa, uning uchish vaqti qanday o’zgaradi A) 4 martta ortadi B) o’zgarmaydi C) 2 marta kamayadi D) 2 marta ortadi 3 / 25 Yer sirtidagi jism yerga F kuch bilan tortilmoqda. Yer sirtidan h=2R balandlikka ko’tarilsa yerga qanday kuch bilan tortiladi? R-Ep radus A) F/16 B) F/2 C) F/4 D) F/9 4 / 25 Lift a A) P=m(g-a) B) (P=mg) C) P=m(g+a) D) P=m(a-g) 5 / 25 Ko’tarilish balandligi 4 marta ortishi uchun yuqoriga otilgan jismning boshlang’ich tezligini necha marta oshirish lozim A) 45 martta B) 60 martta C) 55 martta D) 50 martta 6 / 25 Zambarakdan gorizantga burchak ostida uchib chiqqan snaryad 12 sekund uchgan. Snaryad ko’tarilgan eng yuqori balandlik qancha A) 20m B) 360m C) 180m D) 10m 7 / 25 Agar jism biror balandlikdan ikki baravar katta tezlik bilan gorizantal otilsa, uning uchish uzoqligi qanday o’zgaradi A) 2 marta kamayadi B) 4 martta ortadi C) o’zgarmaydi D) 2 marta ortadi 8 / 25 Ikki jism bir biriga F kuchi bilan tortilmoqda. Agar birining massasi n marta kamaytirilsa ular qanday kuch bilan tortiladi A) F*n B) F(n-1) C) F/n D) F(n+1) 9 / 25 Qaysi shart bajarilganda, jism suyuqlikda tekis cho’ka boshlaydi? (mg-og’irlik kuchi, Fa- Arximed kuchi, F-qarshilik kuchi) 1) m g > F = F a 2) m g = F 3) m g = F = F a 4) mg < F = F a A) 3 B) 4 C) 2 D) 1 10 / 25 Xalqaro birliklar sistemasida kuch birligi A) kg / s² B) kg*m / s² C) m / s² D) kg*m²/s² 11 / 25 Massasi 0,5 kg bo’lgan koptokka 0,02 s davomida zarb berilgandan keyin u 10 m / s tezlik oladi. Zarbning o’rtacha kuchini toping A) 1000 N B) 200 N C) 250 N D) 500 N 12 / 25 Odam liftda turibdi. Odamga ta’sir qiluvchi kuchlar: mg – og’irlik kuchi, N – tayanch reaksiya kuchi, Lift yuqoriga xarakatlana boshlaganda kuchlar orasidagi munosabatni ko’rsating. 1) mg > N 2) mg < N 3) mg = N 4) mg = 0; N = 0 A) 1 B) 4 C) 2 D) 3 13 / 25 Odam liftda turibdi. Odamga ta’sir qiluvchi kuchlar: mg – og’irlik kuchi, N – tayanch reaksiya kuchi, Lift tekis xarakatlanganda kuchlar orasidagi munosabatni ko’rsating. Lift yuqoriga xarakatlana boshlaydi 1) mg > N 2) mg < N 3) mg = N 4) mg = 0; N = 0 A) 4 B) 3 C) 2 D) 1 14 / 25 Avtomobil 5 m/s2 tezlanish bilan tinch holatdan harakat boshladi. U 4s da necha metr yo’l o’tadi? A) 20 B) 40 C) 10 D) 30 15 / 25 Samolyot qo’nish paytida g’ildiraklari yerga tekkandagi tezligi 360 km/soat. Agar uning tezlanishi 2m/s2 bo’lsa, u qancha vaqtdan keyin to’xtaydi A) 25 s B) 100 s C) 5 s D) 50 s 16 / 25 Jismning harakat tenglamasi x = 2 – 3 t + 2 t2 formula bilan berilgan. Bu harakat uchun tezlik tenglamasini yozing A) υ= 4 + 3 t B) υ= - 3 + 4 t C) υ = 4 t D) υ= 4 - 3 t 17 / 25 m/s2 tezlanish bilan to’g’ri chiziq bo’ylab harakatlanayotgan jismning holatidan boshlab birinchi sekunda qanday masofani (m) o’tadi? A) 4 B) 8 C) 6 D) 7 18 / 25 Joyidan qo’zg’algan jism 0,2 m/s2 tezlanish bilan harakatlanganda 1 minutda u qanday tezlikka erishadi A) 120 m/s B) 0,12 m/s C) 12 m/s D) 1,2 m/s 19 / 25 Yuqoriga tik otilgan jism H balandlikkacha ko’tarildi. U 4H balandlikkacha ko’tarilishi uchun otish tezligini qanday o’zgartirishi kerak? A) 2marta orttirish B) 4marta orttirish C) 5marta kamaytirish D) 1marta orttirish 20 / 25 Erkin tushib harakat qilayotgan jismning tezligi har sekundda qanchaga o’zgaradi A) 15 m/s B) 5 m/s C) 10 m/s D) o’zgarmaydi 21 / 25 Jism harakat tenglamasi x=5+3t–t2 formula bilan berilgan. Jismning boshlang’ich koordinatasi nimaga teng? A) 1 m B) 5 m C) 3 m D) 9 m 22 / 25 Tekis tezlanuvchan harakat qilayotgan “Matiz” 10 s davomida tezligini 54 km / soat dan 100 km / soat ga oshirdi. «Matiz»ning tezlanishini toping A) 13 m/s² B) 2,5 m/s² C) 3 m/s² D) 15 m/s² 23 / 25 Aylanma tekis harakatda aylanish davri va chastotasi bog’lanishi formulasini ko’rsating A) t=T*N B) T=2¶R/V C) T=t/N D) T=1/v 24 / 25 Soatning minut mili burchakli tezligini toping A) π/30 B) π/1800 C) π/10 D) π/2600 25 / 25 Velosiped g’ildiragining o’qidan eng uzoq nuqtasi 0,02 s davomida 20 km yo’lni bosib o’tdi. Velosipedning tezligini toping A) 36 km/soat B) 4 km/soat C) 3,6 km/soat D) 0,36 km/soat 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz