Uy » Choraklik online testlar » Fizika choraklik » 7-sinf Fizika 4-chorak Fizika choraklik 7-sinf Fizika 4-chorak InfoMaster Aprel 26, 2021 1017 Ko'rishlar 0 SaqlashSaqlanganOlib tashlandi 1 0 Tomonidan yaratilgan InfoMaster 7-sinf Fizika 4-chorak Testni Vafaqulov Alisher tayyorladi. 1 / 25 Erkin tushish deb qaysi harakatga aytiladi A) jismga hech qanday kuch ta’sir qilmagandagi harakatiga B) jismning havosiz joyda faqat yerning tortish ta’sridagi harakatiga C) qo’ldan qo’yib yuborgan jism harakatiga D) xar qanday harakatga 2 / 25 Tezlanishning o’lchov birligini ko’rsating A) m²/s B) m/s C) m/s² D) s/ m² 3 / 25 Jism yerdan 35 m/s tezlik bilan tik yuqoriga otildi. U yerga necha sekunddan so’ng tushadi? A) 3 B) 7 C) 5 D) 9 4 / 25 Jism harakat tenglamasi x=5+3t–t2 formula bilan berilgan. Jismning boshlang’ich koordinatasi nimaga teng? A) 3 m B) 5 m C) 9 m D) 1 m 5 / 25 Jism tezlik proporsiyasining vaqtga bog’lanish v = 3+2t (m/s) ko’rinishga ega. Ko’chish proyeksiyasining vaqtga bog’lanishi qanday? A) S = 3t + 2 t² B) S = 2t + 3 ² C) S = 2t² D) S = 3t + 1 t² 6 / 25 Jism tekis tezlanuvchan harakat boshlab, 3-sekundda 5 m yo’l o’tdi. U harakatning boshlang’ich 3 sekundida qanday yo’l o’tadi (m) ? A) 11 B) 9 C) 13 D) 7 7 / 25 Jism 20 m/s tezlik bilan tik yuqoriga otildi. Jism necha sekund eng baland nuqtasigacha ko’tariladi? g = 10 m/s2 A) 3 c B) 2 c C) 1 c D) 4 c 8 / 25 Boshlang’ich tezliksiz erkin tushayotgan jism birinchi sekunda qanday masofani o’tadi?g = 10 m/s2 A) 5 m B) 50 m C) 0,5 m D) 5,5 m 9 / 25 Tezlanish formulasi qanday ifodalanadi A) a = (v - v˳)/t B) S = at² / 2 C) p = F / S D) p = m / v 10 / 25 Joyidan qo’zg’algan jism 0,3 m/s2 tezlanish bilan harakat qilib, qancha vaqtda 9 m/s tezlikka erishadi? A) 30 s B) 20 s C) 25 s D) 15 s 11 / 25 Yerning tortishish kuchi ta’sirida jismning yer atrofida aylana bo’ylab, harakatlanishida erishtiradigan tezlik ………. deyiladi A) 1-kosmik tezlik B) 2-kosmik tezlik C) 3-kosmik tezlik D) notekis tezlik 12 / 25 Oyning yer atrofida aylanish tezligi nimaga teng A) 30 km/s B) 1 km/s C) 40 km/s D) 10 km/s 13 / 25 Raketa quyosh sistemasini tark etishi uchun u yerdan 16,7 km/s tezlik bilan uchirilishi kerak. Bu tezlikni nomi A) 1-kosmik tezlik B) 2-kosmik tezlik C) notekis tezlik D) 3-kosmik tezlik 14 / 25 Odam liftda turibdi. Odamga ta’sir qiluvchi kuchlar: mg – og’irlik kuchi, N – tayanch reaksiya kuchi, Lift pastda to’xtashdan oldin sekinlashganda kuchlar orasidagi munosabatni ko’rsating. Lift pastda to’xtashdan oldin sekinlashyapti 1) mg > N 2) mg < N 3) mg = N 4) mg = 0; N = 0 A) 2 B) 1 C) 3 D) 4 15 / 25 1 m/s2 tezlanish bilan tushayotgan liftdagi 20 kg massali bolaning og’irligi qancha? A) 170 N B) 190 N C) 180 N D) 200 N 16 / 25 Massasi 4 kg bo’lgan jism biror kuch ta’siri ostida 2 m/s2 tezlanish oldi. Shunday kuch ta’siri ostida massasi 10 kg bo’lgan jism qanday tezlanish oladi? A) 0,8 m/s² B) 1 m/s² C) 2 m/s² D) 0 17 / 25 Aylanma tekis harakatdagi chiziqli tezlik formulasini ko’rsating. 1) V=2¶R/T, 2) V=wR, 3)V=2¶RV A) 3 B) 1,2,3 C) 1 D) 2 18 / 25 Aylanma tekis harakatga chiziqli tezlik va burchakli tezlik bog’lanish formulasini ko’rsating A) ω=2p/T B) ω=2p υ C) υ=ωR D) υ=2pR/T 19 / 25 Aylanma tekis harakatda tezlanish qanday yo’nalgan? A) xar xil yo’nalgan bo’lishi mumkin B) urinma bo’ylab C) radius bo’ylab markazdan D) radius bo’ylab markazga 20 / 25 Avtomabil 90 km/soat tezlik bilan tekis harakatlanmoqda. Agar avtomobil g’ildiragining raidusi 35 sm bo’lsa, g’ildirak markazidan shuncha masofa uzoqlikdagi nuqtasining markaziga intilma tezlanishini toping. (m/s2) A) 50 B) 2000 C) 2800 D) 1786 21 / 25 Soatning sekund mili burchakli tezligini toping. (rad/s) A) π/1800 B) π/10 C) π/30 D) π/2600 22 / 25 Burchakli ko’chishning vaqtga nisbati qanday fizik kattalik? A) davr B) tezlanish C) burchakli tezlik D) chastota 23 / 25 Jismning vaqt birligi ichida to’liq aylanishlari soni aylanishi ….. deb ataladi A) tezligi B) davri C) chastotasi D) tezlanishi 24 / 25 Avtomabil 200 m radiusli aylana yo’lda 72 km/soat tezlik bilan harakatlanadi. Uning markaziga intilma tezlanishi qancha m/s2 ga teng? A) 2 B) 5 C) 4 D) 3 25 / 25 Uzunligi 25 sm bo’lgan ipga bog’langan sharcha 5 m/s chiziqli tezlik bilan aylanmoqda. Sharning markaziga intilma tezlanishini toping. (m/s2) A) 1 B) 2 C) 10 D) 100 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz