Uy » Choraklik online testlar » Fizika choraklik » 7-sinf Fizika 4-chorak Fizika choraklik 7-sinf Fizika 4-chorak InfoMaster Aprel 26, 2021 1044 Ko'rishlar 0 SaqlashSaqlanganOlib tashlandi 1 0 Tomonidan yaratilgan InfoMaster 7-sinf Fizika 4-chorak Testni Vafaqulov Alisher tayyorladi. 1 / 25 Agar jism biror balandlikdan ikki baravar katta tezlik bilan gorizantal otilsa, uning uchish vaqti qanday o’zgaradi A) 2 marta ortadi B) 4 martta ortadi C) o’zgarmaydi D) 2 marta kamayadi 2 / 25 Yer sirtidagi h=2R balandlikda erkin tushish tezlanishi nimaga teng A) g/2 B) g C) g/9 D) g/4 3 / 25 Yer uchun uchunchi kosmik tezlik qiymatini ko’rsating A) 7,9 m/s B) 11,2 km/s C) 16,7 km/s D) 7,9 km/s 4 / 25 Gravitatsion doimiy xalqaro birliklar sistemasida qanday birlik bilan aniqlanadi A) N/m² B) kg*m/S² C) m³/kg*s² D) N*kg 5 / 25 Lift a A) (P=mg) B) P=m(g-a) C) P=m(a-g) D) P=m(g+a) 6 / 25 Jismning harakat tenglamasi x = 2 – 3 t + 2 t2 formula bilan berilgan. Bu harakat uchun tezlik tenglamasini yozing A) υ = 4 t B) υ= 4 + 3 t C) υ= 4 - 3 t D) υ= - 3 + 4 t 7 / 25 Yuqoriga tik otilgan jism H balandlikkacha ko’tarildi. U 4H balandlikkacha ko’tarilishi uchun otish tezligini qanday o’zgartirishi kerak? A) 5marta kamaytirish B) 2marta orttirish C) 4marta orttirish D) 1marta orttirish 8 / 25 Joyidan qo’zg’algan jism 0,3 m/s2 tezlanish bilan harakat qilib, qancha vaqtda 9 m/s tezlikka erishadi? A) 30 s B) 20 s C) 15 s D) 25 s 9 / 25 25 m/s tezlik bilan yuqoriga tik otilgan jismning 2 s dan keyingi tezligi qancha bo’ladi? A) 5 m/s B) 15 m/s C) 10 m/s D) 20 m/s 10 / 25 Tezlanishning o’lchov birligini ko’rsating A) m/s B) m/s² C) m²/s D) s/ m² 11 / 25 Tezligi υ=5-3 t (m/s) tenglama bilan berilgan jismning boshlangich tezligi (m/s) nimaga teng? A) 3 B) 2 C) 4 D) 5 12 / 25 O’zaro ta’sirlashuvchi jismlarning bir-biriga ta’sir kuchlari bir to’g’ri chiziq bo’yicha yo’nalgan, moduli bo’yicha teng va yo’nalish bo’yicha qarama-qarshidir. Bu ....... A) Nyutonning 1 qonuni B) Nyutonning 3 qonuni C) Nyutonning 2 qonuni D) Nyutonning butun olam tortishish kuchi qonuni 13 / 25 Odam liftda turibdi. Odamga ta’sir qiluvchi kuchlar: mg – og’irlik kuchi, N – tayanch reaksiya kuchi, Lift yuqoriga xarakatlana boshlaganda kuchlar orasidagi munosabatni ko’rsating. 1) mg > N 2) mg < N 3) mg = N 4) mg = 0; N = 0 A) 2 B) 3 C) 1 D) 4 14 / 25 Massasi m = 10 kg bo’lgan jismga 25 N kuch ta’sir qilmoqda. Shu kuch ta’sirida u qanday tezlanish bilan harakat qiladi? A) 2,5 m / s² B) 6 m / s ² C) 3 m / s² D) 1 m / s² 15 / 25 Odam liftda turibdi. Odamga ta’sir qiluvchi kuchlar: mg – og’irlik kuchi, N – tayanch reaksiya kuchi, Lift tekis xarakatlanganda kuchlar orasidagi munosabatni ko’rsating. Lift yuqoriga xarakatlana boshlaydi 1) mg > N 2) mg < N 3) mg = N 4) mg = 0; N = 0 A) 4 B) 2 C) 3 D) 1 16 / 25 1 m/s2 tezlanish bilan tushayotgan liftdagi 20 kg massali bolaning og’irligi qancha? A) 200 N B) 180 N C) 190 N D) 170 N 17 / 25 Odam liftda turibdi. Odamga ta’sir qiluvchi kuchlar: mg – og’irlik kuchi, N – tayanch reaksiya kuchi, Lift tinch turganda kuchlar orasidagi munosabatni ko’rsating 1) mg > N 2) mg < N 3) mg = N 4) mg = 0; N = 0 A) 1 B) 3 C) 4 D) 2 18 / 25 Nyutonning 3 qonuni formulasi qaysi ifodada to’g’ri ko’rsatilgan? A) F = - k x B) F = mv²/ R C) F1 =- F2 D) F = mg 19 / 25 Soatning minut mili aylanishining chastotasini toping.(Hz) A) 100 B) 1/100 C) 1/3600 D) 1/7200 20 / 25 Aylanma tekis harakatda chiziqli tezlik bilan burchak tezlik orasidagi munosabat formulasini ko’rsating A) w=2¶V B) w=4/t C) V=wR D) w=2¶/T 21 / 25 Soatning 30 mm uzunlikdagi minut uchi 10 minutda 31,4 mm uzunlikdagi yo’lni bosib o’tdi. Minut mili uchining burilish burchagini toping. (rad) A) 3 rad B) 4 rad C) 1,05 rad D) 5 rad 22 / 25 Aylanma tekis harakatda tezlanish qanday yo’nalgan? A) xar xil yo’nalgan bo’lishi mumkin B) radius bo’ylab markazdan C) urinma bo’ylab D) radius bo’ylab markazga 23 / 25 Soatning vaqt mili burchakli tezligini toping. (rad/s) A) π/2600 B) π/1800 C) π/10 D) π/30 24 / 25 Aylanma tekis harakatda aylanish davri va chastotasi bog’lanishi formulasini ko’rsating A) T=t/N B) T=1/v C) T=2¶R/V D) t=T*N 25 / 25 Burchakli ko’chishning vaqtga nisbati qanday fizik kattalik? A) chastota B) tezlanish C) burchakli tezlik D) davr 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz