Uy » Choraklik online testlar » Fizika choraklik » 7-sinf Fizika 4-chorak Fizika choraklik 7-sinf Fizika 4-chorak InfoMaster Aprel 26, 2021 1036 Ko'rishlar 0 SaqlashSaqlanganOlib tashlandi 1 0 Tomonidan yaratilgan InfoMaster 7-sinf Fizika 4-chorak Testni Vafaqulov Alisher tayyorladi. 1 / 25 Agar jism biror balandlikdan ikki baravar katta tezlik bilan gorizantal otilsa, uning uchish uzoqligi qanday o’zgaradi A) 2 marta kamayadi B) o’zgarmaydi C) 4 martta ortadi D) 2 marta ortadi 2 / 25 Zambarakdan gorizantga burchak ostida uchib chiqqan snaryad 12 sekund uchgan. Snaryad ko’tarilgan eng yuqori balandlik qancha A) 10m B) 360m C) 20m D) 180m 3 / 25 Gravitatsion doimiy xalqaro birliklar sistemasida qanday birlik bilan aniqlanadi A) kg*m/S² B) N/m² C) m³/kg*s² D) N*kg 4 / 25 Liftdagi odam o’ta yuklanishga duch kelishi mumkinmi? A) Xa lift tezlanish bilan pastga tushganda B) Yo’q C) Xa agar lift tezlanish bilan yuqoriga ko’tarilsa D) Xa lift yuqoriga ko’tarilganda 5 / 25 Yerning quyosh atrofida aylanish tezligi nimaga teng A) 40 km/s B) 1 km/s C) 10 km/s D) 30 km/s 6 / 25 Oyning yer atrofida aylanish tezligi nimaga teng A) 30 km/s B) 40 km/s C) 1 km/s D) 10 km/s 7 / 25 Yer sirtidagi jism yerga F kuch bilan tortilmoqda. Yer sirtidan h=2R balandlikka ko’tarilsa yerga qanday kuch bilan tortiladi? R-Ep radus A) F/2 B) F/9 C) F/16 D) F/4 8 / 25 Yerga tortilishi tufayli jismning tayanchga yoki osmaga tasr etadigan kuchi .......... deb ataladi A) reaksiya kuchi B) bosim kuchi C) jism og’irligi D) og’irlik kuchi 9 / 25 Jismning harakat tenglamasi x = 2 – 3 t + 2 t2 formula bilan berilgan. Bu harakat uchun tezlik tenglamasini yozing A) υ = 4 t B) υ= 4 - 3 t C) υ= 4 + 3 t D) υ= - 3 + 4 t 10 / 25 Jism tezlik proporsiyasining vaqtga bog’lanish v = 3+2t (m/s) ko’rinishga ega. Ko’chish proyeksiyasining vaqtga bog’lanishi qanday? A) S = 2t² B) S = 3t + 1 t² C) S = 3t + 2 t² D) S = 2t + 3 ² 11 / 25 Tekis tezlanuvchan harakat qilayotgan “Matiz” 10 s davomida tezligini 54 km / soat dan 100 km / soat ga oshirdi. «Matiz»ning tezlanishini toping A) 13 m/s² B) 15 m/s² C) 3 m/s² D) 2,5 m/s² 12 / 25 Uzunligi 25 sm bo’lgan ipga bog’langan sharcha 5 m/s chiziqli tezlik bilan aylanmoqda. Sharning markaziga intilma tezlanishini toping. (m/s2) A) 10 B) 100 C) 1 D) 2 13 / 25 Markazga intilma tezlanish formulasi qaysi ifodada to'g'ri ko’rsatilgan? A) a=F/m B) a=v²/R C) a=v/t D) a=(v-v˳)/t 14 / 25 Aylana bo’ylab tekis harakatda markazga intilma tezlanish formulasini ko’rsating. 1) a=v2/R, 2) a=v2/2R, 3) a=v/t A) 1,2 B) 3 C) 1 D) 2 15 / 25 Velosiped g’ildiragining o’qidan eng uzoq nuqtasi 0,02 s davomida 20 km yo’lni bosib o’tdi. Velosipedning tezligini toping A) 0,36 km/soat B) 4 km/soat C) 36 km/soat D) 3,6 km/soat 16 / 25 Aylanma tekis harakatdagi chiziqli tezlik formulasini ko’rsating. 1) V=2¶R/T, 2) V=wR, 3)V=2¶RV A) 1,2,3 B) 1 C) 2 D) 3 17 / 25 Soatning minut mili burchakli tezligini toping A) π/30 B) π/1800 C) π/2600 D) π/10 18 / 25 Aylanma tekis harakatda chiziqli tezlik bilan burchak tezlik orasidagi munosabat formulasini ko’rsating A) w=2¶/T B) V=wR C) w=2¶V D) w=4/t 19 / 25 Jismning vaqt birligi ichida to’liq aylanishlari soni aylanishi ….. deb ataladi A) tezlanishi B) chastotasi C) tezligi D) davri 20 / 25 60 N kuch jismga 0,8 m/s2 tezlanish beradi. Qanday kuch bu jismga 2 m/s2 tezlanish beradi? A) 24 N B) 240 N C) 15 N D) 150 N 21 / 25 Suv quyilgan idish lift kabinasiga joylashtirilgan. Agar lift tezlanish bilan yuqoriga harakatlansa, suvning idish tubiga bosimi qanday o’zgaradi? A) O’zgarmaydi B) Ortishi xam, kamayishi xam mumkin C) Ortadi D) Kamayadi 22 / 25 Odam liftda turibdi. Odamga ta’sir qiluvchi kuchlar: mg – og’irlik kuchi, N – tayanch reaksiya kuchi, Lift tinch turganda kuchlar orasidagi munosabatni ko’rsating 1) mg > N 2) mg < N 3) mg = N 4) mg = 0; N = 0 A) 4 B) 2 C) 3 D) 1 23 / 25 Odam liftda turibdi. Odamga ta’sir qiluvchi kuchlar: mg – og’irlik kuchi, N – tayanch reaksiya kuchi, Lift yuqoriga xarakatlana boshlaganda kuchlar orasidagi munosabatni ko’rsating. 1) mg > N 2) mg < N 3) mg = N 4) mg = 0; N = 0 A) 3 B) 4 C) 1 D) 2 24 / 25 Nyutonning 3 qonuni formulasi qaysi ifodada to’g’ri ko’rsatilgan? A) F1 =- F2 B) F = mv²/ R C) F = - k x D) F = mg 25 / 25 Motosikl botiq ko’prik ustida tekis harakatlanmoqda. Ko’prikning eng quyi nuqtasiga yetganida unga qo’yilgan kuchlarning teng ta’sir etuvchisi qanday yo’nalgan bo’ladi? A) Orqaga B) Pastga C) Oldinga D) Yuqoriga 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz