Uy » Choraklik online testlar » Fizika choraklik » 7-sinf Fizika 4-chorak Fizika choraklik 7-sinf Fizika 4-chorak InfoMaster Aprel 26, 2021 1106 Ko'rishlar 0 SaqlashSaqlanganOlib tashlandi 1 1 Tomonidan yaratilgan InfoMaster 7-sinf Fizika 4-chorak Testni Vafaqulov Alisher tayyorladi. 1 / 25 Boshlang’ich tezliksiz erkin tushayotgan jism birinchi sekunda qanday masofani o’tadi?g = 10 m/s2 A) 0,5 m B) 5 m C) 5,5 m D) 50 m 2 / 25 Jism tezlik proporsiyasining vaqtga bog’lanish v = 3+2t (m/s) ko’rinishga ega. Ko’chish proyeksiyasining vaqtga bog’lanishi qanday? A) S = 2t + 3 ² B) S = 2t² C) S = 3t + 2 t² D) S = 3t + 1 t² 3 / 25 Tezlanish formulasi qanday ifodalanadi A) p = m / v B) a = (v - v˳)/t C) S = at² / 2 D) p = F / S 4 / 25 Joyidan qo’zg’algan jism 0,2 m/s2 tezlanish bilan harakatlanganda 1 minutda u qanday tezlikka erishadi A) 1,2 m/s B) 120 m/s C) 12 m/s D) 0,12 m/s 5 / 25 Jismning harakat tenglamasi x = 2 – 3 t + 2 t2 formula bilan berilgan. Bu harakat uchun tezlik tenglamasini yozing A) υ= 4 + 3 t B) υ = 4 t C) υ= 4 - 3 t D) υ= - 3 + 4 t 6 / 25 m/s2 tezlanish bilan to’g’ri chiziq bo’ylab harakatlanayotgan jismning holatidan boshlab birinchi sekunda qanday masofani (m) o’tadi? A) 8 B) 7 C) 4 D) 6 7 / 25 Aylanma tekis harakatda chiziqli tezlik bilan burchak tezlik orasidagi munosabat formulasini ko’rsating A) w=2¶/T B) V=wR C) w=2¶V D) w=4/t 8 / 25 Velosiped raridusi 25 m bo’lgan aylanma yo’lda 10 m/s tezlik bilan tekis harakatlanmoqda. Uning markazga intilma tezlanishini toping. (m/s²) A) 3 B) 5 C) 4 D) 2 9 / 25 Soatning minut mili burchakli tezligini toping A) π/10 B) π/2600 C) π/1800 D) π/30 10 / 25 Uzunligi 25 sm bo’lgan ipga bog’langan sharcha 5 m/s chiziqli tezlik bilan aylanmoqda. Sharning markaziga intilma tezlanishini toping. (m/s2) A) 100 B) 1 C) 2 D) 10 11 / 25 Aylanma tekis harakatda aylanish davri va chastotasi bog’lanishi formulasini ko’rsating A) t=T*N B) T=1/v C) T=2¶R/V D) T=t/N 12 / 25 Avtomabil 90 km/soat tezlik bilan tekis harakatlanmoqda. Agar avtomobil g’ildiragining raidusi 35 sm bo’lsa, g’ildirak markazidan shuncha masofa uzoqlikdagi nuqtasining markaziga intilma tezlanishini toping. (m/s2) A) 2800 B) 2000 C) 50 D) 1786 13 / 25 Aylana bo’ylab tekis harakatda markazga intilma tezlanish formulasini ko’rsating. 1) a=v2/R, 2) a=v2/2R, 3) a=v/t A) 3 B) 1 C) 2 D) 1,2 14 / 25 Massasi 4 kg bo’lgan jism biror kuch ta’siri ostida 2 m/s2 tezlanish oldi. Shunday kuch ta’siri ostida massasi 10 kg bo’lgan jism qanday tezlanish oladi? A) 1 m/s² B) 0,8 m/s² C) 2 m/s² D) 0 15 / 25 1 m/s2 tezlanish bilan tushayotgan liftdagi 20 kg massali bolaning og’irligi qancha? A) 190 N B) 170 N C) 200 N D) 180 N 16 / 25 Qaysi shart bajarilganda, jism suyuqlikda tekis cho’ka boshlaydi? (mg-og’irlik kuchi, Fa- Arximed kuchi, F-qarshilik kuchi) 1) m g > F = F a 2) m g = F 3) m g = F = F a 4) mg < F = F a A) 1 B) 3 C) 4 D) 2 17 / 25 Odam liftda turibdi. Odamga ta’sir qiluvchi kuchlar: mg – og’irlik kuchi, N – tayanch reaksiya kuchi, Lift pastda to’xtashdan oldin sekinlashganda kuchlar orasidagi munosabatni ko’rsating. Lift pastda to’xtashdan oldin sekinlashyapti 1) mg > N 2) mg < N 3) mg = N 4) mg = 0; N = 0 A) 1 B) 2 C) 4 D) 3 18 / 25 Odam liftda turibdi. Odamga ta’sir qiluvchi kuchlar: mg – og’irlik kuchi, N – tayanch reaksiya kuchi, Lift tinch turganda kuchlar orasidagi munosabatni ko’rsating 1) mg > N 2) mg < N 3) mg = N 4) mg = 0; N = 0 A) 4 B) 3 C) 2 D) 1 19 / 25 Nyutonning 3 qonuni formulasi qaysi ifodada to’g’ri ko’rsatilgan? A) F = - k x B) F = mv²/ R C) F = mg D) F1 =- F2 20 / 25 Yer uchun uchunchi kosmik tezlik qiymatini ko’rsating A) 7,9 km/s B) 16,7 km/s C) 11,2 km/s D) 7,9 m/s 21 / 25 Yer sirtidagi h=2R balandlikda erkin tushish tezlanishi nimaga teng A) g/2 B) g/9 C) g D) g/4 22 / 25 Raketa quyosh sistemasini tark etishi uchun u yerdan 16,7 km/s tezlik bilan uchirilishi kerak. Bu tezlikni nomi A) 1-kosmik tezlik B) 2-kosmik tezlik C) 3-kosmik tezlik D) notekis tezlik 23 / 25 Agar jism biror balandlikdan ikki baravar katta tezlik bilan gorizantal otilsa, uning uchish uzoqligi qanday o’zgaradi A) 2 marta ortadi B) 2 marta kamayadi C) o’zgarmaydi D) 4 martta ortadi 24 / 25 Agar jism biror balandlikdan ikki baravar katta tezlik bilan gorizantal otilsa, uning uchish vaqti qanday o’zgaradi A) 2 marta kamayadi B) 4 martta ortadi C) o’zgarmaydi D) 2 marta ortadi 25 / 25 Liftdagi odam o’ta yuklanishga duch kelishi mumkinmi? A) Xa agar lift tezlanish bilan yuqoriga ko’tarilsa B) Yo’q C) Xa lift yuqoriga ko’tarilganda D) Xa lift tezlanish bilan pastga tushganda 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz