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Matematika choraklik

10-sinf Matematika 3-chorak

InfoMaster

Aprel 20, 2021

706 Ko'rishlar 7 izohlar

SaqlashSaqlanganOlib tashlandi 3

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OMAD YOR BO'LSIN!

Tomonidan yaratilgan InfoMaster

10-sinf Matematika 3-chorak

Testni Imomnazarov Ibrohim tayyorladi.

1 / 25

Tekislikda A(3;1) va B(7;3) nuqtalardan teng uzoqlikda joylashgan C(5;x) nuqtani toping.

A) (5;2)

B) (5;3)

C) (4;2)

D) (4;3)

2 / 25

Teglamani yeching

A) 5/2

B) 1/2

C) 1

D) 1/3

3 / 25

Tenglamani katta ildizini toping:
(x−5)(x+4)(x−11)=0

A) 5

B) 16

C) 11

D) -4

4 / 25

Bikvadrat tenglamaning ildizlari yig‘indisini toping:

A) -1

B) 11/3

C) 1

D) 0

5 / 25

Teng kuchli tenglamalarni ko‘rsating:

A) hammasi

B) 1 va 3;

C) 1 va 2;

D) 2 va 3;

6 / 25

Tenglamalar sistemasining nechta yechimi bor?

A) 1

B) 2

C) 4

D) 3

7 / 25

Mulohaza deb nimaga aytiladi?

A) So’roq gapga.

B) Rost yoki yolg’on bo’ladigan darak gapga.

C) Faqat yolg’on darak gapga.

D) Faqat rost darak gapga.

8 / 25

Ushbu ifoda qanday o’qiladi?

A) A to’plam cheksiz to’plam;

B) A to’plam bo’sh to’plam;

C) A to’plamning elementlar soni 6 ta;

D) A to’plamning elementlar soni 9 ta;

9 / 25

U=N, P={8 dan katta butun sonlar} bo’lsa n(P) ni toping.

A) Cheksiz ko’p

B) 15 ta

C) 7 ta

D) 8 ta

10 / 25

x∈A kabi yozuvni o’qilishi to’g’ri ko’rsatilgan qatorni toping.

A) bunday ifoda yo’q

B) to’g’ri javob yo’q.

C) x element A ga tegishli;

D) x element A ga tegishli emas;

11 / 25

A to’plamning to’ldiruvchisi qanday belgilanadi?

A) A'

B) A∩B

C) A~B

D) A''

12 / 25

Har doim rost bo’ladigan mulohaza nima deyiladi ?

A) Tavtologiya

B) Teng kuchli

C) Dezyunksiya

D) Konyuksiya

13 / 25

Ikki mulohaza "agar ... bo‘lsa, u holda ..." ibora bilan boglansa, u holda mulohazalar .......ega bo‘lamiz.

A) Implikatsiyasiga

B) Ekvivalensiyaga

C) Dezyunksiyaga

D) Konversiyaga

14 / 25

Quyidagi mulohazaning rostlik jadvalida nechta rost qatnashadi ? ¬(p∨q)

A) 2 ta

B) 1 ta

C) 3 ta

D) 4 ta

15 / 25

Grafigikka qarab finksiyani toping.

A) y=sin2x

B) y=sin2x+1

C) y=2cosx

D) y=cos2x+1

16 / 25

Grafigikka qarab finksiyani toping.

A) y=2sinx

B) y=cosx

C) y=2cosx

D) y=3sinx

17 / 25

Hisoblang: arctg

A) -π

B) π/4

C) π/3

D) π/6

18 / 25

Hisoblang:

A) -π/4

B) -π/3

C) π/3

D) π

19 / 25

Grafigikka qarab finksiyani toping.

A) y=cosx-1

B) y=cosx-2

C) y=sinx-2

D) y=2cosx+1

20 / 25

Hisoblang:

A) π/6

B) π/4

C) π

D) 4π/3

21 / 25

Hisoblang:
arcsin 0

A) 3π/2

B) 0

C) π

D) π/2

22 / 25

Hisoblang:

A) -π/6

B) 6π/5

C) π/3

D) 5π/6

23 / 25

Hisoblang:

A) 5π/3

B) π/3

C) 3π/2

D) 2π/3

24 / 25

Hisoblang:

A) 5π/2

B) 2π/3

C) π/3

D) 3π/3

25 / 25

Funksiyaning davrini aniqlang: y=cosx/3 (gradusda)

A) 120

B) 240

C) 1080

D) 1200

0%

Baholash mezoni

86%-100% 5 baho

71%-85% 4 baho

56%-70% 3 baho

55% va kamiga 2 baho

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