Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 115 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 1 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 Parallelogrammning yuzi 213 ga, tomonlaridan biri 7 ga va o’tkir burchagi 600 ga teng bo’lsa, ikkinchi tomonini toping A) 5 B) 6 C) 8 D) 4 2 / 30 Agar f(x)=ax3-5x2+b va bo’lsa, a ni toping. A) 2 B) 1 C) 0 D) 3 3 / 30 tenglamani yeching. A) 2019 B) 2018 C) 0 D) 2017 4 / 30 Tengsizlikni yeching. A) (-4;2)v(2;3) B) (2;4) C) (-3;2)v(2;4) D) (-3;2) 5 / 30 Anvar tub son o’yladi va o’ylagan sonini 5 ga ko’paytirib, 8 ni ayirgan edi, yana tub son hosil bo’ldi. Anvar qanday son o’ylagan? A) aniqlab bo’lmaydi B) 374389 C) 2 D) 412967 6 / 30 Agar geometrik progressiyaning ketma–ket dastlabki uchta hadining yig’indisi 62 ga, ularning o’nli logarifmlari yig’indisi 3 ga teng bo’lsa, shu geometrik progressiyaning birinchi hadini toping. A) 2 yoki 50 B) 50 C) 10 D) 10 yoki 50 7 / 30 Quyidagilardan qaysi biri barcha lar uchun ma’noga ega (aniqlangan)? A) ⁴ᴷ⁺³√-√2k+1 B) ²ᴷ⁺⁴v2k+1/k²+1 C) 4k+1/1/8:7-1/56 D) (512-1/2⁻⁹)° 8 / 30 7 sonini uchta natural sonlar yig’indisi ko’rinishida necha xil usulda yozish mumkin? A) 3 B) 6 C) 4 D) 5 9 / 30 y= funktsiyaning aniqlanish sohasini toping. A) (-∞;2) B) [2;∞) C) (-∞;2)v(2;∞) D) (2;∞) 10 / 30 Rasmda ko‘rsatilgan ko‘pyoqlardan qaysi birida 4 ta yoq, 6 ta qirra bor? A) 1, 2 B) 2 C) 3 D) 1, 3 11 / 30 Tengsizlik nechta butun yechimga ega? A) cheksiz ko’p B) 3 C) 4 D) 1 12 / 30 A(2;-2,5) nuqtadan y= - 4x parabolagacha bo’lgan eng qisqa masofani toping. A) 1,5 B) √3/2 C) √5/2 D) 1 13 / 30 To’g’ri burchakli uchburchakning gipotenuzasi 13 ga, katetlaridan biri 52 ga teng. Gipotenuzaga tushirilgan balandlik uzunligini toping A) 7 B) 4 C) 5 D) 6 14 / 30 Tomoni 25 ga diagonallaridan biri 4 ga teng bo’lgan rombning yuzini toping. A) 32 B) 24√5 C) 16 D) 8√5 15 / 30 Radiuslari orasidagi burchagi 36o va radiusi 5 ga teng bo`lgan sektor yoyining uzunligini toping. A) π B) 2π/3 C) 2π D) π/2 16 / 30 Hisoblang: A) 2 B) -1 C) 3 D) 1 17 / 30 |x2-5x-14|+20≥5|x+2|+4|x-7| tengsizlikni yeching. A) (-∞;-6]v{2}v[12;∞) B) [-2;4]v{6} C) [2;4]v{2}v[3;∞) D) [1;6] 18 / 30 Agar va b-a=4 bo’lsa, a+b ni toping. A) 4 B) 3 C) 3,5 D) 2 19 / 30 Bankda qo`yilgan pul bir yildan kegin foydasi bilan 2600 so`m bo`ldi; Agar bank yillik 30% foyda to`lasa, boshida qancha pul qo`yilgan bo`ladi ? A) 2000 B) 2200 C) 1900 D) 2100 20 / 30 a(x+2)=2x+1 tenglama a ning qanday qiymatida yechimga ega emas? A) (-∞;2)v(2;∞) B) (-∞;2) C) (∞;∞) D) (2;∞) 21 / 30 bo’lsa, ni x orqali ifodalang. A) 2/x B) 25/x C) x/25 D) 2-x 22 / 30 To’g’ri burchakli uchburchakning gipotenuzasi 5 ga, bir katetining gipotenuzadagi proyeksiyasi 1,6 ga teng. Ikkinchi katetning kvadratini toping. A) 18 B) 14 C) 16 D) 17 23 / 30 To‘g‘ri to‘rtburchakning eni 25% ga orttirildi, bo‘yi esa 25% ga kamaytirildi. Natijada uning yuzi qanday o‘zgardi? A) 6,25% ga ortadi B) o‘zgarmaydi C) 2,5% ga ortadi D) 6,25% ga kamayadi 24 / 30 Sin9x =4sin3x tenglamani yeching A) πn, n€Ζ B) π/2+πn, n€Ζ C) π/3+πn, n€Ζ D) πn/3, n€Ζ 25 / 30 a=sin 1; b=sin 2; c=sin 3; d=sin 4 va e=sin 5 sonlarni kamayish tartibida joylashtiring. A) e>b>a>d>c B) b>a>c>d>e C) b>c>a>d>e D) a>b>c>d>e 26 / 30 Ifodani soddalashtiring. [ln(ln x)-ln(loge10)].log10e A) ln(ln x) B) lg(lg x) C) ln(lg x) D) lg(ln x) 27 / 30 Agar f(x)=4x3-6x2-2x+3x .log3e bo’lsa, u holda ni toping. A) 3e B) e C) √2e D) 1 28 / 30 Agar x,y sonlar (x+5)2+(y-12)2=142 tenglikni qanoatlantirsa, x2+y2 ifodaning eng kichik qiymatini toping. A) 1 B) √3 C) 2 D) √2 29 / 30 Rombning balandligi 8 ga dioganallarining ko’paytmasi 80 ga teng. Rombning perimetrini toping A) 32 B) 20 C) 24 D) 16 30 / 30 tenglamalar sistemasini yeching A) (3;–4) B) (4;–3) C) (–4;3) D) (4;3) 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
