Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 121 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 1 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 To’g’ri burchakli uchburchakning gipotenuzasi 13 ga, katetlaridan biri 52 ga teng. Gipotenuzaga tushirilgan balandlik uzunligini toping A) 5 B) 7 C) 4 D) 6 2 / 30 Ifodani soddalashtiring. 2 cos55o.cos40o.sin55o+cos110o.sin40o A) 0,5 B) 2 C) 0 D) 1 3 / 30 Hisoblang. A) 2/17 B) 2/34 C) 15/34 D) 17/34 4 / 30 Rasmda ko‘rsatilgan ko‘pyoqlardan qaysi birida 4 ta yoq, 6 ta qirra bor? A) 1, 3 B) 2 C) 1, 2 D) 3 5 / 30 Ikki burchagi graduslari yig’indisi uchinchi burchagi gradusiga teng bo’lgan uchburchak qanday uchburchak deyiladi? A) o’tmas burchakli uchburchak B) o’tkir burchakli uchburchak C) to’gri burchakli uchburchak D) teng tomonli uchburchak 6 / 30 Soat 3:37 bo’lganda minut va soat millari orasidagi burchakni toping. A) 100° B) 112,5° C) 113,5° D) 113° 7 / 30 tenglamalar sistemasini yeching A) (4;3) B) (4;–3) C) (–4;3) D) (3;–4) 8 / 30 Tomoni 25 ga diagonallaridan biri 4 ga teng bo’lgan rombning yuzini toping. A) 16 B) 24√5 C) 32 D) 8√5 9 / 30 y=cos(2sinx) funksiyaning qiymatlar sohasini toping. A) [0;1] B) [0;cos2] C) [-1;1] D) [cos2;1] 10 / 30 Sin9x =4sin3x tenglamani yeching A) π/2+πn, n€Ζ B) π/3+πn, n€Ζ C) πn/3, n€Ζ D) πn, n€Ζ 11 / 30 y= funktsiyaning aniqlanish sohasini toping. A) (-∞;2)v(2;∞) B) [2;∞) C) (2;∞) D) (-∞;2) 12 / 30 O’q kesimining diagonallari o’zaro perpendikulyar bo’lgan kesik konus yasovchisi va asos tekisligi orasidagi burchak ga teng. Agar o’q kesimining diagonali ga teng bo’lsa, kesik konus asosining yuzini toping. A) πa²/4cos²α B) πa²(1-2sinα/4sin²) C) πa²/4sin²α D) πa²(1+2cosα/4sin²) 13 / 30 x2-5|x|-6=0 tenglama ildizini toping A) ±;±6 B) ±6 C) -1;6 D) -1;-6 14 / 30 Radiusi 25 bo’lgan doirada 48 ga teng vatar o’tkazilgan. Doira markazidan shu vatargacha masofani toping. A) 9 B) 8 C) 7 D) 10 15 / 30 Agar funksiya berilgan bo’lsa, u holda M=ning qiymatini toping. A) e⁻⁴⁹⁵⁰ B) e⁴⁹⁵⁰ C) e⁻⁵⁰⁵⁰ D) e⁵⁰⁵⁰ 16 / 30 Soddalashtiring. A) 2018 B) 2018a/a+1 C) 2019 D) a+1 17 / 30 |x2-5x-14|+20≥5|x+2|+4|x-7| tengsizlikni yeching. A) [1;6] B) [-2;4]v{6} C) (-∞;-6]v{2}v[12;∞) D) [2;4]v{2}v[3;∞) 18 / 30 Konsert zalining birinchi qatorida 40 ta o’rindiq bor. Har bir keyingi qatordagi o’rindiqlar soni oldingi qatordan 4 ga ko’p. Agar konsert zalida jami 40 ta qator bo’lsa, u holda shu zaldagi barcha o’rindiqlar sonini toping. A) 4720 B) 4760 C) 4680 D) 4716 19 / 30 ABCD to’gri to’rtburchak ichidan olingan O nuqtadan A, B, C, D uchlarigacha bo’lgan masofalar mos ravishda 1; 2; 1,5; 1,2 ga teng bo’ladigan barcha to’g’ri to’rtburchaklar sonini toping A) cheksiz ko’p B) 1 C) 2 D) 0 20 / 30 sistemadan x+y ning qiymatini toping. A) -12 B) 35/4 C) 6 D) 12 21 / 30 funksiya uchun quyidagi mulohazalardan qaysi biri o’rinli? A) juft ham emas, toq ham emas funksiya B) juft funksiya C) bunday funksiya mavjud emas D) toq funksiya 22 / 30 O’qishni bilmaydigan bola alifbening A,A,A, N,N, S- 6 ta harflarini ixtiyoriy ravishda terib chiqadi. Bunda ANANAS so’zining hosil bo’lish ehtimolini toping. A) 1/60 B) 5/720 C) 5/24 D) 6/720 23 / 30 Bir vaqtning o’zida 9,13, . . . ,405 va 15,21, . . . ,255 ketma–ketliklarning hadlari bo’lgan sonlarning eng kattasi va eng kichigining ayirmasini toping A) 150 B) 228 C) 147 D) 231 24 / 30 tenglamani yeching. A) 2019 B) 2018 C) 0 D) 2017 25 / 30 Uchburchakning balandligi 12 ga teng bo’lib, u asosni 5:16 nidbatda bo’ladi. Agar asosning uzunligi 21 ga teng bo’lsa, uchburchakning perimetrini toping A) 48 B) 108 C) 52 D) 54 26 / 30 sistema yagona yechimga ega bo’ladigan a ning barcha qiymatlari to’plamini toping. A) {2;4} B) {-1;2} C) {1;2} D) {-1;3} 27 / 30 Ostki asosining yuzi 20π va ustki asosining yuzi 10π ga teng bo‘lgan kesik konus berilgan. Agar kesik konusga shar ichki chizilgan bo‘lsa, u holda kesik konus hajmining shar hajmiga nisbatini toping. A) 2√2/3 B) 3√3+1/5 C) 5√3+3/3 D) 3√2+2/4 28 / 30 Parallelogrammning yuzi 213 ga, tomonlaridan biri 7 ga va o’tkir burchagi 600 ga teng bo’lsa, ikkinchi tomonini toping A) 5 B) 6 C) 4 D) 8 29 / 30 Musobaqada 5 ta ishtirokchidan 3 tasiga 1, 2, 3-o’rinlarni necha xil usulda berish mumkin? A) 18 B) 47 C) 120 D) 60 30 / 30 Tenglamaning ildizlari yig`indisini toping. A) 6 B) 5 C) 3 D) 4 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
