Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 126 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 3 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 tenglamalar sistemasini yeching A) (4;–4) B) (-4;-4) C) (-4;4) D) (4;4) 2 / 30 Agar sinx+cosx=a bo’lsa, ning qiymatini toping. A) 2/5 B) 1/2 C) 1/3 D) -1/2 3 / 30 Rombning balandligi 8 ga dioganallarining ko’paytmasi 80 ga teng. Rombning perimetrini toping A) 16 B) 24 C) 20 D) 32 4 / 30 Agar x,y sonlar (x+5)2+(y-12)2=142 tenglikni qanoatlantirsa, x2+y2 ifodaning eng kichik qiymatini toping. A) 1 B) 2 C) √2 D) √3 5 / 30 y= funktsiyaning aniqlanish sohasini toping. A) [2;∞) B) (2;∞) C) (-∞;2)v(2;∞) D) (-∞;2) 6 / 30 O’qishni bilmaydigan bola alifbening A,A,A, N,N, S- 6 ta harflarini ixtiyoriy ravishda terib chiqadi. Bunda ANANAS so’zining hosil bo’lish ehtimolini toping. A) 5/24 B) 5/720 C) 6/720 D) 1/60 7 / 30 sistemadan x+y+z ning qiymatini toping. A) -139/41 B) 140/41 C) 150/41 D) 139/41 8 / 30 Rombning yuzi 96 ga, dioganallaridan biri 16 ga teng. Romb tomonini toping. A) 10 B) 9 C) 12 D) 11 9 / 30 Sin9x =4sin3x tenglamani yeching A) πn/3, n€Ζ B) π/2+πn, n€Ζ C) πn, n€Ζ D) π/3+πn, n€Ζ 10 / 30 n ning qanday qiymatida ushbu 81 .82 .83 .….8n=51222 tenglik o’rinli bo’ladi? A) 12 B) 14 C) 11 D) 10 11 / 30 ABCD kvadrat ichidan olingan O nuqtadan A, B, C uchlarigacha bo’lgan masofalar mos ravishda 3, 4, 5 ga teng bo’lsa, u holda OD kesma uzunligini toping. A) 6 B) 3 C) √37 D) √32 12 / 30 a ning qanday qiymatlarida ushbu 7x-a-13=(a-5)(x+7) tenglama yagona yechimga ega A) a=12 B) a ning bunday qiymati yo’q C) a≠5 D) a≠12 13 / 30 Muntazam uchburchakli piramidaning yon qirrasi asos tekisligi bilan 45o li burchak tashkil etgan bo‘lsa, u holda piramidaning yon sirti yuzining uning asosi yuziga nisbatini toping. A) 2√5 B) 3√3 C) 2√3 D) 4 14 / 30 Bog’bon uch kun davomida o’nta daraxt ko’chati o’tqazishi lozim. Agar bog’bon bir kunda eng kamida bitta ko’chat o’tqazadigan bo’lsa, u shu ishni kunlar bo’yicha necha xil usul bilan taqsimlashi mumkin? A) 25 B) 32 C) 30 D) 36 15 / 30 To’g’ri to’rtburchakning perimetri 50 ga teng. Bir tomoni boshqa tomonidan 5 ga ko’p. To’g’ri to’rtburchakning yuzini toping. A) 150 B) 225 C) 50 D) 60 16 / 30 Radiusi 1 ga teng aylana uchta yoyga bo`lingan. Ularga mos markaziy burchaklar 1, 2 va 6 sonlariga proporsional. Yoylardan eng kattasining uzunligini toping. A) 2π/3 B) 3π/2 C) 3π/4 D) 4π/3 17 / 30 sistemada xy ning qiymatini toping. A) 64 B) 60 C) 80 D) 75 18 / 30 x2-5|x|-6=0 tenglama ildizini toping A) ±6 B) ±;±6 C) -1;-6 D) -1;6 19 / 30 Ifodani soddalashtiring. [ln(ln x)-ln(loge10)].log10e A) lg(ln x) B) lg(lg x) C) ln(ln x) D) ln(lg x) 20 / 30 A) 1 B) 0 C) √6 D) 2 21 / 30 Agar funksiya berilgan bo’lsa, u holda M=ning qiymatini toping. A) e⁴⁹⁵⁰ B) e⁻⁵⁰⁵⁰ C) e⁵⁰⁵⁰ D) e⁻⁴⁹⁵⁰ 22 / 30 Musobaqada 5 ta ishtirokchidan 3 tasiga 1, 2, 3-o’rinlarni necha xil usulda berish mumkin? A) 47 B) 18 C) 120 D) 60 23 / 30 To‘g‘ri to‘rtburchakning eni 25% ga orttirildi, bo‘yi esa 25% ga kamaytirildi. Natijada uning yuzi qanday o‘zgardi? A) o‘zgarmaydi B) 2,5% ga ortadi C) 6,25% ga kamayadi D) 6,25% ga ortadi 24 / 30 Radiuslari orasidagi burchagi 36o va radiusi 5 ga teng bo`lgan sektor yoyining uzunligini toping. A) 2π B) π/2 C) 2π/3 D) π 25 / 30 Tenglamaning ildizlari yig`indisini toping. A) 4 B) 3 C) 5 D) 6 26 / 30 To’g’ri burchakli uchburchakning gipotenuzasi 13 ga, katetlaridan biri 52 ga teng. Gipotenuzaga tushirilgan balandlik uzunligini toping A) 4 B) 6 C) 5 D) 7 27 / 30 Ostki asosining yuzi 32π va ustki asosining yuzi 18π ga teng bo‘lgan kesik konus berilgan. Agar kesik konusga shar ichki chizilgan bo‘lsa, u holda sharning sirtini toping. A) 56π B) 96π C) 72π D) 100π 28 / 30 To’rtburchakli muntazam piramidaning yon qirrasidagi ikki yoqli burchak 120 ga teng. Diagonal kesimining yuzasi S ga teng bo’lsa, uning yon sirtini toping. A) 0,5S B) 3S C) 4S D) 2S 29 / 30 Tomoni 25 ga diagonallaridan biri 4 ga teng bo’lgan rombning yuzini toping. A) 32 B) 16 C) 8√5 D) 24√5 30 / 30 Parallelogrammning yuzi 213 ga, tomonlaridan biri 7 ga va o’tkir burchagi 600 ga teng bo’lsa, ikkinchi tomonini toping A) 8 B) 5 C) 4 D) 6 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
