Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 121 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 1 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 a=sin 1; b=sin 2; c=sin 3; d=sin 4 va e=sin 5 sonlarni kamayish tartibida joylashtiring. A) b>a>c>d>e B) e>b>a>d>c C) a>b>c>d>e D) b>c>a>d>e 2 / 30 Ostki asosining yuzi 32π va ustki asosining yuzi 18π ga teng bo‘lgan kesik konus berilgan. Agar kesik konusga shar ichki chizilgan bo‘lsa, u holda sharning sirtini toping. A) 56π B) 72π C) 96π D) 100π 3 / 30 sistema a ning qanday qiymatida cheksiz ko’p yechimga ega? A) (-∞;6) B) (2;∞) C) (-∞;6])v[6;∞) D) 6 4 / 30 Bog’bon uch kun davomida o’nta daraxt ko’chati o’tqazishi lozim. Agar bog’bon bir kunda eng kamida bitta ko’chat o’tqazadigan bo’lsa, u shu ishni kunlar bo’yicha necha xil usul bilan taqsimlashi mumkin? A) 36 B) 32 C) 25 D) 30 5 / 30 sin2x-cos2x=1 tenglama [-π; 2π] oraliqda nechta ildizga ega? A) 6 B) 9 C) 10 D) 7 6 / 30 Tengsizlikni yeching. A) to'g'ri javob yo'q B) (-1/³ √2 ;0) C) 0 D) (0;+∞) 7 / 30 Tengsizlik nechta butun yechimga ega? A) 1 B) 3 C) 4 D) cheksiz ko’p 8 / 30 Agar va b-a=4 bo’lsa, a+b ni toping. A) 3 B) 4 C) 2 D) 3,5 9 / 30 a ning qanday qiymatlarida ushbu 7x-a-13=(a-5)(x+7) tenglama yagona yechimga ega A) a≠5 B) a=12 C) a≠12 D) a ning bunday qiymati yo’q 10 / 30 x(t)=t2+6t+5 qonuniyat bo’yicha harakatlanayotgan moddiy nuqta harakat boshlangandan necha sekund o’tgach boshlang’ich nuqtaga nisbatan 77 metr masofaga siljiydi? A) 10 B) 6 C) 8 D) 7 11 / 30 y= funksiyaning aniqlanish sohasini toping A) (0,2) B) (-∞;0])v[2;∞) C) (2;∞) D) (-∞;0)v(2;∞) 12 / 30 Perimetri 60 ga teng bo’lgan parallelogrammning tomonlari nisbati 2:3 ga, o’tkir burchagi esa 300 ga teng. Parallelogrammning yuzini toping. A) 48√3 B) 52√3 C) 54 D) 108 13 / 30 To’g’ri burchakli uchburchakning yuzi 24 ga, katetlaridan biri 6 ga teng bo’lsa, gipotenuzasini toping A) 11 B) 10 C) 12 D) √46 14 / 30 sistemadan x+y+z ning qiymatini toping. A) 140/41 B) -139/41 C) 139/41 D) 150/41 15 / 30 A) 2 B) 5 C) 3 D) 1 16 / 30 ifodaning qiymatini toping. A) 0,5 B) -2 C) 0 D) -0,5 17 / 30 Quyidagilardan qaysi biri barcha lar uchun ma’noga ega (aniqlangan)? A) ⁴ᴷ⁺³√-√2k+1 B) ²ᴷ⁺⁴v2k+1/k²+1 C) (512-1/2⁻⁹)° D) 4k+1/1/8:7-1/56 18 / 30 Agar bank qo`yilgan pulga 40% yillik foyda bersa, qo`yilgan 5000 so`m pul bir yildan keyin qancha bo`ladi ? A) 7200 B) 7000 C) 6200 D) 6900 19 / 30 Bir vaqtning o’zida 9,13, . . . ,405 va 15,21, . . . ,255 ketma–ketliklarning hadlari bo’lgan sonlarning eng kattasi va eng kichigining ayirmasini toping A) 231 B) 228 C) 150 D) 147 20 / 30 bo’lsa ni toping. Bunda funksiya f(x) ga teskari funksiya. A) -10 B) -14 C) -12 D) -4 21 / 30 Tenglamani yeching. (x+2)+(x+4)+(x+6)+…+(x+100)=2800 A) 3 B) 7 C) 4 D) 5 22 / 30 sistemada xy ning qiymatini toping. A) 64 B) 75 C) 80 D) 60 23 / 30 Tomoni 12 ga teng bo`lgan teng tomonli uchburchakga ichki chizilgan aylana uzunligini toping. A) 4√3π B) 2√3π C) 3π D) 12π 24 / 30 (-3;4) nuqtaga absissa, ordinata o’qlariga va koordinata boshiga nisbatan simmetrik bo’lgan nuqtalarni tutashtirishdan hosil bo’lgan uchburchakning eng kata tomonini toping. A) 24 B) 10 C) 14 D) 12 25 / 30 Ifodani soddalashtiring. 2 cos55o.cos40o.sin55o+cos110o.sin40o A) 0 B) 2 C) 0,5 D) 1 26 / 30 funksiya uchun quyidagi mulohazalardan qaysi biri o’rinli? A) juft ham emas, toq ham emas funksiya B) toq funksiya C) bunday funksiya mavjud emas D) juft funksiya 27 / 30 Teng yonli uchburchakning tomonlari 5, 5 va 6 ga teng. Bu uchburchakning bissektiritsalari va medianalari kesishgan nuqtalar A) 1 B) 1/2 C) 1/6 D) 1,2 28 / 30 Ushbu funksiyaning boshlang’ich funksiyasini toping. A) ln(|x+4+|x-1|)+c B) ln|x-1/x+4|+c C) ln|x+4/x-1|+c D) ln(|x+4*|x-1|)+c 29 / 30 Tomoni 2 ga teng kvadratga tashqi chizilgan aylana uzunligini toping. A) 3π B) 2π/3 C) 2π D) 4π 30 / 30 Hisoblang A) 2 B) 1/2 C) √3 D) √3/2 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
