Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 154 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 Konsert zalining birinchi qatorida 40 ta o’rindiq bor. Har bir keyingi qatordagi o’rindiqlar soni oldingi qatordan 4 ga ko’p. Agar konsert zalida jami 40 ta qator bo’lsa, u holda shu zaldagi barcha o’rindiqlar sonini toping. A) 4680 B) 4760 C) 4716 D) 4720 2 / 30 Soddalashtiring. (0<m<7) A) 7-2m B) m C) 2m-7 D) 7 3 / 30 y=cos(2sinx) funksiyaning qiymatlar sohasini toping. A) [0;1] B) [cos2;1] C) [-1;1] D) [0;cos2] 4 / 30 Agar f(x)=4x3-6x2-2x+3x .log3e bo’lsa, u holda ni toping. A) e B) 3e C) 1 D) √2e 5 / 30 Hisoblang A) -1 B) 1 C) 0 D) 2 6 / 30 Ifodani soddalashtiring. 2 cos55o.cos40o.sin55o+cos110o.sin40o A) 0,5 B) 0 C) 2 D) 1 7 / 30 sonning oxirgi raqamini toping. A) 4 B) 8 C) 6 D) 2 8 / 30 integralning qiymatini toping. A) 0 B) -π/2 C) π/4 D) π/2 9 / 30 Ushbu funksiyaning boshlang’ich funksiyasini toping. A) ln(|x+4*|x-1|)+c B) ln|x+4/x-1|+c C) ln(|x+4+|x-1|)+c D) ln|x-1/x+4|+c 10 / 30 Agar f(x)=ax3-5x2+b va bo’lsa, a ni toping. A) 0 B) 3 C) 1 D) 2 11 / 30 sistema yagona yechimga ega bo’ladigan a ning barcha qiymatlari to’plamini toping. A) {-1;2} B) {-1;3} C) {2;4} D) {1;2} 12 / 30 tenglamalar sistemasini yeching A) (4;–4) B) (4;4) C) (-4;-4) D) (-4;4) 13 / 30 Radiusi 1 ga teng aylana uchta yoyga bo`lingan. Ularga mos markaziy burchaklar 1, 2 va 6 sonlariga proporsional. Yoylardan eng kattasining uzunligini toping. A) 3π/2 B) 2π/3 C) 4π/3 D) 3π/4 14 / 30 To’g’ri burchakli uchburchakning gipotenuzasi 5 ga, bir katetining gipotenuzadagi proyeksiyasi 1,6 ga teng. Ikkinchi katetning kvadratini toping. A) 16 B) 14 C) 18 D) 17 15 / 30 m ning qanday eng katta butun qiymatida y=2x-mx-5+m funksiyaning grafigi 1,3,4 –choraklarda yotadi? A) 5 B) 2 C) 1 D) 3 16 / 30 Tomoni 25 ga diagonallaridan biri 4 ga teng bo’lgan rombning yuzini toping. A) 32 B) 24√5 C) 16 D) 8√5 17 / 30 Hisoblang A) 3√3 B) √3 C) 1 D) 2√3 18 / 30 Agar sinx+cosx=a bo’lsa, ning qiymatini toping. A) 1/3 B) 1/2 C) 2/5 D) -1/2 19 / 30 Perimetri 60 ga teng bo’lgan parallelogrammning tomonlari nisbati 2:3 ga, o’tkir burchagi esa 300 ga teng. Parallelogrammning yuzini toping. A) 54 B) 52√3 C) 108 D) 48√3 20 / 30 Anvar tub son o’yladi va o’ylagan sonini 5 ga ko’paytirib, 8 ni ayirgan edi, yana tub son hosil bo’ldi. Anvar qanday son o’ylagan? A) 374389 B) aniqlab bo’lmaydi C) 412967 D) 2 21 / 30 a ning 7x-a-13=(a-5)(x+7) tenglama yechimga ega bo’lmaydigan qiymatining natural bo’luvchilar sonini toping. A) 12 B) 6 C) 4 D) 8 22 / 30 Tomoni 6 ga teng bo`lgan teng tomonli uchburchakga tashqi chizilgan doiraning yuzini toping. A) 12π B) 7 π C) 6 π D) 10 π 23 / 30 To’rtburchakli muntazam piramidaning yon qirrasidagi ikki yoqli burchak 120 ga teng. Diagonal kesimining yuzasi S ga teng bo’lsa, uning yon sirtini toping. A) 0,5S B) 4S C) 2S D) 3S 24 / 30 Muntazam uchburchakli piramidaning yon qirrasi asos tekisligi bilan 45o li burchak tashkil etgan bo‘lsa, u holda piramidaning yon sirti yuzining uning asosi yuziga nisbatini toping. A) 3√3 B) 4 C) 2√3 D) 2√5 25 / 30 Musobaqada 5 ta ishtirokchidan 3 tasiga 1, 2, 3-o’rinlarni necha xil usulda berish mumkin? A) 60 B) 47 C) 18 D) 120 26 / 30 Teng yonli trpetsiyaning asoslari 15 va 25 ga balandligi esa 15 ga teng trapetsiyaning dioganalini toping A) 25 B) 30 C) 20 D) 28 27 / 30 Uchburchakning balandligi 12 ga teng bo’lib, u asosni 5:16 nidbatda bo’ladi. Agar asosning uzunligi 21 ga teng bo’lsa, uchburchakning perimetrini toping A) 52 B) 108 C) 48 D) 54 28 / 30 Bog’bon uch kun davomida o’nta daraxt ko’chati o’tqazishi lozim. Agar bog’bon bir kunda eng kamida bitta ko’chat o’tqazadigan bo’lsa, u shu ishni kunlar bo’yicha necha xil usul bilan taqsimlashi mumkin? A) 36 B) 25 C) 32 D) 30 29 / 30 AA1A2A3A4A5A6 muntazam oltiburchakli piramidaning hajmi ga va balandligi 2 ga teng bo‘lsa, u holda AA2A6 kesim yuzini toping. A) 3 B) √15 C) 2 D) √5 30 / 30 Fazoda (1;2;3) nuqtalardan o’tuvchi to’g’ri chiziq tenglamasini tuzing. A) -x-y+z=0 B) 2x+3y+z=0 C) x-1/2=y-2/3=z-3/4 D) x=y/3=z/2 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
