Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 192 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 Ikki burchagi graduslari yig’indisi uchinchi burchagi gradusiga teng bo’lgan uchburchak qanday uchburchak deyiladi? A) teng tomonli uchburchak B) o’tmas burchakli uchburchak C) o’tkir burchakli uchburchak D) to’gri burchakli uchburchak 2 / 30 |x2-5x-14|+20≥5|x+2|+4|x-7| tengsizlikni yeching. A) [1;6] B) (-∞;-6]v{2}v[12;∞) C) [2;4]v{2}v[3;∞) D) [-2;4]v{6} 3 / 30 funksiya uchun quyidagi mulohazalardan qaysi biri o’rinli? A) toq funksiya B) juft ham emas, toq ham emas funksiya C) bunday funksiya mavjud emas D) juft funksiya 4 / 30 To’g’ri to’rtburchakning perimetri 50 ga teng. Bir tomoni boshqa tomonidan 5 ga ko’p. To’g’ri to’rtburchakning yuzini toping. A) 225 B) 50 C) 60 D) 150 5 / 30 Soddalashtiring. A) 2018a/a+1 B) a+1 C) 2018 D) 2019 6 / 30 Ushbu funksiyaning boshlang’ich funksiyasini toping. A) ln|x-1/x+4|+c B) ln(|x+4*|x-1|)+c C) ln(|x+4+|x-1|)+c D) ln|x+4/x-1|+c 7 / 30 sistema a ning qanday qiymatida cheksiz ko’p yechimga ega? A) (-∞;6) B) 6 C) (2;∞) D) (-∞;6])v[6;∞) 8 / 30 Agar f(x)=ax3-5x2+b va bo’lsa, a ni toping. A) 2 B) 1 C) 0 D) 3 9 / 30 tenglamalar sistemasini yeching A) (4;–3) B) (3;–4) C) (4;3) D) (–4;3) 10 / 30 A) 1 B) 2 C) √6 D) 0 11 / 30 Tomoni 6 ga teng bo`lgan teng tomonli uchburchakga tashqi chizilgan doiraning yuzini toping. A) 6 π B) 10 π C) 12π D) 7 π 12 / 30 Tenglamani yeching. (x+2)+(x+4)+(x+6)+…+(x+100)=2800 A) 4 B) 5 C) 7 D) 3 13 / 30 a ning 7x-a-13=(a-5)(x+7) tenglama yechimga ega bo’lmaydigan qiymatining natural bo’luvchilar sonini toping. A) 4 B) 12 C) 6 D) 8 14 / 30 Tengsizlik nechta butun yechimga ega? A) 4 B) 1 C) cheksiz ko’p D) 3 15 / 30 Tenglamaning ildizlari yig`indisini toping. A) 3 B) 5 C) 6 D) 4 16 / 30 Markazi nuqtada bo‘lgan aylanaga va urinmalar o‘tkazilgan bo’lib, va nuqtalar urinish nuqtalari bo’lsin. Aylanadagi Q nuqtadan o‘tkazilgan uchinchi urinma va kesmalarni X va Y nuqtalarda kesib o‘tadi. Agar uchburchakka ichki chizilgan aylana markazi bo‘lsa, u holda burchakni toping. A) 90° B) 30° C) 72° D) 60° 17 / 30 To’g’ri burchakli uchburchakning yuzi 24 ga, katetlaridan biri 6 ga teng bo’lsa, gipotenuzasini toping A) √46 B) 12 C) 11 D) 10 18 / 30 x(t)=t2+7t-6 qonuniyat bo’yicha harakatlanayotgan moddiy nuqtaning tezligi harakat boshlangandan necha sekund o’tgach 87 m/s ga teng bo’ladi? A) 54 B) 50 C) 36 D) 40 19 / 30 A(2;-2,5) nuqtadan y= - 4x parabolagacha bo’lgan eng qisqa masofani toping. A) √3/2 B) √5/2 C) 1 D) 1,5 20 / 30 Ostki asosining yuzi 20π va ustki asosining yuzi 10π ga teng bo‘lgan kesik konus berilgan. Agar kesik konusga shar ichki chizilgan bo‘lsa, u holda kesik konus hajmining shar hajmiga nisbatini toping. A) 2√2/3 B) 3√2+2/4 C) 5√3+3/3 D) 3√3+1/5 21 / 30 tenglamani yeching. A) 2019 B) 2018 C) 0 D) 2017 22 / 30 Agar geometrik progressiyaning ketma–ket dastlabki uchta hadining yig’indisi 62 ga, ularning o’nli logarifmlari yig’indisi 3 ga teng bo’lsa, shu geometrik progressiyaning birinchi hadini toping. A) 10 yoki 50 B) 2 yoki 50 C) 50 D) 10 23 / 30 Agar f(x)=sin2x va g(x)=cos2x bo’lsa, u holda f(g(x)) funksiyaning hosilasini toping. A) 4sin2x*cos(cos2x) B) -4sin2x*cos(2cos2x) C) 4sin2x*cos(2cos2x) D) -4sin2x*cos(cos2x) 24 / 30 sistemadan x+y+z ning qiymatini toping. A) 150/41 B) -139/41 C) 140/41 D) 139/41 25 / 30 Sin9x =4sin3x tenglamani yeching A) πn/3, n€Ζ B) π/2+πn, n€Ζ C) π/3+πn, n€Ζ D) πn, n€Ζ 26 / 30 Perimetri 60 ga teng bo’lgan parallelogrammning tomonlari nisbati 2:3 ga, o’tkir burchagi esa 300 ga teng. Parallelogrammning yuzini toping. A) 54 B) 52√3 C) 108 D) 48√3 27 / 30 sin2x-cos2x=1 tenglama [-π; 2π] oraliqda nechta ildizga ega? A) 9 B) 10 C) 7 D) 6 28 / 30 ifodaning qiymatini toping. A) -0,5 B) 0 C) -2 D) 0,5 29 / 30 Teng yonli uchburchakning tomonlari 5, 5 va 6 ga teng. Bu uchburchakning bissektiritsalari va medianalari kesishgan nuqtalar A) 1/2 B) 1/6 C) 1 D) 1,2 30 / 30 Ushbu arifmetik progressiyaning manfiy hadlari yig’indisini toping. A) -0,25 B) -0,5 C) -0,75 D) -1 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
