Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 192 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 Markazi nuqtada bo‘lgan aylanaga va urinmalar o‘tkazilgan bo’lib, va nuqtalar urinish nuqtalari bo’lsin. Aylanadagi Q nuqtadan o‘tkazilgan uchinchi urinma va kesmalarni X va Y nuqtalarda kesib o‘tadi. Agar uchburchakka ichki chizilgan aylana markazi bo‘lsa, u holda burchakni toping. A) 60° B) 72° C) 90° D) 30° 2 / 30 A(2;-2,5) nuqtadan y= - 4x parabolagacha bo’lgan eng qisqa masofani toping. A) √5/2 B) 1 C) 1,5 D) √3/2 3 / 30 y= funksiyaning aniqlanish sohasini toping A) (-∞;0)v(2;∞) B) (-∞;0])v[2;∞) C) (2;∞) D) (0,2) 4 / 30 Tenglamani yeching. (x+2)+(x+4)+(x+6)+…+(x+100)=2800 A) 3 B) 5 C) 4 D) 7 5 / 30 Bekzodda 50 so’m va Sobirda 70 so’m pul bor edi. Anvar Bekzodga o’z pulining 10 foizini bergandan so’ng, Bekzod Sobirga pulining yarmini berdi. So’ng Sobir Anvarga pulining 10 foizini berdi. Anvar o’zidagi pullarini hisoblab, pullari dastlabki holdagi puli bilan teng ekanligini bildi. Anvarda qancha pul bo’lgan? A) 100 B) 127 C) 375 D) 400 6 / 30 Ushbu arifmetik progressiyaning manfiy hadlari yig’indisini toping. A) -0,75 B) -1 C) -0,25 D) -0,5 7 / 30 Musobaqada 5 ta ishtirokchidan 3 tasiga 1, 2, 3-o’rinlarni necha xil usulda berish mumkin? A) 18 B) 60 C) 47 D) 120 8 / 30 Agar funksiya berilgan bo’lsa, u holda M=ning qiymatini toping. A) e⁵⁰⁵⁰ B) e⁻⁴⁹⁵⁰ C) e⁻⁵⁰⁵⁰ D) e⁴⁹⁵⁰ 9 / 30 sistemada xy ning qiymatini toping. A) 60 B) 80 C) 64 D) 75 10 / 30 “Tutgan balig‘ining og‘irligi qancha?” degan savolga baliqchi: “Baliqning dumi 3 kg, boshi uning dumi hamda tanasi yarmining og‘irligiga teng, tanasi esa boshi va dumining og‘irligiga teng”, deb javob berdi. Baliqning og‘irligini (kg) toping. A) 18 B) 6 C) 3 D) 12 11 / 30 ifodaning qiymatini toping. A) -0,5 B) 0,5 C) 0 D) -2 12 / 30 Hisoblang. 11+192+1993+19994+199995+1999996+19999997+199999998+1999999999 A) 222222222222 B) 22222222220 C) 2222222175 D) 222220175 13 / 30 Agar x,y sonlar (x+5)2+(y-12)2=142 tenglikni qanoatlantirsa, x2+y2 ifodaning eng kichik qiymatini toping. A) 1 B) √2 C) √3 D) 2 14 / 30 y=cos(2sinx) funksiyaning qiymatlar sohasini toping. A) [0;cos2] B) [-1;1] C) [0;1] D) [cos2;1] 15 / 30 Ostki asosining yuzi 20π va ustki asosining yuzi 10π ga teng bo‘lgan kesik konus berilgan. Agar kesik konusga shar ichki chizilgan bo‘lsa, u holda kesik konus hajmining shar hajmiga nisbatini toping. A) 3√2+2/4 B) 3√3+1/5 C) 5√3+3/3 D) 2√2/3 16 / 30 |x2-5x-14|+20≥5|x+2|+4|x-7| tengsizlikni yeching. A) [-2;4]v{6} B) [2;4]v{2}v[3;∞) C) [1;6] D) (-∞;-6]v{2}v[12;∞) 17 / 30 bo’lsa, ni x orqali ifodalang. A) 25/x B) 2-x C) 2/x D) x/25 18 / 30 To’g’ri burchakli uchburchakning gipotenuzasi 5 ga, bir katetining gipotenuzadagi proyeksiyasi 1,6 ga teng. Ikkinchi katetning kvadratini toping. A) 17 B) 14 C) 18 D) 16 19 / 30 Agar arctga+ arctgb + arctgc= bo’lsa, a+b+c ni toping. A) ab B) ab/c C) abc D) 1 20 / 30 Ikki burchagi graduslari yig’indisi uchinchi burchagi gradusidan katta bo’lgan uchburchaklar sonini toping. A) cheksiz ko’p B) 2019 C) 1 D) 0 21 / 30 Parallelogrammning tomonlari nisbati 3:5 kabi. Agar parallelogrmmning perimetri 48 ga burchaklaridan biri 1200 ga teng bo’lsa, uning yuzini toping. A) 67,5√3 B) 48√3 C) 135√3/4 D) 67,5 22 / 30 a(x+2)=2x+1 tenglama a ning qanday qiymatida yechimga ega emas? A) (-∞;2) B) (2;∞) C) (-∞;2)v(2;∞) D) (∞;∞) 23 / 30 Bog’bon uch kun davomida o’nta daraxt ko’chati o’tqazishi lozim. Agar bog’bon bir kunda eng kamida bitta ko’chat o’tqazadigan bo’lsa, u shu ishni kunlar bo’yicha necha xil usul bilan taqsimlashi mumkin? A) 30 B) 25 C) 32 D) 36 24 / 30 a ning qanday qiymatlarida ushbu 7x-a-13=(a-5)(x+7) tenglama yagona yechimga ega A) a ning bunday qiymati yo’q B) a≠5 C) a≠12 D) a=12 25 / 30 Hisoblang: A) 1 B) 3 C) -1 D) 2 26 / 30 Tengsizlikni yeching. A) (-3;2) B) (2;4) C) (-4;2)v(2;3) D) (-3;2)v(2;4) 27 / 30 A) 2 B) 1 C) 5 D) 3 28 / 30 Tenglamaning ildizlari yig’indisi va ko’paytmasining yig’indisini toping. |x+1|.|x-4|=5 A) -6 B) -3 C) 9 D) 6 29 / 30 To’g’ri burchakli uchburchakning yuzi 24 ga, katetlaridan biri 6 ga teng bo’lsa, gipotenuzasini toping A) 12 B) 10 C) 11 D) √46 30 / 30 Fazoda (1;2;3) nuqtalardan o’tuvchi to’g’ri chiziq tenglamasini tuzing. A) -x-y+z=0 B) 2x+3y+z=0 C) x=y/3=z/2 D) x-1/2=y-2/3=z-3/4 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
