Barcha fanlardan online testlar

Matematika abituriyent testi №1

InfoMaster

Aprel 5, 2022

121 Ko'rishlar 1 izoh

SaqlashSaqlanganOlib tashlandi 0

Tomonidan yaratilgan InfoMaster

Matematika abituriyentlar uchun №1

1 / 30

A) 1

B) 0

C) 2

D) √6

2 / 30

Bankda qo`yilgan pul bir yildan kegin foydasi bilan 2600 so`m bo`ldi; Agar bank yillik 30% foyda to`lasa, boshida qancha pul qo`yilgan bo`ladi ?

A) 2200

B) 1900

C) 2100

D) 2000

3 / 30

sonning oxirgi raqamini toping.

A) 6

B) 2

C) 4

D) 8

4 / 30

Radiuslari orasidagi burchagi 36^o va radiusi 5 ga teng bo`lgan sektor yoyining uzunligini toping.

A) π

B) 2π

C) π/2

D) 2π/3

5 / 30

Agar arctga+ arctgb + arctgc= bo’lsa, a+b+c ni toping.

A) ab

B) ab/c

C) abc

D) 1

6 / 30

A(2;-2,5) nuqtadan y= - 4x parabolagacha bo’lgan eng qisqa masofani toping.

A) 1

B) 1,5

C) √5/2

D) √3/2

7 / 30

Quyidagi 2x-y+3z=2018 va x+5y+z=2019 tekisliklarning holatini aniqlang.

A) o’zaro parallel

B) ayqash

C) aniqlab bo’lmaydi

D) o’zaro perpendikulyar

8 / 30

Tenglamani yeching.

|x²-11x+10|=x²-11x+10

A) 1; 10

B) (-∞;1]v[10;∞)

C) [10;∞)

D) (-∞;1]

9 / 30

Tenglamaning ildizlari yig`indisini toping.

A) 5

B) 4

C) 3

D) 6

10 / 30

Agar x,y sonlar (x+5)²+(y-12)²=14² tenglikni qanoatlantirsa, x²+y² ifodaning eng kichik qiymatini toping.

A) 1

B) 2

C) √3

D) √2

11 / 30

To’g’ri burchakli uchburchakning yuzi 24 ga, katetlaridan biri 6 ga teng bo’lsa, gipotenuzasini toping

A) √46

B) 12

C) 11

D) 10

12 / 30

Tengsizlikni yeching.

A) (2;4)

B) (-3;2)

C) (-3;2)v(2;4)

D) (-4;2)v(2;3)

13 / 30

Hisoblang

A) 1/2

B) √3

C) 2

D) √3/2

14 / 30

Ikki burchagi graduslari yig’indisi uchinchi burchagi gradusidan katta bo’lgan uchburchaklar sonini toping.

A) 0

B) 2019

C) 1

D) cheksiz ko’p

15 / 30

Ushbu (y⁶+y³+1)(y³+1)(y³-1)-y⁶+y³+1 ifodani soddalashtish natijasida ko’phad hosil qilindi. Uning nechta hadi bor?

A) 2

B) 3

C) 4

D) 1

16 / 30

Soddalashtiring.

A) 2018

B) a+1

C) 2019

D) 2018a/a+1

17 / 30

y= funktsiyaning aniqlanish sohasini toping.

A) (-∞;2)v(2;∞)

B) (2;∞)

C) [2;∞)

D) (-∞;2)

18 / 30

Teng yonli trpetsiyaning asoslari 15 va 25 ga balandligi esa 15 ga teng trapetsiyaning dioganalini toping

A) 28

B) 25

C) 30

D) 20

19 / 30

funktsiyaning aniqlanish sohasini toping.

A) (-∞;1)v(2;∞)

B) (1;2)

C) (-∞;1]v[2;∞)

D) [1;2]

20 / 30

Tengsizlik nechta butun yechimga ega?

A) 3

B) cheksiz ko’p

C) 4

D) 1

21 / 30

Radiusi 25 bo’lgan doirada 48 ga teng vatar o’tkazilgan. Doira markazidan shu vatargacha masofani toping.

A) 10

B) 9

C) 7

D) 8

22 / 30

To’rtburchakli muntazam piramidaning yon qirrasidagi ikki yoqli burchak 120 ga teng. Diagonal kesimining yuzasi S ga teng bo’lsa, uning yon sirtini toping.

A) 0,5S

B) 3S

C) 2S

D) 4S

23 / 30

To’g’ri to’rtburchakning perimetri 50 ga teng. Bir tomoni boshqa tomonidan 5 ga ko’p. To’g’ri to’rtburchakning yuzini toping.

A) 225

B) 60

C) 150

D) 50

24 / 30

Ushbu arifmetik progressiyaning manfiy hadlari yig’indisini toping.

A) -0,5

B) -1

C) -0,75

D) -0,25

25 / 30

(-3;4) nuqtaga absissa, ordinata o’qlariga va koordinata boshiga nisbatan simmetrik bo’lgan nuqtalarni tutashtirishdan hosil bo’lgan uchburchakning eng kata tomonini toping.

A) 24

B) 10

C) 12

D) 14

26 / 30

To’rtburchakning uchi M (0, 4) ; N(-4,0) ; P(-3;2) uchlari berilgan. Agar bo’lsa, Q uchining koordinatalarini toping.

A) (-7;-1)

B) (7; 1)

C) (-7; 1)

D) (4; -3)

27 / 30

y=cos(2sinx) funksiyaning qiymatlar sohasini toping.

A) [cos2;1]

B) [-1;1]

C) [0;1]

D) [0;cos2]

28 / 30

ABCD to’gri to’rtburchak ichidan olingan O nuqtadan A, B, C, D uchlarigacha bo’lgan masofalar mos ravishda 3, 4, 5, 6 ga teng bo’lsa, u holda AB tomon uzunligini toping.

A) bunday to’gri to’rtburchak mavjud emas

B) √7

C) 2

D) √37

29 / 30

Agar geometrik progressiyaning ketma–ket dastlabki uchta hadining yig’indisi 62 ga, ularning o’nli logarifmlari yig’indisi 3 ga teng bo’lsa, shu geometrik progressiyaning birinchi hadini toping.

A) 10

B) 2 yoki 50

C) 10 yoki 50

D) 50

30 / 30

ifodaning qiymatini toping.