Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 121 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 1 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 Radiuslari orasidagi burchagi 36o va radiusi 5 ga teng bo`lgan sektor yoyining uzunligini toping. A) 2π/3 B) 2π C) π D) π/2 2 / 30 Agar x,y sonlar (x+5)2+(y-12)2=142 tenglikni qanoatlantirsa, x2+y2 ifodaning eng kichik qiymatini toping. A) √3 B) 1 C) 2 D) √2 3 / 30 Tenglamani yeching. (x+2)+(x+4)+(x+6)+…+(x+100)=2800 A) 5 B) 4 C) 3 D) 7 4 / 30 Anvar tub son o’yladi va o’ylagan sonini 5 ga ko’paytirib, 8 ni ayirgan edi, yana tub son hosil bo’ldi. Anvar qanday son o’ylagan? A) 374389 B) 412967 C) 2 D) aniqlab bo’lmaydi 5 / 30 Agar bank qo’yilgan pulga 40% yillik bersa, qo’yilgan 4500 so’m pul bir yildan so’ng qancha bo’ladi? A) 6200 B) 6000 C) 6100 D) 6300 6 / 30 Soddalashtiring. (0<m<7) A) 7 B) 2m-7 C) 7-2m D) m 7 / 30 ABCD kvadrat ichidan olingan O nuqtadan A, B, C uchlarigacha bo’lgan masofalar mos ravishda 3, 4, 5 ga teng bo’lsa, u holda OD kesma uzunligini toping. A) √32 B) √37 C) 3 D) 6 8 / 30 Soat 3:37 bo’lganda minut va soat millari orasidagi burchakni toping. A) 113,5° B) 112,5° C) 100° D) 113° 9 / 30 Rombning balandligi 8 ga dioganallarining ko’paytmasi 80 ga teng. Rombning perimetrini toping A) 32 B) 20 C) 16 D) 24 10 / 30 Tomoni 2 ga teng kvadratga tashqi chizilgan aylana uzunligini toping. A) 2π B) 2π/3 C) 4π D) 3π 11 / 30 Muntazam uchburchakli piramidaning yon qirrasi asos tekisligi bilan 45o li burchak tashkil etgan bo‘lsa, u holda piramidaning yon sirti yuzining uning asosi yuziga nisbatini toping. A) 3√3 B) 4 C) 2√3 D) 2√5 12 / 30 To’g’ri burchakli uchburchakning gipotenuzasi 13 ga, katetlaridan biri 52 ga teng. Gipotenuzaga tushirilgan balandlik uzunligini toping A) 6 B) 4 C) 5 D) 7 13 / 30 a=sin 1; b=sin 2; c=sin 3; d=sin 4 va e=sin 5 sonlarni kamayish tartibida joylashtiring. A) a>b>c>d>e B) e>b>a>d>c C) b>a>c>d>e D) b>c>a>d>e 14 / 30 Uchburchakning balandligi 12 ga teng bo’lib, u asosni 5:16 nidbatda bo’ladi. Agar asosning uzunligi 21 ga teng bo’lsa, uchburchakning perimetrini toping A) 54 B) 52 C) 108 D) 48 15 / 30 Agar f(x)=ax3-5x2+b va bo’lsa, a ni toping. A) 0 B) 3 C) 2 D) 1 16 / 30 To’rtburchakli muntazam piramidaning yon qirrasidagi ikki yoqli burchak 120 ga teng. Diagonal kesimining yuzasi S ga teng bo’lsa, uning yon sirtini toping. A) 3S B) 4S C) 0,5S D) 2S 17 / 30 O’q kesimining diagonallari o’zaro perpendikulyar bo’lgan kesik konus yasovchisi va asos tekisligi orasidagi burchak ga teng. Agar o’q kesimining diagonali ga teng bo’lsa, kesik konus asosining yuzini toping. A) πa²/4sin²α B) πa²(1-2sinα/4sin²) C) πa²/4cos²α D) πa²(1+2cosα/4sin²) 18 / 30 Ushbu arifmetik progressiyaning manfiy hadlari yig’indisini toping. A) -0,25 B) -1 C) -0,5 D) -0,75 19 / 30 ABCD to’gri to’rtburchak ichidan olingan O nuqtadan A, B, C, D uchlarigacha bo’lgan masofalar mos ravishda 3, 4, 5, 6 ga teng bo’lsa, u holda AB tomon uzunligini toping. A) √37 B) 2 C) √7 D) bunday to’gri to’rtburchak mavjud emas 20 / 30 To’g’ri burchakli uchburchakning gipotenuzasi 5 ga, bir katetining gipotenuzadagi proyeksiyasi 1,6 ga teng. Ikkinchi katetning kvadratini toping. A) 17 B) 18 C) 14 D) 16 21 / 30 bo’lsa ni toping. Bunda funksiya f(x) ga teskari funksiya. A) -10 B) -12 C) -4 D) -14 22 / 30 Ikki burchagi graduslari yig’indisi uchinchi burchagi gradusiga teng bo’lgan uchburchak qanday uchburchak deyiladi? A) o’tmas burchakli uchburchak B) to’gri burchakli uchburchak C) o’tkir burchakli uchburchak D) teng tomonli uchburchak 23 / 30 Tomoni 12 ga teng bo`lgan teng tomonli uchburchakga ichki chizilgan aylana uzunligini toping. A) 2√3π B) 12π C) 4√3π D) 3π 24 / 30 Teng yonli uchburchakning tomonlari 5, 5 va 6 ga teng. Bu uchburchakning bissektiritsalari va medianalari kesishgan nuqtalar A) 1 B) 1/6 C) 1/2 D) 1,2 25 / 30 Parallelogrammning tomonlari nisbati 3:5 kabi. Agar parallelogrmmning perimetri 48 ga burchaklaridan biri 1200 ga teng bo’lsa, uning yuzini toping. A) 135√3/4 B) 67,5 C) 48√3 D) 67,5√3 26 / 30 y= funksiyaning aniqlanish sohasini toping A) (0,2) B) (2;∞) C) (-∞;0])v[2;∞) D) (-∞;0)v(2;∞) 27 / 30 Soddalashtiring. A) 2018 B) a+1 C) 2018a/a+1 D) 2019 28 / 30 |x2-5x-14|+20≥5|x+2|+4|x-7| tengsizlikni yeching. A) [2;4]v{2}v[3;∞) B) (-∞;-6]v{2}v[12;∞) C) [-2;4]v{6} D) [1;6] 29 / 30 y=cos(2sinx) funksiyaning qiymatlar sohasini toping. A) [-1;1] B) [cos2;1] C) [0;1] D) [0;cos2] 30 / 30 Hisoblang. 11+192+1993+19994+199995+1999996+19999997+199999998+1999999999 A) 222222222222 B) 222220175 C) 2222222175 D) 22222222220 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
