Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 148 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 sonning oxirgi raqamini toping. A) 6 B) 8 C) 2 D) 4 2 / 30 a=sin 1; b=sin 2; c=sin 3; d=sin 4 va e=sin 5 sonlarni kamayish tartibida joylashtiring. A) b>a>c>d>e B) b>c>a>d>e C) e>b>a>d>c D) a>b>c>d>e 3 / 30 Muntazam uchburchakli piramidaning yon qirrasi asos tekisligi bilan 45o li burchak tashkil etgan bo‘lsa, u holda piramidaning yon sirti yuzining uning asosi yuziga nisbatini toping. A) 2√5 B) 3√3 C) 2√3 D) 4 4 / 30 Radiusi 1 ga teng aylana uchta yoyga bo`lingan. Ularga mos markaziy burchaklar 1, 2 va 6 sonlariga proporsional. Yoylardan eng kattasining uzunligini toping. A) 4π/3 B) 2π/3 C) 3π/2 D) 3π/4 5 / 30 To‘g‘ri to‘rtburchakning eni 25% ga orttirildi, bo‘yi esa 25% ga kamaytirildi. Natijada uning yuzi qanday o‘zgardi? A) 2,5% ga ortadi B) o‘zgarmaydi C) 6,25% ga ortadi D) 6,25% ga kamayadi 6 / 30 Ikki burchagi graduslari yig’indisi uchinchi burchagi gradusidan katta bo’lgan uchburchaklar sonini toping. A) 0 B) 1 C) cheksiz ko’p D) 2019 7 / 30 To’rtburchakning uchi M (0, 4) ; N(-4,0) ; P(-3;2) uchlari berilgan. Agar bo’lsa, Q uchining koordinatalarini toping. A) (4; -3) B) (7; 1) C) (-7;-1) D) (-7; 1) 8 / 30 Teng yonli uchburchakning tomonlari 5, 5 va 6 ga teng. Bu uchburchakning bissektiritsalari va medianalari kesishgan nuqtalar A) 1,2 B) 1/6 C) 1/2 D) 1 9 / 30 Agar f(x)=ax3-5x2+b va bo’lsa, a ni toping. A) 3 B) 0 C) 1 D) 2 10 / 30 sistema yagona yechimga ega bo’ladigan a ning barcha qiymatlari to’plamini toping. A) {-1;2} B) {2;4} C) {-1;3} D) {1;2} 11 / 30 x(t)=t2+6t+5 qonuniyat bo’yicha harakatlanayotgan moddiy nuqta harakat boshlangandan necha sekund o’tgach boshlang’ich nuqtaga nisbatan 77 metr masofaga siljiydi? A) 6 B) 7 C) 10 D) 8 12 / 30 Hisoblang A) √3/2 B) 2 C) √3 D) 1/2 13 / 30 Tenglamaning nechta ildizi bor? |x+1|=|2x-1| A) 2 B) 4 C) 1 D) 3 14 / 30 Markazi nuqtada bo‘lgan aylanaga va urinmalar o‘tkazilgan bo’lib, va nuqtalar urinish nuqtalari bo’lsin. Aylanadagi Q nuqtadan o‘tkazilgan uchinchi urinma va kesmalarni X va Y nuqtalarda kesib o‘tadi. Agar uchburchakning perimetri 48 va aylana radiusi 7 ga teng bo‘lsa, u holda kesma uzunligini toping A) 15 B) 12 C) 25 D) 30 15 / 30 Perimetri 60 ga teng bo’lgan parallelogrammning tomonlari nisbati 2:3 ga, o’tkir burchagi esa 300 ga teng. Parallelogrammning yuzini toping. A) 48√3 B) 54 C) 52√3 D) 108 16 / 30 Tenglamaning ildizlari yig`indisini toping. A) 6 B) 4 C) 3 D) 5 17 / 30 ABCD to’gri to’rtburchak ichidan olingan O nuqtadan A, B, C, D uchlarigacha bo’lgan masofalar mos ravishda 3, 4, 5, 6 ga teng bo’lsa, u holda AB tomon uzunligini toping. A) √37 B) bunday to’gri to’rtburchak mavjud emas C) √7 D) 2 18 / 30 A(2;-2,5) nuqtadan y= - 4x parabolagacha bo’lgan eng qisqa masofani toping. A) 1,5 B) 1 C) √5/2 D) √3/2 19 / 30 Agar funksiya berilgan bo’lsa, u holda M=ning qiymatini toping. A) e⁻⁵⁰⁵⁰ B) e⁴⁹⁵⁰ C) e⁵⁰⁵⁰ D) e⁻⁴⁹⁵⁰ 20 / 30 sistemadan x+y ning qiymatini toping. A) -12 B) 12 C) 35/4 D) 6 21 / 30 y=cos(2sinx) funksiyaning qiymatlar sohasini toping. A) [0;cos2] B) [0;1] C) [cos2;1] D) [-1;1] 22 / 30 a(x+2)=2x+1 tenglama a ning qanday qiymatida yechimga ega emas? A) (2;∞) B) (∞;∞) C) (-∞;2)v(2;∞) D) (-∞;2) 23 / 30 Tenglamaning ildizlari yig’indisi va ko’paytmasining yig’indisini toping. |x+1|.|x-4|=5 A) 9 B) -3 C) -6 D) 6 24 / 30 To’g’ri burchakli uchburchakning yuzi 24 ga, katetlaridan biri 6 ga teng bo’lsa, gipotenuzasini toping A) 11 B) 12 C) √46 D) 10 25 / 30 Ostki asosining yuzi 32π va ustki asosining yuzi 18π ga teng bo‘lgan kesik konus berilgan. Agar kesik konusga shar ichki chizilgan bo‘lsa, u holda sharning sirtini toping. A) 100π B) 96π C) 72π D) 56π 26 / 30 Fazoda (1;2;3) nuqtalardan o’tuvchi to’g’ri chiziq tenglamasini tuzing. A) x=y/3=z/2 B) -x-y+z=0 C) x-1/2=y-2/3=z-3/4 D) 2x+3y+z=0 27 / 30 Rombning yuzi 96 ga, dioganallaridan biri 16 ga teng. Romb tomonini toping. A) 10 B) 9 C) 12 D) 11 28 / 30 Bir vaqtning o’zida 9,13, . . . ,405 va 15,21, . . . ,255 ketma–ketliklarning hadlari bo’lgan sonlarning eng kattasi va eng kichigining ayirmasini toping A) 150 B) 231 C) 147 D) 228 29 / 30 Tomoni 25 ga diagonallaridan biri 4 ga teng bo’lgan rombning yuzini toping. A) 24√5 B) 32 C) 8√5 D) 16 30 / 30 bo’lsa ni toping. Bunda funksiya f(x) ga teskari funksiya. A) -14 B) -4 C) -12 D) -10 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
