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Matematika abituriyent testi №1

InfoMaster

Aprel 5, 2022

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Matematika abituriyentlar uchun №1

1 / 30

Ostki asosining yuzi 20π va ustki asosining yuzi 10π ga teng bo‘lgan kesik konus berilgan. Agar kesik konusga shar ichki chizilgan bo‘lsa, u holda kesik konus hajmining shar hajmiga nisbatini toping.

A) 2√2/3

B) 5√3+3/3

C) 3√2+2/4

D) 3√3+1/5

2 / 30

Tengsizlik nechta butun yechimga ega?

A) 3

B) 4

C) cheksiz ko’p

D) 1

3 / 30

A) 0

B) √6

C) 2

D) 1

4 / 30

tenglamani yeching.

A) 2019

B) 2017

C) 0

D) 2018

5 / 30

Soat 3:37 bo’lganda minut va soat millari orasidagi burchakni toping.

A) 100°

B) 113,5°

C) 112,5°

D) 113°

6 / 30

Agar x,y sonlar (x+5)²+(y-12)²=14² tenglikni qanoatlantirsa, x²+y² ifodaning eng kichik qiymatini toping.

A) √2

B) 2

C) √3

D) 1

7 / 30

“Tutgan balig‘ining og‘irligi qancha?” degan savolga baliqchi: “Baliqning dumi 3 kg, boshi uning dumi hamda tanasi yarmining og‘irligiga teng, tanasi esa boshi va dumining og‘irligiga teng”, deb javob berdi. Baliqning og‘irligini (kg) toping.

A) 12

B) 6

C) 3

D) 18

8 / 30

integralning qiymatini toping.

A) 0

B) π/2

C) -π/2

D) π/4

9 / 30

To’g’ri burchakli uchburchakning gipotenuzasi 13 ga, katetlaridan biri 52 ga teng. Gipotenuzaga tushirilgan balandlik uzunligini toping

A) 7

B) 5

C) 4

D) 6

10 / 30

Tengsizlikni yeching.

A) 0

B) to'g'ri javob yo'q

C) (0;+∞)

D) (-1/³ √2 ;0)

11 / 30

Bog’bon uch kun davomida o’nta daraxt ko’chati o’tqazishi lozim. Agar bog’bon bir kunda eng kamida bitta ko’chat o’tqazadigan bo’lsa, u shu ishni kunlar bo’yicha necha xil usul bilan taqsimlashi mumkin?

A) 30

B) 25

C) 36

D) 32

12 / 30

Ostki asosining yuzi 32π va ustki asosining yuzi 18π ga teng bo‘lgan kesik konus berilgan. Agar kesik konusga shar ichki chizilgan bo‘lsa, u holda sharning sirtini toping.

A) 100π

B) 96π

C) 56π

D) 72π

13 / 30

Agar bank qo`yilgan pulga 40% yillik foyda bersa, qo`yilgan 5000 so`m pul bir yildan keyin qancha bo`ladi ?

A) 6900

B) 7200

C) 7000

D) 6200

14 / 30

Anvar tub son o’yladi va o’ylagan sonini 5 ga ko’paytirib, 8 ni ayirgan edi, yana tub son hosil bo’ldi. Anvar qanday son o’ylagan?

A) 412967

B) 374389

C) 2

D) aniqlab bo’lmaydi

15 / 30

Ifodani soddalashtiring. [ln(ln x)-ln(log_e10)]^.log₁₀e

A) lg(ln x)

B) ln(lg x)

C) lg(lg x)

D) ln(ln x)

16 / 30

Ushbu (y⁶+y³+1)(y³+1)(y³-1)-y⁶+y³+1 ifodani soddalashtish natijasida ko’phad hosil qilindi. Uning nechta hadi bor?

A) 3

B) 4

C) 1

D) 2

17 / 30

To’rtburchakning uchi M (0, 4) ; N(-4,0) ; P(-3;2) uchlari berilgan. Agar bo’lsa, Q uchining koordinatalarini toping.

A) (4; -3)

B) (-7;-1)

C) (-7; 1)

D) (7; 1)

18 / 30

Tenglamani yeching.

|x²-11x+10|=x²-11x+10

A) 1; 10

B) [10;∞)

C) (-∞;1]v[10;∞)

D) (-∞;1]

19 / 30

Quyidagi 2x-y+3z=2018 va x+5y+z=2019 tekisliklarning holatini aniqlang.

A) ayqash

B) aniqlab bo’lmaydi

C) o’zaro perpendikulyar

D) o’zaro parallel

20 / 30

To‘g‘ri to‘rtburchakning eni 25% ga orttirildi, bo‘yi esa 25% ga kamaytirildi. Natijada uning yuzi qanday o‘zgardi?

A) 6,25% ga ortadi

B) 6,25% ga kamayadi

C) 2,5% ga ortadi

D) o‘zgarmaydi

21 / 30

Tenglamaning ildizlari yig`indisini toping.

A) 6

B) 5

C) 3

D) 4

22 / 30

Agar f(x)=sin2x va g(x)=cos2x bo’lsa, u holda f(g(x)) funksiyaning hosilasini toping.

A) 4sin2x*cos(cos2x)

B) -4sin2x*cos(cos2x)

C) -4sin2x*cos(2cos2x)

D) 4sin2x*cos(2cos2x)

23 / 30

Konsert zalining birinchi qatorida 40 ta o’rindiq bor. Har bir keyingi qatordagi o’rindiqlar soni oldingi qatordan 4 ga ko’p. Agar konsert zalida jami 40 ta qator bo’lsa, u holda shu zaldagi barcha o’rindiqlar sonini toping.

A) 4716

B) 4720

C) 4680

D) 4760

24 / 30

Soddalashtiring. (0<m<7)