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Matematika abituriyent testi №1

InfoMaster

Aprel 5, 2022

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Matematika abituriyentlar uchun №1

1 / 30

Yuzasi 10 ga teng bo’lgan kvadratning ketma-ket ikki uchidan o’tuvchi aylana chizilgan. Uchinchi uchidan aylanaga urunma o’tkazilgan. Urunma tomondan ikki marta katta bo’lsa, aylana radiusini toping.

A) 5

B) 10

C) 6

D) 4

2 / 30

qonuniyat bo’yicha harakatlanayotgan moddiy nuqta harakatning 200- metrida qanday tezlikka (m/s) erishadi?

A) 36

B) 42

C) 32

D) 38

3 / 30

tenglamani yeching.

A) 2018

B) 0

C) 2017

D) 2019

4 / 30

y= funktsiyaning aniqlanish sohasini toping.

A) (2;∞)

B) [2;∞)

C) (-∞;2)

D) (-∞;2)v(2;∞)

5 / 30

Agar f(x)=sin2x va g(x)=cos2x bo’lsa, u holda f(g(x)) funksiyaning hosilasini toping.

A) -4sin2x*cos(cos2x)

B) -4sin2x*cos(2cos2x)

C) 4sin2x*cos(2cos2x)

D) 4sin2x*cos(cos2x)

6 / 30

Tenglamaning nechta ildizi bor? |x+1|=|2x-1|

A) 2

B) 1

C) 4

D) 3

7 / 30

m ning qanday eng katta butun qiymatida y=2x-mx-5+m funksiyaning grafigi 1,3,4 –choraklarda yotadi?

A) 5

B) 2

C) 3

D) 1

8 / 30

integralning qiymatini toping.

A) π/4

B) π/2

C) 0

D) -π/2

9 / 30

A) 1

B) √6

C) 2

D) 0

10 / 30

Hisoblang

A) 2

B) 1

C) 0

D) -1

11 / 30

Musobaqada 5 ta ishtirokchidan 3 tasiga 1, 2, 3-o’rinlarni necha xil usulda berish mumkin?

A) 120

B) 47

C) 60

D) 18

12 / 30

Ushbu (y⁶+y³+1)(y³+1)(y³-1)-y⁶+y³+1 ifodani soddalashtish natijasida ko’phad hosil qilindi. Uning nechta hadi bor?

A) 1

B) 4

C) 3

D) 2

13 / 30

Rombning yuzi 96 ga, dioganallaridan biri 16 ga teng. Romb tomonini toping.

A) 12

B) 10

C) 9

D) 11

14 / 30

sistemadan x+y ning qiymatini toping.

A) 6

B) 12

C) -12

D) 35/4

15 / 30

ifodaning qiymatini toping.

A) 0,5

B) -0,5

C) -2

D) 0

16 / 30

Rasmda ko‘rsatilgan ko‘pyoqlardan qaysi birida 4 ta yoq, 6 ta qirra bor?

A) 1, 3

B) 2

C) 3

D) 1, 2

17 / 30

Ostki asosining yuzi 16π ga va ustki asosining yuzi 4π ga teng bo‘lgan kesik konus berilgan. Agar kesik konusga shar ichki chizilgan bo‘lsa, u holda sharning hajmini toping.

A) 3√2π/4

B) (5√3+3)π/3

C) 64√2π/3

D) 8√2π/5

18 / 30

x²-5|x|-6=0 tenglama ildizini toping

A) -1;6

B) ±;±6

C) -1;-6

D) ±6

19 / 30

O’q kesimining diagonallari o’zaro perpendikulyar bo’lgan kesik konus yasovchisi va asos tekisligi orasidagi burchak ga teng. Agar o’q kesimining diagonali ga teng bo’lsa, kesik konus asosining yuzini toping.

A) πa²/4cos²α

B) πa²/4sin²α

C) πa²(1-2sinα/4sin²)

D) πa²(1+2cosα/4sin²)

20 / 30

sistema yagona yechimga ega bo’ladigan a ning barcha qiymatlari to’plamini toping.

A) {-1;3}

B) {1;2}

C) {2;4}

D) {-1;2}

21 / 30

sonning oxirgi raqamini toping.

A) 8

B) 4

C) 6

D) 2

22 / 30

Fazoda (1;2;3) nuqtalardan o’tuvchi to’g’ri chiziq tenglamasini tuzing.

A) x=y/3=z/2

B) 2x+3y+z=0

C) -x-y+z=0

D) x-1/2=y-2/3=z-3/4

23 / 30

Rombning balandligi 8 ga dioganallarining ko’paytmasi 80 ga teng. Rombning perimetrini toping

A) 24

B) 16

C) 20

D) 32

24 / 30

To’g’ri burchakli uchburchakning gipotenuzasi 5 ga, bir katetining gipotenuzadagi proyeksiyasi 1,6 ga teng. Ikkinchi katetning kvadratini toping.

A) 18

B) 14

C) 16

D) 17

25 / 30

To’g’ri to’rtburchakning perimetri 50 ga teng. Bir tomoni boshqa tomonidan 5 ga ko’p. To’g’ri to’rtburchakning yuzini toping.

A) 50

B) 60

C) 150

D) 225

26 / 30

Agar bank qo`yilgan pulga 40% yillik foyda bersa, qo`yilgan 5000 so`m pul bir yildan keyin qancha bo`ladi ?

A) 7200

B) 6200

C) 6900

D) 7000

27 / 30

Ifodani soddalashtiring.

2 cos55^o.cos40^o.sin55^o+cos110^o.sin40^o

A) 0,5

B) 2

C) 0

D) 1

28 / 30

a=sin 1; b=sin 2; c=sin 3; d=sin 4 va e=sin 5 sonlarni kamayish tartibida joylashtiring.

A) b>c>a>d>e

B) a>b>c>d>e

C) e>b>a>d>c

D) b>a>c>d>e

29 / 30

Agar bank qo’yilgan pulga 40% yillik bersa, qo’yilgan 4500 so’m pul bir yildan so’ng qancha bo’ladi?

A) 6000

B) 6100

C) 6300

D) 6200

30 / 30

Muntazam uchburchakli piramidaning yon qirrasi asos tekisligi bilan 45^o li burchak tashkil etgan bo‘lsa, u holda piramidaning yon sirti yuzining uning asosi yuziga nisbatini toping.

A) 2√5

B) 2√3

C) 4

D) 3√3