Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 192 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 4 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 Agar f(x)=sin2x va g(x)=cos2x bo’lsa, u holda f(g(x)) funksiyaning hosilasini toping. A) -4sin2x*cos(cos2x) B) -4sin2x*cos(2cos2x) C) 4sin2x*cos(cos2x) D) 4sin2x*cos(2cos2x) 2 / 30 y=cos(2sinx) funksiyaning qiymatlar sohasini toping. A) [cos2;1] B) [0;cos2] C) [0;1] D) [-1;1] 3 / 30 Agar arctga+ arctgb + arctgc= bo’lsa, a+b+c ni toping. A) abc B) ab C) 1 D) ab/c 4 / 30 y= funksiyaning aniqlanish sohasini toping A) (0,2) B) (2;∞) C) (-∞;0])v[2;∞) D) (-∞;0)v(2;∞) 5 / 30 Bir vaqtning o’zida 9,13, . . . ,405 va 15,21, . . . ,255 ketma–ketliklarning hadlari bo’lgan sonlarning eng kattasi va eng kichigining ayirmasini toping A) 228 B) 231 C) 147 D) 150 6 / 30 Agar f(x)=ax3-5x2+b va bo’lsa, a ni toping. A) 3 B) 0 C) 1 D) 2 7 / 30 sistemada xy ning qiymatini toping. A) 64 B) 80 C) 75 D) 60 8 / 30 Agar bank qo’yilgan pulga 40% yillik bersa, qo’yilgan 4500 so’m pul bir yildan so’ng qancha bo’ladi? A) 6000 B) 6100 C) 6200 D) 6300 9 / 30 funksiya uchun quyidagi mulohazalardan qaysi biri o’rinli? A) toq funksiya B) juft ham emas, toq ham emas funksiya C) juft funksiya D) bunday funksiya mavjud emas 10 / 30 Bekzodda 50 so’m va Sobirda 70 so’m pul bor edi. Anvar Bekzodga o’z pulining 10 foizini bergandan so’ng, Bekzod Sobirga pulining yarmini berdi. So’ng Sobir Anvarga pulining 10 foizini berdi. Anvar o’zidagi pullarini hisoblab, pullari dastlabki holdagi puli bilan teng ekanligini bildi. Anvarda qancha pul bo’lgan? A) 375 B) 100 C) 127 D) 400 11 / 30 Agar x,y sonlar (x+5)2+(y-12)2=142 tenglikni qanoatlantirsa, x2+y2 ifodaning eng kichik qiymatini toping. A) √3 B) √2 C) 2 D) 1 12 / 30 Parallelogrammning yuzi 213 ga, tomonlaridan biri 7 ga va o’tkir burchagi 600 ga teng bo’lsa, ikkinchi tomonini toping A) 6 B) 8 C) 5 D) 4 13 / 30 Tomoni 12 ga teng bo`lgan teng tomonli uchburchakga ichki chizilgan aylana uzunligini toping. A) 3π B) 4√3π C) 2√3π D) 12π 14 / 30 A) 5 B) 2 C) 3 D) 1 15 / 30 Hisoblang A) 0 B) 2 C) -1 D) 1 16 / 30 7 sonini uchta natural sonlar yig’indisi ko’rinishida necha xil usulda yozish mumkin? A) 4 B) 6 C) 5 D) 3 17 / 30 Konsert zalining birinchi qatorida 40 ta o’rindiq bor. Har bir keyingi qatordagi o’rindiqlar soni oldingi qatordan 4 ga ko’p. Agar konsert zalida jami 40 ta qator bo’lsa, u holda shu zaldagi barcha o’rindiqlar sonini toping. A) 4720 B) 4716 C) 4760 D) 4680 18 / 30 Agar geometrik progressiyaning ketma–ket dastlabki uchta hadining yig’indisi 62 ga, ularning o’nli logarifmlari yig’indisi 3 ga teng bo’lsa, shu geometrik progressiyaning birinchi hadini toping. A) 50 B) 10 yoki 50 C) 2 yoki 50 D) 10 19 / 30 a(x+2)=2x+1 tenglama a ning qanday qiymatida yechimga ega emas? A) (∞;∞) B) (2;∞) C) (-∞;2)v(2;∞) D) (-∞;2) 20 / 30 Ushbu (y6+y3+1)(y3+1)(y3-1)-y6+y3+1 ifodani soddalashtish natijasida ko’phad hosil qilindi. Uning nechta hadi bor? A) 3 B) 1 C) 2 D) 4 21 / 30 (-3;4) nuqtaga absissa, ordinata o’qlariga va koordinata boshiga nisbatan simmetrik bo’lgan nuqtalarni tutashtirishdan hosil bo’lgan uchburchakning eng kata tomonini toping. A) 14 B) 10 C) 24 D) 12 22 / 30 Sin9x =4sin3x tenglamani yeching A) π/3+πn, n€Ζ B) π/2+πn, n€Ζ C) πn/3, n€Ζ D) πn, n€Ζ 23 / 30 Ostki asosining yuzi 16π ga va ustki asosining yuzi 4π ga teng bo‘lgan kesik konus berilgan. Agar kesik konusga shar ichki chizilgan bo‘lsa, u holda sharning hajmini toping. A) 3√2π/4 B) 64√2π/3 C) 8√2π/5 D) (5√3+3)π/3 24 / 30 O’qishni bilmaydigan bola alifbening A,A,A, N,N, S- 6 ta harflarini ixtiyoriy ravishda terib chiqadi. Bunda ANANAS so’zining hosil bo’lish ehtimolini toping. A) 6/720 B) 5/720 C) 1/60 D) 5/24 25 / 30 a=sin 1; b=sin 2; c=sin 3; d=sin 4 va e=sin 5 sonlarni kamayish tartibida joylashtiring. A) b>a>c>d>e B) b>c>a>d>e C) e>b>a>d>c D) a>b>c>d>e 26 / 30 Fazoda (1;2;3) nuqtalardan o’tuvchi to’g’ri chiziq tenglamasini tuzing. A) -x-y+z=0 B) x=y/3=z/2 C) x-1/2=y-2/3=z-3/4 D) 2x+3y+z=0 27 / 30 a ning 7x-a-13=(a-5)(x+7) tenglama yechimga ega bo’lmaydigan qiymatining natural bo’luvchilar sonini toping. A) 4 B) 8 C) 12 D) 6 28 / 30 To’g’ri burchakli uchburchakning yuzi 24 ga, katetlaridan biri 6 ga teng bo’lsa, gipotenuzasini toping A) 12 B) √46 C) 11 D) 10 29 / 30 Tenglamaning nechta ildizi bor? |x+1|=|2x-1| A) 2 B) 4 C) 3 D) 1 30 / 30 Perimetri 60 ga teng bo’lgan parallelogrammning tomonlari nisbati 2:3 ga, o’tkir burchagi esa 300 ga teng. Parallelogrammning yuzini toping. A) 52√3 B) 54 C) 48√3 D) 108 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
