Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 221 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 8 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 Tenglamani yeching. (x+2)+(x+4)+(x+6)+…+(x+100)=2800 A) 3 B) 7 C) 5 D) 4 2 / 30 Tomoni 6 ga teng bo`lgan teng tomonli uchburchakga tashqi chizilgan doiraning yuzini toping. A) 10 π B) 12π C) 7 π D) 6 π 3 / 30 AA1A2A3A4A5A6 muntazam oltiburchakli piramidaning hajmi ga va balandligi 2 ga teng bo‘lsa, u holda AA2A6 kesim yuzini toping. A) √5 B) 3 C) 2 D) √15 4 / 30 sistemada xy ning qiymatini toping. A) 75 B) 64 C) 60 D) 80 5 / 30 Tenglamaning ildizlari yig`indisini toping. A) 3 B) 6 C) 5 D) 4 6 / 30 Quyidagi 2x-y+3z=2018 va x+5y+z=2019 tekisliklarning holatini aniqlang. A) aniqlab bo’lmaydi B) ayqash C) o’zaro perpendikulyar D) o’zaro parallel 7 / 30 Rombning balandligi 8 ga dioganallarining ko’paytmasi 80 ga teng. Rombning perimetrini toping A) 16 B) 20 C) 32 D) 24 8 / 30 sin2x-cos2x=1 tenglama [-π; 2π] oraliqda nechta ildizga ega? A) 9 B) 6 C) 7 D) 10 9 / 30 Tenglamani yeching. |x2-11x+10|=x2-11x+10 A) (-∞;1]v[10;∞) B) [10;∞) C) (-∞;1] D) 1; 10 10 / 30 Ostki asosining yuzi 20π va ustki asosining yuzi 10π ga teng bo‘lgan kesik konus berilgan. Agar kesik konusga shar ichki chizilgan bo‘lsa, u holda kesik konus hajmining shar hajmiga nisbatini toping. A) 3√3+1/5 B) 5√3+3/3 C) 2√2/3 D) 3√2+2/4 11 / 30 Agar f(x)=4x3-6x2-2x+3x .log3e bo’lsa, u holda ni toping. A) √2e B) 3e C) 1 D) e 12 / 30 Parallelogrammning tomonlari nisbati 3:5 kabi. Agar parallelogrmmning perimetri 48 ga burchaklaridan biri 1200 ga teng bo’lsa, uning yuzini toping. A) 67,5√3 B) 48√3 C) 67,5 D) 135√3/4 13 / 30 Soddalashtiring. (0<m<7) A) m B) 7-2m C) 2m-7 D) 7 14 / 30 Uchburchakning balandligi 12 ga teng bo’lib, u asosni 5:16 nidbatda bo’ladi. Agar asosning uzunligi 21 ga teng bo’lsa, uchburchakning perimetrini toping A) 54 B) 52 C) 108 D) 48 15 / 30 Ifodani soddalashtiring. [ln(ln x)-ln(loge10)].log10e A) ln(lg x) B) lg(lg x) C) lg(ln x) D) ln(ln x) 16 / 30 Agar f(x)=ax3-5x2+b va bo’lsa, a ni toping. A) 3 B) 0 C) 1 D) 2 17 / 30 To’rtburchakning uchi M (0, 4) ; N(-4,0) ; P(-3;2) uchlari berilgan. Agar bo’lsa, Q uchining koordinatalarini toping. A) (-7;-1) B) (4; -3) C) (7; 1) D) (-7; 1) 18 / 30 integralning qiymatini toping. A) 0 B) -π/2 C) π/4 D) π/2 19 / 30 Markazi nuqtada bo‘lgan aylanaga va urinmalar o‘tkazilgan bo’lib, va nuqtalar urinish nuqtalari bo’lsin. Aylanadagi Q nuqtadan o‘tkazilgan uchinchi urinma va kesmalarni X va Y nuqtalarda kesib o‘tadi. Agar uchburchakning perimetri 48 va aylana radiusi 7 ga teng bo‘lsa, u holda kesma uzunligini toping A) 25 B) 15 C) 12 D) 30 20 / 30 Agar arctga+ arctgb + arctgc= bo’lsa, a+b+c ni toping. A) ab/c B) ab C) abc D) 1 21 / 30 Tomoni 2 ga teng kvadratga tashqi chizilgan aylana uzunligini toping. A) 2π/3 B) 3π C) 4π D) 2π 22 / 30 funktsiyaning aniqlanish sohasini toping. A) (-∞;1)v(2;∞) B) (-∞;1]v[2;∞) C) (1;2) D) [1;2] 23 / 30 y= funktsiyaning aniqlanish sohasini toping. A) [2;∞) B) (2;∞) C) (-∞;2) D) (-∞;2)v(2;∞) 24 / 30 Parallelogrammning yuzi 213 ga, tomonlaridan biri 7 ga va o’tkir burchagi 600 ga teng bo’lsa, ikkinchi tomonini toping A) 4 B) 5 C) 8 D) 6 25 / 30 Tengsizlikni yeching. A) 0 B) to'g'ri javob yo'q C) (0;+∞) D) (-1/³ √2 ;0) 26 / 30 Agar f(x)=sin2x va g(x)=cos2x bo’lsa, u holda f(g(x)) funksiyaning hosilasini toping. A) 4sin2x*cos(2cos2x) B) -4sin2x*cos(2cos2x) C) -4sin2x*cos(cos2x) D) 4sin2x*cos(cos2x) 27 / 30 a=sin 1; b=sin 2; c=sin 3; d=sin 4 va e=sin 5 sonlarni kamayish tartibida joylashtiring. A) a>b>c>d>e B) b>a>c>d>e C) b>c>a>d>e D) e>b>a>d>c 28 / 30 Teng yonli trpetsiyaning asoslari 15 va 25 ga balandligi esa 15 ga teng trapetsiyaning dioganalini toping A) 30 B) 28 C) 20 D) 25 29 / 30 funksiya uchun quyidagi mulohazalardan qaysi biri o’rinli? A) bunday funksiya mavjud emas B) juft ham emas, toq ham emas funksiya C) juft funksiya D) toq funksiya 30 / 30 Anvar tub son o’yladi va o’ylagan sonini 5 ga ko’paytirib, 8 ni ayirgan edi, yana tub son hosil bo’ldi. Anvar qanday son o’ylagan? A) aniqlab bo’lmaydi B) 412967 C) 2 D) 374389 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
