Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 164 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 2 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 Tenglamaning ildizlari yig’indisi va ko’paytmasining yig’indisini toping. |x+1|.|x-4|=5 A) -3 B) 6 C) 9 D) -6 2 / 30 Soat 3:37 bo’lganda minut va soat millari orasidagi burchakni toping. A) 113,5° B) 112,5° C) 100° D) 113° 3 / 30 a=sin 1; b=sin 2; c=sin 3; d=sin 4 va e=sin 5 sonlarni kamayish tartibida joylashtiring. A) b>a>c>d>e B) e>b>a>d>c C) a>b>c>d>e D) b>c>a>d>e 4 / 30 sistema a ning qanday qiymatida cheksiz ko’p yechimga ega? A) (-∞;6])v[6;∞) B) 6 C) (2;∞) D) (-∞;6) 5 / 30 7 sonini uchta natural sonlar yig’indisi ko’rinishida necha xil usulda yozish mumkin? A) 4 B) 6 C) 3 D) 5 6 / 30 Tomoni 12 ga teng bo`lgan teng tomonli uchburchakga ichki chizilgan aylana uzunligini toping. A) 12π B) 3π C) 2√3π D) 4√3π 7 / 30 Muntazam uchburchakli piramidaning yon qirrasi asos tekisligi bilan 45o li burchak tashkil etgan bo‘lsa, u holda piramidaning yon sirti yuzining uning asosi yuziga nisbatini toping. A) 2√3 B) 2√5 C) 4 D) 3√3 8 / 30 O’qishni bilmaydigan bola alifbening A,A,A, N,N, S- 6 ta harflarini ixtiyoriy ravishda terib chiqadi. Bunda ANANAS so’zining hosil bo’lish ehtimolini toping. A) 6/720 B) 5/720 C) 5/24 D) 1/60 9 / 30 Radiusi 1 ga teng aylana uchta yoyga bo`lingan. Ularga mos markaziy burchaklar 1, 2 va 6 sonlariga proporsional. Yoylardan eng kattasining uzunligini toping. A) 3π/4 B) 4π/3 C) 3π/2 D) 2π/3 10 / 30 integralning qiymatini toping. A) -π/2 B) 0 C) π/2 D) π/4 11 / 30 Hisoblang A) 2√3 B) 1 C) √3 D) 3√3 12 / 30 Agar x,y sonlar (x+5)2+(y-12)2=142 tenglikni qanoatlantirsa, x2+y2 ifodaning eng kichik qiymatini toping. A) 1 B) √2 C) √3 D) 2 13 / 30 Bir vaqtning o’zida 9,13, . . . ,405 va 15,21, . . . ,255 ketma–ketliklarning hadlari bo’lgan sonlarning eng kattasi va eng kichigining ayirmasini toping A) 150 B) 231 C) 147 D) 228 14 / 30 Uchburchakning balandligi 12 ga teng bo’lib, u asosni 5:16 nidbatda bo’ladi. Agar asosning uzunligi 21 ga teng bo’lsa, uchburchakning perimetrini toping A) 108 B) 48 C) 54 D) 52 15 / 30 Ikki burchagi graduslari yig’indisi uchinchi burchagi gradusidan katta bo’lgan uchburchaklar sonini toping. A) 1 B) 0 C) 2019 D) cheksiz ko’p 16 / 30 ABCD to’gri to’rtburchak ichidan olingan O nuqtadan A, B, C, D uchlarigacha bo’lgan masofalar mos ravishda 3, 4, 5, 6 ga teng bo’lsa, u holda AB tomon uzunligini toping. A) 2 B) √37 C) bunday to’gri to’rtburchak mavjud emas D) √7 17 / 30 To’rtburchakli muntazam piramidaning yon qirrasidagi ikki yoqli burchak 120 ga teng. Diagonal kesimining yuzasi S ga teng bo’lsa, uning yon sirtini toping. A) 2S B) 4S C) 3S D) 0,5S 18 / 30 funktsiyaning aniqlanish sohasini toping. A) (-∞;1)v(2;∞) B) (1;2) C) [1;2] D) (-∞;1]v[2;∞) 19 / 30 Qaysi javobda faqat juft funksiyalar ko’rsatilgan? A) 3, 4 B) 1, 3 C) 2, 3 D) 1,4 20 / 30 Ostki asosining yuzi 16π ga va ustki asosining yuzi 4π ga teng bo‘lgan kesik konus berilgan. Agar kesik konusga shar ichki chizilgan bo‘lsa, u holda sharning hajmini toping. A) 3√2π/4 B) 64√2π/3 C) (5√3+3)π/3 D) 8√2π/5 21 / 30 |x2-5x-14|+20≥5|x+2|+4|x-7| tengsizlikni yeching. A) [2;4]v{2}v[3;∞) B) [-2;4]v{6} C) (-∞;-6]v{2}v[12;∞) D) [1;6] 22 / 30 To‘g‘ri to‘rtburchakning eni 25% ga orttirildi, bo‘yi esa 25% ga kamaytirildi. Natijada uning yuzi qanday o‘zgardi? A) 6,25% ga ortadi B) o‘zgarmaydi C) 6,25% ga kamayadi D) 2,5% ga ortadi 23 / 30 y= funksiyaning aniqlanish sohasini toping A) (0,2) B) (-∞;0)v(2;∞) C) (-∞;0])v[2;∞) D) (2;∞) 24 / 30 sistemadan x+y ning qiymatini toping. A) -12 B) 12 C) 35/4 D) 6 25 / 30 Markazi nuqtada bo‘lgan aylanaga va urinmalar o‘tkazilgan bo’lib, va nuqtalar urinish nuqtalari bo’lsin. Aylanadagi Q nuqtadan o‘tkazilgan uchinchi urinma va kesmalarni X va Y nuqtalarda kesib o‘tadi. Agar uchburchakning perimetri 48 va aylana radiusi 7 ga teng bo‘lsa, u holda kesma uzunligini toping A) 12 B) 25 C) 15 D) 30 26 / 30 Fazoda (1;2;3) nuqtalardan o’tuvchi to’g’ri chiziq tenglamasini tuzing. A) x-1/2=y-2/3=z-3/4 B) 2x+3y+z=0 C) -x-y+z=0 D) x=y/3=z/2 27 / 30 tenglamalar sistemasini yeching A) (4;4) B) (-4;4) C) (4;–4) D) (-4;-4) 28 / 30 Agar f(x)=ax3-5x2+b va bo’lsa, a ni toping. A) 0 B) 2 C) 1 D) 3 29 / 30 Agar geometrik progressiyaning ketma–ket dastlabki uchta hadining yig’indisi 62 ga, ularning o’nli logarifmlari yig’indisi 3 ga teng bo’lsa, shu geometrik progressiyaning birinchi hadini toping. A) 2 yoki 50 B) 50 C) 10 D) 10 yoki 50 30 / 30 ABCD kvadrat ichidan olingan O nuqtadan A, B, C uchlarigacha bo’lgan masofalar mos ravishda 3, 4, 5 ga teng bo’lsa, u holda OD kesma uzunligini toping. A) √32 B) √37 C) 3 D) 6 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz