Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 218 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 8 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 sistemada xy ning qiymatini toping. A) 75 B) 64 C) 60 D) 80 2 / 30 Agar bank qo`yilgan pulga 40% yillik foyda bersa, qo`yilgan 5000 so`m pul bir yildan keyin qancha bo`ladi ? A) 6200 B) 6900 C) 7200 D) 7000 3 / 30 Agar sinx+cosx=a bo’lsa, ning qiymatini toping. A) 2/5 B) -1/2 C) 1/2 D) 1/3 4 / 30 7 sonini uchta natural sonlar yig’indisi ko’rinishida necha xil usulda yozish mumkin? A) 3 B) 6 C) 5 D) 4 5 / 30 ifodaning qiymatini toping. A) 0 B) -0,5 C) 0,5 D) -2 6 / 30 Parallelogrammning yuzi 213 ga, tomonlaridan biri 7 ga va o’tkir burchagi 600 ga teng bo’lsa, ikkinchi tomonini toping A) 4 B) 8 C) 5 D) 6 7 / 30 A) 0 B) √6 C) 1 D) 2 8 / 30 Markazi nuqtada bo‘lgan aylanaga va urinmalar o‘tkazilgan bo’lib, va nuqtalar urinish nuqtalari bo’lsin. Aylanadagi Q nuqtadan o‘tkazilgan uchinchi urinma va kesmalarni X va Y nuqtalarda kesib o‘tadi. Agar uchburchakka ichki chizilgan aylana markazi bo‘lsa, u holda burchakni toping. A) 90° B) 72° C) 30° D) 60° 9 / 30 Konsert zalining birinchi qatorida 40 ta o’rindiq bor. Har bir keyingi qatordagi o’rindiqlar soni oldingi qatordan 4 ga ko’p. Agar konsert zalida jami 40 ta qator bo’lsa, u holda shu zaldagi barcha o’rindiqlar sonini toping. A) 4760 B) 4716 C) 4720 D) 4680 10 / 30 Ifodani soddalashtiring. [ln(ln x)-ln(loge10)].log10e A) lg(lg x) B) ln(ln x) C) lg(ln x) D) ln(lg x) 11 / 30 sistema a ning qanday qiymatida cheksiz ko’p yechimga ega? A) (-∞;6) B) (-∞;6])v[6;∞) C) (2;∞) D) 6 12 / 30 AA1A2A3A4A5A6 muntazam oltiburchakli piramidaning hajmi ga va balandligi 2 ga teng bo‘lsa, u holda AA2A6 kesim yuzini toping. A) √15 B) 3 C) √5 D) 2 13 / 30 Bekzodda 50 so’m va Sobirda 70 so’m pul bor edi. Anvar Bekzodga o’z pulining 10 foizini bergandan so’ng, Bekzod Sobirga pulining yarmini berdi. So’ng Sobir Anvarga pulining 10 foizini berdi. Anvar o’zidagi pullarini hisoblab, pullari dastlabki holdagi puli bilan teng ekanligini bildi. Anvarda qancha pul bo’lgan? A) 375 B) 127 C) 100 D) 400 14 / 30 Teng yonli uchburchakning tomonlari 5, 5 va 6 ga teng. Bu uchburchakning bissektiritsalari va medianalari kesishgan nuqtalar A) 1 B) 1/2 C) 1/6 D) 1,2 15 / 30 Tenglamaning nechta ildizi bor? |x+1|=|2x-1| A) 2 B) 3 C) 1 D) 4 16 / 30 Uchburchakning balandligi 12 ga teng bo’lib, u asosni 5:16 nidbatda bo’ladi. Agar asosning uzunligi 21 ga teng bo’lsa, uchburchakning perimetrini toping A) 108 B) 48 C) 54 D) 52 17 / 30 x(t)=t2+7t-6 qonuniyat bo’yicha harakatlanayotgan moddiy nuqtaning tezligi harakat boshlangandan necha sekund o’tgach 87 m/s ga teng bo’ladi? A) 36 B) 54 C) 40 D) 50 18 / 30 funktsiyaning aniqlanish sohasini toping. A) (-∞;1]v[2;∞) B) [1;2] C) (-∞;1)v(2;∞) D) (1;2) 19 / 30 Tenglamaning ildizlari yig`indisini toping. A) 4 B) 6 C) 3 D) 5 20 / 30 Bankda qo`yilgan pul bir yildan kegin foydasi bilan 2600 so`m bo`ldi; Agar bank yillik 30% foyda to`lasa, boshida qancha pul qo`yilgan bo`ladi ? A) 2100 B) 2200 C) 2000 D) 1900 21 / 30 bo’lsa, ni x orqali ifodalang. A) 2/x B) 2-x C) x/25 D) 25/x 22 / 30 Hisoblang. A) 17/34 B) 15/34 C) 2/17 D) 2/34 23 / 30 n ning qanday qiymatida ushbu 81 .82 .83 .….8n=51222 tenglik o’rinli bo’ladi? A) 10 B) 14 C) 11 D) 12 24 / 30 Agar funksiya berilgan bo’lsa, u holda M=ning qiymatini toping. A) e⁻⁴⁹⁵⁰ B) e⁵⁰⁵⁰ C) e⁴⁹⁵⁰ D) e⁻⁵⁰⁵⁰ 25 / 30 Rombning yuzi 96 ga, dioganallaridan biri 16 ga teng. Romb tomonini toping. A) 10 B) 12 C) 11 D) 9 26 / 30 Soat 3:37 bo’lganda minut va soat millari orasidagi burchakni toping. A) 112,5° B) 113,5° C) 113° D) 100° 27 / 30 sistemadan x+y ning qiymatini toping. A) 12 B) 35/4 C) 6 D) -12 28 / 30 x(t)=t2+6t+5 qonuniyat bo’yicha harakatlanayotgan moddiy nuqta harakat boshlangandan necha sekund o’tgach boshlang’ich nuqtaga nisbatan 77 metr masofaga siljiydi? A) 7 B) 10 C) 8 D) 6 29 / 30 O’q kesimining diagonallari o’zaro perpendikulyar bo’lgan kesik konus yasovchisi va asos tekisligi orasidagi burchak ga teng. Agar o’q kesimining diagonali ga teng bo’lsa, kesik konus asosining yuzini toping. A) πa²/4cos²α B) πa²(1-2sinα/4sin²) C) πa²/4sin²α D) πa²(1+2cosα/4sin²) 30 / 30 Agar f(x)=sin2x va g(x)=cos2x bo’lsa, u holda f(g(x)) funksiyaning hosilasini toping. A) 4sin2x*cos(cos2x) B) 4sin2x*cos(2cos2x) C) -4sin2x*cos(2cos2x) D) -4sin2x*cos(cos2x) 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
