Barcha fanlardan online testlar

Matematika abituriyent testi №1

InfoMaster

Aprel 5, 2022

133 Ko'rishlar 1 izoh

SaqlashSaqlanganOlib tashlandi 0

Tomonidan yaratilgan InfoMaster

Matematika abituriyentlar uchun №1

1 / 30

To’g’ri burchakli uchburchakning yuzi 24 ga, katetlaridan biri 6 ga teng bo’lsa, gipotenuzasini toping

A) 10

B) 12

C) 11

D) √46

2 / 30

Ostki asosining yuzi 20π va ustki asosining yuzi 10π ga teng bo‘lgan kesik konus berilgan. Agar kesik konusga shar ichki chizilgan bo‘lsa, u holda kesik konus hajmining shar hajmiga nisbatini toping.

A) 2√2/3

B) 3√2+2/4

C) 3√3+1/5

D) 5√3+3/3

3 / 30

Tenglamaning nechta ildizi bor? |x+1|=|2x-1|

A) 4

B) 1

C) 3

D) 2

4 / 30

Agar f(x)=ax³-5x²+b va bo’lsa, a ni toping.

A) 3

B) 0

C) 1

D) 2

5 / 30

200 kishidan iborat turistlar guruxida 140 kishi ingliz tilini, 90 kishi nemis tilini va 46 kishi ikkala tilni biladi. Ikkala tilni xam bilmaydigan turistlar necha foizni tashkil qiladi.

A) 8

B) 4

C) 12

D) 16

6 / 30

Agar sinx+cosx=a bo’lsa, ning qiymatini toping.

A) 1/3

B) -1/2

C) 1/2

D) 2/5

7 / 30

y= $\sqrt{2x^{2}-4x}$ funksiyaning aniqlanish sohasini toping

A) (2;∞)

B) (-∞;0])v[2;∞)

C) (0,2)

D) (-∞;0)v(2;∞)

8 / 30

O’q kesimining diagonallari o’zaro perpendikulyar bo’lgan kesik konus yasovchisi va asos tekisligi orasidagi burchak ga teng. Agar o’q kesimining diagonali ga teng bo’lsa, kesik konus asosining yuzini toping.

A) πa²/4sin²α

B) πa²(1+2cosα/4sin²)

C) πa²(1-2sinα/4sin²)

D) πa²/4cos²α

9 / 30

Agar x,y sonlar (x+5)²+(y-12)²=14² tenglikni qanoatlantirsa, x²+y² ifodaning eng kichik qiymatini toping.

A) 1

B) √3

C) 2

D) √2

10 / 30

Teng yonli uchburchakning tomonlari 5, 5 va 6 ga teng. Bu uchburchakning bissektiritsalari va medianalari kesishgan nuqtalar

A) 1/2

B) 1,2

C) 1

D) 1/6

11 / 30

tenglamani yeching.

A) 0

B) 2017

C) 2018

D) 2019

12 / 30

Tomoni 6 ga teng bo`lgan teng tomonli uchburchakga tashqi chizilgan doiraning yuzini toping.

A) 7 π

B) 6 π

C) 10 π

D) 12π

13 / 30

Musobaqada 5 ta ishtirokchidan 3 tasiga 1, 2, 3-o’rinlarni necha xil usulda berish mumkin?

A) 47

B) 18

C) 60

D) 120

14 / 30

a(x+2)=2x+1 tenglama a ning qanday qiymatida yechimga ega emas?

A) (2;∞)

B) (∞;∞)

C) (-∞;2)v(2;∞)

D) (-∞;2)

15 / 30

To’g’ri to’rtburchakning perimetri 50 ga teng. Bir tomoni boshqa tomonidan 5 ga ko’p. To’g’ri to’rtburchakning yuzini toping.

A) 150

B) 225

C) 50

D) 60

16 / 30

Tengsizlikni yeching.

A) (-3;2)

B) (-4;2)v(2;3)

C) (2;4)

D) (-3;2)v(2;4)

17 / 30

a ning 7x-a-13=(a-5)(x+7) tenglama yechimga ega bo’lmaydigan qiymatining natural bo’luvchilar sonini toping.

A) 12

B) 6

C) 8

D) 4

18 / 30

Anvar tub son o’yladi va o’ylagan sonini 5 ga ko’paytirib, 8 ni ayirgan edi, yana tub son hosil bo’ldi. Anvar qanday son o’ylagan?

A) 412967

B) aniqlab bo’lmaydi

C) 374389

D) 2

19 / 30

Rombning yuzi 96 ga, dioganallaridan biri 16 ga teng. Romb tomonini toping.

A) 10

B) 9

C) 12

D) 11

20 / 30

Ifodani soddalashtiring. [ln(ln x)-ln(log_e10)]^.log₁₀e

A) ln(lg x)

B) lg(ln x)

C) ln(ln x)

D) lg(lg x)

21 / 30

y=cos(2sinx) funksiyaning qiymatlar sohasini toping.

A) [0;1]

B) [cos2;1]

C) [-1;1]

D) [0;cos2]

22 / 30

Hisoblang

A) √3

B) 1/2

C) √3/2

D) 2

23 / 30

sonning oxirgi raqamini toping.

A) 4

B) 8

C) 6

D) 2

24 / 30

Qaysi javobda faqat juft funksiyalar ko’rsatilgan?

A) 1, 3

B) 2, 3

C) 1,4

D) 3, 4

25 / 30

ABCD to’gri to’rtburchak ichidan olingan O nuqtadan A, B, C, D uchlarigacha bo’lgan masofalar mos ravishda 3, 4, 5, 6 ga teng bo’lsa, u holda AB tomon uzunligini toping.

A) 2

B) √37

C) √7

D) bunday to’gri to’rtburchak mavjud emas

26 / 30

sistema yagona yechimga ega bo’ladigan a ning barcha qiymatlari to’plamini toping.