Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 122 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 2 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 Agar funksiya berilgan bo’lsa, u holda M=ning qiymatini toping. A) e⁵⁰⁵⁰ B) e⁻⁴⁹⁵⁰ C) e⁻⁵⁰⁵⁰ D) e⁴⁹⁵⁰ 2 / 30 Agar geometrik progressiyaning ketma–ket dastlabki uchta hadining yig’indisi 62 ga, ularning o’nli logarifmlari yig’indisi 3 ga teng bo’lsa, shu geometrik progressiyaning birinchi hadini toping. A) 10 B) 2 yoki 50 C) 10 yoki 50 D) 50 3 / 30 Ostki asosining yuzi 20π va ustki asosining yuzi 10π ga teng bo‘lgan kesik konus berilgan. Agar kesik konusga shar ichki chizilgan bo‘lsa, u holda kesik konus hajmining shar hajmiga nisbatini toping. A) 5√3+3/3 B) 3√2+2/4 C) 2√2/3 D) 3√3+1/5 4 / 30 To’g’ri burchakli uchburchakning gipotenuzasi 13 ga, katetlaridan biri 52 ga teng. Gipotenuzaga tushirilgan balandlik uzunligini toping A) 5 B) 4 C) 6 D) 7 5 / 30 tenglamani yeching. A) 0 B) 2018 C) 2019 D) 2017 6 / 30 Hisoblang. 11+192+1993+19994+199995+1999996+19999997+199999998+1999999999 A) 2222222175 B) 222222222222 C) 22222222220 D) 222220175 7 / 30 Ushbu arifmetik progressiyaning manfiy hadlari yig’indisini toping. A) -0,75 B) -0,5 C) -0,25 D) -1 8 / 30 Ifodani soddalashtiring. [ln(ln x)-ln(loge10)].log10e A) lg(ln x) B) ln(lg x) C) ln(ln x) D) lg(lg x) 9 / 30 Soat 3:37 bo’lganda minut va soat millari orasidagi burchakni toping. A) 113° B) 100° C) 112,5° D) 113,5° 10 / 30 Parallelogrammning yuzi 213 ga, tomonlaridan biri 7 ga va o’tkir burchagi 600 ga teng bo’lsa, ikkinchi tomonini toping A) 6 B) 4 C) 5 D) 8 11 / 30 Bir vaqtning o’zida 9,13, . . . ,405 va 15,21, . . . ,255 ketma–ketliklarning hadlari bo’lgan sonlarning eng kattasi va eng kichigining ayirmasini toping A) 147 B) 231 C) 150 D) 228 12 / 30 m ning qanday eng katta butun qiymatida y=2x-mx-5+m funksiyaning grafigi 1,3,4 –choraklarda yotadi? A) 1 B) 3 C) 5 D) 2 13 / 30 Markazi nuqtada bo‘lgan aylanaga va urinmalar o‘tkazilgan bo’lib, va nuqtalar urinish nuqtalari bo’lsin. Aylanadagi Q nuqtadan o‘tkazilgan uchinchi urinma va kesmalarni X va Y nuqtalarda kesib o‘tadi. Agar uchburchakning perimetri 48 va aylana radiusi 7 ga teng bo‘lsa, u holda kesma uzunligini toping A) 30 B) 12 C) 15 D) 25 14 / 30 funksiya uchun quyidagi mulohazalardan qaysi biri o’rinli? A) bunday funksiya mavjud emas B) toq funksiya C) juft funksiya D) juft ham emas, toq ham emas funksiya 15 / 30 Tenglamaning ildizlari yig`indisini toping. A) 6 B) 4 C) 3 D) 5 16 / 30 Agar va b-a=4 bo’lsa, a+b ni toping. A) 4 B) 2 C) 3 D) 3,5 17 / 30 O’q kesimining diagonallari o’zaro perpendikulyar bo’lgan kesik konus yasovchisi va asos tekisligi orasidagi burchak ga teng. Agar o’q kesimining diagonali ga teng bo’lsa, kesik konus asosining yuzini toping. A) πa²(1-2sinα/4sin²) B) πa²/4cos²α C) πa²/4sin²α D) πa²(1+2cosα/4sin²) 18 / 30 ABCD kvadrat ichidan olingan O nuqtadan A, B, C uchlarigacha bo’lgan masofalar mos ravishda 3, 4, 5 ga teng bo’lsa, u holda OD kesma uzunligini toping. A) √37 B) 6 C) 3 D) √32 19 / 30 A) 0 B) 1 C) √6 D) 2 20 / 30 Ikki burchagi graduslari yig’indisi uchinchi burchagi gradusidan katta bo’lgan uchburchaklar sonini toping. A) 0 B) cheksiz ko’p C) 2019 D) 1 21 / 30 Tengsizlik nechta butun yechimga ega? A) 1 B) 4 C) 3 D) cheksiz ko’p 22 / 30 |x2-5x-14|+20≥5|x+2|+4|x-7| tengsizlikni yeching. A) (-∞;-6]v{2}v[12;∞) B) [2;4]v{2}v[3;∞) C) [1;6] D) [-2;4]v{6} 23 / 30 tenglamalar sistemasini yeching A) (-4;-4) B) (4;4) C) (-4;4) D) (4;–4) 24 / 30 Uchburchakning balandligi 12 ga teng bo’lib, u asosni 5:16 nidbatda bo’ladi. Agar asosning uzunligi 21 ga teng bo’lsa, uchburchakning perimetrini toping A) 54 B) 52 C) 108 D) 48 25 / 30 O’qishni bilmaydigan bola alifbening A,A,A, N,N, S- 6 ta harflarini ixtiyoriy ravishda terib chiqadi. Bunda ANANAS so’zining hosil bo’lish ehtimolini toping. A) 6/720 B) 5/720 C) 1/60 D) 5/24 26 / 30 Rombning yuzi 96 ga, dioganallaridan biri 16 ga teng. Romb tomonini toping. A) 11 B) 10 C) 9 D) 12 27 / 30 sistemadan x+y+z ning qiymatini toping. A) 140/41 B) 139/41 C) 150/41 D) -139/41 28 / 30 y=cos(2sinx) funksiyaning qiymatlar sohasini toping. A) [-1;1] B) [0;1] C) [0;cos2] D) [cos2;1] 29 / 30 Tenglamaning ildizlari yig’indisi va ko’paytmasining yig’indisini toping. |x+1|.|x-4|=5 A) -6 B) 9 C) -3 D) 6 30 / 30 Rombning balandligi 8 ga dioganallarining ko’paytmasi 80 ga teng. Rombning perimetrini toping A) 32 B) 16 C) 24 D) 20 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
