Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 221 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 8 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 Hisoblang A) 2 B) -1 C) 0 D) 1 2 / 30 Tomoni 6 ga teng bo`lgan teng tomonli uchburchakga tashqi chizilgan doiraning yuzini toping. A) 7 π B) 6 π C) 10 π D) 12π 3 / 30 sistema a ning qanday qiymatida cheksiz ko’p yechimga ega? A) 6 B) (2;∞) C) (-∞;6) D) (-∞;6])v[6;∞) 4 / 30 Radiusi 25 bo’lgan doirada 48 ga teng vatar o’tkazilgan. Doira markazidan shu vatargacha masofani toping. A) 8 B) 7 C) 9 D) 10 5 / 30 200 kishidan iborat turistlar guruxida 140 kishi ingliz tilini, 90 kishi nemis tilini va 46 kishi ikkala tilni biladi. Ikkala tilni xam bilmaydigan turistlar necha foizni tashkil qiladi. A) 16 B) 8 C) 12 D) 4 6 / 30 Tomoni 2 ga teng kvadratga tashqi chizilgan aylana uzunligini toping. A) 3π B) 2π/3 C) 4π D) 2π 7 / 30 a=sin 1; b=sin 2; c=sin 3; d=sin 4 va e=sin 5 sonlarni kamayish tartibida joylashtiring. A) b>c>a>d>e B) a>b>c>d>e C) e>b>a>d>c D) b>a>c>d>e 8 / 30 Tenglamani yeching. |x2-11x+10|=x2-11x+10 A) [10;∞) B) 1; 10 C) (-∞;1] D) (-∞;1]v[10;∞) 9 / 30 ifodaning qiymatini toping. A) -2 B) 0,5 C) -0,5 D) 0 10 / 30 Agar f(x)=ax3-5x2+b va bo’lsa, a ni toping. A) 1 B) 0 C) 3 D) 2 11 / 30 y= funktsiyaning aniqlanish sohasini toping. A) [2;∞) B) (-∞;2) C) (-∞;2)v(2;∞) D) (2;∞) 12 / 30 To’rtburchakning uchi M (0, 4) ; N(-4,0) ; P(-3;2) uchlari berilgan. Agar bo’lsa, Q uchining koordinatalarini toping. A) (-7;-1) B) (7; 1) C) (4; -3) D) (-7; 1) 13 / 30 sonning oxirgi raqamini toping. A) 6 B) 4 C) 8 D) 2 14 / 30 Ifodani soddalashtiring. 2 cos55o.cos40o.sin55o+cos110o.sin40o A) 2 B) 1 C) 0,5 D) 0 15 / 30 x(t)=t2+7t-6 qonuniyat bo’yicha harakatlanayotgan moddiy nuqtaning tezligi harakat boshlangandan necha sekund o’tgach 87 m/s ga teng bo’ladi? A) 50 B) 36 C) 40 D) 54 16 / 30 Ikki burchagi graduslari yig’indisi uchinchi burchagi gradusidan katta bo’lgan uchburchaklar sonini toping. A) cheksiz ko’p B) 0 C) 2019 D) 1 17 / 30 Yuzasi 10 ga teng bo’lgan kvadratning ketma-ket ikki uchidan o’tuvchi aylana chizilgan. Uchinchi uchidan aylanaga urunma o’tkazilgan. Urunma tomondan ikki marta katta bo’lsa, aylana radiusini toping. A) 5 B) 4 C) 6 D) 10 18 / 30 A) √6 B) 1 C) 0 D) 2 19 / 30 Agar f(x)=sin2x va g(x)=cos2x bo’lsa, u holda f(g(x)) funksiyaning hosilasini toping. A) 4sin2x*cos(2cos2x) B) -4sin2x*cos(2cos2x) C) 4sin2x*cos(cos2x) D) -4sin2x*cos(cos2x) 20 / 30 integralning qiymatini toping. A) π/4 B) π/2 C) -π/2 D) 0 21 / 30 a ning 7x-a-13=(a-5)(x+7) tenglama yechimga ega bo’lmaydigan qiymatining natural bo’luvchilar sonini toping. A) 4 B) 6 C) 12 D) 8 22 / 30 Teng yonli uchburchakning tomonlari 5, 5 va 6 ga teng. Bu uchburchakning bissektiritsalari va medianalari kesishgan nuqtalar A) 1,2 B) 1 C) 1/6 D) 1/2 23 / 30 Radiuslari orasidagi burchagi 36o va radiusi 5 ga teng bo`lgan sektor yoyining uzunligini toping. A) π/2 B) π C) 2π/3 D) 2π 24 / 30 Agar geometrik progressiyaning ketma–ket dastlabki uchta hadining yig’indisi 62 ga, ularning o’nli logarifmlari yig’indisi 3 ga teng bo’lsa, shu geometrik progressiyaning birinchi hadini toping. A) 2 yoki 50 B) 10 C) 10 yoki 50 D) 50 25 / 30 Agar f(x)=4x3-6x2-2x+3x .log3e bo’lsa, u holda ni toping. A) 3e B) e C) 1 D) √2e 26 / 30 Markazi nuqtada bo‘lgan aylanaga va urinmalar o‘tkazilgan bo’lib, va nuqtalar urinish nuqtalari bo’lsin. Aylanadagi Q nuqtadan o‘tkazilgan uchinchi urinma va kesmalarni X va Y nuqtalarda kesib o‘tadi. Agar uchburchakning perimetri 48 va aylana radiusi 7 ga teng bo‘lsa, u holda kesma uzunligini toping A) 30 B) 12 C) 15 D) 25 27 / 30 x2-5|x|-6=0 tenglama ildizini toping A) ±6 B) -1;-6 C) ±;±6 D) -1;6 28 / 30 Tenglamani yeching. (x+2)+(x+4)+(x+6)+…+(x+100)=2800 A) 5 B) 7 C) 4 D) 3 29 / 30 Anvar tub son o’yladi va o’ylagan sonini 5 ga ko’paytirib, 8 ni ayirgan edi, yana tub son hosil bo’ldi. Anvar qanday son o’ylagan? A) aniqlab bo’lmaydi B) 374389 C) 2 D) 412967 30 / 30 Bir vaqtning o’zida 9,13, . . . ,405 va 15,21, . . . ,255 ketma–ketliklarning hadlari bo’lgan sonlarning eng kattasi va eng kichigining ayirmasini toping A) 147 B) 231 C) 150 D) 228 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
