Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 164 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 2 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 Agar x,y sonlar (x+5)2+(y-12)2=142 tenglikni qanoatlantirsa, x2+y2 ifodaning eng kichik qiymatini toping. A) 2 B) √2 C) 1 D) √3 2 / 30 Qaysi javobda faqat juft funksiyalar ko’rsatilgan? A) 1,4 B) 1, 3 C) 3, 4 D) 2, 3 3 / 30 Musobaqada 5 ta ishtirokchidan 3 tasiga 1, 2, 3-o’rinlarni necha xil usulda berish mumkin? A) 120 B) 47 C) 18 D) 60 4 / 30 Ostki asosining yuzi 16π ga va ustki asosining yuzi 4π ga teng bo‘lgan kesik konus berilgan. Agar kesik konusga shar ichki chizilgan bo‘lsa, u holda sharning hajmini toping. A) 3√2π/4 B) 64√2π/3 C) (5√3+3)π/3 D) 8√2π/5 5 / 30 Agar arctga+ arctgb + arctgc= bo’lsa, a+b+c ni toping. A) 1 B) ab C) abc D) ab/c 6 / 30 Ag ar tgα=2 bo’lsa, u holda ni hisoblang A) 10/27 B) -10/27 C) 10/3 D) -10/3 7 / 30 tenglamani yeching. A) 2019 B) 2017 C) 2018 D) 0 8 / 30 |x2-5x-14|+20≥5|x+2|+4|x-7| tengsizlikni yeching. A) [1;6] B) [2;4]v{2}v[3;∞) C) [-2;4]v{6} D) (-∞;-6]v{2}v[12;∞) 9 / 30 Tenglamani yeching. (x+2)+(x+4)+(x+6)+…+(x+100)=2800 A) 5 B) 3 C) 7 D) 4 10 / 30 a=sin 1; b=sin 2; c=sin 3; d=sin 4 va e=sin 5 sonlarni kamayish tartibida joylashtiring. A) e>b>a>d>c B) b>c>a>d>e C) b>a>c>d>e D) a>b>c>d>e 11 / 30 Tenglamaning ildizlari yig’indisi va ko’paytmasining yig’indisini toping. |x+1|.|x-4|=5 A) -3 B) 6 C) -6 D) 9 12 / 30 Agar f(x)=sin2x va g(x)=cos2x bo’lsa, u holda f(g(x)) funksiyaning hosilasini toping. A) -4sin2x*cos(cos2x) B) 4sin2x*cos(2cos2x) C) -4sin2x*cos(2cos2x) D) 4sin2x*cos(cos2x) 13 / 30 sistemada xy ning qiymatini toping. A) 64 B) 60 C) 80 D) 75 14 / 30 To‘g‘ri to‘rtburchakning eni 25% ga orttirildi, bo‘yi esa 25% ga kamaytirildi. Natijada uning yuzi qanday o‘zgardi? A) 2,5% ga ortadi B) 6,25% ga kamayadi C) 6,25% ga ortadi D) o‘zgarmaydi 15 / 30 Agar funksiya berilgan bo’lsa, u holda M=ning qiymatini toping. A) e⁵⁰⁵⁰ B) e⁻⁵⁰⁵⁰ C) e⁴⁹⁵⁰ D) e⁻⁴⁹⁵⁰ 16 / 30 Agar va b-a=4 bo’lsa, a+b ni toping. A) 3,5 B) 2 C) 4 D) 3 17 / 30 To’rtburchakli muntazam piramidaning yon qirrasidagi ikki yoqli burchak 120 ga teng. Diagonal kesimining yuzasi S ga teng bo’lsa, uning yon sirtini toping. A) 2S B) 3S C) 4S D) 0,5S 18 / 30 Radiuslari orasidagi burchagi 36o va radiusi 5 ga teng bo`lgan sektor yoyining uzunligini toping. A) 2π B) 2π/3 C) π D) π/2 19 / 30 Hisoblang A) 0 B) 2 C) -1 D) 1 20 / 30 7 sonini uchta natural sonlar yig’indisi ko’rinishida necha xil usulda yozish mumkin? A) 3 B) 4 C) 5 D) 6 21 / 30 Tomoni 6 ga teng bo`lgan teng tomonli uchburchakga tashqi chizilgan doiraning yuzini toping. A) 7 π B) 6 π C) 12π D) 10 π 22 / 30 Teng yonli uchburchakning tomonlari 5, 5 va 6 ga teng. Bu uchburchakning bissektiritsalari va medianalari kesishgan nuqtalar A) 1,2 B) 1/6 C) 1 D) 1/2 23 / 30 Bekzodda 50 so’m va Sobirda 70 so’m pul bor edi. Anvar Bekzodga o’z pulining 10 foizini bergandan so’ng, Bekzod Sobirga pulining yarmini berdi. So’ng Sobir Anvarga pulining 10 foizini berdi. Anvar o’zidagi pullarini hisoblab, pullari dastlabki holdagi puli bilan teng ekanligini bildi. Anvarda qancha pul bo’lgan? A) 100 B) 375 C) 127 D) 400 24 / 30 x2-5|x|-6=0 tenglama ildizini toping A) ±6 B) ±;±6 C) -1;6 D) -1;-6 25 / 30 Ushbu arifmetik progressiyaning manfiy hadlari yig’indisini toping. A) -0,75 B) -1 C) -0,5 D) -0,25 26 / 30 Tengsizlik nechta butun yechimga ega? A) cheksiz ko’p B) 1 C) 4 D) 3 27 / 30 sistema a ning qanday qiymatida cheksiz ko’p yechimga ega? A) (2;∞) B) (-∞;6) C) 6 D) (-∞;6])v[6;∞) 28 / 30 Agar sinx+cosx=a bo’lsa, ning qiymatini toping. A) 1/2 B) 2/5 C) 1/3 D) -1/2 29 / 30 Tomoni 25 ga diagonallaridan biri 4 ga teng bo’lgan rombning yuzini toping. A) 8√5 B) 32 C) 16 D) 24√5 30 / 30 sin2x-cos2x=1 tenglama [-π; 2π] oraliqda nechta ildizga ega? A) 7 B) 6 C) 9 D) 10 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
