Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 194 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 Ushbu (y6+y3+1)(y3+1)(y3-1)-y6+y3+1 ifodani soddalashtish natijasida ko’phad hosil qilindi. Uning nechta hadi bor? A) 4 B) 3 C) 1 D) 2 2 / 30 AA1A2A3A4A5A6 muntazam oltiburchakli piramidaning hajmi ga va balandligi 2 ga teng bo‘lsa, u holda AA2A6 kesim yuzini toping. A) 2 B) √5 C) √15 D) 3 3 / 30 Musobaqada 5 ta ishtirokchidan 3 tasiga 1, 2, 3-o’rinlarni necha xil usulda berish mumkin? A) 120 B) 18 C) 60 D) 47 4 / 30 A) √6 B) 1 C) 2 D) 0 5 / 30 a ning qanday qiymatlarida ushbu 7x-a-13=(a-5)(x+7) tenglama yagona yechimga ega A) a=12 B) a≠12 C) a≠5 D) a ning bunday qiymati yo’q 6 / 30 Hisoblang: A) -1 B) 1 C) 3 D) 2 7 / 30 Arifmetik progressiyada a17=33 va a45=89. Progressiyaning birinchi hadi hamda ayirmasining o’rta geometrigini toping. A) 2 B) 2√2 C) √2 D) 4 8 / 30 Radiusi 1 ga teng aylana uchta yoyga bo`lingan. Ularga mos markaziy burchaklar 1, 2 va 6 sonlariga proporsional. Yoylardan eng kattasining uzunligini toping. A) 2π/3 B) 3π/4 C) 4π/3 D) 3π/2 9 / 30 Ostki asosining yuzi 20π va ustki asosining yuzi 10π ga teng bo‘lgan kesik konus berilgan. Agar kesik konusga shar ichki chizilgan bo‘lsa, u holda kesik konus hajmining shar hajmiga nisbatini toping. A) 2√2/3 B) 3√2+2/4 C) 5√3+3/3 D) 3√3+1/5 10 / 30 “Tutgan balig‘ining og‘irligi qancha?” degan savolga baliqchi: “Baliqning dumi 3 kg, boshi uning dumi hamda tanasi yarmining og‘irligiga teng, tanasi esa boshi va dumining og‘irligiga teng”, deb javob berdi. Baliqning og‘irligini (kg) toping. A) 6 B) 12 C) 18 D) 3 11 / 30 Quyidagi va to’g’ri chiziqlarning o’zaro holatini aniqlang. A) o’zaro kesishadi B) ayqash to’gri chiziqlar C) o’zaro parallel D) o’zaro perpendikulyar 12 / 30 Tengsizlikni yeching. A) 0 B) (-1/³ √2 ;0) C) to'g'ri javob yo'q D) (0;+∞) 13 / 30 (-3;4) nuqtaga absissa, ordinata o’qlariga va koordinata boshiga nisbatan simmetrik bo’lgan nuqtalarni tutashtirishdan hosil bo’lgan uchburchakning eng kata tomonini toping. A) 12 B) 14 C) 10 D) 24 14 / 30 y= funktsiyaning aniqlanish sohasini toping. A) (-∞;2) B) (-∞;2)v(2;∞) C) [2;∞) D) (2;∞) 15 / 30 qonuniyat bo’yicha harakatlanayotgan moddiy nuqta harakatning 200- metrida qanday tezlikka (m/s) erishadi? A) 42 B) 38 C) 36 D) 32 16 / 30 Soat 3:37 bo’lganda minut va soat millari orasidagi burchakni toping. A) 113,5° B) 100° C) 113° D) 112,5° 17 / 30 tenglamalar sistemasini yeching A) (4;4) B) (-4;-4) C) (-4;4) D) (4;–4) 18 / 30 tenglamani yeching. A) 2018 B) 2019 C) 2017 D) 0 19 / 30 Teng yonli trpetsiyaning asoslari 15 va 25 ga balandligi esa 15 ga teng trapetsiyaning dioganalini toping A) 28 B) 20 C) 25 D) 30 20 / 30 To‘g‘ri to‘rtburchakning eni 25% ga orttirildi, bo‘yi esa 25% ga kamaytirildi. Natijada uning yuzi qanday o‘zgardi? A) 6,25% ga kamayadi B) 2,5% ga ortadi C) 6,25% ga ortadi D) o‘zgarmaydi 21 / 30 Markazi O nuqtada bo‘lgan aylanaga PA va PB urinmalar o‘tkazilgan bo’lib, A va B nuqtalar urinish nuqtalari bo’lsin. Aylanadagi Q nuqtadan o‘tkazilgan uchinchi urinma PA va PB kesmalarni X va Y nuqtalarda kesib o‘tadi. Agar XQ=YQ bo‘lsa, u holda PXY uchburchak qanday uchburchak bo‘ladi? A) muntazam uchburchak B) to`g`ri burchakli uchburchak C) teng yonli uchburchak D) ixtiyoriy uchburchak 22 / 30 Ag ar tgα=2 bo’lsa, u holda ni hisoblang A) 10/27 B) -10/27 C) 10/3 D) -10/3 23 / 30 Agar sinx+cosx=a bo’lsa, ning qiymatini toping. A) 2/5 B) -1/2 C) 1/2 D) 1/3 24 / 30 sonning oxirgi raqamini toping. A) 2 B) 4 C) 6 D) 8 25 / 30 Soddalashtiring. (0<m<7) A) 7-2m B) m C) 7 D) 2m-7 26 / 30 a=sin 1; b=sin 2; c=sin 3; d=sin 4 va e=sin 5 sonlarni kamayish tartibida joylashtiring. A) e>b>a>d>c B) b>a>c>d>e C) a>b>c>d>e D) b>c>a>d>e 27 / 30 Ifodani soddalashtiring. 2 cos55o.cos40o.sin55o+cos110o.sin40o A) 0 B) 2 C) 0,5 D) 1 28 / 30 O’qishni bilmaydigan bola alifbening A,A,A, N,N, S- 6 ta harflarini ixtiyoriy ravishda terib chiqadi. Bunda ANANAS so’zining hosil bo’lish ehtimolini toping. A) 6/720 B) 1/60 C) 5/720 D) 5/24 29 / 30 Ushbu funksiyaning boshlang’ich funksiyasini toping. A) ln(|x+4*|x-1|)+c B) ln(|x+4+|x-1|)+c C) ln|x+4/x-1|+c D) ln|x-1/x+4|+c 30 / 30 Bekzodda 50 so’m va Sobirda 70 so’m pul bor edi. Anvar Bekzodga o’z pulining 10 foizini bergandan so’ng, Bekzod Sobirga pulining yarmini berdi. So’ng Sobir Anvarga pulining 10 foizini berdi. Anvar o’zidagi pullarini hisoblab, pullari dastlabki holdagi puli bilan teng ekanligini bildi. Anvarda qancha pul bo’lgan? A) 127 B) 400 C) 375 D) 100 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz