Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 225 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 Teng yonli trpetsiyaning asoslari 15 va 25 ga balandligi esa 15 ga teng trapetsiyaning dioganalini toping A) 25 B) 20 C) 28 D) 30 2 / 30 Ikki burchagi graduslari yig’indisi uchinchi burchagi gradusiga teng bo’lgan uchburchak qanday uchburchak deyiladi? A) teng tomonli uchburchak B) o’tkir burchakli uchburchak C) to’gri burchakli uchburchak D) o’tmas burchakli uchburchak 3 / 30 Tomoni 6 ga teng bo`lgan teng tomonli uchburchakga tashqi chizilgan doiraning yuzini toping. A) 10 π B) 6 π C) 7 π D) 12π 4 / 30 To’rtburchakning uchi M (0, 4) ; N(-4,0) ; P(-3;2) uchlari berilgan. Agar bo’lsa, Q uchining koordinatalarini toping. A) (-7; 1) B) (-7;-1) C) (7; 1) D) (4; -3) 5 / 30 Tenglamani yeching. |x2-11x+10|=x2-11x+10 A) (-∞;1]v[10;∞) B) [10;∞) C) (-∞;1] D) 1; 10 6 / 30 Agar f(x)=4x3-6x2-2x+3x .log3e bo’lsa, u holda ni toping. A) √2e B) 1 C) 3e D) e 7 / 30 sistemada xy ning qiymatini toping. A) 60 B) 80 C) 64 D) 75 8 / 30 qonuniyat bo’yicha harakatlanayotgan moddiy nuqta harakatning 200- metrida qanday tezlikka (m/s) erishadi? A) 32 B) 42 C) 36 D) 38 9 / 30 y= funktsiyaning aniqlanish sohasini toping. A) (2;∞) B) [2;∞) C) (-∞;2)v(2;∞) D) (-∞;2) 10 / 30 Soddalashtiring. A) a+1 B) 2018a/a+1 C) 2019 D) 2018 11 / 30 Ushbu funksiyaning boshlang’ich funksiyasini toping. A) ln|x-1/x+4|+c B) ln(|x+4*|x-1|)+c C) ln(|x+4+|x-1|)+c D) ln|x+4/x-1|+c 12 / 30 “Tutgan balig‘ining og‘irligi qancha?” degan savolga baliqchi: “Baliqning dumi 3 kg, boshi uning dumi hamda tanasi yarmining og‘irligiga teng, tanasi esa boshi va dumining og‘irligiga teng”, deb javob berdi. Baliqning og‘irligini (kg) toping. A) 3 B) 6 C) 12 D) 18 13 / 30 bo’lsa, ni x orqali ifodalang. A) 2/x B) 2-x C) x/25 D) 25/x 14 / 30 Qaysi javobda faqat juft funksiyalar ko’rsatilgan? A) 1, 3 B) 2, 3 C) 1,4 D) 3, 4 15 / 30 Agar geometrik progressiyaning ketma–ket dastlabki uchta hadining yig’indisi 62 ga, ularning o’nli logarifmlari yig’indisi 3 ga teng bo’lsa, shu geometrik progressiyaning birinchi hadini toping. A) 50 B) 10 C) 10 yoki 50 D) 2 yoki 50 16 / 30 ABCD kvadrat ichidan olingan O nuqtadan A, B, C uchlarigacha bo’lgan masofalar mos ravishda 3, 4, 5 ga teng bo’lsa, u holda OD kesma uzunligini toping. A) √32 B) √37 C) 6 D) 3 17 / 30 Tenglamaning nechta ildizi bor? |x+1|=|2x-1| A) 3 B) 1 C) 2 D) 4 18 / 30 Soat 3:37 bo’lganda minut va soat millari orasidagi burchakni toping. A) 100° B) 113,5° C) 112,5° D) 113° 19 / 30 Quyidagi va to’g’ri chiziqlarning o’zaro holatini aniqlang. A) o’zaro kesishadi B) o’zaro parallel C) ayqash to’gri chiziqlar D) o’zaro perpendikulyar 20 / 30 a ning qanday qiymatlarida ushbu 7x-a-13=(a-5)(x+7) tenglama yagona yechimga ega A) a ning bunday qiymati yo’q B) a≠12 C) a≠5 D) a=12 21 / 30 m ning qanday eng katta butun qiymatida y=2x-mx-5+m funksiyaning grafigi 1,3,4 –choraklarda yotadi? A) 1 B) 5 C) 2 D) 3 22 / 30 y= funksiyaning aniqlanish sohasini toping A) (2;∞) B) (0,2) C) (-∞;0)v(2;∞) D) (-∞;0])v[2;∞) 23 / 30 Radiusi 1 ga teng aylana uchta yoyga bo`lingan. Ularga mos markaziy burchaklar 1, 2 va 6 sonlariga proporsional. Yoylardan eng kattasining uzunligini toping. A) 3π/4 B) 2π/3 C) 3π/2 D) 4π/3 24 / 30 a ning 7x-a-13=(a-5)(x+7) tenglama yechimga ega bo’lmaydigan qiymatining natural bo’luvchilar sonini toping. A) 12 B) 4 C) 6 D) 8 25 / 30 tenglamani yeching. A) 2019 B) 2018 C) 2017 D) 0 26 / 30 Anvar tub son o’yladi va o’ylagan sonini 5 ga ko’paytirib, 8 ni ayirgan edi, yana tub son hosil bo’ldi. Anvar qanday son o’ylagan? A) 412967 B) 374389 C) aniqlab bo’lmaydi D) 2 27 / 30 Bankda qo`yilgan pul bir yildan kegin foydasi bilan 2600 so`m bo`ldi; Agar bank yillik 30% foyda to`lasa, boshida qancha pul qo`yilgan bo`ladi ? A) 2100 B) 2200 C) 1900 D) 2000 28 / 30 a(x+2)=2x+1 tenglama a ning qanday qiymatida yechimga ega emas? A) (2;∞) B) (∞;∞) C) (-∞;2) D) (-∞;2)v(2;∞) 29 / 30 To‘g‘ri to‘rtburchakning eni 25% ga orttirildi, bo‘yi esa 25% ga kamaytirildi. Natijada uning yuzi qanday o‘zgardi? A) o‘zgarmaydi B) 6,25% ga kamayadi C) 6,25% ga ortadi D) 2,5% ga ortadi 30 / 30 Hisoblang A) 0 B) -1 C) 1 D) 2 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
