Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 133 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 4 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 Bir vaqtning o’zida 9,13, . . . ,405 va 15,21, . . . ,255 ketma–ketliklarning hadlari bo’lgan sonlarning eng kattasi va eng kichigining ayirmasini toping A) 147 B) 150 C) 231 D) 228 2 / 30 To’g’ri to’rtburchakning perimetri 50 ga teng. Bir tomoni boshqa tomonidan 5 ga ko’p. To’g’ri to’rtburchakning yuzini toping. A) 225 B) 150 C) 60 D) 50 3 / 30 Arifmetik progressiyada a17=33 va a45=89. Progressiyaning birinchi hadi hamda ayirmasining o’rta geometrigini toping. A) 2 B) 2√2 C) 4 D) √2 4 / 30 A(2;-2,5) nuqtadan y= - 4x parabolagacha bo’lgan eng qisqa masofani toping. A) √3/2 B) √5/2 C) 1 D) 1,5 5 / 30 Radiusi 1 ga teng aylana uchta yoyga bo`lingan. Ularga mos markaziy burchaklar 1, 2 va 6 sonlariga proporsional. Yoylardan eng kattasining uzunligini toping. A) 3π/4 B) 4π/3 C) 3π/2 D) 2π/3 6 / 30 Radiuslari orasidagi burchagi 36o va radiusi 5 ga teng bo`lgan sektor yoyining uzunligini toping. A) π/2 B) π C) 2π D) 2π/3 7 / 30 Soddalashtiring. A) 2019 B) 2018a/a+1 C) a+1 D) 2018 8 / 30 Ifodani soddalashtiring. [ln(ln x)-ln(loge10)].log10e A) ln(ln x) B) lg(lg x) C) lg(ln x) D) ln(lg x) 9 / 30 Tengsizlik nechta butun yechimga ega? A) 4 B) 3 C) cheksiz ko’p D) 1 10 / 30 Quyidagi va to’g’ri chiziqlarning o’zaro holatini aniqlang. A) o’zaro perpendikulyar B) ayqash to’gri chiziqlar C) o’zaro parallel D) o’zaro kesishadi 11 / 30 Ushbu (y6+y3+1)(y3+1)(y3-1)-y6+y3+1 ifodani soddalashtish natijasida ko’phad hosil qilindi. Uning nechta hadi bor? A) 1 B) 4 C) 3 D) 2 12 / 30 Parallelogrammning yuzi 213 ga, tomonlaridan biri 7 ga va o’tkir burchagi 600 ga teng bo’lsa, ikkinchi tomonini toping A) 6 B) 5 C) 8 D) 4 13 / 30 Agar f(x)=4x3-6x2-2x+3x .log3e bo’lsa, u holda ni toping. A) √2e B) 3e C) 1 D) e 14 / 30 sistemadan x+y ning qiymatini toping. A) 35/4 B) 12 C) 6 D) -12 15 / 30 Ushbu arifmetik progressiyaning manfiy hadlari yig’indisini toping. A) -0,5 B) -0,75 C) -1 D) -0,25 16 / 30 Agar sinx+cosx=a bo’lsa, ning qiymatini toping. A) 2/5 B) 1/2 C) 1/3 D) -1/2 17 / 30 Tomoni 2 ga teng kvadratga tashqi chizilgan aylana uzunligini toping. A) 3π B) 4π C) 2π D) 2π/3 18 / 30 Hisoblang A) 3√3 B) 2√3 C) √3 D) 1 19 / 30 a ning qanday qiymatlarida ushbu 7x-a-13=(a-5)(x+7) tenglama yagona yechimga ega A) a≠12 B) a ning bunday qiymati yo’q C) a=12 D) a≠5 20 / 30 y=cos(2sinx) funksiyaning qiymatlar sohasini toping. A) [0;1] B) [-1;1] C) [cos2;1] D) [0;cos2] 21 / 30 x2-5|x|-6=0 tenglama ildizini toping A) -1;-6 B) -1;6 C) ±;±6 D) ±6 22 / 30 Hisoblang. 11+192+1993+19994+199995+1999996+19999997+199999998+1999999999 A) 22222222220 B) 2222222175 C) 222222222222 D) 222220175 23 / 30 sistemadan x+y+z ning qiymatini toping. A) 150/41 B) 139/41 C) 140/41 D) -139/41 24 / 30 Rombning yuzi 96 ga, dioganallaridan biri 16 ga teng. Romb tomonini toping. A) 9 B) 12 C) 10 D) 11 25 / 30 Hisoblang. A) 2/34 B) 17/34 C) 15/34 D) 2/17 26 / 30 sistema a ning qanday qiymatida cheksiz ko’p yechimga ega? A) (2;∞) B) 6 C) (-∞;6])v[6;∞) D) (-∞;6) 27 / 30 bo’lsa ni toping. Bunda funksiya f(x) ga teskari funksiya. A) -4 B) -14 C) -10 D) -12 28 / 30 Tenglamaning ildizlari yig’indisi va ko’paytmasining yig’indisini toping. |x+1|.|x-4|=5 A) 6 B) -6 C) 9 D) -3 29 / 30 x(t)=t2+6t+5 qonuniyat bo’yicha harakatlanayotgan moddiy nuqta harakat boshlangandan necha sekund o’tgach boshlang’ich nuqtaga nisbatan 77 metr masofaga siljiydi? A) 10 B) 7 C) 8 D) 6 30 / 30 Ifodani soddalashtiring. 2 cos55o.cos40o.sin55o+cos110o.sin40o A) 2 B) 1 C) 0 D) 0,5 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
