Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 164 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 2 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 Teng yonli uchburchakning tomonlari 5, 5 va 6 ga teng. Bu uchburchakning bissektiritsalari va medianalari kesishgan nuqtalar A) 1,2 B) 1 C) 1/2 D) 1/6 2 / 30 Agar x,y sonlar (x+5)2+(y-12)2=142 tenglikni qanoatlantirsa, x2+y2 ifodaning eng kichik qiymatini toping. A) √3 B) √2 C) 1 D) 2 3 / 30 Ushbu funksiyaning boshlang’ich funksiyasini toping. A) ln|x+4/x-1|+c B) ln(|x+4*|x-1|)+c C) ln(|x+4+|x-1|)+c D) ln|x-1/x+4|+c 4 / 30 a(x+2)=2x+1 tenglama a ning qanday qiymatida yechimga ega emas? A) (∞;∞) B) (2;∞) C) (-∞;2)v(2;∞) D) (-∞;2) 5 / 30 tenglamalar sistemasini yeching A) (-4;4) B) (4;–4) C) (-4;-4) D) (4;4) 6 / 30 Ifodani soddalashtiring. [ln(ln x)-ln(loge10)].log10e A) lg(lg x) B) ln(lg x) C) lg(ln x) D) ln(ln x) 7 / 30 Agar geometrik progressiyaning ketma–ket dastlabki uchta hadining yig’indisi 62 ga, ularning o’nli logarifmlari yig’indisi 3 ga teng bo’lsa, shu geometrik progressiyaning birinchi hadini toping. A) 10 yoki 50 B) 2 yoki 50 C) 50 D) 10 8 / 30 Qaysi javobda faqat juft funksiyalar ko’rsatilgan? A) 1,4 B) 3, 4 C) 1, 3 D) 2, 3 9 / 30 Ikki burchagi graduslari yig’indisi uchinchi burchagi gradusidan katta bo’lgan uchburchaklar sonini toping. A) 1 B) cheksiz ko’p C) 2019 D) 0 10 / 30 Agar funksiya berilgan bo’lsa, u holda M=ning qiymatini toping. A) e⁴⁹⁵⁰ B) e⁻⁵⁰⁵⁰ C) e⁻⁴⁹⁵⁰ D) e⁵⁰⁵⁰ 11 / 30 Yuzasi 10 ga teng bo’lgan kvadratning ketma-ket ikki uchidan o’tuvchi aylana chizilgan. Uchinchi uchidan aylanaga urunma o’tkazilgan. Urunma tomondan ikki marta katta bo’lsa, aylana radiusini toping. A) 4 B) 5 C) 6 D) 10 12 / 30 “Tutgan balig‘ining og‘irligi qancha?” degan savolga baliqchi: “Baliqning dumi 3 kg, boshi uning dumi hamda tanasi yarmining og‘irligiga teng, tanasi esa boshi va dumining og‘irligiga teng”, deb javob berdi. Baliqning og‘irligini (kg) toping. A) 18 B) 6 C) 12 D) 3 13 / 30 sistemadan x+y ning qiymatini toping. A) 35/4 B) -12 C) 12 D) 6 14 / 30 a ning qanday qiymatlarida ushbu 7x-a-13=(a-5)(x+7) tenglama yagona yechimga ega A) a≠5 B) a ning bunday qiymati yo’q C) a=12 D) a≠12 15 / 30 ifodaning qiymatini toping. A) -2 B) 0,5 C) -0,5 D) 0 16 / 30 Ushbu (y6+y3+1)(y3+1)(y3-1)-y6+y3+1 ifodani soddalashtish natijasida ko’phad hosil qilindi. Uning nechta hadi bor? A) 4 B) 3 C) 2 D) 1 17 / 30 To’g’ri burchakli uchburchakning gipotenuzasi 13 ga, katetlaridan biri 52 ga teng. Gipotenuzaga tushirilgan balandlik uzunligini toping A) 4 B) 5 C) 7 D) 6 18 / 30 Soat 3:37 bo’lganda minut va soat millari orasidagi burchakni toping. A) 100° B) 113° C) 112,5° D) 113,5° 19 / 30 Teng yonli trpetsiyaning asoslari 15 va 25 ga balandligi esa 15 ga teng trapetsiyaning dioganalini toping A) 28 B) 25 C) 20 D) 30 20 / 30 ABCD to’gri to’rtburchak ichidan olingan O nuqtadan A, B, C, D uchlarigacha bo’lgan masofalar mos ravishda 1; 2; 1,5; 1,2 ga teng bo’ladigan barcha to’g’ri to’rtburchaklar sonini toping A) cheksiz ko’p B) 1 C) 2 D) 0 21 / 30 Ikki burchagi graduslari yig’indisi uchinchi burchagi gradusiga teng bo’lgan uchburchak qanday uchburchak deyiladi? A) to’gri burchakli uchburchak B) o’tmas burchakli uchburchak C) teng tomonli uchburchak D) o’tkir burchakli uchburchak 22 / 30 Arifmetik progressiyada a17=33 va a45=89. Progressiyaning birinchi hadi hamda ayirmasining o’rta geometrigini toping. A) √2 B) 2 C) 4 D) 2√2 23 / 30 x(t)=t2+7t-6 qonuniyat bo’yicha harakatlanayotgan moddiy nuqtaning tezligi harakat boshlangandan necha sekund o’tgach 87 m/s ga teng bo’ladi? A) 36 B) 50 C) 40 D) 54 24 / 30 Tenglamaning nechta ildizi bor? |x+1|=|2x-1| A) 4 B) 2 C) 1 D) 3 25 / 30 O’qishni bilmaydigan bola alifbening A,A,A, N,N, S- 6 ta harflarini ixtiyoriy ravishda terib chiqadi. Bunda ANANAS so’zining hosil bo’lish ehtimolini toping. A) 1/60 B) 5/24 C) 6/720 D) 5/720 26 / 30 y=cos(2sinx) funksiyaning qiymatlar sohasini toping. A) [0;1] B) [-1;1] C) [0;cos2] D) [cos2;1] 27 / 30 funktsiyaning aniqlanish sohasini toping. A) [1;2] B) (1;2) C) (-∞;1]v[2;∞) D) (-∞;1)v(2;∞) 28 / 30 Agar f(x)=ax3-5x2+b va bo’lsa, a ni toping. A) 0 B) 1 C) 2 D) 3 29 / 30 x(t)=t2+6t+5 qonuniyat bo’yicha harakatlanayotgan moddiy nuqta harakat boshlangandan necha sekund o’tgach boshlang’ich nuqtaga nisbatan 77 metr masofaga siljiydi? A) 7 B) 6 C) 10 D) 8 30 / 30 7 sonini uchta natural sonlar yig’indisi ko’rinishida necha xil usulda yozish mumkin? A) 4 B) 3 C) 6 D) 5 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
