Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 138 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 5 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 Tenglamani yeching. (x+2)+(x+4)+(x+6)+…+(x+100)=2800 A) 5 B) 7 C) 4 D) 3 2 / 30 tenglamani yeching. A) 0 B) 2019 C) 2018 D) 2017 3 / 30 Hisoblang A) 1 B) 2 C) 0 D) -1 4 / 30 To’rtburchakli muntazam piramidaning yon qirrasidagi ikki yoqli burchak 120 ga teng. Diagonal kesimining yuzasi S ga teng bo’lsa, uning yon sirtini toping. A) 2S B) 3S C) 0,5S D) 4S 5 / 30 Tomoni 12 ga teng bo`lgan teng tomonli uchburchakga ichki chizilgan aylana uzunligini toping. A) 2√3π B) 12π C) 4√3π D) 3π 6 / 30 Yuzasi 10 ga teng bo’lgan kvadratning ketma-ket ikki uchidan o’tuvchi aylana chizilgan. Uchinchi uchidan aylanaga urunma o’tkazilgan. Urunma tomondan ikki marta katta bo’lsa, aylana radiusini toping. A) 10 B) 4 C) 5 D) 6 7 / 30 Quyidagilardan qaysi biri barcha lar uchun ma’noga ega (aniqlangan)? A) 4k+1/1/8:7-1/56 B) ⁴ᴷ⁺³√-√2k+1 C) (512-1/2⁻⁹)° D) ²ᴷ⁺⁴v2k+1/k²+1 8 / 30 Hisoblang. 11+192+1993+19994+199995+1999996+19999997+199999998+1999999999 A) 222220175 B) 2222222175 C) 222222222222 D) 22222222220 9 / 30 Hisoblang A) 2√3 B) 3√3 C) √3 D) 1 10 / 30 Parallelogrammning tomonlari nisbati 3:5 kabi. Agar parallelogrmmning perimetri 48 ga burchaklaridan biri 1200 ga teng bo’lsa, uning yuzini toping. A) 67,5 B) 135√3/4 C) 48√3 D) 67,5√3 11 / 30 a ning 7x-a-13=(a-5)(x+7) tenglama yechimga ega bo’lmaydigan qiymatining natural bo’luvchilar sonini toping. A) 4 B) 12 C) 8 D) 6 12 / 30 Radiusi 1 ga teng aylana uchta yoyga bo`lingan. Ularga mos markaziy burchaklar 1, 2 va 6 sonlariga proporsional. Yoylardan eng kattasining uzunligini toping. A) 4π/3 B) 3π/2 C) 2π/3 D) 3π/4 13 / 30 Agar arctga+ arctgb + arctgc= bo’lsa, a+b+c ni toping. A) 1 B) abc C) ab/c D) ab 14 / 30 Agar funksiya berilgan bo’lsa, u holda M=ning qiymatini toping. A) e⁻⁵⁰⁵⁰ B) e⁻⁴⁹⁵⁰ C) e⁵⁰⁵⁰ D) e⁴⁹⁵⁰ 15 / 30 Tengsizlik nechta butun yechimga ega? A) 1 B) 4 C) cheksiz ko’p D) 3 16 / 30 AA1A2A3A4A5A6 muntazam oltiburchakli piramidaning hajmi ga va balandligi 2 ga teng bo‘lsa, u holda AA2A6 kesim yuzini toping. A) √15 B) 2 C) √5 D) 3 17 / 30 Agar sinx+cosx=a bo’lsa, ning qiymatini toping. A) -1/2 B) 2/5 C) 1/3 D) 1/2 18 / 30 y= funktsiyaning aniqlanish sohasini toping. A) (-∞;2)v(2;∞) B) (-∞;2) C) [2;∞) D) (2;∞) 19 / 30 Tomoni 25 ga diagonallaridan biri 4 ga teng bo’lgan rombning yuzini toping. A) 24√5 B) 8√5 C) 32 D) 16 20 / 30 Ikki burchagi graduslari yig’indisi uchinchi burchagi gradusidan katta bo’lgan uchburchaklar sonini toping. A) 2019 B) 1 C) cheksiz ko’p D) 0 21 / 30 Markazi O nuqtada bo‘lgan aylanaga PA va PB urinmalar o‘tkazilgan bo’lib, A va B nuqtalar urinish nuqtalari bo’lsin. Aylanadagi Q nuqtadan o‘tkazilgan uchinchi urinma PA va PB kesmalarni X va Y nuqtalarda kesib o‘tadi. Agar XQ=YQ bo‘lsa, u holda PXY uchburchak qanday uchburchak bo‘ladi? A) ixtiyoriy uchburchak B) muntazam uchburchak C) teng yonli uchburchak D) to`g`ri burchakli uchburchak 22 / 30 Ushbu (y6+y3+1)(y3+1)(y3-1)-y6+y3+1 ifodani soddalashtish natijasida ko’phad hosil qilindi. Uning nechta hadi bor? A) 3 B) 4 C) 1 D) 2 23 / 30 ABCD kvadrat ichidan olingan O nuqtadan A, B, C uchlarigacha bo’lgan masofalar mos ravishda 3, 4, 5 ga teng bo’lsa, u holda OD kesma uzunligini toping. A) 3 B) √32 C) √37 D) 6 24 / 30 bo’lsa, ni x orqali ifodalang. A) 25/x B) x/25 C) 2/x D) 2-x 25 / 30 Agar f(x)=sin2x va g(x)=cos2x bo’lsa, u holda f(g(x)) funksiyaning hosilasini toping. A) -4sin2x*cos(2cos2x) B) -4sin2x*cos(cos2x) C) 4sin2x*cos(2cos2x) D) 4sin2x*cos(cos2x) 26 / 30 To’g’ri burchakli uchburchakning gipotenuzasi 13 ga, katetlaridan biri 52 ga teng. Gipotenuzaga tushirilgan balandlik uzunligini toping A) 6 B) 7 C) 4 D) 5 27 / 30 Tomoni 2 ga teng kvadratga tashqi chizilgan aylana uzunligini toping. A) 2π B) 4π C) 2π/3 D) 3π 28 / 30 Agar f(x)=ax3-5x2+b va bo’lsa, a ni toping. A) 2 B) 0 C) 3 D) 1 29 / 30 “Tutgan balig‘ining og‘irligi qancha?” degan savolga baliqchi: “Baliqning dumi 3 kg, boshi uning dumi hamda tanasi yarmining og‘irligiga teng, tanasi esa boshi va dumining og‘irligiga teng”, deb javob berdi. Baliqning og‘irligini (kg) toping. A) 6 B) 12 C) 18 D) 3 30 / 30 qonuniyat bo’yicha harakatlanayotgan moddiy nuqta harakatning 200- metrida qanday tezlikka (m/s) erishadi? A) 38 B) 32 C) 42 D) 36 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
