Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 121 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 1 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 A) 1 B) 0 C) 2 D) √6 2 / 30 Bankda qo`yilgan pul bir yildan kegin foydasi bilan 2600 so`m bo`ldi; Agar bank yillik 30% foyda to`lasa, boshida qancha pul qo`yilgan bo`ladi ? A) 2200 B) 1900 C) 2100 D) 2000 3 / 30 sonning oxirgi raqamini toping. A) 6 B) 2 C) 4 D) 8 4 / 30 Radiuslari orasidagi burchagi 36o va radiusi 5 ga teng bo`lgan sektor yoyining uzunligini toping. A) π B) 2π C) π/2 D) 2π/3 5 / 30 Agar arctga+ arctgb + arctgc= bo’lsa, a+b+c ni toping. A) ab B) ab/c C) abc D) 1 6 / 30 A(2;-2,5) nuqtadan y= - 4x parabolagacha bo’lgan eng qisqa masofani toping. A) 1 B) 1,5 C) √5/2 D) √3/2 7 / 30 Quyidagi 2x-y+3z=2018 va x+5y+z=2019 tekisliklarning holatini aniqlang. A) o’zaro parallel B) ayqash C) aniqlab bo’lmaydi D) o’zaro perpendikulyar 8 / 30 Tenglamani yeching. |x2-11x+10|=x2-11x+10 A) 1; 10 B) (-∞;1]v[10;∞) C) [10;∞) D) (-∞;1] 9 / 30 Tenglamaning ildizlari yig`indisini toping. A) 5 B) 4 C) 3 D) 6 10 / 30 Agar x,y sonlar (x+5)2+(y-12)2=142 tenglikni qanoatlantirsa, x2+y2 ifodaning eng kichik qiymatini toping. A) 1 B) 2 C) √3 D) √2 11 / 30 To’g’ri burchakli uchburchakning yuzi 24 ga, katetlaridan biri 6 ga teng bo’lsa, gipotenuzasini toping A) √46 B) 12 C) 11 D) 10 12 / 30 Tengsizlikni yeching. A) (2;4) B) (-3;2) C) (-3;2)v(2;4) D) (-4;2)v(2;3) 13 / 30 Hisoblang A) 1/2 B) √3 C) 2 D) √3/2 14 / 30 Ikki burchagi graduslari yig’indisi uchinchi burchagi gradusidan katta bo’lgan uchburchaklar sonini toping. A) 0 B) 2019 C) 1 D) cheksiz ko’p 15 / 30 Ushbu (y6+y3+1)(y3+1)(y3-1)-y6+y3+1 ifodani soddalashtish natijasida ko’phad hosil qilindi. Uning nechta hadi bor? A) 2 B) 3 C) 4 D) 1 16 / 30 Soddalashtiring. A) 2018 B) a+1 C) 2019 D) 2018a/a+1 17 / 30 y= funktsiyaning aniqlanish sohasini toping. A) (-∞;2)v(2;∞) B) (2;∞) C) [2;∞) D) (-∞;2) 18 / 30 Teng yonli trpetsiyaning asoslari 15 va 25 ga balandligi esa 15 ga teng trapetsiyaning dioganalini toping A) 28 B) 25 C) 30 D) 20 19 / 30 funktsiyaning aniqlanish sohasini toping. A) (-∞;1)v(2;∞) B) (1;2) C) (-∞;1]v[2;∞) D) [1;2] 20 / 30 Tengsizlik nechta butun yechimga ega? A) 3 B) cheksiz ko’p C) 4 D) 1 21 / 30 Radiusi 25 bo’lgan doirada 48 ga teng vatar o’tkazilgan. Doira markazidan shu vatargacha masofani toping. A) 10 B) 9 C) 7 D) 8 22 / 30 To’rtburchakli muntazam piramidaning yon qirrasidagi ikki yoqli burchak 120 ga teng. Diagonal kesimining yuzasi S ga teng bo’lsa, uning yon sirtini toping. A) 0,5S B) 3S C) 2S D) 4S 23 / 30 To’g’ri to’rtburchakning perimetri 50 ga teng. Bir tomoni boshqa tomonidan 5 ga ko’p. To’g’ri to’rtburchakning yuzini toping. A) 225 B) 60 C) 150 D) 50 24 / 30 Ushbu arifmetik progressiyaning manfiy hadlari yig’indisini toping. A) -0,5 B) -1 C) -0,75 D) -0,25 25 / 30 (-3;4) nuqtaga absissa, ordinata o’qlariga va koordinata boshiga nisbatan simmetrik bo’lgan nuqtalarni tutashtirishdan hosil bo’lgan uchburchakning eng kata tomonini toping. A) 24 B) 10 C) 12 D) 14 26 / 30 To’rtburchakning uchi M (0, 4) ; N(-4,0) ; P(-3;2) uchlari berilgan. Agar bo’lsa, Q uchining koordinatalarini toping. A) (-7;-1) B) (7; 1) C) (-7; 1) D) (4; -3) 27 / 30 y=cos(2sinx) funksiyaning qiymatlar sohasini toping. A) [cos2;1] B) [-1;1] C) [0;1] D) [0;cos2] 28 / 30 ABCD to’gri to’rtburchak ichidan olingan O nuqtadan A, B, C, D uchlarigacha bo’lgan masofalar mos ravishda 3, 4, 5, 6 ga teng bo’lsa, u holda AB tomon uzunligini toping. A) bunday to’gri to’rtburchak mavjud emas B) √7 C) 2 D) √37 29 / 30 Agar geometrik progressiyaning ketma–ket dastlabki uchta hadining yig’indisi 62 ga, ularning o’nli logarifmlari yig’indisi 3 ga teng bo’lsa, shu geometrik progressiyaning birinchi hadini toping. A) 10 B) 2 yoki 50 C) 10 yoki 50 D) 50 30 / 30 ifodaning qiymatini toping. A) -2 B) 0,5 C) 0 D) -0,5 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz