Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 189 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 3 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 Ifodani soddalashtiring. 2 cos55o.cos40o.sin55o+cos110o.sin40o A) 2 B) 1 C) 0,5 D) 0 2 / 30 bo’lsa, ni x orqali ifodalang. A) 25/x B) 2-x C) x/25 D) 2/x 3 / 30 tenglamani yeching. A) 2018 B) 2019 C) 2017 D) 0 4 / 30 sistema a ning qanday qiymatida cheksiz ko’p yechimga ega? A) (-∞;6])v[6;∞) B) 6 C) (2;∞) D) (-∞;6) 5 / 30 Konsert zalining birinchi qatorida 40 ta o’rindiq bor. Har bir keyingi qatordagi o’rindiqlar soni oldingi qatordan 4 ga ko’p. Agar konsert zalida jami 40 ta qator bo’lsa, u holda shu zaldagi barcha o’rindiqlar sonini toping. A) 4716 B) 4760 C) 4720 D) 4680 6 / 30 y=cos(2sinx) funksiyaning qiymatlar sohasini toping. A) [0;cos2] B) [cos2;1] C) [-1;1] D) [0;1] 7 / 30 Quyidagi va to’g’ri chiziqlarning o’zaro holatini aniqlang. A) ayqash to’gri chiziqlar B) o’zaro parallel C) o’zaro perpendikulyar D) o’zaro kesishadi 8 / 30 Ikki burchagi graduslari yig’indisi uchinchi burchagi gradusidan katta bo’lgan uchburchaklar sonini toping. A) 0 B) 1 C) 2019 D) cheksiz ko’p 9 / 30 Tengsizlikni yeching. A) 0 B) to'g'ri javob yo'q C) (0;+∞) D) (-1/³ √2 ;0) 10 / 30 Hisoblang A) 2 B) 1 C) 0 D) -1 11 / 30 Tomoni 25 ga diagonallaridan biri 4 ga teng bo’lgan rombning yuzini toping. A) 8√5 B) 16 C) 32 D) 24√5 12 / 30 O’qishni bilmaydigan bola alifbening A,A,A, N,N, S- 6 ta harflarini ixtiyoriy ravishda terib chiqadi. Bunda ANANAS so’zining hosil bo’lish ehtimolini toping. A) 1/60 B) 6/720 C) 5/720 D) 5/24 13 / 30 Ushbu arifmetik progressiyaning manfiy hadlari yig’indisini toping. A) -0,75 B) -0,25 C) -1 D) -0,5 14 / 30 sistemada xy ning qiymatini toping. A) 64 B) 60 C) 75 D) 80 15 / 30 ABCD kvadrat ichidan olingan O nuqtadan A, B, C uchlarigacha bo’lgan masofalar mos ravishda 3, 4, 5 ga teng bo’lsa, u holda OD kesma uzunligini toping. A) 3 B) √32 C) 6 D) √37 16 / 30 Qaysi javobda faqat juft funksiyalar ko’rsatilgan? A) 1, 3 B) 3, 4 C) 2, 3 D) 1,4 17 / 30 Ushbu (y6+y3+1)(y3+1)(y3-1)-y6+y3+1 ifodani soddalashtish natijasida ko’phad hosil qilindi. Uning nechta hadi bor? A) 2 B) 4 C) 1 D) 3 18 / 30 Agar f(x)=sin2x va g(x)=cos2x bo’lsa, u holda f(g(x)) funksiyaning hosilasini toping. A) 4sin2x*cos(cos2x) B) -4sin2x*cos(2cos2x) C) -4sin2x*cos(cos2x) D) 4sin2x*cos(2cos2x) 19 / 30 A(2;-2,5) nuqtadan y= - 4x parabolagacha bo’lgan eng qisqa masofani toping. A) 1,5 B) √3/2 C) 1 D) √5/2 20 / 30 Tengsizlik nechta butun yechimga ega? A) 4 B) 1 C) cheksiz ko’p D) 3 21 / 30 y= funktsiyaning aniqlanish sohasini toping. A) (-∞;2) B) (2;∞) C) (-∞;2)v(2;∞) D) [2;∞) 22 / 30 tenglamalar sistemasini yeching A) (-4;4) B) (4;4) C) (4;–4) D) (-4;-4) 23 / 30 Tenglamani yeching. (x+2)+(x+4)+(x+6)+…+(x+100)=2800 A) 7 B) 3 C) 5 D) 4 24 / 30 Hisoblang A) √3/2 B) √3 C) 2 D) 1/2 25 / 30 Musobaqada 5 ta ishtirokchidan 3 tasiga 1, 2, 3-o’rinlarni necha xil usulda berish mumkin? A) 47 B) 60 C) 120 D) 18 26 / 30 Rasmda ko‘rsatilgan ko‘pyoqlardan qaysi birida 4 ta yoq, 6 ta qirra bor? A) 3 B) 1, 2 C) 1, 3 D) 2 27 / 30 qonuniyat bo’yicha harakatlanayotgan moddiy nuqta harakatning 200- metrida qanday tezlikka (m/s) erishadi? A) 32 B) 42 C) 38 D) 36 28 / 30 Tomoni 2 ga teng kvadratga tashqi chizilgan aylana uzunligini toping. A) 4π B) 2π/3 C) 2π D) 3π 29 / 30 Radiuslari orasidagi burchagi 36o va radiusi 5 ga teng bo`lgan sektor yoyining uzunligini toping. A) 2π B) 2π/3 C) π D) π/2 30 / 30 a(x+2)=2x+1 tenglama a ning qanday qiymatida yechimga ega emas? A) (2;∞) B) (-∞;2)v(2;∞) C) (-∞;2) D) (∞;∞) 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
