Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 198 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 funktsiyaning aniqlanish sohasini toping. A) (-∞;1)v(2;∞) B) (-∞;1]v[2;∞) C) (1;2) D) [1;2] 2 / 30 |x2-5x-14|+20≥5|x+2|+4|x-7| tengsizlikni yeching. A) [1;6] B) [-2;4]v{6} C) [2;4]v{2}v[3;∞) D) (-∞;-6]v{2}v[12;∞) 3 / 30 Hisoblang. 11+192+1993+19994+199995+1999996+19999997+199999998+1999999999 A) 222222222222 B) 222220175 C) 22222222220 D) 2222222175 4 / 30 A) 1 B) 2 C) 3 D) 5 5 / 30 Ushbu funksiyaning boshlang’ich funksiyasini toping. A) ln|x-1/x+4|+c B) ln(|x+4+|x-1|)+c C) ln(|x+4*|x-1|)+c D) ln|x+4/x-1|+c 6 / 30 Bir vaqtning o’zida 9,13, . . . ,405 va 15,21, . . . ,255 ketma–ketliklarning hadlari bo’lgan sonlarning eng kattasi va eng kichigining ayirmasini toping A) 231 B) 150 C) 147 D) 228 7 / 30 Rombning yuzi 96 ga, dioganallaridan biri 16 ga teng. Romb tomonini toping. A) 12 B) 10 C) 9 D) 11 8 / 30 Tomoni 12 ga teng bo`lgan teng tomonli uchburchakga ichki chizilgan aylana uzunligini toping. A) 4√3π B) 2√3π C) 3π D) 12π 9 / 30 Arifmetik progressiyada a17=33 va a45=89. Progressiyaning birinchi hadi hamda ayirmasining o’rta geometrigini toping. A) √2 B) 2 C) 2√2 D) 4 10 / 30 a=sin 1; b=sin 2; c=sin 3; d=sin 4 va e=sin 5 sonlarni kamayish tartibida joylashtiring. A) e>b>a>d>c B) a>b>c>d>e C) b>a>c>d>e D) b>c>a>d>e 11 / 30 sistemada xy ning qiymatini toping. A) 75 B) 60 C) 80 D) 64 12 / 30 sistema a ning qanday qiymatida cheksiz ko’p yechimga ega? A) (2;∞) B) (-∞;6])v[6;∞) C) (-∞;6) D) 6 13 / 30 sistemadan x+y+z ning qiymatini toping. A) 150/41 B) -139/41 C) 139/41 D) 140/41 14 / 30 Radiusi 25 bo’lgan doirada 48 ga teng vatar o’tkazilgan. Doira markazidan shu vatargacha masofani toping. A) 10 B) 8 C) 9 D) 7 15 / 30 Parallelogrammning yuzi 213 ga, tomonlaridan biri 7 ga va o’tkir burchagi 600 ga teng bo’lsa, ikkinchi tomonini toping A) 8 B) 6 C) 4 D) 5 16 / 30 x(t)=t2+7t-6 qonuniyat bo’yicha harakatlanayotgan moddiy nuqtaning tezligi harakat boshlangandan necha sekund o’tgach 87 m/s ga teng bo’ladi? A) 40 B) 50 C) 36 D) 54 17 / 30 Tenglamani yeching. |x2-11x+10|=x2-11x+10 A) [10;∞) B) 1; 10 C) (-∞;1] D) (-∞;1]v[10;∞) 18 / 30 To’rtburchakning uchi M (0, 4) ; N(-4,0) ; P(-3;2) uchlari berilgan. Agar bo’lsa, Q uchining koordinatalarini toping. A) (-7;-1) B) (-7; 1) C) (4; -3) D) (7; 1) 19 / 30 sin2x-cos2x=1 tenglama [-π; 2π] oraliqda nechta ildizga ega? A) 6 B) 9 C) 10 D) 7 20 / 30 n ning qanday qiymatida ushbu 81 .82 .83 .….8n=51222 tenglik o’rinli bo’ladi? A) 12 B) 10 C) 14 D) 11 21 / 30 Markazi O nuqtada bo‘lgan aylanaga PA va PB urinmalar o‘tkazilgan bo’lib, A va B nuqtalar urinish nuqtalari bo’lsin. Aylanadagi Q nuqtadan o‘tkazilgan uchinchi urinma PA va PB kesmalarni X va Y nuqtalarda kesib o‘tadi. Agar XQ=YQ bo‘lsa, u holda PXY uchburchak qanday uchburchak bo‘ladi? A) muntazam uchburchak B) to`g`ri burchakli uchburchak C) ixtiyoriy uchburchak D) teng yonli uchburchak 22 / 30 Tenglamaning ildizlari yig`indisini toping. A) 4 B) 5 C) 3 D) 6 23 / 30 Ifodani soddalashtiring. [ln(ln x)-ln(loge10)].log10e A) ln(lg x) B) lg(ln x) C) lg(lg x) D) ln(ln x) 24 / 30 200 kishidan iborat turistlar guruxida 140 kishi ingliz tilini, 90 kishi nemis tilini va 46 kishi ikkala tilni biladi. Ikkala tilni xam bilmaydigan turistlar necha foizni tashkil qiladi. A) 4 B) 12 C) 8 D) 16 25 / 30 To’g’ri burchakli uchburchakning gipotenuzasi 13 ga, katetlaridan biri 52 ga teng. Gipotenuzaga tushirilgan balandlik uzunligini toping A) 5 B) 4 C) 7 D) 6 26 / 30 x(t)=t2+6t+5 qonuniyat bo’yicha harakatlanayotgan moddiy nuqta harakat boshlangandan necha sekund o’tgach boshlang’ich nuqtaga nisbatan 77 metr masofaga siljiydi? A) 8 B) 7 C) 6 D) 10 27 / 30 Ag ar tgα=2 bo’lsa, u holda ni hisoblang A) 10/3 B) 10/27 C) -10/3 D) -10/27 28 / 30 Tomoni 6 ga teng bo`lgan teng tomonli uchburchakga tashqi chizilgan doiraning yuzini toping. A) 12π B) 10 π C) 7 π D) 6 π 29 / 30 Ostki asosining yuzi 20π va ustki asosining yuzi 10π ga teng bo‘lgan kesik konus berilgan. Agar kesik konusga shar ichki chizilgan bo‘lsa, u holda kesik konus hajmining shar hajmiga nisbatini toping. A) 2√2/3 B) 5√3+3/3 C) 3√3+1/5 D) 3√2+2/4 30 / 30 Agar va b-a=4 bo’lsa, a+b ni toping. A) 4 B) 3 C) 2 D) 3,5 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz