Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 247 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 Bir vaqtning o’zida 9,13, . . . ,405 va 15,21, . . . ,255 ketma–ketliklarning hadlari bo’lgan sonlarning eng kattasi va eng kichigining ayirmasini toping A) 147 B) 228 C) 231 D) 150 2 / 30 Agar bank qo`yilgan pulga 40% yillik foyda bersa, qo`yilgan 5000 so`m pul bir yildan keyin qancha bo`ladi ? A) 7000 B) 7200 C) 6200 D) 6900 3 / 30 Rasmda ko‘rsatilgan ko‘pyoqlardan qaysi birida 4 ta yoq, 6 ta qirra bor? A) 1, 3 B) 1, 2 C) 2 D) 3 4 / 30 Teng yonli uchburchakning tomonlari 5, 5 va 6 ga teng. Bu uchburchakning bissektiritsalari va medianalari kesishgan nuqtalar A) 1/6 B) 1,2 C) 1/2 D) 1 5 / 30 Arifmetik progressiyada a17=33 va a45=89. Progressiyaning birinchi hadi hamda ayirmasining o’rta geometrigini toping. A) 2 B) √2 C) 4 D) 2√2 6 / 30 ABCD kvadrat ichidan olingan O nuqtadan A, B, C uchlarigacha bo’lgan masofalar mos ravishda 3, 4, 5 ga teng bo’lsa, u holda OD kesma uzunligini toping. A) 3 B) √37 C) √32 D) 6 7 / 30 a=sin 1; b=sin 2; c=sin 3; d=sin 4 va e=sin 5 sonlarni kamayish tartibida joylashtiring. A) b>a>c>d>e B) b>c>a>d>e C) a>b>c>d>e D) e>b>a>d>c 8 / 30 Hisoblang A) 1/2 B) √3 C) 2 D) √3/2 9 / 30 Ostki asosining yuzi 20π va ustki asosining yuzi 10π ga teng bo‘lgan kesik konus berilgan. Agar kesik konusga shar ichki chizilgan bo‘lsa, u holda kesik konus hajmining shar hajmiga nisbatini toping. A) 3√2+2/4 B) 5√3+3/3 C) 2√2/3 D) 3√3+1/5 10 / 30 Bog’bon uch kun davomida o’nta daraxt ko’chati o’tqazishi lozim. Agar bog’bon bir kunda eng kamida bitta ko’chat o’tqazadigan bo’lsa, u shu ishni kunlar bo’yicha necha xil usul bilan taqsimlashi mumkin? A) 32 B) 30 C) 36 D) 25 11 / 30 To’rtburchakli muntazam piramidaning yon qirrasidagi ikki yoqli burchak 120 ga teng. Diagonal kesimining yuzasi S ga teng bo’lsa, uning yon sirtini toping. A) 4S B) 3S C) 2S D) 0,5S 12 / 30 Rombning balandligi 8 ga dioganallarining ko’paytmasi 80 ga teng. Rombning perimetrini toping A) 32 B) 20 C) 24 D) 16 13 / 30 Ikki burchagi graduslari yig’indisi uchinchi burchagi gradusidan katta bo’lgan uchburchaklar sonini toping. A) 1 B) 2019 C) 0 D) cheksiz ko’p 14 / 30 ifodaning qiymatini toping. A) -2 B) -0,5 C) 0 D) 0,5 15 / 30 funksiya uchun quyidagi mulohazalardan qaysi biri o’rinli? A) toq funksiya B) juft ham emas, toq ham emas funksiya C) juft funksiya D) bunday funksiya mavjud emas 16 / 30 Ushbu arifmetik progressiyaning manfiy hadlari yig’indisini toping. A) -0,5 B) -1 C) -0,75 D) -0,25 17 / 30 O’qishni bilmaydigan bola alifbening A,A,A, N,N, S- 6 ta harflarini ixtiyoriy ravishda terib chiqadi. Bunda ANANAS so’zining hosil bo’lish ehtimolini toping. A) 5/24 B) 1/60 C) 6/720 D) 5/720 18 / 30 Tomoni 6 ga teng bo`lgan teng tomonli uchburchakga tashqi chizilgan doiraning yuzini toping. A) 6 π B) 12π C) 7 π D) 10 π 19 / 30 y= funktsiyaning aniqlanish sohasini toping. A) (-∞;2)v(2;∞) B) (2;∞) C) (-∞;2) D) [2;∞) 20 / 30 A) 2 B) 0 C) √6 D) 1 21 / 30 Rombning yuzi 96 ga, dioganallaridan biri 16 ga teng. Romb tomonini toping. A) 12 B) 9 C) 10 D) 11 22 / 30 Agar va b-a=4 bo’lsa, a+b ni toping. A) 4 B) 3,5 C) 3 D) 2 23 / 30 x2-5|x|-6=0 tenglama ildizini toping A) ±6 B) -1;-6 C) -1;6 D) ±;±6 24 / 30 To‘g‘ri to‘rtburchakning eni 25% ga orttirildi, bo‘yi esa 25% ga kamaytirildi. Natijada uning yuzi qanday o‘zgardi? A) 6,25% ga ortadi B) 2,5% ga ortadi C) o‘zgarmaydi D) 6,25% ga kamayadi 25 / 30 Muntazam uchburchakli piramidaning yon qirrasi asos tekisligi bilan 45o li burchak tashkil etgan bo‘lsa, u holda piramidaning yon sirti yuzining uning asosi yuziga nisbatini toping. A) 4 B) 2√3 C) 2√5 D) 3√3 26 / 30 tenglamalar sistemasini yeching A) (3;–4) B) (4;–3) C) (–4;3) D) (4;3) 27 / 30 x(t)=t2+6t+5 qonuniyat bo’yicha harakatlanayotgan moddiy nuqta harakat boshlangandan necha sekund o’tgach boshlang’ich nuqtaga nisbatan 77 metr masofaga siljiydi? A) 8 B) 7 C) 10 D) 6 28 / 30 Musobaqada 5 ta ishtirokchidan 3 tasiga 1, 2, 3-o’rinlarni necha xil usulda berish mumkin? A) 47 B) 60 C) 18 D) 120 29 / 30 Hisoblang. 11+192+1993+19994+199995+1999996+19999997+199999998+1999999999 A) 222222222222 B) 22222222220 C) 2222222175 D) 222220175 30 / 30 Anvar tub son o’yladi va o’ylagan sonini 5 ga ko’paytirib, 8 ni ayirgan edi, yana tub son hosil bo’ldi. Anvar qanday son o’ylagan? A) 412967 B) 2 C) 374389 D) aniqlab bo’lmaydi 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz