Uy » Choraklik online testlar » Fizika choraklik » 7-sinf Fizika 4-chorak Fizika choraklik 7-sinf Fizika 4-chorak InfoMaster Aprel 26, 2021 1072 Ko'rishlar 0 SaqlashSaqlanganOlib tashlandi 1 0 Tomonidan yaratilgan InfoMaster 7-sinf Fizika 4-chorak Testni Vafaqulov Alisher tayyorladi. 1 / 25 Jismning harakat tenglamasi x = 2 – 3 t + 2 t2 formula bilan berilgan. Bu harakat uchun tezlik tenglamasini yozing A) υ= - 3 + 4 t B) υ= 4 + 3 t C) υ = 4 t D) υ= 4 - 3 t 2 / 25 Jism tezlik proporsiyasining vaqtga bog’lanish v = 3+2t (m/s) ko’rinishga ega. Ko’chish proyeksiyasining vaqtga bog’lanishi qanday? A) S = 2t² B) S = 3t + 2 t² C) S = 3t + 1 t² D) S = 2t + 3 ² 3 / 25 Tezlanish formulasi qanday ifodalanadi A) a = (v - v˳)/t B) p = F / S C) S = at² / 2 D) p = m / v 4 / 25 Avtomobil 5 m/s2 tezlanish bilan tinch holatdan harakat boshladi. U 4s da necha metr yo’l o’tadi? A) 20 B) 40 C) 10 D) 30 5 / 25 Joyidan qo’zg’algan jism 0,2 m/s2 tezlanish bilan harakatlanganda 1 minutda u qanday tezlikka erishadi A) 120 m/s B) 0,12 m/s C) 1,2 m/s D) 12 m/s 6 / 25 25 m/s tezlik bilan yuqoriga tik otilgan jismning 2 s dan keyingi tezligi qancha bo’ladi? A) 20 m/s B) 10 m/s C) 5 m/s D) 15 m/s 7 / 25 Aylanma tekis harakatdagi chiziqli tezlik formulasini ko’rsating. 1) V=2¶R/T, 2) V=wR, 3)V=2¶RV A) 1 B) 1,2,3 C) 2 D) 3 8 / 25 Soatning sekund mili burchakli tezligini toping. (rad/s) A) π/2600 B) π/30 C) π/10 D) π/1800 9 / 25 Aylanma tekis harakatga chiziqli tezlik va burchakli tezlik bog’lanish formulasini ko’rsating A) ω=2p/T B) υ=2pR/T C) υ=ωR D) ω=2p υ 10 / 25 Soatning minut mili burchakli tezligini toping A) π/30 B) π/10 C) π/1800 D) π/2600 11 / 25 Agar moddiy nuqta aylana bo’ylab teng vaqtlar orasida teng yollarni bosib o’tsa, bunday harakat ....... harakat deyiladi A) tekis aylanma tezlik B) tekis C) aylanma o’zgaruvchan D) notekis 12 / 25 Markazga intilma tezlanish formulasi qaysi ifodada to'g'ri ko’rsatilgan? A) a=(v-v˳)/t B) a=v²/R C) a=v/t D) a=F/m 13 / 25 Aylanish davri bilan chiziqli tezligi orasidagi munosabat formulasini toping. A) V=wR B) V=2¶R/T C) V=S/t D) V=at 14 / 25 Liftdagi odam o’ta yuklanishga duch kelishi mumkinmi? A) Xa lift tezlanish bilan pastga tushganda B) Yo’q C) Xa lift yuqoriga ko’tarilganda D) Xa agar lift tezlanish bilan yuqoriga ko’tarilsa 15 / 25 Yerning quyosh atrofida aylanish tezligi nimaga teng A) 30 km/s B) 1 km/s C) 10 km/s D) 40 km/s 16 / 25 Oyning yer atrofida aylanish tezligi nimaga teng A) 10 km/s B) 40 km/s C) 1 km/s D) 30 km/s 17 / 25 Raketa quyosh sistemasini tark etishi uchun u yerdan 16,7 km/s tezlik bilan uchirilishi kerak. Bu tezlikni nomi A) notekis tezlik B) 1-kosmik tezlik C) 3-kosmik tezlik D) 2-kosmik tezlik 18 / 25 Yerning tortishish kuchi ta’sirida jismning yer atrofida aylana bo’ylab, harakatlanishida erishtiradigan tezlik ………. deyiladi A) 2-kosmik tezlik B) 1-kosmik tezlik C) notekis tezlik D) 3-kosmik tezlik 19 / 25 Yer uchun uchunchi kosmik tezlik qiymatini ko’rsating A) 7,9 m/s B) 7,9 km/s C) 16,7 km/s D) 11,2 km/s 20 / 25 60 N kuch jismga 0,8 m/s2 tezlanish beradi. Qanday kuch bu jismga 2 m/s2 tezlanish beradi? A) 150 N B) 24 N C) 240 N D) 15 N 21 / 25 Qaysi shart bajarilganda, jism suyuqlikda tekis cho’ka boshlaydi? (mg-og’irlik kuchi, Fa- Arximed kuchi, F-qarshilik kuchi) 1) m g > F = F a 2) m g = F 3) m g = F = F a 4) mg < F = F a A) 3 B) 1 C) 4 D) 2 22 / 25 Massasi m = 10 kg bo’lgan jismga 25 N kuch ta’sir qilmoqda. Shu kuch ta’sirida u qanday tezlanish bilan harakat qiladi? A) 3 m / s² B) 2,5 m / s² C) 6 m / s ² D) 1 m / s² 23 / 25 Massasi 0,5 kg bo’lgan koptokka 0,02 s davomida zarb berilgandan keyin u 10 m / s tezlik oladi. Zarbning o’rtacha kuchini toping A) 1000 N B) 200 N C) 250 N D) 500 N 24 / 25 Odam liftda turibdi. Odamga ta’sir qiluvchi kuchlar: mg – og’irlik kuchi, N – tayanch reaksiya kuchi, Lift yuqorida to’xtashdan oldin sekinlashganda kuchlar orasidagi munosabatni ko’rsating. Lift yuqorida to’xtashdan oldin sekinlashyapti 1) mg > N 2) mg < N 3) mg = N 4) mg = 0; N = 0 A) 1 B) 2 C) 4 D) 3 25 / 25 Odam liftda turibdi. Odamga ta’sir qiluvchi kuchlar: mg – og’irlik kuchi, N – tayanch reaksiya kuchi, Lift pastda to’xtashdan oldin sekinlashganda kuchlar orasidagi munosabatni ko’rsating. Lift pastda to’xtashdan oldin sekinlashyapti 1) mg > N 2) mg < N 3) mg = N 4) mg = 0; N = 0 A) 2 B) 4 C) 3 D) 1 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz