Uy » Choraklik online testlar » Fizika choraklik » 7-sinf Fizika 4-chorak Fizika choraklik 7-sinf Fizika 4-chorak InfoMaster Aprel 26, 2021 1103 Ko'rishlar 0 SaqlashSaqlanganOlib tashlandi 1 1 Tomonidan yaratilgan InfoMaster 7-sinf Fizika 4-chorak Testni Vafaqulov Alisher tayyorladi. 1 / 25 Soatning minut mili aylanishining chastotasini toping.(Hz) A) 1/100 B) 1/3600 C) 1/7200 D) 100 2 / 25 Uzunligi 25 sm bo’lgan ipga bog’langan sharcha 5 m/s chiziqli tezlik bilan aylanmoqda. Sharning markaziga intilma tezlanishini toping. (m/s2) A) 1 B) 100 C) 2 D) 10 3 / 25 Velosiped raridusi 25 m bo’lgan aylanma yo’lda 10 m/s tezlik bilan tekis harakatlanmoqda. Uning markazga intilma tezlanishini toping. (m/s²) A) 2 B) 3 C) 5 D) 4 4 / 25 Aylanma tekis harakatda chiziqli tezlik bilan burchak tezlik orasidagi munosabat formulasini ko’rsating A) w=2¶V B) w=2¶/T C) V=wR D) w=4/t 5 / 25 Soatning minut mili burchakli tezligini toping A) π/30 B) π/10 C) π/1800 D) π/2600 6 / 25 Aylanma tekis harakatdagi chiziqli tezlik formulasini ko’rsating. 1) V=2¶R/T, 2) V=wR, 3)V=2¶RV A) 1,2,3 B) 3 C) 2 D) 1 7 / 25 Agar jism biror balandlikdan ikki baravar katta tezlik bilan gorizantal otilsa, uning uchish vaqti qanday o’zgaradi A) o’zgarmaydi B) 2 marta kamayadi C) 2 marta ortadi D) 4 martta ortadi 8 / 25 Raketa quyosh sistemasini tark etishi uchun u yerdan 16,7 km/s tezlik bilan uchirilishi kerak. Bu tezlikni nomi A) 3-kosmik tezlik B) 1-kosmik tezlik C) 2-kosmik tezlik D) notekis tezlik 9 / 25 Zambarakdan gorizantga burchak ostida uchib chiqqan snaryad 12 sekund uchgan. Snaryad ko’tarilgan eng yuqori balandlik qancha A) 180m B) 20m C) 360m D) 10m 10 / 25 Lift a A) (P=mg) B) P=m(g+a) C) P=m(g-a) D) P=m(a-g) 11 / 25 Yerga tortilishi tufayli jismning tayanchga yoki osmaga tasr etadigan kuchi .......... deb ataladi A) og’irlik kuchi B) jism og’irligi C) reaksiya kuchi D) bosim kuchi 12 / 25 Jismning yerga tortilish kuchi …… deb ataladi A) reaksiya kuchi B) og’irlik kuchi C) bosim kuchi D) jism og’irligi 13 / 25 Odam liftda turibdi. Odamga ta’sir qiluvchi kuchlar: mg – og’irlik kuchi, N – tayanch reaksiya kuchi, Lift yuqorida to’xtashdan oldin sekinlashganda kuchlar orasidagi munosabatni ko’rsating. Lift yuqorida to’xtashdan oldin sekinlashyapti 1) mg > N 2) mg < N 3) mg = N 4) mg = 0; N = 0 A) 1 B) 3 C) 2 D) 4 14 / 25 Odam liftda turibdi. Odamga ta’sir qiluvchi kuchlar: mg – og’irlik kuchi, N – tayanch reaksiya kuchi, Lift tinch turganda kuchlar orasidagi munosabatni ko’rsating 1) mg > N 2) mg < N 3) mg = N 4) mg = 0; N = 0 A) 4 B) 3 C) 1 D) 2 15 / 25 Motosikl botiq ko’prik ustida tekis harakatlanmoqda. Ko’prikning eng quyi nuqtasiga yetganida unga qo’yilgan kuchlarning teng ta’sir etuvchisi qanday yo’nalgan bo’ladi? A) Orqaga B) Oldinga C) Yuqoriga D) Pastga 16 / 25 Gorizontal tekislikda yotgan 6 kg massali jism qanday kuch ta’sirida 1s da 2 m/s tezlikka erishadi? Jismga ta’sir etayotgan ishqalanish kuchi 4 N ga teng deb xisoblang A) 16 B) 8 C) 4 D) 12 17 / 25 1 m/s2 tezlanish bilan tushayotgan liftdagi 20 kg massali bolaning og’irligi qancha? A) 170 N B) 200 N C) 190 N D) 180 N 18 / 25 Qaysi shart bajarilganda, jism suyuqlikda tekis cho’ka boshlaydi? (mg-og’irlik kuchi, Fa- Arximed kuchi, F-qarshilik kuchi) 1) m g > F = F a 2) m g = F 3) m g = F = F a 4) mg < F = F a A) 1 B) 3 C) 4 D) 2 19 / 25 Jism 20 m/s tezlik bilan tik yuqoriga otildi. Jism necha sekund eng baland nuqtasigacha ko’tariladi? g = 10 m/s2 A) 4 c B) 1 c C) 3 c D) 2 c 20 / 25 Erkin tushish deb qaysi harakatga aytiladi A) qo’ldan qo’yib yuborgan jism harakatiga B) jismga hech qanday kuch ta’sir qilmagandagi harakatiga C) jismning havosiz joyda faqat yerning tortish ta’sridagi harakatiga D) xar qanday harakatga 21 / 25 Jism tekis tezlanuvchan harakat boshlab, 3-sekundda 5 m yo’l o’tdi. U harakatning boshlang’ich 3 sekundida qanday yo’l o’tadi (m) ? A) 13 B) 9 C) 7 D) 11 22 / 25 Balkondan boshlang’ich tezliksiz tushib ketgan jism 1 s da yerga etib kelgan bo’lsa, u qanday balandlikdan (m) tushgan? A) 20 B) 10 C) 5 D) 15 23 / 25 Erkin tushib harakat qilayotgan jismning tezligi har sekundda qanchaga o’zgaradi A) 5 m/s B) 10 m/s C) 15 m/s D) o’zgarmaydi 24 / 25 Tezlanish formulasi qanday ifodalanadi A) S = at² / 2 B) a = (v - v˳)/t C) p = m / v D) p = F / S 25 / 25 Tezlanishning o’lchov birligini ko’rsating A) m/s B) m/s² C) s/ m² D) m²/s 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz