Uy » Choraklik online testlar » Fizika choraklik » 7-sinf Fizika 4-chorak Fizika choraklik 7-sinf Fizika 4-chorak InfoMaster Aprel 26, 2021 1043 Ko'rishlar 0 SaqlashSaqlanganOlib tashlandi 1 0 Tomonidan yaratilgan InfoMaster 7-sinf Fizika 4-chorak Testni Vafaqulov Alisher tayyorladi. 1 / 25 Agar jism biror balandlikdan ikki baravar katta tezlik bilan gorizantal otilsa, uning uchish vaqti qanday o’zgaradi A) 2 marta kamayadi B) 2 marta ortadi C) 4 martta ortadi D) o’zgarmaydi 2 / 25 Oyning yer atrofida aylanish tezligi nimaga teng A) 40 km/s B) 30 km/s C) 1 km/s D) 10 km/s 3 / 25 Yer sirtidagi jism yerga F kuch bilan tortilmoqda. Yer sirtidan h=2R balandlikka ko’tarilsa yerga qanday kuch bilan tortiladi? R-Ep radus A) F/16 B) F/2 C) F/4 D) F/9 4 / 25 Aylanma tekis harakatda aylanish davri va chastotasi bog’lanishi formulasini ko’rsating A) T=1/v B) t=T*N C) T=t/N D) T=2¶R/V 5 / 25 Soatning minut mili aylanishining chastotasini toping.(Hz) A) 1/100 B) 1/7200 C) 100 D) 1/3600 6 / 25 Velosiped raridusi 25 m bo’lgan aylanma yo’lda 10 m/s tezlik bilan tekis harakatlanmoqda. Uning markazga intilma tezlanishini toping. (m/s²) A) 4 B) 2 C) 5 D) 3 7 / 25 Avtomabil 200 m radiusli aylana yo’lda 72 km/soat tezlik bilan harakatlanadi. Uning markaziga intilma tezlanishi qancha m/s2 ga teng? A) 2 B) 4 C) 5 D) 3 8 / 25 Aylana bo’ylab tekis harakatda markazga intilma tezlanish formulasini ko’rsating. 1) a=v2/R, 2) a=v2/2R, 3) a=v/t A) 1 B) 2 C) 1,2 D) 3 9 / 25 Aylanma tekis harakatda tezlanish qanday yo’nalgan? A) radius bo’ylab markazdan B) xar xil yo’nalgan bo’lishi mumkin C) urinma bo’ylab D) radius bo’ylab markazga 10 / 25 Avtomabil 90 km/soat tezlik bilan tekis harakatlanmoqda. Agar avtomobil g’ildiragining raidusi 35 sm bo’lsa, g’ildirak markazidan shuncha masofa uzoqlikdagi nuqtasining markaziga intilma tezlanishini toping. (m/s2) A) 2800 B) 2000 C) 1786 D) 50 11 / 25 Soatning 30 mm uzunlikdagi minut uchi 10 minutda 31,4 mm uzunlikdagi yo’lni bosib o’tdi. Minut mili uchining burilish burchagini toping. (rad) A) 5 rad B) 1,05 rad C) 4 rad D) 3 rad 12 / 25 Soatning vaqt mili burchakli tezligini toping. (rad/s) A) π/30 B) π/1800 C) π/10 D) π/2600 13 / 25 Burchakli ko’chishning vaqtga nisbati qanday fizik kattalik? A) tezlanish B) chastota C) davr D) burchakli tezlik 14 / 25 1000 mN necha N? A) 70 B) 1 C) 10 D) 400 15 / 25 Massasi m = 10 kg bo’lgan jismga 25 N kuch ta’sir qilmoqda. Shu kuch ta’sirida u qanday tezlanish bilan harakat qiladi? A) 3 m / s² B) 1 m / s² C) 6 m / s ² D) 2,5 m / s² 16 / 25 Nyutonning 2-qonuni formulasini ko’rsating A) a = F / m B) a = v/t C) a = v² /R D) a = 2s/ t² 17 / 25 Odam liftda turibdi. Odamga ta’sir qiluvchi kuchlar: mg – og’irlik kuchi, N – tayanch reaksiya kuchi, Lift yuqorida to’xtashdan oldin sekinlashganda kuchlar orasidagi munosabatni ko’rsating. Lift yuqorida to’xtashdan oldin sekinlashyapti 1) mg > N 2) mg < N 3) mg = N 4) mg = 0; N = 0 A) 1 B) 3 C) 2 D) 4 18 / 25 Qaysi shart bajarilganda, jism suyuqlikda tekis cho’ka boshlaydi? (mg-og’irlik kuchi, Fa- Arximed kuchi, F-qarshilik kuchi) 1) m g > F = F a 2) m g = F 3) m g = F = F a 4) mg < F = F a A) 1 B) 2 C) 3 D) 4 19 / 25 Gorizontal tekislikda yotgan 6 kg massali jism qanday kuch ta’sirida 1s da 2 m/s tezlikka erishadi? Jismga ta’sir etayotgan ishqalanish kuchi 4 N ga teng deb xisoblang A) 12 B) 4 C) 8 D) 16 20 / 25 Joyidan qo’zg’algan jism 0,2 m/s2 tezlanish bilan harakatlanganda 1 minutda u qanday tezlikka erishadi A) 0,12 m/s B) 12 m/s C) 120 m/s D) 1,2 m/s 21 / 25 Avtomobil 5 m/s2 tezlanish bilan tinch holatdan harakat boshladi. U 4s da necha metr yo’l o’tadi? A) 40 B) 10 C) 20 D) 30 22 / 25 Tekis tezlanuvchan harakat qilayotgan “Matiz” 10 s davomida tezligini 54 km / soat dan 100 km / soat ga oshirdi. «Matiz»ning tezlanishini toping A) 2,5 m/s² B) 15 m/s² C) 13 m/s² D) 3 m/s² 23 / 25 Boshlang’ich tezliksiz erkin tushayotgan jism 3-sekund ichida qanday masofani o’tadi? g = 10 m/s2 A) 5 m/s B) 10 m/s C) 25 m/s D) 15 m/s 24 / 25 Jismning harakat tenglamasi x = 2 – 3 t + 2 t2 formula bilan berilgan. Bu harakat uchun tezlik tenglamasini yozing A) υ = 4 t B) υ= - 3 + 4 t C) υ= 4 + 3 t D) υ= 4 - 3 t 25 / 25 Jism harakat tenglamasi x=5+3t–t2 formula bilan berilgan. Jismning boshlang’ich koordinatasi nimaga teng? A) 9 m B) 1 m C) 5 m D) 3 m 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz