Uy » Choraklik online testlar » Fizika choraklik » 7-sinf Fizika 4-chorak Fizika choraklik 7-sinf Fizika 4-chorak InfoMaster Aprel 26, 2021 1051 Ko'rishlar 0 SaqlashSaqlanganOlib tashlandi 1 0 Tomonidan yaratilgan InfoMaster 7-sinf Fizika 4-chorak Testni Vafaqulov Alisher tayyorladi. 1 / 25 Massasi m = 10 kg bo’lgan jismga 25 N kuch ta’sir qilmoqda. Shu kuch ta’sirida u qanday tezlanish bilan harakat qiladi? A) 6 m / s ² B) 2,5 m / s² C) 1 m / s² D) 3 m / s² 2 / 25 Gorizontal tekislikda yotgan 6 kg massali jism qanday kuch ta’sirida 1s da 2 m/s tezlikka erishadi? Jismga ta’sir etayotgan ishqalanish kuchi 4 N ga teng deb xisoblang A) 8 B) 4 C) 12 D) 16 3 / 25 Agar reaktiv samolyot dvigatelining tortish kuchi 90 k N bo’lsa, massasi 60 t bo’lgan samolyot tezlik olish vaqtida qanday tezlanish bilan harakatlanadi? A) 0,5 m/s² B) 0 C) 1 m/s² D) 2 m/s² 4 / 25 Massasi 0,5 kg bo’lgan koptokka 0,02 s davomida zarb berilgandan keyin u 10 m / s tezlik oladi. Zarbning o’rtacha kuchini toping A) 200 N B) 250 N C) 1000 N D) 500 N 5 / 25 Massasi 4 kg bo’lgan jism biror kuch ta’siri ostida 2 m/s2 tezlanish oldi. Shunday kuch ta’siri ostida massasi 10 kg bo’lgan jism qanday tezlanish oladi? A) 1 m/s² B) 0,8 m/s² C) 2 m/s² D) 0 6 / 25 Ko’tarilish balandligi 4 marta ortishi uchun yuqoriga otilgan jismning boshlang’ich tezligini necha marta oshirish lozim A) 50 martta B) 55 martta C) 45 martta D) 60 martta 7 / 25 Yer uchun ikkinchi kosmik tezlik qiymatini ko’rsating A) 11,2 km/s B) 7,9 m/s C) 16,7 km/s D) 7,9 km/s 8 / 25 Raketa quyosh sistemasini tark etishi uchun u yerdan 16,7 km/s tezlik bilan uchirilishi kerak. Bu tezlikni nomi A) 2-kosmik tezlik B) notekis tezlik C) 1-kosmik tezlik D) 3-kosmik tezlik 9 / 25 Agar jism biror balandlikdan ikki baravar katta tezlik bilan gorizantal otilsa, uning uchish uzoqligi qanday o’zgaradi A) 2 marta ortadi B) o’zgarmaydi C) 2 marta kamayadi D) 4 martta ortadi 10 / 25 Yer uchun uchunchi kosmik tezlik qiymatini ko’rsating A) 7,9 m/s B) 16,7 km/s C) 11,2 km/s D) 7,9 km/s 11 / 25 Velosiped raridusi 25 m bo’lgan aylanma yo’lda 10 m/s tezlik bilan tekis harakatlanmoqda. Uning markazga intilma tezlanishini toping. (m/s²) A) 5 B) 3 C) 2 D) 4 12 / 25 Agar moddiy nuqta aylana bo’ylab teng vaqtlar orasida teng yollarni bosib o’tsa, bunday harakat ....... harakat deyiladi A) notekis B) tekis C) tekis aylanma tezlik D) aylanma o’zgaruvchan 13 / 25 Aylanish davri bilan chiziqli tezligi orasidagi munosabat formulasini toping. A) V=S/t B) V=2¶R/T C) V=at D) V=wR 14 / 25 Aylanma tekis harakatda tezlanish qanday yo’nalgan? A) radius bo’ylab markazdan B) urinma bo’ylab C) radius bo’ylab markazga D) xar xil yo’nalgan bo’lishi mumkin 15 / 25 Uzunligi 25 sm bo’lgan ipga bog’langan sharcha 5 m/s chiziqli tezlik bilan aylanmoqda. Sharning markaziga intilma tezlanishini toping. (m/s2) A) 10 B) 100 C) 2 D) 1 16 / 25 Soatning 30 mm uzunlikdagi minut uchi 10 minutda 31,4 mm uzunlikdagi yo’lni bosib o’tdi. Minut mili uchining burchak tezligini toping. A) 1,7 rad/s B) 0,0017 rad/s C) 0,017 rad/s D) 0,17 rad/s 17 / 25 Aylana bo’ylab tekis harakatda markazga intilma tezlanish formulasini ko’rsating. 1) a=v2/R, 2) a=v2/2R, 3) a=v/t A) 3 B) 1 C) 1,2 D) 2 18 / 25 Tekis sekinlanuvchan harakatda tezlik va tezlanish ishoralarining munosabatini ko’rsating. 1) υ0 > 0, a<0 2) υ0 = 0, a<0 3) υ0 < 0, a>0 4) υ >0, a>0 A) 2,3 B) 4 C) 1,3 D) 3,4 19 / 25 Samolyot qo’nish paytida g’ildiraklari yerga tekkandagi tezligi 360 km/soat. Agar uning tezlanishi 2m/s2 bo’lsa, u qancha vaqtdan keyin to’xtaydi A) 25 s B) 5 s C) 100 s D) 50 s 20 / 25 Jism tezlik proporsiyasining vaqtga bog’lanish v = 3+2t (m/s) ko’rinishga ega. Ko’chish proyeksiyasining vaqtga bog’lanishi qanday? A) S = 3t + 1 t² B) S = 2t² C) S = 2t + 3 ² D) S = 3t + 2 t² 21 / 25 Tekis tezlanuvchan harakat qilayotgan “Matiz” 10 s davomida tezligini 54 km / soat dan 100 km / soat ga oshirdi. «Matiz»ning tezlanishini toping A) 15 m/s² B) 13 m/s² C) 2,5 m/s² D) 3 m/s² 22 / 25 Boshlang’ich tezliksiz erkin tushayotgan jism 3-sekund ichida qanday masofani o’tadi? g = 10 m/s2 A) 25 m/s B) 5 m/s C) 15 m/s D) 10 m/s 23 / 25 Tekis tezlanuvchan harakatda tezlik va tezlanish ishoralarning munosabatini ko’rsating. 1) υ0 > 0, a>0 2) υ0 > 0, a<0 3) υ0 < 0, a<0 4) υ0<0, a>0 A) 2,4 B) 1,3 C) 1,2 D) 3,4 24 / 25 Jism yerdan 35 m/s tezlik bilan tik yuqoriga otildi. U yerga necha sekunddan so’ng tushadi? A) 5 B) 3 C) 9 D) 7 25 / 25 Tezlanish formulasi qanday ifodalanadi A) p = m / v B) p = F / S C) S = at² / 2 D) a = (v - v˳)/t 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz