Uy » Choraklik online testlar » Fizika choraklik » 7-sinf Fizika 4-chorak Fizika choraklik 7-sinf Fizika 4-chorak InfoMaster Aprel 26, 2021 1136 Ko'rishlar 0 SaqlashSaqlanganOlib tashlandi 1 4 Tomonidan yaratilgan InfoMaster 7-sinf Fizika 4-chorak Testni Vafaqulov Alisher tayyorladi. 1 / 25 0,1 s davomida g’ildirak 1 chapga buriladi. Uning o’qidan 5sm uzoqlikdagi nuqtasining chiziqli tezligini toping A) 50m/s B) 0,5 m/s C) 10m/s D) 5 m/s 2 / 25 Soatning sekund mili burchakli tezligini toping. (rad/s) A) π/10 B) π/2600 C) π/30 D) π/1800 3 / 25 Velosiped g’ildiragining o’qidan eng uzoq nuqtasi 0,02 s davomida 20 km yo’lni bosib o’tdi. Velosipedning tezligini toping A) 0,36 km/soat B) 3,6 km/soat C) 4 km/soat D) 36 km/soat 4 / 25 Agar moddiy nuqta aylana bo’ylab teng vaqtlar orasida teng yollarni bosib o’tsa, bunday harakat ....... harakat deyiladi A) tekis B) aylanma o’zgaruvchan C) tekis aylanma tezlik D) notekis 5 / 25 Odam liftda turibdi. Odamga ta’sir qiluvchi kuchlar: mg – og’irlik kuchi, N – tayanch reaksiya kuchi, Lift tinch turganda kuchlar orasidagi munosabatni ko’rsating 1) mg > N 2) mg < N 3) mg = N 4) mg = 0; N = 0 A) 1 B) 3 C) 2 D) 4 6 / 25 O’zaro ta’sirlashuvchi jismlarning bir-biriga ta’sir kuchlari bir to’g’ri chiziq bo’yicha yo’nalgan, moduli bo’yicha teng va yo’nalish bo’yicha qarama-qarshidir. Bu ....... A) Nyutonning 2 qonuni B) Nyutonning 3 qonuni C) Nyutonning butun olam tortishish kuchi qonuni D) Nyutonning 1 qonuni 7 / 25 1 m/s2 tezlanish bilan tushayotgan liftdagi 20 kg massali bolaning og’irligi qancha? A) 190 N B) 200 N C) 170 N D) 180 N 8 / 25 Odam liftda turibdi. Odamga ta’sir qiluvchi kuchlar: mg – og’irlik kuchi, N – tayanch reaksiya kuchi, Lift yuqorida to’xtashdan oldin sekinlashganda kuchlar orasidagi munosabatni ko’rsating. Lift yuqorida to’xtashdan oldin sekinlashyapti 1) mg > N 2) mg < N 3) mg = N 4) mg = 0; N = 0 A) 4 B) 3 C) 1 D) 2 9 / 25 Nyutonning 3 qonuni formulasi qaysi ifodada to’g’ri ko’rsatilgan? A) F1 =- F2 B) F = - k x C) F = mg D) F = mv²/ R 10 / 25 1000 mN necha N? A) 400 B) 1 C) 10 D) 70 11 / 25 Tennischi 100 kg massali koptokni 250 N kuch bilan urganda koptok 50 m/s tezlik oldi. Zarb necha sekund davom etgan? A) 100 B) 10 C) 20 D) 50 12 / 25 Lift a A) (P=mg) B) P=m(g-a) C) P=m(g+a) D) P=m(a-g) 13 / 25 Liftdagi odam o’ta yuklanishga duch kelishi mumkinmi? A) Yo’q B) Xa lift tezlanish bilan pastga tushganda C) Xa lift yuqoriga ko’tarilganda D) Xa agar lift tezlanish bilan yuqoriga ko’tarilsa 14 / 25 Yer sirtidagi jism yerga F kuch bilan tortilmoqda. Yer sirtidan h=2R balandlikka ko’tarilsa yerga qanday kuch bilan tortiladi? R-Ep radus A) F/9 B) F/4 C) F/16 D) F/2 15 / 25 Ko’tarilish balandligi 4 marta ortishi uchun yuqoriga otilgan jismning boshlang’ich tezligini necha marta oshirish lozim A) 55 martta B) 60 martta C) 50 martta D) 45 martta 16 / 25 Zambarakdan gorizantga burchak ostida uchib chiqqan snaryad 12 sekund uchgan. Snaryad ko’tarilgan eng yuqori balandlik qancha A) 20m B) 180m C) 360m D) 10m 17 / 25 Jismning harakat tenglamasi x = 2 – 3 t + 2 t2 formula bilan berilgan. Bu harakat uchun tezlik tenglamasini yozing A) υ= 4 - 3 t B) υ= 4 + 3 t C) υ= - 3 + 4 t D) υ = 4 t 18 / 25 Avtomobil 5 m/s2 tezlanish bilan tinch holatdan harakat boshladi. U 4s da necha metr yo’l o’tadi? A) 30 B) 20 C) 10 D) 40 19 / 25 Tekis tezlanuvchan harakatda tezlik va tezlanish ishoralarning munosabatini ko’rsating. 1) υ0 > 0, a>0 2) υ0 > 0, a<0 3) υ0 < 0, a<0 4) υ0<0, a>0 A) 1,2 B) 3,4 C) 1,3 D) 2,4 20 / 25 Tezligi υ=5-3 t (m/s) tenglama bilan berilgan jismning boshlangich tezligi (m/s) nimaga teng? A) 3 B) 2 C) 5 D) 4 21 / 25 Jism tezlik proporsiyasining vaqtga bog’lanish v = 3+2t (m/s) ko’rinishga ega. Ko’chish proyeksiyasining vaqtga bog’lanishi qanday? A) S = 3t + 1 t² B) S = 2t + 3 ² C) S = 3t + 2 t² D) S = 2t² 22 / 25 Jism harakat tenglamasi x=5+3t–t2 formula bilan berilgan. Jismning boshlang’ich koordinatasi nimaga teng? A) 3 m B) 5 m C) 9 m D) 1 m 23 / 25 Tezlanishning o’lchov birligini ko’rsating A) m/s² B) m/s C) s/ m² D) m²/s 24 / 25 Tezlanish formulasi qanday ifodalanadi A) S = at² / 2 B) p = m / v C) a = (v - v˳)/t D) p = F / S 25 / 25 Boshlang’ich tezliksiz erkin tushayotgan jism birinchi sekunda qanday masofani o’tadi?g = 10 m/s2 A) 5 m B) 5,5 m C) 0,5 m D) 50 m 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz