Uy » Choraklik online testlar » Matematika choraklik » 7-sinf Matematika 3-chorak Matematika choraklik 7-sinf Matematika 3-chorak InfoMaster Aprel 7, 2021 3069 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 6 0 OMAD YOR BO'LSIN! Tomonidan yaratilgan InfoMaster 7-sinf Matematika 3-chorak Testni Mamadoliyev Diyorbek tayyorladi. 1 / 25 Uchta nuqta to`g`ri chiziqni nechta bo`lakka bo`ladi ? A) 3 B) 4 C) 2 D) 9 2 / 25 Har biri x so`mdan 12 ta daftar va har biri y so`mdan 2 ta ruchka sotib olindi. Hamma xarid qancha turadi ? A) 14 +x +y B) 12x + 2y C) (x + 12) • (y + 2) D) 14xy 3 / 25 Algebraik ifodaning son qiymatini hisoblang: bunda, A) -5 B) 5 C) 3 D) 4 4 / 25 75 gradusli burchakka qo`shni burchakni toping. A) 115 gradus B) 45 gradus C) 15 gradus D) 105 gradus 5 / 25 Burchak bissektrisasi uning tomoni bilan 41°li burchak hosil qiladi. Berilgan burchakni toping. A) 139° B) 49° C) 59 ° D) 82° 6 / 25 Bo`yi enidan 3 marta katta bo`lgan to`g`ri to`rtburchakning perimetri 120 sm ga teng. Shu to`g`ri to`rtburchakning bo`yini toping. A) 15 sm B) 60 sm C) 90 sm D) 45 sm 7 / 25 Teng yonli uchburchakning asosining uzunligi a ga teng bo`lib, u yon tomonlaridan 5 ga ortiq. Shu uchburchakning perimetrini hisoblash uchun ifoda tuzing. A) 3a B) 3a -10 C) 3a +5 D) 3a + 10 8 / 25 Tenglamani yeching: 0,04x = 4 A) 0,16 B) 100 C) 0,016 D) 10 9 / 25 Agar bo`lsa, BC ni toping. ? A) 4,3 sm B) 5,3 sm C) 7,3 sm D) 17,3 sm 10 / 25 Tenglik shaklida yozing: a va b sonlari yig`indisining ikkilangani ularning ko`paytmasiga teng. A) a + b • 2 = a • b B) 2∙(a+b) = a • b C) 2∙(a+b) = 2a • b D) a + b = 2 • a • b 11 / 25 a sonni shunday tanlangki, 3x - 4 = a - 2x tenglama x = 1 ildizga ega bo`lsin A) 1 B) 5 C) 0 D) -9 12 / 25 Soatning soat mili 3 soatda necha gradusga buriladi ? A) 90 ° B) 30° C) 45° D) 60° 13 / 25 Uzunliklari 4 sm, 5 sm , 6 sm, 7 sm bo`lgan kesmalardan nechta uchburchak yasash mumkin ? A) 5 B) 4 C) 2 D) 3 14 / 25 Hisoblang: 139∙15 + 18∙139 + 15∙261 + 18∙261. A) 1320 B) 132400 C) 13200 D) 1324 15 / 25 Agar uchburchakning ikkita burchagi 600 va 400 ga teng bo`lsa, uning noma’lum burchagini toping A) 100° B) 20° C) 120° D) 80° 16 / 25 Agar uchburchakning burchaklari 2,3,4 sonlariga proporsional bo`lsa, ularni toping. A) 80°, 120°, 160° B) 40°, 60°, 80° C) 20°, 30°, 40° D) 30°, 45°, 60° 17 / 25 Quyidagi mulohazalardan qaysi biri noto`g`ri ? A) Uchburchakda katta burchak qarshisida katta tomon yotadi. B) Uchburchakda kichik burchak qarshisida kichik tomon yotadi C) Uchburchakda katta tomon qarshisida katta burchak yotadi . D) Uchburchakda kichik burchak qarshisida katta tomon yotadi. 18 / 25 Ko`paytuvchilarga ajrating: 16a2 – 81. A) (4a – 9)² B) (4a-3)(4a+3) C) (4a-9)(4a+9) D) (16a – 81)(16a +81) 19 / 25 Soddalashtiring: (c-3)2 – (c+3)(3-c) A) 2c²–6c+18 B) 2c²– 6c C) 0 D) -6c 20 / 25 Hisoblang: 29,42 – 29,32. A) 58,7 B) 0,01 C) 0, 587 D) 5,87 21 / 25 Agar uchburchakning ikkita burchagi 400 va 300 ga teng bo`lsa, uning uchinchi burchagiga qo`shni burchagini toping A) 70° B) 120° C) 110° D) 100° 22 / 25 Ikki to`g`ri chiziqning kesishishidan hosil bo`lgan burchaklardan ikkitasining yig`indisi 1200. Bu burchaklarni toping A) 60gradus , 60gradus B) 45gradus, 75gradus C) 15gradus , 105gradus D) 30gradus , 90gradus 23 / 25 Birhadning son qiymatini toping:, bunda y = -15, x = 6. A) 3 B) 1 C) 12 D) 18 24 / 25 Uchburchakning bir uchidan shu uchining qarshisidagi tomonga tushirilgan perpendikulyar nima deb ataladi A) to`g`ri javob yo`q B) bissektrisa C) balandlik D) mediana 25 / 25 Hisoblang: A) 1/3 B) 9 C) 1/9 D) 3 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
