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Matematika choraklik

10-sinf Matematika 4-chorak

InfoMaster

Aprel 20, 2021

399 Ko'rishlar 10 izohlar

SaqlashSaqlanganOlib tashlandi 1

1

OMAD YOR BO'LSIN!

Tomonidan yaratilgan InfoMaster

10-sinf Matematika 4-chorak

Testni Imomnazarov Ibrohim tayyorladi.

1 / 25

Ko`paytmani toping.

(6-3i)(1+4i)

A) 18+28i

B) -36+4i

C) 18+21i

D) 27-24i

2 / 25

Ayirmani toping.

(2+6i)-(-4+2i)

A) 4-6i

B) 6+4i

C) 6-4i

D) 2+6i

3 / 25

Kompleks sonni haqiqiy va mavhum qismlarini toping.

A) Re(z)=1/2, Im(z)=0.5

B) Re(z)=4, Im(z)=1/2

C) Re(z)=-4, Im(z)=0.5

D) Re(z)=4, Im(z)=-0.5

4 / 25

Yig‘indini toping.

9i-(3-8i)

A) -3+i

B) -3+17i

C) -1-3i

D) -i

5 / 25

Ko`paytmani toping.

(-3+2i)(8+4i)

A) -32+4i

B) 6-4i

C) 18+28i

D) -36+4i

6 / 25

Tenglamani yeching:

A) -1

B) 3

C) 4

D) -2

7 / 25

Irratsional tenglamani yeching.
$\sqrt{8x+3}=2$

A) 1/8

B) 8

C) 2

D) 1/4

8 / 25

p⇒q bu yerda « Yetarli shart » qaysi ?

A) p mulohaza q uchun yetarli shart

B) bunday tushuncha yo’q

C) q mulohaza p uchun yetarli shart

D) to’g’ri javob yo’q

9 / 25

Quyidagi mulohazalar teng kuchlimi ?
(p∨q) va ¬p∧¬q

A) Teng kuchli

B) Mulohazalarning berilishi xato

C) Tavtologiya

D) Teng kuchli emas

10 / 25

U={x| 3 ≤x< 12, x∈N} , A={x| 5

A) 3 ta

B) 10 ta

C) 9 ta

D) 2 ta

11 / 25

Quyidagi mulohazaning rostlik jadvalida nechta rost qatnashadi ? ¬(p∨q)

A) 4 ta

B) 1 ta

C) 3 ta

D) 2 ta

12 / 25

Diagrammadan foydalanib, quyidagi to‘plammi elementlari sonini toping: ¬A∩B

A) n(¬A∩B)=14

B) n(¬A∩B)=7

C) n(¬A∩B)=16

D) n(¬A∩B)=5

13 / 25

Tenglamalar sistemasining nechta yechimi bor?

A) 1

B) 3

C) 4

D) 2

14 / 25

Tekislikda A(3;1) va B(7;3) nuqtalardan teng uzoqlikda joylashgan C(5;x) nuqtani toping.

A) (5;3)

B) (5;2)

C) (4;3)

D) (4;2)

15 / 25

Bikvadrat tenglamaning ildizlari yig‘indisini toping:

A) 11/3

B) 0

C) 1

D) -1

16 / 25

Hisoblang:
arcsin 1

A) π

B) π/2

C) 3π/2

D) 0

17 / 25

Hisoblang: arcsin √3/2

A) π/6

B) π/3

C) 3π/2

D) π/2

18 / 25

Funksiyaning davrini aniqlang:
y=sin6x (gradusda)

A) 120

B) 60

C) 180

D) 240

19 / 25

Hisoblang:
arctg $\sqrt{3}$

A) -π/6

B) π/4

C) π/3

D) π/6

20 / 25

Grafigikka qarab finksiyani toping.

A) y=3sinx

B) y=cosx

C) y=2cosx

D) y=2sinx

21 / 25

Grafigikka qarab finksiyani toping.

A) y=sinx+1

B) y=cosx-1

C) y=2cosx+1

D) y=cosx+1

22 / 25

Hisoblang: arcsin(1/2)

A) π/2

B) π/6

C) 3π/2

D) π/3

23 / 25

Hisoblang:

A) π/4

B) π/6

C) π

D) 4π/3

24 / 25

Hisoblang: arccos 1/2

A) π/6

B) 2π/3

C) 3π/4

D) π/3

25 / 25

Hisoblang:

A) 5π/6

B) π/3

C) π/6

D) -π/6

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Author: InfoMaster

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