Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №6 Matematika attestatsiya Matematika attestatsiya №6 InfoMaster Yanvar 30, 2022 71 Ko'rishlar 2 izohlar SaqlashSaqlanganOlib tashlandi 0 0% 0 ovozlar, 0 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №6 1 / 40 tengsizlikni yeching. A) 2 B) 4 C) 1 D) 3 2 / 40 y=kx+n funksiyaning grafigi I va III chorakdan o‘tishi uchun k va n qanday bo‘lishi kerak? A) n < 0, k = 0 B) n > 0, k = 0 C) n = 0, k < 0 D) n = 0, k > 0 3 / 40 Uchlari A(4;5;1), B(2;3;0) va C(2;–1;–3) nuqtalarda joylashgan uchburchakning BD medianasi uzunligini toping. A) 2 B) 1 C) √2 D) √3 4 / 40 Qadam uzunligi deb biricnhi iz tovon oxiridan ikkinchi iz tovon oxirigacha bo'lgan masofaga aytiladi. Erkak kishi yurayotganda uning qadami va qadamlar soni orasidagi bog'lanish quyidagi formula bilan ifodalanadi: (n/P) = 140. Bu yerda n – bir minutdagi qadamlar soni. P – qadam uzunligi (m). Hikmat 1 minutda 70 qadam bossa, formula yordamida uning qadami uzunligini toping. A) 0,5 m yoki 50 cm B) 0,9 m yoki 90 cm C) 0,6 m yoki 60 cm D) 0,7 m yoki 70 cm 5 / 40 Bir idishda 32/5 kg, ikkinchisida esa unga qaraganda 16/5 kg ortiq yog` bor. Ikkala idishda qancha yog` bor? A) 64/5 B) 48/5 C) 10 D) 16 6 / 40 Standart shaklda yozing 0,000000000000013 1,3·10-12 1,3·10-13 1,3·10-14 1,3·10-15 A) 2 B) 4 C) 1 D) 3 7 / 40 a,b,c -1 dan katta musbat sonlar uchun a³=b² va a4=c5 bo'lsa, logbc ni toping. A) 1/3 B) 5/6 C) 8/15 D) 1/2 8 / 40 Funksiyaning aniqlanish sohasini toping. A) [-3;2] B) (-∞;3]∪[2;∞) C) (-∞;0)∪(0;∞) D) x∈R 9 / 40 Burchagi 120° ga teng bo‘lgan doiraviy sektorga ichki doira chizilgan. Berilgan doiraning radiusi R ga teng bo‘lsa, yangi doiraning radiusi topilsin. A) 1,5R B) √3R(2-√3) C) R(√3-√2) D) 3R 10 / 40 f(x)+f(3x)+f(5x)+...+f(39x)=(3x+10)4 bo'lsa, f'(0) ni toping. A) 10 B) 25 C) 0 D) 30 11 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 1 B) 4 C) 2 D) 3 12 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 4√2 B) 6 C) 4√3 D) 3√2 13 / 40 a+b+c=10, bo‘lsa, ni toping. A) 11 B) 4 C) 6 D) 5 14 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 2 B) 1 C) 4 D) 3 15 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 105 B) 100 C) 96 D) 25 16 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 2√2 B) 4√3 C) 2√3 D) 3√2 17 / 40 sonlarini taqqolsang. A) c B) c C) b D) a 18 / 40 bo‘lsa, A) 3/2 B) 2 C) 2/3 D) 1 19 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 6 B) 8 C) 12 D) 10 20 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) π/4+πk, k∈Z B) Ø C) 0 D) -π/4+πk, k∈Z 21 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) DC < AD B) AB = BC C) BC > AD D) BD = BC 22 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 15 B) 10 C) 8 D) 20 23 / 40 Hisoblang: A) 9/10 B) 19/20 C) 20/21 D) 10/11 24 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 43 B) 42 C) 44 D) 45 25 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 5 yoki –15 B) 4 yoki –12 C) 6 D) 3 yoki –8 26 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 5 B) 10 C) 11 D) 7 27 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) -3 B) 5 C) -6 D) -4 28 / 40 x²-√11x+1=0 0 bo‘lsa, A) 11 B) 9 C) 10 D) 12 29 / 40 Tenglamalar sistemani yeching: A) (9; 0), (28; -1) B) (7; 2), (28; -1) C) (2; 3) D) (9; 0), (2; 7) 30 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 1 B) 3 C) 2 D) 4 31 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 14 B) 12 C) 10 D) 20 32 / 40 Tengsizlik nechta butun juft yechimga ega? A) 110 B) 115 C) 112 D) 116 33 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 48 B) 32 C) 42 D) 64 34 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 8 B) 6 C) 7 D) 5 35 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 16(π-2) B) 32 C) 8(π+2) D) 64 36 / 40 √3 A) 21/10 B) 3/2 C) 5/5 D) 7/3 37 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) √3ctg40° tg70° B) 4 √3tg50° tg70° C) 2√3tg50° tg70° D) √3tg50° tg70° 38 / 40 Chizmadan foydalanib α ni toping. A) 30° B) 20° C) 50° D) 40° 39 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) cd/b B) 1 C) bd/c D) bc/d 40 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) -2 B) 8 C) 3 D) 5 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16