Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №6 Matematika attestatsiya Matematika attestatsiya №6 InfoMaster Yanvar 30, 2022 97 Ko'rishlar 2 izohlar SaqlashSaqlanganOlib tashlandi 0 0% 0 ovozlar, 0 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №6 1 / 40 |x+1|=2|x–2| tenglamaning ildizlari yig’indisini toping. A) 0 B) 6 C) 5 D) 7 2 / 40 Berilgan sonlarning yig’indisini toping. A) 1/4 B) -452/18 C) 2/4 D) 3/18 3 / 40 Qadam uzunligi deb biricnhi iz tovon oxiridan ikkinchi iz tovon oxirigacha bo'lgan masofaga aytiladi. Erkak kishi yurayotganda uning qadami va qadamlar soni orasidagi bog'lanish quyidagi formula bilan ifodalanadi: (n/P) = 140. Bu yerda n – bir minutdagi qadamlar soni. P – qadam uzunligi (m). Hikmat 1 minutda 70 qadam bossa, formula yordamida uning qadami uzunligini toping. A) 0,7 m yoki 70 cm B) 0,9 m yoki 90 cm C) 0,5 m yoki 50 cm D) 0,6 m yoki 60 cm 4 / 40 Tengsizlikni yeching. A) [-3;-2] B) [-2;1]∪{-3} C) [-3;2]∪{1} D) (-∞;-2] 5 / 40 Hisoblang: A) 2 B) 4 C) 1 D) 3 6 / 40 x ni toping ? A) 6 B) 4 C) 3 D) 5 7 / 40 cos75° ·cos 45° ·cos15° ni hisoblang. A) √3/4 B) 1/8 C) √3/8 D) √2/8 8 / 40 Tenglamalar sistemasidan foydalanib x + y + z ni toping: A) berilganlar yetarli emas B) 8 C) 6 D) 10 9 / 40 ABC o‘tkir burchakli uchburchakda sinA=4/5 va sinB=15/13 bo'lsa, sinC ni qiymatini toping. A) 36/65 B) 40/63 C) 48/65 D) 56/65 10 / 40 Burchagi 120° ga teng bo‘lgan doiraviy sektorga ichki doira chizilgan. Berilgan doiraning radiusi R ga teng bo‘lsa, yangi doiraning radiusi topilsin. A) 1,5R B) 3R C) √3R(2-√3) D) R(√3-√2) 11 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 12 B) 8 C) 10 D) 6 12 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 64 B) 32 C) 48 D) 42 13 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 4√2 B) 4√3 C) 6 D) 3√2 14 / 40 Chizmadan foydalanib α ni toping. A) 50° B) 20° C) 40° D) 30° 15 / 40 Tengsizlik nechta butun juft yechimga ega? A) 115 B) 116 C) 112 D) 110 16 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 15 B) 8 C) 20 D) 10 17 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 10 B) 8 C) 6√7 D) 4√7 18 / 40 x²-√11x+1=0 0 bo‘lsa, A) 9 B) 12 C) 11 D) 10 19 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 2 B) 4 C) 1 D) 3 20 / 40 Tenglamalar sistemani yeching: A) (9; 0), (28; -1) B) (9; 0), (2; 7) C) (2; 3) D) (7; 2), (28; -1) 21 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) 5 B) -6 C) -4 D) -3 22 / 40 Ifodaning qiymatini toping. A) 0,(04) B) 0,0(4) C) 0,0(2) D) 0,04 23 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 10 B) 20 C) 14 D) 12 24 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 3√2 B) 2√2 C) 4√3 D) 2√3 25 / 40 Rasmdagi shakl perimetrini toping. A) 24 B) 30 C) 28 D) 32 26 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) BD = BC B) BC > AD C) DC < AD D) AB = BC 27 / 40 bo‘lsa, A) 2/3 B) 2 C) 1 D) 3/2 28 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) bd/c B) cd/b C) 1 D) bc/d 29 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 3 yoki –8 B) 5 yoki –15 C) 6 D) 4 yoki –12 30 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) 0 B) π/4+πk, k∈Z C) Ø D) -π/4+πk, k∈Z 31 / 40 sonlarini taqqolsang. A) a B) c C) b D) c 32 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 32 B) 64 C) 8(π+2) D) 16(π-2) 33 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) √3ctg40° tg70° B) 2√3tg50° tg70° C) 4 √3tg50° tg70° D) √3tg50° tg70° 34 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 2 B) 1 C) 3 D) 4 35 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 35 B) 14 C) 24 D) 23 36 / 40 Hisoblang: A) 20/21 B) 10/11 C) 9/10 D) 19/20 37 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 6 B) 7 C) 8 D) 5 38 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 12 B) 13 C) 14 D) 15 39 / 40 Hisoblang: A) -1/2 B) -√3/2 C) 0 D) 1/32 40 / 40 √3 A) 5/5 B) 7/3 C) 21/10 D) 3/2 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 14 Matematika fanidan attestatsiya savollari №16