Matematika attestatsiya №6 Yanvar 30, 2022Yanvar 30, 2022 da chop etilgan InfoMaster tomonidan Matematika attestatsiya №6 ga 1 fikr bildirilgan 0% 0 ovozlar, 0 o'rtacha 8 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №6 1 / 40 ni hisoblang. A) e-1 B) (e+1)/2 C) e+1 D) (e-1)/2 2 / 40 Teng yonli trapetsiya asosidagi burchakning sinusi 0,6 ga, asoslarining ayirmasi 4 ga teng bo‘lsa, trapetsiyaning yon tomonini toping. A) 2,5 B) 3 C) 2 D) 4 3 / 40 Tenglama ildizlari ayirmasining modulini toping. A) 2√5 B) √5+5 C) 5 D) √5 4 / 40 Hisoblang: A) 9 B) 4 C) 27 D) 7 5 / 40 Soddalashtiring: A) 3 B) 2 C) 1 D) Aniqlab bo`lmaydi 6 / 40 Tengsizlikni qanoatlantiradigan eng kichik ikkita butunsonning yig`indisini toping? A) 6 B) 3 C) 4 D) 5 7 / 40 108 sonining natural bo‘luvchilari ko‘paytmasi quyidagilardan qaysi biriga teng? 212·318 22·33 28·310 26·39 A) 4 B) 3 C) 1 D) 2 8 / 40 Raqamlari yig‘indisi 10 bo‘lgan nechta turli 3 xonali son bor? A) 0,432 B) 0,144 C) 0,216 D) 0,288 9 / 40 Quyidagi sonini 9 ga bo‘lganda qoladigan qoldiqni toping. A) 8 B) 1 C) 5 D) 0 10 / 40 To‘g‘ri burchakli uchburchakning bir burchagi 52° ga teng bo‘lsa, to‘g‘ri burchak uchidan tushirilgan balandlik va mediana orasidagi burchakni toping. A) 7° B) 14° C) 17° D) 24° 11 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 11 B) 10 C) 7 D) 5 12 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 3 B) 4 C) 1 D) 2 13 / 40 Ifodaning qiymatini toping. A) 0,0(4) B) 0,04 C) 0,0(2) D) 0,(04) 14 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) AB = BC B) BC > AD C) DC < AD D) BD = BC 15 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 10 B) 8 C) 4√7 D) 6√7 16 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 32 B) 16(π-2) C) 8(π+2) D) 64 17 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 42 B) 43 C) 45 D) 44 18 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 15 B) 14 C) 12 D) 13 19 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 3 yoki –8 B) 4 yoki –12 C) 6 D) 5 yoki –15 20 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 25 B) 100 C) 105 D) 96 21 / 40 Hisoblang: A) 0 B) -√3/2 C) -1/2 D) 1/32 22 / 40 a+b+c=10, bo‘lsa, ni toping. A) 6 B) 4 C) 5 D) 11 23 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) √3ctg40° tg70° B) 4 √3tg50° tg70° C) 2√3tg50° tg70° D) √3tg50° tg70° 24 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) cd/b B) 1 C) bc/d D) bd/c 25 / 40 Tengsizlik nechta butun juft yechimga ega? A) 115 B) 110 C) 116 D) 112 26 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 23 B) 14 C) 24 D) 35 27 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 14 B) 12 C) 20 D) 10 28 / 40 bo‘lsa, A) 2 B) 1 C) 2/3 D) 3/2 29 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 20 B) 15 C) 8 D) 10 30 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) π/4+πk, k∈Z B) Ø C) -π/4+πk, k∈Z D) 0 31 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 3√2 B) 2√2 C) 2√3 D) 4√3 32 / 40 Rasmdagi shakl perimetrini toping. A) 28 B) 32 C) 24 D) 30 33 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 5 B) -2 C) 3 D) 8 34 / 40 Tenglamani yeching: A) 6; -5 B) 5 C) -6 D) -6; 5 35 / 40 Chizmadan foydalanib α ni toping. A) 40° B) 50° C) 30° D) 20° 36 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 11 B) 121 C) berilganlar yetarli emas D) 22 37 / 40 x²-√11x+1=0 0 bo‘lsa, A) 11 B) 10 C) 12 D) 9 38 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 1 B) 3 C) 2 D) 4 39 / 40 Hisoblang: A) 10/11 B) 9/10 C) 19/20 D) 20/21 40 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 42 B) 64 C) 48 D) 32 O'rtacha ball 61% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Matematika attestatsiya