Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №6 Matematika attestatsiya Matematika attestatsiya №6 InfoMaster Yanvar 30, 2022 97 Ko'rishlar 2 izohlar SaqlashSaqlanganOlib tashlandi 0 0% 0 ovozlar, 0 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №6 1 / 40 Teng yonli trapetsiya asosidagi burchakning sinusi 0,6 ga, asoslarining ayirmasi 4 ga teng bo‘lsa, trapetsiyaning yon tomonini toping. A) 2 B) 4 C) 3 D) 2,5 2 / 40 ni hisoblang. A) (e-1)/2 B) (e+1)/2 C) e+1 D) e-1 3 / 40 f(x)=3x-2 funksiyaning qiymatlar sohasini toping. A) [-1; ∞) B) (-1; ∞) C) (0; ∞) D) (-2; ∞) 4 / 40 tenglamaning ildizlari yig'indisini(agar ildizi bitta bo'lsa, o'zini) toping. A) 0 B) 3 C) 2 D) 1 5 / 40 Quyida berilgan shakillar ichidagi sonlar yig`indisi nolgateng bo`lishi uchun . Nechanchi shakilni olib tashlash kerak? A) 2 B) 1 C) 4 D) 3 6 / 40 Chizmaga ko`ra x ning eng kichik butun qiymatinitoping ? A) 8 B) 6 C) 7 D) 9 7 / 40 275+330 sonini 41 ga bo‘lganda qoladigan qoldiqni aniqlang. A) 9 B) 0 C) 5 D) 1 8 / 40 Bo‘yi 130 cm, eni 90 cm, balandligi 60 cm bo‘lgan idishdagi suvning 234 litri olindi. Idishda qolgan suvning (sathi) balandligini toping. A) 25 B) 40 C) 20 D) 35 9 / 40 Agar bo‘lsa, m/n ni toping. A) 4 B) (1+√5)/2 C) 3 D) 2 10 / 40 7/3 kasrning o‘nli kasr yoyilmasida verguldan keyingi 100- raqamni toping. A) 2 B) 1 C) 5 D) 4 11 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 6 B) 3√2 C) 4√2 D) 4√3 12 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 3 B) 1 C) 4 D) 2 13 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 2√3 B) 4√3 C) 2√2 D) 3√2 14 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 45 B) 42 C) 43 D) 44 15 / 40 Chizmadan foydalanib α ni toping. A) 50° B) 20° C) 30° D) 40° 16 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 1 B) 4 C) 3 D) 2 17 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 25 B) 96 C) 105 D) 100 18 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 32 B) 64 C) 48 D) 42 19 / 40 Tenglamani yeching: A) 6; -5 B) -6 C) 5 D) -6; 5 20 / 40 bo‘lsa, A) 2 B) 2/3 C) 3/2 D) 1 21 / 40 a+b+c=10, bo‘lsa, ni toping. A) 11 B) 4 C) 6 D) 5 22 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 5 B) 11 C) 7 D) 10 23 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 3 B) 4 C) 2 D) 1 24 / 40 Rasmdagi shakl perimetrini toping. A) 28 B) 24 C) 32 D) 30 25 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) BD = BC B) BC > AD C) AB = BC D) DC < AD 26 / 40 Tenglamalar sistemani yeching: A) (7; 2), (28; -1) B) (9; 0), (28; -1) C) (2; 3) D) (9; 0), (2; 7) 27 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 32 B) 64 C) 8(π+2) D) 16(π-2) 28 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 15 B) 13 C) 12 D) 14 29 / 40 Hisoblang: A) 1/32 B) -√3/2 C) -1/2 D) 0 30 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 8 B) 5 C) 7 D) 6 31 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 10 B) 6 C) 8 D) 12 32 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) -2 B) 3 C) 8 D) 5 33 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 1 B) 3 C) 2 D) 4 34 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 10 B) 20 C) 12 D) 14 35 / 40 Tengsizlik nechta butun juft yechimga ega? A) 115 B) 116 C) 112 D) 110 36 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 6 B) 5 yoki –15 C) 3 yoki –8 D) 4 yoki –12 37 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) -3 B) 5 C) -4 D) -6 38 / 40 sonlarini taqqolsang. A) b B) c C) a D) c 39 / 40 Hisoblang: A) 19/20 B) 9/10 C) 20/21 D) 10/11 40 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) √3tg50° tg70° B) 4 √3tg50° tg70° C) 2√3tg50° tg70° D) √3ctg40° tg70° O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 14 Matematika fanidan attestatsiya savollari №16