Uy » Online olimpiada » Matematika olimpiada » 11-sinf Matematika olimpiada №3 Matematika olimpiadaViloyat 2021-2022 o'quv yili 11-sinf Matematika olimpiada №3 InfoMaster Avgust 19, 2024 68 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0 12345678910111213141516171819202122232425 Vaqtingiz tugadi! 11-sinf Matematika olimpiada №3 2021-2022 o'quv yilida viloyat bosqichida tushgan savollar 1 / 25 1. ko‘phadning barcha koeffitsientlari va ozod hadining yig‘indisini toping. A) -238 B) -247 C) 245 D) 125 2 / 25 2. funksiyaning aniqlanish sohasini toping. A) (-∞;4/3)∪(4/3;∞) B) (-∞;2/3)∪(2/3;∞) C) (-∞;4/3) D) (2/3;∞) 3 / 25 3. Ikki xonali sonni qandaydir natural songa bo‘lganda bo‘linmada 3 va qoldiqda 8 hosil bo‘ladi. Agar bo‘linuvchining raqamlari o‘rni almashtirilsa va bo‘luvchi son o‘zgarishsiz qoldirilsa, u holda bo‘linmada 2 va qoldiqda 5 hosil bo‘ladi. Bo‘linuvchning dastlabki qiymatini toping. A) 53 B) 65 C) 73 D) 55 4 / 25 4. Tenglamalar sistemasi nechta yechimga ega? A) 10 B) 12 C) 6 D) 8 5 / 25 5. Soddalashtiring: A) 3sin2x B) cosx C) 3cos2x D) 3cosx 6 / 25 6. Hisoblang: A) 1.5 B) 1 C) 2 D) 0 7 / 25 7. Funksiyaning eng kichik qiymatini toping. ?(?) = (2? + 6)5 − 4(2? + 6)4, bunda |? + 3| ≤ 2. A) -2¹¹ B) -4⁵ C) -2⁹ D) -4⁴ 8 / 25 8. Teng yonli АВС uchburchakda: АВ = ВС = 25 sm va АС = 14 sm. ВС tomonga AD balandlikning D asosida urinuvchi va АС tomon o‘rtasidan o‘tuvchi aylana radiusini toping. A) 3 B) 177/48 C) 211/47 D) 175/48 9 / 25 9. 80 ni qanday musbat butun songa bo‘lganda, hosil bo‘ladigan qoldiq bo‘linmaning 25%iga teng bo‘ladi? A) 21 B) 10 C) 11 D) 19 10 / 25 10. Aylananing ОА, ОВ, ОС radiuslari o‘tkazilgan. Agar bo‘lsa, АОВ burchakni toping. A) 30° B) 60° C) 120° D) 90° 11 / 25 11. АВCDE beshburchak berilgan, М, N, Р va Q nuqtalar —АВ, ВС, CD va DE tomonlarning o‘rtalari. Agar U va V — МP? va NQ ning o‘rtasi bo‘lsa, АЕ: UV nisbatni toping. A) 3 B) 5 C) 6 D) 4 12 / 25 12. Soddalashtiring: A) 1 B) 2sinα C) 2 D) cosα 13 / 25 13. Hisoblang: 1 + 2 ∙ 2 + 3 ∙ 22 + 4 ∙ 23+. … + 100 ∙ 299 A) C B) D C) B D) A 14 / 25 14. Aylanaga АВС uchburchak ichki chizilgan. Uchburchakning СС1medianasining davomi aylanani ? nuqtada kesib o‘tadi. ni toping. A) √5 B) 2 C) 1 D) 4 15 / 25 15. ABC uchburchakning AC tomonida shunday D nuqta olinganki, bunda ∠ABC=∠BDC, 5AB=4BD. Agar BC=10 bo‘lsa, ACni toping. A) 8 B) 6 C) 10 D) 12 16 / 25 16. Agar a = √5 + 1 va b = √5 − 1 bo‘lsa, 2a² − ab − a² ifodaning qiymatini toping. A) 6√5 + 1 B) 6√5 + 2 C) √5 + 6 D) 3√5 + 6 17 / 25 17. To‘g‘ri burchakli uchburchak o‘tkir burchaklari yarimlarining tangenslari ko‘paytmasi 1/6 ga teng bo‘lsa, uchburchak o‘tkir burchaklarining kosinuslari yig‘indisini toping. A) √5/2 B) 4/3 C) 1.4 D) √6/2 18 / 25 18. Agar ? + 4/√?= 17 bo‘lsa, ? + 4√? ni toping. A) 3 B) 4 C) 2 D) 1 19 / 25 19. Hisoblang: (1 − tg5°)(1 − tg20°)2 + 2(2tg20° + tg5°) A) 4 B) 1 C) 2 D) 3 20 / 25 20. АВС uchburchak ∠C=60° burchagining bissektrisasi 5√3 ga teng. Agar АС : ВС = 5 :2 bo‘lsa, ВС ni toping. A) B B) D C) C D) A 21 / 25 21. (?²+ 4? + 8)² + 3?³ + 14?² + 24? = 0 tenglamaning ildizlari yig’indisini toping. A) -11 B) -7 C) -6 D) -5 22 / 25 22. Agar ?(?) = ?2021 + 3?2020 + 3?2019 − ?2018 + 1 bo‘lsa, ni toping. A) 1 B) 0 C) 3 D) 2 23 / 25 23. Soddalashtiring: A) III B) II C) IV D) I 24 / 25 24. bo‘lsa, ?² + ?² ni toping. A) 61/20 B) 20 C) 20.2 D) 65/21 25 / 25 25. Sektor perimetri 28 sm ga teng, uning yuzi esa 49 sm2. Sektor yoyining uzunligini toping. A) 18 sm B) 7 sm C) 12 sm D) 14 sm 0% Testni qayta ishga tushiring Author: InfoMaster Foydali bo'lsa mamnunmiz
