7-sinf Matematika olimpiada №1 Aprel 29, 2022Aprel 29, 2022 da chop etilgan InfoMaster tomonidan 7-sinf Matematika olimpiada №1 ga 1 fikr bildirilgan 8 12345678910111213141516171819202122232425 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster 7-sinflar Matematika olimpiada №1 2019-yil bilimlar bellashuvida tushgan savollar Ismi familiyangizni kriting! Iltimos ma'lumotlaringizni to'g'ri kritishga e'tibor bering! 1 / 25 1. Hisoblang: A) IV B) II C) III D) I 2 / 25 2. Agar a=-8,3 bo`lsa, 0,6a+0,4∙(a-5,5) ifodaning qiymatini toping. A) 1,05 B) 10,5 C) – 1,05 D) – 10,5 3 / 25 3. Tenglamani yeching. 4,5-1,6∙(5x-3)=1,2∙(4x-1)-15,1 A) 0 B) 2 C) 1 D) 3 4 / 25 4. Ikkita parallel to`g`ri chiziqlarni to`g`ri chiziq bilan kesishishidan hosil bo`lgan mos burchaklarning yig`indisi 2100 ga teng.Bu burchaklarni toping. A) 110°; 100° B) 105°; 105° C) 80°; 130° D) 115°; 95° 5 / 25 5. M ni shunday birhad bilan almashtiringki, natijada noma’lumning barcha qiymatlarida to`g`ri tenglik hosil bo`lsin: A) III B) II C) I D) IV 6 / 25 6. Ifodani soddalashtiring: A) 15x⁶y¹⁰ B) 15x⁵y⁶ C) 15x⁷y¹⁰ D) 15x⁵y¹⁰ 7 / 25 7. Umumiy AB asosga ega bo`lgan ACB va ADB uchburchaklar berilgan. CD va AB lar O nuqtada kesishadi. Agar ∠DAB= ∠CBA, ∠CAB= ∠DBA, DB=24 sm bo`lsa, CA ni toping. A) 48 sm B) 24 sm C) 30 sm D) 12 sm 8 / 25 8. Uchburchakning ikkita uchidagi tashqi burchaklari o`zaro teng va perimetri 74 sm, uning bir tomoni 16 sm ga teng. Ikkita qolgan tomonlarini toping. A) 29, 30 B) 29, 29 C) 31, 29 D) 27, 32 9 / 25 9. Agar qo`shni burchaklardan biri ikkinchisidan 450 katta bo`lsa,ularni toping . A) 112°30'; 67°30' B) 113°;67° C) 135°;45° D) 111°30'; 68°30' 10 / 25 10. Gazlamaning narxi 20 Ma’lum vaqtdan so’ng, yangi narx ham 25 ortdi. Gazlamaning narxi jami necha foiz ortdi? A) 70 % B) 55 % C) 60 % D) 50 % 11 / 25 11. Sonni standart ko`rinishda yozing: 1247800000 A) III B) IV C) II D) I 12 / 25 12. Ifodani ko`paytuvchilarga ajrating: 9b²-(a-3b)² A) a² B) (6b-a)a C) 18b²-a²+6ab D) (6b-a)(6b+a) 13 / 25 13. Algebraik kasrni qisqartiring: A) IV B) II C) I D) III 14 / 25 14. Tenglamani yeching: 8x+5=119+(7-3x) A) 1,2 B) 12 C) 11 D) 1,1 15 / 25 15. A, B va C nuqtalar bir to`g`ri chiziqda yotadi. Agar AB=14 sm, BC=16,5 sm bo`lsa, AC ni toping. A) 2,5 sm va 30,5 sm B) 2,5 sm C) 30,5 sm D) 3,5 sm va 29,5 sm 16 / 25 16. Qo`shni burchaklar 1450 va 350 ga teng. Bu qo`shni burchaklar bissektrisalari tashkil qilgan burchakni toping. A) 70° B) 86° C) 80° D) 90° 17 / 25 17. Uchburchakning ikki bissektrissasining kesishishidan hosil bo`lgan burchak 1280 ga teng. Uchburchakning uchinchi burchagini toping. A) 64 B) 67 C) 65 D) 66 18 / 25 18. Tenglamaning ildizi x0 bo’lsa, 18:x0 ifodaning son qiymatini toping. A) -7 B) 78/7 C) 6 D) 7 19 / 25 19. Ifodani soddalashtiring: 125a³-225a² b+135ab²-27b³ A) (5a)³-(3b)³ B) (3a+5b)³ C) (3a-5b)³ D) (5a-3b)³ 20 / 25 20. To`g`ri burchakli parallelepipedning asosi tomoni c sm ga teng bo`lgan kvadratdan iborat bo`lib,balandligi d Bu parallelepipeddan qirrasi c sm bo`lgan kub qirqib olindi. Qolgan qismining hajmi V (sm3)ni hisoblash formulasini tuzing. Agar c=2,5 sm, d=4 sm bo`lsa, V ni toping. A) 81/8 B) 9 C) 75/8 D) 1/8 21 / 25 21. Soddalashtiring: 5b-(6b-a)-(a-6b) A) 5b B) 5b+2a C) 17b-2a D) 5b-2a 22 / 25 22. To`g`ri burchakli uchburchakning gipotenuzasiga tushirilgan medianasi 8 sm. Uchburchakning burchaklaridan biri 600 bo`lsa, bu burchakka yopishgan tomonlarini toping (sm). A) 9 B) 5 C) 7 D) 8 23 / 25 23. ABC uchburchakning AD medianasi BC tomondan keyin DE= AD bo`lgan kesmaga davom ettirilib, E nuqta B nuqta bilan tutashtirildi.Agar ∠ACD=450, ∠ABD=350 bo`lsa, ∠ABE ni toping. A) 80° B) 70° C) 75° D) 10° 24 / 25 24. 1, 2, 3, 4, 5, 6 va 7 raqamlaridan, ularni takrorlamasdan nechta 4 xonali son tuzish mumkin? A) 34 ta B) 35 ta C) 36 ta D) 33 ta 25 / 25 25. Ifodaning qiymatini toping: A) 15 B) 25 C) 125 D) 195 0% Testni qayta ishga tushiring tomonidan Wordpress Quiz plugin Matematika olimpiada
