Uy » Online olimpiada » Matematika olimpiada » 7-sinf Matematika olimpiada №1 Matematika olimpiada 7-sinf Matematika olimpiada №1 InfoMaster Aprel 29, 2022 1139 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 3 0 12345678910111213141516171819202122232425 Vaqtingiz tugadi! 7-sinflar Matematika olimpiada №1 2019-yil bilimlar bellashuvida tushgan savollar Ismi familiyangizni kriting! Iltimos ma'lumotlaringizni to'g'ri kritishga e'tibor bering! 1 / 25 1. Ifodani soddalashtiring: 125a³-225a² b+135ab²-27b³ A) (3a-5b)³ B) (3a+5b)³ C) (5a)³-(3b)³ D) (5a-3b)³ 2 / 25 2. ABC uchburchakning AD medianasi BC tomondan keyin DE= AD bo`lgan kesmaga davom ettirilib, E nuqta B nuqta bilan tutashtirildi.Agar ∠ACD=450, ∠ABD=350 bo`lsa, ∠ABE ni toping. A) 80° B) 10° C) 75° D) 70° 3 / 25 3. Algebraik kasrni qisqartiring: A) IV B) II C) III D) I 4 / 25 4. O’lchovlari 8 va 20 ga teng bo’lgan to’g’ri to’rt burchaklardan eng kamida nechtasini birlashtirib, kvadrat hosil qilish mumkin? A) 10 B) 9 C) 11 D) 15 5 / 25 5. Uchburchakning ikki bissektrissasining kesishishidan hosil bo`lgan burchak 1280 ga teng. Uchburchakning uchinchi burchagini toping. A) 66 B) 65 C) 64 D) 67 6 / 25 6. Bir ishni 10 kishi 8 kunda bajara oladi. 2 kundan so`ng, uchinchi kuni ularga yordam berish uchun bir necha kishi qo`shildi va qolgan ishni 4 kunda bajarishdi. Necha kishi kelib qo`shilgan? A) 6 B) 4 C) 5 D) 3 7 / 25 7. Soddalashtiring: 5b-(6b-a)-(a-6b) A) 5b B) 5b-2a C) 17b-2a D) 5b+2a 8 / 25 8. Ikkita parallel to`g`ri chiziqlarni to`g`ri chiziq bilan kesishishidan hosil bo`lgan mos burchaklarning yig`indisi 2100 ga teng.Bu burchaklarni toping. A) 115°; 95° B) 80°; 130° C) 105°; 105° D) 110°; 100° 9 / 25 9. Tenglamaning ildizi x0 bo’lsa, 18:x0 ifodaning son qiymatini toping. A) 7 B) 78/7 C) -7 D) 6 10 / 25 10. Agar a=-8,3 bo`lsa, 0,6a+0,4∙(a-5,5) ifodaning qiymatini toping. A) 1,05 B) – 10,5 C) 10,5 D) – 1,05 11 / 25 11. Umumiy AB asosga ega bo`lgan ACB va ADB uchburchaklar berilgan. CD va AB lar O nuqtada kesishadi. Agar ∠DAB= ∠CBA, ∠CAB= ∠DBA, DB=24 sm bo`lsa, CA ni toping. A) 48 sm B) 24 sm C) 12 sm D) 30 sm 12 / 25 12. Ko’paytuvchilarga ajrating: x⁴+x²+1 A) III B) IV C) II D) I 13 / 25 13. M ni shunday birhad bilan almashtiringki, natijada noma’lumning barcha qiymatlarida to`g`ri tenglik hosil bo`lsin: A) IV B) II C) I D) III 14 / 25 14. Telefon stansiyasi mijozlarining uy telefon raqamlari 7 xonali sonlardan iborat va 573 sonidan boshlanadi. Shu stansiya nechta mijozga xizmat ko`rsatishi mumkin? A) 1000 B) 15000 C) 30000 D) 10000 15 / 25 15. Tenglamani yeching: 8x+5=119+(7-3x) A) 12 B) 1,2 C) 1,1 D) 11 16 / 25 16. Ifodani soddalashtiring: A) 15x⁵y⁶ B) 15x⁵y¹⁰ C) 15x⁶y¹⁰ D) 15x⁷y¹⁰ 17 / 25 17. Uchburchakning ikkita uchidagi tashqi burchaklari o`zaro teng va perimetri 74 sm, uning bir tomoni 16 sm ga teng. Ikkita qolgan tomonlarini toping. A) 31, 29 B) 27, 32 C) 29, 30 D) 29, 29 18 / 25 18. Ifodaning qiymatini toping: A) 15 B) 195 C) 125 D) 25 19 / 25 19. Gazlamaning narxi 20 Ma’lum vaqtdan so’ng, yangi narx ham 25 ortdi. Gazlamaning narxi jami necha foiz ortdi? A) 60 % B) 55 % C) 50 % D) 70 % 20 / 25 20. Sonni standart ko`rinishda yozing: 1247800000 A) IV B) III C) II D) I 21 / 25 21. Qo`shni burchaklar 1450 va 350 ga teng. Bu qo`shni burchaklar bissektrisalari tashkil qilgan burchakni toping. A) 70° B) 90° C) 80° D) 86° 22 / 25 22. Tenglamani yeching. 4,5-1,6∙(5x-3)=1,2∙(4x-1)-15,1 A) 3 B) 2 C) 1 D) 0 23 / 25 23. A, B va C nuqtalar bir to`g`ri chiziqda yotadi. Agar AB=14 sm, BC=16,5 sm bo`lsa, AC ni toping. A) 3,5 sm va 29,5 sm B) 30,5 sm C) 2,5 sm va 30,5 sm D) 2,5 sm 24 / 25 24. Ifodani ko`paytuvchilarga ajrating: 9b²-(a-3b)² A) a² B) (6b-a)(6b+a) C) 18b²-a²+6ab D) (6b-a)a 25 / 25 25. Hisoblang: A) I B) IV C) II D) III 0% Testni qayta ishga tushiring Author: InfoMaster Foydali bo'lsa mamnunmiz
