Uy » Online olimpiada » Matematika olimpiada » 7-sinf Matematika olimpiada №1 Matematika olimpiada 7-sinf Matematika olimpiada №1 InfoMaster Aprel 29, 2022 2523 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 4 3 12345678910111213141516171819202122232425 Vaqtingiz tugadi! 7-sinflar Matematika olimpiada №1 2019-yil bilimlar bellashuvida tushgan savollar Ismi familiyangizni kriting! Iltimos ma'lumotlaringizni to'g'ri kritishga e'tibor bering! 1 / 25 1. Umumiy AB asosga ega bo`lgan ACB va ADB uchburchaklar berilgan. CD va AB lar O nuqtada kesishadi. Agar ∠DAB= ∠CBA, ∠CAB= ∠DBA, DB=24 sm bo`lsa, CA ni toping. A) 30 sm B) 48 sm C) 24 sm D) 12 sm 2 / 25 2. Hisoblang: A) IV B) III C) II D) I 3 / 25 3. Sonni standart ko`rinishda yozing: 1247800000 A) III B) II C) IV D) I 4 / 25 4. Tenglamani yeching. 4,5-1,6∙(5x-3)=1,2∙(4x-1)-15,1 A) 0 B) 3 C) 1 D) 2 5 / 25 5. A, B va C nuqtalar bir to`g`ri chiziqda yotadi. Agar AB=14 sm, BC=16,5 sm bo`lsa, AC ni toping. A) 2,5 sm va 30,5 sm B) 2,5 sm C) 3,5 sm va 29,5 sm D) 30,5 sm 6 / 25 6. O’lchovlari 8 va 20 ga teng bo’lgan to’g’ri to’rt burchaklardan eng kamida nechtasini birlashtirib, kvadrat hosil qilish mumkin? A) 9 B) 10 C) 15 D) 11 7 / 25 7. To`g`ri burchakli uchburchakning gipotenuzasiga tushirilgan medianasi 8 sm. Uchburchakning burchaklaridan biri 600 bo`lsa, bu burchakka yopishgan tomonlarini toping (sm). A) 8 B) 9 C) 5 D) 7 8 / 25 8. Qo`shni burchaklar 1450 va 350 ga teng. Bu qo`shni burchaklar bissektrisalari tashkil qilgan burchakni toping. A) 86° B) 90° C) 70° D) 80° 9 / 25 9. Uchburchakning ikkita uchidagi tashqi burchaklari o`zaro teng va perimetri 74 sm, uning bir tomoni 16 sm ga teng. Ikkita qolgan tomonlarini toping. A) 27, 32 B) 29, 29 C) 31, 29 D) 29, 30 10 / 25 10. Ko’paytuvchilarga ajrating: x⁴+x²+1 A) IV B) I C) II D) III 11 / 25 11. Algebraik kasrni qisqartiring: A) IV B) I C) II D) III 12 / 25 12. Uchburchakning ikki bissektrissasining kesishishidan hosil bo`lgan burchak 1280 ga teng. Uchburchakning uchinchi burchagini toping. A) 64 B) 66 C) 67 D) 65 13 / 25 13. Agar a=-8,3 bo`lsa, 0,6a+0,4∙(a-5,5) ifodaning qiymatini toping. A) – 10,5 B) – 1,05 C) 1,05 D) 10,5 14 / 25 14. Telefon stansiyasi mijozlarining uy telefon raqamlari 7 xonali sonlardan iborat va 573 sonidan boshlanadi. Shu stansiya nechta mijozga xizmat ko`rsatishi mumkin? A) 30000 B) 10000 C) 15000 D) 1000 15 / 25 15. Ikkita parallel to`g`ri chiziqlarni to`g`ri chiziq bilan kesishishidan hosil bo`lgan mos burchaklarning yig`indisi 2100 ga teng.Bu burchaklarni toping. A) 110°; 100° B) 105°; 105° C) 80°; 130° D) 115°; 95° 16 / 25 16. Tenglamani yeching: 8x+5=119+(7-3x) A) 1,2 B) 12 C) 11 D) 1,1 17 / 25 17. To`g`ri burchakli parallelepipedning asosi tomoni c sm ga teng bo`lgan kvadratdan iborat bo`lib,balandligi d Bu parallelepipeddan qirrasi c sm bo`lgan kub qirqib olindi. Qolgan qismining hajmi V (sm3)ni hisoblash formulasini tuzing. Agar c=2,5 sm, d=4 sm bo`lsa, V ni toping. A) 1/8 B) 9 C) 75/8 D) 81/8 18 / 25 18. 1, 2, 3, 4, 5, 6 va 7 raqamlaridan, ularni takrorlamasdan nechta 4 xonali son tuzish mumkin? A) 33 ta B) 35 ta C) 36 ta D) 34 ta 19 / 25 19. ABC uchburchakning AD medianasi BC tomondan keyin DE= AD bo`lgan kesmaga davom ettirilib, E nuqta B nuqta bilan tutashtirildi.Agar ∠ACD=450, ∠ABD=350 bo`lsa, ∠ABE ni toping. A) 70° B) 75° C) 10° D) 80° 20 / 25 20. Soddalashtiring: 5b-(6b-a)-(a-6b) A) 5b B) 17b-2a C) 5b-2a D) 5b+2a 21 / 25 21. M ni shunday birhad bilan almashtiringki, natijada noma’lumning barcha qiymatlarida to`g`ri tenglik hosil bo`lsin: A) III B) IV C) II D) I 22 / 25 22. Tenglamaning ildizi x0 bo’lsa, 18:x0 ifodaning son qiymatini toping. A) 78/7 B) 7 C) 6 D) -7 23 / 25 23. Ifodani soddalashtiring: 125a³-225a² b+135ab²-27b³ A) (5a-3b)³ B) (3a+5b)³ C) (5a)³-(3b)³ D) (3a-5b)³ 24 / 25 24. Ifodani soddalashtiring: A) 15x⁶y¹⁰ B) 15x⁷y¹⁰ C) 15x⁵y¹⁰ D) 15x⁵y⁶ 25 / 25 25. Agar qo`shni burchaklardan biri ikkinchisidan 450 katta bo`lsa,ularni toping . A) 135°;45° B) 113°;67° C) 111°30'; 68°30' D) 112°30'; 67°30' 0% Testni qayta ishga tushiring Author: InfoMaster Foydali bo'lsa mamnunmiz
