Uy » Online olimpiada » Matematika olimpiada » 7-sinf Matematika olimpiada №1 Matematika olimpiada 7-sinf Matematika olimpiada №1 InfoMaster Aprel 29, 2022 1378 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 3 7 12345678910111213141516171819202122232425 Vaqtingiz tugadi! 7-sinflar Matematika olimpiada №1 2019-yil bilimlar bellashuvida tushgan savollar Ismi familiyangizni kriting! Iltimos ma'lumotlaringizni to'g'ri kritishga e'tibor bering! 1 / 25 1. Algebraik kasrni qisqartiring: A) IV B) I C) II D) III 2 / 25 2. ABC uchburchakning AD medianasi BC tomondan keyin DE= AD bo`lgan kesmaga davom ettirilib, E nuqta B nuqta bilan tutashtirildi.Agar ∠ACD=450, ∠ABD=350 bo`lsa, ∠ABE ni toping. A) 70° B) 75° C) 80° D) 10° 3 / 25 3. Uchburchakning ikki bissektrissasining kesishishidan hosil bo`lgan burchak 1280 ga teng. Uchburchakning uchinchi burchagini toping. A) 65 B) 64 C) 67 D) 66 4 / 25 4. Ifodaning qiymatini toping: A) 125 B) 25 C) 15 D) 195 5 / 25 5. Ifodani soddalashtiring: A) 15x⁵y⁶ B) 15x⁷y¹⁰ C) 15x⁵y¹⁰ D) 15x⁶y¹⁰ 6 / 25 6. A, B va C nuqtalar bir to`g`ri chiziqda yotadi. Agar AB=14 sm, BC=16,5 sm bo`lsa, AC ni toping. A) 2,5 sm B) 30,5 sm C) 2,5 sm va 30,5 sm D) 3,5 sm va 29,5 sm 7 / 25 7. To`g`ri burchakli uchburchakning gipotenuzasiga tushirilgan medianasi 8 sm. Uchburchakning burchaklaridan biri 600 bo`lsa, bu burchakka yopishgan tomonlarini toping (sm). A) 8 B) 9 C) 5 D) 7 8 / 25 8. Telefon stansiyasi mijozlarining uy telefon raqamlari 7 xonali sonlardan iborat va 573 sonidan boshlanadi. Shu stansiya nechta mijozga xizmat ko`rsatishi mumkin? A) 30000 B) 10000 C) 1000 D) 15000 9 / 25 9. 1, 2, 3, 4, 5, 6 va 7 raqamlaridan, ularni takrorlamasdan nechta 4 xonali son tuzish mumkin? A) 34 ta B) 33 ta C) 36 ta D) 35 ta 10 / 25 10. To`g`ri burchakli parallelepipedning asosi tomoni c sm ga teng bo`lgan kvadratdan iborat bo`lib,balandligi d Bu parallelepipeddan qirrasi c sm bo`lgan kub qirqib olindi. Qolgan qismining hajmi V (sm3)ni hisoblash formulasini tuzing. Agar c=2,5 sm, d=4 sm bo`lsa, V ni toping. A) 1/8 B) 81/8 C) 75/8 D) 9 11 / 25 11. Hisoblang: A) II B) I C) III D) IV 12 / 25 12. M ni shunday birhad bilan almashtiringki, natijada noma’lumning barcha qiymatlarida to`g`ri tenglik hosil bo`lsin: A) III B) II C) IV D) I 13 / 25 13. Tenglamaning ildizi x0 bo’lsa, 18:x0 ifodaning son qiymatini toping. A) 78/7 B) 7 C) -7 D) 6 14 / 25 14. Tenglamani yeching. 4,5-1,6∙(5x-3)=1,2∙(4x-1)-15,1 A) 0 B) 1 C) 3 D) 2 15 / 25 15. Gazlamaning narxi 20 Ma’lum vaqtdan so’ng, yangi narx ham 25 ortdi. Gazlamaning narxi jami necha foiz ortdi? A) 55 % B) 60 % C) 50 % D) 70 % 16 / 25 16. Ikkita parallel to`g`ri chiziqlarni to`g`ri chiziq bilan kesishishidan hosil bo`lgan mos burchaklarning yig`indisi 2100 ga teng.Bu burchaklarni toping. A) 110°; 100° B) 80°; 130° C) 115°; 95° D) 105°; 105° 17 / 25 17. Ifodani soddalashtiring: 125a³-225a² b+135ab²-27b³ A) (3a+5b)³ B) (5a-3b)³ C) (3a-5b)³ D) (5a)³-(3b)³ 18 / 25 18. Ko’paytuvchilarga ajrating: x⁴+x²+1 A) II B) I C) III D) IV 19 / 25 19. Asosi BC bo`lgan teng yonli ABC uchburchakning perimetri 40 sm va teng tomonli BCD uchburchakning perimetri 45 sm ga teng. AB va BC tomonlarni toping. A) AB =16 sm; BC =12 sm; B) AB =12,5 sm; BC =15 sm; C) AB =12 sm; BC =16 sm; D) AB =15 sm; BC =12,5 sm; 20 / 25 20. Sonni standart ko`rinishda yozing: 1247800000 A) II B) I C) IV D) III 21 / 25 21. Qo`shni burchaklar 1450 va 350 ga teng. Bu qo`shni burchaklar bissektrisalari tashkil qilgan burchakni toping. A) 90° B) 86° C) 70° D) 80° 22 / 25 22. Soddalashtiring: 5b-(6b-a)-(a-6b) A) 17b-2a B) 5b+2a C) 5b D) 5b-2a 23 / 25 23. Tenglamani yeching: 8x+5=119+(7-3x) A) 1,2 B) 12 C) 11 D) 1,1 24 / 25 24. O’lchovlari 8 va 20 ga teng bo’lgan to’g’ri to’rt burchaklardan eng kamida nechtasini birlashtirib, kvadrat hosil qilish mumkin? A) 11 B) 9 C) 15 D) 10 25 / 25 25. Uchburchakning ikkita uchidagi tashqi burchaklari o`zaro teng va perimetri 74 sm, uning bir tomoni 16 sm ga teng. Ikkita qolgan tomonlarini toping. A) 29, 29 B) 31, 29 C) 29, 30 D) 27, 32 0% Testni qayta ishga tushiring Author: InfoMaster Foydali bo'lsa mamnunmiz