Barcha fanlardan online testlar

7-sinf Matematika olimpiada №1

InfoMaster

Aprel 29, 2022

520 Ko'rishlar 1 izoh

SaqlashSaqlanganOlib tashlandi 1

7-sinflar Matematika olimpiada №1

2019-yil bilimlar bellashuvida tushgan savollar

Ismi familiyangizni kriting!

Iltimos ma'lumotlaringizni to'g'ri kritishga e'tibor bering!

1 / 25

1. To`g`ri burchakli uchburchakning gipotenuzasiga tushirilgan medianasi 8 sm. Uchburchakning burchaklaridan biri 60⁰bo`lsa, bu burchakka yopishgan tomonlarini toping (sm).

A) 7

B) 8

C) 5

D) 9

2 / 25

2. Ifodaning qiymatini toping:

A) 125

B) 195

C) 25

D) 15

3 / 25

3. Tenglamani yeching: 8x+5=119+(7-3x)

A) 11

B) 1,2

C) 12

D) 1,1

4 / 25

4. Algebraik kasrni qisqartiring:

A) I

B) II

C) III

D) IV

5 / 25

5. Agar qo`shni burchaklardan biri ikkinchisidan 45⁰katta bo`lsa,ularni toping .

A) 113°;67°

B) 111°30'; 68°30'

C) 135°;45°

D) 112°30'; 67°30'

6 / 25

6. Ifodani soddalashtiring: 125a³-225a² b+135ab²-27b³

A) (5a-3b)³

B) (5a)³-(3b)³

C) (3a+5b)³

D) (3a-5b)³

7 / 25

7. Ko’paytuvchilarga ajrating: x⁴+x²+1

A) II

B) III

C) IV

D) I

8 / 25

8. Agar a=-8,3 bo`lsa, 0,6a+0,4∙(a-5,5) ifodaning qiymatini toping.

A) – 1,05

B) – 10,5

C) 1,05

D) 10,5

9 / 25

9. Asosi BC bo`lgan teng yonli ABC uchburchakning perimetri 40 sm va teng tomonli BCD uchburchakning perimetri 45 sm ga teng. AB va BC tomonlarni toping.

A) AB =12 sm; BC =16 sm;

B) AB =16 sm; BC =12 sm;

C) AB =15 sm; BC =12,5 sm;

D) AB =12,5 sm; BC =15 sm;

10 / 25

10. Umumiy AB asosga ega bo`lgan ACB va ADB uchburchaklar berilgan. CD va AB lar O nuqtada kesishadi. Agar ∠DAB= ∠CBA, ∠CAB= ∠DBA, DB=24 sm bo`lsa, CA ni toping.

A) 12 sm

B) 24 sm

C) 30 sm

D) 48 sm

11 / 25

11. 1, 2, 3, 4, 5, 6 va 7 raqamlaridan, ularni takrorlamasdan nechta 4 xonali son tuzish mumkin?

A) 36 ta

B) 33 ta

C) 34 ta

D) 35 ta

12 / 25

12. Qo`shni burchaklar 145⁰va 35⁰ga teng. Bu qo`shni burchaklar bissektrisalari tashkil qilgan burchakni toping.

A) 86°

B) 80°

C) 70°

D) 90°

13 / 25

13. Uchburchakning ikki bissektrissasining kesishishidan hosil bo`lgan burchak 128⁰ ga teng. Uchburchakning uchinchi burchagini toping.

A) 64

B) 66

C) 65

D) 67

14 / 25

14. Sonni standart ko`rinishda yozing: 1247800000

A) II

B) I

C) IV

D) III

15 / 25

15. Tenglamaning ildizi x₀bo’lsa, 18:x₀ ifodaning son qiymatini toping.

A) -7

B) 78/7

C) 6

D) 7

16 / 25

16. A, B va C nuqtalar bir to`g`ri chiziqda yotadi. Agar AB=14 sm, BC=16,5 sm bo`lsa, AC ni toping.

A) 2,5 sm

B) 30,5 sm

C) 3,5 sm va 29,5 sm

D) 2,5 sm va 30,5 sm

17 / 25

17. Tenglamani yeching. 4,5-1,6∙(5x-3)=1,2∙(4x-1)-15,1

A) 3

B) 2

C) 0

D) 1

18 / 25

18. Ifodani soddalashtiring:

A) 15x⁶y¹⁰

B) 15x⁷y¹⁰

C) 15x⁵y¹⁰

D) 15x⁵y⁶

19 / 25

19. Uchburchakning ikkita uchidagi tashqi burchaklari o`zaro teng va perimetri 74 sm, uning bir tomoni 16 sm ga teng. Ikkita qolgan tomonlarini toping.

A) 29, 29

B) 27, 32

C) 29, 30

D) 31, 29

20 / 25

20. O’lchovlari 8 va 20 ga teng bo’lgan to’g’ri to’rt burchaklardan eng kamida nechtasini birlashtirib, kvadrat hosil qilish mumkin?

A) 9

B) 10

C) 15

D) 11

21 / 25

21. Ifodani ko`paytuvchilarga ajrating: 9b²-(a-3b)²

A) 18b²-a²+6ab

B) (6b-a)(6b+a)

C) (6b-a)a

D) a²

22 / 25

22. Hisoblang:

A) I

B) II

C) III

D) IV

23 / 25

23. To`g`ri burchakli parallelepipedning asosi tomoni c sm ga teng bo`lgan kvadratdan iborat bo`lib,balandligi d Bu parallelepipeddan qirrasi c sm bo`lgan kub qirqib olindi. Qolgan qismining hajmi V (sm³)ni hisoblash formulasini tuzing. Agar c=2,5 sm, d=4 sm bo`lsa, V ni toping.

A) 9

B) 75/8

C) 1/8

D) 81/8

24 / 25

24. M ni shunday birhad bilan almashtiringki, natijada noma’lumning barcha qiymatlarida to`g`ri tenglik hosil bo`lsin:

A) I

B) IV

C) III

D) II

25 / 25

25. Telefon stansiyasi mijozlarining uy telefon raqamlari 7 xonali sonlardan iborat va 573 sonidan boshlanadi. Shu stansiya nechta mijozga xizmat ko`rsatishi mumkin?

A) 10000

B) 15000

C) 1000

D) 30000