Uy » Online olimpiada » Matematika olimpiada » 7-sinf Matematika olimpiada №1 Matematika olimpiada 7-sinf Matematika olimpiada №1 InfoMaster Aprel 29, 2022 1374 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 3 7 12345678910111213141516171819202122232425 Vaqtingiz tugadi! 7-sinflar Matematika olimpiada №1 2019-yil bilimlar bellashuvida tushgan savollar Ismi familiyangizni kriting! Iltimos ma'lumotlaringizni to'g'ri kritishga e'tibor bering! 1 / 25 1. Uchburchakning ikkita uchidagi tashqi burchaklari o`zaro teng va perimetri 74 sm, uning bir tomoni 16 sm ga teng. Ikkita qolgan tomonlarini toping. A) 31, 29 B) 27, 32 C) 29, 29 D) 29, 30 2 / 25 2. Ifodani soddalashtiring: A) 15x⁷y¹⁰ B) 15x⁶y¹⁰ C) 15x⁵y¹⁰ D) 15x⁵y⁶ 3 / 25 3. Agar a=-8,3 bo`lsa, 0,6a+0,4∙(a-5,5) ifodaning qiymatini toping. A) 10,5 B) – 1,05 C) 1,05 D) – 10,5 4 / 25 4. Tenglamani yeching: 8x+5=119+(7-3x) A) 1,2 B) 1,1 C) 12 D) 11 5 / 25 5. O’lchovlari 8 va 20 ga teng bo’lgan to’g’ri to’rt burchaklardan eng kamida nechtasini birlashtirib, kvadrat hosil qilish mumkin? A) 9 B) 15 C) 10 D) 11 6 / 25 6. Soddalashtiring: 5b-(6b-a)-(a-6b) A) 5b-2a B) 5b+2a C) 5b D) 17b-2a 7 / 25 7. Algebraik kasrni qisqartiring: A) IV B) II C) III D) I 8 / 25 8. Umumiy AB asosga ega bo`lgan ACB va ADB uchburchaklar berilgan. CD va AB lar O nuqtada kesishadi. Agar ∠DAB= ∠CBA, ∠CAB= ∠DBA, DB=24 sm bo`lsa, CA ni toping. A) 30 sm B) 12 sm C) 48 sm D) 24 sm 9 / 25 9. To`g`ri burchakli parallelepipedning asosi tomoni c sm ga teng bo`lgan kvadratdan iborat bo`lib,balandligi d Bu parallelepipeddan qirrasi c sm bo`lgan kub qirqib olindi. Qolgan qismining hajmi V (sm3)ni hisoblash formulasini tuzing. Agar c=2,5 sm, d=4 sm bo`lsa, V ni toping. A) 9 B) 81/8 C) 75/8 D) 1/8 10 / 25 10. Agar qo`shni burchaklardan biri ikkinchisidan 450 katta bo`lsa,ularni toping . A) 112°30'; 67°30' B) 135°;45° C) 111°30'; 68°30' D) 113°;67° 11 / 25 11. Hisoblang: A) I B) II C) IV D) III 12 / 25 12. Ifodani soddalashtiring: 125a³-225a² b+135ab²-27b³ A) (5a)³-(3b)³ B) (5a-3b)³ C) (3a-5b)³ D) (3a+5b)³ 13 / 25 13. M ni shunday birhad bilan almashtiringki, natijada noma’lumning barcha qiymatlarida to`g`ri tenglik hosil bo`lsin: A) III B) I C) IV D) II 14 / 25 14. Telefon stansiyasi mijozlarining uy telefon raqamlari 7 xonali sonlardan iborat va 573 sonidan boshlanadi. Shu stansiya nechta mijozga xizmat ko`rsatishi mumkin? A) 10000 B) 15000 C) 30000 D) 1000 15 / 25 15. Ifodani ko`paytuvchilarga ajrating: 9b²-(a-3b)² A) (6b-a)a B) 18b²-a²+6ab C) (6b-a)(6b+a) D) a² 16 / 25 16. Tenglamani yeching. 4,5-1,6∙(5x-3)=1,2∙(4x-1)-15,1 A) 0 B) 1 C) 3 D) 2 17 / 25 17. Ko’paytuvchilarga ajrating: x⁴+x²+1 A) II B) I C) III D) IV 18 / 25 18. ABC uchburchakning AD medianasi BC tomondan keyin DE= AD bo`lgan kesmaga davom ettirilib, E nuqta B nuqta bilan tutashtirildi.Agar ∠ACD=450, ∠ABD=350 bo`lsa, ∠ABE ni toping. A) 10° B) 70° C) 75° D) 80° 19 / 25 19. A, B va C nuqtalar bir to`g`ri chiziqda yotadi. Agar AB=14 sm, BC=16,5 sm bo`lsa, AC ni toping. A) 30,5 sm B) 3,5 sm va 29,5 sm C) 2,5 sm va 30,5 sm D) 2,5 sm 20 / 25 20. To`g`ri burchakli uchburchakning gipotenuzasiga tushirilgan medianasi 8 sm. Uchburchakning burchaklaridan biri 600 bo`lsa, bu burchakka yopishgan tomonlarini toping (sm). A) 5 B) 8 C) 7 D) 9 21 / 25 21. 1, 2, 3, 4, 5, 6 va 7 raqamlaridan, ularni takrorlamasdan nechta 4 xonali son tuzish mumkin? A) 35 ta B) 33 ta C) 36 ta D) 34 ta 22 / 25 22. Uchburchakning ikki bissektrissasining kesishishidan hosil bo`lgan burchak 1280 ga teng. Uchburchakning uchinchi burchagini toping. A) 67 B) 65 C) 66 D) 64 23 / 25 23. Sonni standart ko`rinishda yozing: 1247800000 A) I B) III C) II D) IV 24 / 25 24. Ifodaning qiymatini toping: A) 25 B) 15 C) 125 D) 195 25 / 25 25. Tenglamaning ildizi x0 bo’lsa, 18:x0 ifodaning son qiymatini toping. A) 7 B) -7 C) 78/7 D) 6 0% Testni qayta ishga tushiring Author: InfoMaster Foydali bo'lsa mamnunmiz
