Matematika attestatsiya №8

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OMAD YOR BO'LSIN!

Matematika fanidan attestatsiya savollari №8

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Testda 76% va undan yuqori natija oling va sertifikatni yuklab oling.

1 / 40

Agar f(g(x))=x^2-5x+6  va g(x)=x-2  bo'lsa  f(4)  ning qiymatini toping.

2 / 40

Tengsizlikni yeching.

3 / 40

Quyidagi berilgan qoldiqli bo`lishlardan qaysi biri to`g`ribajarilgan ?
a)76 : 9 = 7 (qoldiq 13);
b)20 : 7 = 2 (qoldiq 6);
d)54 : 15 = 4 (qoldiq 1)

4 / 40

Dastlabki n ta hadining yig‘indisi formula bilan aniqlanadigan arifmetik progressiyaning 6-hadini toping.

5 / 40

1+sin 2x = 7(sin x + cos x) tenglamani yeching.

 

6 / 40

 ni hisoblang.

 

7 / 40

Tenglamaning haqiqiy ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping.

8 / 40

Quyidagilardan qaysi biri to‘g‘ri?

9 / 40

Agar a∈[-3;1] va b∈[-2;2]bo‘lsa, a² + b³ qanday oraliqda bo‘ladi?

10 / 40

22022 raqamlar yig‘indisidan hosil bo‘lgan sonning raqamlar yig‘indisidan hosil bo‘lgan sonning  raqamlar yig‘indisi hosil qilindi va hokazo. Oxirida bitta raqam qolgan bo‘lsa, shu raqamni toping.

11 / 40

(a²+b²+9)x²+2(a+b+3)x+3 = 0 tenglama haqiqiy yechimlarga ega bo‘lsa, 3a – b ni toping.

12 / 40

f(x) = log₃(x+3) bo'lsa,  f-1(3)  ni toping.

13 / 40

Birinchi va oxirgi raqami juft bo‘lgan va 1000 ga bo‘linmaydigan barcha to‘rtxonali sonlar nechta?

14 / 40

Tenglamaning haqiqiy ildizlari o‘rta arifmetigini toping:

15 / 40

Agar aylananing o‘zaro parallel bo‘lgan uzunliklari 38, 38 va 34 ga teng vatarlari orasidagi masofalar bir xil bo‘lsa, shu masofani toping.

16 / 40

Uchburchakning 10 ga teng balandligi uning asosini 4 va 10 ga teng kesmalarga ajratadi. Uchburchakning qolgan ikki tomonidan kichigiga o‘tkazilgan mediana uzunligini uchdan birini toping.

17 / 40

Hisoblang.

18 / 40

Kubning diagonalidan ushbu diagonal bilan kesishmaydigan qirrasigacha bo‘lgan masofa 4 ga teng. Kubning hajmini toping.

19 / 40

Hisoblang.

20 / 40

ABC to‘g‘ri burchakli uchburchakda ∠B =90° , BC = 28, AC =100 va AB tomonda D nuqta shunday olinganki BD = 21 bo‘ladi. sin (∠ACD) ?

21 / 40

Agar a,b>0 sonlari uchun f(a·b) = f(a) + f(b) tengligi, p – tub sonlari uchun esa  f(p)=p tengligi
qanoatlantirilsa, u holda f(25/11) ning qiymatini toping.

22 / 40

I, M , O - turli natural sonlar uchun I·M·O = 2022 bo‘lsa, I + M+O yig‘indining mumkin bo‘lgan eng katta va eng kichik qiymatlari yig‘indisini toping.

23 / 40

Agar cos9α = 4cosα bo'lsa, (4cos²3α-3)(4cos²α-3) ning qiymatini toping.

24 / 40

x>0 da x + √x = 3 bo'lsa,  √x -3/√x  ifodaning qiymatini toping.

25 / 40

y=sin²(x/2-π/4)  + 2cos2x  funksiyaning eng kichik musbat davrini toping

26 / 40

f (x) = (x² )1−logxa funksiya uchun, f (3x+1) = ax−1 bo`lsa, a parametr quyidagilardan qaysi biriga teng?

27 / 40

Ushbu {1, 2, 3, 4, …, 37} to‘plamdan shunday ikkita son tanlanganki, ularning ko‘paytmasi qolgan 35 ta sonning yig‘indisiga teng. Shu ikki sonning farqini toping.

28 / 40

Agar n = 2018 bo‘lsa,  ifodaning qiymatini toping.

29 / 40

∇ABC da ∠BAC = 30° , AC = f ′(3) va AB = f (3) bo‘lsa, ∇ABC ning yuzini toping. Bunda f(x) = x³ - 5x -4

30 / 40

Arifmetik progressiyada a3+a6+a9+....+a3n=80 bo‘lsa,  a2n-3+an+6=16 bo‘lsa, n ning qiymatini toping.

31 / 40

f(g(x))=x² + 4x - 1,   g(x)=x + a   va f′(0)=1 bo'lsa, α ni toping.

32 / 40

To‘g‘ri burchakli uchburchakning gipotenuzasidan olingan nuqtadan uning katetlariga parallel qilib o‘tkazilgan to‘g‘ri chiziqlar uchburchakdan bitta kvadrat va ikkita kichkina to‘g‘ri burchakli uchburchak ajratadi. Agar shu uchburchaklardan birining yuzining kvadrat yuziga nisbati m ga teng bo‘lsa, ikkinchi uchburchak yuzining shu kvadrat yuziga nisbatini toping.

33 / 40

Agar N = 34·34·63·270 sonning toq bo‘luvchilari yig‘indisining, juft bo‘luvchilari yig‘indisiga nisbatini toping.

34 / 40

ABCD to‘g‘ri to‘rtburchakda CD tomonining o‘rtasi E nuqta, EA kesmaning o‘rtasi esa F nuqta.  AB=4 va bu to‘g‘ri to‘rtburchakning yuzi 8 ga teng bo‘lsa, BF/FA nisbat nechiga teng bo‘ladi?

35 / 40

Agar bo‘lsa, √200 ni x orqali ifodalang.

36 / 40

Agar Sn arifmetik progressiyaning birinchi n ta hadining yig‘indisi bo‘lsa, Sn+3 − 3Sn+2 + 3Sn+1 − Sn ni hisoblang.

37 / 40

Agar x+1/x=1 bo'lsa,   ning qiymatini toping.

38 / 40

x, y, z sonlari uchun x > y > z va x + y + z + 18 munosabatlar o‘rinli. Bu 3 ta son bir-biridan 1, 2 va 3 sonlariga farq qiladi. Shunga ko‘ra x ning mumkin bo‘lgan barcha qiymatlari yig‘indisini
toping.

39 / 40

ABCD to‘g‘ri to‘rtburchak bo‘lib, DM kesma to‘rtburchak tekisligiga perpendikulyar. Agar DM kesmaning uzunligi butun son bo‘lib, MA, MC va MB kesma uzunliklari mos ravsihda ketma-ket kelgan toq sonlar bo‘lsa, u holda MABCD piramida hajmini toping.

40 / 40

ABCD to‘g‘ri to‘rtburchakda AB = 20, BC = 10. CD tomondan shunday E nuqta olinganki, bunda ∠CBE = 15° . AE kesma uzunligini toping.

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Baholash mezoni

- 75 foiz va undan yuqori ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, oliy malaka toifasi (bosh o’qituvchi lavozimi) saqlansin”;

- 75 foizdan past ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, birinchi malaka toifasi (yetakchi o’qituvchi lavozimi)ga tushirilsin”;

- 75 foiz va undan yuqori ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, oliy malaka toifasi (bosh o’qituvchi lavozimi) berilsin”;

- 74 foizdan 65 foizgacha ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, birinchi malaka toifasi (yetakchi o’qituvchi lavozimi) saqlansin”;

- 65 foizdan kam ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, ikkinchi malaka toifasi (katta o’qituvchi lavozimi)ga tushirilsin”

- 64 foizdan 60 foizgacha ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, ikkinchi malaka toifasi (katta o’qituvchi lavozimi) saqlansin”;

- 60 foizdan kam ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, mutaxassis (oliy yoki o’rta maxsus, kasb-hunar ma'lumotli o’qituvchi) lavozimiga tushirilsin”

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“ Matematika attestatsiya №8” bo‘yicha fikrlar (30)

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