Matematika attestatsiya №7

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Matematika fanidan attestatsiya savollari №7

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Testda 76% va undan yuqori natija oling va sertifikatni yuklab oling.

1 / 40

Kamayish tartibida joylashtiring.

a)5√6
b)12
c)4√10

A) c>a>b

B) b>a>c

C) a>b>c

D) a>c>b

2 / 40

tenglamalar sistemasi yechimga ega bo‘ladigan a ning barcha qiymatlari to‘plamini toping.

A) 4

B) 3

C) 2

D) 1

3 / 40

Aniq integralni hisoblang:

A) 0

B) 3

C) 0,5

D) 2

4 / 40

x⁴+8x³+ax²+bx+1 ko'phadning kvadrati bo'lsa, a va b koeffitiyentlarning barcha qiymatlari yig'indisini toping.

A) 32

B) 27

C) 48

D) 26

5 / 40

Quyida berilgan tizimda yonma - yon shakillardagisonlar ustida pasdagi ( EKUB yoki EKUK topish) amali bajariladi , natija amal pastigi shakilga yoziladi

Shunga ko`ra 1 , 2 va 3 amallar EKUB yoki EKUK dan qaysi biri bo`lishi kerak

A) 1-EKUB 2-EKUB 3-EKUB

B) 1-EKUB 2-EKUK 3-EKUK

C) 1-EKUB 2-EKUK 3-EKUB

D) 1-EKUB 2-EKUB 3-EKUK

6 / 40

Hisoblang 200−199+198−197+⋯+4−3

A) 100

B) 101

C) 98

D) 99

7 / 40

Burchagi 120° ga teng bo‘lgan doiraviy sektorga ichki doira chizilgan. Berilgan doiraning radiusi R ga teng bo‘lsa, yangi doiraning radiusi topilsin.

A) R(√3-√2)

B) 3R

C) √3R(2-√3)

D) 1,5R

8 / 40

Agar f(x) funksiya (-∞;∞) da qat’iy o‘suvchi funksiya bo‘lsa, y =3 f(x)-8 funksiya uchun quyidagi mulohazalardan qaysi biri to‘g‘ri bo‘ladi?

A) dastlab kamayadi, keyin o‘sadi

B) qat’iy o‘suvchi

C) dastlab o‘sadi, keyin kamayadi

D) qat’iy kamayuvchi

9 / 40

Tenglamani yeching:

A) 5

B) -6; 5

C) 6; -5

D) -6

10 / 40

b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi?

A) 3 yoki –8

B) 5 yoki –15

C) 4 yoki –12

D) 6

11 / 40

Hisoblang:

A) 16/9

B) 9/16

C) 36/16

D) 1

12 / 40

ning natural bo‘luvchlari 70 ta bo‘lsa, x ni toping.

A) 4

B) 2

C) 5

D) 3

13 / 40

va
EKUB( x, y, z)= 6 bo‘lsa,
EKUK)x, y, z)= ?

A) 216

B) 264

C) 240

D) 192

14 / 40

Tenglamalar sistemasidan foydalanib x + 3y ni toping.

A) 4

B) 6

C) 8

D) 5

15 / 40

ABCD trapetsiyaning AD kichik asosi 6 ga teng. C burchagining CF bissektrisasi AB tomonga perpendikulyar bo‘lib, bunda BF = 3AF = 6 bo‘lsa, katta asos uzunligini toping.

A) 15

B) 18

C) 12

D) 9

16 / 40

Tenglamaning haqiqiy ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping.

A) 12

B) 8

C) 1

D) 9

17 / 40

Agar bo‘lsa, tgα ni toping.

A) 1

B) 2

C) 4

D) 3

18 / 40

|x²-5ax|=15a tenglama bitta manfiy va 3 ta musbat ildizga ega bo‘ladigan a larni toping.

A) (0;2,4]

B) (0; 2,5]

C) (2,4;∞)

D) [2,5;∞)

19 / 40

Diagonallarining soni tomonlari sonidan 1,5 marta ko‘p bo‘lgan muntazam ko‘pburchakning tomoni 4 ga teng bo‘lsa, unga ichki chizilgan doira yuzini toping.

A) 10π

B) 12π

C) 16π

D) 8π

20 / 40

4·(-5)-6·(-3)+(-5)·(-2) sonli ifoda qiymatini toping.

A) 12

B) 48

C) 8

D) -12

21 / 40

3 ni 14 ga bo‘lganda verguldan keyingi yettinchi raqamni toping.

A) 7

B) 6

C) 5

D) 8

22 / 40

ABCD qavariq to‘rtburchakka aylana ichki chizilgan. AB = 8 va BC = 12 bo‘lsa, CD – AD ayirmani toping?

A) 3

B) 4

C) 2

D) aniqlab bo’lmaydi

23 / 40

P(x)=3x⁵-2x⁴+4x³+2x²-1 ko‘phadni x²- x +1 ga bo‘lgandagi qoldiqni toping.

A) x+4

B) x-1

C) x-4

D) x-10

24 / 40

Tenglama nechta yechimga ega?

A) 2

B) 0

C) 3

D) 1

25 / 40

Tengsizlikning manfiy yechimlari o‘rta arifmetigini toping.

A) -1

B) -2

C) -1,5

D) -3

26 / 40

sonining oxirgi raqamini toping.

A) 1

B) 0

C) 3

D) 9

27 / 40

ABCD parallelogrammda A burchakdan o‘tkazilgan bissektrisa BC tomonni E nuqtada kesib o‘tadi. Agar AB=9 va AD=15 cm bo‘lsa, BE va EC kesmalarni (cm) toping.

A) 10;5

B) 9; 6

C) 5; 10

D) 6; 9

28 / 40

bo‘lsa, f ''(1) ning qiymatini toping.

A) -24

B) 0

C) -12

D) 12

29 / 40

ni hisoblang.

A) 30

B) 0,3

C) 3

D) 15

30 / 40

8x²+4x³-3x-7=0 tenglama ildizlari ko‘paytmasini toping.

A) -3

B) -4

C) -2

D) 1,75

31 / 40

Ifodani soddalashtiring:

A) 0

B) 2

C) 1

D) √3

32 / 40

Ishchining maoshi 900000 so‘m edi. Uning maoshi ketma-ket ikki marta bir xil foizga oshgandan so‘ng, 1190250 so‘m bo‘ldi. Maosh har safar necha foizga oshgan?

A) 12

B) 18

C) 14

D) 15

33 / 40

Qavariq ko‘pburchakning diagonallari soni 5 ga teng bo‘lsa, burchaklari sonini toping.

A) 7

B) 4

C) 5

D) 6

34 / 40

x va y natural sonlar uchun 20∙x! = y! bo‘lsa, y ning qabul qiladigan qiymatlari yig‘indisini toping.

A) 20

B) 25

C) 23

D) 26

35 / 40

Kasrni hisoblang:

A) -5

B) 14/3

C) 0

D) -14/3

36 / 40

Tengsizlikning qanoatlantiruvchi barcha butun sonlar ko‘paytmasini toping.

A) 3

B) -4

C) 2

D) -2

37 / 40

Tenglamani yeching.

A) 9

B) 25

C) 3

D) 5

38 / 40

Agar n ta juft son va m ta toq sonlarni qo‘shganda juft son chiqsa, m ning qiymati qanday?

A) toq

B) 0

C) juft

D) 1

39 / 40

x, 24 va 30 sonlarining EKUBi 6, EKUKi 360 ga teng. Bunga ko‘ra x ning eng kichik qiymatini toping.

A) 12

B) 18

C) 10

D) 15

40 / 40

(a∈N) a sonining qanday eng kichik qiymatida (65–a) ifoda mukammal sonlardan biriga teng bo‘ladi?

A) 59

B) 28

C) 37

D) 17

Baholash mezoni

- 75 foiz va undan yuqori ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, oliy malaka toifasi (bosh o’qituvchi lavozimi) saqlansin”;

- 75 foizdan past ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, birinchi malaka toifasi (yetakchi o’qituvchi lavozimi)ga tushirilsin”;

- 75 foiz va undan yuqori ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, oliy malaka toifasi (bosh o’qituvchi lavozimi) berilsin”;

- 74 foizdan 65 foizgacha ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, birinchi malaka toifasi (yetakchi o’qituvchi lavozimi) saqlansin”;

- 65 foizdan kam ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, ikkinchi malaka toifasi (katta o’qituvchi lavozimi)ga tushirilsin”

- 64 foizdan 60 foizgacha ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, ikkinchi malaka toifasi (katta o’qituvchi lavozimi) saqlansin”;

- 60 foizdan kam ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, mutaxassis (oliy yoki o’rta maxsus, kasb-hunar ma'lumotli o’qituvchi) lavozimiga tushirilsin”

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