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Matematika attestatsiya №6

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Yanvar 30, 2022

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Matematika fanidan attestatsiya savollari №6

1 / 40

y=4cos 2x+cos8x funksiyaning hosilasini toping

A) -16cos3x*sin5x

B) 16cos3x*cos5x

C) 16sin3x*sin5x

D) 16sin3x*cos5x

2 / 40

$cos6x-4cos2x<0$ tengsizlikni yeching.

A) 2

B) 1

C) 3

D) 4

3 / 40

Qadam uzunligi deb biricnhi iz tovon oxiridan ikkinchi iz tovon oxirigacha bo'lgan masofaga aytiladi. Erkak kishi yurayotganda uning qadami va qadamlar soni orasidagi bog'lanish quyidagi formula bilan ifodalanadi: (n/P) = 140. Bu yerda n – bir minutdagi qadamlar soni. P – qadam uzunligi (m). Hikmat 1 minutda 70 qadam bossa, formula yordamida uning qadami uzunligini toping.

A) 0,9 m yoki 90 cm

B) 0,7 m yoki 70 cm

C) 0,5 m yoki 50 cm

D) 0,6 m yoki 60 cm

4 / 40

Tenglama ildizlari ayirmasining modulini toping.

A) √5+5

B) 2√5

C) √5

D) 5

5 / 40

Quyida berilgan holatda stol va uni atrofida qo’yiladigan stullarning holati berilgan va raqamlangan k-holatda stullarning raqamlari yig`indisi 351 taga teng bo`lsa, k ni toping ?

A) 12

B) 13

C) 11

D) 10

6 / 40

Hisoblang: -1²¹+(-1³⁵)-(-1)²⁸

A) -1

B) 0

C) -3

D) -2

7 / 40

x²-n≤0 tengsizlik o‘rinli bo‘ladigan x ning 7 ta butun ildizi bor bo‘lsa. n nechta turli butun qiymat qabul qiladi?

A) 9

B) 15

C) 7

D) 12

8 / 40

Integralni hisoblang:

A) 3

B) 2

C) 1

D) 4

9 / 40

Tenglamani yeching:

A) 9/5

B) 6/5

C) 5/9

D) 5*4

10 / 40

Yig‘indini toping.

A) 1/12

B) 1/9

C) 1/6

D) 1/4

11 / 40

x²-√11x+1=0 0 bo‘lsa,

A) 9

B) 10

C) 12

D) 11

12 / 40

6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang.

A) 14

B) 12

C) 13

D) 15

13 / 40

Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d)

A) 1

B) cd/b

C) bc/d

D) bd/c

14 / 40

Tenglamalar sistemani yeching:

A) (9; 0), (2; 7)

B) (2; 3)

C) (9; 0), (28; -1)

D) (7; 2), (28; -1)

15 / 40

Hisoblang:

A) 0

B) -1/2

C) -√3/2

D) 1/32

16 / 40

sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping.

A) 23

B) 35

C) 14

D) 24

17 / 40

Tengsizlik nechta butun juft yechimga
ega?

A) 115

B) 110

C) 112

D) 116

18 / 40

ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping.

A) 6

B) 10

C) 8

D) 12

19 / 40

tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping.

A) 3

B) 5

C) 8

D) -2

20 / 40

Hisoblang:

A) 1

B) cos50°

C) cos10°

D) sin10°

21 / 40

To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping.

A) 32

B) 48

C) 64

D) 42

22 / 40

ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping.

A) 4√2

B) 6

C) 4√3

D) 3√2

23 / 40

bo‘lsa,

A) 3/2

B) 1

C) 2

D) 2/3

24 / 40

P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng?

A) 5

B) -4

C) -3

D) -6

25 / 40

√3

A) 5/5

B) 21/10

C) 7/3

D) 3/2

26 / 40

P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping.

2¹ºº-1
(2¹ºº-1)x+2(2⁹⁹-1)
(2¹ºº-1)x-2(2⁹⁹-1)
2¹ººx-3·2¹⁰⁰

A) 3

B) 4

C) 1

D) 2

27 / 40

Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping.

A) 8(π+2)

B) 64

C) 32

D) 16(π-2)

28 / 40

3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping.

A) 100

B) 105

C) 96

D) 25

29 / 40

a+b+c=10, bo‘lsa, ni toping.