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Matematika attestatsiya №6

InfoMaster

Yanvar 30, 2022

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Matematika fanidan attestatsiya savollari №6

1 / 40

Quyidagi javoblardan qaysi biri tengsizlikni yechimi bo'la oladi?

A) 1

B) 2

C) 4

D) 3

2 / 40

Abdulla, Samandar va Jamshid 3 ta stulga necha xil usulda utirishi mumkin?

A) 7

B) 9

C) 6

D) 27

3 / 40

1·2·3· ... ·30 ko'paytmani tub ko'paytuvchilarga ajratganda ko'apytmada 2ⁿ, 3^m va 7^k lar ishtirok etsa, n+m+k ni toping.

A) 46

B) 40

C) 50

D) 44

4 / 40

Ushbu sistemaga ko'ra (ac+bd)² ni toping.

A) 4

B) 1

C) 3

D) 2

5 / 40

Tengsizlikni qanoatlantiradigan eng kichik ikkita butunsonning yig`indisini toping?

A) 6

B) 5

C) 3

D) 4

6 / 40

Hisoblang?

A) 2

B) 4

C) 0,25

D) 0,5

7 / 40

108 sonining natural bo‘luvchilari ko‘paytmasi quyidagilardan qaysi biriga teng?

2¹²·3¹⁸
2²·3³
2⁸·3¹⁰
2⁶·3⁹

A) 1

B) 3

C) 2

D) 4

8 / 40

Quyidagi sonini 9 ga bo‘lganda qoladigan qoldiqni toping.

A) 8

B) 1

C) 0

D) 5

9 / 40

To‘g‘ri burchakli uchburchakning bir burchagi 52° ga teng bo‘lsa, to‘g‘ri burchak uchidan tushirilgan balandlik va mediana orasidagi burchakni toping.

A) 24°

B) 7°

C) 14°

D) 17°

10 / 40

x>0 bo‘lsa, 128x+1/x² yig‘indining eng kichik qiymatini toping.

A) 16

B) 64

C) 32

D) 48

11 / 40

Agar geometrik progressiyaning umumiy hadi b_n= 3·2ⁿ bo‘lsa, ni toping.

A) 2

B) 1

C) 4

D) 3

12 / 40

Hisoblang:

A) cos10°

B) 1

C) cos50°

D) sin10°

13 / 40

Sonlarining o‘rta geometrik qiymatini toping.

A) 2√3

B) 3√2

C) 4√3

D) 2√2

14 / 40

Chizmadan foydalanib α ni toping.

A) 40°

B) 30°

C) 50°

D) 20°

15 / 40

kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping.

A) 11

B) 7

C) 5

D) 10

16 / 40

sonlarini taqqolsang.

A) b

B) c

C) a

D) c

17 / 40

Tenglamani yeching:

A) 6; -5

B) 5

C) -6; 5

D) -6

18 / 40

vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping.

A) 3

B) 1

C) 4

D) 2

19 / 40

3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping.

A) 25

B) 100

C) 96

D) 105

20 / 40

Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping.

A) 8(π+2)

B) 16(π-2)

C) 64

D) 32

21 / 40

b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi?

A) 4 yoki –12

B) 5 yoki –15

C) 3 yoki –8

D) 6

22 / 40

Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping.

A) 10

B) 8

C) 4√7

D) 6√7

23 / 40

Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi?

A) 42

B) 44

C) 43

D) 45

24 / 40

Tenglamalar sistemasining ildizlari yig‘indisini toping.

A) 20

B) 12

C) 14

D) 10

25 / 40

Ifodaning qiymatini toping.

A) 0,04

B) 0,0(4)

C) 0,(04)

D) 0,0(2)

26 / 40

Kvadratlarning yuzlari yig‘indisini toping.

A) 121

B) 11

C) 22

D) berilganlar yetarli emas

27 / 40

a_n - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping:

A) 7

B) 8

C) 6

D) 5

28 / 40

Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng?

A) √3tg50° tg70°

B) 2√3tg50° tg70°

C) √3ctg40° tg70°

D) 4 √3tg50° tg70°

29 / 40

1+sin 2x = 7(sin x + cos x) tenglamani yeching.

A) π/4+πk, k∈Z

B) -π/4+πk, k∈Z

C) Ø

D) 0

30 / 40

bo‘lsa,

A) 1

B) 2/3

C) 2

D) 3/2

31 / 40

A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping.

A) 15

B) 8

C) 20

D) 10

32 / 40

Hisoblang:

A) 10/11

B) 20/21

C) 9/10

D) 19/20

33 / 40

Tenglamalar sistemani yeching:

A) (9; 0), (28; -1)

B) (2; 3)

C) (7; 2), (28; -1)

D) (9; 0), (2; 7)

34 / 40

x²-√11x+1=0 0 bo‘lsa,

A) 12

B) 10

C) 11

D) 9

35 / 40

ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping.

A) 8

B) 10

C) 6

D) 12

36 / 40

ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping.

A) 4√2

B) 3√2

C) 4√3

D) 6

37 / 40

P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping.